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  • Android : List View or SPinner

    - by Ram
    Team, I would like to know how to display a List View or SPinner using key and value pairs in Android platform. For example take Contacts Contact has id, First Name, LastName, i would like to display First Name and Last Name in the list view or in the spinner, id1, lastname1, firstname1 id2, lastname2, firstname2 id3, lastname3, firstname3 Once the user selected any value in the List view or spin list, I need to get the key value from the List view or spinner. How to do it? Any help or examples is greatly appreciated. Thanks, Ramesh

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  • asp.net mvc 2 multiple partial view

    - by 303
    Hey Guys, I have a contoller that renders 3 different views. But I also have a common part (div) for every view. I thought that I can create an UserControl with own controller and include that control on my views (New controller and view as controll). How should I use that UserControl? Should it be a partial view? Or different approach - can I have multiple partial views on one page? I've been searching the web for the last view days and haven't found working solution that suits me. Also I want to use Strongly Typed views/data. Cheers

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  • Mvp View knows Model

    - by userbb
    I'm trying to use MVP and I notice that my View must know Model that should not happen in MVP I presume. here is example: public partial class TestForm : Form, ITestPresenter { public void LoadList(IEnumerable<AppSignature> data) { testPresenterBindingSource.DataSource = data; } } public interface ITestPresenter { event EventHandler<EventArgs> Load; void LoadList(IEnumerable<AppSignature> data); } and the problem is that in TestForm I need reference to AppSignature. In all tutorials I saw, there are some simple examples like public void LoadList(IEnumerable<String> data) where there is no need reference to model. But how i.e DataGridView can publish current row data?

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  • Why self.view is not available

    - by amok
    I have this code in the main view controller and it is working just fine and as I wanted. loadingActionSheet = [[UIActionSheet alloc] initWithTitle:@"Posting To Twitter..." delegate:nil cancelButtonTitle:@"Cancel" destructiveButtonTitle:nil otherButtonTitles:nil]; [loadingActionSheet showInView:self.view]; I wanted that code to be reusable from different part of the project so I moved it in a separate file (UIView based). The poblem that I am facing is that self.view is not available there and I don't know why because I am learning and I don't know enough to understand what I am missing. What do I have to do/add/change to have the actionsheet shown in my current view even if that code lives somewhere else?

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  • Saving data in a inherited django model

    - by aldeano
    I'm building an app to save data and some calculations made with those datas, the idea is keep the data in one model and the calculations in other. So, the models are like this: class FreshData(models.Model): name = models.CharField(max_length=20) one = models.IntegerField() two = models.IntegerField() def save(self, *args, **kwargs): Calculations() Calculations.three = self.one + self.two super(FreshData, self).save(*args, **kwargs) Calculations.save() class Calculations(FreshData): three = models.IntegerField() I've got a valueerror pointing out "self.one" and "self.two" as without value. I keep the idea in witch my design is wrong and django has a simpler way to store related data.

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  • In django, how can I include some default records in my models.py?

    - by kdt
    If I have a models.py like class WidgetType(models.Model): name = models.CharField(max_length=200) class Widget(models.Model): typeid = models.ForeignKey(WidgetType) data = models.CharField(max_length=200) How can I build in a set of built in constant values for WidgetType when I know I'm only going to have a certain few types of widget? Clearly I could fire up my admin interface and add them by hand, but I'd like to simplify configuration by having it built into the python.

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  • Extending a view to the left side, animated

    - by Heinrich
    Hi, I have a view that I want to extend on the left side using an animation. All borders but the left one should remain the same, so the x position and the width of the view are changing. I use this code: [UIView beginAnimations:nil context:nil]; [UIView setAnimationDuration:5.0]; self.frame = CGRectMake(self.frame.origin.x-100, self.frame.origin.y, self.frame.size.width+100, self.frame.size.height); [UIView commitAnimations]; If I run this code, the width of the view is set to the new value immediately and then the view is moved to the new x point, but why? How can I change this behaviour? Thanks for your ideas!

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  • iPad pushing a split view in navigator-based application

    - by FabioWong
    I had read a lot of post from the web, but I still cannot find out how can I make this out. Please help me in detail. I need to make a split-view inside a navigation because I need to make a login system. After login, then we can see the split view. I found that someone say must need to set it to be root view, some say do not need. However I cannot do it in both way. Can anyone teach me how to do that step by step?? Here is what I did. - (void)viewDidLoad { [super viewDidLoad]; GOTSorOE_EN *gotsORoeEN = [[[GOTSorOE_EN alloc]initWithNibName:@"GOTSorOE_EN" bundle:nil]autorelease]; OEFileList_EN *oeFileListEN = [[[OEFileList_EN alloc]initWithNibName:@"OEFileList_EN" bundle:nil]autorelease]; gotsORoeEN.oeFileListEN = oeFileListEN; splitViewController = [[[UISplitViewController alloc]init]autorelease]; splitViewController.viewControllers = [NSArray arrayWithObjects:gotsORoeEN, oeFileListEN, nil]; self.view = splitViewController.view; }

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  • measuring a view before rendering it

    - by nourdine
    hello I need to find out how big a view will be after attaching it to its parent. I have overridden this method: onMeasure(int, int); but it looks like this method is invoked only when I actually add my custom view to it's container using: addView(myView); Do you think there is a way to get this information before rendering the view itself? Basically I need to know the actuall size before attaching it and not attach the view at all if it would take more certain amount of space. anybody?

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  • how to change color of table view title

    - by madhavi
    hello, Can we change the color of the table view title the string which i am showing appears in gray color can we choose color for it .Is there any property of table view title i am not asking for table view header or footer i mean the title - (NSString *)tableView:(UITableView *)tableView titleForHeaderInSection:(NSInteger)section { // Keep space in the following line ........ DONT REMOVE return [NSString stringWithFormat:@"Select your service:"]; }

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  • sql create view in one to many relation

    - by new to sql
    i want to create a view in a one-to-many relatiom. here is my relations: (a -* b) and (a -* c). i want to create a view to have this data : a1 - (all b's related to a1 + all c's relted to a1) i don't wnat sth like (a1 ,b1,c1 - a1,b1,c2 ,...) how can i create this view ?

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  • BlackBerry threading model

    - by Rory Fitzpatrick
    I've read a lot of comments mention in passing that the BlackBerry threading model deviates from the Java standard and can cause issues, but no amount of googling has enlightened me on what this means exactly. I've been developing a fairly large business application for the BlackBerry and, although I don't really have any previous experience with Java multi-threaded applications, haven't come across any issue that we've been able to blame on threading, other than what we caused ourselves. Can someone describe exactly how the BlackBerry threading model is different, and how I as a developer should take that into account? Obviously any links on the topic would also be great.

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  • Django populate select field based on model query

    - by Mike
    I have the following model class DNS(models.Model): domain = models.ForeignKey(Domain) host_start = models.CharField(max_length=150, blank=True, null=True) type = models.SmallIntegerField(max_length=1, default=0, choices=DNS_CHOICE) value = models.SmallIntegerField(max_length=3, default=0, blank=True, null=True) ip = models.IPAddressField(blank=True, null=True) host_end = models.ForeignKey("DNS", blank=True, null=True) other_end = HostnameField(max_length=150, blank=True, null=True) created = models.DateTimeField(auto_now_add=True) sticky = models.BooleanField(default=0) other = models.BooleanField(default=0) When I try to init a form with just foreignkeys on host_end.. it always shows all entries in the DNS table domain = Domain.objects.get(id=request.GET['domain'], user=request.user, active=1) form = DNSFormCNAME(initial={'ip': settings.MAIN_IP, 'type': request.GET['type'], 'host_end': DNS.objects.filter(domain=domain)}) I just want the zones that match that domain.. not all domains.

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  • Rails: Pass association object to the View

    - by Fedyashev Nikita
    Model Item belongs_to User. In my controller I have code like this: @items = Item.find(:all) I need to have a corresponding User models for each item in my View templates. it works in controller(but not in View template): @items.each { |item| item.user } But manual looping just to build associations for View template kinda smells. How can I do this not in a creepy way?

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  • Post and Comment with the same Model.

    - by xRobot
    I have created a simple project where everyone can create one or more Blog. I want to use this models for Post and for Comment: class Post_comment(models.Model): content_type = models.ForeignKey(ContentType) object_id = models.PositiveIntegerField(_('object ID')) content_object = generic.GenericForeignKey() # Hierarchy Field parent = models.ForeignKey('self', null=True, blank=True, default=None, related_name='children') # User Field user = models.ForeignKey(User) # Date Fields date_submitted = models.DateTimeField(_('date/time submitted'), default = datetime.now) date_modified = models.DateTimeField(_('date/time modified'), default = datetime.now) title = models.CharField(_('title'), max_length=60, blank=True, null=True) post_comment = models.TextField(_('post_comment')) markup = models.IntegerField(choices=MARKUP_CHOICES, default=DEFAULT_MARKUP, null=True, blank=True) if it is a comment the parent is not null. So in most case the text field will contain a little bit of text. Can I use this model for both Post and Comment ?

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  • Forcing Reload of View when returning from FlipSideView of Utility Application

    - by Chris McCall
    I've got a Utility Application for iPhone 3.1.3. I have my main view loading fine. I flip over to the flipside view of the utility app and change some settings. How can I call the code I've currently got in viewDidLoad in the main view to refresh it, as settings have changed? Do I create a public method and call it from the viewDidUnload method of the flipside view? Do I call viewDidLoad directly? What's the best way to do this?

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  • How do I define a foreign key that points to a class of a different name in ActiveRecord with Rails?

    - by Mark
    Hi there, I have a model Follow that defines a user_id and a followed_user_id. If you've used Twitter, this should make sense. I'm trying to make followed_user_id point to a User model, so I can access the user that is being followed through f.followed_user (in the same way that if I have an Entry with belongs_to :user and a user_id column I can use entry.user to get the user.) How can I do this? Thanks!

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  • Hint to MVC view generator for primary key on POCOs

    - by myotherme
    When generating a strongly-typed Index view for my model I always get the following: <%= Html.ActionLink("Edit", "Edit", new { /* id=item.PrimaryKey */ }) %> I am using a POCO class for use with our ORM. As I understand it when using LINQ to SQL the view code will know which field is the primary key. Is there a way that I can an attribute to the property (or class) that will let the View Generator know that the ID property if the primary key?

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  • Backbone JS central model where all views can use

    - by chchrist
    I am new to backbone js and require js. I use requirejS to organize my backbone code into modules. I don't know if this has any importance to what I want though. I want to have a central model where all my views will have access to. They should be able to get and set values. I don't want to use it as each view model though. I need to keep in memory search options, user status (logged in/out) etc. Any ideas? EDIT Maybe the answer is here? Share resources across different amd modules

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  • Django - Expression based model constraints

    - by rtmie
    Is it possible to set an expression based constraint on a django model object, e.g. If I want to impose a constraint where an owner can have only one widget of a given type that is not in an expired state, but can have as many others as long as they are expired. Obviously I can do this by overriding the save method, but I am wondering if it can be done by setting constraints, e.g. some derivative of the unique_together constraint WIDGET_STATE_CHOICES = ( ('NEW', 'NEW'), ('ACTIVE', 'ACTIVE'), ('EXPIRED', 'EXPIRED') ) class MyWidget(models.Model): owner = models.CharField(max_length=64) widget_type = models.CharField(max_length = 10) widget_state = models.CharField(max_length = 10, choices = WIDGET_STATE_CHOICES) #I'd like to be able to do something like class Meta: unique_together = (("owner","widget_type","widget_state" != 'EXPIRED')

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  • json data not rendered in backbone view

    - by user2535706
    I have been trying to render the json data to the view by calling the rest api and the code is as follows: var Profile = Backbone.Model.extend({ dataType:'jsonp', defaults: { intuitId: null, email: null, type: null }, }); var ProfileList = Backbone.Collection.extend({ model: Profile, url: '/v1/entities/6414256167329108895' }); var ProfileView = Backbone.View.extend({ el: "#profiles", template: _.template($('#profileTemplate').html()), render: function() { _.each(this.model.models, function(profile) { var profileTemplate = this.template(this.model.toJSON()); $(this.el).append(tprofileTemplate); }, this); return this; } }); var profiles = new ProfileList(); var profilesView = new ProfileView({model: profiles}); profiles.fetch(); profilesView.render(); and the html file is as follows: <!DOCTYPE html> <html> <head> <title>SPA Example</title> <!-- <link rel="stylesheet" type="text/css" href="src/css/reset.css" /> <link rel="stylesheet" type="text/css" href="src/css/harmony_compiled.css" /> --> </head> <body class="harmony"> <header> <div class="title">SPA Example</div> </header> <div id="profiles"></div> <script id="profileTemplate" type="text/template"> <div class="profile"> <div class="info"> <div class="intuitId"> <%= intuitId %> </div> <div class="email"> <%= email %> </div> <div class="type"> <%= type %> </div> </div> </div> </script> </body> </html> This gives me an error and the render function isn't invoking properly and the render function is called even before the REST API returns the JSON response. Could anyone please help me to figure out where I went wrong. Any help is highly appreciated Thank you

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  • inheritance from the django user model results in error when changing password

    - by Jerome
    I inherited form the django user model like so: from django.db import models from django.contrib.auth.models import User, UserManager from django.utils.translation import ugettext_lazy as _ class NewUserModel(User): custom_field_1 = models.CharField(_('custom field 1'), max_length=250, null=True, blank=True) custom_field_2 = models.CharField(_('custom field 2'), max_length=250, null=True, blank=True) objects = UserManager() When i go to the admin and add an entry into this model, it saves fine, but below the "Password" field where it has this text "Use '[algo]$[salt]$[hexdigest]' or use the change password form.", if i click on the "change password form' link, it produces this error Truncated incorrect DOUBLE value: '7/password' What can i do to fix this?

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  • ASP.NET MVC Model Binders, html id

    - by Stacey
    Using the Model Binders in ASP.NET MVC 2.0, you can do something like this... [DisplayName("User Name")] public string Name { get; set; } <%: Html.TextBoxFor( m => m.Name ) :%> and then in your HTML, you get a result like this.. <label for="UserName">User Name</label> <input type="text" id="UserName" name="UserName" /> That works fine, but I want to have better control over the HTML ID. Is there any way to do this through the model binding method?

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