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  • Password remember does not work as needed

    - by sweetsecret
    On the website I am working on it has been deployed but the problem I am facing is that when I enter a username and password and click on the check box to remember...It remembers the password for sometime.. wen I login in after 5 or 10 minutes it remembers the password but aftr a long period of time like about 2hours it forgets the username and password and i have to type it in all over again... this dint used to happen with the old server as even I could sign in and it remembered the password the next day until i log off... what can be the reason The session state im using is:

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  • Hashbytes comparison in stored proceduring not matching record

    - by Michael Itzoe
    The password field in my user table (SQL Server 2008) is encrypted using HASHBYTES on insertion. I have a stored procedure with parameters for the username and plain-text password which does a SELECT using that username and the password sent through HASHBYTES, then returns the user record if it finds a match. The SP is always returning an empty recordset, but if I copy and paste just the SELECT from the SP to a new query window, it returns the matched record. There're no other statements in the SP. I'm missing something here; what is it?

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  • Can tapping next textfield trigger same behavior as "Done" key?

    - by trevrosen
    I've got two textfields in a row for username and password. When you're finished putting in your username, the most natural thing to do is to just tap on the next textfield, like you would with a web form. But that doesn't work -- you can't edit the next field until you press "Done" on the keyboard for the first field and then tap on the second one. My question is: is it possible to set up two textfields so that you end editing on the first one and begin editing the second when you tap the second field?

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  • simple form validation in dancer/perl

    - by devnull
    I am trying to do a simple form validation in perl dancer but I was wondering what would be the best way to validate simple parameters (e.g. field cannot be empty, validity of the email, minimum length of a field) in dancer/perl without any extra plugin or CPAN module here is the code so far post '/register' => sub { my $db = connect_db(); my $sql = 'insert into users (username, email, password, motivation) values (?, ?, ? ,?)'; my $sth = $db->prepare($sql) or die $db->errstr; $sth->execute(params->{'username'}, params->{'email'},params->{'password'}, params->{'motivation'}) or die $sth->errstr; set_flash('Hey you signed up !'); redirect '/thanks'; }; I did google it and I found several ways to do validation using CPAN modules like Form::Foo but how do it without that ?

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  • POST and multiple submit buttons on form (iphone)

    - by Jonathan
    NSString *reqURL = [NSString stringWithFormat:@"%@/login",SERVER_URL]; NSMutableURLRequest *req = [[NSMutableURLRequest alloc]initWithURL:[NSURL URLWithString:reqURL]]; [req setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"content-type"]; NSData *myRequestData = [NSData dataWithBytes:[@"username=whatever&password=whatever" UTF8String] length: [@"username=whatever&password=whatever" length]]; [req setHTTPMethod: @"POST"]; [req setHTTPBody: myRequestData]; NSData *returnData = [NSURLConnection sendSynchronousRequest:req returningResponse: nil error: nil]; NSString *html = [[NSString alloc] initWithData:returnData encoding:NSUTF8StringEncoding]; I got this code from another question I asked. But what happens if there is more than one submit button. I really have no idea how to ask this question. An example of such situation is on the logout page for this site. There are no fields to enter data into, but there are 2 submit buttons. How can I "simulate clicking" on one of those buttons using code like the above (so not using a UIWebView)

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  • Sending passwords over the web

    - by Falmarri
    So I'm working on a mobile platform application that I'd like to have users authenticate over the web. I was wondering the best way to do security. The user is sending a password for HTTP to a php server wich authenticates against a mysql database on the same server. Obviously I don't want to send the password in plain text over the internet, but I also don't want to do 2 SHA hashes. This is what the server looks like (in pseudocode) $pass = $_POST['pass']; if ((get PASSWORD where USERNAME = USERNAME) == SHA($pass)) return PASS; This is pretty standard and I don't think there's any other way to do this. But I was wondering how I should prepare the data before sending it over the internet.

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  • Understanding Nested If.. Else statements

    - by user1174762
    For some reason my PHP login script keeps returning "invalid email/password combination", yet i know I am entering the correct email and password. Does anyone see what I might be doing wrong? <?php $email= $_POST['email']; $password= $_POST['password']; if (!empty($email) && !empty($password)) { $connect= mysqli_connect("localhost", "root", "", "si") or die('error connecting with the database'); $query= "SELECT user_id, email, password FROM users WHERE email='$email' AND password='$password'"; $result= mysqli_query($connect, $query) or die('error with query'); if (mysqli_num_rows($result) == 1) { $row= mysqli_fetch_array($result); setcookie('user_id', $row['user_id']); echo "you are now logged in"; } else { echo "invalid username/password combination"; } } else { echo" you must fill out both username and password"; } ?>

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  • How to return a message from my repository class to my controller and then to my view in asp.net-mvc

    - by Pandiya Chendur
    I use this for checking an existing emailId in my table and inserting it...It works fine how to show message to user when he tries to register with an existing mailId.... if (!taxidb.Registrations.Where(u => u.EmailId == reg.EmailId).Any()) { taxidb.Registrations.InsertOnSubmit(reg); taxidb.SubmitChanges(); } and my controller has this, RegistrationBO reg = new RegistrationBO(); reg.UserName = collection["UserName"]; reg.OrgName = collection["OrgName"]; reg.Address = collection["Address"]; reg.EmailId = collection["EmailId"]; reg.Password = collection["Password"]; reg.CreatedDate = System.DateTime.Now; reg.IsDeleted = Convert.ToByte(0); regrep.registerUser(reg); Any sugesstion how to show "EmailID" already exists to the user with asp.net mvc...

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  • make db connection persistent throught zend framework

    - by kamikaze_pilot
    I'm using zend framework. currently everytime I need to use the db I go ahead and connect to the DB: function connect(){ $connParams = array("host" => $host, "port" => $port, "username" => $username, "password" => $password, "dbname" => $dbname); $db = new Zend_Db_Adapter_Pdo_Mysql($connParams); return $db } so I would just call the connect() function everytime I need to use the db My question is...suppose I want to reuse $db everywhere in my site and only connect once in the very initial stage of the site load and then close the connection right before the site gets sent to the user, what would be the best practice to accomplish this? Which file in Zend should I save $db in, what method should I use to save it (global variable?), and which file should I do the connection closing in?

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  • User authentication in Django. Problems with is_authenticated

    - by tim
    I have one problem with users menu. So, I want, that authenticated user can see his/her profile page and logout (links) in menu. It works (when I logging in) on index page: index, page1, profile, logout ,but, if I go to the, for example, page1 I can see in menu: index, page1, login, not profile and logout. How to fix it? in urls: url(r'^accounts/login/$', 'django.contrib.auth.views.login' ), url(r'^accounts/logout/$', 'django.contrib.auth.views.logout_then_login' ), url(r'^accounts/profile/$', 'my_app.views.profile' ), in views: def profile(request): if not request.user.is_authenticated(): return HttpResponseRedirect("/accounts/login/") else: user = request.user.is_authenticated() return render_to_response('profile.html',locals()) Part of index.html: {% if user.is_authenticated or request.user.is_authenticated %} <li><a href="/accounts/profile/">Profile</a></li> <li><a href="/accounts/logout/">logout</a></li> {% else %} <li><a href="/accounts/login/">login</a></li> {% endif %} login.html: {% extends "index.html" %} {% load url from future %} {% block application %} {% if form.errors %} <p>Try one more time</p> {% endif %} <form method="post" action="{% url 'django.contrib.auth.views.login' %}"> {% csrf_token %} <table> <tr> <td>{{ form.username.label_tag }}</td> <td>{{ form.username }}</td> </tr> <tr> <td>{{ form.password.label_tag }}</td> <td>{{ form.password }}</td> </tr> </table> <input type="submit" value="Login" /> <input type="hidden" name="next" value="{{ next }}" /> </form> {% endblock %} profile.html: {% extends "index.html" %} {% block application %} {% if request.user.is_authenticated %} <p>Welcome, {{ request.user.username }}. Thanks for logging in.</p> {% else %} <p>Welcome, new user. Please log in.</p> {% endif %} {% endblock %}

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  • Please clarify a few points concerning Java Servlets

    - by EugeneP
    suppose, I use Tomcat as a web container. Is it true that once all the servlets found in a web-app/WEBAPPNAME are init(IALIZED) then every change of a Servlet's property will be seen to every session. So session 1 changes a property userName of a Servlet1 from "user1" to "user2" session 1 is closed. session 2 starts. It will see "user2" as the only value of Servlet1.userName property?? Any change of a Servlet's field will be seen to all subsequent sessions? Are servlets singletons, aren't they?

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  • jQuery append breaks my HTML form (with submit button)

    - by JimFing
    I'm trying to create a form with a submit button via jQuery using append(). So the following: out.append('<form name="input" action="/createuser" method="get">'); out.append('Username: <input type="text" name="user" />'); out.append('<input type="submit" value="Submit" />'); out.append('</form>'); However, clicking on submit, nothing happens! However if I do the following: var s = '<form name="input" action="/createuser" method="get">' + 'Username: <input type="text" name="user" />' + '<input type="submit" value="Submit" />' + '</form>'; out.html(s); Then the submit button works fine! I'm happy to use the 2nd method, but would rather know what the problem is here. Thanks

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  • PHP, MySQL - My own version of SALT (I call salty) - Login Issue

    - by Fabio Anselmo
    Ok I wrote my own version of SALT I call it salty lol don't make fun of me.. Anyway the registration part of my script as follows is working 100% correctly. //generate SALTY my own version of SALT and I likes me salt.. lol function rand_string( $length ) { $chars = "ABCDEFGHIJKLMNOPQRSTUWXYZabcdefghijklmnopqrstuwxyz1234567890"; $size = strlen( $chars ); for( $i = 0; $i < $length; $i++ ) { $str .= $chars[ rand( 0, $size - 1 ) ]; } return $str; } $salty = rand_string( 256 ); //generate my extra salty pw $password = crypt('password'); $hash = $password . $salty; $newpass = $hash; //insert the data in the database include ('../../scripts/dbconnect.php'); //Update db record with my salty pw ;) // TESTED WITH AND WITHOUT SALTY //HENCE $password and $newpass mysql_query("UPDATE `Register` SET `Password` = '$password' WHERE `emailinput` = '$email'"); mysql_close($connect); However my LOGIN script is failing. I have it setup to TEST and echo if its login or not. It always returns FAILED. I entered the DB and changed the crypted salty pw to "TEST" and I got a SUCCESS. So my problem is somewhere in this LOGIN script I assume. Now I am not sure how to implement my $Salty in this. But also be advised that even without SALTY (just using crypt to store my pass) - I was still unable to perform a login successfully. And if you're gonna suggest i use blowfish - note that my webhost doesn't have it supported and i don't know how to install it. here's my login script: if (isset($_POST['formsubmitted'])) { include ('../../scripts/dbconnect.php'); $username = mysql_real_escape_string($_POST['username']); $password = crypt(mysql_real_escape_string($_POST['password'])); $qry = "SELECT ID FROM Register WHERE emailinput='$username' AND Password='$password'"; $result = mysql_query($qry); if(mysql_num_rows($result) > 0) { echo 'SUCCESS'; //START SESSION } else { echo 'FAILED'; //YOU ARE NOT LOGGED IN } } So what's wrong with this login? Why isn't it working just using the crypt/storing only crypt? How can i make it work storing both the crypt and randomly generated SALTY :) ? Ty advance

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  • Double Inner Join generates unexpected error

    - by Itamar Marom
    In my database I have three tables: Users: UserID (Auto Numbering), UserName, UserPassword and a few other unimportant fields. PrivateMessages: MessageID (Auto Numbering), SenderID and a few other fields defining the message content. MessageStatus: MessageID, ReceiverID, MessageWasRead (Boolean) What I need is a query to which I input a user's id and I get all the private messages he has received. In addition, I also need to receive each message's sender UserName. For this I wrote the following query: SELECT Users.*, PrivateMessages.*, MessageStatus.* FROM PrivateMessages INNER JOIN Users ON PrivateMessages.SenderID = Users.UserID INNER JOIN MessageStatus ON PrivateMessages.MessageID = MessageStatus.MessageID WHERE MessageStatus.ReceiverID=[@userid]; But for some reason when I try saving it in my Access database, I get the following error (translated to English by me, since my office is in a different language): Syntax error (missing operator) at expression: "PrivateMessages.SenderID = Users.UserID INNER JOIN MessageStatus ON PrivateMessages.MessageID = MessageStatus.MessageI". Any ideas what could cause this? Thanks.

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  • Jquery get array details

    - by Matt
    I'm having trouble getting a response back from a Jquery ajax call... (It's a script to authenticate a user, and needs to return their name and user ID. My understanding was that I could encode it as JSON and get the data in the format below. It is returning an error of "undefined" for the alert(). The javascript $.ajax({ type: "POST", url: "myURL.php", data: {username: username, password: password}, success: function(results) { //THIS IS WHERE THE PROBLEM IS alert('Hi '+results.name); //Should be "Hi Basil Fawlty" } }); The PHP (myURL.php) //This comes from a SQL call that returns the following name json_encode(array( 'id'=>1, 'name'=>'Basil Fawlty' )); Any help or ideas on where I am going wrong would be greatly appreciated! Thanks.

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  • Unexpected space between DIV elements

    - by jon
    my code for the php page displaying the divs <?php session_start(); require_once("classlib/mainspace.php"); if (isset($_SESSION['username'])==FALSE) { header("location:login.php"); } $user = new User($_SESSION['username']); ?><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <link rel="stylesheet" type="text/css" href="style/style.css" /> <title>SimpleTask - Home</title> </head> <body> <div id="main"> <div id="menu"> <div id="items"> <ul> <li><a href="home.php">home</a></li> <li>&bull;</li> <li><a href="projects.php">my projects</a></li> <li>&bull;</li> <li><a href="comments.php">my comments</a></li> </ul> </div> <div id="user"> <p>Welcome, <?php echo $user->GetRealName(); ?><br/><a href="editprofile.php">edit profile</a> &bull; <a href="logout.php">logout</a></p> </div> </div> <div id="content"> <h1>HOME</h1> </div> <div id="footer"> <p>footer text goes here here here here</p> </div> </div> </body> </html> and you can find my CSS here http://tasker.efficaxdevelopment.com/style/style.css and to view the live page go here http://tasker.efficaxdevelopment.com/login.php username:admin password:password

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  • What does Apache need to support both mysqli and PDO?

    - by Nathan Long
    I'm considering changing some PHP code to use PDO for database access instead of mysqli (because the PDO syntax makes more sense to me and is database-agnostic). To do that, I'd need both methods to work while I'm making the changeover. My problem is this: so far, either one or the other method will crash Apache. Right now I'm using XAMPP in Windows XP, and PHP Version 5.2.8. Mysqli works fine, and so does this: $dbc = new PDO("mysql:host=$hostname;dbname=$dbname", $username, $password); echo 'Connected to database'; $sql = "SELECT * FROM `employee`"; But this line makes Apache crash: $dbc->query($sql); I don't want to redo my entire Apache or XAMPP installation, but I'd like for PDO to work. So I tried updating libmysql.dll from here, as oddvibes recommended here. That made my simple PDO query work, but then mysqli queries crashed Apache. (I also tried the suggestion after that one, to update php_pdo_mysql.dll and php_pdo.dll, to no effect.) Test Case I created this test script to compare PDO vs mysqli. With the old copy of libmysql.dll, it crashes if $use_pdo is true and doesn't if it's false. With the new copy of libmysql.dll, it's the opposite. if ($use_pdo){ $dbc = new PDO("mysql:host=$hostname;dbname=$dbname", $username, $password); echo 'Connected to database<br />'; $sql = "SELECT * FROM `employee`"; $dbc->query($sql); foreach ($dbc->query($sql) as $row){ echo $row['firstname'] . ' ' . $row['lastname'] . "<br>\n"; } } else { $dbc = @mysqli_connect($hostname, $username, $password, $dbname) OR die('Could not connect to MySQL: ' . mysqli_connect_error()); $sql = "SELECT * FROM `employee`"; $result = @mysqli_query($dbc, $sql) or die(mysqli_error($dbc)); while ($row = mysqli_fetch_array($result,MYSQLI_ASSOC)) { echo $row['firstname'] . ' ' . $row['lastname'] . "<br>\n"; } } What does Apache need in order to support both methods of database query?

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  • How to call a jquery function from an action method in controller?

    - by Hasan Fahim
    I have a requirement to open a popup from an action method in controller. The action method is basically registering a user. [HttpPost] public ActionResult Register(RegisterModel model) { if (ModelState.IsValid) { MembershipCreateStatus createStatus; Membership.CreateUser(model.UserName, model.Password, model.Email, null, null, true, null, out createStatus); if (createStatus == MembershipCreateStatus.Success) { FormsAuthentication.SetAuthCookie(model.UserName, false /* createPersistentCookie */); //------------------------------------------ //I need to call a jquery function from here //------------------------------------------ return RedirectToAction("Index", "Home"); } else { ModelState.AddModelError("", ErrorCodeToString(createStatus)); } } return View(model); } The jquery function, present in the view, would just make a hidden DIV, visible, and set the opacity, etc, to represent a popup. I need to call such a jquery function from the controller's action method shown above.

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  • Problem with character encoding on email sent via PHP?

    - by cosgrove
    Hi everybody, Having some trouble sending properly formatted HTML e-mail from a PHP script. I am running PHP 5.3.0 and Apache 2.2.11 on Windows XP Professional. The output looks like this: Agent Summary for Support on Tuesday April 20 2010=20 Ext. Name Time Volume 137 Agent Name 01:27:25 1 138 =09 00:00:00 0 139 =09 00:00:00 0 You see the =20 and =09 in there? If you look at the HTML you also see = signs being turned into =3D. I figure this is a character encoding issue as I read the following at Wikipedia: ISO-8859-1 and Windows-1252 confusion It is very common to mislabel text data with the charset label ISO-8859-1, even though the data is really Windows-1252 encoded. In Windows-1252, codes between 0x80 and 0x9F are used for letters and punctuation, whereas they are control codes in ISO-8859-1. Many web browsers and e-mail clients will interpret ISO-8859-1 control codes as Windows-1252 characters in order to accommodate such mislabeling but it is not standard behaviour and care should be taken to avoid generating these characters in ISO-8859-1 labeled content. This looks like the problem but I don't know how to fix. My code looks like this: ob_start(); report_queue_summary($yesterday,$yesterday,$first_extension,$last_extension,$queue); $body_report = ob_get_contents(); ob_end_clean(); $body_footer = "This is an automatically generated e-mail."; $message = new Mail_mime(); $html = $body_header.$body_report.$body_footer; $message->setHTMLBody($html); $body = $message->get(); $extraheaders = array("From"=>"***redacted***","To"=>$recipient, "Subject"=>"Agent Summary for $yesterday [$queue]", "Content-type"=>"text/html; charset=iso-8859-1"); $headers = $message->headers($extraheaders); # setup e-mail; $host = "*********"; $port = "26"; $username = "*****"; $password = "*****"; # Send e-mail $smtp = Mail::factory('smtp', array ('host' => $host, 'port' => $port, 'auth' => true, 'username' => $username, 'password' => $password)); $mail = $smtp->send($recipient, $extraheaders, $body); if (PEAR::isError($mail)) { echo("" . $mail->getMessage() . ""); } else { echo("Message successfully sent!"); } Is the problem that I'm using output buffering?

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  • Linq to SQl Stored Procedure Problem( it can't figure out the return type)

    - by chobo2
    Hi I have this SP USE [Test] GO SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO CREATE PROCEDURE [dbo].[UsersInsert](@UpdatedProdData XML) AS INSERT INTO dbo.UserTable(UserId,UserName,LicenseId,Password,PasswordSalt,Email,IsApproved,IsLockedOut,CreateDate, LastLoginDate,LastLockOutDate,FailedPasswordAttempts,RoleId) SELECT @UpdatedProdData.value('(/ArrayOfUsers/Users/UserId)[1]', 'uniqueidentifier'), @UpdatedProdData.value('(/ArrayOfUsers/Users/UserName)[1]', 'varchar(20)'), @UpdatedProdData.value('(/ArrayOfUsers/Users/LicenseId)[1]', 'varchar(50)'), @UpdatedProdData.value('(/ArrayOfUsers/Users/Password)[1]', 'varchar(128)'), @UpdatedProdData.value('(/ArrayOfUsers/Users/PasswordSalt)[1]', 'varchar(128)'), @UpdatedProdData.value('(/ArrayOfUsers/Users/Email)[1]', 'varchar(50)'), @UpdatedProdData.value('(/ArrayOfUsers/Users/IsApproved)[1]', 'bit'), @UpdatedProdData.value('(/ArrayOfUsers/Users/IsLockedOut)[1]', 'bit'), @UpdatedProdData.value('(/ArrayOfUsers/Users/CreateDate)[1]', 'datetime'), @UpdatedProdData.value('(/ArrayOfUsers/Users/LastLoginDate)[1]', 'datetime'), @UpdatedProdData.value('(/ArrayOfUsers/Users/LastLockOutDate)[1]', 'datetime'), @UpdatedProdData.value('(/ArrayOfUsers/Users/FailedPasswordAttempts)[1]', 'int'), @UpdatedProdData.value('(/ArrayOfUsers/Users/RoleId)[1]', 'int') Now this SP creates just fine. It's when I go to VS2010 and try to drag this SP in my method panel of my linq to sql file in design view. It tells me that it can't figure out the return type. I try to go to the properties but it does not have "none" as a choice and I can't type it in. It should be "none" so how do I set it to "none"?

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  • Persistence scheme & state data for low memory situations (iphone)

    - by Robin Jamieson
    What happens to state information held by a class's variable after coming back from a low memory situation? I know that views will get unloaded and then reloaded later but what about some ancillary classes & data held in them that's used by the controller that launched the view? Sample scenario in question: @interface MyCustomController: UIViewController { ServiceAuthenticator *authenticator; } -(id)initWithAuthenticator:(ServiceAuthenticator *)auth; // the user may press a button that will cause the authenticator // to post some data to the service. -(IBAction)doStuffButtonPressed:(id)sender; @end @interface ServiceAuthenticator { BOOL hasValidCredentials; // YES if user's credentials have been validated NSString *username; NSString *password; // password is not stored in plain text } -(id)initWithUserCredentials:(NSString *)username password:(NSString *)aPassword; -(void)postData:(NSString *)data; @end The app delegate creates the ServiceAuthenticator class with some user data (read from plist file) and the class logs the user with the remote service. inside MyAppDelegate's applicationDidFinishLaunching: - (void)applicationDidFinishLaunching:(UIApplication *)application { ServiceAuthenticator *auth = [[ServiceAuthenticator alloc] initWithUserCredentials:username password:userPassword]; MyCustomController *controller = [[MyCustomController alloc] initWithNibName:...]; controller.authenticator = auth; // Configure and show the window [window addSubview:..]; // make everything visible [window makeKeyAndVisible]; } Then whenever the user presses a certain button, 'MyCustomController's doStuffButtonPressed' is invoked. -(IBAction)doStuffButtonPressed:(id)sender { [authenticator postData:someDataFromSender]; } The authenticator in-turn checks to if the user is logged in (BOOL variable indicates login state) and if so, exchanges data with the remote service. The ServiceAuthenticator is the kind of class that validates the user's credentials only once and all subsequent calls to the object will be to postData. Once a low memory scenario occurs and the associated nib & MyCustomController will get unloaded -- when it's reloaded, what's the process for resetting up the 'ServiceAuthenticator' class & its former state? I'm periodically persisting all of the data in my actual model classes. Should I consider also persisting the state data in these utility style classes? Is that the pattern to follow?

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  • Simple XML parsing error

    - by phpeffedup
    I'm trying to iterate through a Twitter XML File, where the container tag is , and each user is . I need to create a variable $id based on the XML attribute for each user. Username is already instantiated. $url = "http://api.twitter.com/1/statuses/friends/$username.xml"; $xmlpure = file_get_contents($url); $listxml = simplexml_load_string($xmlpure); foreach($listxml->users->children() as $child) { $id = $child->{"id"}; //Do another action } But I'm getting this error: Warning: main() [function.main]: Node no longer exists in /home/.../bonus.php on line 32 Line 32 is the foreach statement, and I don't actually USE the main() method. What am I doing wrong?

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  • Why is hibernate returning a proxy object?

    - by predhme
    I have a service method that returns an object from the database. This method is called from numerous parts of the system. However, one particular method is getting a return type of ObjectClass_$$_javassist_somenumber as the type. Which is throwing things off. I call the service method exactly the same as everywhere else, so why would hibernate return the proxy as opposed to the natural object? I know there are ways to expose the "proxied" object, but I don't feel like I should have to do that. The query is simply hibernateTemplate.find("from User u where u.username = ?", username)

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  • Adding an additional link button to a form (using form->create)

    - by cloudhead
    I have recently been assigned a CSS & design project that's in a CakePHP environment and would like to know if I can add an additional button to the form, for a "sign up" link. The form is currently: echo $form->create('User', array('action' => 'login')); echo $form->inputs(array( 'legend' => 'Please log in:', 'username', 'password')); echo $form->end('Login'); I would like to inject a button that goes to an action of 'register', preferably after the "Login" button, on the same line, like this: username: [ ] password: [ ] [Log In] [Register] I have everything but the 'register' button. Is this possible using the 'automagic' form creation? Thank you.

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  • Declaring and creating an object then adding to collection VS Adding object to collection using new

    - by ZeeMan
    Ok so the title may have been confusing so i have posted 2 code snippets to illustrate what i mean. NOTE: allUsers is just a collection. RegularUser regUser = new RegularUser(userName, password, name, emailAddress); allUsers.Add(regUser); VS allUsers.Add(new RegularUser(userName, password, name, emailAddress)); Which snippet A or B is better and why? What are the advantages or disadvantages? The example i wrote was C# but does the language (C#, Java etc) make a difference?

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