Search Results

Search found 4391 results on 176 pages for 'tree hacker'.

Page 92/176 | < Previous Page | 88 89 90 91 92 93 94 95 96 97 98 99  | Next Page >

  • Set compression level when generating a ZIP file using RubyZip

    - by Vincent Robert
    Hi, I have a Ruby program that zips a directory tree of XML files using the rubyzip gem. My problem is that the file is starting to be heavy and I would like to increase the compression level, since compression time is not an issue. I could not find in the rubyzip documentation a way to specify the compression level for the created ZIP file. Anyone know how to change this setting?

    Read the article

  • Is Pharo just a repackaging/rebranding of Squeak?

    - by number5
    I'm trying to learn some Smalltalk. Fisrt found was Squeak, but since it has been removed from Gentoo ebuild tree because of security problem, so I decided to find an alternative. Then I found Pharo through Seaside project, after I downloaded Pharo 1.0 package, there are actually a SqueakVM inside! So, my question is: Is Pharo just a repackaging/rebranding of Squeak? And are those security problem of Squeak (bundle unsecure libs) still applied to Pharo? Thanks!

    Read the article

  • Repository organization and selective checkout

    - by Maurizio Reginelli
    I am using TortoiseSVN and I have a SVN repository organized in this way: folder1 folder2 trunk tag branches folder3 trunk tag branches folder4 folder5 trunk tag branches I would like to know if there is a way to checkout only trunk directories, keeping the entire tree under the versioning control: folder1 folder2 trunk folder3 trunk folder4 folder5 trunk In this way I can update all trunks with a single update command on folder1, without updating tags and branches which can be full of data.

    Read the article

  • Visualizing the SiteMap of a large (page number) website

    - by Michael
    I'm looking for a tool or service that can spider a web domain with a large number of pages, create a sitemap, and then visualize that map in a way that will help me see, understand and group content (I'm new to the site) Something like a tree-view or other standard Site Map visualizations would be great. I am yet unable to find a tool that does this (I've found plenty of things to spider the site and create an xml file, nothing to visualize it) Thanks!

    Read the article

  • git create branch with untracked files

    - by Surya
    I've a master branch with a .gitignore file with directory X listed in it. (X is not being tracked). When I try to add a branch tracking a remote using the command git checkout -b mybranch origin/mybranch The remote branch is tracking X directory, and hence this checkout fails with the error Untracked working tree file 'X' would be overwritten by merge. what is the way out ? Surya

    Read the article

  • Git dirctet acyclic graph - children know their parents but not the other way around

    - by dayscott
    Git is implemented as a directed acyclic graph. Children know their parents but not the other way round. This makes sense because i can reach every commit only through a branch or a tag ( generally speaking through a reference). That's how i traverse the tree. What other reasons had the developers of Git to make "the children know their parents but not the other way around"?/ What are the key benefits of this?

    Read the article

  • How can I append a description to a Zend_Form_Element?

    - by Mallika Iyer
    I have the following Zend_Form_Element: $imginstructions = "Some description"; $img = $this->createElement('select','img'); $img->setAttrib('class', 'image-select'); $imgdecorator = $img->getDecorator('Description'); $imgdecorator->setOption('escape', false); $img->setLabel('Image:') ->setRequired(true) ->addMultiOptions($images) ->setValue('') ->setDescription($imginstructions) ->addErrorMessage('You must select an image'); $img->size = 5; $this->addElement($img); The description should appear next to the select box. The problem is : When an error is thrown, the html rendered changes so the description shows up below the select box, instead of beside it. HTML rendered before error is thrown: <dd id="img-element"> <select size="5" class="image-select" id="img" name="img" style="display: none;"> ...........options.............. </select> <p class="description">Some Description</p></dd> HTML rendered after error is thrown: <dd id="img-element"> <select size="5" class="image-select" id="img" name="img" style="display: none;"> ...........options.............. </select> <ul class="errors"><li>You must select an image</li></ul> <p class="description">Some Description</p></dd> Is there a way to force the error message to be appended as the last element in the DOM tree for the dd element? Something like: <dd id="img-element"> <select size="5" class="image-select" id="img" name="img" style="display: none;"> ...........options.............. </select> <p class="description">Some Description</p> <ul class="errors"><li>You must select an image</li></ul></dd> so the 'ul' is at the end of the dd DOM tree. Thanks, I appreciate your taking the time to respond to this question!

    Read the article

  • I am trying to build a list of limitations of all graph algorithms

    - by Jack
    Single Source shortest Path Dijkstra's - directed and undirected - works only for positive edge weights - cycles ?? Bellman Ford - directed - no cycles should exist All source shortest path Floyd Warshall - no info Minimum Spanning Tree ( no info about edge weights or nature of graph or cycles) Kruskal's Prim's - undirected Baruvka's

    Read the article

  • What is the minimum interface that has the Count property in .Net

    - by SoMoS
    Hello, I need to change a method that has one parameter that takes a serie of objects. I need to find the lowest Interface (in inheritance tree) that has the Count property. Until now I was using the IEnumerable but as this has not Count I need to change it to the wider interface possible so the method can work with the biggest number of types of series (collections, lists, arrays, etc). Thanks in advance.

    Read the article

  • Mistake in the Code

    - by vibha
    myTree.on('click',function(node){ if(node.isLeaf()) { Ext.Msg.alert("You are in value ",nodeValue,"whose name is",nodeName); alert("You are in value ",nodeValue,"whose name is",nodeName); } }); myTree is a TreePanel. I'm getting a tree but click function is not working. I'm very new to extjs. Help me out. Thanks in advance

    Read the article

  • External event to Fullcalendar

    - by enfix
    I need to create a dinamic page with a Fullcalendar plugin. I want to drag event (div) to calendar from a sidebar. Any idea to do this with Fullcalendar or with other plugin ? Any example ? I found this link http://github.com/arshaw/fullcalendar/tree/fcdraggable, but don't work fine and it has some bug.

    Read the article

  • Javascript + Pretty Print JSON

    - by FlySwat
    I'm looking for a jQuery plugin or a standalone script that will take a javascript object and create a navigatable tree like the FireBug plug in does. Does this exist, or will I need to write one? Googling hasn't found much yet.

    Read the article

  • jsTree and SVG Editor conflict in active selected items?

    - by marknt15
    Hi, I'm using jsTree and SVG-Edit in the same file but there is a conflict in the active selected item. For example I clicked a tree item then I cannot draw in the svgcanvas div anymore. Maybe because of you click the item in jsTree then it's always selected and the svgcanvad div will not be active anymore? Any help, tips or tutorials will help. Thanks, Mark

    Read the article

  • Conditional action based on whether any file in a directory has a ctime newer than X

    - by jberryman
    I would like to run a backup job on a directory tree from a bash script if any of the files have been modified in the last 30 minutes. I think I can hack together something using find with the -ctime flag, but I'm sure there is a standard way to examine a directory for changes. I know that I can inspect the ctime of the top level directory to see if files were added, but I need to be able to see changes also. FWIW, I am using duplicity to backup directories to S3.

    Read the article

  • How do I switch Ruby-on-Rails into en-UK

    - by Nick Clarke
    Hi, I'm trying to switch one of my websites into en-UK so that I get the correct date and currency formats etc... I have found this yaml file: http://github.com/mattetti/globalite/blob/master/lang/rails/en-UK.yml Any ideas if there is a better one to use? I also checked here but could not see it: http://github.com/svenfuchs/rails-i18n/tree/master/rails/locale Thanks, Nick

    Read the article

  • HierarchicalDataTemplate Distinct leaves

    - by miguel
    I have a set of data that is structured like this: ItemA.GroupA ItemB.GroupA ItemC.GroupB ItemD.GroupC I need to present the data in a WPF Tree View like this: GroupA --- ItemA --- ItemB GroupB --- ItemC GroupC --- ItemD What XAML can I use to group the leaves by distinct value? For instance, there could be multple items in the collection which are GroupA.ItemA, however, I only want to present the node and leaf once.

    Read the article

  • Information Gain and Entropy

    - by dhorn
    I recently read this question regarding information gain and entropy. I think I have a semi-decent grasp on the main idea, but I'm curious as what to do with situations such as follows: If we have a bag of 7 coins, 1 of which is heavier than the others, and 1 of which is lighter than the others, and we know the heavier coin + the lighter coin is the same as 2 normal coins, what is the information gain associated with picking two random coins and weighing them against each other? Our goal here is to identify the two odd coins. I've been thinking this problem over for a while, and can't frame it correctly in a decision tree, or any other way for that matter. Any help? EDIT: I understand the formula for entropy and the formula for information gain. What I don't understand is how to frame this problem in a decision tree format. EDIT 2: Here is where I'm at so far: Assuming we pick two coins and they both end up weighing the same, we can assume our new chances of picking H+L come out to 1/5 * 1/4 = 1/20 , easy enough. Assuming we pick two coins and the left side is heavier. There are three different cases where this can occur: HM: Which gives us 1/2 chance of picking H and a 1/4 chance of picking L: 1/8 HL: 1/2 chance of picking high, 1/1 chance of picking low: 1/1 ML: 1/2 chance of picking low, 1/4 chance of picking high: 1/8 However, the odds of us picking HM are 1/7 * 5/6 which is 5/42 The odds of us picking HL are 1/7 * 1/6 which is 1/42 And the odds of us picking ML are 1/7 * 5/6 which is 5/42 If we weight the overall probabilities with these odds, we are given: (1/8) * (5/42) + (1/1) * (1/42) + (1/8) * (5/42) = 3/56. The same holds true for option B. option A = 3/56 option B = 3/56 option C = 1/20 However, option C should be weighted heavier because there is a 5/7 * 4/6 chance to pick two mediums. So I'm assuming from here I weight THOSE odds. I am pretty sure I've messed up somewhere along the way, but I think I'm on the right path! EDIT 3: More stuff. Assuming the scale is unbalanced, the odds are (10/11) that only one of the coins is the H or L coin, and (1/11) that both coins are H/L Therefore we can conclude: (10 / 11) * (1/2 * 1/5) and (1 / 11) * (1/2) EDIT 4: Going to go ahead and say that it is a total 4/42 increase.

    Read the article

< Previous Page | 88 89 90 91 92 93 94 95 96 97 98 99  | Next Page >