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  • Is .NET a write once, run anywhere (WORA) platform like Java claims to be?

    - by Scott Saad
    I remember Sun's slogan so vividly... "Write Once, Run Anywhere". The idea being that since programs are compiled into standard byte codes, any device with a Java Virtual Machine could run it. Over the years, Java seems to have made it onto many platforms/devices. Is this the intention or was it ever the intention of .NET. If so, what kind of efforts are being put forth to make this a reality?

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  • serial port in C

    - by user222820
    I have written a program in C to send a byte to serial port (com). I have used BIOSCOM to send data but I guess that it doesn't open the port. Please tell how I can open and close a com port in C. My code is here: #define COM1 1; bioscom (1 , 65 , COM1); Please help me...

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  • Objective-C Decimal to Base 16 Hex conversion

    - by JustinXXVII
    Does anyone have a code snippet or a class that will take a long long and turn it into a 16 byte Hex string? I'm looking to turn data like this long long decimalRepresentation = 1719886131591410351; and turn it into this //Base 16 Hex Output: 17DE435307A07300 The %x operator doesn't want to work for me NSLog(@"Hex: %x",decimalRepresentation); //console : "Hex: 7a072af" As you can see that's not even close. Any help is truly appreciated!

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  • Show loading image when pdf rendering

    - by Pankaj
    I am displaying pdf on my page like this <object data="/Customer/GetPricedMaterialPDF?projID=<%= ViewData["ProjectID"]%>" type="application/pdf" width="960" height="900" style="margin-top: -33px;"> <p> It appears you don't have a PDF plugin for this browser. No biggie... you can <a href="/Customer/GetPricedMaterialPDF?projID=<%= ViewData["ProjectID"]%>">click here to download the PDF file. </a> </p> </object> and Controller function are public FileStreamResult GetPricedMaterialPDF(string projID) { System.IO.Stream fileStream = GeneratePDF(projID); HttpContext.Response.AddHeader("content-disposition", "attachment; filename=form.pdf"); return new FileStreamResult(fileStream, "application/pdf"); } private System.IO.Stream GeneratePDF(string projID) { //create your pdf and put it into the stream... pdf variable below //comes from a class I use to write content to PDF files System.IO.MemoryStream ms = new System.IO.MemoryStream(); Project proj = GetProject(projID); List<File> ff = proj.GetFiles(Project_Thin.Folders.IntegrationFiles, true); string fileName = string.Empty; if (ff != null && ff.Count > 0 && ff.Where(p => p.AccessToUserID == CurrentCustomer.CustomerID).Count() > 0) { ff = ff.Where(p => p.AccessToUserID == CurrentCustomer.CustomerID).ToList(); foreach (var item in ff) { fileName = item.FileName; } byte[] bArr = new byte[] { }; bArr = GetJDLFile(fileName); ms.Write(bArr, 0, bArr.Length); ms.Position = 0; } return ms; } Now my problem is function on controller taking 10 to 20 second to process pdf, data="/Customer/GetPricedMaterialPDF?projID=<%= ViewData["ProjectID"]%>" at that time my page shows blank, which i don't want. i want to show loading image at that time. How can i do this...

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  • Is it possible to gzip and upload this string to Amazon S3 without ever being written to disk?

    - by BigJoe714
    I know this is probably possible using Streams, but I wasn't sure the correct syntax. I would like to pass a string to the Save method and have it gzip the string and upload it to Amazon S3 without ever being written to disk. The current method inefficiently reads/writes to disk in between. The S3 PutObjectRequest has a constructor with InputStream input as an option. import java.io.*; import java.util.zip.GZIPOutputStream; import com.amazonaws.auth.PropertiesCredentials; import com.amazonaws.services.s3.AmazonS3; import com.amazonaws.services.s3.AmazonS3Client; import com.amazonaws.services.s3.model.PutObjectRequest; public class FileStore { public static void Save(String data) throws IOException { File file = File.createTempFile("filemaster-", ".htm"); file.deleteOnExit(); Writer writer = new OutputStreamWriter(new FileOutputStream(file)); writer.write(data); writer.flush(); writer.close(); String zippedFilename = gzipFile(file.getAbsolutePath()); File zippedFile = new File(zippedFilename); zippedFile.deleteOnExit(); AmazonS3 s3 = new AmazonS3Client(new PropertiesCredentials( new FileInputStream("AwsCredentials.properties"))); String bucketName = "mybucket"; String key = "test/" + zippedFile.getName(); s3.putObject(new PutObjectRequest(bucketName, key, zippedFile)); } public static String gzipFile(String filename) throws IOException { try { // Create the GZIP output stream String outFilename = filename + ".gz"; GZIPOutputStream out = new GZIPOutputStream(new FileOutputStream(outFilename)); // Open the input file FileInputStream in = new FileInputStream(filename); // Transfer bytes from the input file to the GZIP output stream byte[] buf = new byte[1024]; int len; while ((len = in.read(buf)) > 0) { out.write(buf, 0, len); } in.close(); // Complete the GZIP file out.finish(); out.close(); return outFilename; } catch (IOException e) { throw e; } } }

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  • Sending an integer to COM1 using SerialPort

    - by Galwegian
    I'm having difficulty sending an integer to a serial port... I'm trying stuff like this, which run fine but I'm not picking anything up at the port. Private Sub fireToPort() Dim sPort As New SerialPort("COM1", 56000, Parity.None, 8, StopBits.One) sPort.Open() sPort.Write(New Byte() {Hex(1), 255}, 0, 0) sPort.Close() End Sub Any advice?

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  • The confusion on python encoding

    - by zhangzhong
    I retrieved the data encoded in big5 from database,and I want to send the data as email of html content, the code is like this: html += """<tr><td>""" html += """unicode(rs[0], 'big5')""" # rs[0] is data encoded in big5 I run the script, but the error raised: UnicodeDecodeError: 'ascii' codec can't decode byte...... However, I tried the code in interactive python command line, there are no errors raised, could you give me the clue?

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  • Active Directory validate service account and user accounts

    - by Padur
    Hello folks I have an issue here, I guess you all know what is AD service account and why it is used for, if not please see the below description ? SSL-Explorer requires a dedicated Active Directory account to use for authenticating AD users. This account serves as a link to your Active Directory database. If the Service Account is not found on your AD database then the SSL-Explorer service will not start. Well I have Active Directory service account details and user submitted login/password details.In the code below I validated service account by giving MEMBER_GRPUP and adminPassword and I check whether the user exists in Active Directory by submitting samaaccountname but my question here is how do I validate the password submitted for that user? I am not sure how to do this, I appreciate if anybody has any suggestions on this. Thanks for your time. public boolean validateUserFromActiveDirectory(String userId) { final String MEMBER_GROUP = "CN=asdadasd,OU=asdasdasd Accounts,OU=adasdas,OU=asdasdas,DC=asdasdas,DC=asdasdas,DC=adasdasd,DC=asdasdasd"; String employeeNumber = ""; final String LDAP_INIT_CTX = "com.sun.jndi.ldap.LdapCtxFactory"; final String LDAP_URL = "ldap://xx-ssssssss.eee.eee.eeeee.eeeee:636"; final String MY_ATTRS[] = { "employeeNumber" }; String adminPassword = "somepassword"; String securityProtocol = "ssl"; boolean isValidUser = false; try { Hashtable env = new Hashtable(); env.put(Context.INITIAL_CONTEXT_FACTORY, LDAP_INIT_CTX); env.put(Context.PROVIDER_URL, LDAP_URL); env.put(Context.SECURITY_AUTHENTICATION, "simple"); env.put(Context.REFERRAL, "follow"); env.put(Context.SECURITY_PRINCIPAL, MEMBER_GROUP); env.put(Context.SECURITY_CREDENTIALS, adminPassword); env.put(Context.SECURITY_PROTOCOL, securityProtocol); //C:\Documents and Settings\yourusername\Local Settings\Temp File tf = File.createTempFile("adentTruststore", ".jks"); tf.deleteOnExit(); byte buffer[] = new byte[0x1000]; ClassLoader cl = JNDI.class.getClassLoader(); InputStream in = cl.getResourceAsStream( "someTruststore.jks"); FileOutputStream out = new FileOutputStream(tf); int cnt; while ((cnt = in.read(buffer)) != -1) out.write(buffer, 0, cnt); in.close(); out.close(); System.setProperty("javax.net.ssl.trustStore", tf .getAbsolutePath()); DirContext context = new InitialLdapContext(env, null); SearchControls searchControls = new SearchControls(); searchControls.setSearchScope(SearchControls.SUBTREE_SCOPE); NamingEnumeration results = context.search( "XX=ent,XX=abc,XX=aaaaa,XX=aaaa", "(sAMAccountName=" + userId + ")", searchControls); if (results != null && results.hasMore()) { //some logic } } } catch (Exception e) { e.printStackTrace(); } return isValidUser; }

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  • Processing image data in java me

    - by Trimack
    Hi, I want to process raw data from a picture taken in java me with byte[] snap = videoControl.getSnapshot(encoding); My question is, whether I should try working already with snap or should I first create the image from this array Image im = Image.createImage(snap, 0, snap.length); and then work with that? Or is there some better documentation of both methods, i.e. getSnapshot and createImage than the Java API reference?

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  • TCP/UDP and ethernet MTU Fragmentation

    - by Fantastic Fourier
    I've read various sites and tutorials online but I am still confused. If the message is bigger than IP MTU, then send() returns the byte sent. What happens to the rest of the message? Am I to call send() again and attempt to send rest of the message? Or is that something IP layer should take care of automatically?

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  • Running Network Application on port Server side give me error how can i solve it?

    - by Phsika
    if i run Server App. Exception occurs: on Dinle.Start() System.Net.SocketException - Only one usage of each socket address (protocol/network address/port) is normally permitted How can i solve this error? Server.cs using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Windows.Forms; using System.IO; using System.Net; using System.Net.Sockets; using System.Threading; namespace Server { public partial class Server : Form { Thread kanal; public Server() { InitializeComponent(); try { kanal = new Thread(new ThreadStart(Dinle)); kanal.Start(); kanal.Priority = ThreadPriority.Normal; this.Text = "Kanla Çalisti"; } catch (Exception ex) { this.Text = "kanal çalismadi"; MessageBox.Show("hata:" + ex.ToString()); kanal.Abort(); throw; } } private void Server_Load(object sender, EventArgs e) { Dinle(); } private void btn_Listen_Click(object sender, EventArgs e) { Dinle(); } void Dinle() { // IPAddress localAddr = IPAddress.Parse("localhost"); // TcpListener server = new TcpListener(port); // server = new TcpListener(localAddr, port); //TcpListener Dinle = new TcpListener(localAddr,51124); TcpListener Dinle = new TcpListener(51124); try { while (true) { Dinle.Start(); Exception is occured. Socket Baglanti = Dinle.AcceptSocket(); if (!Baglanti.Connected) { MessageBox.Show("Baglanti Yok"); } else { TcpClient tcpClient = Dinle.AcceptTcpClient(); if (tcpClient.ReceiveBufferSize 0) { byte[] Dizi = new byte[250000]; Baglanti.Receive(Dizi, Dizi.Length, 0); string Yol; saveFileDialog1.Title = "Dosyayi kaydet"; saveFileDialog1.ShowDialog(); Yol = saveFileDialog1.FileName; FileStream Dosya = new FileStream(Yol, FileMode.Create); Dosya.Write(Dizi, 0, Dizi.Length - 20); Dosya.Close(); listBox1.Items.Add("dosya indirildi"); listBox1.Items.Add("Dosya Boyutu=" + Dizi.Length.ToString()); listBox1.Items.Add("Indirilme Tarihi=" + DateTime.Now); listBox1.Items.Add("--------------------------------"); } } } } catch (Exception ex) { MessageBox.Show("hata:" + ex.ToString()); } } } }

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  • Is there any sence in performing binary AND with a number where all bits are set to 1

    - by n535
    Greetings everybody. I have seen examples of such operations for so many times that i began to think that i am getting something wrong with binary arithmetics. Is there any sense to perform the following: byte value = someAnotherByteValue & 0xFF; I don't really understand this, because it does not change anything anyway. Thanks for help. P.S. I was trying to search for information both elsewhere and here, but unsuccessfully.

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  • downloaded zip file returns zero has 0 bytes as size

    - by Yaw Reuben
    I have written a Java web application that allows a user to download files from a server. These files are quite large and so are zipped together before download. It works like this: 1. The user gets a list of files that match his/her criteria 2. If the user likes a file and wants to download he/she selects it by checking a checkbox 3. The user then clicks "download" 4. The files are then zipped and stored on a server 5. The user this then presented with a page which contains a link to the downloadable zip file 6. However on downloading the zip file the file that is downloaded is 0 bytes in size I have checked the remote server and the zip file is being created properly, all that is left is to serve the file the user somehow, can you see where I might be going wrong, or suggest a better way to serve the zip file. The code that creates the link is: <% String zipFileURL = (String) request.getAttribute("zipFileURL"); %> <p><a href="<% out.print(zipFileURL); %> ">Zip File Link</a></p> The code that creates the zipFileURL variable is: public static String zipFiles(ArrayList<String> fileList, String contextRootPath) { //time-stamping Date date = new Date(); Timestamp timeStamp = new Timestamp(date.getTime()); Iterator fileListIterator = fileList.iterator(); String zipFileURL = ""; try { String ZIP_LOC = contextRootPath + "WEB-INF" + SEP + "TempZipFiles" + SEP; BufferedInputStream origin = null; zipFileURL = ZIP_LOC + "FITS." + timeStamp.toString().replaceAll(":", ".").replaceAll(" ", ".") + ".zip"; FileOutputStream dest = new FileOutputStream(ZIP_LOC + "FITS." + timeStamp.toString().replaceAll(":", ".").replaceAll(" ", ".") + ".zip"); ZipOutputStream out = new ZipOutputStream(new BufferedOutputStream( dest)); // out.setMethod(ZipOutputStream.DEFLATED); byte data[] = new byte[BUFFER]; while(fileListIterator.hasNext()) { String fileName = (String) fileListIterator.next(); System.out.println("Adding: " + fileName); FileInputStream fi = new FileInputStream(fileName); origin = new BufferedInputStream(fi, BUFFER); ZipEntry entry = new ZipEntry(fileName); out.putNextEntry(entry); int count; while ((count = origin.read(data, 0, BUFFER)) != -1) { out.write(data, 0, count); } origin.close(); } out.close(); } catch (Exception e) { e.printStackTrace(); } return zipFileURL; }

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  • " addressof " VB6 to VB.NET

    - by johan
    Hello, I´m having some problem to convert my VB6 project to VB.NET I dont understan how this "addressof" function should be in VB.NET My VB6 code: Declare Function MP4_ClientStart Lib "hikclient.dll" (pClientinfo As CLIENT_VIDEOINFO, ByVal abab As Long) As Long Public Sub ReadDataCallBack(ByVal nPort As Long, pPacketBuffer As Byte, ByVal nPacketSize As Long) If Not bSaved_DVS Then bSaved_DVS = True HW_OpenStream hChannelHandle, pPacketBuffer, nPacketSize End If HW_InputData hChannelHandle, pPacketBuffer, nPacketSize End Sub nn1 = MP4_ClientStart(clientinfo, AddressOf ReadDataCallBack)

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  • Java HTTP Request Occasionally Hangs

    - by behrk2
    Hello Everyone, For the majority of the time, my HTTP Requests work with no problem. However, occasionally they will hang. The code that I am using is set up so that if the request succeeds (with a response code of 200 or 201), then call screen.requestSucceeded(). If the request fails, then call screen.requestFailed(). When the request hangs, however, it does so before one of the above methods are called. Is there something wrong with my code? Should I be using some sort of best practice to prevent any hanging? The following is my code. I would appreciate any help. Thanks! HttpConnection connection = (HttpConnection) Connector.open(url + connectionParameters); connection.setRequestMethod(method); connection.setRequestProperty("WWW-Authenticate", "OAuth realm=api.netflix.com"); if (method.equals("POST")) { connection.setRequestProperty("Content-type", "application/x-www-form-urlencoded"); } int responseCode = connection.getResponseCode(); System.out.println("RESPONSE CODE: " + responseCode); if (connection instanceof HttpsConnection) { HttpsConnection secureConnection = (HttpsConnection) connection; String issuer = secureConnection.getSecurityInfo() .getServerCertificate().getIssuer(); UiApplication.getUiApplication().invokeLater( new DialogRunner( "Secure Connection! Certificate issued by: " + issuer)); } if (responseCode != 200 && responseCode != 201) { screen.requestFailed("Unexpected response code: " + responseCode); connection.close(); return; } String contentType = connection.getHeaderField("Content-type"); ByteArrayOutputStream baos = new ByteArrayOutputStream(); InputStream responseData = connection.openInputStream(); byte[] buffer = new byte[20000]; int bytesRead = 0; while ((bytesRead = responseData.read(buffer)) > 0) { baos.write(buffer, 0, bytesRead); } baos.close(); connection.close(); screen.requestSucceeded(baos.toByteArray(), contentType); } catch (IOException ex) { screen.requestFailed(ex.toString()); }

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  • Vaadin: Downloaded file has whole path as file name

    - by javydreamercsw
    I have a download action implemented on my Vaadin application but for some reason the downloaded file has the original file's full path as the file name. Any idea? You can see the code on this post. Edit: Here's the important part of the code: package com.bluecubs.xinco.core.server.vaadin; import com.bluecubs.xinco.core.server.XincoConfigSingletonServer; import com.vaadin.Application; import com.vaadin.terminal.DownloadStream; import com.vaadin.terminal.FileResource; import java.io.*; import java.net.URLEncoder; import java.util.UUID; import java.util.logging.Level; import java.util.logging.Logger; import java.util.zip.CRC32; import java.util.zip.CheckedInputStream; /** * * @author Javier A. Ortiz Bultrón<[email protected]> */ public class FileDownloadResource extends FileResource { private final String fileName; private File download; private File newFile; public FileDownloadResource(File sourceFile, String fileName, Application application) { super(sourceFile, application); this.fileName = fileName; } protected void cleanup() { if (newFile != null && newFile.exists()) { newFile.delete(); } if (download != null && download.exists() && download.listFiles().length == 0) { download.delete(); } } @Override public DownloadStream getStream() { try { //Copy file to directory for downloading InputStream in = new CheckedInputStream(new FileInputStream(getSourceFile()), new CRC32()); download = new File(XincoConfigSingletonServer.getInstance().FileRepositoryPath + System.getProperty("file.separator") + UUID.randomUUID().toString()); newFile = new File(download.getAbsolutePath() + System.getProperty("file.separator") + fileName); download.mkdirs(); OutputStream out = new FileOutputStream(newFile); newFile.deleteOnExit(); download.deleteOnExit(); byte[] buf = new byte[1024]; int len; while ((len = in.read(buf)) > 0) { out.write(buf, 0, len); } in.close(); out.close(); final DownloadStream ds = new DownloadStream( new FileInputStream(newFile), getMIMEType(), fileName); ds.setParameter("Content-Disposition", "attachment; filename=" + URLEncoder.encode(fileName, "utf-8")); ds.setCacheTime(getCacheTime()); return ds; } catch (final FileNotFoundException ex) { Logger.getLogger(FileDownloadResource.class.getName()).log(Level.SEVERE, null, ex); return null; } catch (IOException ex) { Logger.getLogger(FileDownloadResource.class.getName()).log(Level.SEVERE, null, ex); return null; } } } I already debugged and verified that fileName only contains the file's name not the whole path.

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  • Java: Detecting image format, resize (scale) and save as JPEG

    - by BoDiE2003
    This is the code I have, it actually works, not perfectly but it does, the problem is that the resized thumbnails are not pasting on the white Drawn rectangle, breaking the images aspect ratio, here is the code, could someone suggest me a fix for it, please? Thank you import java.awt.Color; import java.awt.Graphics2D; import java.awt.Image; import java.awt.RenderingHints; import java.awt.geom.Rectangle2D; import java.awt.image.BufferedImage; import java.io.BufferedInputStream; import java.io.ByteArrayInputStream; import java.io.ByteArrayOutputStream; import java.io.IOException; import java.io.InputStream; import javax.imageio.ImageIO; import org.apache.commons.logging.Log; import org.apache.commons.logging.LogFactory; public class ImageScalerImageIoImpl implements ImageScaler { private static final String OUTPUT_FORMAT_ID = "jpeg"; // Re-scaling image public byte[] scaleImage(byte[] originalImage, int targetWidth, int targetHeight) { try { InputStream imageStream = new BufferedInputStream( new ByteArrayInputStream(originalImage)); Image image = (Image) ImageIO.read(imageStream); int thumbWidth = targetWidth; int thumbHeight = targetHeight; // Make sure the aspect ratio is maintained, so the image is not skewed double thumbRatio = (double)thumbWidth / (double)thumbHeight; int imageWidth = image.getWidth(null); int imageHeight = image.getHeight(null); double imageRatio = (double)imageWidth / (double)imageHeight; if (thumbRatio < imageRatio) { thumbHeight = (int)(thumbWidth / imageRatio); } else { thumbWidth = (int)(thumbHeight * imageRatio); } // Draw the scaled image BufferedImage thumbImage = new BufferedImage(thumbWidth, thumbHeight, BufferedImage.TYPE_INT_RGB); System.out.println("Thumb width Buffered: " + thumbWidth + " || Thumb height Buffered: " + thumbHeight); Graphics2D graphics2D = thumbImage.createGraphics(); // Use of BILNEAR filtering to enable smooth scaling graphics2D.setRenderingHint(RenderingHints.KEY_INTERPOLATION, RenderingHints.VALUE_INTERPOLATION_BILINEAR); // graphics2D.drawImage(image, 0, 0, thumbWidth, thumbHeight, null); // White Background graphics2D.setPaint(Color.WHITE); graphics2D.fill(new Rectangle2D.Double(0, 0, targetWidth, targetHeight)); graphics2D.fillRect(0, 0, targetWidth, targetHeight); System.out.println("Target width: " + targetWidth + " || Target height: " + targetHeight); // insert the resized thumbnail between X and Y of the image graphics2D.drawImage(image, 0, 0, thumbWidth, thumbHeight, null); System.out.println("Thumb width: " + thumbWidth + " || Thumb height: " + thumbHeight); // Write the scaled image to the outputstream ByteArrayOutputStream out = new ByteArrayOutputStream(); ImageIO.write(thumbImage, OUTPUT_FORMAT_ID, out); return out.toByteArray(); } catch (IOException ioe) { throw new ImageResizingException(ioe); } } }

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  • access elements of a void *?

    - by user146780
    I have a void pointer and want to access elements from it. How could I transform a void * into an unsigned byte pointer so I can access its elements (which I know are actually unsigned bytes). Thanks Using C++

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  • Android - OPENGL cube is NOT in the display

    - by Marc Ortiz
    I'm trying to display a square on my display and i can't. Whats my problem? How can I display it on the screen (center of the screen)? I let my code below! Here's my render class: public class GLRenderEx implements Renderer { private GLCube cube; Context c; GLCube quad; // ( NEW ) // Constructor public GLRenderEx(Context context) { // Set up the data-array buffers for these shapes ( NEW ) quad = new GLCube(); // ( NEW ) } // Call back when the surface is first created or re-created. @Override public void onSurfaceCreated(GL10 gl, EGLConfig config) { // NO CHANGE - SKIP } // Call back after onSurfaceCreated() or whenever the window's size changes. @Override public void onSurfaceChanged(GL10 gl, int width, int height) { // NO CHANGE - SKIP } // Call back to draw the current frame. @Override public void onDrawFrame(GL10 gl) { // Clear color and depth buffers using clear-values set earlier gl.glClear(GL10.GL_COLOR_BUFFER_BIT | GL10.GL_DEPTH_BUFFER_BIT); gl.glLoadIdentity(); // Reset model-view matrix ( NEW ) gl.glTranslatef(-1.5f, 0.0f, -6.0f); // Translate left and into the // screen ( NEW ) // Translate right, relative to the previous translation ( NEW ) gl.glTranslatef(3.0f, 0.0f, 0.0f); quad.draw(gl); // Draw quad ( NEW ) } } And here is my square class: public class GLCube { private FloatBuffer vertexBuffer; // Buffer for vertex-array private float[] vertices = { // Vertices for the square -1.0f, -1.0f, 0.0f, // 0. left-bottom 1.0f, -1.0f, 0.0f, // 1. right-bottom -1.0f, 1.0f, 0.0f, // 2. left-top 1.0f, 1.0f, 0.0f // 3. right-top }; // Constructor - Setup the vertex buffer public GLCube() { // Setup vertex array buffer. Vertices in float. A float has 4 bytes ByteBuffer vbb = ByteBuffer.allocateDirect(vertices.length * 4); vbb.order(ByteOrder.nativeOrder()); // Use native byte order vertexBuffer = vbb.asFloatBuffer(); // Convert from byte to float vertexBuffer.put(vertices); // Copy data into buffer vertexBuffer.position(0); // Rewind } // Render the shape public void draw(GL10 gl) { // Enable vertex-array and define its buffer gl.glEnableClientState(GL10.GL_VERTEX_ARRAY); gl.glVertexPointer(3, GL10.GL_FLOAT, 0, vertexBuffer); // Draw the primitives from the vertex-array directly gl.glDrawArrays(GL10.GL_TRIANGLE_STRIP, 0, vertices.length / 3); gl.glDisableClientState(GL10.GL_VERTEX_ARRAY); } } Thanks!!

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  • Writing to a comet stream using tomcat 6.0

    - by user301247
    Hey I'm new to java servlets and I am trying to write one that uses comet so that I can create a long polling Ajax request. I can successfully start the stream and perform operations but I can't write anything out. Here is my code: public class CometTestServlet extends HttpServlet implements CometProcessor { /** * */ private static final long serialVersionUID = 1070949541963627977L; private MessageSender messageSender = null; protected ArrayList<HttpServletResponse> connections = new ArrayList<HttpServletResponse>(); public void event(CometEvent cometEvent) throws IOException, ServletException { HttpServletRequest request = cometEvent.getHttpServletRequest(); HttpServletResponse response = cometEvent.getHttpServletResponse(); //final PrintWriter out = response.getWriter(); if (cometEvent.getEventType() == CometEvent.EventType.BEGIN) { PrintWriter writer = response.getWriter(); writer.println("<!doctype html public \"-//w3c//dtd html 4.0 transitional//en\">"); writer.println("<head><title>JSP Chat</title></head><body bgcolor=\"#FFFFFF\">"); writer.println("</body></html>"); writer.flush(); cometEvent.setTimeout(10 * 1000); //cometEvent.close(); } else if (cometEvent.getEventType() == CometEvent.EventType.ERROR) { log("Error for session: " + request.getSession(true).getId()); synchronized(connections) { connections.remove(response); } cometEvent.close(); } else if (cometEvent.getEventType() == CometEvent.EventType.END) { log("End for session: " + request.getSession(true).getId()); synchronized(connections) { connections.remove(response); } PrintWriter writer = response.getWriter(); writer.println("</body></html>"); cometEvent.close(); } else if (cometEvent.getEventType() == CometEvent.EventType.READ) { //handleReadEvent(cometEvent); InputStream is = request.getInputStream(); byte[] buf = new byte[512]; do { int n = is.read(buf); //can throw an IOException if (n > 0) { log("Read " + n + " bytes: " + new String(buf, 0, n) + " for session: " + request.getSession(true).getId()); } else if (n < 0) { //error(cometEvent, request, response); return; } } while (is.available() > 0); } } Any help would be appreciated.

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  • Saving a bitmap to a Memorystream produces an inverted colors image

    - by Raphael
    I've created an image with GDI+ on my application and now I must convert this image to an array of bytes. My first thought was this simple code: public byte[] ToByte() { MemoryStream ms = new MemoryStream(); bitmap.Save(ms, ImageFormat.Bmp); return ms.GetBuffer(); } The problem with this approach is that when I finally save this image into a file the colors are inverted. What I'm I doing wrong?

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