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• SQL Server and Hyper-V Dynamic Memory Part 3

  - by SQLOS Team

  In parts 1 and 2 of this series we looked at the basics of Hyper-V Dynamic Memory and SQL Server memory management. In this part Serdar looks at configuration guidelines for SQL Server memory management. Part 3: Configuration Guidelines for Hyper-V Dynamic Memory and SQL Server Now that we understand SQL Server Memory Management and Hyper-V Dynamic Memory basics, let’s take a look at general configuration guidelines in order to utilize benefits of Hyper-V Dynamic Memory in your SQL Server VMs. Requirements Host Operating System Requirements Hyper-V Dynamic Memory feature is introduced with Windows Server 2008 R2 SP1. Therefore in order to use Dynamic Memory for your virtual machines, you need to have Windows Server 2008 R2 SP1 or Microsoft Hyper-V Server 2008 R2 SP1 in your Hyper-V host. Guest Operating System Requirements In addition to this Dynamic Memory is only supported in Standard, Web, Enterprise and Datacenter editions of windows running inside VMs. Make sure that your VM is running one of these editions. For additional requirements on each operating system see “Dynamic Memory Configuration Guidelines” here. SQL Server Requirements All versions of SQL Server support Hyper-V Dynamic Memory. However, only certain editions of SQL Server are aware of dynamically changing system memory. To have a truly dynamic environment for your SQL Server VMs make sure that you are running one of the SQL Server editions listed below: ·         SQL Server 2005 Enterprise ·         SQL Server 2008 Enterprise / Datacenter Editions ·         SQL Server 2008 R2 Enterprise / Datacenter Editions Configuration guidelines for other versions of SQL Server are covered below in the FAQ section. Guidelines for configuring Dynamic Memory Parameters Here is how to configure Dynamic Memory for your SQL VMs in a nutshell: Hyper-V Dynamic Memory Parameter Recommendation Startup RAM 1 GB + SQL Min Server Memory Maximum RAM > SQL Max Server Memory Memory Buffer % 5 Memory Weight Based on performance needs   Startup RAM In order to ensure that your SQL Server VMs can start correctly, ensure that Startup RAM is higher than configured SQL Min Server Memory for your VMs. Otherwise SQL Server service will need to do paging in order to start since it will not be able to see enough memory during startup. Also note that Startup Memory will always be reserved for your VMs. This will guarantee a certain level of performance for your SQL Servers, however setting this too high will limit the consolidation benefits you’ll get out of your virtualization environment. Maximum RAM This one is obvious. If you’ve configured SQL Max Server Memory for your SQL Server, make sure that Dynamic Memory Maximum RAM configuration is higher than this value. Otherwise your SQL Server will not grow to memory values higher than the value configured for Dynamic Memory. Memory Buffer % Memory buffer configuration is used to provision file cache to virtual machines in order to improve performance. Due to the fact that SQL Server is managing its own buffer pool, Memory Buffer setting should be configured to the lowest value possible, 5%. Configuring a higher memory buffer will prevent low resource notifications from Windows Memory Manager and it will prevent reclaiming memory from SQL Server VMs. Memory Weight Memory weight configuration defines the importance of memory to a VM. Configure higher values for the VMs that have higher performance requirements. VMs with higher memory weight will have more memory under high memory pressure conditions on your host. Questions and Answers Q1 – Which SQL Server memory model is best for Dynamic Memory? The best SQL Server model for Dynamic Memory is “Locked Page Memory Model”. This memory model ensures that SQL Server memory is never paged out and it’s also adaptive to dynamically changing memory in the system. This will be extremely useful when Dynamic Memory is attempting to remove memory from SQL Server VMs ensuring no SQL Server memory is paged out. You can find instructions on configuring “Locked Page Memory Model” for your SQL Servers here. Q2 – What about other SQL Server Editions, how should I configure Dynamic Memory for them? Other editions of SQL Server do not adapt to dynamically changing environments. They will determine how much memory they should allocate during startup and don’t change this value afterwards. Therefore make sure that you configure a higher startup memory for your VM because that will be all the memory that SQL Server utilize Tune Maximum Memory and Memory Buffer based on the other workloads running on the system. If there are no other workloads consider using Static Memory for these editions. Q3 – What if I have multiple SQL Server instances in a VM? Having multiple SQL Server instances in a VM is not a general recommendation for predictable performance, manageability and isolation. In order to achieve a predictable behavior make sure that you configure SQL Min Server Memory and SQL Max Server Memory for each instance in the VM. And make sure that: ·         Dynamic Memory Startup Memory is greater than the sum of SQL Min Server Memory values for the instances in the VM ·         Dynamic Memory Maximum Memory is greater than the sum of SQL Max Server Memory values for the instances in the VM Q4 – I’m using Large Page Memory Model for my SQL Server. Can I still use Dynamic Memory? The short answer is no. SQL Server does not dynamically change its memory size when configured with Large Page Memory Model. In virtualized environments Hyper-V provides large page support by default. Most of the time, Large Page Memory Model doesn’t bring any benefits to a SQL Server if it’s running in virtualized environments. Q5 – How do I monitor SQL performance when I’m trying Dynamic Memory on my VMs? Use the performance counters below to monitor memory performance for SQL Server: Process - Working Set: This counter is available in the VM via process performance counters. It represents the actual amount of physical memory being used by SQL Server process in the VM. SQL Server – Buffer Cache Hit Ratio: This counter is available in the VM via SQL Server counters. This represents the paging being done by SQL Server. A rate of 90% or higher is desirable. Conclusion These blog posts are a quick start to a story that will be developing more in the near future. We’re still continuing our testing and investigations to provide more detailed configuration guidelines with example performance numbers with a white paper in the upcoming months. Now it’s time to give SQL Server and Hyper-V Dynamic Memory a try. Use this guidelines to kick-start your environment. See what you think about it and let us know of your experiences. - Serdar Sutay Originally posted at http://blogs.msdn.com/b/sqlosteam/

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• Accessing Current URL using Prototype

  - by Jason Nerer

  Hi folks, following Ryan Bates Screencast #114 I'm trying to generate endless pages using prototype. In difference to Ryan's showcase my URL called via the AJAX request shall be handled dynamically, cause I do not always call the same URL when the user reaches the end of my page. So my JS running in backround looks like that and uses document.location.href instead a fixed URL: var currentPage = 1; function checkScroll() { if (nearBottomOfPage()) { currentPage++; new Ajax.Request(document.location.href + '?page=' + currentPage, {asynchronous:true, evalScripts:true, method:'get'}); } else { setTimeout("checkScroll()", 250); } } function nearBottomOfPage() { return scrollDistanceFromBottom() < 10; } function scrollDistanceFromBottom(argument) { return pageHeight() - (window.pageYOffset + self.innerHeight); } function pageHeight() { return Math.max(document.body.scrollHeight, document.body.offsetHeight); } document.observe('dom:loaded', checkScroll); The question is: The code seems to work in Safari but fails in FF 3.6. It seems that FF calculates scrollHeight or offsetHeight differently. How can I prevent that? Thx in advance. Jason

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• SQL SERVER – Weekly Series – Memory Lane – #035

  - by Pinal Dave

  Here is the list of selected articles of SQLAuthority.com across all these years. Instead of just listing all the articles I have selected a few of my most favorite articles and have listed them here with additional notes below it. Let me know which one of the following is your favorite article from memory lane. 2007 Row Overflow Data Explanation  In SQL Server 2005 one table row can contain more than one varchar(8000) fields. One more thing, the exclusions has exclusions also the limit of each individual column max width of 8000 bytes does not apply to varchar(max), nvarchar(max), varbinary(max), text, image or xml data type columns. Comparison Index Fragmentation, Index De-Fragmentation, Index Rebuild – SQL SERVER 2000 and SQL SERVER 2005 An old but like a gold article. Talks about lots of concepts related to Index and the difference from earlier version to the newer version. I strongly suggest that everyone should read this article just to understand how SQL Server has moved forward with the technology. Improvements in TempDB SQL Server 2005 had come up with quite a lots of improvements and this blog post describes them and explains the same. If you ask me what is my the most favorite article from early career. I must point out to this article as when I wrote this one I personally have learned a lot of new things. Recompile All The Stored Procedure on Specific TableI prefer to recompile all the stored procedure on the table, which has faced mass insert or update. sp_recompiles marks stored procedures to recompile when they execute next time. This blog post explains the same with the help of a script.  2008 SQLAuthority Download – SQL Server Cheatsheet You can download and print this cheat sheet and use it for your personal reference. If you have any suggestions, please let me know and I will see if I can update this SQL Server cheat sheet. Difference Between DBMS and RDBMS What is the difference between DBMS and RDBMS? DBMS – Data Base Management System RDBMS – Relational Data Base Management System or Relational DBMS High Availability – Hot Add Memory Hot Add CPU and Hot Add Memory are extremely interesting features of the SQL Server, however, personally I have not witness them heavily used. These features also have few restriction as well. I blogged about them in detail. 2009 Delete Duplicate Rows I have demonstrated in this blog post how one can identify and delete duplicate rows. Interesting Observation of Logon Trigger On All Servers – Solution The question I put forth in my previous article was – In single login why the trigger fires multiple times; it should be fired only once. I received numerous answers in thread as well as in my MVP private news group. Now, let us discuss the answer for the same. The answer is – It happens because multiple SQL Server services are running as well as intellisense is turned on. Blog post demonstrates how we can do the same with the help of SQL scripts. Management Studio New Features I have selected my favorite 5 features and blogged about it. IntelliSense for Query Editing Multi Server Query Query Editor Regions Object Explorer Enhancements Activity Monitors Maximum Number of Index per Table One of the questions I asked in my user group was – What is the maximum number of Index per table? I received lots of answers to this question but only two answers are correct. Let us now take a look at them in this blog post. 2010 Default Statistics on Column – Automatic Statistics on Column The truth is, Statistics can be in a table even though there is no Index in it. If you have the auto- create and/or auto-update Statistics feature turned on for SQL Server database, Statistics will be automatically created on the Column based on a few conditions. Please read my previously posted article, SQL SERVER – When are Statistics Updated – What triggers Statistics to Update, for the specific conditions when Statistics is updated. 2011 T-SQL Scripts to Find Maximum between Two Numbers In this blog post there are two different scripts listed which demonstrates way to find the maximum number between two numbers. I need your help, which one of the script do you think is the most accurate way to find maximum number? Find Details for Statistics of Whole Database – DMV – T-SQL Script I was recently asked is there a single script which can provide all the necessary details about statistics for any database. This question made me write following script. I was initially planning to use sp_helpstats command but I remembered that this is marked to be deprecated in future. 2012 Introduction to Function SIGN SIGN Function is very fundamental function. It will return the value 1, -1 or 0. If your value is negative it will return you negative -1 and if it is positive it will return you positive +1. Let us start with a simple small example. Template Browser – A Very Important and Useful Feature of SSMS Templates are like a quick cheat sheet or quick reference. Templates are available to create objects like databases, tables, views, indexes, stored procedures, triggers, statistics, and functions. Templates are also available for Analysis Services as well. The template scripts contain parameters to help you customize the code. You can Replace Template Parameters dialog box to insert values into the script. An invalid floating point operation occurred If you run any of the above functions they will give you an error related to invalid floating point. Honestly there is no workaround except passing the function appropriate values. SQRT of a negative number will give you result in real numbers which is not supported at this point of time as well LOG of a negative number is not possible (because logarithm is the inverse function of an exponential function and the exponential function is NEVER negative). Validating Spatial Object with IsValidDetailed Function SQL Server 2012 has introduced the new function IsValidDetailed(). This function has made my life very easy. In simple words, this function will check if the spatial object passed is valid or not. If it is valid it will give information that it is valid. If the spatial object is not valid it will return the answer that it is not valid and the reason for the same. This makes it very easy to debug the issue and make the necessary correction. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Memory Lane, PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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• Python sorting list of dictionaries by multiple keys

  - by simi

  I have a list of dicts: b = [{u'TOT_PTS_Misc': u'Utley, Alex', u'Total_Points': 96.0}, {u'TOT_PTS_Misc': u'Russo, Brandon', u'Total_Points': 96.0}, {u'TOT_PTS_Misc': u'Chappell, Justin', u'Total_Points': 96.0}, {u'TOT_PTS_Misc': u'Foster, Toney', u'Total_Points': 80.0}, {u'TOT_PTS_Misc': u'Lawson, Roman', u'Total_Points': 80.0}, {u'TOT_PTS_Misc': u'Lempke, Sam', u'Total_Points': 80.0}, {u'TOT_PTS_Misc': u'Gnezda, Alex', u'Total_Points': 78.0}, {u'TOT_PTS_Misc': u'Kirks, Damien', u'Total_Points': 78.0}, {u'TOT_PTS_Misc': u'Worden, Tom', u'Total_Points': 78.0}, {u'TOT_PTS_Misc': u'Korecz, Mike', u'Total_Points': 78.0}, {u'TOT_PTS_Misc': u'Swartz, Brian', u'Total_Points': 66.0}, {u'TOT_PTS_Misc': u'Burgess, Randy', u'Total_Points': 66.0}, {u'TOT_PTS_Misc': u'Smugala, Ryan', u'Total_Points': 66.0}, {u'TOT_PTS_Misc': u'Harmon, Gary', u'Total_Points': 66.0}, {u'TOT_PTS_Misc': u'Blasinsky, Scott', u'Total_Points': 60.0}, {u'TOT_PTS_Misc': u'Carter III, Laymon', u'Total_Points': 60.0}, {u'TOT_PTS_Misc': u'Coleman, Johnathan', u'Total_Points': 60.0}, {u'TOT_PTS_Misc': u'Venditti, Nick', u'Total_Points': 60.0}, {u'TOT_PTS_Misc': u'Blackwell, Devon', u'Total_Points': 60.0}, {u'TOT_PTS_Misc': u'Kovach, Alex', u'Total_Points': 60.0}, {u'TOT_PTS_Misc': u'Bolden, Antonio', u'Total_Points': 60.0}, {u'TOT_PTS_Misc': u'Smith, Ryan', u'Total_Points': 60.0}] and I need to use a multi key sort reversed by Total_Points, then not reversed by TOT_PTS_Misc. This can be done at the command prompt like so: a = sorted(b, key=lambda d: (-d['Total_Points'], d['TOT_PTS_Misc'])) But I have to run this through a function, where I pass in the list and the sort keys. For example, def multikeysort(dict_list, sortkeys):. How can the lambda line be used which will sort the list, for an arbitrary number of keys that are passed in to the multikeysort function, and take into consideration that the sortkeys may have any number of keys and those that need reversed sorts will be identified with a '-' before it?

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• C - array count, strtok, etc

  - by Pedro

  Hi... i have a little problem on my code... HI open a txt that have this: LEI;7671;Maria Albertina da silva;[email protected]; 9;8;12;9;12;11;6;15;7;11; LTCGM;6567;Artur Pereira Ribeiro;[email protected]; 6;13;14;12;11;16;14; LEI;7701;Ana Maria Carvalho;[email protected]; 8;13;11;7;14;12;11;16;14; LEI, LTCGM are the college; 7671, 6567, 7701 is student number; Maria, Artur e Ana are the students name; [email protected], ...@gmail are emails from students; the first number of every line is the total of classes that students have; after that is students school notes; example: College: LEI Number: 7671 Name: Maria Albertina da Silva email: [email protected] total of classes: 9 Classe Notes: 8 12 9 12 11 6 15 7 11. My code: typedef struct aluno{ char sigla[5];//college char numero[80];//number char nome[80];//student name char email[20];//email int total_notas;// total of classes char tot_not[40]; // total classes char notas[20];// classe notes int nota; //class notes char situacao[80]; //situation (aproved or disaproved) }ALUNO; void ordena(ALUNO*alunos, int tam)//bubble sort { int i=0; int j=0; char temp[100]; for( i=0;i<tam;i++) for(j=0;j<tam-1;j++) if(strcmp( alunos[i].sigla[j], alunos[i].sigla[j+1])>0){ strcpy(temp, alunos[i].sigla[j]); strcpy(alunos[i].sigla[j],alunos[i].sigla[j+1]); strcpy(alunos[i].sigla[j+1], temp); } } void xml(ALUNO*alunos, int tam){ FILE *fp; char linha[60];//line int soma, max, min, count;//biggest note and lowest note and students per course count float media; //media of notes fp=fopen("example.txt","r"); if(fp==NULL){ exit(1); } else{ while(!(feof(fp))){ soma=0; media=0; max=0; min=0; count=0; fgets(linha,60,fp); if(linha[0]=='L'){ if(ap_dados=strtok(linha,";")){ strcpy(alunos[i].sigla,ap_dados);//copy to struct // i need to call bubble sort here, but i don't know how printf("College: %s\n",alunos[i].sigla); if(ap_dados=strtok(NULL,";")){ strcpy(alunos[i].numero,ap_dados);//copy to struct printf("number: %s\n",alunos[i].numero); if(ap_dados=strtok(NULL,";")){ strcpy(alunos[i].nome, ap_dados);//copy to struct printf("name: %s\n",alunos[i].nome); if(ap_dados=strtok(NULL,";")){ strcpy(alunos[i].email, ap_dados);//copy to struct printf("email: %s\n",alunos[i].email); } } } }i++; } if(isdigit(linha[0])){ if(info_notas=strtok(linha,";")){ strcpy(alunos[i].tot_not,info_notas); alunos[i].total_notas=atoi(alunos[i].tot_not);//total classes for(z=0;z<=alunos[i].total_notas;z++){ if(info_notas=strtok(NULL,";")){ strcpy(alunos[i].notas,info_notas); alunos[i].nota=atoi(alunos[i].notas); // student class notes } soma=soma + alunos[i].nota; media=soma/alunos[i].total_notas;//doesn't work if(alunos[i].nota>max){ max=alunos[i].nota;;//doesn't work } else{ if(min<alunos[i].nota){ min=alunos[i].nota;;//doesn't work } } //now i need to count the numbers of students in the same college, but doesn't work /*If(strcmp(alunos[i].sigla, alunos[i+1].sigla)=0){ count ++; printf("%d\n", count); here for LEI should appear 2 students and for LTCGM appear 1, don't work }*/ //Now i need to see if student is aproved or disaproved // Student is disaproved if he gets 3 notes under 10, how can i do that? } printf("media %d\n",media); //media printf("Nota maxima %d\n",max);// biggest note printf("Nota minima %d\n",min); //lowest note }i++; } } } fclose(fp); } int main(int argc, char *argv[]){ ALUNO alunos; FILE *fp; int tam; fp=fopen(nomeFicheiro,"r"); alunos = (ALUNO*) calloc (tam, sizeof(ALUNO)); xml(alunos,nomeFicheiro, tam); system("PAUSE"); return 0; }

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• Athentication Problem - not recognizing 'else' - Ruby on rails...

  - by bgadoci

  I can't seem to figure out what I am doing wrong here. I have implemented the Super Simple Authentication from Ryan Bates tutorial and while the login portion is functioning correctly, I can't get an error message and redirect to happen correctly for a bad login. Ryan Bates admits in his comments he left this out but can't seem to implement his recommendation. Basically what is happening is that when someone logs in correctly it works. When a bad password is entered it does the same redirect and flashes 'successfully logged in' thought they are not. The admin links do not show (which is correct and are the links protected by the <% if admin? %) but I need it to say 'failed login' and redirect to login path. Here is my code: SessionsController class SessionsController < ApplicationController def create if session[:password] = params[:password] flash[:notice] = 'Successfully logged in' redirect_to posts_path else flash[:notice] = "whoops" redirect_to login_path end end def destroy reset_session flash[:notice] = 'Successfully logged out' redirect_to posts_path end end ApplicationController class ApplicationController < ActionController::Base helper_method :admin? protected def authorize unless admin? flash[:error] = "unauthorized request" redirect_to posts_path false end end def admin? session[:password] == "string0826" end helper :all # include all helpers, all the time protect_from_forgery # See ActionController::RequestForgeryProtection for details # end

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• How can I save an entire list of items true or false?

  - by JZ

  I'm following Ryan Bates, Railscast episode 52 and I've translated relevant parts of the code to work with Rails 3.0.0.beta2. In Ryan's case, he simply marks items incomplete and saves a timestamp. If an Item contains a timestamp the model returns the item in the completed list. I'm attempting to save ALL values true or false, depending on whether the check_box_tag is selected or not (using boolean). I am able to save ONLY selected items, true or false. How can I save an entire list of items true or false, depending on whether the checkbox is selected? The following is my attempt: controller logic: def yardsign Add.update_all(["yardsign=?", true], :id => params[:yard_ids]) redirect_to adds_path end html.erb: <%= form_tag yardsign_adds_path, :method => :put do %> <% @adds.each do |add| %> <td><%= check_box_tag "yard_ids[]", add.id %></td> <% end %> <% end %> routes.rb resources :adds do collection do put :yardsign end end Terminal Started POST "/adds/yardsign" for 127.0.0.1 at 2010-04-15 19:22:49 Processing by AddsController#yardsign as HTML Parameters: {"commit"=>"Update", "yardsigntakers"=>["1", "2"], "authenticity_token"=>"3arhsxg/Ky+0W7RNM2T3QditMTJmOnLR5CqmMYWN4Qw="} User Load (0.3ms) SELECT "users".* FROM "users" WHERE ("users"."id" = 1) LIMIT 1 SQL (1.8ms) UPDATE "adds" SET yardsign='t' WHERE ("adds"."id" IN (1, 2)) Redirected to http://localhost:3000/adds

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• Authentication Problem - not recognizing 'else' - Ruby on rails...

  - by bgadoci

  I can't seem to figure out what I am doing wrong here. I have implemented the Super Simple Authentication from Ryan Bates tutorial and while the login portion is functioning correctly, I can't get an error message and redirect to happen correctly for a bad login. Ryan Bates admits in his comments he left this out but can't seem to implement his recommendation. Basically what is happening is that when someone logs in correctly it works. When a bad password is entered it does the same redirect and flashes 'successfully logged in' thought they are not. The admin links do not show (which is correct and are the links protected by the <% if admin? %) but I need it to say 'failed login' and redirect to login path. Here is my code: SessionsController class SessionsController < ApplicationController def create if session[:password] = params[:password] flash[:notice] = 'Successfully logged in' redirect_to posts_path else flash[:notice] = "whoops" redirect_to login_path end end def destroy reset_session flash[:notice] = 'Successfully logged out' redirect_to posts_path end end ApplicationController class ApplicationController < ActionController::Base helper_method :admin? protected def authorize unless admin? flash[:error] = "unauthorized request" redirect_to posts_path false end end def admin? session[:password] == "123456" end helper :all # include all helpers, all the time protect_from_forgery # See ActionController::RequestForgeryProtection for details # end

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• finding numbers of days between two date to make a dynamic columns

  - by Chandradyani

  Dear all, I have a select query that currently produces the following results: DoctorName Team 1 2 3 4 5 6 7 ... 31 Visited dr. As   A                             x    x ...      2 times dr. Sc   A                          x          ...      1 times dr. Gh   B                                  x ...      1 times dr. Nd   C                                     ... x    1 times Using the following query: DECLARE @startDate = '1/1/2010', @enddate = '1/31/2010' SELECT d.doctorname, t.teamname, MAX(CASE WHEN ca.visitdate = 1 THEN 'x' ELSE NULL END) AS 1, MAX(CASE WHEN ca.visitdate = 2 THEN 'x' ELSE NULL END) AS 2, MAX(CASE WHEN ca.visitdate = 3 THEN 'x' ELSE NULL END) AS 3, ... MAX(CASE WHEN ca.visitdate = 31 THEN 'x' ELSE NULL END) AS 31, COUNT(*) AS visited FROM CACTIVITY ca JOIN DOCTOR d ON d.id = ca.doctorid JOIN TEAM t ON t.id = ca.teamid WHERE ca.visitdate BETWEEN @startdate AND @enddate GROUP BY d.doctorname, t.teamname the problem is I want to make the column of date are dynamic for example if ca.visitdate BETWEEN '2/1/2012' AND '2/29/2012' so the result will be : DoctorName Team 1 2 3 4 5 6 7 ... 29 Visited dr. As   A                             x    x ...      2 times dr. Sc   A                          x          ...      1 times dr. Gh   B                                  x ...      1 times dr. Nd   C                                     ... x    1 times Can somebody help me how to get numbers of days between two date and help me revised the query so it can looping MAX(CASE WHEN ca.visitdate = 1 THEN 'x' ELSE NULL END) AS 1 as many as numbers of days? Please please

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• Finding the heaviest length-constrained path in a weighted Binary Tree

  - by Hristo

  UPDATE I worked out an algorithm that I think runs in O(n*k) running time. Below is the pseudo-code: routine heaviestKPath( T, k ) // create 2D matrix with n rows and k columns with each element = -8 // we make it size k+1 because the 0th column must be all 0s for a later // function to work properly and simplicity in our algorithm matrix = new array[ T.getVertexCount() ][ k + 1 ] (-8); // set all elements in the first column of this matrix = 0 matrix[ n ][ 0 ] = 0; // fill our matrix by traversing the tree traverseToFillMatrix( T.root, k ); // consider a path that would arc over a node globalMaxWeight = -8; findArcs( T.root, k ); return globalMaxWeight end routine // node = the current node; k = the path length; node.lc = node’s left child; // node.rc = node’s right child; node.idx = node’s index (row) in the matrix; // node.lc.wt/node.rc.wt = weight of the edge to left/right child; routine traverseToFillMatrix( node, k ) if (node == null) return; traverseToFillMatrix(node.lc, k ); // recurse left traverseToFillMatrix(node.rc, k ); // recurse right // in the case that a left/right child doesn’t exist, or both, // let’s assume the code is smart enough to handle these cases matrix[ node.idx ][ 1 ] = max( node.lc.wt, node.rc.wt ); for i = 2 to k { // max returns the heavier of the 2 paths matrix[node.idx][i] = max( matrix[node.lc.idx][i-1] + node.lc.wt, matrix[node.rc.idx][i-1] + node.rc.wt); } end routine // node = the current node, k = the path length routine findArcs( node, k ) if (node == null) return; nodeMax = matrix[node.idx][k]; longPath = path[node.idx][k]; i = 1; j = k-1; while ( i+j == k AND i < k ) { left = node.lc.wt + matrix[node.lc.idx][i-1]; right = node.rc.wt + matrix[node.rc.idx][j-1]; if ( left + right > nodeMax ) { nodeMax = left + right; } i++; j--; } // if this node’s max weight is larger than the global max weight, update if ( globalMaxWeight < nodeMax ) { globalMaxWeight = nodeMax; } findArcs( node.lc, k ); // recurse left findArcs( node.rc, k ); // recurse right end routine Let me know what you think. Feedback is welcome. I think have come up with two naive algorithms that find the heaviest length-constrained path in a weighted Binary Tree. Firstly, the description of the algorithm is as follows: given an n-vertex Binary Tree with weighted edges and some value k, find the heaviest path of length k. For both algorithms, I'll need a reference to all vertices so I'll just do a simple traversal of the Tree to have a reference to all vertices, with each vertex having a reference to its left, right, and parent nodes in the tree. Algorithm 1 For this algorithm, I'm basically planning on running DFS from each node in the Tree, with consideration to the fixed path length. In addition, since the path I'm looking for has the potential of going from left subtree to root to right subtree, I will have to consider 3 choices at each node. But this will result in a O(n*3^k) algorithm and I don't like that. Algorithm 2 I'm essentially thinking about using a modified version of Dijkstra's Algorithm in order to consider a fixed path length. Since I'm looking for heaviest and Dijkstra's Algorithm finds the lightest, I'm planning on negating all edge weights before starting the traversal. Actually... this doesn't make sense since I'd have to run Dijkstra's on each node and that doesn't seem very efficient much better than the above algorithm. So I guess my main questions are several. Firstly, do the algorithms I've described above solve the problem at hand? I'm not totally certain the Dijkstra's version will work as Dijkstra's is meant for positive edge values. Now, I am sure there exist more clever/efficient algorithms for this... what is a better algorithm? I've read about "Using spine decompositions to efficiently solve the length-constrained heaviest path problem for trees" but that is really complicated and I don't understand it at all. Are there other algorithms that tackle this problem, maybe not as efficiently as spine decomposition but easier to understand? Thanks.

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• Restoring databases to a set drive and directory

  - by okeofs

   Restoring databases to a set drive and directory Introduction Often people say that necessity is the mother of invention. In this case I was faced with the dilemma of having to restore several databases, with multiple ‘ndf’ files, and having to restore them with different physical file names, drives and directories on servers other than the servers from which they originated. As most of us would do, I went to Google to see if I could find some code to achieve this task and found some interesting snippets on Pinal Dave’s website. Naturally, I had to take it further than the code snippet, HOWEVER it was a great place to start. Creating a temp table to hold database file details First off, I created a temp table which would hold the details of the individual data files within the database. Although there are a plethora of fields (within the temp table below), I utilize LogicalName only within this example. The temporary table structure may be seen below:   create table #tmp ( LogicalName nvarchar(128)  ,PhysicalName nvarchar(260)  ,Type char(1)  ,FileGroupName nvarchar(128)  ,Size numeric(20,0)  ,MaxSize numeric(20,0), Fileid tinyint, CreateLSN numeric(25,0), DropLSN numeric(25, 0), UniqueID uniqueidentifier, ReadOnlyLSN numeric(25,0), ReadWriteLSN numeric(25,0), BackupSizeInBytes bigint, SourceBlocSize int, FileGroupId int, LogGroupGUID uniqueidentifier, DifferentialBaseLSN numeric(25,0), DifferentialBaseGUID uniqueidentifier, IsReadOnly bit, IsPresent bit,  TDEThumbPrint varchar(50) )    We now declare and populate a variable(@path), setting the variable to the path to our SOURCE database backup. declare @path varchar(50) set @path = 'P:\DATA\MYDATABASE.bak'   From this point, we insert the file details of our database into the temp table. Note that we do so by utilizing a restore statement HOWEVER doing so in ‘filelistonly’ mode.   insert #tmp EXEC ('restore filelistonly from disk = ''' + @path + '''')   At this point, I depart from what I gleaned from Pinal Dave.   I now instantiate a few more local variables. The use of each variable will be evident within the cursor (which follows):   Declare @RestoreString as Varchar(max) Declare @NRestoreString as NVarchar(max) Declare @LogicalName  as varchar(75) Declare @counter as int Declare @rows as int set @counter = 1 select @rows = COUNT(*) from #tmp  -- Count the number of records in the temp                                    -- table   Declaring and populating the cursor At this point I do realize that many people are cringing about the use of a cursor. Being an Oracle professional as well, I have learnt that there is a time and place for cursors. I would remind the reader that the data that will be read into the cursor is from a local temp table and as such, any locking of the records (within the temp table) is not really an issue.   DECLARE MY_CURSOR Cursor  FOR  Select LogicalName  From #tmp   Parsing the logical names from within the cursor. A small caveat that works in our favour,  is that the first logical name (of our database) is the logical name of the primary data file (.mdf). Other files, except for the very last logical name, belong to secondary data files. The last logical name is that of our database log file.   I now open my cursor and populate the variable @RestoreString Open My_Cursor  set @RestoreString =  'RESTORE DATABASE [MYDATABASE] FROM DISK = N''P:\DATA\ MYDATABASE.bak''' + ' with  '   We now fetch the first record from the temp table.   Fetch NEXT FROM MY_Cursor INTO @LogicalName   While there are STILL records left within the cursor, we dynamically build our restore string. Note that we are using concatenation to create ‘one big restore executable string’.   Note also that the target physical file name is hardwired, as is the target directory.   While (@@FETCH_STATUS <> -1) BEGIN IF (@@FETCH_STATUS <> -2) -- As long as there are no rows missing select @RestoreString = case  when @counter = 1 then -- This is the mdf file    @RestoreString + 'move  N''' + @LogicalName + '''' + ' TO N’’X:\DATA1\'+ @LogicalName + '.mdf' + '''' + ', '   -- OK, if it passes through here we are dealing with an .ndf file -- Note that Counter must be greater than 1 and less than the number of rows.   when @counter > 1 and @counter < @rows then -- These are the ndf file(s)    @RestoreString + 'move  N''' + @LogicalName + '''' + ' TO N’’X:\DATA1\'+ @LogicalName + '.ndf' + '''' + ', '   -- OK, if it passes through here we are dealing with the log file When @LogicalName like '%log%' then    @RestoreString + 'move  N''' + @LogicalName + '''' + ' TO N’’X:\DATA1\'+ @LogicalName + '.ldf' +'''' end --Increment the counter   set @counter = @counter + 1 FETCH NEXT FROM MY_CURSOR INTO @LogicalName END   At this point we have populated the varchar(max) variable @RestoreString with a concatenation of all the necessary file names. What we now need to do is to run the sp_executesql stored procedure, to effect the restore.   First, we must place our ‘concatenated string’ into an nvarchar based variable. Obviously this will only work as long as the length of @RestoreString is less than varchar(max) / 2.   set @NRestoreString = @RestoreString EXEC sp_executesql @NRestoreString   Upon completion of this step, the database should be restored to the server. I now close and deallocate the cursor, and to be clean, I would also drop my temp table.   CLOSE MY_CURSOR DEALLOCATE MY_CURSOR GO   Conclusion Restoration of databases on different servers with different physical names and on different drives are a fact of life. Through the use of a few variables and a simple cursor, we may achieve an efficient and effective way to achieve this task.

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• Java Program Compiles and Runs, but doesn't work

  - by Richard Long

  When I run this program I enter information in a text box, push the search button, but nothing happens. The program just sits there until I press Cntrl C to break it. It looks like it should work, but I can't figure out what is hanging the program up. Here is the code: First class: import java.io.*; import java.awt.*; import javax.swing.*; import java.awt.event.*; import java.util.*; public class NameGameFrame extends JFrame { public static String name; static JTextField textfield = new JTextField(20); static JTextArea textarea = new JTextArea(30,30); public static String num; public static String [] fields; public static int [] yearRank; public static boolean match; public static int getInts, marker, year, max; public static void main( String[] args) { JFrame frame = new JFrame(); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.setTitle("Name Game"); frame.setLocation(500,400); frame.setSize(800,800); JPanel panel = new JPanel(new GridBagLayout()); GridBagConstraints c = new GridBagConstraints(); JLabel label = new JLabel("Enter the Name or Partial Name to search:"); c.gridx = 0; c.gridy = 0; c.insets = new Insets(2,2,2,2); panel.add(label,c); c.gridx = 0; c.gridy = 1; panel.add(textarea,c); JButton button = new JButton("Search"); c.gridx = 1; c.gridy = 1; panel.add(button,c); c.gridx = 1; c.gridy = 0; panel.add(textfield,c); frame.getContentPane().add(panel, BorderLayout.NORTH); frame.pack(); frame.setVisible(true); button.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent ae) { name = textfield.getText(); java.io.File file = new java.io.File("namesdata.txt"); try { Scanner input = new Scanner(file); num = input.nextLine(); NameRecord nr = new NameRecord(name); while (input.hasNext()) { if(match = num.toLowerCase().contains(name.toLowerCase())) { nr.getRank(); nr.getBestYear(marker); } } } catch(FileNotFoundException e) { System.err.format("File does not exist\n"); } textarea.setText(fields[0]); } }); } } This is the second class: import java.io.*; import java.util.*; public class NameRecord { public NameRecord( String name) { } public static int getBestYear(int marker) { switch (marker) { case 1: year = 1900; break; case 2: year = 1910; break; case 3: year = 1920; break; case 4: year = 1930; break; case 5: year = 1940; break; case 6: year = 1950; break; case 7: year = 1960; break; case 8: year = 1970; break; case 9: year = 1980; break; case 10: year = 1990; break; case 11: year = 2000; break; } return year; } public static int getRank() { fields = num.split(" "); max = 0; for (int i = 1; i<12; i++) { getInts = Integer.parseInt(fields[i]); if(getInts>max) { max = getInts; marker = i; } } return max; } }

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• Hue, saturation, brightness, contrast effect in hlsl

  - by Vibhore Tanwer

  I am new to pixel shader, and I am trying to write a simple brightness, contrast, hue, saturation effect. I have written a shader for it but I doubt that my shader is not providing me correct result, Brightness, contrast, saturation is working fine, problem is with hue. if I apply hue between -1 to 1, it seems to be working fine, but to make things more sharp, I need to apply hue value between -180 and 180, like we can apply hue in Paint.NET. Here is my code. // Amount to shift the Hue, range 0 to 6 float Hue; float Brightness; float Contrast; float Saturation; float Alpha; sampler Samp : register(S0); // Converts the rgb value to hsv, where H's range is -1 to 5 float3 rgb_to_hsv(float3 RGB) { float r = RGB.x; float g = RGB.y; float b = RGB.z; float minChannel = min(r, min(g, b)); float maxChannel = max(r, max(g, b)); float h = 0; float s = 0; float v = maxChannel; float delta = maxChannel - minChannel; if (delta != 0) { s = delta / v; if (r == v) h = (g - b) / delta; else if (g == v) h = 2 + (b - r) / delta; else if (b == v) h = 4 + (r - g) / delta; } return float3(h, s, v); } float3 hsv_to_rgb(float3 HSV) { float3 RGB = HSV.z; float h = HSV.x; float s = HSV.y; float v = HSV.z; float i = floor(h); float f = h - i; float p = (1.0 - s); float q = (1.0 - s * f); float t = (1.0 - s * (1 - f)); if (i == 0) { RGB = float3(1, t, p); } else if (i == 1) { RGB = float3(q, 1, p); } else if (i == 2) { RGB = float3(p, 1, t); } else if (i == 3) { RGB = float3(p, q, 1); } else if (i == 4) { RGB = float3(t, p, 1); } else /* i == -1 */ { RGB = float3(1, p, q); } RGB *= v; return RGB; } float4 mainPS(float2 uv : TEXCOORD) : COLOR { float4 col = tex2D(Samp, uv); float3 hsv = rgb_to_hsv(col.xyz); hsv.x += Hue; // Put the hue back to the -1 to 5 range //if (hsv.x > 5) { hsv.x -= 6.0; } hsv = hsv_to_rgb(hsv); float4 newColor = float4(hsv,col.w); float4 colorWithBrightnessAndContrast = newColor; colorWithBrightnessAndContrast.rgb /= colorWithBrightnessAndContrast.a; colorWithBrightnessAndContrast.rgb = colorWithBrightnessAndContrast.rgb + Brightness; colorWithBrightnessAndContrast.rgb = ((colorWithBrightnessAndContrast.rgb - 0.5f) * max(Contrast + 1.0, 0)) + 0.5f; colorWithBrightnessAndContrast.rgb *= colorWithBrightnessAndContrast.a; float greyscale = dot(colorWithBrightnessAndContrast.rgb, float3(0.3, 0.59, 0.11)); colorWithBrightnessAndContrast.rgb = lerp(greyscale, colorWithBrightnessAndContrast.rgb, col.a * (Saturation + 1.0)); return colorWithBrightnessAndContrast; } technique TransformTexture { pass p0 { PixelShader = compile ps_2_0 mainPS(); } } Please If anyone can help me learning what am I doing wrong or any suggestions? Any help will be of great value. EDIT: Images of the effect at hue 180: On the left hand side, the effect I got with @teodron answer. On the right hand side, The effect Paint.NET gives and I'm trying to reproduce.

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• Red Gate's on the road in 2012 - Will you catch us?

  - by RedAndTheCommunity

  Annabel Bradford, our Communities and Events Manager, tells all about her experience of our 1st SQL Saturday of the year. The first stop this year was SQL Saturday #104 Colorado Springs, back in early January. I made the trip across from the UK just for this SQL Saturday event, and I'm so glad I did. I picked up Max from Red Gate's Pasadena office and we flew into Colorado Springs airport late on Friday evening to be greeted by freezing temperatures, which was quite a shock after the California sunshine. Rising before the sun, we arrived at Mr Biggs, the venue for the event, in the darkness. It was great to see so many smiling attendees so bright and early on a Saturday morning. Everyone was eager to learn more about SQL Server, and hundreds of people came and chatted with us at the table, saw demos and learnt more about Red Gate tools. The event highlights for the attendees were definitely the unlimited lazer quest, bowling and pool available during the break times. For Max, Grant Fritchey and I on the Red Gate table, the highlights have to be meeting customers and getting the opportunity to meet attendees who'd heard of, but wanted to know more about, Red Gate. We were delighted to hear lots of valuable feedback that we took back to share with the team. As a thank you for sharing insights about their work lives and how they use SQL Server and Red Gate tools, attendees are able to take away Red Gate SQL Server books. We aim to have a range of titles available when we exhibit, so that attendees can choose a book that's going to be most interesting to them, and that they can use as a reference back at the office. Every time I meet a Red Gate user or a member of the SQL community, I'm always overwhelmed by the enthusiasm they have for their industry. Everyone who gives up their time to learn more about their job should be rewarded, and at Red Gate we like to do just that. Red Gate has long supported the SQL community through sponsorship to facilitate user group meetings and community events, but it's only though face-to-face contact that we really get a chance to see the impact of our support. I hope we'll have the chance to see you on the road at some point this year. We'll be at a range of events, including free SQL Saturdays, one day free events 'the Red Gate way', two-day Rallys, and full-week conferences. Next stop is SQL Saturday #109 Silicon Valley on March 3rd where you'll meet Jeff and Arneh, two of our US-based SQL team members. Be sure to ask them any questions you've got about the Red Gate tools, as these guys will be delighted to hear your questions, show you the options, and will make a note of your feedback to send through to the development team. Until the next time. Happy learning! Annabel                         Grant, Max and Annabel at SQL Saturday #104 Colorado Springs

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• problem with frustum AABB culling in DirectX

  - by Matthew Poole

  Hi, I am currently working on a project with a few friends, and I am trying to get frustum culling working. Every single tutorial or article I go to shows that my math is correct and that this should be working. I thought maybe posting here, somebody would catch something I could not. Thank you. Here are the important code snippets /create the projection matrix void CD3DCamera::SetLens(float fov, float aspect, float nearZ, float farZ) { D3DXMatrixPerspectiveFovLH(&projMat, D3DXToRadian(fov), aspect, nearZ, farZ); } //build the view matrix after changes have been made to camera void CD3DCamera::BuildView() { //keep axes orthoganal D3DXVec3Normalize(&look, &look); //up D3DXVec3Cross(&up, &look, &right); D3DXVec3Normalize(&up, &up); //right D3DXVec3Cross(&right, &up, &look); D3DXVec3Normalize(&right, &right); //fill view matrix float x = -D3DXVec3Dot(&position, &right); float y = -D3DXVec3Dot(&position, &up); float z = -D3DXVec3Dot(&position, &look); viewMat(0,0) = right.x; viewMat(1,0) = right.y; viewMat(2,0) = right.z; viewMat(3,0) = x; viewMat(0,1) = up.x; viewMat(1,1) = up.y; viewMat(2,1) = up.z; viewMat(3,1) = y; viewMat(0,2) = look.x; viewMat(1,2) = look.y; viewMat(2,2) = look.z; viewMat(3,2) = z; viewMat(0,3) = 0.0f; viewMat(1,3) = 0.0f; viewMat(2,3) = 0.0f; viewMat(3,3) = 1.0f; } void CD3DCamera::BuildFrustum() { D3DXMATRIX VP; D3DXMatrixMultiply(&VP, &viewMat, &projMat); D3DXVECTOR4 col0(VP(0,0), VP(1,0), VP(2,0), VP(3,0)); D3DXVECTOR4 col1(VP(0,1), VP(1,1), VP(2,1), VP(3,1)); D3DXVECTOR4 col2(VP(0,2), VP(1,2), VP(2,2), VP(3,2)); D3DXVECTOR4 col3(VP(0,3), VP(1,3), VP(2,3), VP(3,3)); // Planes face inward frustum[0] = (D3DXPLANE)(col2); // near frustum[1] = (D3DXPLANE)(col3 - col2); // far frustum[2] = (D3DXPLANE)(col3 + col0); // left frustum[3] = (D3DXPLANE)(col3 - col0); // right frustum[4] = (D3DXPLANE)(col3 - col1); // top frustum[5] = (D3DXPLANE)(col3 + col1); // bottom // Normalize the frustum for( int i = 0; i < 6; ++i ) D3DXPlaneNormalize( &frustum[i], &frustum[i] ); } bool FrustumCheck(D3DXVECTOR3 max, D3DXVECTOR3 min, const D3DXPLANE* frustum) { // Test assumes frustum planes face inward. D3DXVECTOR3 P; D3DXVECTOR3 Q; bool ret = false; for(int i = 0; i < 6; ++i) { // For each coordinate axis x, y, z... for(int j = 0; j < 3; ++j) { // Make PQ point in the same direction as the plane normal on this axis. if( frustum[i][j] > 0.0f ) { P[j] = min[j]; Q[j] = max[j]; } else { P[j] = max[j]; Q[j] = min[j]; } } if(D3DXPlaneDotCoord(&frustum[i], &Q) < 0.0f ) ret = false; } return true; }

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• My Dog, Cross-Channel Shopping, and Fusion SCM

  - by Kathryn Perry

  A guest post by Mark Carson, Director, Oracle Fusion Supply Chain Management I was walking my dog Max in an open space behind my house. As we tromped through the tall weeds I remembered it is tick season and that I should get Max some protection. While he sniffed merrily in the tick infested brush, I started shopping in the middle of an open field on my phone. I thought it would be convenient to pick up the tick medicine from a pet store on the way home. Searching the pet store website I saw that they had the medicine, but there was no information on whether the store had any in stock and there were no options for shipping it to the store for pickup. I could return it, but not pick it up which seamed kind of odd. I really didn't feel like making calls to the local stores to find out if they had it. Since the product is popular, I tried one of the large 'everything' stores. Browsing its website I could see that it could be shipped to me, shipped to the store for free, and that the store nearest to me had it in stock. Needless to say, this store became a better option. This experience is a small example of why retailers, distributors, and manufactures have placed a high priority on enabling 'cross-channel commerce.' Shoppers like you and me expect to be able to search, compare, buy and return products on-line and over the phone using a variety of devices including PDAs, tablets and in-store kiosks. The pet store lost my business because its web channel had limited information about its stores. I have spoken with many customers and prospects about cross-channel commerce. They all realize the business implications and urgency behind cross-channel commerce but recognize there are challenges to enable it. New and existing applications must be integrated together globally through a consistent cross-channel business process. Integration is required between applications that provide the initial shopping experience and delivery applications associated with warehouses, stores, and partners. The enablement must be accomplished in a flexible way to react to fast-changing product portfolios and new acquisitions, while at the same time minimizing costs through reuse of existing systems. Meanwhile, the business must continue to grow and decision makers need to balance new capability with peak seasons. The challenges above are not unique to retail. Any customer in any industry who has multiple points for capturing orders and multiple points for fulfilling orders will face these challenges. With this in mind, we had a unique opportunity in Fusion SCM to re-think how to build a set of modular and flexible applications in the order management space that would make these challenges easier to conquer. The results are Fusion Distributed Order Orchestration and Global Order Promising. These applications can help companies, such as the pet store, enable true cross-channel commerce. The apps provide highly adaptable and flexible business processes to automate order orchestration across multiple cross-channel systems. They also show a global view of supply across warehouses, stores, and partners for real-time availability and more accurate order promising. Additional capability includes a standards-based integration framework for seamless execution and the ability to reuse existing systems for faster and lower cost implementations. OK, that was a mouthful of features and benefits. As Max waited to cross the street (he can do basic math too), I wondered if he could relate. He does not care about leash laws, pick-up courtesy, where he can/can't walk, what time of day it is, or even ticks. He does not care about how all these things could make walking complicated. He just wants to walk. Similarly, customers just want to shop and companies just want to make it easier to sell and deliver. You can learn more about Distributed Order Orchestration and Global Order Promising in cross-channel here.

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• ??Data Guard???????Redo GAP

  - by JaneZhang(???)

    ?Oracle Data Guard?,Redo Gap??????????????????redo????????????,?????????redo??????????,?????????????:ARC:????MRP:Media Recovery Process,????????redoRFS:Remote File Server ,???????????redo??FAL:Fetch Archive Log????:?????????gap?,??????????gap?????:Oracle 11.2.0.2 on Linux 5.????:1.?????????????:Primary:MAX(SEQUENCE#)--------------           86Standby:MAX(SEQUENCE#)--------------           862. ??????,??gap:????????: #ifconfig eth0 down???????switch logfile:SQL>alter system switch logfile;SQL>alter system switch logfile;...Primary:MAX(SEQUENCE#)--------------           96????alert log?????????????:TNS-00513: Destination host unreachable   nt secondary err code: 101   nt OS err code: 0Error 12543 received logging on to the standbyFAL[server, ARCp]: Error 12543 creating remote archivelog file 'STANDBY'FAL[server, ARCp]: FAL archive failed, see trace file.ARCH: FAL archive failed. Archiver continuingORACLE Instance orcl - Archival Error. Archiver continuing.3.??????????????,????????????:mv *.arc ../4. ???????:#ifconfig eth0 up5.??,???ARC???????????????????MRP???gap??gap fetching.??alert log:Thu Mar 29 19:58:49 2012Media Recovery Waiting for thread 1 sequence 87 (in transit) <====  ?????,??87...Thu Mar 29 20:08:45 2012...Media Recovery Waiting for thread 1 sequence 94Thu Mar 29 20:11:01 2012RFS[61]: Assigned to RFS process 13643RFS[61]: Opened log for thread 1 sequence 97 dbid 1285401128 branch 757620395Archived Log entry 80 added for thread 1 sequence 97 rlc 757620395 ID 0x4c9d8928 dest 2:Thu Mar 29 20:11:02 2012RFS[62]: Assigned to RFS process 13645RFS[62]: Selected log 4 for thread 1 sequence 98 dbid 1285401128 branch 757620395Thu Mar 29 20:11:02 2012Primary database is in MAXIMUM PERFORMANCE modeRe-archiving standby log 4 thread 1 sequence 98Thu Mar 29 20:11:02 2012Archived Log entry 81 added for thread 1 sequence 98 ID 0x4c9d8928 dest 1:RFS[63]: Assigned to RFS process 13647RFS[63]: Selected log 4 for thread 1 sequence 99 dbid 1285401128 branch 757620395Thu Mar 29 20:11:05 2012Fetching gap sequence in thread 1, gap sequence 94-96 <===========?gap...6.??MRP?trace,?????MRP ??fetching gap:MRP trace:*** 2012-03-29 20:08:45.375 4265 krsh.cMedia Recovery Waiting for thread 1 sequence 94*** 2012-03-29 20:11:05.543*** 2012-03-29 20:11:05.543 4265 krsh.cFetching gap sequence in thread 1, gap sequence 94-96 <==========MRP?gap.Redo shipping client performing standby login*** 2012-03-29 20:11:05.593 4595 krsu.cLogged on to standby successfullyClient logon and security negotiation successful!7.????????????,???RFS????????, MRP ????????apply.Thu Mar 29 20:12:06 2012RFS[64]: Assigned to RFS process 13649RFS[64]: Opened log for thread 1 sequence 94 dbid 1285401128 branch 757620395Archived Log entry 82 added for thread 1 sequence 94 rlc 757620395 ID 0x4c9d8928 dest 2:Thu Mar 29 20:12:06 2012RFS[65]: Assigned to RFS process 13651RFS[65]: Opened log for thread 1 sequence 95 dbid 1285401128 branch 757620395Thu Mar 29 20:12:06 2012RFS[66]: Assigned to RFS process 13653RFS[66]: Opened log for thread 1 sequence 96 dbid 1285401128 branch 757620395Archived Log entry 83 added for thread 1 sequence 95 rlc 757620395 ID 0x4c9d8928 dest 2:Archived Log entry 84 added for thread 1 sequence 96 rlc 757620395 ID 0x4c9d8928 dest 2:Thu Mar 29 20:12:16 2012Media Recovery Log /home/oracle/arch1/standby/1_94_757620395.arcMedia Recovery Log /home/oracle/arch1/standby/1_95_757620395.arcMedia Recovery Log /home/oracle/arch1/standby/1_96_757620395.arcMedia Recovery Log /home/oracle/arch1/standby/1_97_757620395.arcMedia Recovery Log /home/oracle/arch1/standby/1_98_757620395.arc????:????????,????gap???,???ARC?????????gap??,????????????MRP???apply log??????gap,???????FAL????? ?:?11g,??????ARC??????RFS?MRP?????????????gap. 8. ????????MRP??FAL??gap??,????????????,??MRP?trace???:FAL[client, MRP0],?????FAL??? *** 2012-03-29 21:18:15.964 4265 krsh.cError 1031 received logging on to the standby*** 2012-03-29 21:18:15.964 4265 krsh.cFAL[client, MRP0]: Error 1031 connecting to PRIMARY for fetching gap sequence

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• Sql Query - Limiting query results

  - by Gublooo

  I am quite certain we cannot use the LIMIT clause for what I want to do - so wanted to find if there are any other ways we can accomplish this. I have a table which captures which user visited which store. Every time a user visits a store, a row is inserted into this table. Some of the fields are shopping_id (primary key) store_id user_id Now what I want is - for a given set of stores, find the top 5 users who have visited the store max number of times. I can do this 1 store at a time as: select store_id,user_id,count(1) as visits from shopping where store_id = 60 group by user_id,store_id order by visits desc Limit 5 This will give me the 5 users who have visited store_id=60 the max times What I want to do is provide a list of 10 store_ids and for each store fetch the 5 users who have visited that store max times select store_id,user_id,count(1) as visits from shopping where store_id in (60,61,62,63,64,65,66) group by user_id,store_id order by visits desc Limit 5 This will not work as the Limit at the end will return only 5 rows rather than 5 rows for each store. Any ideas on how I can achieve this. I can always write a loop and pass 1 store at a time but wanted to know if there is a better way

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• Using UIScreen to drive a VGA display - doesn't seem to show the UIWindow?

  - by Peter Hajas

  HI there, I'm trying to use UIScreen to drive a separate screen with the VGA dongle on my iPad. Here's what I've got in my root view controller's viewDidLoad: //Code to detect if an external display is connected to the iPad. NSLog(@"Number of screens: %d", [[UIScreen screens]count]); //Now, if there's an external screen, we need to find its modes, itereate through them and find the highest one. Once we have that mode, break out, and set the UIWindow. if([[UIScreen screens]count] > 1) //if there are more than 1 screens connected to the device { CGSize max; UIScreenMode *maxScreenMode; for(int i = 0; i < [[[[UIScreen screens] objectAtIndex:1] availableModes]count]; i++) { UIScreenMode *current = [[[[UIScreen screens]objectAtIndex:1]availableModes]objectAtIndex:i]; if(current.size.width > max.width); { max = current.size; maxScreenMode = current; } } //Now we have the highest mode. Turn the external display to use that mode. UIScreen *external = [[UIScreen screens] objectAtIndex:1]; external.currentMode = maxScreenMode; //Boom! Now the external display is set to the proper mode. We need to now set the screen of a new UIWindow to the external screen external_disp = [externalDisplay alloc]; external_disp.drawImage = drawViewController.drawImage; UIWindow *newwindow = [UIWindow alloc]; [newwindow addSubview:external_disp.view]; newwindow.screen = external; }

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• Select a distinct record, filtering is not working..

  - by help_inmssql

  Hello EVery I am new to SQl. query to result in the following records. I have a table with records as c1 c2 c3 c4 c5 c6 1 John 2.3.2010 12:09:54 4 7 99 2 mike 2.3.2010 13:09:59 8 6 88 3 ahmad 2.3.2010 13:09:59 1 9 19 4 Jim 23.3.2010 16:35:14 4 5 99 5 run 23.3.2010 12:09:54 3 8 12 I want to fecth only records. i.e only 1 latest record per day. If both of them happen at the same time, sort by C1.so in 1&3 it should fetch 3. 3 ahmad 2.3.2010 14:09:59 1 9 19 4 Jim 23.3.2010 16:35:14 4 5 99 I have got a new problem in this. If i filter the records based on conditions the last record is missing. I tried many ways but still it is failing. Here update_log is my table. SELECT * FROM update_log t1 WHERE (t1.c3) = ( SELECT MAX(t2.c3) FROM update_log t2 WHERE DATEDIFF(dd,t2.c3, t1.c3) = 0 ) and t1.c3 > '02.03.2010' and t1.modified_at <= '22.03.2010' ORDER BY t1.c3 ASC. But i am not able to retrieve the record 4 Jim 23.3.2010 16:35:14 4 5 99 I dont know this query results in only 3 ahmad 2.3.2010 14:09:59 1 9 19 The format of the column c3 is datetime. I am pumping the data into the column as using $date = date("d.m.Y H:i",time()); -- simple date fetch of today. Another query that i tried for the same purpose. select * from (select convert(varchar(10), c3,104) as date, max(c3) as max_date, max(c1) as Nr from update_log group by convert(varchar(10), c3,104)) as t2 inner join update_log as t1 on (t2.max_date = t1.c3 and convert(varchar(10), c3,104) = date and t1.[c1]= Nr) WHERE t1.c3 >= '02.03.2010' and t1.c3 <= '16.04.2010' . I even tried this way..the same error last record is not coming..

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• mysql error in php

  - by fusion

  i'm trying to run this php code which should display a quote from mysql, but can't figure out where is it going wrong. the result variable is null or empty. can someone help me out. thanks! <?php include 'config.php'; // 'text' is the name of your table that contains // the information you want to pull from $rowcount = mysql_query("select count(*) as rows from quotes"); // Gets the total number of items pulled from database. while ($row = mysql_fetch_assoc($rowcount)) { $max = $row["rows"]; //print_r ($max); } // Selects an item's index at random $rand = rand(1,$max)-1; print_r ($rand); $result = mysql_query("select * from quotes limit $rand, 1") or die ('Error: '.mysql_error()); if (!$result or mysql_num_rows($result)) { echo "Empty"; } else{ while ($row = mysql_fetch_array($result)) { $randomOutput = $row['cQuotes']; echo '<p>' . $randomOutput . '</p>'; } }

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• Human age program in pascal

  - by bah

  Hi, I have this task and i can't figure out how to do it. I need to find persons age in days, there are given birth and death dates, there's data file: 8 Albertas Einšteinas 1879 03 14 1955 04 18 Balys Sruoga 1896 02 02 1947 10 16 Antanas Vienuolis 1882 04 07 1957 08 17 Ernestas Rezerfordas 1871 08 30 1937 10 17 Nilsas Boras 1885 10 07 1962 11 18 Nežiniukas Pirmasis 8 05 24 8 05 25 Nežiniukas Antrasis 888 05 25 888 05 25 Nežiniukas Treciasis 1 01 01 125 01 01 and there's how result file should look like: 1879 3 14 1955 4 18 27775 1896 2 2 1947 10 16 18871 1882 4 7 1957 8 17 27507 1871 8 30 1937 10 17 24138 1885 10 7 1962 11 18 28147 8 5 24 8 5 25 1 888 5 25 888 5 25 0 1 1 1 125 1 1 45260 Few things to notice: all februarys have 28 days. My function for calculating age: function AmziusFunc(Mas : TZmogus) : longint; var i, s : integer; amzius, max : longint; begin max := 125 * 365; amzius := (Mas.mirY - Mas.gimY) * 365 + (Mas.mirM - Mas.gimM) * 31 + (Mas.mirD - Mas.gimD); if ( amzius >= max ) then amzius := 0; AmziusFunc := amzius; end; What should i change there? Thanks.

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• How to draw line inside a scatter plot

  - by ruffy

  I can't believe that this is so complicated but I tried and googled for a while now. I just want to analyse my scatter plot with a few graphical features. For starters, I want to add simply a line. So, I have a few (4) points and like in this plot [1] I want to add a line to it. http://en.wikipedia.org/wiki/File:ROC_space-2.png [1] Now, this won't work. And frankly, the documentation-examples-gallery combo and content of matplotlib is a bad source for information. My code is based upon a simple scatter plot from the gallery: # definitions for the axes left, width = 0.1, 0.85 #0.65 bottom, height = 0.1, 0.85 #0.65 bottom_h = left_h = left+width+0.02 rect_scatter = [left, bottom, width, height] # start with a rectangular Figure fig = plt.figure(1, figsize=(8,8)) axScatter = plt.axes(rect_scatter) # the scatter plot: p1 = axScatter.scatter(x[0], y[0], c='blue', s = 70) p2 = axScatter.scatter(x[1], y[1], c='green', s = 70) p3 = axScatter.scatter(x[2], y[2], c='red', s = 70) p4 = axScatter.scatter(x[3], y[3], c='yellow', s = 70) p5 = axScatter.plot([1,2,3], "r--") plt.legend([p1, p2, p3, p4, p5], [names[0], names[1], names[2], names[3], "Random guess"], loc = 2) # now determine nice limits by hand: binwidth = 0.25 xymax = np.max( [np.max(np.fabs(x)), np.max(np.fabs(y))] ) lim = ( int(xymax/binwidth) + 1) * binwidth axScatter.set_xlim( (-lim, lim) ) axScatter.set_ylim( (-lim, lim) ) xText = axScatter.set_xlabel('FPR / Specificity') yText = axScatter.set_ylabel('TPR / Sensitivity') bins = np.arange(-lim, lim + binwidth, binwidth) plt.show() Everything works, except the p5 which is a line. Now how is this supposed to work? What's good practice here?

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• How does Subsonic handle connections?

  - by Quintin Par

  In Nhibernate you start a session by creating it during a BeginRequest and close at EndRequest public class Global: System.Web.HttpApplication { public static ISessionFactory SessionFactory = CreateSessionFactory(); protected static ISessionFactory CreateSessionFactory() { return new Configuration() .Configure(Path.Combine(AppDomain.CurrentDomain.BaseDirectory, "hibernate.cfg.xml")) .BuildSessionFactory(); } public static ISession CurrentSession { get{ return (ISession)HttpContext.Current.Items["current.session"]; } set { HttpContext.Current.Items["current.session"] = value; } } protected void Global() { BeginRequest += delegate { CurrentSession = SessionFactory.OpenSession(); }; EndRequest += delegate { if(CurrentSession != null) CurrentSession.Dispose(); }; } } What’s the equivalent in Subsonic? The way I understand, Nhibernate will close all the connections at endrequest. Reason: While trouble shooting some legacy code in a Subsonic project I get a lot of MySQL timeouts,suggesting that the code is not closing the connections MySql.Data.MySqlClient.MySqlException: error connecting: Timeout expired. The timeout period elapsed prior to obtaining a connection from the pool. This may have occurred because all pooled connections were in use and max pool size was reached. Generated: Tue, 11 Aug 2009 05:26:05 GMT System.Web.HttpUnhandledException: Exception of type 'System.Web.HttpUnhandledException' was thrown. --- MySql.Data.MySqlClient.MySqlException: error connecting: Timeout expired. The timeout period elapsed prior to obtaining a connection from the pool. This may have occurred because all pooled connections were in use and max pool size was reached. at MySql.Data.MySqlClient.MySqlPool.GetConnection() at MySql.Data.MySqlClient.MySqlConnection.Open() at SubSonic.MySqlDataProvider.CreateConnection(String newConnectionString) at SubSonic.MySqlDataProvider.CreateConnection() at SubSonic.AutomaticConnectionScope..ctor(DataProvider provider) at SubSonic.MySqlDataProvider.GetReader(QueryCommand qry) at SubSonic.DataService.GetReader(QueryCommand cmd) at SubSonic.ReadOnlyRecord`1.LoadByParam(String columnName, Object paramValue) My connection string is as follows <connectionStrings> <add name="xx" connectionString="Data Source=xx.net; Port=3306; Database=db; UID=dbuid; PWD=xx;Pooling=true;Max Pool Size=12;Min Pool Size=2;Connection Lifetime=60" /> </connectionStrings>

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• "Undefined symbols" linker error with simple template class

  - by intregus

  Been away from C++ for a few years and am getting a linker error from the following code: Gene.h #ifndef GENE_H_INCLUDED #define GENE_H_INCLUDED template <typename T> class Gene { public: T getValue(); void setValue(T value); void setRange(T min, T max); private: T value; T minValue; T maxValue; }; #endif // GENE_H_INCLUDED Gene.cpp #include "Gene.h" template <typename T> T Gene<T>::getValue() { return this->value; } template <typename T> void Gene<T>::setValue(T value) { if(value >= this->minValue && value <= this->minValue) { this->value = value; } } template <typename T> void Gene<T>::setRange(T min, T max) { this->minValue = min; this->maxValue = max; } Using Code::Blocks and GCC if it matters to anyone. Also, clearly porting some GA stuff to C++ for fun and practice.

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