how to pass the parameters to the urlconnection in java/android?
- by androidbase
hi all,
i can establish a connection using HttpUrlConnection. my code below.
client = new DefaultHttpClient();
URL action_url = new URL(actionUrl);
conn = (HttpURLConnection) action_url.openConnection();
conn.setDoOutput(true);
conn.setDoInput(true);
conn.setRequestProperty("domain", "bschool.hbs.edu");
conn.setRequestProperty("userType", "2");
conn.setRequestProperty("referer", "http://www.alumni.hbs.edu/");
conn.setRequestProperty("Content-Type",
"application/x-www-form-urlencoded");
conn.setRequestMethod(HttpPost.METHOD_NAME);
DataOutputStream ds = new DataOutputStream(conn.getOutputStream());
String content = "username=username1&password=password11";
Log.v(TAG, "content: " + content);
ds.writeBytes(content);
ds.flush();
ds.close();
InputStream in = conn.getInputStream();//**getting filenotfound exception here.**
BufferedReader reader = new BufferedReader(
new InputStreamReader(in));
StringBuilder str1 = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
str1.append(line);
Log.v(TAG, "line:" + line);
}
in.close();
s = str1.toString();
getting filenotfound exception. dont know why?
else give me some suggestion to pass username and passwrod parameter to the url by code..
