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  • URL path changes between dev and published version

    - by Bob Horn
    I just got Scott Hanselman's chat app with SignalR working with ASP.NET MVC 4. After hours of configuration, trial and error, and getting different versions of Windows to talk to each other on my home network, it's all working except that I'm left with one issue that I'm not sure how to handle. This line of javascript has to change, depending on if I'm running the app through Visual Studio or the published (IIS) version: Works when running within VS: var connection = $.connection('echo'); Works with published version: var connection = $.connection('ChatWithSignalR/echo'); When I run within VS, the URL is: http://localhost:9145/ And the published version is: http://localhost/ChatWithSignalR If I don't change that line of code, and try to run the app within VS, using the javascript that has ChatWithSignalR in it, I get an error like this: Failed to load resource: the server responded with a status of 404 (Not Found) http://localhost:9145/ChatWithSignalR/echo/negotiate?_=1347809290826 What can I do so that I can use the same javascript code and have it work in both scenarios? var connection = $.connection('??????'); Note, this is in my Global.asax.cs: RouteTable.Routes.MapConnection<MyConnection>("echo", "echo/{*operation}");

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  • Fastest method to define whether a number is a triangular number

    - by psihodelia
    A triangular number is the sum of the n natural numbers from 1 to n. What is the fastest method to find whether a given positive integer number is a triangular one? I suppose, there must be a hidden pattern in a binary representation of such numbers (like if you need to find whether a number is even/odd you check its least significant bit). Here is a cut of the first 1200th up to 1300th triangular numbers, you can easily see a bit-pattern here (if not, try to zoom out): (720600, '10101111111011011000') (721801, '10110000001110001001') (723003, '10110000100000111011') (724206, '10110000110011101110') (725410, '10110001000110100010') (726615, '10110001011001010111') (727821, '10110001101100001101') (729028, '10110001111111000100') (730236, '10110010010001111100') (731445, '10110010100100110101') (732655, '10110010110111101111') (733866, '10110011001010101010') (735078, '10110011011101100110') (736291, '10110011110000100011') (737505, '10110100000011100001') (738720, '10110100010110100000') (739936, '10110100101001100000') (741153, '10110100111100100001') (742371, '10110101001111100011') (743590, '10110101100010100110') (744810, '10110101110101101010') (746031, '10110110001000101111') (747253, '10110110011011110101') (748476, '10110110101110111100') (749700, '10110111000010000100') (750925, '10110111010101001101') (752151, '10110111101000010111') (753378, '10110111111011100010') (754606, '10111000001110101110') (755835, '10111000100001111011') (757065, '10111000110101001001') (758296, '10111001001000011000') (759528, '10111001011011101000') (760761, '10111001101110111001') (761995, '10111010000010001011') (763230, '10111010010101011110') (764466, '10111010101000110010') (765703, '10111010111100000111') (766941, '10111011001111011101') (768180, '10111011100010110100') (769420, '10111011110110001100') (770661, '10111100001001100101') (771903, '10111100011100111111') (773146, '10111100110000011010') (774390, '10111101000011110110') (775635, '10111101010111010011') (776881, '10111101101010110001') (778128, '10111101111110010000') (779376, '10111110010001110000') (780625, '10111110100101010001') (781875, '10111110111000110011') (783126, '10111111001100010110') (784378, '10111111011111111010') (785631, '10111111110011011111') (786885, '11000000000111000101') (788140, '11000000011010101100') (789396, '11000000101110010100') (790653, '11000001000001111101') (791911, '11000001010101100111') (793170, '11000001101001010010') (794430, '11000001111100111110') (795691, '11000010010000101011') (796953, '11000010100100011001') (798216, '11000010111000001000') (799480, '11000011001011111000') (800745, '11000011011111101001') (802011, '11000011110011011011') (803278, '11000100000111001110') (804546, '11000100011011000010') (805815, '11000100101110110111') (807085, '11000101000010101101') (808356, '11000101010110100100') (809628, '11000101101010011100') (810901, '11000101111110010101') (812175, '11000110010010001111') (813450, '11000110100110001010') (814726, '11000110111010000110') (816003, '11000111001110000011') (817281, '11000111100010000001') (818560, '11000111110110000000') (819840, '11001000001010000000') (821121, '11001000011110000001') (822403, '11001000110010000011') (823686, '11001001000110000110') (824970, '11001001011010001010') (826255, '11001001101110001111') (827541, '11001010000010010101') (828828, '11001010010110011100') (830116, '11001010101010100100') (831405, '11001010111110101101') (832695, '11001011010010110111') (833986, '11001011100111000010') (835278, '11001011111011001110') (836571, '11001100001111011011') (837865, '11001100100011101001') (839160, '11001100110111111000') (840456, '11001101001100001000') (841753, '11001101100000011001') (843051, '11001101110100101011') (844350, '11001110001000111110') For example, can you also see a rotated normal distribution curve, represented by zeros between 807085 and 831405?

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  • Efficient mapping for a particular finite integer set

    - by R..
    I'm looking for a small, fast (in both directions) bijective mapping between the following list of integers and a subset of the range 0-127: 0x200C, 0x200D, 0x200E, 0x200F, 0x2013, 0x2014, 0x2015, 0x2017, 0x2018, 0x2019, 0x201A, 0x201C, 0x201D, 0x201E, 0x2020, 0x2021, 0x2022, 0x2026, 0x2030, 0x2039, 0x203A, 0x20AA, 0x20AB, 0x20AC, 0x20AF, 0x2116, 0x2122 One obvious solution is: y = x>>2 & 0x40 | x & 0x3f; x = 0x2000 | y<<2 & 0x100 | y & 0x3f; Edit: I was missing some of the values, particularly 0x20Ax, which don't work with the above. Another obvious solution is a lookup table, but without making it unnecessarily large, a lookup table would require some bit rearrangement anyway and I suspect the whole task can be better accomplished with simple bit rearrangement. For the curious, those magic numbers are the only "large" Unicode codepoints that appear in legacy ISO-8859 and Windows codepages.

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  • How does the stream manipulators work?

    - by Narek
    It is well known that the user can define stream manipulators like this: ostream& tab(ostream & output) { return output<< '\t'; } And this can be used in main() like this: cout<<'a'<<tab<<'b'<<'c'<<endl; Please explain me how does this all work? If operator<< assumes as a second parameter a pointer to the function that takes and returns ostream &, then please explain my why it is necessary? What would be wrong if the function does not take and return ostream & but it was void instead of ostream &? Also it is interesting why “dec”, “hex” manipulators take effect until I don’t change between them, but user defined manipulators should be always used in order to take effect for each streaming?

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  • C#: Loop through substring patterns in a string

    - by ilann
    my pattern is the following: {(code)} where code is a number (up to 6 digits), or 2 letter followed by a number. For example: {(45367)} {(265367)} {(EF127012)} I want to find all occurrences in a long string, I can't just use pure regex , because I need to preform some action when i find a match (like logging the position and the type of the match).

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  • string update in sqlserver

    - by Thiyaneshwaran S
    Currently i have varchar field. The delimiter is "$P$P$". The delimiter will appear atleast once and atmost twice in the varchar data. Eg. Sample Heading$P$P$Sample description$P$P$Sample conclusion Sample Heading$P$P$Sample Description If the delimiter appears twice, i need to insert a text before the second occurance of the delimiter. Eg: Sample Heading$P$P$Sample DescriptionINSERT TEXT HERE$P$P$Sample Conclusion If the delimiter occurs only once, then i need to insert a text at the end of the field. Eg: Sample Heading$P$P$Sample DescriptionAPPEND TEXT HERE How this can be done in sql query?

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  • Remove specified text from beginning of lines only if present (C#)

    - by Zach
    I have a textbox in which the user can edit text, in a scripting language. I've figured out how to let the user comment out lines in one click, but can't seem to figure out how to uncomment properly. For example, if the box has: Normal Text is here More normal text -- Commented text -- More commented text Normal Text again --Commented Text Again So, when the user selects any amount of text and decides to uncomment, the "--" is removed from the beginning of the lines that have it. The lines without the "--" should be unaffected. In short, I want an uncomment function that performs similar to the one in Visual Studio. Is there any way to accomplish this? Thanks

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  • How do I unpack bits from a structure's stream_data in c code?

    - by Chelp
    Ex. typedef struct { bool streamValid; dword dateTime; dword timeStamp; stream_data[800]; } RadioDataA; Ex. Where stream_data[800] contains: **Variable** **Length (in bits)** packetID 8 packetL 8 versionMajor 4 versionMinor 4 radioID 8 etc.. I need to write: void unpackData(radioDataA *streamData, MA_DataA *maData) { //unpack streamData (from above) & put some of the data into maData //How do I read in bits of data? I know it's by groups of 8 but I don't understand how. //MAData is also a struct. }

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  • Strings - Filling In Leading Zeros Wtih A Zero

    - by headscratch
    I'm reading an array of hard-coded strings of numeric characters - all positions are filled with a character, even for the leading zeros. Thus, can confidently parse it using substring(start, end) to convert to numeric. Example: "0123 0456 0789" However, a string coming from a database does not fill in the leading zero with a 'zero character', it simply fetches the '123 456 789', which is correct for an arithmetic number but not for my needs and makes for parsing trouble. Before writing conditionals to check for leading zeros and adding them to the string if needed, is there a simple way of specifying they be filled with a character ? I'm not finding this in my Java book... I could have done the three conditionals in the time it took to post this but, this is more about 'education'... Thanks

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  • whats wrong with strcpy()

    - by blacktooth
    What is wrong with strcpy() in this code? void process_filedata(char *filename) { void* content; const char * buffer; char * temp; char * row; char * col; int lsize,buflen,tmp,num_scan; //num_scan - number of characters scanned int m=0,p=0,d=0,j=0; //m - machine, p - phase, d- delimiter, j - job FILE *file_pointer = fopen("machinetimesnew.csv","r"); if(file_pointer == NULL) { error_flag = print_error("Error opening file"); if(error_flag) exit(1); } fseek(file_pointer, 0 ,SEEK_END); lsize = ftell(file_pointer); buflen = lsize; rewind(file_pointer); // content = (char*) malloc(sizeof(char)*lsize); fread(content,1,lsize,file_pointer); buffer = (const char*) content; strcpy(temp,buffer); row = strtok(temp,"\n"); ............... ............... I am getting a segmentation fault..

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  • Format String become xxx1, xx10 or 1****, 10*** etc

    - by trycatch4j
    Hi all, I have following numbers : 1, 2, 3, 4, 10 But I want to print those numbers like this: 0001 0002 0003 0004 0010 I have searched in Google. the keyword is number format. But I've got nothing, I just get, format decimal such ass 1,000,000.00. I hope you can suggest me a reference or give me something to solve this problem. Thanks Edit, we can use NumberFormat, or String.format("%4d", somevalue); but it just for adding 0 character before integer. How If I wanna use character such as x, # or maybe whitespace. So the character become: xxxx1 xxx10 or ####1 ###10 or 1#### 10###

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  • How could I insert a string into the response stream anywhere I want?

    - by DM
    There may be an easy way to do this but I can't see it... I created a simple Http Module that starts a timer on the PreRequestHandler and stops the timer on the PostRequestHandler to calculate the time it took the page to load. I then create some simple html and write my results to Response.Write. Since I'm doing this in the PostRequestHandler it's adding my results after the </html> tag. That's fine for testing but I need in a scenario where the page needs to validate. I can't seem to figure out how I could manipulate the Response object to insert my results before the </body> tag. Response.Write and Response.Output.Write don't have that flexibility and I couldn't see a way to work with the Response as a string. Am I missing something easy?

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  • binary number comparison

    - by EquinoX
    If I have a 32 bit two's complement number and I want to know what is the easiest way to know of two numbers are equal... what would be the fastest bitwise operator to know this? I know xor'ing both numbers and check if the results are zero works well... any other one's? how about if a number is greater than 0?? I can check the 31'st bit to see if it's greater or equal to 0..but how about bgtz?

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  • Getting the fractional part of a float without using modf()

    - by knight666
    Hi, I'm developing for a platform without a math library, so I need to build my own tools. My current way of getting the fraction is to convert the float to fixed point (multiply with (float)0xFFFF, cast to int), get only the lower part (mask with 0xFFFF) and convert it back to a float again. However, the imprecision is killing me. I'm using my Frac() and InvFrac() functions to draw an anti-aliased line. Using modf I get a perfectly smooth line. With my own method pixels start jumping around due to precision loss. This is my code: const float fp_amount = (float)(0xFFFF); const float fp_amount_inv = 1.f / fp_amount; inline float Frac(float a_X) { return ((int)(a_X * fp_amount) & 0xFFFF) * fp_amount_inv; } inline float Frac(float a_X) { return (0xFFFF - (int)(a_X * fp_amount) & 0xFFFF) * fp_amount_inv; } Thanks in advance!

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  • Why string.Replace("X","Y") works only when assigned to new string?

    - by Petr
    Hi, I guess it has to do something with string being a reference type but I dont get why simply string.Replace("X","Y") does not work? Why I need to do `string A=stringB.Replace("X","Y") I thought it is just a method to be done on specified instance? Thanks for explanation EDIT: Thank you so far. I extend my question Why "b+="FFF"works but the b.replace is not?

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  • How does one find a '.' in a string object in Object-C

    - by NaZer
    I am working on getting a simple calculator working as part of my adventure to learning Object-C and iOS development. In Object-C using NSString, how does one look for a period in a string? Based on the comments this is what I got so far. NSString * tmp = [display text]; NSLog(@"%@", tmp); // Shows the number on the display correctly int x = [tmp rangeOfString:@"."].location; NSLog(@"%i", x); // Shows some random signed number if (x < 0) { [display setText:[[display text] stringByAppendingFormat:@"."]]; } It is still not working :(

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  • how to retrieve substring from string having variable length of character in php?

    - by user187580
    Hello I have some data in the format of C222 = 50 C1234P687 = 'some text' C123YYY = 'text' C444 = 89 C345 = 3 C122P687 = 'some text' C122YYY = 'text' .... .... so basically 3 different forms "C" number = value, example - C444 = 89 "C" number "P" number = value, example - C123P687 = 'some text' "C" number "YYY" = value Only number is of variable length on the left side of (=) sign. Values vary. I want to store the data in db as INSERT INTO datatable c_id = "number after C" p_id = "number after P" // if it exists for a line of data value = 'value' yyy = 'value' Any ideas how to retrieve these numbers? Thanks

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