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  • Httpclient not returning entire response

    - by whakojacko
    Using HttpClient 4.0, Im having an issue where the response I get from the ResponseHandler is only about half of what the actual page content should be (~61k bytes in the string vs ~125k in the page returned to a browser). I cant seem to find any place where there might be some sort of limit that would limit this. Any ideas?

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  • priority queue implementation

    - by davit-datuashvili
    i have implemented priority queue and i am interested if it is correct public class priqueue { private int n,maxsize; int x[]; void swap(int i,int j){ int t=x[i]; x[i]=x[j]; x[j]=t; } public priqueue(int m){ maxsize=m; x=new int [maxsize+1]; n=0; } void insert(int t){ int i,p; x[++n]=t; for (i=n;i>1 && x[p=i/2] >x[i];i=p) swap(p,i); } public int extramin(){ int i,c; int t=x[1]; x[1]=x[n--]; for (i=1;(c=2*i)<=n;i=c){ if (c+1<=n && x[c+1]<x[c]) c++; if (x[i]<=x[c]) break; swap(c,i); } return t; } public void display(){ for (int j=0;j<x.length;j++){ System.out.println(x[j]); } } } public class priorityqueue { public static void main(String[] args) { priqueue pr=new priqueue(12); pr.insert(20); pr.insert(12); pr.insert(22); pr.insert(15); pr.insert(35); pr.insert(17); pr.insert(40); pr.insert(51); pr.insert(26); pr.insert(19); pr.insert(29); pr.insert(23); pr.extramin(); pr.display(); } } //result: 0 12 15 17 20 19 22 40 51 26 35 29 23

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  • help with google android

    - by hero
    how powerfull is google android bluetooth programming? is it considered a low level programming langauge/emulator that enables me to have full control over bluetooth? ie protocols,encryption,layers....

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  • JVM memory management & garbage collection book?

    - by Max
    Hi. Could anyone advice a book (or any other source) that would thoroughly reveal internals of JVM memory management & garbage collection (optimization, work, circular references, pecularities, discussions for various JVM impls...)? [What I've found so far are separate articles devoted to various aspects but no weighty tome :). Some good materials for Hotspot implementation are here. ] Thanks a lot for any advice you give.

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  • How do I "valueOf" an enum given a class name?

    - by stevemac
    Lets say I have a simple Enum called Animal defined as: public enum Animal { CAT, DOG } and I have a method like: private static Object valueOf(String value, Class<?> classType) { if (classType == String.class) { return value; } if (classType == Integer.class) { return Integer.parseInt(value); } if (classType == Long.class) { return Long.parseLong(value); } if (classType == Boolean.class) { return Boolean.parseBoolean(value); } // Enum resolution here } What can I put inside this method to return an instance of my enum where the value is of the classType? I have looked at trying: if (classType == Enum.class) { return Enum.valueOf((Class<Enum>)classType, value); } But that doesn't work.

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  • Why do I get a Null Pointer Exception?

    - by Roman
    I have this code: Manager manager = new Manager("Name"); MyWindowListener windowListener = new MyWindowListener(); manager.addWindowListener(windowListener); Eclipse writes that I have a NullPointerException in the last line. What can be the reason for that. I do have constructors in the Manager and MyWindowListener. If it's important MyWindowListener implements WindowListener.

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  • Calculations coming out to 0.0?

    - by Nick Gibson
    A simple percentage calculation. It wont return a value except 0.0 and I think once or twice it returned 100.0%. Other than that it won't do a thing. I have tried playing with the code in several different ways and it just wont work. for (int loop = 1; loop < loopCount; loop++) { aa = r.nextInt(10+1); abc = (int) aa; String[] userAnswer = new String[x]; int totalQues = (correctAnswer + wrongAnswer), actualQues = (totalQues - 1); if(abc < x) { userAnswer[abc] = JOptionPane.showInputDialog(null,"Question "+quesNum+"\n\n"+questions[abc]+"\n\nA: "+a[abc]+"\nB: "+b[abc]+"\nC: "+c[abc]+"\nD: "+d[abc]+"\nCorrect Answers: "+correctAnswer+"\nWrong Answers: "+wrongAnswer+"\nTotal Questions: "+totalQues); if(userAnswer[abc].equals(answers[abc])) { correctAnswer++; } else { wrongAnswer++; }//else if(actualQues == x); { score = (correctAnswer / actualQues) * 100; JOptionPane.showMessageDialog(null,"The test is finished."); JOptionPane.showMessageDialog(null,"You scored "+score+"%"); }//if }//if }//for

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  • How the clients (client sockets) are identified?

    - by Roman
    To my understanding by serverSocket = new ServerSocket(portNumber) we create an object which potentially can "listen" to the indicated port. By clientSocket = serverSocket.accept() we force the server socket to "listen" to its port and to "accept" a connection from any client which tries to connect to the server through the port associated with the server. When I say "client tries to connect to the server" I mean that client program executes "nameSocket = new Socket(serverIP,serverPort)". If client is trying to connect to the server, the server "accepts" this client (i.e. creates a "client socket" associated with this client). If a new client tries to connect to the server, the server creates another client socket (associated with the new client). But how the server knows if it is a "new" client or an "old" one which has already its socket? Or, in other words, how the clients are identified? By their IP? By their IP and port? By some "signatures"? What happens if an "old" client tries to use Socket(serverIP,serverIP) again? Will server create the second socket associated with this client?

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  • MediaType of REST

    - by user357243
    Hi, I am beginner in REST web services. I wrote a program of REST to display the HTML or XML. The @Path annotation's value is @Path("{typeDocument}"). There are two methods for GET : @GET @Produces(MediaType.TEXT_XML) public String getXml(@PathParam("typeDocument") String typeDocument) to display XML file, and @GET @Produces(MediaType.TEXT_HTML) public String getHtml(@PathParam("typeDocument") String typeDocument) to display HTML. The browser Firefox always excutes getHtml() when URL is either http://localhost:8080/sources/html or localhost:8080/sources/xml But IE always excutes getXml(). How to excute the correct method, as defined by URL, in different browser ? Thanks a lot.

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  • How to make compareTo sort a list alphabetically?

    - by Alex
    Hi How do I change my code so that it lists the elements in alphabetical order from a to z. Right now it's ordering from z to a. I can't figure it out and am stuck :-/ String sName1 = ((Address)o).getSurname().toLowerCase(); String sName2 = (this.surname).toLowerCase(); int result = (sName1).compareTo(sName2); return result; Thanks :)

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  • Format String become xxx1, xx10 or 1****, 10*** etc

    - by trycatch4j
    Hi all, I have following numbers : 1, 2, 3, 4, 10 But I want to print those numbers like this: 0001 0002 0003 0004 0010 I have searched in Google. the keyword is number format. But I've got nothing, I just get, format decimal such ass 1,000,000.00. I hope you can suggest me a reference or give me something to solve this problem. Thanks Edit, we can use NumberFormat, or String.format("%4d", somevalue); but it just for adding 0 character before integer. How If I wanna use character such as x, # or maybe whitespace. So the character become: xxxx1 xxx10 or ####1 ###10 or 1#### 10###

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  • @Path and regular expression (Jersey/REST)

    - by Castanho
    Hi there! I'm using Jersey in a REST project and I'm needing to use regular expression. Digging about it is simple like: @Path("/resources) public class MyResource { @GET @Path("{subResources:.*}/bar") public String get() {...} } But, I'm only capable of using regex if in my @Path contains a variable or text value, example: @Path("{SubResource1}/{subResources:.*}/bar") Or @Path("hardCodeString/{subResources:.*}/bar") Today I could run with this solution of a variable, but is not oK for my perspective. Question Does anyone have worked with something related? I'm doing something wrong? I think that this could be a bug, when working with more then one @Path, one in the Class and other in the Method. Any tips is appreciated! Regards

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  • starting index from 1 not from 0

    - by M.H
    My question is simple (I think it is silly too) ,how can I start the index in an ArrayList from 1 instead of 0 ? is this possible directly (I mean is there a code for this ) ?. Actually a friend asked me this question today, first I thought that it is a silly question but after a while I thought if there is a direct way to do that and decided to ask it to you (maybe you have some brilliant ideas :) )

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  • download html source android?

    - by mars
    I'm trying to download a website source code and display it in a textbox but I seem to get an error and can't figure it out :s public void getHtml() throws ClientProtocolException, IOException { HttpClient httpClient = new DefaultHttpClient(); HttpContext localContext = new BasicHttpContext(); HttpGet httpGet = new HttpGet("http://www.spartanjava.com"); HttpResponse response = httpClient.execute(httpGet, localContext); String result = ""; BufferedReader reader = new BufferedReader( new InputStreamReader( response.getEntity().getContent() ) ); String line = null; while ((line = reader.readLine()) != null){ result += line + "\n"; Toast.makeText(activity.this, line.toString(), Toast.LENGTH_LONG).show(); } } how come this doesn't work and throw an IOException?

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