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  • Building ASP.NET Web Forms to Use a MySQL Database

    The MySQL database is the best open source database which means it can be used for free without obtaining or paying for a license. In ASP.NET 3.5 hosting there are some hosting packages that let you use the MySQL database because it can be a cheaper hosting alternative when compared to using the MS SQL database. However things can be a bit complicated when querying a MySQL database in an ASP.NET environment.... Advance Your IT Career Online IT Degree Programs. Advance Your IT Career While You Work. Search now.

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  • Eliminating Downtime During Database Upgrades: A Customer Case Study

    - by irem.radzik(at)oracle.com
    Planned outages, such as database, OS, hardware upgrades and migrations, are a fact of life. Even though they are "planned" and many of them are performed during "off business hours", they can still interrupt operations-- especially for global operations and online businesses. For this reason many IT organizations postpone these critical infrastructure improvement projects, which in turn result in delays in advancing business operations. This week, on Thursday January 13th, we will host a free webcast on this topic, and will feature Oracle GoldenGate's customer Atmos Energy. Atmos Energy implemented Oracle GoldenGate for eliminating downtime during their database upgrade from Oracle Database 8.1.7 to Oracle Database 11.1.0.7. Jos Francis, Lead DBA for Atmos, and Ronald Nedd, Sr. DBA for Atmos, will be presenting their database upgrade project and their solution architecture. Join us at this live webcast and hear from our customer and product management how to eliminate planned outages with Oracle GoldenGate's real-time, heterogeneous data replication capabilities.

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  • Webcast Series: Accelerate Business-Critical Database Deployments with Oracle Optimized Solutions

    - by ferhat
    Join us for this two-part Webcast series and learn how to safely consolidate business-critical databases and deliver quantifiable benefits to the business: Save up to 75% in operational and acquisition costs Save millions of dollars consolidating legacy infrastructure Leverage best practices from thousands of customer environments Increase end user productivity with 75% faster time to operations and 4x faster throughput   The Oracle Optimized Solution for Oracle Database  provides extensive guidelines for architecting and deploying complete database solutions that deliver superior performance and availability while minimizing cost and risk. Oracle’s world-class engineering teams work together to define these optimal architectures using Oracle's powerful SPARC M-Series and SPARC T-Series servers together with Oracle Solaris and Oracle's SAN, NAS, and flash-based storage to run the industry-leading Oracle Database. Quite simply, the Oracle Optimized Solution for Oracle Database makes it easier for you to deliver and manage business critical database environments that are fast, secure and cost-effective. Available On-Demand PART 1: Why Architecture Matters When Deploying Business-Critical Databases PART 2: How To Consolidate Databases Using Oracle Optimized Solutions   Presented by: Lawrence McIntosh, Principal Enterprise Architect, Oracle Optimized Solutions Ken Kutzer, Principal Product Manager, Infrastructure Solutions, Oracle  

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  • Should custom data elements be stored as XML or database entries?

    - by meteorainer
    There are a ton of questions like this, but they are mostly very generalized, so I'd like to get some views on my specific usage. General: I'm building a new project on my own in Django. It's focus will be on small businesses. I'd like to make it somewhat customizble for my clients so they can add to their customer/invoice/employee/whatever items. My models would reflect boilerplate items that all ModelX might have. For example: first name last name email address ... Then my user's would be able to add fields for whatever data they might like. I'm still in design phase and am building this myself, so I've got some options. Working on... Right now the 'extra items' models have a FK to the generic model (Customer and CustomerDataPoints for example). All values in the extra data points are stored as char and will be coerced/parced into their actual format at view building. In this build the user could theoretically add whatever values they want, group them in sets and generally access them at will from the views relavent to that model. Pros: Low storage overhead, very extensible, searchable Cons: More sql joins My other option is to use some type of markup, or key-value pairing stored directly onto the boilerplate models. This coul essentially just be any low-overhead method weather XML or literal strings. The view and form generated from the stored data would be taking control of validation and reoganizing on updates. Then it would just dump the data back in as a char/blob/whatever. Something like: <datapoint type='char' value='something' required='true' /> <datapoint type='date' value='01/01/2001' required='false' /> ... Pros: No joins needed, Updates for validation and views are decoupled from data Cons: Much higher storage overhead, limited capacity to search on extra content So my question is: If you didn't live in the contraints impose by your company what method would you use? Why? What benefits or pitfalls do you see down the road for me as a small business trying to help other small businesses? Just to clarify, I am not asking about custom UI elements, those I can handle with forms and template snippets. I'm asking primarily about data storage and retreival of non standardized data relative to a boilerplate model.

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  • I want a trivial example of where MongoDB can scale but a relational database will have trouble

    - by Ryan Weir
    I'm just learning to use MongoDB, and when discussing with other programmers would like a quick example of why NoSQL can be a good choice compared to a traditional RDBMS - however the scenarios I come up with and can find online seem pretty contrived. E.g. a blog with lots of traffic could be represented relationally, but will require some performance tuning and joins across tables (assuming full denormalization is being used). Whereas MongoDB would allow direct retrieval from one collection to the same effect. But the response I'm getting from other programmers is "why not just keep it relational and then add some trivial caching later?" Does anybody have a less contrived example where MongoDB will really shine and a relational db will fall over much quicker? The smaller the project/system the better, because it leaves less room for disagreement. Something along the lines of the complexity of the blog example would be really useful. Thanks.

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  • SQL Server architecture - they want to move my database to new instance...Why?

    - by O'MALLEY
    Our current production database environment contains about 10 similarily managed databases. Our agency has just purchased and is installing new blade chasses and wants to move my database to a new instance (leaving the other 9 on another). This decision is being driven by one of our IT staff, not a DBA. I am a project manager, not a DBA but I know enough to not necesarrily have a good feeling about this decision and I am urging our IT department to make a sound decision based on what is best for the database. Our IT department has stated that it is not good to have all our eggs in one basket, and has also stated that my database contains "regulatory data" so it should be on its own instance. A couple of truths: - None of the databases on the current instance are OLTP databases nor are any of them data warehouses - My database currently has joins/views to a couple of the other databases in the production environment So my questions are as follows: Am I wrong to disregard a statement about eggs in baskets? (hello, this is why we have maintenance plans/disaster recovery plans). I'll mention that other databases also have regulatory data too. What types of questions do I need to ask to determine if this is a sound decicion? (A DBA friend mentioned that if the service level agreement of said database does not radically differ from the others then why do they want to do this?) I have done some research on linked servers. What arguments should I bring forth about the fact that I have views setup that rely on data from other DBs currently?

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  • Oracle Database 12c

    - by David Allan
    Exciting day today as Oracle Database 12c is released. You can find lots of information on the release on OTN here. With this release comes another milestone on Oracle's Data Integration roadmap - OWB is no longer shipped with the database. You will notice that the OWB documentation is no longer included with the Oracle Database documentation, you can compare and contrast the 11.2 and 12.1 documentation below. OWB 11gR2 is still supported with Oracle Database 12c, you will need 11.2.0.3 plus at least CP2 which has been certified with Oracle Database 12c. The 11.2.0.4 release will wrapper this into one install.

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  • If all variables are a subset of the superkey, is the database design 5NF? [migrated]

    - by Lukazoid
    I have a table called LogMessages, which has the following columns: Level A numeric value which represents Trace, Debug, Info, Warning, Error or Fatal Time A UTC time Message Foreign key to a Messages table Source Foreign key to a Sources table User Foreign key to a Users table From what I can see, all of these columns are a part of the super key; if any single value differs to an existing row, a new row can be created. My question is, does this design comply to fifth normal form? I am unsure as some groups of data will be repeating, however I don't believe this violates 5NF? (correct me if I'm wrong)

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  • What is the best database design for managing historical information? [closed]

    - by Emmad Kareem
    Say you have a Person table with columns such as: ID, FirstName, LastName, BirthCountry, ...etc. And you want to keep track of changes on such a table. For example, the user may want to see previous names of a person or previous addresses, etc. The normalized way is to keep names in separate table, addresses in a separate table,...etc. and the main person table will contain only the information that you are not interested in monitoring changes for (such information will be updated in place). The problem I see here, aside form the coding hassle due to the extensive number of joins required in a real-life situation, is that I have never seen this type of design in any real application (maybe because most did not provide this feature!). So, is there a better way to design this? Thanks.

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  • WP: Oracle Multitenant on SuperCluster T5-8: Study of Database Consolidation Efficiency

    - by uwes
    Consolidation in the data center is the driving factor in reducing capital and operational expense in IT today. This is particularly relevant as customers invest more in cloud infrastructure and associated service delivery. Database consolidation is a strategic component in this effort. Oracle Database 12 c introduces Oracle Multitenant , a new database consolidation model in which multiple Pluggable Databases (PDBs) are consolidated within a Container Database (CDB). While keeping many of the isolation aspects of single databases, it allows PDBs to share the system global area (SGA) and background processes of a common CDB . The white paper recently published on OTN: Oracle Multitenant on SuperCluster T5-8: Study of Database Consolidation Efficiency analyzes and quantifies savings in compute resources, efficiencies in transaction processing, and consolidation density of Oracle Multitenant compared to consolidated single instance databases (SIDBs) running in a bare-metal environment.

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  • How to deploy ASP.NET application with MS SQL server database

    - by Maddy
    I want to deploy my website with MS SQL server database. It's my first time and I have never done it before. What I have come to know from my googling is that I must have a domain(.com/.net/.co) and a host(for my web pages .aspx & .cs(confusion here if I can also deploy my database)). Now, I am not getting to where I have to deploy my database. If I also have to buy a seperate SQL Server database or a host consisting of every thing (means I can deploy both my ASP.NET application & database as well).

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  • How would one build a relational database on a key-value store, a-la Berkeley DB's SQL interface?

    - by coleifer
    I've been checking out Berkeley DB and was impressed to find that it supported a SQL interface that is "nearly identical" to SQLite. http://docs.oracle.com/cd/E17076_02/html/bdb-sql/dbsqlbasics.html#identicalusage I'm very curious, at a high-level, how this kind of interface might have been architected. For instance: since values are "transparent", how do you efficiently query and sort by value how are limits and offsets performed efficiently on large result sets how would the keys be structured and serialized for good average-case performance

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  • Is there other ways to do insert/update/delete on a remote oracle database?

    - by gunbuster363
    I asked a question recently concerning the speed of execution of insert/update/delete using JDBC driver in a remote machine, but the problem cannot be solved easily. I would like to ask, is there any other way to execute the insert/update/delete to the oracle? The current situation is this: the DB is on a seperate machine than the java program used to update the DB. I looked up the internet and found people suggesting using pure sql or pl/sql to do the update, is that possible? And do we need to operate the sql or pl/sql in a local machine? Because I have no knowledge about pl/sql, so I am not sure if we can create some kind of script and call it on a remote machine. Let say the situation is like this: the input data is on machine A, and the original java program are also on machine A, but the oracle is on machine B. is there any other approach other than JDBC?

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  • why my code still cannot connect with database? [closed]

    - by Wen Teng
    package com.mems.travis; import java.util.ArrayList; import java.util.List; import org.apache.http.NameValuePair; import org.apache.http.message.BasicNameValuePair; import org.json.JSONObject; import android.app.Activity; import android.app.AlertDialog; import android.content.DialogInterface; import android.content.Intent; import android.os.AsyncTask; import android.os.Bundle; import android.util.Log; import android.view.View; import android.widget.Button; import android.widget.EditText; import android.widget.RadioButton; public class UserRegister extends Activity { JSONParser jsonParser = new JSONParser(); EditText inputName; EditText inputUsername; EditText inputEmail; EditText inputPassword; RadioButton button1; RadioButton button2; Button button3; int success = 0; // url to create new product private static String url_register_user = "http://192.168.1.100/MEMS/add_user.php"; // JSON Node names private static final String TAG_SUCCESS = "success"; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_user_register); // Edit Text inputName = (EditText) findViewById(R.id.nameTextBox); inputUsername = (EditText) findViewById(R.id.usernameTextBox); inputEmail = (EditText) findViewById(R.id.emailTextBox); inputPassword = (EditText) findViewById(R.id.pwTextBox); // Create button //RadioButton button1 = (RadioButton) findViewById(R.id.studButton); // RadioButton button2 = (RadioButton) findViewById(R.id.shopownerButton); Button button3 = (Button) findViewById(R.id.regSubmitButton); // button click event button3.setOnClickListener(new View.OnClickListener() { public void onClick(View view) { String name = inputName.getText().toString(); String username = inputUsername.getText().toString(); String email = inputEmail.getText().toString(); String password = inputPassword.getText().toString(); if (name.contentEquals("")||username.contentEquals("")||email.contentEquals("")||password.contentEquals("")) { AlertDialog.Builder builder = new AlertDialog.Builder(UserRegister.this); // 2. Chain together various setter methods to set the dialog characteristics builder.setMessage(R.string.nullAlert) .setTitle(R.string.alertTitle); builder.setPositiveButton(R.string.ok, new DialogInterface.OnClickListener() { public void onClick(DialogInterface dialog, int id) { // User clicked OK button } }); // 3. Get the AlertDialog from create() AlertDialog dialog = builder.show(); } else { new RegisterNewUser().execute(); } } }); } class RegisterNewUser extends AsyncTask<String, String, String>{ protected String doInBackground(String... args) { String name = inputName.getText().toString(); String username = inputUsername.getText().toString(); String email = inputEmail.getText().toString(); String password = inputPassword.getText().toString(); // Building Parameters List<NameValuePair> params = new ArrayList<NameValuePair>(); params.add(new BasicNameValuePair("name", name)); params.add(new BasicNameValuePair("username", username)); params.add(new BasicNameValuePair("email", email)); params.add(new BasicNameValuePair("password", password)); // getting JSON Object // Note that create product url accepts POST method JSONObject json = jsonParser.makeHttpRequest(url_register_user, "GET", params); // check log cat for response Log.d("Send Notification", json.toString()); try { int success = json.getInt(TAG_SUCCESS); if (success == 1) { // successfully created product Intent i = new Intent(getApplicationContext(), StudentLogin.class); startActivity(i); finish(); } else { // failed to register } } catch (Exception e) { e.printStackTrace(); } return null; } } }

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  • when should a database table be broken into multiple tables with relations?

    - by GSto
    I have an application that needs to store client data, and part of that is some data about their employer as well. Assuming that a client can only have one employer, and that the chance of people having identical employer data is slim to none, which schema would make more sense to use? Schema 1 Client Table: ------------------- id int name varchar(255), email varchar(255), address varchar(255), city varchar(255), state char(2), zip varchar(16), employer_name varchar(255), employer_phone varchar(255), employer_address varchar(255), employer_city varchar(255), employer_state char(2), employer_zip varchar(16) **Schema 2** Client Table ------------------ id int name varchar(255), email varchar(255), address varchar(255), city varchar(255), state char(2), zip varchar(16), Employer Table --------------------- id int name varchar(255), phone varchar(255), address varchar(255), city varchar(255), state char(2), zip varchar(16) patient_id int Part of me thinks that since are clearly two different 'objects' in the real world, seperating them out into two different tables makes sense. However, since a client will always have an employer, I'm also not seeing any real benefits to seperating them out, and it would make querying data about clients more complex. Is there any benefit / reason for creating two tables in a situation like this one instead of one?

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  • ?Oracle DB 11gR2 ??????????????????????????????????????!

    - by Yuichi.Hayashi
    ??????????????????????????????????????????????????????????????(????????)?????????????????????????? ?????????????????????????????????? ???????????????????????????????????????????·????????????????????????????????????????????Oracle Database????????????????????????????????????????????????????????????????????????????? Oracle Database?????????????????????????????????????????????????????????(????????)??????????????????????????????????? Oracle Database ??????????? Oracle Database???????????????????????? ??????????!!?????? ?Oracle Database???? ????Oracle Database???????11gR2???????????????????????????????????????????????????????????????????????!?????????????????????????! ??????????? Oracle??????????????????????????????????????????????????????????????????????????CPU?????????????????????????????????????????/????????????????????????? ?????????????????????Oracle Database???????????????????????????????????????????????????????????????? ????????????????? ??????????????????????????????????????????????????? ????11g R2?????????????????????DBMS_AUDIT_MGMT???????????????????????11g R1(11.1.0.7)???????????????????????????????????Oracle Audit Vault?????????????????????11g R2????????????????????????????????????????????? ??????????????????????????????????????????????????????????????????????????????????????????????????·????????????????????????????????????????????????????????! ????????/??/??/??????/???????????????????Oracle Audit Vault??????????????????? ?????????? ? ??????????????????????????????????!? ? ???????????????/????????????????!?

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  • Problem while inserting data from GUI layer to database

    - by Rahul
    Hi all, I am facing problem while i am inserting new record from GUI part to database table. I have created database table Patient with id, name, age etc....id is identity primary key. My problem is while i am inserting duplicate name in table the control should go to else part, and display the message like...This name is already exits, pls try with another name... but in my coding not getting..... Here is all the code...pls somebody point me out whats wrong or how do this??? GUILayer: protected void BtnSubmit_Click(object sender, EventArgs e) { if (!Page.IsValid) return; int intResult = 0; string name = TxtName.Text.Trim(); int age = Convert.ToInt32(TxtAge.Text); string gender; if (RadioButtonMale.Checked) { gender = RadioButtonMale.Text; } else { gender = RadioButtonFemale.Text; } string city = DropDownListCity.SelectedItem.Value; string typeofdisease = ""; foreach (ListItem li in CheckBoxListDisease.Items) { if (li.Selected) { typeofdisease += li.Value; } } typeofdisease = typeofdisease.TrimEnd(); PatientBAL PB = new PatientBAL(); PatientProperty obj = new PatientProperty(); obj.Name = name; obj.Age = age; obj.Gender = gender; obj.City = city; obj.TypeOFDisease = typeofdisease; try { intResult = PB.ADDPatient(obj); if (intResult > 0) { lblMessage.Text = "New record inserted successfully."; TxtName.Text = string.Empty; TxtAge.Text = string.Empty; RadioButtonMale.Enabled = false; RadioButtonFemale.Enabled = false; DropDownListCity.SelectedIndex = 0; CheckBoxListDisease.SelectedIndex = 0; } else { lblMessage.Text = "Name [<b>" + TxtName.Text + "</b>] alredy exists, try another name"; } } catch (Exception ex) { lblMessage.Text = ex.Message.ToString(); } finally { obj = null; PB = null; } } BAL layer: public class PatientBAL { public int ADDPatient(PatientProperty obj) { PatientDAL pdl = new PatientDAL(); try { return pdl.InsertData(obj); } catch { throw; } finally { pdl=null; } } } DAL layer: public class PatientDAL { public string ConString = ConfigurationManager.ConnectionStrings["ConString"].ConnectionString; public int InsertData(PatientProperty obj) { SqlConnection con = new SqlConnection(ConString); con.Open(); SqlCommand com = new SqlCommand("LoadData",con); com.CommandType = CommandType.StoredProcedure; try { com.Parameters.AddWithValue("@Name", obj.Name); com.Parameters.AddWithValue("@Age",obj.Age); com.Parameters.AddWithValue("@Gender",obj.Gender); com.Parameters.AddWithValue("@City", obj.City); com.Parameters.AddWithValue("@TypeOfDisease", obj.TypeOFDisease); return com.ExecuteNonQuery(); } catch { throw; } finally { com.Dispose(); con.Close(); } } } Property Class: public class PatientProperty { private string name; private int age; private string gender; private string city; private string typedisease; public string Name { get { return name; } set { name = value; } } public int Age { get { return age; } set { age = value; } } public string Gender { get { return gender; } set { gender = value; } } public string City { get { return city; } set { city = value; } } public string TypeOFDisease { get { return typedisease; } set { typedisease = value; } } } This is my stored Procedure: CREATE PROCEDURE LoadData ( @Name varchar(50), @Age int, @Gender char(10), @City char(10), @TypeofDisease varchar(50) ) as insert into Patient(Name, Age, Gender, City, TypeOfDisease)values(@Name,@Age, @Gender, @City, @TypeofDisease) GO

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  • Hibernate won't save into database

    - by Blitzkr1eg
    I mapped some classes to some tables with hibernate in java, i set hibernate to show SQL, it opens the session, it show that id does the SQL, it closes the session but there are no modifications to the database. Entity public class Profesor implements Comparable<Profesor> { private int id; private String nume; private String prenume; private int departament_id; private Set<Disciplina> listaDiscipline; //the teacher gives some courses} public class Disciplina implements Comparable<Disciplina>{ //the course class private int id; private String denumire; private String syllabus; private String schNotare; private Set<Lectie> lectii; private Set<Tema> listaTeme; private Set<Grup> listaGrupuri; // the course gets teached/assigmened to some groups of students private Set<Assignment> listAssignments;} Mapping <hibernate-mapping default-cascade="all"> <class name="model.Profesor" table="devgar_scoala.profesori"> <id name="id" column="id"> <generator class="increment"/> </id> <set name="listaDiscipline" table="devgar_scoala.`profesori-discipline`"> <key column="Profesori_id" /> <many-to-many class="model.Disciplina" column="Discipline_id" /> </set> <property name="nume" column="Nume" type="string" /> <property name="prenume" column="Prenume" type="string" /> <property name="departament_id" column="Departamente_id" type="integer" /> </class> <class name="model.Grup" table="devgar_scoala.grupe"> <id name="id" unsaved-value="0"> <generator class="increment"/> </id> <set name="listaStudenti" table="devgar_scoala.`studenti-grupe`"> <key column="Grupe_id" /> <many-to-many column="Studenti_nrMatricol" class="model.Student" /> </set> <property name="nume" column="Grupa" type="string"/> <property name="programStudiu" column="progStudii_id" type="integer" /> </class> <class name="model.Disciplina" table="devgar_scoala.discipline" > <id name="id" > <generator class="increment"/> </id> <property name="denumire" column="Denumire" type="string"/> <property name="syllabus" type="string" column="Syllabus"/> <property name="schNotare" type="string" column="SchemaNotare"/> <set name="listaGrupuri" table="devgar_scoala.`Discipline-Grupe`"> <key column="Discipline_id" /> <many-to-many column="Grupe_id" class="model.Grup" /> </set> <set name="lectii" table="devgar_scoala.lectii"> <key column="Discipline_id" not-null="true"/> <one-to-many class="model.Lectie" /> </set> </class> The only 'funny' thing is that the Profesor object gets loaded not with/by Hibernate but with manual classic SQL Java. Thats why i save the Profesor object like this p - the manually loaded Profesor object Profesor p2 = (Profesor) session.merge(p); session.saveOrUpdate(p2); //flush session of course After this i get in the Java console: Hibernate: insert into devgar_scoala.grupe (Grupa, progStudii_id, id) values (?, ?, ?) but when i look into the database there are no new rows in the table Grupe (the Groups table)

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  • Lost Permission on Files using wrong chmod syntax Centos 5.5

    - by alloutfallout
    Hello, I was trying to remove write permissions on an entire directory, and I used the incorrect command: chmod 644 -r sites/default I meant to type chmod -R 644 sites/default The result was this: chmod: cannot access `644': No such file or directory $ ls -als sites total 24 4 drwxr-xr-x 5 user group 4096 Jan 11 10:54 . 4 drwxrwxr-x 14 user group 4096 Jan 11 10:11 .. 4 drwxr-xr-x 4 user group 4096 Jan 5 01:25 all 4 d-w------- 3 user group 4096 Jan 11 10:43 default 4 -rw-r--r-- 1 user group 1849 Apr 15 2010 example.sites.php I fixed the permissions on the default folder with $ chmod 644 sites/default But, the following ls shows a all the files with red backgrounds and question marks. I can't access any files unless I am root. $ ls -als sites/default total 0 ? ?--------- ? ? ? ? ? . ? ?--------- ? ? ? ? ? .. ? ?--------- ? ? ? ? ? default.settings.php ? ?--------- ? ? ? ? ? files ? ?--------- ? ? ? ? ? settings.php When I log in as root, I can edit all of the files, and their permissions appear correctly. I do not know how to undo the damage caused by using -r with chmod instead of -R. Any Suggestions?

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  • Samba4/Ubuntu Shares Incorrectly Available to All Users

    - by Dan
    I've got my Ubuntu server working with Samba4 and got it set up as the Primary domain controller on my network with AD and all that goodness. However, I'm trying to get my Samba configuration to work with the users and groups I've defined with the Active Directory tools from Windows. For instance, I've got a share X which I want users A and B (as part of the 'management' group, known as LLGrpManager in my setup) to see, but no body else. However, after making changes to the configuration, restarting Samba, I test by connecting to the share with my Mac over Samba as user 'C' which isn't part of the management group, and I can, incorrectly, see the X share. I've tried alsorts of combinations of specifying the group with no luck at all. I've got a feeling that my global config might be too lenient or something to do with file permissions but being a bit green, I'm without clue. My /etc/samba/smb.conf # Global parameters [global] server role = domain controller server string = Office Server workgroup = LLDOMAIN realm = lldomain.local netbios name = DUMBO passdb backend = samba4 logon path = \\%L\profiles\%U logon drive = L: log file = /var/log/samba/%m.log max log size = 50 security = ads domain logons = yes domain master = auto usershare allow guests = no valid users = %S [netlogon] path = /var/lib/samba/sysvol/lldomain.local/scripts read only = no guest ok = no [sysvol] path = /var/lib/samba/sysvol read only = No guest ok = no valid users = @LLDOMAIN\LLGrpManager [ShareX] path = /data comment = Entire Data Volume guest ok = no comment = Entire Data Volume guest ok = no valid users = @LLDOMAIN\LLGrpManager admin users = @LLDOMAIN\LLGrpManager browsable = no inherit acls = yes inherit permissions = yes ... My /etc/nsswitch.conf I've also instructed the system to use the nss winbind library when searching for users or groups by adding the stanza passwd and group in /etc/nsswitch.conf: passwd: compat winbind group: compat winbind shadow: compat Permissions on the folder in question drwxrwxrwt 8 root root 4.0K Oct 28 19:11 data

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  • Delegating account unlock rights in AD

    - by ewall
    I'm trying to delegate the rights to unlock user accounts in our Active Directory domain. This should be easy, and I've done it before... but every time the user tries to unlock an account (using the LockoutStatus tool), he gets denied with the error "You do not have the necessary permissions to unlock this account." Here's what I've done: I created a domain local group and added the members who should have the rights. This was created over a week ago, so the users have logged out and in again. In ADUC, I've used the Delegate Rights wizard on the OU which contains our user accounts to grant permissions to Read lockoutTime and Writer lockoutTime to the group, per MSKB 279723 I have double-checked the permissions were applied correctly in ADSIEdit. I have forced replication between all domain controllers to ensure the permission changes were copied over. The user testing it has logged out and in again to ensure he has any changes applied to his account. ...That covers all the bases I can think of. Anything else I could be missing?

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  • Linux NFS create mask and force user equivalent

    - by Mike
    I have two Linux servers: fileserver Debian 5.0.3 (2.6.26-2-686) Samba version 3.4.2 apache Ubuntu 10.04 LTS (2.6.32-23-generic) Apache 2.2.14 I have a number of Samba shares on fileserver so that I can access files from Windows PCs. I am also exporting /data/www-data to the apache server, where I have it mounted as /var/www. The setup is okay, except for when I come to create files on the NFS mount. I end up with files that cannot be read by Apache, or which cannot be modified by other users on my system. With Samba, I can specify force user, force group, create mask and directory mask, and this ensures that all files are created with suitable permissions for my Apache web server. I can't find a way to do this with NFS. Is there a way to force permissions and ownership with NFS - am I missing something obvious? Although I've spent quite a bit of time with Linux, and am weaning myself off Windows, I still haven't quite got to grip with Linux permissions... If this is not the right way to do things, I am open to alternative suggestions.

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  • Setting umask for all users

    - by Yarin
    I'm trying to set the default umask to 002 for all users including root on my CentOS box. According to this and other answers, this can be achieved by editing /etc/profile. However the comments at the top of that file say: It's NOT a good idea to change this file unless you know what you are doing. It's much better to create a custom.sh shell script in /etc/profile.d/ to make custom changes to your environment, as this will prevent the need for merging in future updates. So I went ahead and created the following file: /etc/profile.d/myapp.sh with the single line: umask 002 Now, when I create a file logged in as root, the file is born with 664 permissions, the way I had hoped. But files created by my Apache wsgi application, or files created with sudo, still default to 644 permissions... $ touch newfile (as root): Result = 664 (Works) $ sudo touch newfile: Result = 644 (Doesn't work) Files created by Apache wsgi app: Result = 644 (Doesn't work) Files created by Python's RotatingFileHandler: Result = 644 (Doesn't work) Why is this happening, and how can I ensure 664 file permissions system wide, no matter what creates the file? UPDATE: I ended up finding a cleaner solution to this on a per-directory basis using ACLs, which I describe here.

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  • Change to different user, or let different user execute a command

    - by WG-
    I have a problem. There is a server which I can access with an account by ssh, lets say WG. Now there is a folder with the following permissions. drwxr-s---+ 855 vvz www-data 20K Aug 21 17:56 pictures I want to copy this folder using rsync, however since I am not the user www-data but WG I cannot execute rsync. So I want www-data to execute a rsync command. However, I do not posses sudo powers. My friend however tells me that I am actually able to execute the rsync command as www-data, but he will not tell me how. I asked him for some clues and he told me that it had something to do with reverse shell (which I figured out to be that you connect by ssh to your server and then you connect back to your own server, or something). I also asked if it was by-design or actually a flaw in the system. He tells me it is both. Furthermore I think it has something to do with the group permissions. If I just make sure that I am with the group permissions then I can also read the files. Anybody has a clue?

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  • Can't do anything with Ext. HDD, ".Trashes" is probably the boogyman. (On a MAC!)

    - by Sander Schaeffer
    I bought a external Harddrive today, A Samsung. But I'm not able to do anything with it A few notes on that. I can't put anything on the harddrive. It keeps on 'preparing copying files' I can delete anything on the harddrive system files, except the folder ".Trashes". It gives error 'Unexpected error: -50' I've tried to empty my own trashcan, no changes. I've set the file permission on the .Trashes to read/write everyone, doesn;t change a thing Trying to format the whole drive with DiskUtility, but quits at start, because the drive cannot be deactivated I've tried a few terminal commands sudo -s -r rf /Volumes/Untitled\ 1/.Trashes - Directory not empty -r rf /Volumes/Untitled\ 1/.Trashes - no permissions Also cd /Volumes ls -al cd name_of_partition ls -al -rm -rf .Trashes Again: Permission error. Also: I can't change drive permissions via Disk Utility, via the button 'recover drive permissions', because it is 'blank' I really can't figure out how to delete .Trashes, format the drive or get the damn thing working. Any suggestions? p.s. If this is the wrong Stack Exchange site: Please redirect me!

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