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  • Best practice? Using DPM to backup VMs within each VM or through the host?

    - by andrew
    We've got two Hyper-V hosts running multiple VMs (all flavors of Windows Servers). One of the VMs is running MS Data Protection Manager 2010, which runs beautifully (most of the time) and is connected to a separate NAS via iSCSI for the DPM storage. I noticed when I installed the DPM agent on the Hyper-V hosts, it enumerates the VMs in the DPM Protection listing. I don't want to burn through my storage space too fast with duplicate protection, so I was wondering: Is it recommended to back up VMs through the host, or is it better to install the DPM agent on each VM and backup as I would any other machine? It would seem as though most people (currently including me) do it the second way, but is there any advantage to including the entries under HyperV (Backup using Child Partition Snapshop)?

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  • (PHP) User is being forced to RE-LOGIN after trying to do something on an admin page

    - by hatorade
    I have created an admin panel for a client in PHP, which requires a login. Here is the code at the top of the admin page requiring the user to be logged in: admin.php <?php session_start(); require("_lib/session_functions.php"); require("_lib/db.php"); db_connect(); //if the user has not logged in if(!isLoggedIn()) { header('Location: login_form.php'); die(); } ?> Obviously, the if statement is what catches them and forces them to log in. Here is the code on the resulting login page: login_form.php <form name="login" action="login.php" method="post"> Username: <input type="text" name="username" /> Password: <input type="password" name="password" /> <input type="submit" value="Login" /> </form> Which posts info to this controller page: login.php <?php session_start(); //must call session_start before using any $_SESSION variables include '_lib/session_functions.php'; $username = $_POST['username']; $password = $_POST['password']; include '_lib/db.php'; db_connect(); // Connect to the DB $username = mysql_real_escape_string($username); $query = "SELECT password, salt FROM users WHERE username = '$username';"; $result = mysql_query($query); if(mysql_num_rows($result) < 1) //no such user exists { header('Location: login_form.php?login=fail'); die(); } $userData = mysql_fetch_array($result, MYSQL_ASSOC); db_disconnect(); $hash = hash('sha256', $password . $userData['salt']); if($hash != $userData['password']) //incorrect password { header('Location: login_form.php?login=fail'); die(); } else { validateUser(); //sets the session data for this user } header('Location: admin.php'); ?> and the session functions page that provides login functions contains this: session_functions.php <?php function validateUser() { session_regenerate_id (); //this is a security measure $_SESSION['valid'] = 1; $_SESSION['userid'] = $username; } function isLoggedIn() { if($_SESSION['valid']) return true; return false; } function logout() { $_SESSION = array(); //destroy all of the session variables if (ini_get("session.use_cookies")) { $params = session_get_cookie_params(); setcookie(session_name(), '', time() - 42000, $params["path"], $params["domain"], $params["secure"], $params["httponly"] ); } session_destroy(); } ?> I grabbed the sessions_functions.php code of an online tutorial, so it could be suspicious. Any ideas why the user logs in to the admin panel, tries to do something, is forced to re-login, and THEN is allowed to do stuff like normal in the admin panel?

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  • Html LogIn form not functioning

    - by Tony C
    Ok, I have a login form that looks like this: <form id="loginForm" name="loginForm" method="post" action="login-exec.php"> <table width="300" border="0" align="center" cellpadding="2" cellspacing="0"> <tr> <td width="112"><b>Login</b></td> <td width="188"><input name="login" type="text" class="textfield" id="login" /></td> </tr> <tr> <td><b>Password</b></td> <td><input name="password" type="password" class="textfield" id="password" /></td> </tr> <tr> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login" /></td> </tr> </table> </form> Now, This form is on a page in a directory called members. When i put it on a page in the home directory and change the action to "members/login-exec.php" When I try to logIn it just refreshes the page, but the name of the page in the browser changes to the actions taking place in the form. Any ideas on making this work guys? EDIT, heres the login-exec.php code: <?php //Start session session_start(); //Include database connection details require_once('config.php'); //Array to store validation errors $errmsg_arr = array(); //Validation error flag $errflag = false; //Connect to mysql server $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } //Select database $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } //Function to sanitize values received from the form. Prevents SQL injection function clean($str) { $str = @trim($str); if(get_magic_quotes_gpc()) { $str = stripslashes($str); } return mysql_real_escape_string($str); } //Sanitize the POST values $login = clean($_POST['login']); $password = clean($_POST['password']); //Input Validations if($login == '') { $errmsg_arr[] = 'Login ID missing'; $errflag = true; } if($password == '') { $errmsg_arr[] = 'Password missing'; $errflag = true; } //If there are input validations, redirect back to the login form if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; session_write_close(); header("location: login-form.php"); exit(); } //Create query $qry="SELECT * FROM members WHERE login='$login' AND passwd='".md5($_POST['password'])."'"; $result=mysql_query($qry); //Check whether the query was successful or not if($result) { if(mysql_num_rows($result) == 1) { //Login Successful session_regenerate_id(); $member = mysql_fetch_assoc($result); $_SESSION['SESS_MEMBER_ID'] = $member['member_id']; $_SESSION['SESS_FIRST_NAME'] = $member['firstname']; $_SESSION['SESS_LAST_NAME'] = $member['lastname']; session_write_close(); header("location: members.php"); exit(); }else { //Login failed header("location: login-failed.php"); exit(); } }else { die("Query failed"); } ?>

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  • I'm trying to pass a string from my first ViewController to my second ViewController but it returns NULL

    - by Dashony
    In my first view controller I have 3 input fields each of them take the user input into and saves it into a string such as: address, username and password as NSUserDefaults. This part works fine. In my second view controller I'm trying to take the 3 strings from first controller (address, username and password) create a html link based on the 3 strings. I've tried many ways to access the 3 strings with no luck, the result I get is NULL. Here is my code: //.h file - first view controller with the 3 input fields CamSetup.h #import <UIKit/UIKit.h> @interface CamSetup : UIViewController <UITextFieldDelegate> { NSString * address; NSString * username; NSString * password; IBOutlet UITextField * addressField; IBOutlet UITextField * usernameField; IBOutlet UITextField * passwordField; } -(IBAction) saveAddress: (id) sender; -(IBAction) saveUsername: (id) sender; -(IBAction) savePassword: (id) sender; @property(nonatomic, retain) UITextField *addressField; @property(nonatomic, retain) UITextField *usernameField; @property(nonatomic, retain) UITextField *passwordField; @property(nonatomic, retain) NSString *address; @property(nonatomic, retain) NSString *username; @property(nonatomic, retain) NSString *password; @end //.m file - first view controller CamSetup.m #import "CamSetup.h" @interface CamSetup () @end @implementation CamSetup @synthesize addressField, usernameField, passwordField, address, username, password; -(IBAction) saveAddress: (id) sender { address = [[NSString alloc] initWithFormat:addressField.text]; [addressField setText:address]; NSUserDefaults *stringDefaultAddress = [NSUserDefaults standardUserDefaults]; [stringDefaultAddress setObject:address forKey:@"stringKey1"]; NSLog(@"String [%@]", address); } -(IBAction) saveUsername: (id) sender { username = [[NSString alloc] initWithFormat:usernameField.text]; [usernameField setText:username]; NSUserDefaults *stringDefaultUsername = [NSUserDefaults standardUserDefaults]; [stringDefaultUsername setObject:username forKey:@"stringKey2"]; NSLog(@"String [%@]", username); } -(IBAction) savePassword: (id) sender { password = [[NSString alloc] initWithFormat:passwordField.text]; [passwordField setText:password]; NSUserDefaults *stringDefaultPassword = [NSUserDefaults standardUserDefaults]; [stringDefaultPassword setObject:password forKey:@"stringKey3"]; NSLog(@"String [%@]", password); } - (void)viewDidLoad { [addressField setText:[[NSUserDefaults standardUserDefaults] objectForKey:@"stringKey1"]]; [usernameField setText:[[NSUserDefaults standardUserDefaults] objectForKey:@"stringKey2"]]; [passwordField setText:[[NSUserDefaults standardUserDefaults] objectForKey:@"stringKey3"]]; [super viewDidLoad]; } @end //.h second view controller LiveView.h #import <UIKit/UIKit.h> #import "CamSetup.h" @interface LiveView : UIViewController { NSString *theAddress; NSString *theUsername; NSString *thePassword; CamSetup *camsetup; //here is an instance of the first class } @property (nonatomic, retain) NSString *theAddress; @property (nonatomic, retain) NSString *theUsername; @property (nonatomic, retain) NSString *thePassword; @end //.m second view LiveView.m file #import "LiveView.h" @interface LiveView () @end @implementation LiveView @synthesize theAddress, theUsername, thePassword; - (void)viewDidLoad { [super viewDidLoad]; theUsername = camsetup.username; //this is probably not right? NSLog(@"String [%@]", theUsername); //resut here is NULL NSLog(@"String [%@]", camsetup.username); //and here NULL as well } @end

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  • Welcome Relief

    - by michael.seback
    Government organizations are experiencing unprecedented demand for social services. The current economy continues to put immense stress on social service organizations. Increased need for food assistance, employment security, housing aid and other critical services is keeping agencies busier than ever. ... The Kansas Department of Labor (KDOL) uses Oracle's social services solution in its employment security program. KDOL has used Siebel Customer Relationship Management (CRM) for nearly a decade, and recently purchased Oracle Policy Automation to improve its services even further. KDOL implemented Siebel CRM in 2002, and has expanded its use of it over the years. The agency started with Siebel CRM in the call center and later moved it into case management. Siebel CRM has been a strong foundation for KDOL in the face of rising demand for unemployment benefits, numerous labor-related law changes, and an evolving IT environment. ... The result has been better service for constituents. "It's really enabled our staff to be more effective in serving clients," said Hubka. That's a trend the department plans to continue. "We're 100 percent down the path of Siebel, in terms of what we're doing in the future," Hubka added. "Their vision is very much in line with what we're planning on doing ourselves." ... Community Services is the leading agency responsible for the safety and well-being of children and young people within Australia's New South Wales (NSW) Government. Already a longtime Oracle Case Management user, Community Services recently implemented Oracle Policy Automation to ensure accurate, consistent decisions in the management of child safety. "Oracle Policy Automation has helped to provide a vehicle for the consistent application of the Government's 'Keep Them Safe' child protection action plan," said Kerry Holling, CIO for Community Services. "We believe this approach is a world-first in the structured decisionmaking space for child protection and we believe our department is setting an example that other child protection agencies will replicate." ... Read the full case study here.

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  • Why can't I reinstall MySQL?

    - by Johannes Nielsen
    I've been looking all around the Internet for an answer but didn't find anything. I hope you can help me now. I have a server with MySQL. From one day to another, MySQL didn't let me enter with my root password anymore (accsess denied for user 'root'@'localhost' using password: 'YES'). So I tried two ways to reset the password: No.1: I typed: shell> /etc/init.d/mysqld stop To stop MySQL. Then I restarted it skipping the grant-tables: shell> mysqld_safe --skip-grant-tables So I was able to log in as root and change the password using: mysql> UPDATE mysql.user SET Password = PASSWORD('MyNewPassword') WHERE User = 'root'; FLUSH PRIVILEGES; I restarted MySQL and tried to log in as root with my new password - didn't work. So I tried the solution that's described here: http://dev.mysql.com/doc/refman/5.0/en/resetting-permissions.html (I don't want to post it here because this post is already pretty long). Didn't work either. Actually it made it worse, because since that day, every time I try to start MySQL, it doesn't even ask me for my password, but I get: shell> ERROR 2002 (HY000): Can't connect to local MySQL server through socket '/var/run/mysqld/mysqld.sock' (111) Well, I've looked up what it means and found that my mysqld.sock is missing. I tried to create it using touch but MySQL can't start with that socket. Now I'm trying to reinstall MySQL but everytime I type in shell> apt-get --purge remove mysql-server mysql-common mysql-client In that or any other order or every one of those three alone, I get: shell> Reading package lists... Done shell> Building dependency tree shell> Reading state information... Done shell> Package mysql-client is not installed, so not removed shell> Package mysql-server is not installed, so not removed shell> You might want to run 'apt-get -f install' to correct these: shell> The following packages have unmet dependencies: shell> libmysqlclient18 : Depends: mysql-common (>= 5.5.28-0ubuntu0.12.04.2) but it is not going to be installed shell> libmysqlclient18:i386 : Depends: mysql-common:i386 (>= 5.5.28-0ubuntu0.12.04.2) shell> mysql-client-5.5 : Depends: mysql-common (>= 5.5.28-0ubuntu0.12.04.2) but it is not going to be installed shell> mysql-server-5.5 : PreDepends: mysql-common (>= 5.5.28-0ubuntu0.12.04.2) but it is not going to be installed shell> psa-firewall : Depends: plesk-core (>= 11.0.9) but it is not installable shell> Depends: mysql-server but it is not going to be installed shell> psa-spamassassin : Depends: plesk-core (>= 11.0.9) but it is not installable shell> psa-vpn : Depends: plesk-core (>= 11.0.9) but it is not installable shell> Depends: plesk-base (>= 11.0.9) but it is not installable shell> Depends: mysql-server but it is not going to be installed shell> E: Unmet dependencies. Try 'apt-get -f install' with no packages (or specify a solution). So I said to my self "let's just remove those files with depenencies, too" (that psa-stuff since plesk is virtual and can't be uninstalled)... Guess what happened: shell> Reading package lists... Done shell> Building dependency tree shell> Reading state information... Done shell> Package mysql-client is not installed, so not removed shell> Package mysql-server is not installed, so not removed shell> You might want to run 'apt-get -f install' to correct these: shell> The following packages have unmet dependencies: shell> libmysqlclient18 : Depends: mysql-common (>= 5.5.28-0ubuntu0.12.04.2) but it is not going to be installed shell> libmysqlclient18:i386 : Depends: mysql-common:i386 (>= 5.5.28-0ubuntu0.12.04.2) shell> mysql-client-5.5 : Depends: mysql-common (>= 5.5.28-0ubuntu0.12.04.2) but it is not going to be installed shell> mysql-server-5.5 : PreDepends: mysql-common (>= 5.5.28-0ubuntu0.12.04.2) but it is not going to be installed shell> E: Unmet dependencies. Try 'apt-get -f install' with no packages (or specify a solution). Of course I tried apt-get -f install, too many times even. What am I doing wrong? No matter, which other packages I include into apt-get --purge remove, I always get new dependencies. Do I have to delete every MySQL-related directory and file manually? Hope there's someone out there who can help me! Cheers! EDIT: After trying apt-get purge mysql-server mysql-common mysql-client libmysqlclient18 libmysqlclient18:i386 mysql-client-5.5 mysql-server-5.5 psa-firewall psa-spamassassin psa-vpn Reading package lists... Done Building dependency tree Reading state information... Done Package mysql-client is not installed, so not removed Package mysql-server is not installed, so not removed You might want to run 'apt-get -f install' to correct these: The following packages have unmet dependencies: libdbd-mysql-perl : Depends: libmysqlclient18 (>= 5.5.13-1) but it is not going to be installed libmyodbc : Depends: libmysqlclient18 (>= 5.5.13-1) but it is not going to be installed libqt4-sql-mysql:i386 : Depends: libmysqlclient18:i386 (>= 5.5.13-1) but it is not going to be installed php5-mysql : Depends: libmysqlclient18 (>= 5.5.13-1) but it is not going to be installed ruby-mysql : Depends: libmysqlclient18 (>= 5.5.13-1) but it is not going to be installed E: Unmet dependencies. Try 'apt-get -f install' with no packages (or specify a solution). So I tried to remove all these and got: Building dependency tree Reading state information... Done Package mysql-client is not installed, so not removed Package mysql-server is not installed, so not removed You might want to run 'apt-get -f install' to correct these:qlclient18:i386 mysql The following packages have unmet dependencies: libmysql-ruby1.8 : Depends: ruby-mysql but it is not going to be installed E: Unmet dependencies. Try 'apt-get -f install' with no packages (or specify a solution). And actually I think removing that file, too solved my problem :-S Next time I'll try everything before asking :D Thank you Eric for keeping me couraged to just go on removing :D

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  • Controlar Autentificaci&oacute;n Crystal Reports

    - by Jason Ulloa
    Para todos los que hemos trabajamos con Crystal Reports, no es un secreto que cuando tratamos de conectar nuestro reporte directamente a la base de datos, se nos viene encima el problema de autenticación. Es decir nuestro reporte al momento de iniciar la carga nos solicita autentificarnos en el servidor y sino lo hacemos, simplemente no veremos el reporte. Esto, además de ser tedioso para los usuarios se convierte en un problema de seguridad bastante grande, de ahí que en la mayoría de los casos se recomienda utilizar dataset. Sin embargo, para todos los que aún sabiendo esto no desean utilizar datasets, sino que, quieren conectar su crystal directamente veremos como implementar una pequeña clase que nos ayudará con esa tarea. Generalmente, cuando trabajamos con una aplicación web, nuestra cadena de conexión esta incluida en el web.config y también en muchas ocasiones contiene los datos como el usuario y password para acceder a la base de datos.  De esta cadena de conexión y estos datos es de los que nos ayudaremos para implementar la autentificación en el reporte. Generalmente, la cadena de conexión se vería así <connectionStrings> <remove name="LocalSqlServer"/> <add name="xxx" connectionString="Data Source=.\SqlExpress;Integrated Security=False;Initial Catalog=xxx;user id=myuser;password=mypass" providerName="System.Data.SqlClient"/> </connectionStrings>   Para nuestro ejemplo, nombraremos a nuestra clase CrystalRules (es solo algo que pensé de momento) 1. Primer Paso Creamos una variable de tipo SqlConnectionStringBuilder, a la cual le asignaremos la cadena de conexión que definimos en el web.config, y que luego utilizaremos para obtener los datos del usuario y el password para el crystal report. SqlConnectionStringBuilder builder = new SqlConnectionStringBuilder(ConfigurationManager.ConnectionStrings["xxx"].ConnectionString); 2. Implementación de propiedad Para ser más ordenados crearemos varias propiedad de tipo Privado, que se encargarán de recibir los datos de:   La Base de datos, el password, el usuario y el servidor private string _dbName; private string _serverName; private string _userID; private string _passWord;   private string dataBase { get { return _dbName; } set { _dbName = value; } }   private string serverName { get { return _serverName; } set { _serverName = value; } }   private string userName { get { return _userID; } set { _userID = value; } }   private string dataBasePassword { get { return _passWord; } set { _passWord = value; } } 3. Creación del Método para aplicar los datos de conexión Una vez que ya tenemos las propiedades, asignaremos a las variables los valores que se han recogido en el SqlConnectionStringBuilder. Y crearemos una variable de tipo ConnectionInfo para aplicar los datos de conexión. internal void ApplyInfo(ReportDocument _oRpt) { dataBase = builder.InitialCatalog; serverName = builder.DataSource; userName = builder.UserID; dataBasePassword = builder.Password;   Database oCRDb = _oRpt.Database; Tables oCRTables = oCRDb.Tables; //Table oCRTable = default(Table); TableLogOnInfo oCRTableLogonInfo = default(TableLogOnInfo); ConnectionInfo oCRConnectionInfo = new ConnectionInfo();   oCRConnectionInfo.DatabaseName = _dbName; oCRConnectionInfo.ServerName = _serverName; oCRConnectionInfo.UserID = _userID; oCRConnectionInfo.Password = _passWord;   foreach (Table oCRTable in oCRTables) { oCRTableLogonInfo = oCRTable.LogOnInfo; oCRTableLogonInfo.ConnectionInfo = oCRConnectionInfo; oCRTable.ApplyLogOnInfo(oCRTableLogonInfo);     }   }   4. Creación del report document y aplicación de la seguridad Una vez recogidos los datos y asignados, crearemos un elemento report document al cual le asignaremos el CrystalReportViewer y le aplicaremos los datos de acceso que obtuvimos anteriormente public void loadReport(string repName, CrystalReportViewer viewer) {   // attached our report to viewer and set database login. ReportDocument report = new ReportDocument(); report.Load(HttpContext.Current.Server.MapPath("~/Reports/" + repName)); ApplyInfo(report); viewer.ReportSource = report; } Al final, nuestra clase completa ser vería así public class CrystalRules { SqlConnectionStringBuilder builder = new SqlConnectionStringBuilder(ConfigurationManager.ConnectionStrings["Fatchoy.Data.Properties.Settings.FatchoyConnectionString"].ConnectionString);   private string _dbName; private string _serverName; private string _userID; private string _passWord;   private string dataBase { get { return _dbName; } set { _dbName = value; } }   private string serverName { get { return _serverName; } set { _serverName = value; } }   private string userName { get { return _userID; } set { _userID = value; } }   private string dataBasePassword { get { return _passWord; } set { _passWord = value; } }   internal void ApplyInfo(ReportDocument _oRpt) { dataBase = builder.InitialCatalog; serverName = builder.DataSource; userName = builder.UserID; dataBasePassword = builder.Password;   Database oCRDb = _oRpt.Database; Tables oCRTables = oCRDb.Tables; //Table oCRTable = default(Table); TableLogOnInfo oCRTableLogonInfo = default(TableLogOnInfo); ConnectionInfo oCRConnectionInfo = new ConnectionInfo();   oCRConnectionInfo.DatabaseName = _dbName; oCRConnectionInfo.ServerName = _serverName; oCRConnectionInfo.UserID = _userID; oCRConnectionInfo.Password = _passWord;   foreach (Table oCRTable in oCRTables) { oCRTableLogonInfo = oCRTable.LogOnInfo; oCRTableLogonInfo.ConnectionInfo = oCRConnectionInfo; oCRTable.ApplyLogOnInfo(oCRTableLogonInfo);     }   }   public void loadReport(string repName, CrystalReportViewer viewer) {   // attached our report to viewer and set database login. ReportDocument report = new ReportDocument(); report.Load(HttpContext.Current.Server.MapPath("~/Reports/" + repName)); ApplyInfo(report); viewer.ReportSource = report; }       #region instance   private static CrystalRules m_instance;   // Properties public static CrystalRules Instance { get { if (m_instance == null) { m_instance = new CrystalRules(); } return m_instance; } }   public DataDataContext m_DataContext { get { return DataDataContext.Instance; } }     #endregion instance   }   Si bien, la solución no es robusta y no es la mas segura. En casos de uso como una intranet y cuando estamos contra tiempo, podría ser de gran ayuda.

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  • MySQL for Excel 1.1.3 has been released

    - by Javier Treviño
    The MySQL Windows Experience Team is proud to announce the release of MySQL for Excel version 1.1.3, the  latest addition to the MySQL Installer for Windows. MySQL for Excel is an application plug-in enabling data analysts to very easily access and manipulate MySQL data within Microsoft Excel. It enables you to directly work with a MySQL database from within Microsoft Excel so you can easily do tasks such as: Importing MySQL Data into Excel Exporting Excel data directly into MySQL to a new or existing table Editing MySQL data directly within Excel MySQL for Excel is installed using the MySQL Installer for Windows. The MySQL installer comes in 2 versions   Full (150 MB) which includes a complete set of MySQL products with their binaries included in the download Web (1.5 MB - a network install) which will just pull MySQL for Excel over the web and install it when run.   You can download MySQL Installer from our official Downloads page at http://dev.mysql.com/downloads/installer/. MySQL for Excel 1.1.3 introduces the following features:   Upon saving a Workbook containing Worksheets in Edit Mode, the user is asked if he wants to exit the Edit Mode on all Worksheets before their parent Workbook is saved so the Worksheets are saved unprotected, otherwise the Worksheets will remain protected and the users will be able to unprotect them later retrieving the passkeys from the application log after closing MySQL for Excel. Added background coloring to the column names header row of an Import Data operation to have the same look as the one in an Edit Data operation (i.e. gray-ish background). Connection passwords can be stored securely just like MySQL Workbench does and these secured passwords are shared with Workbench in the same way connections are. Changed the way the MySQL for Excel ribbon toggle button works, instead of just showing or hiding the add-in it actually opens and closes it. Added a connection test before any operation against the database (schema creation, data import, append, export or edition) so the operation dialog is not shown and a friendlier error message is shown.   Also this release contains the following bug fixes:   Added a check on every connection test for an expired password, if the password has been expired a dialog is now shown to the user to reset the password. Bug #17354118 - DON'T HANDLE EXPIRED PASSWORDS Added code to escape text values to be imported to an Excel worksheet that start with an equals sign so Excel does not treat those values as formulas that will fail evaluation. This is an option turned on by default that can be turned off by users if they wish to import values to be treated as Excel formulas. Bug #17354102 - ERROR IMPORTING TEXT VALUES TO EXCEL STARTING WITH AN EQUALS SIGN Added code to properly check the reason for a failing connection, if it's a failing password the user gets a dialog to retry the connection with a different password until the connection succeeds, a connection error not related to the password is thrown or the user cancels. If the failing connection is not related to a bad password an error message is shown to the users indicating the reason of the failure. Bug #16239007 - CONNECTIONS TO MYSQL SERVICES NOT RUNNING DISPLAY A WRONG PASSWORD ERROR MESSAGE Added global options dialog that can be accessed from the Schema Selection and DB Object Selection panels where the timeouts for the connection to the DB Server and for the query commands can be changed from their default values (15 seconds for the connection timeout and 30 seconds for the query timeout). MySQL Bug #68732, Bug #17191646 - QUERY TIMEOUT CANNOT BE ADJUSTED IN MYSQL FOR EXCEL Changed the Varchar(65,535) data type shown in the Export Data data type combo box to Text since the maximum row size is 65,535 bytes and any autodetected column data type with a length greater than 4,000 should be set to Text actually for the table to be created successfully. MySQL Bug #69779, Bug #17191633 - EXPORT FAILS FOR EXCEL FILES CONTAINING > 4000 CHARACTERS OF TEXT PER CELL Removed code that was replacing all spaces typed by the user in an overriden data type for a new column in an Export Data operation, also improved the data type detection code to flag as invalid data types with parenthesis but without any text inside or where the contents inside the parenthesis are not valid for the specific data type. Bug #17260260 - EXPORT DATA SET TYPE NOT WORKING WITH MEMBER VALUES CONTAINING SPACES Added support for the year data type with a length of 2 or 4 and a validation that valid values are integers between 1901-2155 (for 4-digit years) or between 0-99 (for 2-digit years). Bug #17259915 - EXPORT DATA YEAR DATA TYPE NOT RECOGNIZED IF DECLARED WITH A DISPLAY WIDTH) Fixed code for Export Data operations where users overrode the data type for columns typing Text in the data type combobox, which is a valid data type but was not recognized as such. Bug #17259490 - EXPORT DATA TEXT DATA TYPE NOT RECOGNIZED AS A VALID DATA TYPE Changed the location of the registry where the MySQL for Excel add-in is installed to HKEY_LOCAL_MACHINE instead of HKEY_CURRENT_USER so the add-in is accessible by all users and not only to the user that installed it. For this to work with Excel 2007 a hotfix may be required (see http://support.microsoft.com/kb/976477). MySQL Bug #68746, Bug #16675992 - EXCEL-ADD-IN IS ONLY INSTALLED FOR USER ACCOUNT THAT THE INSTALLATION RUNS UNDER Added support for Excel 2013 Single Document Interface, now that Excel 2013 creates 1 window per workbook also the Excel Add-In maintains an independent custom task pane in each window. MySQL Bug #68792, Bug #17272087 - MYSQL FOR EXCEL SIDEBAR DOES NOT APPEAR IN EXCEL 2013 (WITH WORKAROUND) Included the latest MySQL Utility with a code fix for the COM exception thrown when attempting to open Workbench in the Manage Connections window. Bug #17258966 - MYSQL WORKBENCH NOT OPENED BY CLICKING MANAGE CONNECTIONS HOTLABEL Fixed code for Append Data operations that was not applying a calculated automatic mapping correctly when the source and target tables had different number of columns, some columns with the same name but some of those lying on column indexes beyond the limit of the other source/target table. MySQL Bug #69220, Bug #17278349 - APPEND DOESN'T AUTOMATICALLY DETECT EXCEL COL HEADER WITH SAME NAME AS SQL FIELD Fixed some code for Edit Data operations that was escaping special characters twice (during edition in Excel and then upon sending the query to the MySQL server). MySQL Bug #68669, Bug #17271693 - A BACKSLASH IS INSERTED BEFORE AN APOSTROPHE EDITING TABLE WITH MYSQL FOR EXCEL Upgraded MySQL Utility with latest version that encapsulates dialog base classes and introduces more classes to handle Workbench connections, and removed these from the Excel project. Bug #16500331 - CAN'T DELETE CONNECTIONS CREATED WITHIN ADDIN You can access the MySQL for Excel documentation at http://dev.mysql.com/doc/refman/5.6/en/mysql-for-excel.html You can find our team’s blog at http://blogs.oracle.com/MySQLOnWindows. You can also post questions on our MySQL for Excel forum found at http://forums.mysql.com/. Enjoy and thanks for the support!

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  • Secure Your Wireless Router: 8 Things You Can Do Right Now

    - by Chris Hoffman
    A security researcher recently discovered a backdoor in many D-Link routers, allowing anyone to access the router without knowing the username or password. This isn’t the first router security issue and won’t be the last. To protect yourself, you should ensure that your router is configured securely. This is about more than just enabling Wi-Fi encryption and not hosting an open Wi-Fi network. Disable Remote Access Routers offer a web interface, allowing you to configure them through a browser. The router runs a web server and makes this web page available when you’re on the router’s local network. However, most routers offer a “remote access” feature that allows you to access this web interface from anywhere in the world. Even if you set a username and password, if you have a D-Link router affected by this vulnerability, anyone would be able to log in without any credentials. If you have remote access disabled, you’d be safe from people remotely accessing your router and tampering with it. To do this, open your router’s web interface and look for the “Remote Access,” “Remote Administration,” or “Remote Management” feature. Ensure it’s disabled — it should be disabled by default on most routers, but it’s good to check. Update the Firmware Like our operating systems, web browsers, and every other piece of software we use, router software isn’t perfect. The router’s firmware — essentially the software running on the router — may have security flaws. Router manufacturers may release firmware updates that fix such security holes, although they quickly discontinue support for most routers and move on to the next models. Unfortunately, most routers don’t have an auto-update feature like Windows and our web browsers do — you have to check your router manufacturer’s website for a firmware update and install it manually via the router’s web interface. Check to be sure your router has the latest available firmware installed. Change Default Login Credentials Many routers have default login credentials that are fairly obvious, such as the password “admin”. If someone gained access to your router’s web interface through some sort of vulnerability or just by logging onto your Wi-Fi network, it would be easy to log in and tamper with the router’s settings. To avoid this, change the router’s password to a non-default password that an attacker couldn’t easily guess. Some routers even allow you to change the username you use to log into your router. Lock Down Wi-Fi Access If someone gains access to your Wi-Fi network, they could attempt to tamper with your router — or just do other bad things like snoop on your local file shares or use your connection to downloaded copyrighted content and get you in trouble. Running an open Wi-Fi network can be dangerous. To prevent this, ensure your router’s Wi-Fi is secure. This is pretty simple: Set it to use WPA2 encryption and use a reasonably secure passphrase. Don’t use the weaker WEP encryption or set an obvious passphrase like “password”. Disable UPnP A variety of UPnP flaws have been found in consumer routers. Tens of millions of consumer routers respond to UPnP requests from the Internet, allowing attackers on the Internet to remotely configure your router. Flash applets in your browser could use UPnP to open ports, making your computer more vulnerable. UPnP is fairly insecure for a variety of reasons. To avoid UPnP-based problems, disable UPnP on your router via its web interface. If you use software that needs ports forwarded — such as a BitTorrent client, game server, or communications program — you’ll have to forward ports on your router without relying on UPnP. Log Out of the Router’s Web Interface When You’re Done Configuring It Cross site scripting (XSS) flaws have been found in some routers. A router with such an XSS flaw could be controlled by a malicious web page, allowing the web page to configure settings while you’re logged in. If your router is using its default username and password, it would be easy for the malicious web page to gain access. Even if you changed your router’s password, it would be theoretically possible for a website to use your logged-in session to access your router and modify its settings. To prevent this, just log out of your router when you’re done configuring it — if you can’t do that, you may want to clear your browser cookies. This isn’t something to be too paranoid about, but logging out of your router when you’re done using it is a quick and easy thing to do. Change the Router’s Local IP Address If you’re really paranoid, you may be able to change your router’s local IP address. For example, if its default address is 192.168.0.1, you could change it to 192.168.0.150. If the router itself were vulnerable and some sort of malicious script in your web browser attempted to exploit a cross site scripting vulnerability, accessing known-vulnerable routers at their local IP address and tampering with them, the attack would fail. This step isn’t completely necessary, especially since it wouldn’t protect against local attackers — if someone were on your network or software was running on your PC, they’d be able to determine your router’s IP address and connect to it. Install Third-Party Firmwares If you’re really worried about security, you could also install a third-party firmware such as DD-WRT or OpenWRT. You won’t find obscure back doors added by the router’s manufacturer in these alternative firmwares. Consumer routers are shaping up to be a perfect storm of security problems — they’re not automatically updated with new security patches, they’re connected directly to the Internet, manufacturers quickly stop supporting them, and many consumer routers seem to be full of bad code that leads to UPnP exploits and easy-to-exploit backdoors. It’s smart to take some basic precautions. Image Credit: Nuscreen on Flickr     

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  • Trying to configure HWIC-3G-HSPA

    - by user1174838
    I'm trying to configure a couple of Cisco 1941 routes. The are both identical routers. Each as a HWIC-1T (Smart Serial interface) and a HWIC-3G-HSPA 3G interface. These routers are to be sent to remote sites. We have connectivity to one of the sites but if remote site A gors down we lose connectivity to remote site B. The HWIC-1T is the primary WAN interface using frame relay joining the two remote sites We want the HWIC-3G-HSPA to be usable for direct connectivity from head office to remote site B, and also the HWIC-3G-HSPA is do be used for comms between the remote sites when the frame relay is down (happens quite a bit). I initialy tried to do dynamic routing using EIGRP however in my lab setup of laptop - 1941 - 1941 - laptop, I was unable to get end to end connectivity. I later settled on static routing and have got end to end connectivity but only over frame relay, not the HWIC-3G-HSPA. The sanitized running config for remote site A: version 15.1 service tcp-keepalives-in service tcp-keepalives-out service timestamps debug datetime msec service timestamps log datetime msec service password-encryption service udp-small-servers service tcp-small-servers ! hostname remoteA ! boot-start-marker boot-end-marker ! ! logging buffered 51200 warnings enable secret 5 censored ! no aaa new-model clock timezone wst 8 0 ! no ipv6 cef ip source-route ip cef ! ip domain name yourdomain.com multilink bundle-name authenticated ! chat-script gsm "" "ATDT*98*1#" TIMEOUT 30 "CONNECT" ! username admin privilege 15 secret 5 censored ! controller Cellular 0/1 ! interface Embedded-Service-Engine0/0 no ip address shutdown ! interface GigabitEthernet0/0 ip address 192.168.2.5 255.255.255.0 duplex auto speed auto ! interface GigabitEthernet0/1 no ip address shutdown duplex auto speed auto ! interface Serial0/0/0 ip address 10.1.1.2 255.255.255.252 encapsulation frame-relay cdp enable frame-relay interface-dlci 16 frame-relay lmi-type ansi ! interface Cellular0/1/0 ip address negotiated encapsulation ppp dialer in-band dialer idle-timeout 2147483 dialer string gsm dialer-group 1 async mode interactive ppp chap hostname censored ppp chap password 7 censored cdp enable ! interface Cellular0/1/1 no ip address encapsulation ppp ! interface Dialer0 no ip address ! ip forward-protocol nd ! no ip http server no ip http secure-server ! ip route 0.0.0.0 0.0.0.0 Serial0/0/0 210 permanent ip route 0.0.0.0 0.0.0.0 Cellular0/1/0 220 permanent ip route 172.31.2.0 255.255.255.0 Cellular0/1/0 permanent ip route 192.168.3.0 255.255.255.0 10.1.1.1 permanent ip route 192.168.3.0 255.255.255.0 Cellular0/1/0 210 permanent ! access-list 1 permit any dialer-list 1 protocol ip list 1 ! control-plane ! line con 0 logging synchronous login local line aux 0 line 2 no activation-character no exec transport preferred none transport input all transport output pad telnet rlogin lapb-ta mop udptn v120 ssh stopbits 1 line 0/1/0 exec-timeout 0 0 script dialer gsm login modem InOut no exec transport input all rxspeed 7200000 txspeed 5760000 line 0/1/1 no exec rxspeed 7200000 txspeed 5760000 line vty 0 4 access-class 23 in privilege level 15 password 7 censored login local transport input all line vty 5 15 access-class 23 in privilege level 15 password 7 censored login local transport input all line vty 16 1370 password 7 censored login transport input all ! scheduler allocate 20000 1000 end The sanitized running config for remote site B: version 15.1 service tcp-keepalives-in service tcp-keepalives-out service timestamps debug datetime msec service timestamps log datetime msec service password-encryption service udp-small-servers service tcp-small-servers ! hostname remoteB ! boot-start-marker boot-end-marker ! logging buffered 51200 warnings enable secret 5 censored ! no aaa new-model clock timezone wst 8 0 ! no ipv6 cef ip source-route ip cef ! no ip domain lookup ip domain name yourdomain.com multilink bundle-name authenticated ! chat-script gsm "" "ATDT*98*1#" TIMEOUT 30 "CONNECT" username admin privilege 15 secret 5 censored ! controller Cellular 0/1 ! interface Embedded-Service-Engine0/0 no ip address shutdown ! interface GigabitEthernet0/0 ip address 192.168.3.1 255.255.255.0 duplex auto speed auto ! interface GigabitEthernet0/1 no ip address shutdown duplex auto speed auto ! interface Serial0/0/0 ip address 10.1.1.1 255.255.255.252 encapsulation frame-relay clock rate 2000000 cdp enable frame-relay interface-dlci 16 frame-relay lmi-type ansi frame-relay intf-type dce ! interface Cellular0/1/0 ip address negotiated encapsulation ppp dialer in-band dialer idle-timeout 2147483 dialer string gsm dialer-group 1 async mode interactive ppp chap hostname censored ppp chap password 7 censored ppp ipcp dns request cdp enable ! interface Cellular0/1/1 no ip address encapsulation ppp ! interface Dialer0 no ip address ! ip forward-protocol nd ! no ip http server no ip http secure-server ! ip route 0.0.0.0 0.0.0.0 Serial0/0/0 210 permanent ip route 0.0.0.0 0.0.0.0 Cellular0/1/0 220 permanent ip route 172.31.2.0 255.255.255.0 Cellular0/1/0 permanent ip route 192.168.2.0 255.255.255.0 10.1.1.2 permanent ip route 192.168.2.0 255.255.255.0 Cellular0/1/0 210 permanent ! kron occurrence PING in 1 recurring policy-list ICMP ! access-list 1 permit any dialer-list 1 protocol ip list 1 ! control-plane ! line con 0 logging synchronous login local line aux 0 line 2 no activation-character no exec transport preferred none transport input all transport output pad telnet rlogin lapb-ta mop udptn v120 ssh stopbits 1 line 0/1/0 exec-timeout 0 0 script dialer gsm login modem InOut no exec transport input all rxspeed 7200000 txspeed 5760000 line 0/1/1 no exec rxspeed 7200000 txspeed 5760000 line vty 0 4 access-class 23 in privilege level 15 password 7 censored login transport input all line vty 5 15 access-class 23 in privilege level 15 password 7 censored login transport input all line vty 16 1370 password 7 censored login transport input all ! scheduler allocate 20000 1000 end The last problem I'm having is the 3G interfaces go down after only a few minutes of inactivity. I've tried using kron to ping the local HWIC-3G-HSPA interface (cellular 0/1/0) every minute but that hasn't been successful. Manually pinging the IP assigned (by the telco) to ce0/1/0 does bring the interface up. Any ideas? Thanks

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  • call a class method from inside an instance method from a module mixin (rails)

    - by sean
    Curious how one would go about calling a class method from inside an instance method of a module which is included by an active record class. For example I want both user and client models to share the nuts and bolts of password encryption. # app/models class User < ActiveRecord::Base include Encrypt end class Client < ActiveRecord::Base include Encrypt end # app/models/shared/encrypt.rb module Encrypt def authenticate # I want to call the ClassMethods#encrypt_password method when @user.authenticate is run self.password_crypted == self.encrypt_password(self.password) end def self.included(base) base.extend ClassMethods end module ClassMethods def encrypt_password(password) Digest::SHA1.hexdigest(password) end end end However, this fails. Says that the class method cannot be found when the instance method calls it. I can call User.encrypt_password('password') but User.new.encrypt_password fails Any thoughts?

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  • Cannot add margin to Legend element in Safari & Chrome

    - by Graham
    I have some pretty straightforward markup: <form action=""> <fieldset class="compact"> <legend>Member Tools</legend> <label for="username">Username</label> <input name="username" id="username" type="text"/> <label for="password">Password</label> <input name="password" id="password" type="password" /> </fieldset> </form> I am attempting to add a small margin to the bottom of the Legend element, this works just fine in Firefox 2 and 3 as well as IE 5-8, however in Safari and Chrome adding a margin does nothing. As far as I know legend is just another block level element and Webkit should have no issue adding a margin to it, or am I incorrect?

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  • iPhone: Issue disabling Auto-Cap/autocorrect on a UITextField

    - by phil swenson
    For some reason, even though I disable the auto-cap and auto-correct of my UITextField, it's still capitalizing the first letter of my input. Here is the code: UITextField* textField = [[[UITextField alloc] initWithFrame:CGRectMake(90.0, 10.0, 213.0, 25.0)] autorelease]; [textField setClearButtonMode:UITextFieldViewModeWhileEditing]; textField.returnKeyType = UIReturnKeyGo; textField.autocorrectionType = FALSE; textField.autocapitalizationType = UITextAutocapitalizationTypeNone; textField.delegate = self; if (inputFieldType == Email) { label.text = @"Email:"; textField.keyboardType = UIKeyboardTypeEmailAddress; emailTextField = textField; textField.placeholder = @"Email Address"; } else { // password textField.secureTextEntry = TRUE; label.text = @"Password:"; if (inputFieldType == Password){ textField.placeholder = @"Password"; passwordTextField = textField; } if (inputFieldType == ConfirmPassword){ textField.placeholder = @"Confirm Password"; confirmPasswordTextField = textField; } } See screenshot:

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  • Unable to compare valuesfrom mysql in a prepared statement

    - by Cortopasta
    I can't seem to get this to connect to the database so that I can run my prepared statement. Does anybody have an idea what I've forgotten? private function check_credentials($plain_username, $password) { global $dbcon; $ac = new ac(); $ac->dbconnect(); $userid = $dbcon->prepare('SELECT id FROM users WHERE username = :username AND password = :password LIMIT 1'); $userid->bindParam(':username', $plain_username); $userid->bindParam(':password', $password); $userid->execute(); $id = $userid->fetch(); Return $id; } EDIT: I changed the SQL query from a SELECT FROM query, to an INSERT INTO query and it worked. WHat the heck is going on?

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  • Invalid character in a Base-64 string

    - by swetha
    I am getting this error when I am validating the user with sql membership provider this.provider.ValidateUser(userName, password); the password i have used is "freetrial". I tried trimming the spaces but still no luck!!! and the call stack is as follows: [FormatException: Invalid character in a Base-64 string.] System.Convert.FromBase64String(String s) +0 System.Web.Security.MembershipProvider.EncodePassword(String pass, Int32 passwordFormat, String salt) +54 System.Web.Security.SqlMembershipProvider.CheckPassword(String username, String password, Boolean updateLastLoginActivityDate, Boolean failIfNotApproved, String& salt, Int32& passwordFormat) +169 System.Web.Security.SqlMembershipProvider.CheckPassword(String username, String password, Boolean updateLastLoginActivityDate, Boolean failIfNotApproved) +42 System.Web.Security.SqlMembershipProvider.ValidateUser(String username, String password) +78

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  • PDO prepared statement not working for login system

    - by Cortopasta
    Anybody no what I'm doing wrong here? I have a username and password hashed in my database, but i can't seem to get it to match the one I submit through the script. $res = $dbcon->prepare('SELECT id FROM users WHERE name = :name AND password = MD5(:password)'); $res->bindParam(':name', $user); $res->bindParam(':password', $password); $res->execute(); $row = $res->fetch(); for ($i=0; $i<7; $i++) { $row[$i]; }

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  • Stop browser from filling textboxes with details

    - by TenaciousImpy
    Hi, I've run into a really annoying problem, and I'm hoping it's just a setting I've missed. I've got an ASP.NET application which allows users to enter their username/password in various places (e.g. login, change password, change username etc..). When I logged in, the browser asked if I would like to store the user details. Usually, I click 'no', but this time I decided to click 'yes'. Now, certain textboxes in my form are prefilled with the username or password. Is it possible to remove these, as they sometimes appear in textboxes which shouldn't be prefilled. I tried setting AutoCompleteType=none and Text='' but it still gets prefilled. The textboxes don't have much in common, except the same CssClass and, for password boxes, TextMode=password. The names are different, although sometimes they include the word name (e.g. fullName, userName). Is there a way to stop the browser from filling certain textboxes? Thanks

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  • How can I set controls for a web page ??

    - by Rami Jarrar
    I have this login page with https, and i reach to this approach:: import ClientForm import urllib2 request = urllib2.Request("http://ritaj.birzeit.edu") response = urllib2.urlopen(request) forms = ClientForms.ParseResponseEx(response) response.close() f = forms[0] username = str(raw_input("Username: ")) password = str(raw_input("Password: ")) ## Here What To Do request2 = form.click() i get the controls of that page >>> f = forms[0] >>> [c.name for c in f.controls] ['q', 'sitesearch', 'sa', 'domains', 'form:mode', 'form:id', '__confirmed_p', '__refreshing_p', 'return_url', 'time', 'token_id', 'hash', 'username', 'password', 'persistent_p', 'formbutton:ok'] so how can i set the username and password controls of the "non-form form" f ??? and i have another problem,, how to know if its the right username and password ??

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  • Cookbook: SES and UCM setup

    - by George Maggessy
    The purpose of this post is to guide you setting up the integration between UCM and SES. On my next post I’ll show different approaches to integrate WebCenter Portal, UCM and SES based on some common scenarios. Let’s get started. WebCenter Content Configuration WebCenter Content has a component that adds functionality to the content server to allow it to be searched via the Oracle SES. To enable the component installation, go to Administration -&gt; Admin Server and select SESCrawlerExport. Click the update button and restart UCM_server1 managed server. Once the managed server is back, we’ll configure the component. In the menu, under Administration you should see SESCrawlerExport. Click on the link. You’ll see the window below. Click on Configure SESCrawlerExport. Configure the values below: Hostname: SES hostname. Feed Location: Directory where data feeds will be saved. Metadata List: List of metadata that will be searchable by SES. After updating the values click on the Update button. Come back to the SESCrawlerExport Administration UI and click on Take Snapshot button. It will create the data feeds in the specified Feed Location. To check if the correct configuration was done, please access the following URL http://&lt;ucm_server&gt;:&lt;port&gt;/cs/idcplg?IdcService=SES_CRAWLER_DOWLOAD_CONFIG&amp;source=default. It should download config file in the format below: &lt;?xml version="1.0" encoding="UTF-8"?&gt; &lt;rsscrawler xmlns="http://xmlns.oracle.com/search/rsscrawlerconfig"&gt; &lt;feedLocation&gt;&lt;![CDATA[http://adc6160699.us.oracle.com:16200/cs/idcplg?IdcService=SES_CRAWLER_DOWNLOAD_CONTROL&amp;source=default]]&gt;&lt;/feedLocation&gt; &lt;errorFileLocation&gt;&lt;![CDATA[http://adc6160699.us.oracle.com:16200/cs/idcplg?IdcService=SES_CRAWLER_STATUS&amp;IsJava=1&amp;source=default&amp;StatusFeed=]]&gt;&lt;/errorFileLocation&gt; &lt;feedType&gt;controlFeed&lt;/feedType&gt; &lt;sourceName&gt;default&lt;/sourceName&gt; &lt;securityType&gt;attributeBased&lt;/securityType&gt; &lt;securityAttribute name="Account" grant="true"/&gt; &lt;securityAttribute name="DocSecurityGroup" grant="true"/&gt; &lt;securityAttribute name="Collab" grant="true"/&gt; &lt;/rsscrawler&gt; Make sure Account and DocSecurityGroup values are true. SES Configuration Let’s start by configuring the Identity Plug-ins in SES. Go to Global Settings -&gt; System -&gt; Identity Management Setup. Select Oracle Content Server and click the Activate button. We’ll populate the following values: HTTP endpoint for authentication: URL to WebCenter Content. Notice that /cs/idcplg was added at the end of the URL. Admin User: UCM Admin user. This user must have access to all CPOE content. Password: Password to Admin user. Authentication Type: NATIVE. Go back to the Home tab and click on Sources on the top left. Select Oracle Content Server on the right and click the Create button. Configuration URL: URL that point to the configuration file. Example: http://&lt;ucm_hostname&gt;:&lt;port&gt;/cs/idcplg?IdcService=SES_CRAWLER_DOWNLOAD_CONFIG&amp;source=default. User ID: UCM Admin user. Password: Password to Admin user. Click on the Authorization tab and add the appropriate values to the fields below. Make sure you see the ACCOUNT and DOCSECURITYGROUP security attributes at the end of the page. HTTP endpoint for authorization: http://&lt;ucm_hostname&gt;:&lt;port&gt;/cs/idcplg. Display URL prefix: http://&lt;ucm_hostname&gt;:&lt;port&gt;/cs. Administrator user: UCM Admin user. Administrator password. On the Document Types tab, add the documents that should be indexed by SES. As our last step, we’ll configure the Federation Trusted Entities under Global Settings. Entity Name: The user must be present in both the identity management server configured for your WebCenter application and the identity management server configured for Oracle SES. For instance, I used weblogic in my sample. Password: Entity user password.\ Now you are ready to test the integration on the SES UI: http://&lt;ses hostname&gt;:&lt;port&gt;/search/query/.

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  • Encryption using rijndael

    - by user363295
    Hi all. I'm quite new in programming .I wrote the below code in order to prompt the user for a password to encrypting a file, But it just work when the length of password is 8, What can I do on order to accepting any number of characters for the password? string pass = textBox2.Text.ToString(); string password = @"" + pass + ""; UnicodeEncoding UE = new UnicodeEncoding(); byte[] key = UE.GetBytes(password); FileStream fsCrypt = new FileStream(@"c:\\users\\new", FileMode.Create); name = fsCrypt.Name; RijndaelManaged RMCrypto = new RijndaelManaged(); CryptoStream cs = new CryptoStream(fsCrypt, RMCrypto.CreateEncryptor(key, key), CryptoStreamMode.Write); FileStream fsIn = new FileStream(filename, FileMode.Open); int data; while ((data = fsIn.ReadByte()) != -1) cs.WriteByte((byte)data);

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  • SQL Encryption - Asymmetric Key - 2nd Server

    - by Jason Heine
    Hello, I created an asymmetric key on one of my SQL servers (2008). I encrypted a password field and I am able to retrieve that password just fine on my development server. The issue comes into play where I need to move this data to a production server. Here is the code for the key that was created: CREATE MASTER KEY ENCRYPTION BY PASSWORD='#########' CREATE ASYMMETRIC KEY UserEncryptionKey WITH ALGORITHM = RSA_2048 Now, when I run this on the production server, it creates the key just fine. However, when I run my sproc to get the password, it returns NULL. SQL: SELECT EncryptByAsymKey(AsymKey_ID('UserEncryptionKey'), Password ) FROM Users WHERE UserName = '######' Any thoughts on what I need to do to get the encrypted field to work on multiple SQL Servers? Please let me know if I need to clarify something. Thanks

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  • Why does this regular expression fail?

    - by Stephen
    I have a password validation script in PHP that checks a few different regular expressions, and throws a unique error message depending on which one fails. Here is an array of the regular expressions and the error messages that are thrown if the match fails: array( 'rule1' => array( '/^.*[\d].*$/i', 'Password must contain at least one number.' ), 'rule2' => array( '/^.*[a-z].*$/i', 'Password must contain at least one lowercase letter' ), 'rule3' => array( '/^.*[A-Z].*$/i', 'Password must contain at least one uppercase letter' ), 'rule4' => array( '/^.*[~!@#$%^&*()_+=].*$/i', 'Password must contain at least one special character [~!@#$%^&*()_+=]' ) ); For some reason, no matter what I pass through the validation, the "Special Characters" rule fails. I'm guessing it's a problem with the expression. If there's a better (or correct) way to write these expressions, I'm all ears!

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  • How can I login in a website with Pyhon?

    - by Shady
    How can I do it? I was trying to enter some specified link (with urllib), but to do it, I need to log. I have this source from the site <form id="login-form" action="auth/login" method="post"> <div> <!--label for="rememberme">Remember me</label><input type="checkbox" class="remember" checked="checked" name="remember me" /--> <label for="email" id="email-label" class="no-js">Email</label> <input id="email-email" type="text" name="handle" value="" autocomplete="off" /> <label for="combination" id="combo-label" class="no-js">Combination</label> <input id="password-clear" type="text" value="Combination" autocomplete="off" /> <input id="password-password" type="password" name="password" value="" autocomplete="off" /> <input id="sumbitLogin" class="signin" type="submit" value="Sign In" /> It's possible?

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  • How secure is a PostgreSQL database if my server is stolen?

    - by orokusaki
    If I have a server with a database if top secret data in PostgreSQL and my password is practically impossible to crack (128 character string of all sorts of weird chars, generated by hand). The server password is also uncrackable in theory (basically, ignore the possibility of a password crack on the DB). Aside from a password crack, how easy is it to get the data out of this database? Assumptions: Only the DB exists on the server. There is no password in a PHP script or anything like that The person who has the server is a computer / DB / hard-drive recovery expert I'm not using any hard-drive encryption or anything out of the norm for protection I'm trying to understand the risks involved with somebody gaining physical access to my server's hard-drives.

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  • Why is django.test.client.Client not keeping me logged in.

    - by Mystic
    I'm using django.test.client.Client to test whether some text shows up when a user is logged in. However, I the Client object doesn't seem to be keeping me logged in. This test passes if done manually with Firefox but not when done with the Client object. class Test(TestCase): def test_view(self): user.set_password(password) user.save() client = self.client # I thought a more manual way would work, but no luck # client.post('/login', {'username':user.username, 'password':password}) login_successful = client.login(username=user.username, password=password) # this assert passes self.assertTrue(login_successful) response = client.get("/path", follow=True) #whether follow=True or not doesn't seem to work self.assertContains(response, "needle" ) When I print response it returns the login form that is hidden by: {% if not request.user.is_authenticated %} ... form ... {% endif %} This is confirmed when I run ipython manage.py shell. The problem seems to be that the Client object is not keeping the session authenticated.

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