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Search found 5274 results on 211 pages for 'submit'.

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  • problem with select boxes - second options based on first selection

    - by Charles Marsh
    Hello All, I just posted a question about opening in a new window but if I use window.location it doesn't work?? is there a problem with my javascript? <script type="text/javascript"> function setOptions(chosen){ var selbox = document.formName.table; selbox.options.length = 0; if (chosen == " ") { selbox.options[selbox.options.length] = new Option('No diploma selected',' '); } if (chosen == "1") { selbox.options[selbox.options.length] = new Option('first choice - option one','http://www.pitman-training.com'); selbox.options[selbox.options.length] = new Option('first choice - option two','onetwo'); } if (chosen == "2") { selbox.options[selbox.options.length] = new Option('second choice - option one','twoone'); selbox.options[selbox.options.length] = new Option('second choice - option two','twotwo'); selbox.options[selbox.options.length] = new Option('second choice - option three','twothree'); selbox.options[selbox.options.length] = new Option('second choice - option four','twofour'); } if (chosen == "3") { selbox.options[selbox.options.length] = new Option('third choice - option one','threeone'); selbox.options[selbox.options.length] = new Option('third choice - option two','threetwo'); } } </script> Its a little messy I know... <form name="formName" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <select name="optone" size="1" onchange="setOptions(document.formName.optone.options[document.formName.optone.selectedIndex].value);"> <option value=" " selected="selected">Please select a diploma</option> <option value="1">First Choice</option> <option value="2">Second Choice</option> <option value="3">Third Choice</option> </select> <select name="table" size="1" > <option value=" " selected="selected">No diploma selected</option> </select> <input type="submit" onclick="ob=this.form.table;window.location(ob.options[ob.selectedIndex].value)"/> </form> to be honest I'm not happy with this anyway I want a way to hide the Submit button until the second selected box has been selected...but I'm no java expert! Can anyone point me in the right direction?

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  • Array within Form collecting multiple values with the same name possible?

    - by JM4
    Good afternoon, I will first start with the goal I am trying to accomplish and then give a very basic sample of what I need to do. Goal Instead of collecting several variables and naming them with keys individually, I have decided to give in and use an array structure to handle all inputs of the same type and rules. Once I have the variables, I will validate against them and if 'ok' store them in a MySQL table. The table will hold consumer information and will need to store multiple rows of the same type of information. First Pass I will leave out the validation portion of this question because I feel I need to first understand the basics. <form action="?" method="POST" name="Form"> Member 1 First Name:<input type="text" name="MemberFirstName[]" /><br /> Member 1 Last Name: <input type="text" name="MemberLastName[]" /><br /> Member 1 Email: <input type="text" name="MemberEmail[]" /><br /> Member 2 First Name:<input type="text" name="MemberFirstName[]" /><br /> Member 2 Last Name: <input type="text" name="MemberLastName[]" /><br /> Member 2 Email: <input type="text" name="MemberEmail[]" /><br /> Member 3 First Name:<input type="text" name="MemberFirstName[]" /><br /> Member 3 Last Name: <input type="text" name="MemberLastName[]" /><br /> Member 3 Email: <input type="text" name="MemberEmail[]" /><br /> <input type="submit" name="submit" value="Continue" /> </form> I am hoping that each input given for First Name (a required field) will generate a unique key for that particular entry and not overwrite any data entered. Because I am carrying information from page to page (checkout form), I am turning the POST variables into SESSION variables then storing in a mysql database in the end. My hope is to have: <?php $conn = mysql_connect("localhost", "username", "password"); mysql_select_db("DBname",$conn); $sql = "INSERT INTO tablename VALUES ('$_SESSION[Member1FirstName]', '$_SESSION[Member1LastName]', '$_SESSION[Member1Email]', '$_SESSION[Member2FirstName]', '$_SESSION[Member2LastName]', '$_SESSION[Member2Email]', '$_SESSION[Member1FirstName]', '$_SESSION[Member3LastName]', '$_SESSION[Member3Email]')"; $result = mysql_query($sql, $conn) or die(mysql_error()); Header ("Location: completed.php"); ?> Where Member1, Member2, and Member3 values will appear on their own row within the table. I KNOW my code is wrong but I am giving a first shot at the overall business purpose I am trying to achieve and trying to learn how to code the right way. I am very, very new to programming so any 'baby advice' is greatly appreciated.

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  • Scrubyt: Using big5 strings in query_field for fill_textfield

    - by kuribo
    Does anyone know of a way to get fill_textfield to accept a big5-encoded string in the query_field? I keep getting an "unterminated string meets end of file" error with this: require 'rubygems' require 'scrubyt' search_data = Scrubyt::Extractor.define do fetch 'http://www.google.com/ncr' fill_textfield 'q', '????' submit end

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  • MVC validation error with strongly typed view

    - by Remnant
    I have a simple form that I would like to validate on form submission. Note I have stripped out the html for ease of viewing <%=Html.TextBox("LastName", "")%> //Lastname entry <%=Html.ValidationMessage("LastName")%> <%=Html.TextBox("FirstName", "")%>//Firstname entry <%=Html.ValidationMessage("FirstName")%> <%=Html.DropDownList("JobRole", Model.JobRoleList)%> //Dropdownlist of job roles <% foreach (var record in Model.Courses) // Checkboxes of different courses for user to select { %> <li><label><input type="checkbox" name="Courses" value="<%=record.CourseName%>" /><%= record.CourseName%></label></li> <% } %> On submission of this form I would like to check that both FirstName and LastName are populated (i.e. non-zero length). In my controller I have: public ActionResult Submit(string FirstName, string LastName) { if (FirstName.Trim().Length == 0) ModelState.AddModelError("FirstName", "You must enter a first name"); if (LastName.Trim().Length == 0) ModelState.AddModelError("LastName", "You must enter a first name"); if (ModelState.IsValid) { //Update database + redirect to action } return View(); //If ModelState not valid, return to View and show error messages } Unfortunately, this code logic produces an error that states that no objects are found for JobRole and Courses. If I remove the dropdownlist and checkboxes then all works fine. The issue appears to be that when I return the View the view is expecting objects for the dropwdownlist and checkboxes (which is sensible as that is what is in my View code) How can I overcome this problem? Things I have considered: In my controller I could create a JobRoleList object and Course object to pass to the View so that it has the objects to render. The issue with this is that it will overwrite any dropdownlist / checkbox selections that the user has already made. In the parameters of my controller method Submit I could aslo capture the JobRoleList object and Course object to pass back to the View. Again, not sure this would capture any items the user has already selected. I have done much googling and reading but I cannot find a good answer. When I look at examples in books or online (e.g. Nerddinner) all the validation examples involve simple forms with TextBox inputs and don't seems to show instances with multiple checkboxes and dropdownlists. Have I missed something obvious here? What would be best practice in this situation? Thanks

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  • how to implement jquery php progress bar

    - by KittyYoung
    I have a multi-step form where the form on Step3 submits to Step4.php. Step4 is a results page, and it takes some time to load, so I wanted to try and implement a progress bar or a loading bar or something when the user clicks the step3 submit button before Step4.php actually loads. I would think I could do this with jquery? But, I'm not sure how. Is it possible to do this without having to use jquery to post the data to step4.php?

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  • Arrays become null after passing to function in PHP

    - by William
    So when I pass my filled arrays to the function createform the form is created with $max_avatars options, but they have no name or value. Why are my arrays becoming null? <?php $avatar_image_name = array('hacker','samurai','cool','happy','thatsnice','angry','tv','bang'); $avatar_name = array('Hacker','Samurai','Cool','Happy','That\'s nice','Angry','TV','Bang'); $max_avatars = 6; createform($max_avatars, $avatar_image_name, $avatar_name); ?> The function createform: function createform($max_avatars, $avatar_image_name, $avatar_name) { $string ='<table id="formtable"> <tr><td class="formtext">Name:</td><td><input type="text" name=name size=25 /></td></tr> <tr><td class="formtext">Trip:</td><td><input type="text" name=trip size=25 /> (<font style="color: #ff0000">Don\'t use your password</font>)</td></tr> <tr><td class="formtext">Comment</td><td><textarea name=post rows="4" cols="50"></textarea></td></tr> <tr><td class="formtext">Avatar:</td> <td> <select name=avatar>'; for($i = 0; $i < $max_avatars; $i++){ $string = ($string . '<option value="'.$avatar_image_name[i].'">'.$avatar_name[i].'</option>'); } $string = ($string . '</select> </td> <tr><td class="formtext">Extra</td><td>Fortune: <input type="radio" name="extra" value="fortune" /> Poker: <input type="radio" name="extra" value="poker" /></td></tr> </table> <input type=submit value="Submit" id="submitbutton">'); echo $string; }

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  • jQuery How do I focus on contents of iframe after clearing

    - by eknown
    I currently have a wysiwyg iframe where the user can submit input to another area on the page. Once the iframe input is submitted, I set it to clear the content. I want to also automatically focus back into the iframe. This is the code I currently have: postContentClr = $("iframe#textarea1IFrame").contents().find("body") postContentClr.html(" ").focus();

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  • how to maintain checkbox status in pagination in php

    - by abdullah
    i ve used pagination. what the problem is for example: i ve 3 pages 1) in the first i'm clicking some checkboxes and 2) i move on to the second and 3) return back to the 1st page the checkbox that i already checked is unchecked. for form submission i need the checkbox status that i ve checked on all pages should be submit. i need a detail description and clear answer for my question. Is anybody there to help me pls.....

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  • Multi-Part form in Codeigniter

    - by Kevin Brown
    I'm building a survey w/ Codeigniter, and it's getting cumbersomely long...so I want to split it up into sections (about 5). If I want each section to validate, and submit to db after the user clicks "next", what is the best way to do this? I've never made a multi-step process before. Any advice for a noob? :)

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  • jQuery Validation plugin, IE7 "SCRIPT3: Member not found"

    - by jkinz
    I have the following: <html> <head> </head> <body> <div> <form method="post"> <div id="questions"> <label for="question-6">Name of Course:</label> <input type="text" name="name_of_course[response]" value="" id="question-6" class="required"> <label class="control-label" for="reporting-year">Reporting Year: </label> <select name="reporting_year" id="reporting-year"> <option value="-1" selected="selected">Select option...</option> <option value="4">2013-2014</option> <option value="1">2012-2013</option> <option value="2">2011-2012</option> <option value="3">2010-2011</option> </select> </div> <input type="submit" name="submit" value="Save Entry" class="btn"> </form> </div> <script src="//code.jquery.com/jquery.js"></script> <script src="//ajax.aspnetcdn.com/ajax/jquery.validate/1.10.0/jquery.validate.min.js"></script> <script> $(function(){ jQuery.validator.addMethod("notEqual", function(value, element, param) { return this.optional(element) || value !== param; }, "Please select an option"); $('form').validate({ rules:{ 'reporting_year': { notEqual: "-1" } } }); }); </script> </body> </html> Everyone's favorite browser, IE7 (IE10 w/compatibility really) is reporting the following error in the console: SCRIPT3: Member not found. jquery.js, line 2525 character 4 Of course IE8 and above work fine, but my client is using IE7.

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  • Passing Variable in load

    - by Tyler
    I have a load action tied to the submit button of a form. jQuery('#content').load("/control/ajxdata/installs.php?country=" + country); jQuery('#content').load("/control/ajxdata/installs.php",{ 'country': country }); The name, and the id of the form element I am trying to utilize is "country" In the error console, I am getting "Error: country is not defined"

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  • Typing enter/return key in selenium

    - by Nathan
    Looking for a quick way to type an enter or return key in Selenium. Unfortunately the form I'm trying to test (not my own code so I can't modify) doesn't have a submit button. When working with it manually, I just type enter or return, and just need to know how to do that with the Selenium "type" command

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  • Pass deeply nested element to function in JQuery

    - by klez
    I have this form: <form action="contact.php" method="post" id="contactform"> <ol> <li> <label for="name">First Name * </label> <input id="name" name="name" class="text" /> </li> <li> <label for="email">Your email * </label> <input id="email" name="email" class="text" /> </li> <li> <label for="company">Company</label> <input id="company" name="company" class="text" /> </li> <li> <label for="subject">Subject</label> <input id="subject" name="subject" class="text" /> </li> <li> <label for="message">Message * </label> <textarea id="message" name="message" rows="6" cols="50"></textarea> </li> <li class="buttons"> <input type="image" name="imageField" id="imageField" src="images/send.gif" /> </li> </ol> </form> This javascript function that does some basic validation: function validateRequired(field,alerttxt) { with (field) { if (value==null||value=="") { alert(alerttxt); return false; } return true; } } And this script (written with jquery) to intercept the submit event jQuery(document).ready(function(){ $('#contactform').submit(function(){ ... }); }); The problem is that, inside the last script I want to call validateRequired passing each required input/textarea (namely: name, email and message) as first parameter. I tried like this: validateRequired($('#name')); but it doesn't work. How can I do this?

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  • How to make Google Chrome JavaScript console persistent?

    - by zladuric
    Since I'm building a dynamic site, I need to track the changes between pages, ie. Ajax calls, POST, GET stuff and similar stuff. I'm looking for the same functionality like in Firebug (where you can enable "persistent" and the console is not cleared every time you reload a page or submit a form. So, my questions is: is there a way to make Google Chrome JavaScript console persistent? (And if yes, how?)

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  • Search functionality in a lightbox

    - by Salil
    Hi All, I have a page on which there is a link search. onclicking search i open a LIGHTBOX where i get a textfield and Search button. Now i want when i enter keyword in textfield and enter on submit button a result should be shown in a lighbox only. is it possible w/o ajax or i have to use ajax form only. just curious why we used get request instead of post request for Search functionality.

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  • how to handle a array of objects in a session

    - by Robert
    Hello, In the project I'm working on I have got a list List<Item> with objects that Is saved in a session. Session.Add("SessionName", List); In the Controller I build a viewModel with the data from this session var arrayList = (List<Item>)Session["SessionName"]; var arrayListItems= new List<CartItem>(); foreach (var item in arrayList) { var listItem = new Item { Amount = item.Amount, Variant= item.variant, Id = item.Id }; arrayListItems.Add(listItem); } var viewModel = new DetailViewModel { itemList = arrayListItems } and in my View I loop trough the list of Items and make a form for all of them to be able to remove the item. <table> <%foreach (var Item in Model.itemList) { %> <% using (Html.BeginForm()) { %> <tr> <td><%=Html.Hidden(Settings.Prefix + ".VariantId", Item .Variant.Id)%> <td> <%=Html.TextBox(Settings.Prefix + ".Amount", Item.Amount)%></td> <td> <%=Html.Encode(Item.Amount)%> </td> <td> <input type="submit" value="Remove" /> </td> </tr> <% } %> <% } %> </table> When the post from the submit button is handeld the item is removed from the array and post back exactly the same viewModel (with 1 item less in the itemList). return View("view.ascx", viewModel); When the post is handled and the view has reloaded the value's of the html.Hidden and Html.Textbox are the value's of the removed item. The value of the html.Encode is the correct value. When i reload the page the correct values are in the fields. Both times i build the viewModel the exact same way. I cant find the cause or solution of this error. I would be very happy with any help to solve this problem Thanx in advance for any tips or help

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  • jquery return false in form

    - by pradeep
    [CODE] function confirmSubmit() { jConfirm('Is the Appointment Confirmed?', 'Confirmation Dialog', function(r) { if(r){return true;} else {return false;} }); } [/CODE] whjen i submit the foem i call this function and use jConfirm from jquery. i print r .its printing properly like true and false.but return false or return true has no effects.it just shows ths pop up and submits the form,does not wait for confirmation. how to solve this?

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  • Why second user login redirects me to /accounts/profile/ url?

    - by drupality
    I am using Django built in view for user login: url(r'^user/login/$', 'django.contrib.auth.views.login', {'template_name': 'users/templates/login.html'}, name='user-login'), After login when I goto user/login again I can login second time. I submit the form and getting: The current URL, accounts/profile/, didn't match any of these. I haven't declare this url in urls.py. What I am doing wrong? Why framework want to redirect to this url?

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