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  • Linq to Sql, Repositories, and Asp.Net MVC ViewData: How to remove redundancy?

    - by Dr. Zim
    Linq to SQL creates objects which are IQueryable and full of relations. Html Helpers require specific interface objects like IEnumerable<SelectListItem>. What I think could happen: Reuse the objects from Linq to SQL without all the baggage, i.e., return Pocos from the Linq to SQL objects without additional Domain Model classes? Extract objects that easily convert to (or are) Html helper objects like the SelectListItem enumeration? Is there any way to do this without breaking separation of concerns? Some neat oop trick to bridge the needs? For example, if this were within a repository, the SelectListItem wouldn't be there. The select new is a nice way to cut out an object from the Linq to SQL without the baggage but it's still referencing a class that shouldn't be referenced: IEnumerable<SelectListItem> result = (from record in db.table select new SelectListItem { Selected = record.selected, Text= record.Text, Value= record.Value } ).AsEnumerable();

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  • How do I remove the top margin in a web page?

    - by RoryG
    I have had this problem with every web page I have created. There is always a top margin above the 'main container' div I use to place my content in the center of the page. I am using a css style sheet and have set margins and padding in the body to 0px and set the margin and padding to 0 in the div: body{ margin-top: 0px; margin-bottom: 0px; margin-left: 0px; margin-right: 0px; padding: 0; color: black; font-size: 10pt; font-family: "Trebuchet MS", sans-serif; background-color: #E2E2E2;} div.mainContainer{ height: auto; width: 68em; background-color: #FFFFFF; margin: 0 auto; padding: 0;} I have looked online many times, but all I can see to do is set these margin and padding attributes. Is there something else I should be doing? The margin exists in IE and Firefox.

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  • Recursive multiline sed - remove beginning of file until pattern match.

    - by yaya3
    I have nested subdirectories containing html files. For each of these html files I want to delete from the top of the file until the pattern <div id="left- This is my attempt from osx's terminal: find . -name "*.html" -exec sed "s/.*?<div id=\"left-col/<div id=\"left-col/g" '{}' \; I get a lot of html output in the termainal, but no files contain the substitution or are written Thanks

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  • How I can add and remove the attribute "readonly" ?

    - by question_about_the_problem
    $(document).ready(function() { //Check City Value var city_value = parseInt($("#city").val()); if( city_value == 0) { $("#state").attr("readonly", true); //$("#rate").attr("readonly", "readonly"); } else { $("#state").removeAttr("readonly"); //document.getElementById("state").removeAttribute("readonly",0); //get_states(city_value); } /*** //Check State Value var state_value = parseInt($('#state').val()); if( state_value == 0) { $('#rate').attr('readonly', true); } else { $('#rate').attr('readonly', false); } ***/ });

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  • How do I add/remove items to a ListView in virtual mode?

    - by Eric
    If I'm using a ListView in virtual mode then, as I understand it, the list view only keeps track of a small number of items in the list. As the user scrolls it dynamically retrieves items it needs to show from the virtual list. But what if an item is added or removed from the master list? If an item is added/removed outside of the range of indexes being shown by the list view then I would assume the list view would show the added/missing items when the user scrolls to that index. Is this correct? But what if an item is added/removed from the range of indexes the user is currently viewing? How do I trigger the list view to refresh the items it is currently viewing to show the new/missing items?

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  • How to remove the title bar from a JFrame screenshot?

    - by Greg Harman
    I'm capturing a screenshot image of a JFrame via a "double buffering" approach, per below: public BufferedImage getScreenshot() { java.awt.Dimension dim = this.getPreferredSize(); BufferedImage image = new BufferedImage(dim.width, dim.height, BufferedImage.TYPE_INT_RGB); this.paint(image.getGraphics()); return image; } where this extends JFrame. The image that I get has a blank strip along the top where the title bar was. What's the most straightforward way to capture an image of the contents of the JFrame without the extra space allocated for the title bar?

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  • Remove unncessary error raised by paperclip - filename is not recognized by the 'identify' command.

    - by kgpdeveloper
    I've been searching on how to solve this issue but could not find any real and working solution. User model: validates_attachment_content_type :avatar, :content_type = ['image/jpeg', 'image/pjpeg', 'image/x-png', 'image/png', 'image/gif'] Unnecessary error shows up when invalid file type is uploaded: Avatar /tmp/sample,23283,0.txt is not recognized by the 'identify' command. Server details: Ubuntu and Debian which identify results to /usr/bin/identify Specifying command path does not solve the issue: Paperclip.options[:command_path] = "/usr/bin" Any ideas? I looked at geometry.rb file and there seems to be something wrong with it. def self.from_file file file = file.path if file.respond_to? "path" geometry = begin Paperclip.run("identify", %Q[-format "%wx%h" "#{file}"[0]]) rescue PaperclipCommandLineError "" end parse(geometry) || raise(NotIdentifiedByImageMagickError.new("#{file} is not recognized by the 'identify' command.")) end Let me know if anyone has solved the same issue and how. Many thanks.

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  • How do I remove the time from printpreview dialog?

    - by Albo Best
    Here is my code: Imports System.Data.OleDb Imports System.Drawing.Printing Namespace Print Public Class Form1 Inherits System.Windows.Forms.Form Dim PrintC As PrinterClass Dim conn As OleDb.OleDbConnection Dim connectionString As String = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=..\\db1.mdb" Dim sql As String = String.Empty Dim ds As DataSet Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load FillDataGrid() '//create printerclass object PrintC = New PrinterClass(PrintDocument1, dataGrid) End Sub Private Sub FillDataGrid() Try Dim dt As New DataTable Dim ds As New DataSet ds.Tables.Add(dt) Dim da As New OleDbDataAdapter con.Open() da = New OleDbDataAdapter("SELECT * from klient ", con) da.Fill(dt) con.Close() dataGrid.DataSource = dt.DefaultView Dim dTable As DataTable For Each dTable In ds.Tables Dim dgStyle As DataGridTableStyle = New DataGridTableStyle dgStyle.MappingName = dTable.TableName dataGrid.TableStyles.Add(dgStyle) Next ' DataGrid settings dataGrid.CaptionText = "TE GJITHE KLIENTET" dataGrid.HeaderFont = New Font("Verdana", 12) dataGrid.TableStyles(0).GridColumnStyles(0).Width = 60 dataGrid.TableStyles(0).GridColumnStyles(1).Width = 140 dataGrid.TableStyles(0).GridColumnStyles(2).Width = 140 dataGrid.TableStyles(0).GridColumnStyles(3).Width = 140 dataGrid.TableStyles(0).GridColumnStyles(4).Width = 140 dataGrid.TableStyles(0).GridColumnStyles(5).HeaderText = "" dataGrid.TableStyles(0).GridColumnStyles(5).Width = -1 Catch ex As Exception MessageBox.Show(ex.Message) End Try End Sub Private Sub btnPrint_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnPrint.Click 'create printerclass object PrintC = New PrinterClass(PrintDocument1, dataGrid) PrintDocument1.Print() End Sub Private Sub btnPreview_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnPreview.Click 'create printerclass object PrintC = New PrinterClass(PrintDocument1, dataGrid) ''preview Dim ps As New PaperSize("A4", 840, 1150) ps.PaperName = PaperKind.A4 PrintDocument1.DefaultPageSettings.PaperSize = ps PrintPreviewDialog1.WindowState = FormWindowState.Normal PrintPreviewDialog1.StartPosition = FormStartPosition.CenterScreen PrintPreviewDialog1.ClientSize = New Size(600, 600) PrintPreviewDialog1.ShowDialog() End Sub Private Sub PrintDocument1_PrintPage(ByVal sender As System.Object, ByVal e As System.Drawing.Printing.PrintPageEventArgs) Handles PrintDocument1.PrintPage 'print grid Dim morepages As Boolean = PrintC.Print(e.Graphics) If (morepages) Then e.HasMorePages = True End If End Sub End Class End Namespace This is how data looks in DataGrid (that's perfect)... and here is how it looks when I click PrintPreview. (I don't want the time to appear there, the "12:00:00" part. in database the date is stored as Short Date (10-Dec-12) Can somebody suggest a way around that? Imports System Imports System.Windows.Forms Imports System.Drawing Imports System.Drawing.Printing Imports System.Collections Imports System.Data Namespace Print Public Class PrinterClass '//clone of Datagrid Dim PrintGrid As Grid '//printdocument for initial printer settings Private PrintDoc As PrintDocument '//defines whether the grid is ordered right to left Private bRightToLeft As Boolean '//Current Top Private CurrentY As Single = 0 '//Current Left Private CurrentX As Single = 0 '//CurrentRow to print Private CurrentRow As Integer = 0 '//Page Counter Public PageCounter As Integer = 0 '/// <summary> '/// Constructor Class '/// </summary> '/// <param name="pdocument"></param> '/// <param name="dgrid"></param> Public Sub New(ByVal pdocument As PrintDocument, ByVal dgrid As DataGrid) 'MyBase.new() PrintGrid = New Grid(dgrid) PrintDoc = pdocument '//The grid columns are right to left bRightToLeft = dgrid.RightToLeft = RightToLeft.Yes '//init CurrentX and CurrentY CurrentY = pdocument.DefaultPageSettings.Margins.Top CurrentX = pdocument.DefaultPageSettings.Margins.Left End Sub Public Function Print(ByVal g As Graphics, ByRef currentX As Single, ByRef currentY As Single) As Boolean '//use predefined area currentX = currentX currentY = currentY PrintHeaders(g) Dim Morepages As Boolean = PrintDataGrid(g) currentY = currentY currentX = currentX Return Morepages End Function Public Function Print(ByVal g As Graphics) As Boolean CurrentX = PrintDoc.DefaultPageSettings.Margins.Left CurrentY = PrintDoc.DefaultPageSettings.Margins.Top PrintHeaders(g) Return PrintDataGrid(g) End Function '/// <summary> '/// Print the Grid Headers '/// </summary> '/// <param name="g"></param> Private Sub PrintHeaders(ByVal g As Graphics) Dim sf As StringFormat = New StringFormat '//if we want to print the grid right to left If (bRightToLeft) Then CurrentX = PrintDoc.DefaultPageSettings.PaperSize.Width - PrintDoc.DefaultPageSettings.Margins.Right sf.FormatFlags = StringFormatFlags.DirectionRightToLeft Else CurrentX = PrintDoc.DefaultPageSettings.Margins.Left End If Dim i As Integer For i = 0 To PrintGrid.Columns - 1 '//set header alignment Select Case (CType(PrintGrid.Headers.GetValue(i), Header).Alignment) Case HorizontalAlignment.Left 'left sf.Alignment = StringAlignment.Near Case HorizontalAlignment.Center sf.Alignment = StringAlignment.Center Case HorizontalAlignment.Right sf.Alignment = StringAlignment.Far End Select '//advance X according to order If (bRightToLeft) Then '//draw the cell bounds (lines) and back color g.FillRectangle(New SolidBrush(PrintGrid.HeaderBackColor), CurrentX - PrintGrid.Headers(i).Width, CurrentY, PrintGrid.Headers(i).Width, PrintGrid.Headers(i).Height) g.DrawRectangle(New Pen(PrintGrid.LineColor), CurrentX - PrintGrid.Headers(i).Width, CurrentY, PrintGrid.Headers(i).Width, PrintGrid.Headers(i).Height) '//draw the cell text g.DrawString(PrintGrid.Headers(i).CText, PrintGrid.Headers(i).Font, New SolidBrush(PrintGrid.HeaderForeColor), New RectangleF(CurrentX - PrintGrid.Headers(i).Width, CurrentY, PrintGrid.Headers(i).Width, PrintGrid.Headers(i).Height), sf) '//next cell CurrentX -= PrintGrid.Headers(i).Width Else '//draw the cell bounds (lines) and back color g.FillRectangle(New SolidBrush(PrintGrid.HeaderBackColor), CurrentX, CurrentY, PrintGrid.Headers(i).Width, PrintGrid.Headers(i).Height) g.DrawRectangle(New Pen(PrintGrid.LineColor), CurrentX, CurrentY, PrintGrid.Headers(i).Width, PrintGrid.Headers(i).Height) '//draw the cell text g.DrawString(PrintGrid.Headers(i).CText, PrintGrid.Headers(i).Font, New SolidBrush(PrintGrid.HeaderForeColor), New RectangleF(CurrentX, CurrentY, PrintGrid.Headers(i).Width, PrintGrid.Headers(i).Height), sf) '//next cell CurrentX += PrintGrid.Headers(i).Width End If Next '//reset to beginning If (bRightToLeft) Then '//right align CurrentX = PrintDoc.DefaultPageSettings.PaperSize.Width - PrintDoc.DefaultPageSettings.Margins.Right Else '//left align CurrentX = PrintDoc.DefaultPageSettings.Margins.Left End If '//advance to next row CurrentY = CurrentY + CType(PrintGrid.Headers.GetValue(0), Header).Height End Sub Private Function PrintDataGrid(ByVal g As Graphics) As Boolean Dim sf As StringFormat = New StringFormat PageCounter = PageCounter + 1 '//if we want to print the grid right to left If (bRightToLeft) Then CurrentX = PrintDoc.DefaultPageSettings.PaperSize.Width - PrintDoc.DefaultPageSettings.Margins.Right sf.FormatFlags = StringFormatFlags.DirectionRightToLeft Else CurrentX = PrintDoc.DefaultPageSettings.Margins.Left End If Dim i As Integer For i = CurrentRow To PrintGrid.Rows - 1 Dim j As Integer For j = 0 To PrintGrid.Columns - 1 '//set cell alignment Select Case (PrintGrid.Cell(i, j).Alignment) '//left Case HorizontalAlignment.Left sf.Alignment = StringAlignment.Near Case HorizontalAlignment.Center sf.Alignment = StringAlignment.Center '//right Case HorizontalAlignment.Right sf.Alignment = StringAlignment.Far End Select '//advance X according to order If (bRightToLeft) Then '//draw the cell bounds (lines) and back color g.FillRectangle(New SolidBrush(PrintGrid.BackColor), CurrentX - PrintGrid.Cell(i, j).Width, CurrentY, PrintGrid.Cell(i, j).Width, PrintGrid.Cell(i, j).Height) g.DrawRectangle(New Pen(PrintGrid.LineColor), CurrentX - PrintGrid.Cell(i, j).Width, CurrentY, PrintGrid.Cell(i, j).Width, PrintGrid.Cell(i, j).Height) '//draw the cell text g.DrawString(PrintGrid.Cell(i, j).CText, PrintGrid.Cell(i, j).Font, New SolidBrush(PrintGrid.ForeColor), New RectangleF(CurrentX - PrintGrid.Cell(i, j).Width, CurrentY, PrintGrid.Cell(i, j).Width, PrintGrid.Cell(i, j).Height), sf) '//next cell CurrentX -= PrintGrid.Cell(i, j).Width Else '//draw the cell bounds (lines) and back color g.FillRectangle(New SolidBrush(PrintGrid.BackColor), CurrentX, CurrentY, PrintGrid.Cell(i, j).Width, PrintGrid.Cell(i, j).Height) g.DrawRectangle(New Pen(PrintGrid.LineColor), CurrentX, CurrentY, PrintGrid.Cell(i, j).Width, PrintGrid.Cell(i, j).Height) '//draw the cell text '//Draw text by alignment g.DrawString(PrintGrid.Cell(i, j).CText, PrintGrid.Cell(i, j).Font, New SolidBrush(PrintGrid.ForeColor), New RectangleF(CurrentX, CurrentY, PrintGrid.Cell(i, j).Width, PrintGrid.Cell(i, j).Height), sf) '//next cell CurrentX += PrintGrid.Cell(i, j).Width End If Next '//reset to beginning If (bRightToLeft) Then '//right align CurrentX = PrintDoc.DefaultPageSettings.PaperSize.Width - PrintDoc.DefaultPageSettings.Margins.Right Else '//left align CurrentX = PrintDoc.DefaultPageSettings.Margins.Left End If '//advance to next row CurrentY += PrintGrid.Cell(i, 0).Height CurrentRow += 1 '//if we are beyond the page margin (bottom) then we need another page, '//return true If (CurrentY > PrintDoc.DefaultPageSettings.PaperSize.Height - PrintDoc.DefaultPageSettings.Margins.Bottom) Then Return True End If Next Return False End Function End Class End Namespace

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  • Does deleting a branch in git remove it from the history?

    - by Ken Liu
    Coming from svn, just starting to become familiar with git. When a branch is deleted in git, is it removed from the history? In svn, you can easily recover a branch by reverting the delete operation (reverse merge). Like all deletes in svn, the branch is never really deleted, it's just removed from the current tree. If the branch is actually deleted from the history in git, what happens to the changes that were merged from that branch? Are they retained?

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  • jquery: draggable plugin -> remove drag behaviour from html5 video controls?

    - by mathiregister
    hi guys, im working with the jquery ui draggable plugin and i have an html 5 video element with "preload controls" that acts kind of buggy. I $(".thumb").draggable(); if i drag the video by clicking on the video controls and i'm releasing the mouse again, the video still sticks with the mouse. <div class='thumb video'><video width='260' height='200' preload controls> i have no chance to release the video again if i started draggin it at the video controls. any idea how i could fix this! i probaply should script my own video controls to fix this.

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  • Before the lablel for each of the menu item, there is space with the some color, i want to remove th

    - by anandhinaveen
    Hello, I am using richfaces dropDownMenu component which contains a set of rich menuItems. When the menu items are displayed, a extra space is displayed before the lablel for each of the menu item. But I have a requirement of not displaying the space before the labels and to change the color. I used the css to reduce the space: .rich-menu-item-icon img { width: 0px; } .rich-menu-group-icon img { width: 0px; } but, i need to change the color in that place.

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  • How to remove the xmlns:XSI and xmlns:XSD namespaces from the xml output of a webservice in .net fra

    - by Chetan
    HI, This is an old question, i have seen some solutions on this forum itself, but am trying to use webservices for the first time so please bear with me on this one. I have a webservice that returns XML in the following format <subs xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" msisdn="965xxxxxx"> <shortcode label="XXXX"> <channels> <channel> <id>442</id> <name>News</name> <billingperiod>7</billingperiod> <billingamount>3</billingamount> <lastbilling>4/14/2010 1:41:11 PM</lastbilling> </channel> <channel> <id>443</id> <name>News2</name> <billingperiod>7</billingperiod> <billingamount>3</billingamount> <lastbilling>4/14/2010 1:41:19 PM</lastbilling> </channel> </channels> </shortcode> </subs> I want the same XMl output without the xmlns:xsd and xmlns:xsi tags. I have tried the following solution that was suggested: Public Function GetSubscription(....) As String Dim namespaces As New XmlSerializerNamespaces namespaces.Add(String.Empty, String.Empty) Dim serializer As New XmlSerializer(SubsDetail.GetType) Dim sw As New System.IO.StringWriter Dim writer As New System.Xml.XmlTextWriter(sw) writer.Formatting = Formatting.None serializer.Serialize(writer, SubsDetail, namespaces) writer.Close() Return sw.toString() The result was that I got an xml in the following format: <string> <?xml version="1.0" encoding="utf-16"?><subs msisdn="965xxxx"> <shortcode label="XXXX"> <channels> <channel> <id>442</id> <name>News</name> <billingperiod>7</billingperiod> <billingamount>3</billingamount> <lastbilling>4/14/2010 1:41:11 PM</lastbilling> </channel> <channel> <id>443</id> <name>News2</name> <billingperiod>7</billingperiod> <billingamount>3</billingamount> <lastbilling>4/14/2010 1:41:19 PM</lastbilling> </channel> </channels> </shortcode> </subs> </string> Though the format of the xml is correct it is coming as string within the <string> tags. This is really driving me nuts. Can I get the output as xml without the outer string tags?

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  • How change Castor mapping to remove "xmlns:xsi" and "xsi:type" attributes from element in XML output

    - by Derek Mahar
    How do I change the Castor mapping <?xml version="1.0"?> <!DOCTYPE mapping PUBLIC "-//EXOLAB/Castor Mapping DTD Version 1.0//EN" "http://castor.org/mapping.dtd"> <mapping> <class name="java.util.ArrayList" auto-complete="true"> <map-to xml="ArrayList" /> </class> <class name="com.db.spgit.abstrack.ws.response.UserResponse"> <map-to xml="UserResponse" /> <field name="id" type="java.lang.String"> <bind-xml name="id" node="element" /> </field> <field name="deleted" type="boolean"> <bind-xml name="deleted" node="element" /> </field> <field name="name" type="java.lang.String"> <bind-xml name="name" node="element" /> </field> <field name="typeId" type="java.lang.Integer"> <bind-xml name="typeId" node="element" /> </field> <field name="regionId" type="java.lang.Integer"> <bind-xml name="regionId" node="element" /> </field> <field name="regionName" type="java.lang.String"> <bind-xml name="regionName" node="element" /> </field> </class> </mapping> to suppress the xmlns:xsi and xsi:type attributes in the element of the XML output? For example, instead of the output XML <?xml version="1.0" encoding="UTF-8"?> <ArrayList> <UserResponse xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:type="UserResponse"> <name>Tester</name> <typeId>1</typeId> <regionId>2</regionId> <regionName>US</regionName> </UserResponse> </ArrayList> I'd prefer <?xml version="1.0" encoding="UTF-8"?> <ArrayList> <UserResponse> <name>Tester</name> <typeId>1</typeId> <regionId>2</regionId> <regionName>US</regionName> </UserResponse> </ArrayList> such that the element name implies the xsi:type.

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  • VS2010 Web Deploy: how to remove absolute paths and automate setAcl?

    - by Julien Lebosquain
    The integrated Web Deployment in Visual Studio 2010 is pretty nice. It can create a package ready to be deployed using MSDeploy on a target IIS machine. Problem is, this package will be redistributed to a client that will install it himself using the "Import Application" from IIS when MSDeploy is installed. The default package created always include the full path from the development machine, "D:\Dev\XXX\obj\Debug\Package\PackageTmp" in the source manifest file. It doesn't prevent installation of course since it was designed this way, but it looks ugly in the import dialog and has no meaning to the client. Worse he will wonder what are those paths and it looks quite confusing. By customizing the .csproj file (by adding MSBuild properties used by the package creation task), I managed to add additional parameters to the package. However, I spent most of the afternoon in the 2600 lines long Web.Publishing.targets trying to understand what parameter influenced the "development path" behavior, in vain. I also tried to use the setAcl to customize security on a given folder after deployment, but I only managed to do this with MSBuild by using a relative path... it shouldn't matter if I resolve the first problem though. I could modify the generated archive after its creation but I would prefer if everything was automatized using MSBuild. Does anyone know how to do that?

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  • How to remove the file extension in a zsh completion?

    - by meeselet
    I want to adjust zsh so that I can tab complete: myprog <tab> using all *.foo files in ~/somedir, but have it so that it displays them without the .foo extension. Is there any way to do this? This is what I have so far: #compdef myprog typeset -A opt_args local context state line local -a mydirs mydirs="(. ~/somedir)" _arguments -s -S \ "*:name:->foos" \ && return 0 case $state in (foos) _files -W ${mydirs} -g '*.foo(:r)' && return 0 ;; esac return 1 However, this displays double the output for every file (that is, each .foo file is listed with and without its extension). Is there any way around this?

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  • How do I remove implementing types from GWT’s Serialization Policy?

    - by Bluu
    The opposite of this question: http://stackoverflow.com/questions/138099/how-do-i-add-a-type-to-gwts-serialization-policy-whitelist GWT is adding undesired types to the serialization policy and bloating my JS. How do I trim my GWT whitelist by hand? Or should I at all? For example, if I put the interface List on a GWT RPC service class, GWT has to generate Javascript that handles ArrayList, LinkedList, Stack, Vector, ... even though my team knows we're only ever going to return an ArrayList. I could just make the method's return type ArrayList, but I like relying on an interface rather than a specific implementation. After all, maybe one day we will switch it up and return e.g. a LinkedList. In that case, I'd like to force the GWT serialization policy to compile for only ArrayList and LinkedList. No Stacks or Vectors. These implicit restrictions have one huge downside I can think of: a new member of the team starts returning Vectors, which will be a runtime error. So besides the question in the title, what is your experience designing around this?

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  • How do you Remove an Invalid Remote Branch Reference from Git?

    - by Casey
    In my current repo I have the following output: $ git branch -a * master remotes/origin/master remotes/public/master I want to delete 'remotes/public/master' from the branch list: $ git branch -d remotes/public/master error: branch 'remotes/public/master' not found. Also, the output of 'git remote' is strange, since it does not list 'public': $ git remote show origin How can I delete 'remotes/public/master' from the branch list? Update, tried the 'git push' command: $ git push public :master fatal: 'public' does not appear to be a git repository fatal: The remote end hung up unexpectedly Solution: The accepted answer had the solution at the bottom! git gc --prune=now

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  • How do I remove a validate class using jquery?

    - by InnateDev
    I have some options for pricing using radio buttons. When a user selects the radio button with no value my checkbox form must not be validated. here is my code: Options: <input type="radio" name="pricing_option_rect" id="pricing_imp_rect1" checked="checked" value="100">100 <input type="radio" name="pricing_option_rect" id="pricing_imp_rect2" value="200">200 <input type="radio" name="pricing_option_rect" id="pricing_imp_rect3" value="300">300 <input type="radio" name="pricing_option_rect" id="pricing_imp_rect4" value="0" />0 Checkboxes: <input type="checkbox" value="check1" name="rectcat[]" class="{validate:{required:true, minlength:1, maxlength:5}}" />One <input type="checkbox" value="check2" name="rectcat[]" />Two <input type="checkbox" value="check3" name="rectcat[]" />Three <input type="checkbox" value="check4" name="rectcat[]" />Four <input type="checkbox" value="check5" name="rectcat[]" />Five <input type="checkbox" value="check6" name="rectcat[]" />Six <input type="checkbox" value="check7" name="rectcat[]" />Seven <input type="checkbox" value="check8" name="rectcat[]" />Eight <div class="container"><label for="rectcat[]" class="error">Please Select a Minimum of ONE and a Maximum of FIVE categories!</label></div>

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  • How to remove multiple instances and just have one instance while multiple function calls in php ?

    - by Rachel
    public function getHelperInstance() { $user = new Helper(); $user->set($result['data']); return $user; } I am calling getHelper() class multiple times and if $user is not empty than am calling getHelperInstance(), now in my case getHelperInstance() always creates a new instance of Helper() class and so every time I call getHelperInstance() function am creating a new instance of Helper() so is there any way where can I can just create one instance of Helper() and use it multiple times instead of creating a new instance everytime. Any suggestions !!! public function getHelper() { $user = array(); if (!empty($user)) { $user = $this->getHelperInstance(); } return $user; }

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