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• Get ID in GridView

  - by Romil

  Hi, I have One grid say Grid 1 in which there are some columns. There is one view image button, one delete image button and one column which says that color column is Red or Blue. If color column is Red the deleted button is hidden else its shown (Based on user given rights to delete a column or not). Now a user clicks a view button for Red Color Column. If this condition is satisfied, then i want that delete icon should not be present in Grid 2. Grid 2 has 2 columns. One is deleted image button and one is file name (which is uploaded via upload control). So If in Grid One "View Image Button" is clicked for "Red" Column i should be able to hide the delete button from Grid 2. I have tried by writing code in Item command but i am not able to access control of grid2. is this the correct way? Or else suggest me some correct way. Please Make sure that code is compatible with VS 2003. let me know if more inputs are needed. Thanks

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• viewstack causing error 1065 variable not defined issue?

  - by jason

  I've got an flex application where I have a left side TREE control and a viewstack on the right and when someone selects the tree it loads the named viewstack based on the hidden node value of the XML of the tree. But it's throwing a error 1065 variable not defined on a viewstack which worked on the last browser refresh/reload. It's not related to a particular viewstack from what I can tell it just seems to throw the error on certain render events. I've tried to use creationpolicy="all" on the viewstack but it seems to not be of any help. public function treeChanged(event:Event):void { selectedNode=Tree(event.target).selectedItem as XML; //trace(selectedNode.@hidden); //Alert.show([email protected]() + " *"); if([email protected]() == '' || [email protected]() == null){ //Alert.show("NULL !"); return; } mainviewstack.selectedChild = Container(mainviewstack.getChildByName([email protected]())); //Container(mainviewstack.getChildByName(selectedNode.@hidden)); If I add in an alert box before the getchildbyname option the viewstack has time to render and everything works fine, so it leads me to believe the app is not giving it enough time to load the viewstack?

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• How do I send an XML document to an ASP.NET MVC page for manipuation

  - by Decker

  I have some hierarchical data stored as an multiple XML files on the server according to a vendor's schema. In my ASP.NET MVC (2!) application, I'd like the user to choose one of these hierarchies (i.e. file -- I provide a list in my controller's Index action). When the user selects one to "edit" my edit action should return a page that presents the XML hierarchy (it's a representation of a folder tree). So my thoughts are that the view would return HTML that contained a JQuery on load ajax call back to the server for the XML data -- at which point I would present the tree using one of the many JQuery tree controls. On the client side I'd like the user to manipulate the tree and when done, I'd like to post back the new hierarchy where I would replace the original XML file that represents that hierarchy. So my questions are: What form should I use to send the data down? XML or JSON?. If I send down XML then I would have to not only read the XML -- which JQuery can do -- but I would also have to be able to modify that XML and then send it back. Can I use JQuery to modify this XML DOM? And will all the namespace declarations be preserved? What form should I send the data back? If I originally sent the client the hierarchy as JSON (using JsonResult), then presumably I would have a hierarchy of javascript objects. What options would I have to post that back? Would I have to recreate the XML reprentation on the client and post that back? Or should I serialize back to JSON, post that to the server, and then have the server do the work of recreating the XML according to the schema. Thanks for any advice.

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• I am using relational division with EAV, but I need to find results in EAV that have some of the cat

  - by NewToDB

  I have two tables: CREATE TABLE EAV ( subscriber_id INT(1) NOT NULL DEFAULT '0', attribute_id CHAR(62) NOT NULL DEFAULT '', attribute_value CHAR(62) NOT NULL DEFAULT '', PRIMARY KEY (subscriber_id,attribute_id) ) INSERT INTO EAV (subscriber_id, attribute_id, attribute_value) VALUES (1,'color','red') INSERT INTO EAV (subscriber_id, attribute_id, attribute_value) VALUES (1,'size','xl') INSERT INTO EAV (subscriber_id, attribute_id, attribute_value) VALUES (1,'garment','shirt') INSERT INTO EAV (subscriber_id, attribute_id, attribute_value) VALUES (2,'color','red') INSERT INTO EAV (subscriber_id, attribute_id, attribute_value) VALUES (2,'size','xl') INSERT INTO EAV (subscriber_id, attribute_id, attribute_value) VALUES (2,'garment','pants') INSERT INTO EAV (subscriber_id, attribute_id, attribute_value) VALUES (3,'garment','pants') CREATE TABLE CRITERIA ( attribute_id CHAR(62) NOT NULL DEFAULT '', attribute_value CHAR(62) NOT NULL DEFAULT '' ) INSERT INTO CRITERIA (attribute_id, attribute_value) VALUES ('color', 'red') INSERT INTO CRITERIA (attribute_id, attribute_value) VALUES ('size', 'xl') To find all subscribers in the EAV that match my criteria, I use relational division: SELECT DISTINCT(subscriber_id) FROM EAV WHERE subscriber_id IN (SELECT E.subscriber_id FROM EAV AS E JOIN CRITERIA AS CR ON E.attribute_id = CR.attribute_id AND E.attribute_value = CR.attribute_value GROUP BY E.subscriber_id HAVING COUNT() = (SELECT COUNT() FROM CRITERIA)) This gives me an unique list of subscribers who have all the criteria. So that means I get back subscriber 1 and 2 since they are looking for the color red and size xl, and that's exactly my criteria. But what if I want to extend this so that I also get subscriber 3 since this subscriber didn't specifically say what color or size they want (ie. there is no entry for attribute 'color' or 'size' in the EAV table for subscriber 3). Given my current design, is there a way I can extend my query to include subscribers that have zero or more of the attributes defined, and if they do have the attribute defined, then it must match the criteria? Or is there a better way to design the table to aid in querying?

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• JQuery printfunction: no content, no view

  - by Joris

  I got a JQuery printfunction: function doPrintPage() { myWindow = window.open('', '', 'titlebar=yes,menubar=yes,status=yes,scrollbars=yes,width=800,height=600'); myWindow.document.open(); myWindow.document.write(document.getElementById("studentnummer").value); myWindow.document.write(document.getElementById("Voornaam").value + " " + document.getElementById("Tussenvoegsel").value + " " + document.getElementById("Achternaam").value); myWindow.document.write("</br>"); myWindow.document.write("Result"); myWindow.document.write(document.getElementById('tab1').innerHTML); myWindow.document.write("</br>"); myWindow.document.write("Tree"); myWindow.document.write(document.getElementById('tab2').innerHTML); myWindow.document.write("</br>"); myWindow.document.write("Open"); myWindow.document.write(document.getElementById('tab3').innerHTML); myWindow.document.write("</br>"); myWindow.document.write("Free"); myWindow.document.write(document.getElementById('tab4').innerHTML); myWindow.document.close(); myWindow.focus(); } There are 3 gridviews (elements in "tab#"), and on the page that is generated by this script, eacht gridview gets a header (Results, Tree, Open, Free). It is possible that there is no gridview for "Tree". It would be nice if the "tree" header wouldn't be shown either. EDIT: I tried this: if ($('tab4')[0]) {myWindow.document.write("Free"); myWindow.document.write(document.getElementById('tab4').innerHTML); but it seems not to work either... Anyone knows the solution?

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• jsTree: How to create a new ID for the new added node?

  - by marknt15

  Hi, I can normally get the ID of the default tree nodes but my problem is onCreate then jsTree will add a new node but it doesn't have an ID. My question is how can I add an ID to the newly created tree node? What I'm thinking to do is adding the ID HTML attribute to the newly created tree node but how? I need to get the ID of all of the nodes because it will serve as a reference for the node's respective div storage. HTML code: <div class="demo" id="demo_1"> <ul> <li id="phtml_1" class="file"><a href="#"><ins>&nbsp;</ins>Root node 1</a></li> <li id="phtml_2" class="file"><a href="#"><ins>&nbsp;</ins>Root node 2</a></li> </ul> </div> JS code: $("#demo_1").tree({ ui : { theme_name : "apple" }, callback : { onrename : function (NODE, TREE_OBJ) { alert(TREE_OBJ.get_text(NODE)); alert($(NODE).attr('id')); } } }); Cheers, Mark

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• Item rendered via a DataTemplate with any Background Brush renders selection coloring behind item.

  - by Mike L

  I have a ListBox which uses a DataTemplate to render databound items. The XAML for the datatemplate is as follows: <DataTemplate x:Key="NameResultTemplate"> <WrapPanel x:Name="PersonResultWrapper" Margin="0" Orientation="Vertical" Background="{Binding Converter={StaticResource NameResultToColor}, Mode=OneWay}" > <i:Interaction.Triggers> <i:EventTrigger EventName="MouseDown"> <cmd:EventToCommand x:Name="SelectPersonEventCommand" Command="{Binding Search.SelectedPersonCommand, Mode=OneWay, Source={StaticResource Locator}}" CommandParameter="{Binding Mode=OneWay}" /> </i:EventTrigger> </i:Interaction.Triggers> <TextBlock x:Name="txtPersonName" TextWrapping="Wrap" Margin="0" VerticalAlignment="Top" Text="{Binding PersonName}" FontSize="24" Foreground="Black" /> <TextBlock x:Name="txtAgencyName" TextWrapping="Wrap" Text="{Binding AgencyName}" HorizontalAlignment="Left" VerticalAlignment="Bottom" Margin="0" FontStyle="Italic" Foreground="Black" /> <TextBlock x:Name="txtPIDORI" TextWrapping="Wrap" Text="{Binding PIDORI}" HorizontalAlignment="Left" VerticalAlignment="Bottom" Margin="0" FontStyle="Italic" Foreground="Black" /> <TextBlock x:Name="txtDescriptors" TextWrapping="Wrap" Text="{Binding DisplayDescriptors}" Margin="0" VerticalAlignment="Top" Foreground="Black"/> <Separator Margin="0" Width="400" /> </WrapPanel> </DataTemplate> Note that there is a value converter called NameResultToColor which changes the background brush of the rendered WrapPanel to gradient brush depending on certain scenarios. All of this works as I'd expect, except when you click on any of the rendered ListBox items. When you click one, there is only the slightest sign of the selection coloring (the default bluish color). I can see a trace bit of it underneath my gradient-brushed item. If I reset the background brush to "no brush" then the selection rendering works properly. If I set the background brush to a solid color, it also fails to render as I'd expect. How can I get the selection coloring to be on top? What is trumping the selection rendering?

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• I need some help cropping an image in PHP (GD)

  - by evan

  http://i.imgur.com/foT9u.jpg Using that image as an example, here's what I need to do: Crop the blue square to have the same proportional ratio as that of the black square From doing that, I should then be able to resize the blue square to fit into the black square without losing stretching it - It'll retain its proportions. Note: The blue square must be cropped 'from the center'. The original center should remain the center after the crop (it can't be cropped from the top left, for example). Here's what I'm thinking needs to be done (using the, landscape, blue square as the example): Figure out the difference between the black squares width and height Figure out the difference between the blue squares width and height This should tell me how much to crop the blue square by and with how much of a 'top offset' Once it's cropped to fit the black squares proportions, it can then be resized I've been messing around with code similar to: if (BLACK_WIDTH > BLACK_HEIGHT) { $diffHeight = BLACK_WIDTH - BLACK_HEIGHT; $newHeight = $blue_Height - $blue_Height; echo $newHeight; } And using Photoshop to try and get a feel for how this should be done, but it continues to fail .< How should I go about doing this? How can I figure out how much to crop by (depending on if the blue square is landscape or portrait)? How do I then get the offset to retain the blue squares center?

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• Find three numbers appeared only once

  - by shilk

  In a sequence of length n, where n=2k+3, that is there are k unique numbers appeared twice and three numbers appeared only once. The question is: how to find the three unique numbers that appeared only once? for example, in sequence 1 1 2 6 3 6 5 7 7 the three unique numbers are 2 3 5. Note: 3<=n<1e6 and the number will range from 1 to 2e9 Memory limits: 1000KB , this implies that we can't store the whole sequence. Method I have tried(Memory limit exceed): I initialize a tree, and when read in one number I try to remove it from the tree, if the remove returns false(not found), I add it to the tree. Finally, the tree has the three numbers. It works, but is Memory limit exceed. I know how to find one or two such number(s) using bit manipulation. So I wonder if we can find three using the same method(or some method similar)? Method to find one/two number(s) appeared only once: If there is one number appeared only once, we can apply XOR to the sequence to find it. If there are two, we can first apply XOR to the sequence, then separate the sequence into 2 parts by one bit of the result that is 1, and again apply XOR to the 2 parts, and we will find the answer.

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• Filling an Area in visual studio C#

  - by lajoo

  I'm drawing a circle in C# and i have divided it into some parts,i want to fill different parts with different colors,is there anyway to do this? and how?i tried using fillpie() but i couldn't get the arguments to work. here is the code: int r = 150; g.DrawEllipse(Pens.Black, 300 - r, 250 - r, 2 * r, 2 * r); if (p != 0) g.DrawLine(Pens.Black, 300, 250, 300 + r, 250); double sum; sum = 0.0; for (int j = 0; j < p; j++) sum += data[j].value; double angle; angle = 0.0; for (int i = 0; i < p; i++) { angle += (double)(data[i].value / sum) * 2.0 * Math.PI; textBox1.Text += sum.ToString() + " : " + angle.ToString() + ":" + Math.Cos(angle).ToString() + "\r\n"; g.DrawLine(Pens.Black, 300, 250, 300 + (int)(Math.Cos(angle) * r), 250 - (int)(Math.Sin(angle) * r)); //g.FillPie(Brushes.Black, 300-r , 250 - r, r, r ,(float)(angle),(float)(angle+ (data[i].value / sum) * 2.0 * Math.PI)); } this actually divides the circle into different parts,i don't know how to fill them the commented line is where i

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• SWT Drag and Drop support for Text widget

  - by bryantsai

  I've written an application recently using SWT. In one of its dialog box, I have a few widgets, one of which is Text, which is designed to support DND with other widgets. I've first added DND support for the 2 Tree widgets on the same dialog box (both drag source and drop target). Before I added DND support for that Text widget, I noticed that on Linux platform (gtk), SWT Text widget automatically get drag and drop support. That is, I can already drag from the other Tree widgets and drop on this Text (at any position to inserted there), as well as selecting and dragging any text from this Text to other Tree or Text widget. However, this is only working on Linux platform but not on Windows. The same program, if running on Windows, will not have any DND support for that Text widget (Tree widgets of course have DND support since I specifically write for them). So here's what I want to achieve on Windows as well: drop text at any position in Text widget. before dropping and while hovering, able to see the caret position clearly where the intended position to drop. caret position should move along with the mouse cursor. support multi-line in Text widget SOLUTION: DropTarget target = new DropTarget(sytledText, DND.DROP_MOVE | DND.DROP_COPY); target.setTransfer(new Transfer[] { TextTransfer.getInstance() }); target.addDropListener(new StyleTextDropTargetEffect(sytledText)); Use StyledText instead of Text widget Use StyledTextDropTargetEffect (or extend it) and add it as dr op listener

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• Query notation for the sitecore 'source' field in template builder

  - by M.R.

  I am trying to set the the source field of a template using the query notation (or xpath - whichever works), but none of them seems to be working. My content tree is a multisite content tree: France --Page 1 ----Page1A -------Page1AA --Page 2 --Page 3 --METADATA ----Regions US --Page 1 ----Page1A -------Page1AA --Page 2 --Page 3 --METADATA ----Regions Each site has its own METADATA folder, and I want it so that when adding a page inside each of the main country nodes, I want the values to reflect whatever is in the METADATA of that site. I have two different fields for now - a droplink and a treelistex field. So I thought I can just get the parent item that is a country site, and get the metadata folder for that. When I put the following query in both the fields, I get different results: query:./ancestor::*[@@templatename='CountryHome']/METADATA/Regions/* For the droplink field, I get only the first Region (one item) For the treelistex field, I get the entire content tree I then tried to modify the query a little bit and took the 'query' notation out ./ancestor::*[@@templatename='CountryHome']/METADATA/Regions/* If I go to the developer center/xpath builder, and set the context node to any item underneath the main country site, it returns me exactly what I need, but when I put this in the source, I get the entire content tree in both the cases. Help!

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• Alpha blending colors in .NET Compact Framwork 2.0

  - by Adam Haile

  In the Full .NET framework you can use the Color.FromArgb() method to create a new color with alpha blending, like this: Color blended = Color.FromArgb(alpha, color); or Color blended = Color.FromArgb(alpha, red, green , blue); However in the Compact Framework (2.0 specifically), neither of those prototypes are valid, you only get: Color.FromArgb(int red, int green, int blue); and Color.FromArgb(int val); The first one, obviously, doesn't even let you enter an alpha value, but the documentation for the latter shows that "val" is a 32bit ARGB value (as 0xAARRGGBB as opposed to the standard 24bit 0xRRGGBB), so it would make sense that you could just build the ARGB value and pass it to the function. I tried this with the following: private Color FromARGB(byte alpha, byte red, byte green, byte blue) { int val = (alpha << 24) | (red << 16) | (green << 8) | blue; return Color.FromArgb(val); } But no matter what I do, the alpha blending never works, the resulting color always as full opacity, even when setting the alpha value to 0. Has anyone gotten this to work on Compact Framework?

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• Unable to change background colour for JOptionPane

  - by Sunil Kumar Sahoo

  Hi I have created sample progeam which will give same look and feel of a confirm dialog and set the background colour as red. But I donot know what is the problem that my background colour of option is displayed as the default colour but not red. also i need same look and feel of confirm dialog across all platforms. Here is the code that I have written. please help me to solve the issue public class JOptionPaneBackground { public static void main(String[] args) throws Exception { // UIManager.setLookAndFeel(UIManager.getCrossPlatformLookAndFeelClassName()); UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName()); UIDefaults uiDefaults = UIManager.getLookAndFeelDefaults(); List<Object> keys = new ArrayList<Object>(uiDefaults.keySet()); Collections.sort(keys, new Comparator<Object>() { public int compare(Object o1, Object o2) { return (o1.toString()).compareTo(o2.toString()); } }); for (Object key : keys) { System.out.println(String.format("%-40s = %s", key, uiDefaults.get(key))); } UIManager.put("OptionPane.background", Color.red); UIManager.put("Panel.background", Color.red); JOptionPane.showConfirmDialog(null, "Hello World!"); } }

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• How do I get Google Chrome's root bookmarks folder?

  - by Wayne

  Hi, I'm trying to write a better bookmark manager in chrome extensions. The problem is there are no simple examples (that I can find) about how to actually use the bookmarks api (available here: http://code.google.com/chrome/extensions/bookmarks.html ) I've looked at the example source (when I d/led and installed it on my computer it didn't do anything except provide a search box. Typing/typing and pressing return failed to do anything) and can't find anything useful. My ultimate goal is to make an extension that allows me to save pages to come and read later without having to go sign up for an account on some service somewhere. So I plan to create either one or two bookmark folders in the root folder/other bookmarks - at minimum an "unread pages" folder. In that folder I'll create the unread bookmarks. When the user marks the item as read, it will be removed from that folder. So that's what I'm trying to do... any help will be greatly appreciated, even if it's just pointing me to some good examples. UPDATE: ...<script> function display(tree){ document.getElementById("Output").innerHTML = tree; } function start(){ chrome.bookmarks.getTree(display); } </script> </head> <body> <h4 id="Output"></h4> <script> start(); </script> ... That displays [object Object], that suggests (at least to me with a limited JavaScript experience) that an object exists. But how to access the members of that object? changing tree to tree.id or any other of what look to be parameters displays "undefined".

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• I need to speed up a function. Should I use cython, ctypes, or something else?

  - by Peter Stewart

  I'm having a lot of fun learning Python by writing a genetic programming type of application. I've had some great advice from Torsten Marek, Paul Hankin and Alex Martelli on this site. The program has 4 main functions: generate (randomly) an expression tree. evaluate the fitness of the tree crossbreed mutate As all of generate, crossbreed and mutate call 'evaluate the fitness'. it is the busiest function and is the primary bottleneck speedwise. As is the nature of genetic algorithms, it has to search an immense solution space so the faster the better. I want to speed up each of these functions. I'll start with the fitness evaluator. My question is what is the best way to do this. I've been looking into cython, ctypes and 'linking and embedding'. They are all new to me and quite beyond me at the moment but I look forward to learning one and eventually all of them. The 'fitness function' needs to compare the value of the expression tree to the value of the target expression. So it will consist of a postfix evaluator which will read the tree in a postfix order. I have all the code in python. I need advice on which I should learn and use now: cython, ctypes or linking and embedding. Thank you.

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• Why this class assignment is not working in IE

  - by user550750

  I've wrote this peice of code, this works fine in FF and Chrome but not in IE. Why is it? <html> <header> <style type="text/css"> .red{ color: red; } .green{ color: green; } .yellow{ color: yellow; } </style> </header> <body> <div id="mydiv" style="height: 50px">Some contents</div> <div> <input type="radio" value="1" name="change" onclick="onClick(this)">Red</input> <input type="radio" value="2" name="change" onclick="onClick(this)">Green</input> <input type="radio" value="3" name="change" onclick="onClick(this)">Yellow</input> </div> <script type="text/javascript"> function onClick(el){ var className = ""; if(el.value == 1){ className = "red"; }else if(el.value == 2){ className = "green"; }else if(el.value == 3){ className = "yellow"; } document.getElementById("mydiv").setAttribute("class", className); } </script> </body> </html>

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• Thoughts about alternatives to barplot-with-error-bars

  - by gd047

  I was thinking of an alternative to the barplot-with-error-bars plot. To get an idea by example, I roughly 'sketched' what I mean using the following code library(plotrix) plot(0:12,type="n",axes=FALSE) gradient.rect(1,0,3,8,col=smoothColors("red",38,"red"),border=NA,gradient="y") gradient.rect(4,0,6,6,col=smoothColors("blue",38,"blue"),border=NA,gradient="y") lines(c(2,2),c(5.5,10.5)) lines(c(2-.5,2+.5),c(10.5,10.5)) lines(c(2-.5,2+.5),c(5.5,5.5)) lines(c(5,5),c(4.5,7.5)) lines(c(5-.5,5+.5),c(7.5,7.5)) lines(c(5-.5,5+.5),c(4.5,4.5)) gradient.rect(7,8,9,10.5,col=smoothColors("red",100,"white"),border=NA,gradient="y") gradient.rect(7,5.5,9,8,col=smoothColors("white",100,"red"),border=NA,gradient="y") lines(c(7,9),c(8,8),lwd=3) gradient.rect(10,6,12,7.5,col=smoothColors("blue",100,"white"),border=NA,gradient="y") gradient.rect(10,4.5,12,6,col=smoothColors("white",100,"blue"),border=NA,gradient="y") lines(c(10,12),c(6,6),lwd=3) The idea was to use bars like the ones in the second pair, instead of those in the first. However, there is something that I would like to change in the colors. Instead of a linear gradient fill, I would like to adjust the color intensity in accordance with the values of the pdf of the mean estimator. Do you think it is possible? A slightly different idea (where gradient fill isn't an issue) was to use one (or 2 back-to-back) bell curve(s) filled with (solid) color, instead of a rectangle. See for example the shape that corresponds to the letter F here. In that case the bell-curve(s) should (ideally) be drawn using something like plot(x, dnorm(x, mean = my.mean, sd = std.error.of.the.mean)) I have no idea though, of a way to draw rotated (and filled with color) bell curves. Of course, all of the above may be freely judged as midnight springtime dreams :-)

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• how to set a fixed color bar for pcolor in python matplotlib?

  - by user248237

  I am using pcolor with a custom color map to plot a matrix of values. I set my color map so that low values are white and high values are red, as shown below. All of my matrices have values between 0 and 20 (inclusive) and I'd like 20 to always be pure red and 0 to always be pure white, even if the matrix has values that don't span the entire range. For example, if my matrix only has values between 2 and 7, I don't want it to plot 2 as white and 7 as red, but rather color it as if the range is still 0 to 20. How can I do this? I tried using the "ticks=" option of colorbar but it did not work. Here is my current code (assume "my_matrix" contains the values to be plotted): cdict = {'red': ((0.0, 1.0, 1.0), (0.5, 1.0, 1.0), (1.0, 1.0, 1.0)), 'green': ((0.0, 1.0, 1.0), (0.5, 1.0, 1.0), (1.0, 0.0, 0.0)), 'blue': ((0.0, 1.0, 1.0), (0.5, 1.0, 1.0), (1.0, 0.0, 0.0))} my_cmap = matplotlib.colors.LinearSegmentedColormap('my_colormap', cdict, 256) colored_matrix = plt.pcolor(my_matrix, cmap=my_cmap) plt.colorbar(colored_matrix, ticks=[0, 5, 10, 15, 20]) any idea how I can fix this to get the right result? thanks very much.

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• Auditing front end performance on web application

  - by user1018494

  I am currently trying to performance tune the UI of a company web application. The application is only ever going to be accessed by staff, so the speed of the connection between the server and client will always be considerably more than if it was on the internet. I have been using performance auditing tools such as Y Slow! and Google Chrome's profiling tool to try and highlight areas that are worth targeting for investigation. However, these tools are written with the internet in mind. For example, the current suggestions from a Google Chrome audit of the application suggests is as follows: Network Utilization Combine external CSS (Red warning) Combine external JavaScript (Red warning) Enable gzip compression (Red warning) Leverage browser caching (Red warning) Leverage proxy caching (Amber warning) Minimise cookie size (Amber warning) Parallelize downloads across hostnames (Amber warning) Serve static content from a cookieless domain (Amber warning) Web Page Performance Remove unused CSS rules (Amber warning) Use normal CSS property names instead of vendor-prefixed ones (Amber warning) Are any of these bits of advice totally redundant given the connection speed and usage pattern? The users will be using the application frequently throughout the day, so it doesn't matter if the initial hit is large (when they first visit the page and build their cache) so long as a minimal amount of work is done on future page views. For example, is it worth the effort of combining all of our CSS and JavaScript files? It may speed up the initial page view, but how much of a difference will it really make on subsequent page views throughout the working day? I've tried searching for this but all I keep coming up with is the standard internet facing performance advice. Any advice on what to focus my performance tweaking efforts on in this scenario, or other auditing tool recommendations, would be much appreciated.

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• AvoidXferMode Tolerance

  - by kayahr

  I have a problem with the following code: protected void onDraw(Canvas canvas) { Paint paint = new Paint(); // Draw a blue circle paint.setColor(Color.BLUE); canvas.drawCircle(100, 100, 50, paint); // Draw a red circle where it collides with the blue one paint.setXfermode(new AvoidXfermode(Color.BLUE, 0, Mode.TARGET)); paint.setColor(Color.RED); canvas.drawCircle(50, 50, 50, paint); } According to the API documentation of AvoidXfermode the tolerance value 0 means that it looks for an EXACT color match. This should work here because I specify the same color as I used for drawing the first circle. But the result is that the red circle is not drawn at all. When I use a tolerance value of 255 instead then it works (red circle is drawn where it collides with the blue one) but that sounds wrong because with such a high tolerance I think it should draw the circle EVERYWHERE. So what's wrong here? API Documentation? Android? Me?

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• XSLT - How to select top a to top b

  - by user812241

  how can I extract the first 2 C-Values ('Baby' and 'Cola') where B is 'RED'. Input instance is: <Root> <A> <B>BLACK</B> <C>Apple</C> </A> <A> <B>RED</B> <C>Baby</C> </A> <A> <B>GREEN</B> <C>Sun</C> </A> <A> <B>RED</B> <C>Cola</C> </A> <A> <B>RED</B> <C>Mobile</C> </A> </Root> Output instance must be: <Root> <D>Baby</D> <D>Cola</D> </Root> I thought about the combination of for-each and global variables. But in XSLT it is not possible to change the value for a global variable to break the for-each. I have no idea anymore.

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• How to create a new ID for the new added node?

  - by marknt15

  Hi, I can normally get the ID of the default tree nodes but my problem is onCreate then jsTree will add a new node but it doesn't have an ID. My question is how can I add an ID to the newly created tree node? What I'm thinking to do is adding the ID HTML attribute to the newly created tree node but how? I need to get the ID of all of the nodes because it will serve as a reference for the node's respective div storage. HTML code: <div class="demo" id="demo_1"> <ul> <li id="phtml_1" class="file"><a href="#"><ins>&nbsp;</ins>Root node 1</a></li> <li id="phtml_2" class="file"><a href="#"><ins>&nbsp;</ins>Root node 2</a></li> </ul> </div> JS code: $("#demo_1").tree({ ui : { theme_name : "apple" }, callback : { onrename : function (NODE, TREE_OBJ) { alert(TREE_OBJ.get_text(NODE)); alert($(NODE).attr('id')); } } }); Cheers, Mark

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• Whats wrong with this method?

  - by David

  Here's the method: public static String CPUcolor () { System.out.println ("What color am I?") ; String s = getIns() ; System.out.println ("are you sure I'm "+s+"? (Y/N)") ; String a = getIns() ; while (!((a.equals ("y")) || (a.equals ("Y")) || (a.equals ("n")) || (a.equals ("N")))) { System.out.println ("try again") ; a = getIns () ; } if (a.equals ("n") || a.equals("N")) {CPUcolor() ;} System.out.println ("I am "+s) ; return s ; } here is a possible output of this method (y's and n's are user inputs): What color am I? red are you sure I'm red? (Y/N) N What color am I? blue are you sure I'm blue? (Y/N) N What color am I? Yellow are you sure I'm Yellow? (Y/N) y I am Yellow I am blue I am red Why is it that the line's "I am blue" and "I am Blue" printed? Why are they printed in reverse order with red, the first entered, printed last?

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• How do I get rid of the space between <img> elements in a row in a html page?

  - by Aperture

  I'm displaying 3 <img> in a row like this: <div style="width: 950px"> <img src='/UploadedImages/86.jpg' alt='' style="width: 300px; margin: 0px; padding: 0px; border: 1px solid Black" /> <img src='/UploadedImages/85.jpg' alt='' style="width: 300px; margin: 0px; padding: 0px; border: 1px solid Black" /> <img src='/UploadedImages/84.gif' alt='' style="width: 300px; margin: 0px; padding: 0px; border: 1px solid Black" /> </div> As you can see I have thin black borders around the images. My problem is that there are white spaces about 5px wide between the borders of neighbouring images and I have set the margin to be 0px but it does not work. So what is happening here?

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