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  • Connecting flex/php to Active Directory

    - by modz0r
    Is there a way to connect my flex web application to Active Directory, and get the logged username? Right now we have a PHP script connected to the flex application, that gets user/pass input from the user and checks if there's such user in the AD, and that the password is correct. I don't want to ask for user/pass, but to make the application get the domain username that connected to it, so I could use it (check if the user has access to my application and such). Is there a way to do so?

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  • Password remember does not work properly

    - by sweetsecret
    On the website I am working on it has been deployed but the problem I am facing is that when I enter a username and password and click on the check box to remember...It remembers the password for sometime.. wen I login in after 5 or 10 minutes it remembers the password but aftr a long period of time like about 2hours it forgets the username and password and i have to type it in all over again... this dint used to happen with the old server as even I could sign in and it remembered the password the next day until i log off... what can be the reason The session state im using is:

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  • Turning user ID into name (seperate tables) in PHP

    - by mobile
    I am currently trying to display the username of people who i am following, the problem is that during the following process, only the ID of me and the person i'm following is stored. I've got it to the point where the ID's are displayed but i'd like to show the names hyperlinked. $p_id is the profile ID. Here's what I've got: $following = mysql_query("SELECT `follower`, `followed` FROM user_follow WHERE follower=$p_id"); I am following: <?php while($apple = mysql_fetch_array($following)){ echo '<a href="'.$apple['followed'].'">+'.$apple['followed'].'</a> '; }?> The usernames are in a different table "users" under the field "username" - I need them to match up with the ID's that are currently displayed, and be displayed. Any help appreciated, thanks guys

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  • In PHP can I check a boolean on a function call?

    - by Chris
    I have a function which checks the passed value and returns false or true, if false I want it to add something to an array. The code I've written is below. if(!check_input($_POST['username'])){ $errors[] = "Username"; } Right now it adds to my array anyway, regardless of what is entered in the form. Is the way I've written that the correct way to check if the return from check_input() is false? I've checked the function's logic by altering the returns to echoes and it's returning the correct value, I'm just not sure if I'm checking it wrong. I'd previously attempted to write it as $X=check_input etc, and then if(check_value == false) but that doesn't seem to give me the desired result either. Hmmm a quick pointer please!

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  • $.post is not working

    - by BEBO
    i am trying to post data to Mysql using jquery $.post and php page. my code is not running and nothing is added to the mysql table. I am not sure if the path i am creating is wrong but any help would be appreciated. Jquery location: f_js/tasks/TaskTest.js <script type="text/javascript"> $(document).ready(function(){ $("#AddTask").click(function(){ var acct = $('#acct').val(); var quicktask = $('#quicktask').val(); var user = $('#user').val(); $.post('addTask.php',{acct:acct,quicktask:quicktask,user:user}, function(data){ $('#result').fadeIn('slow').html(data); }); }); }); </script> addTask.php (runs the jqeury code) <?php include 'dbconnect.php'; include 'sessions.php'; $acct = $_POST['acct']; $task = $_POST['quicktask']; $taskstatus = 'Active'; //get task Creator $user = $_POST['user']; //query task creator from users table $allusers = mysql_query("SELECT * FROM users WHERE username = '$user'"); while ($rows = mysql_fetch_array($allusers)) { //get first and last name for task creator $taskOwner = $rows['user_firstname']; $taskOwnerLast = $rows['user_lastname']; $taskOwnerFull = $taskOwner." ".$taskOwnerLast; mysql_query("INSERT INTO tasks (taskresource, tasktitle, taskdetail, taskstatus, taskowner, taskOwnerFullName) VALUES ('$acct', '$task', '$task', '$taskstatus', '$user', '$taskOwnerFull' )"); echo "inserted"; } ?> Accountview.php finally the front page <html> <div class="input-cont "> <input type="text" class="form-control col-lg-12" placeholder="Add a quick Task..." name ="quicktask" id="quicktask"> </div> <div class="form-group"> <div class="pull-right chat-features"> <a href="javascript:;"> <i class="icon-camera"></i> </a> <a href="javascript:;"> <i class="icon-link"></i> </a> <input type="button" class="btn btn-danger" name="AddTask" id="AddTask" value="Add" /> <input type="hidden" name="acct" id="acct" value="<?php echo $_REQUEST['acctname']?>"/> <input type="hidden" name="user" id="user" value="<?php $username = $_SESSION['username']; echo $username?>"/> <div id="result">result</div> </div> </div> <!-- js placed at the end of the document so the pages load faster --> <script src="js/jquery.js"></script> <script src="f_js/tasks/TaskTest.js"></script> <!--common script for all pages--> <script src="js/common-scripts.js"></script> <script type="text/javascript" src="assets/gritter/js/jquery.gritter.js"></script> <script src="js/gritter.js" type="text/javascript"></script> <script> </html> Firebug reponse: Response Headers Connection Keep-Alive Content-Length 0 Content-Type text/html Date Fri, 08 Nov 2013 21:48:50 GMT Keep-Alive timeout=5, max=100 Server Apache/2.4.4 (Win32) OpenSSL/0.9.8y PHP/5.4.16 X-Powered-By PHP/5.4.16 refresh 5; URL=index.php Request Headers Accept */* Accept-Encoding gzip, deflate Accept-Language en-US,en;q=0.5 Content-Length 13 Content-Type application/x-www-form-urlencoded; charset=UTF-8 Cookie PHPSESSID=6gufl3guiiddreg8cdlc0htnc6 Host localhost Referer http://localhost/betahtml/AccountView.php?acctname=client%201 User-Agent Mozilla/5.0 (Windows NT 6.3; WOW64; rv:25.0) Gecko/20100101 Firefox/25.0 X-Requested-With XMLHttpRequest

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  • Error in header function

    - by user1178695
    I'm using the php header function for the redirection but it is not working.I'm using the following code. $sql=mysql_query("select * from password where username='$email' and password1 = '$pwd'"); //echo "selct * from password where username='$email' and password = '$pwd'"; $row=mysql_fetch_row($sql); $fieldset=mysql_num_rows($sql); $host=$_SERVER['HTTP_HOST']."/beta/"; if($fieldset>0 && $conEmail !="") { $_SESSION['email']=$email; $_SESSION['Email']=$email; $_SESSION['memberID']=$id; $_SESSION['status']='Admin'; header("location:http://".$host."member.php"); }

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  • file_get_contents not displaying any data

    - by Lance
    I'm doing $info = file_get_contents('http://USERNAME:[email protected]/v2/sales?client_key=CLIENT_KEY'); $info returns nothing. However, when I put the URL into my browser, JSON appears. I tried using cURL without any luck. $data = array('client_key' => 'CLIENT_KEY'); $link = "http://api.appfigures.com/v2/sales"; $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $link); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_setopt($ch, CURLOPT_POST, count($data)); curl_setopt($ch, CURLOPT_POSTFIELDS, http_build_query($data)); curl_setopt($ch, CURLOPT_USERPWD, "username:password"); curl_setopt($ch, CURLOPT_HTTPAUTH, CURLAUTH_BASIC); $jsonData = curl_exec($ch); curl_close($ch); print_r($jsonData); Thanks

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  • Inserting data into a Database

    - by Erebus
    SO I'm making a "basic" login file where a person logs in and the data that person entered on that form gets transfered to another form aka my database/table. I think the problems is here but I'll post the rest of the code. CREATE FUNCTION dbo.Function4 ( parameter1 int = 5, parameter2 datatype ) RETURNS Table1 TABLE (UserName, Password, Password_Confirmation, Assets) AS BEGIN INSERT INTO Table1 (UserName, Password, Password_Confirmation, Assets) VALUES (a,b,c,d); /*SELECT ... FROM ...*/ RETURN END This is the Login Form using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Windows.Forms; namespace Login_Basic { public partial class Form2 : Form { public Form2() { InitializeComponent(); } Form3 Delta = new Form3(); private void label3_Click(object sender, EventArgs e) { } private void Form2_Load(object sender, EventArgs e) { this.Hide(); } private void textBox6_TextChanged(object sender, EventArgs e) { } private void textBox6_KeyPress(object sender, KeyPressEventArgs e) { int i = Convert.ToInt32(e.KeyChar); if (!(Char.IsDigit(e.KeyChar) || Char.IsControl(e.KeyChar) || (e.KeyChar == '.' && this.Text.Contains(".") == false))) e.Handled = true; } private void button1_Click(object sender, EventArgs e) { Delta.Show(); //if (textBox3.Text.Equals("")) //{ // MessageBox.Show("Please enter your username"); //} //else //{ // this.Hide(); //} // if (textBox4.Text.Equals("")) //{ // MessageBox.Show("Please enter your password"); // } // else //{ // this.Hide(); // } // if (textBox5.Text.Equals("")) // { // MessageBox.Show("Please re-enter your password"); // } // else // { // this.Hide(); // } //if (textBox6.Text.Equals("")) //{ // MessageBox.Show("Please enter your amount"); // // } // else // { // this.Hide(); // } } private void button3_Click(object sender, EventArgs e) { this.Hide(); } private void textBox3_TextChanged(object sender, EventArgs e) { } private void textBox4_TextChanged(object sender, EventArgs e) { } private void textBox5_TextChanged(object sender, EventArgs e) { } private void panel2_Paint(object sender, PaintEventArgs e) { /*if (textBox3.Text.Equals("") && textBox4.Text.Equals("") && textBox5.Text.Equals("") && textBox6.Text.Equals("")) { button1.Enabled = false; } else { button1.Enabled = true; }*/ } } } Here's a "Pic" of my database http://s299.photobucket.com/albums/mm305/krsimms123/Code.jpg Thanks in advance (I'll try and check this every few hours so I can help explain anything)

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  • Can't use method return value in write context; Not sure where to go from here

    - by Morgan Green
    This is my source for the variable. <?php if ($admin->get_permissions()=3) echo 'Welcome to the Admin Panel'; else echo 'Sorry, You do not have access to this page'; ?> And the code that I'm actually trying to call with the if statement is: public function get_permissions() { $username = $_SESSION['admin_login']; global $db; $info = $db->get_row("SELECT `permissions` FROM `user` WHERE `username` = '" . $db->escape($username) . "'"); if(is_object($info)) return $info->permissions; else return ''; } This should be a simple way to call my pages that the user is authorized for by using an else if statement. Or So I thought

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  • gauge chart is not displaying any thing

    - by Sandy
    i am trying to display the latest speed in mysql database on guage chart. i have tried so many things but gauge is not display plz any can help me...my code is attached and php part shows the correct value but dont know why guage is not display <?php $host="localhost"; // Host name $username="root"; // Mysql username $password=""; // Mysql password $db_name="mysql"; // Database name $tbl_name="gpsdb"; // Table name // Connect to server and select database. $con=mysql_connect("$host", "$username")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $data = mysql_query("SELECT speed FROM gpsdb WHERE DeviceId=1234 ORDER BY TIME DESC LIMIT 1") or die(mysql_error()); while ($nt = mysql_fetch_assoc($data)) { $speed = $nt['speed']; $jsonTable = json_encode($speed); echo $jsonTable; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="content-type" content="text/html; charset=utf-8"/> <title> Google Visualization API Sample </title> <script type="text/javascript" src="//www.google.com/jsapi"></script> <script type="text/javascript"> google.load('visualization', '1', {packages: ['gauge']}); </script> <script type="text/javascript"> function drawVisualization() { // Create and populate the data table. var data = new google.visualization.DataTable(<?=$speed?>); // Create and draw the visualization. new google.visualization.Gauge(document.getElementById('visualization')). draw(data); } google.setOnLoadCallback(drawVisualization); </script> </head> <body style="font-family: Arial;border: 0 none;"> <div id="visualization" style="width: 600px; height: 300px;"></div> </body> </html>

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  • delete row from mysql through generated table with records

    - by HennySmafter
    I am using 2 pages. On one page it generates a table with the records and a delete button. After pressing delete it goes to the second page which should delete the record. But it doesn't. Below is the code that I am using. PS: The code is adapted from a tutorial I found through Google a while ago. delete_overzicht.php <?php // Load Joomla! configuration file require_once('../../../configuration.php'); // Create a JConfig object $config = new JConfig(); // Get the required codes from the configuration file $server = $config->host; $username = $config->user; $password = $config->password; $database = $config->db; // Connect to db $con = mysqli_connect($server,$username,$password,$database); if (!$con){ die('Could not connect: ' . mysqli_error($con)); } mysqli_select_db($con,$database); // Get results $result = mysqli_query($con,"SELECT * FROM cypg8_overzicht"); echo "<table border='1' id='example' class='tablesorter'><thead><tr><th>Formulier Id</th><th>Domeinnaam</th><th>Bedrijfsnaam</th><th>Datum</th><th>Periode</th><th>Subtotaal</th><th>Dealernaam</th><th>Verwijderen</th></tr></thead><tbody>"; while($row = mysqli_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['formuliernummer'] . "</td>"; echo "<td>" . $row['domeinnaam'] . "</td>"; echo "<td>" . $row['bedrijfsnaam'] . "</td>"; echo "<td>" . $row['datum'] . "</td>"; echo "<td>" . $row['periode'] . "</td>"; echo "<td> &euro; " . $row['subtotaal'] . "</td>"; echo "<td>" . $row['dealercontactpersoon'] . "</td>"; echo "<td><a href='delete.php?id=" . $row['id'] . "'>Verwijderen </a></td>"; echo "</tr>"; } echo "</tbody></table>"; mysqli_close($con); ?> delete.php <?php // Load Joomla! configuration file require_once('../../../configuration.php'); // Create a JConfig object $config = new JConfig(); // Get the required codes from the configuration file $server = $config->host; $username = $config->user; $password = $config->password; $database = $config->db; // Connect to db $con = mysqli_connect($server,$username,$password,$database); if (!$con){ die('Could not connect: ' . mysqli_error($con)); } mysqli_select_db($con,$database); // Check whether the value for id is transmitted if (isset($_GET['id'])) { // Put the value in a separate variable $id = $_GET['id']; // Query the database for the details of the chosen id $result = mysqli_query($con,"DELETE * FROM cypg8_overzicht WHERE id = $id"); } else { die("No valid id specified!"); } ?> Thanks to everyone who is willing to help!

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  • Grails searchable plugin with hasMany

    - by user2624442
    I am using grails searchable plugin to search my domain classes. However, I cannot yet search by my hasMany (skills and interests) fields even though they are of the simple type String. This is my domain class: class EmpactUser { static searchable = [except: ['dateCreated','password','enabled','accountExpired','accountLocked','passwordExpired']] String username String password boolean enabled = true boolean accountExpired boolean accountLocked boolean passwordExpired String email String firstName String lastName String address String phoneNumber String description byte[] avatar byte[] resume Date dateCreated static hasMany = [ skills : String, interests : String, // each user has the ability to list many skills and interests so that they can be matched with a project. ] static constraints = { username blank: false, unique: true password blank: false email email: true, blank: false firstName blank: false lastName blank: false description nullable: true address nullable: true avatar nullable: true, maxSize: 1024 * 1024 * 10 resume nullable: true, maxSize: 1024 * 1024 * 10 phoneNumber nullable: true, matches: "/[(][+]d{3}[)]d+/", maxSize: 30 } } This is the code I am using to search: def empactUserList = EmpactUser.search( searchQuery, [reload: false, result: "every", defaultOperator: "or"]) Am I missing something? Thanks, Alan.

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  • How to configure IIS7 to Redirect member of An active Directory group to static page

    - by user1759075
    On IIS, we have disabled Anonymous authentication and enabled Windows Authentication What we need is to only allow users who are members of an Active Directory security group to access the Access Point at all. All other users should be directed to a static web page that will give them instructions on how to request access. By adding the security group to the website permissions, and removing the \Users group, we have almost achieved this. Users in the group are allowed through, those not in the group are asked for a (Windows) username and password. Instead of requesting the username and password, we want IIS to redirect them to the static page. Please advise me on how can this be done.

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  • Error in PHP with Mysql

    - by maltad
    Hello, Im starting to learn PHP. When I run the script it had an error that said: "Assigned Employee:resource(6) of type (mysql result)" . Please help me and sorry for my bad English Here is the code: include_once 'rnheader.php'; include_once 'rnfunctions.php'; echo ''; echo ' Assigned Employee:'; $query = "SELECT UserName FROM employee where Classification_ClassificationID = '2'"; $result = queryMysql($query); if (!queryMysql($query)) { echo "Query fail: $query" . mysql_error() . ""; } else { var_dump($result); exit; echo ''; // or name="toinsert[]" while ($row = mysqli_fetch_array($result)) { echo '' . htmlspecialchars($row['UserName']) . ''; } } echo ''; ?

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  • How do I require a login for a user in Django?

    - by Di Zou
    In my urls.py I have this: (r'^myapp/$', 'myapp.views.views.index'), (r'^myapp/login/$', 'myapp.views.views.login_user'), In my settings.py I have this: LOGIN_URL = '/myapp/login' In my views.py I have this: @login_required((login_url='/myapp/login/') def index(request): return render_to_response('index.html') def login_user(request): #login stuff return render(request, 'registration/login.html', {'state':state, 'username': username}) I can go to mysite.com/myapp/login and the login page works. However, when I go to mysite.com/myapp/index I do not get redirected to the login page even though I am logged out. Why is that and how do I fix it?

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  • Passing values between pages in JavaScript

    - by buni
    using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.UI; using System.Web.UI.WebControls; using System.Data.SqlClient; using System.Configuration; using System.Text; using System.Web.Services; using System.IO; namespace T_Smade { public partial class ConferenceManagement : System.Web.UI.Page { volatile int i = 0; protected void Page_Load(object sender, EventArgs e) { GetSessionList(); } public void GetSessionList() { string secondResult = ""; string userName = ""; try { if (HttpContext.Current.User.Identity.IsAuthenticated) { userName = HttpContext.Current.User.Identity.Name; } SqlConnection thisConnection = new SqlConnection(@"data Source=ZOLA-PC;AttachDbFilename=D:\2\5.Devp\my DB\ASPNETDB.MDF;Integrated Security=True"); thisConnection.Open(); SqlCommand secondCommand = thisConnection.CreateCommand(); secondCommand.CommandText = "SELECT myApp_Session.session_id FROM myApp_Session, myApp_Role_in_Session where myApp_Role_in_Session.user_name='" + userName + "' and myApp_Role_in_Session.session_id=myApp_Session.session_id"; SqlDataReader secondReader = secondCommand.ExecuteReader(); while (secondReader.Read()) { secondResult = secondResult + secondReader["session_id"].ToString() + ";"; } secondReader.Close(); SqlCommand thisCommand = thisConnection.CreateCommand(); thisCommand.CommandText = "SELECT * FROM myApp_Session;"; SqlDataReader thisReader = thisCommand.ExecuteReader(); while (thisReader.Read()) { test.Controls.Add(GetLabel(thisReader["session_id"].ToString(), thisReader["session_name"].ToString())); string[] compare = secondResult.Split(';'); foreach (string word in compare) { if (word == thisReader["session_id"].ToString()) { test.Controls.Add(GetButton(thisReader["session_name"].ToString(), "Join Session")); } } } thisReader.Close(); thisConnection.Close(); } catch (SqlException ex) { } } private Button GetButton(string id, string name) { Button b = new Button(); b.Text = name; b.ID = "Button_" + id + i; b.Command += new CommandEventHandler(Button_Click); b.CommandArgument = id; i++; return b; } private Label GetLabel(string id, string name) { Label tb = new Label(); tb.Text = name; tb.ID = id; return tb; } protected void Button_Click(object sender, CommandEventArgs e) { Response.Redirect("EnterSession.aspx?session=" + e.CommandArgument.ToString()); } } I have this code when a user clicks a button www.mypage/EnterSession.aspx?session=session_name in the EnterSession.aspx i have used the code below to track the current URL _gaq.push(['pageTrackerTime._trackEvent', 'Category', 'Action', document.location.href, roundleaveSiteEnd]); Now I would also like to track in the Action parameter the session_name from the previous page.see the code below from the previous page test.Controls.Add(GetButton(thisReader["session_name"].ToString(), "Join Session")); Some idea how to do it? Thanx

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  • require user to login in at login screen before giving access to iPhone app that accesses secure web

    - by MikeN
    On iPhone, how do I show a login screen to get username and password before giving access to iPhone app? Also, does the iPhone store a cookie to the secure website like a web browser? I was thinking of giving users to my website a long API key to store in the settings of their iPhone instead of asking them to login with a username/password (seems to be the Slicehost iPhone app approach.) Which is the best way to get a user to login securely? I have full control over the design of the iPhone app and website so have a lot of flexibility.

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  • Error with connecting ftp through php ...

    - by Holicreature
    Hi, I'm trying to connect to my server using php script to upload some files... But it doesn't connect... I dont know what is the error... I'm sure that ftp is enable, i checked it through php_info() What may be the error... <?php error_reporting(E_ALL); $ftp_server = "server.com"; //address of ftp server (leave out ftp://) $ftp_user_name = "Username"; // Username $ftp_user_pass = "Password"; // Password $conn_id = ftp_connect($ftp_server); // set up basic connection $login_result = ftp_login($conn_id,$ftp_user_name,$ftp_user_pass); if ($login_result = ftp_login($conn_id,$ftp_user_name,$ftp_user_pass)) { echo "Connected as ,$ftp_user_name,$ftp_user_pass \n"; } else { echo "Couldn't connect \n"; } ..... ..... .... .... ftp_close($conn_id); // close the FTP stream ?>

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  • Java: How to write "Arabic" in properties file?

    - by SmoothCriminel
    Hi Experts, I want to write "Arabic" in the message resource bundle (properties) file but when I try to save it I get this error: "Save couldn't be completed Some characters cannot be mapped using "ISO-85591-1" character encoding. Either change encoding or remove the character ..." Can anyone guide please? I want to write: global.username = ??? ???????? How should I write the Arabic of "username" in properties file? So, that internationalization works.. BR SC

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  • Non-empty list with null elements returned from Hibernate query

    - by John
    Hi, I'm new to hibernate so not sure if this is an expected behaviour, anyway: Session session = (Session)entityManager.getDelegate(); Criteria criteria = session.createCriteria(myRequest.class); criteria.add(Restrictions.eq("username", username)); criteria.setProjection(Projections.max("accesscount")); List<myRequest> results = criteria.list(); The returned results is a non-empty list with a single null element. I can't think of any reason why it should behave this way, any idea if this is the expected behaviour or have I done something wrong? System is on hibernate/Syabse. Thanks.

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  • How can I get returned value from JavaScript function that contain jQuery.get() ?

    - by Space Cracker
    I have a JavaScript method that call JQuery.get() and i want to return value from itto callee function .. the following is the code : function CheckExistance(userName) { $.get( "JQueryPage.aspx", { name: userName }, function(result) { if (result == "1") { value = true; } else if (result == "0") { value = false; } else if (result == "error") { value = false; } } ); return value; } i want return value; return the value setted in get() function ... i know that get() is asynchronous operation anf i want a solution to do that ?

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  • How to SetCookie() in a System.Net.HttpWebRequest request for another Page2.aspx?

    - by Mike108
    How can I SetCookie in Page1.aspx by a System.Net.HttpWebRequest request for Page2.aspx which handle the SetCookie() function? Page1.aspx and Page2.aspx are in the same webapp. Page1.aspx: protected void Page_Load(object sender, EventArgs e) { string url = "http://localhost/Page2.aspx"; System.Net.HttpWebRequest myReq = (System.Net.HttpWebRequest)System.Net.HttpWebRequest.Create(url); System.Net.HttpWebResponse HttpWResp = (System.Net.HttpWebResponse)myReq.GetResponse(); System.IO.Stream myStream = HttpWResp.GetResponseStream(); } Page2.aspx: protected void Page_Load(object sender, EventArgs e) { string userName = "Lily"; FormsAuthentication.SetAuthCookie(userName, true); }

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  • MySQL Query Problem

    - by user559744
    Hello guys, I'm getting following error message. Please help me. Thanks Notice: Trying to get property of non-object in C:\xampp\htdocs\my\include\user_functions.php on line 34 Here is my Code $conn = db_connection(); if($conn == false) { user_error('Unable to connect to database'); return false; } $query = "UPDATE user SET passwd = '".$new_passwd."' WHERE username = '".$username."' "; $result=$conn->query($query); if($result == false) { user_error('Query Error'.$conn->error); return false; } if($result->num_rows == 1) { echo 'Password changed'; } else { echo 'Failed '; } here is my db_connection function db_connection() { $db = new mysqli('localhost','root','','php_login'); if(!$db) { echo 'Could not connect to database server'; } else { return $db; } }

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