Search Results

Search found 32961 results on 1319 pages for 'java'.

Page 954/1319 | < Previous Page | 950 951 952 953 954 955 956 957 958 959 960 961  | Next Page >

  • Multiply without multiplication, division and bitwise operators, and no loops. Recursion

    - by lxx22
    public class MultiplyViaRecursion{ public static void main(String[] args){ System.out.println("8 * 9 == " + multiply(8, 9)); System.out.println("6 * 0 == " + multiply(6, 0)); System.out.println("0 * 6 == " + multiply(0, 6)); System.out.println("7 * -6 == " + multiply(7, -6)); } public static int multiply(int x, int y){ int result = 0; if(y > 0) return result = (x + multiply(x, (y-1))); if(y == 0) return result; if(y < 0) return result = -multiply(x, -y); return result; } } My question is very simple and basic, why after each "if" the "return" still cannot pass the compilation, error shows missing return.

    Read the article

  • How can I add to List<? extends Number> data structures?

    - by kunjaan
    I have a List which is declared like this : List<? extends Number> foo3 = new ArrayList<Integer>(); I tried to add 3 to foo3. However I get an error message like this: The method add(capture#1-of ? extends Number) in the type List<capture#1-of ? extends Number> is not applicable for the arguments (ExtendsNumber)

    Read the article

  • How to get radio button's id and convert to string?

    - by user3461659
    I am working in Android Studio and am trying to get the ID of the selected radio button and then store the ID in a string. Is this possible? I have tried replacing the .getText() method below with .getId() but it wont let me store it as a string: RadioGroup radioGroup = (RadioGroup) findViewById(R.id.radioGroup); radioGroup.setOnCheckedChangeListener(new RadioGroup.OnCheckedChangeListener() { @Override public void onCheckedChanged(RadioGroup radioGroup, int checkedId) { RadioButton checkedRadioButton = (RadioButton) findViewById(checkedId); String text = checkedRadioButton.getText().toString(); Toast.makeText(getApplicationContext(), text, Toast.LENGTH_SHORT).show(); } });

    Read the article

  • Why is this condition never satisfied ?

    - by Patrick
    I don't know why this condition is never satisfied: I'm comparing two ArrayList values, and it is always false. if ( (Integer) results.get(rank) == (Integer) experts.get(j)) I'm debugging and I have exactly the same 2 values: 3043 and 3043 However it doesn't work. thanks

    Read the article

  • name of class that manipulates the entities

    - by cyberguest
    hi, i have a general question regarding naming convention. if I separate the data and operations into two separate classes. one has the data elements (entity), the other class manipulates the entity class. what do we usually call that class that manipulates the entity class? (the entity I am referring to has nothing to do with any kind of entity framework) manager? controller? operator? manipulator? thanks in advance

    Read the article

  • Expanding collapsed code in Eclipse IDE

    - by rabin
    Instead of going through each (+) sign at the left and clicking them to expand the collapsed code snippets, is there a shortcut or menu item (I couldn't find it, VS has that) to expand all the collapsed code/comments at once? Thanks.

    Read the article

  • the variable only have it value inside while loop?

    - by user1834467
    static void parse(String fileName) throws IOException{ FileReader fileReader=new FileReader((fileName)); BufferedReader bufferedReader = new BufferedReader(fileReader); StringBuilder stringBuilder=new StringBuilder(); String string; StringBuilder myString = null; while((string = bufferedReader.readLine()) != null) { myString =stringBuilder.append(string); String h=myString.toString(); **System.out.println(h);** } } static void parse(String fileName) throws IOException{ FileReader fileReader=new FileReader((fileName)); BufferedReader bufferedReader = new BufferedReader(fileReader); StringBuilder stringBuilder=new StringBuilder(); String string; StringBuilder myString = null; while((string = bufferedReader.readLine()) != null) { myString =stringBuilder.append(string); String h=myString.toString(); } **System.out.println(h);** } when I try the second part of the code, it print out nothing. how can I get the whole h String outside of the while loop? Is it I have to declare the variable h as instance variable instead of local variable?

    Read the article

  • how use in it in main project?

    - by davit-datuashvili
    I have the following interface: public interface MyFunctor { int myFunction(int x); } And I created a class which implements this interface : public class Myfunction1 implements MyFunctor { } how use in main project? i have corrected mistake now i need how run it in main project? i mean in public static void main(String[]args)?

    Read the article

  • Traversing ORM relationships returns duplicate results

    - by NKing253
    I have 4 tables -- store, catalog_galleries, catalog_images, and catalog_financials. When I traverse the relationship from store --> catalog_galleries --> catalog_images in other words: store.getCatalogGallery().getCatalogImages() I get duplicate records. Does anyone know what could be the cause of this? Any suggestions on where to look? The store table has a OneToOne relationship with catalog_galleries which in turn has a OneToMany relationship with catalog_images and an eager fetch type. The store table also has a OneToMany relationship with catalog_financials.

    Read the article

  • Works on development server but it doesn't on Google App Engine (Sessions).

    - by grep
    Hi, I have this code that works just fine on the development server but when I deploy the application, the session isn't created. What am I doing wrong? HttpSession session = req.getSession(true); session.setAttribute("loggedIn", new String("true")); Edit: The sessions are enabled. What I realized now is that the _ah_SESSION variable is not being created, not even on the development server (although it works).

    Read the article

  • Digester: Extracting node name

    - by CaptainHastings
    Hi Guys, Is it possible to extract the node name using apache digester? So, if the xml looks like <furniture> <sofa> ..... </sofa> <coffeeTable> ..... </coffeeTable> </furniture> is it possible to extract the node name "sofa", "coffeeTable"? I know it is possible using xpath but is it possible using digester? Cheers

    Read the article

  • correct method "get next value"

    - by kapec
    Hello!! i need your help! this is my code, it not so good as i wander - it is not working. i have not idea anymore. </code>// need to get next parameter static double getParametr(){ Scanner scanner = new Scanner(System.in); param = scanner.nextDouble(); return param; } .......... ................ if (i==1){ System.out.println("vvedite storoni pryamougolnika: "); Shape parA = new Rectangle(); parA.a = Shape.getParametr(); --- this is ok double aa = parA.a; Shape parB = new Rectangle(); parB.b = Shape.getParametr(); ------ this is no work!!! double bb = parB.b; Rectangle rec = new Rectangle(aa, bb); arrayFigur[i] = rec.area(); } how fix mistake?

    Read the article

  • Are there any data-binding solution that works in C++ and GWT and supports structures polymorphism?

    - by user116854
    I expect it should share a common description, like XmlSchema or IDL and should generate classes for target language. I found Thrift and it's really nice solution, but it doesn't support structures polymorphism. I would like to have collections of base class objects, where I could place instances of subclasses, serialize this and deserialize at the opposite side. Some mechanism of polymorphic behavior support, like Visitor, would be a perfect. Does anybody know something suitable for these requirements?

    Read the article

  • programming help

    - by user208639
    class Person holds personal data Its constructor receives 3 parameters, two Strings representing first and last names and an int representing age public Person(String firstName, String lastName, int age) { its method getName has no parameters and returns a String with format "Lastname, Firstname" its method getAge takes no parameters and returns an int representing the current age its method birthday increases age value by 1 and returns the new age value Create the class Person and paste the whole class into the textbox below public class Person { public Person(String first, String last, int age) { getName = "Lastname, Firstname"; System.out.print(last + first); getAge = age + 1; return getAge; System.out.print(getAge); birthday = age + 1; newAge = birthday; return newAge; } } im getting errors such as "cannot find symbol - variable getName" but when i declare a variable it still not working, i also wanted to ask if i am heading in the right direction or is it all totally wrong? im using a program called BlueJ to work on.

    Read the article

  • OverRiding Help

    - by user445714
    Few questions on over riding. I am interiting a method openRead from another class, the method is to be overridden so that the scanner class uses the provided delimiter pattern, which is referenced. I need to make use of the scanner class useDelmiter method method from another class [code] public boolean openRead() throws FileNotFoundException { sc = new Scanner(new File(fileName)); if (fileName != null) { return true; } else { return false; } } [/code] delimiter [code] protected final String DELIMITERS = "[\s[^'a-zA-Z]]"; [/code] I'm at a loss to how i over ride this using the constant delimiter.

    Read the article

< Previous Page | 950 951 952 953 954 955 956 957 958 959 960 961  | Next Page >