Search Results

Search found 11924 results on 477 pages for 'openoffice org'.

Page 97/477 | < Previous Page | 93 94 95 96 97 98 99 100 101 102 103 104  | Next Page >

  • How to define index by several columns in hibernate entity?

    - by foobar
    Morning. I need to add indexing in hibernate entity. As I know it is possible to do using @Index annotation to specify index for separate column but I need an index for several fields of entity. I've googled and found jboss annotation @Table, that allows to do this (by specification). But (I don't know why) this functionality doesn't work. May be jboss version is lower than necessary, or maybe I don't understant how to use this annotation, but... complex index is not created. Why index may not be created? jboss version 4.2.3.GA Entity example: package somepackage; import org.hibernate.annotations.Index; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.Id; @Entity @org.hibernate.annotations.Table(appliesTo = House.TABLE_NAME, indexes = { @Index(name = "IDX_XDN_DFN", columnNames = {House.XDN, House.DFN} ) } ) public class House { public final static String TABLE_NAME = "house"; public final static String XDN = "xdn"; public final static String DFN = "dfn"; @Id @GeneratedValue private long Id; @Column(name = XDN) private long xdn; @Column(name = DFN) private long dfn; @Column private String address; public long getId() { return Id; } public void setId(long id) { this.Id = id; } public long getXdn() { return xdn; } public void setXdn(long xdn) { this.xdn = xdn; } public long getDfn() { return dfn; } public void setDfn(long dfn) { this.dfn = dfn; } public String getAddress() { return address; } public void setAddress(String address) { this.address = address; } } When jboss/hibernate tries to create table "house" it throws following exception: Reason: org.hibernate.AnnotationException: @org.hibernate.annotations.Table references an unknown table: house

    Read the article

  • reading excel using scriptom for groovy, producing xml

    - by john
    Dear friends, I got a program from http://kousenit.wordpress.com/2007/03/27/groovyness-with-excel-and-xml but I got some very strange results: 1) I can still print xml but two records are not readable. 2) I got exception suggesting some thing missing could some experts enlighten me about what might go wrong? I copied the program and result below. thanks! import org.codehaus.groovy.scriptom.ActiveXObject def addresses = new File('addresses1.xls').canonicalPath def xls = new ActiveXObject('Excel.Application') def workbooks = xls.Workbooks def workbook = workbooks.Open(addresses) // select the active sheet def sheet = workbook.ActiveSheet sheet.Visible = true // get the XML builder ready def builder = new groovy.xml.MarkupBuilder() builder.people { for (row in 2..1000) { def ID = sheet.Range("A${row}").Value.value if (!ID) break // use the builder to write out each person person (id: ID) { name { firstName sheet.Range("B${row}").Value.value lastName sheet.Range("C${row}").Value.value } address { street sheet.Range("D${row}").Value.value city sheet.Range("E${row}").Value.value state sheet.Range("F${row}").Value.value zip sheet.Range("G${row}").Value.value } } } } // close the workbook without asking for saving the file workbook.Close(false, null, false) // quits excel xls.Quit() xls.release() however, i got the following results: <people> <person id='1234.0'> <name> <firstName>[C@128a25</firstName> <lastName>[C@5e45</lastName> </name> <address> <street>[C@179ef7c</street> <city>[C@12f95de</city> <state>[C@138b554</state> <zip>12345.0</zip> </address> </person> </person> Exception thrown May 12, 2010 4:07:15 AM org.codehaus.groovy.runtime.StackTraceUtils sanitize WARNING: Sanitizing stacktrace: java.lang.NullPointerException at org.codehaus.groovy.runtime.callsite.GetEffectivePojoFieldSite.acceptGetProperty(GetEffectivePojoFieldSite.java:43) at org.codehaus.groovy.runtime.callsite.AbstractCallSite.callGetProperty(AbstractCallSite.java:237) at sriptom4_excel$_run_closure1.doCall(sriptom4_excel.groovy:18) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) [1]: http://kousenit.wordpress.com/2007/03/27/groovyness-with-excel-and-xml/

    Read the article

  • Java mail attachment not working on Tomcat

    - by losintikfos
    Hello guys, I have an application which e-mails confirmations. The email part utilises Commons Mail API. The simple code which does the send mail is as shown below; import org.apache.commons.mail.*; ... // Create the attachment EmailAttachment attachment = new EmailAttachment(); attachment.setURL(new URL("http://cashew.org/doc.pdf")); attachment.setDisposition(EmailAttachment.ATTACHMENT); attachment.setDescription("Testing attach"); attachment.setName("doc.pdf"); // Create the email message MultiPartEmail email = new MultiPartEmail(); email.setHostName("mail.cashew.com"); email.addTo("ben@cashew.org"); email.setFrom("lot@cashew.org"); email.setSubject("Testing); email.setMsg("testing message"); // add the attachment email.attach(attachment); // send the email email.send(); My problem is, when I execute this application from Eclipse, I get email sent with attachment without any issues. But when i deploy the application to Tomcat server (I have tried both version 5 & 6 no joy), the e-mail is sent with below content; ------=_Part_0_25002283.1275298567928 Content-Type: text/plain; charset=us-ascii Content-Transfer-Encoding: 7bit testing Regards, los ------=_Part_0_25002283.1275298567928 Content-Type: application/pdf; name="doc.pdf" Content-Transfer-Encoding: base64 Content-Disposition: attachment; filename="doc.pdf" Content-Description: Testing attach JVBERi0xLjQNJeLjz9MNCjYzIDAgb2JqDTw8L0xpbmVhcml6ZWQgMS9MIDMxMzE4Mi9PIDY1L0Ug Mjg2NjY5L04gMS9UIDMxMTgwMi9IIFsgMjgzNiAzNzZdPj4NZW5kb2JqDSAgICAgICAgICAgICAg DQp4cmVmDQo2MyAxMjcNCjAwMDAwMDAwMTYgMDAwMDAgbg0KMDAwMDAwMzM4MCAwMDAwMCBuDQow MDAwMDAzNTIzIDAwMDAwIG4NCjAwMDAwMDQzMDcgMDAwMDAgbg0KMDAwMDAwNTEwOSAwMDAwMCBu DQowMDAwMDA2Mjc5IDAwMDAwIG4NCjAwMDAwMDY0MTAgMDAwMDAgbg0KMDAwMDAwNjU0NiAwMDAw MCBuDQowMDAwMDA3OTY3IDAwMDAwIG4NCjAwMDAwMDkwMjMgMDAwMDAgbg0KMDAwMDAwOTk0OSAw MDAwMCBuDQowMDAwMDExMDAwIDAwMDAwIG4NCjAwMDAwMTIwNTkgMDAwMDAgbg0KMDAwMDAxMjky MCAwMDAwMCBuDQowMDAwMDEyOTU0IDAwMDAwIG4NCjAwMDAwMTI5ODIgMDAwMDAgbg0KMDAwMDAx ....... CnN0YXJ0eHJlZg0KMTE2DQolJUVPRg0K ------=_Part_0_25002283.1275298567928-- One thing also I have noticed is, the header information donot show TO and Subject values. Hmm pretty wierd. I have to point out that, above is not generated of DEBUG, it is the actual message recieved in my outlook client. Can someone help me please! Do anyone knows what's going on?

    Read the article

  • What is usefulness of W3C's Semantic Data Extractor in semantically correct XHTML CSS Development?

    - by metal-gear-solid
    What is the usefulness of W3C's Semantic Data Extractor? http://www.w3.org/2003/12/semantic-extractor.html This tool, geared by an XSLT stylesheet, tries to extract some information from a HTML semantic rich document. It only uses information available through a good usage of the semantics defined in HTML. The aim is to show that providing a semantically rich HTML gives much more value to your code: using a semantically rich HTML code allows a better use of CSS, makes your HTML intelligible to a wider range of user agents (especially search engines bots). As an aside, it can give clues to user agents developers on some hooks that could be interesting to add in their product. After checking validation for CSS and HTML. Should i go for Semantic Data Extractor tool. What it does. and how it can improved our coding.? Is anyone using it? And i check some site randomly with but with most of sites it gives error Using org.apache.xerces.parsers.SAXParser Exception net.sf.saxon.trans.XPathException: org.xml.sax.SAXParseException: The element type "input" must be terminated by the matching end-tag "`</input>`". org.xml.sax.SAXParseException: The element type "input" must be terminated by the matching end-tag "`</input>`".

    Read the article

  • What is usefulness of W3C's "Semantic Data Extractor" in semantically correct XHTML CSS Development?

    - by metal-gear-solid
    What is the usefulness of W3C's Semantic Data Extractor? http://www.w3.org/2003/12/semantic-extractor.html This tool, geared by an XSLT stylesheet, tries to extract some information from a HTML semantic rich document. It only uses information available through a good usage of the semantics defined in HTML. The aim is to show that providing a semantically rich HTML gives much more value to your code: using a semantically rich HTML code allows a better use of CSS, makes your HTML intelligible to a wider range of user agents (especially search engines bots). As an aside, it can give clues to user agents developers on some hooks that could be interesting to add in their product. After checking validation for CSS and HTML. Should i go for Semantic Data Extractor tool. What it does. and how it can improved our coding.? Is anyone using it? And i check some site randomly with but with most of sites it gives error Using org.apache.xerces.parsers.SAXParser Exception net.sf.saxon.trans.XPathException: org.xml.sax.SAXParseException: The element type "input" must be terminated by the matching end-tag "`</input>`". org.xml.sax.SAXParseException: The element type "input" must be terminated by the matching end-tag "`</input>`". Is it possible to get pass every site with this tool? on one site i got this error No top-level heading (h1) found, no outline extracted. Is it necessary to have at least a H1 in any webpage?

    Read the article

  • Web Servicet Client in JBOSS 5.1 with JDK6

    - by dcp
    This is a continuation of the question here: http://stackoverflow.com/questions/2435286/jboss-does-app-have-to-be-compiled-under-same-jdk-as-jboss-is-running-under It's different enough though that it required a new question. I am trying to use jdk6 to run JBOSS 5.1, and I downloaded the JDK6 version of JBOSS 5.1. This works fine and my EAR application deploys fine. However, when I want to run a web service client with code like this: public static void main(String[] args) throws Exception { System.out.println("creating the web service client..."); TestClient client = new TestClient("http://localhost:8080/tc_test_project-tc_test_project/TestBean?wsdl"); Test service = client.getTestPort(); System.out.println("calling service.retrieveAll() using the service client"); List<TestEntity> list = service.retrieveAll(); System.out.println("the number of elements in list retrieved using the client is " + list.size()); } I get the following exception: javax.xml.ws.WebServiceException: java.lang.UnsupportedOperationException: setProperty must be overridden by all subclasses of SOAPMessage at org.jboss.ws.core.jaxws.client.ClientImpl.handleRemoteException(ClientImpl.java:396) at org.jboss.ws.core.jaxws.client.ClientImpl.invoke(ClientImpl.java:302) at org.jboss.ws.core.jaxws.client.ClientProxy.invoke(ClientProxy.java:170) at org.jboss.ws.core.jaxws.client.ClientProxy.invoke(ClientProxy.java:150) Now, here's the really interesting part. If I change the JDK that my the code above is running under from JDK6 to JDK5, the exception above goes away! It's really strange. The only way I found for the code above to run under JDK6 was to take the JBOSS_HOME/lib/endorsed folder and copy it to JDK6_HOME/lib. This seems like it shouldn't be necessary, but it is. Is there any other way to make this work other than using the workaround I just described?

    Read the article

  • Why my test xml is failing with very simple XSD Schema?

    - by JSteve
    Hi all, I am a bit novice in xml schema. I would be grateful if somebody help me out to understand why my xml is not being validated with the schema: Here is my Schema: <?xml version="1.0" encoding="UTF-8"?> <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" targetNamespace="http://www.example.org/testSchema" xmlns="http://www.example.org/testSchema"> <xs:element name="Employee"> <xs:complexType> <xs:sequence> <xs:element name="Name"> <xs:complexType> <xs:sequence> <xs:element name="FirstName" /> <xs:element name="LastName" /> </xs:sequence> </xs:complexType> </xs:element> </xs:sequence> </xs:complexType> </xs:element> </xs:schema> Here is my test xml: <?xml version="1.0" encoding="UTF-8"?> <Employee xmlns="http://www.example.org/testSchema"> <Name> <FirstName>John</FirstName> <LastName>Smith</LastName> </Name> </Employee> I am getting following error by Eclipse xml editor/validator: cvc-complex-type.2.4.a: Invalid content was found starting with element 'Name'. One of '{Name}' is expected. I could not understand what is wrong with this schema or my xml.

    Read the article

  • Java: Exception in thread main java.lang.NoClassDefFoundError

    - by cath
    I am trying to get the Red5 Flash Media Server working on my computer. I have installed it, but when I run the server I get this error Exception in thread "main" java.lang.NoClassDefFoundError: org/red5/server/Bootstrap Caused by: java.lang.ClassNotFoundException: org.red5.server.Bootstrap at java.net.URLClassLoader$1.run(URLClassLoader.java:217) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:205) at java.lang.ClassLoader.loadClass(ClassLoader.java:321) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:294) at java.lang.ClassLoader.loadClass(ClassLoader.java:266) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:334) Could not find the main class: org.red5.server.Bootstrap. Program will exit. I came across this link where someone had the same issue: http://trac.red5.org/ticket/762 It looks like they ran this command: export CLASSPATH=3D$RED5_HOME/lib/slf4j-api-1.5.10.jar:$RED5_HOME/lib/logback- core-0.9.18.jar:$RED5_HOME/lib/logback-classic-0.9.18.jar I have red5 installed in /usr/share/red5, so I ran this: export CLASSPATH=3D$/usr/share/red5/lib/slf4j-api-1.5.10.jar:$/usr/share/red5/lib/logback-core-0.9.18.jar:$/usr/share/red5/lib/logback-classic-0.9.18.jar Yet despite all this I am still seeing the same error message.

    Read the article

  • Serialize a C# class to xml. Store the XML as a string in SQL Server and then restore the class late

    - by BrianK
    I want to serialize a class to xml and store that in a field in a database. I can serialize with this: StringWriter sw = new StringWriter(); XmlSerializer xmlser = new XmlSerializer(typeof(MyClass)); xmlser.Serialize(sw, myClassVariable); string s = sw.ToString(); sw.Close(); Thats works, but it has the namesapces in it. xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" Will these slow down the deserialization because it will go out to those and verify the XML? I got rid of the namespaces by creating a blank XmlSerializerNamespaces and using that to serialize, but then the xml still had namespaces around integer variables: <anyType xmlns:q1="http://www.w3.org/2001/XMLSchema" d3p1:type="q1:int" xmlns:d3p1="http://www.w3.org/2001/XMLSchema-instance"> 3 </anyType> My question is: Is it necessary to have the namesapces for deserialization and if not, how to get rid of them? How do I tell it fields are ints so it doesnt put in "anytype" Thanks, Brian

    Read the article

  • Spring MVC: How to resolve the path to subdirectories of the root 'JSP' folder in a web application

    - by chrisjleu
    What is a simple way to resolve the path to a JSP file that is not located in the root JSP directory of a web application using SpringMVCs viewResolvers? For example, suppose we have the following web application structure: web-app |-WEB-INF |-jsp |-secure |-admin.jsp |-admin2.jsp index.jsp login.jsp I would like to use some out-of-the-box components to resolve the JSP files within the jsp root folder and the secure subdirectory. I have a *-servlet.xml file that defines: an out-of-the-box, InternalResourceViewResolver: <bean id="jspViewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"></property> <property name="prefix" value="/WEB-INF/jsp/"></property> <property name="suffix" value=".jsp"></property> </bean> a handler mapping: <bean id="handlerMapping" class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping"> <property name="mappings"> <props> <prop key="/index.htm">urlFilenameViewController</prop> <prop key="/login.htm">urlFilenameViewController</prop> <prop key="/secure/**">urlFilenameViewController</prop> </props> </property> </bean> an out-of-the-box UrlFilenameViewController controller: <bean id="urlFilenameViewController" class="org.springframework.web.servlet.mvc.UrlFilenameViewController"> </bean> The problem I have is that requests to the JSPs in the secure directory cannot be resolved, as the jspViewResolver only has a prefix defined as /jsp/ and not /jsp/secure/. Is there a way to handle subdirectories like this? I would prefer to keep this structure because I'm also trying to make use of Spring Security and having all secure pages in a subdirectory is a nice way to do this. There's probably a simple way to acheive this but I'm new to Spring and the Spring MVC framework so any pointers would be appreciated.

    Read the article

  • rewrite not a member of LiftRules

    - by José Leal
    Hi guys, I was following http://www.assembla.com/wiki/show/liftweb/URL_Rewriting tutorial for url rewritting in liftweb.. but I get this error: error: value rewrite is not a member of object net.liftweb.http.LiftRules .. it is really odd.. and the documentation says that it exists. I'm using idea IDE, and I've done everything from scratch, using the lift maven blank archifact. Some more info: [INFO] ------------------------------------------------------------------------ [INFO] Building Joseph3 [INFO] task-segment: [tomcat:run] [INFO] ------------------------------------------------------------------------ [INFO] Preparing tomcat:run [INFO] [resources:resources {execution: default-resources}] [WARNING] Using platform encoding (UTF-8 actually) to copy filtered resources, i.e. build is platform dependent! [INFO] Copying 0 resource [INFO] [yuicompressor:compress {execution: default}] [INFO] nb warnings: 0, nb errors: 0 [INFO] artifact org.mortbay.jetty:jetty: checking for updates from scala-tools.org [INFO] artifact org.mortbay.jetty:jetty: checking for updates from central [INFO] [compiler:compile {execution: default-compile}] [INFO] Nothing to compile - all classes are up to date [INFO] [scala:compile {execution: default}] [INFO] Checking for multiple versions of scala [INFO] /home/dpz/Scala/Doit/Joseph3/src/main/scala:-1: info: compiling [INFO] Compiling 2 source files to /home/dpz/Scala/Doit/Joseph3/target/classes at 1274922123910 [ERROR] /home/dpz/Scala/Doit/Joseph3/src/main/scala/bootstrap/liftweb/Boot.scala:16: error: value rewrite is not a member of object net.liftweb.http.LiftRules [INFO] LiftRules.rewrite.prepend(NamedPF("ProductExampleRewrite") { [INFO] ^ [ERROR] one error found [INFO] ------------------------------------------------------------------------ [ERROR] BUILD ERROR [INFO] ------------------------------------------------------------------------ [INFO] wrap: org.apache.commons.exec.ExecuteException: Process exited with an error: 1(Exit value: 1) [INFO] ------------------------------------------------------------------------ [INFO] For more information, run Maven with the -e switch [INFO] ------------------------------------------------------------------------ [INFO] Total time: 19 seconds [INFO] Finished at: Thu May 27 03:02:07 CEST 2010 [INFO] Final Memory: 20M/175M [INFO] ------------------------------------------------------------------------ Process finished with exit code 1 enter code here

    Read the article

  • I have got this error : Failed to create InitialContext using factory specified in hashtable

    - by user85121
    I just want to add a servlet in web.xml, like this : <servlet> <display-name>AxisJMSServlet</display-name> <servlet-name>JMSListener</servlet-name> <servlet-class>com.sinosoft.prpall.web.jms.JMSListenServlet</servlet-class> <load-on-startup>110</load-on-startup> </servlet> Everything is just fine, and when i started my programs, I got this : javax.naming.NoInitialContextException: Failed to create InitialContext using factory specified in hashtable [Root exception is java.lang.NullPointerException] at javax.naming.spi.NamingManager.getInitialContext(NamingManager.java:258) at javax.naming.InitialContext.initializeDefaultInitCtx(InitialContext.java:318) at javax.naming.InitialContext.getDefaultInitCtx(InitialContext.java:348) at javax.naming.InitialContext.internalInit(InitialContext.java:286) at javax.naming.InitialContext.<init>(InitialContext.java:211) at org.apache.axis.components.jms.JNDIVendorAdapter.getConnectionFactory(JNDIVendorAdapter.java:85) at org.apache.axis.components.jms.JNDIVendorAdapter.getQueueConnectionFactory(JNDIVendorAdapter.java:55) at org.apache.axis.transport.jms.JMSConnectorFactory.createConnector(JMSConnectorFactory.java:227) at org.apache.axis.transport.jms.JMSConnectorFactory.createServerConnector(JMSConnectorFactory.java:156) at com.sinosoft.prpall.web.jms.JMSListenServlet.init(JMSListenServlet.java:60) at javax.servlet.GenericServlet.init(GenericServlet.java:241) at weblogic.servlet.internal.StubSecurityHelper$ServletInitAction.run(StubSecurityHelper.java:283) at weblogic.security.acl.internal.AuthenticatedSubject.doAs(AuthenticatedSubject.java:321) at weblogic.security.service.SecurityManager.runAs(SecurityManager.java:120) at weblogic.servlet.internal.StubSecurityHelper.createServlet(StubSecurityHelper.java:64) at weblogic.servlet.internal.StubLifecycleHelper.createOneInstance(StubLifecycleHelper.java:58) at weblogic.servlet.internal.StubLifecycleHelper.<init>(StubLifecycleHelper.java:48) at weblogic.servlet.internal.ServletStubImpl.prepareServlet(ServletStubImpl.java:539) at weblogic.servlet.internal.WebAppServletContext.preloadServlet(WebAppServletContext.java:1981) at weblogic.servlet.internal.WebAppServletContext.loadServletsOnStartup(WebAppServletContext.java:1955) at weblogic.servlet.internal.WebAppServletContext.preloadResources(WebAppServletContext.java:1874) Can anybody tell me what is going on ?

    Read the article

  • Ray Generation Inconsistency

    - by Myx
    I have written code that generates a ray from the "eye" of the camera to the viewing plane some distance away from the camera's eye: R3Ray ConstructRayThroughPixel(...) { R3Point p; double increments_x = (lr.X() - ul.X())/(double)width; double increments_y = (ul.Y() - lr.Y())/(double)height; p.SetX( ul.X() + ((double)i_pos+0.5)*increments_x ); p.SetY( lr.Y() + ((double)j_pos+0.5)*increments_y ); p.SetZ( lr.Z() ); R3Vector v = p-camera_pos; R3Ray new_ray(camera_pos,v); return new_ray; } ul is the upper left corner of the viewing plane and lr is the lower left corner of the viewing plane. They are defined as follows: R3Point org = scene->camera.eye + scene->camera.towards * radius; R3Vector dx = scene->camera.right * radius * tan(scene->camera.xfov); R3Vector dy = scene->camera.up * radius * tan(scene->camera.yfov); R3Point lr = org + dx - dy; R3Point ul = org - dx + dy; Here, org is the center of the viewing plane with radius being the distance between the viewing plane and the camera eye, dx and dy are the displacements in the x and y directions from the center of the viewing plane. The ConstructRayThroughPixel(...) function works perfectly for a camera whose eye is at (0,0,0). However, when the camera is at some different position, not all needed rays are produced for the image. Any suggestions what could be going wrong? Maybe something wrong with my equations? Thanks for the help.

    Read the article

  • How to read spring-application-context.xml and AnnotationConfigWebApplicationContext both in spring mvc

    - by Suvasis
    In case I want to read bean definitions from spring-application-context.xml, I would do this in web.xml file. <context-param> <param-name>contextConfigLocation</param-name> <param-value> /WEB-INF/applicationContext.xml </param-value> </context-param> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> In case I want to read bean definitions through Java Configuration Class (AnnotationConfigWebApplicationContext), I would do this in web.xml <servlet> <servlet-name>appServlet</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <init-param> <param-name>contextClass</param-name> <param-value> org.springframework.web.context.support.AnnotationConfigWebApplicationContext </param-value> </init-param> <init-param> <param-name>contextConfigLocation</param-name> <param-value> org.package.MyConfigAnnotatedClass </param-value> </init-param> </servlet> How do I use both in my application. like reading beans from both configuration xml file and annotated class. Is there a way to load spring beans in xml file while we are using AppConfigAnnotatedClass to instantiate/use rest of the beans.

    Read the article

  • How to wrtie a XML License Line(ended with a forward slash '/') in C#?

    - by Nano HE
    I want to write a XML file as below: <?xml version="1.0" encoding="UTF-8"?> <books xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <License licenseId="" licensePath="" /> Some piece of my code attached here // Create a new file in D:\\ and set the encoding to UTF-8 XmlTextWriter textWriter = new XmlTextWriter("D:\\books.xml", System.Text.Encoding.UTF8); // Format automatically textWriter.Formatting = Formatting.Indented; // Opens the document textWriter.WriteStartDocument(); // Write the namespace declaration. textWriter.WriteStartElement("books", null); // Write the genre attribute. textWriter.WriteAttributeString("xmlns", "xsd", null, "http://www.w3.org/2001/XMLSchema"); textWriter.WriteAttributeString("xmlns", "xsi", null, "http://www.w3.org/2001/XMLSchema-instance"); And now I need to write the License Line below in C# <License licenseId="" licensePath="" /> But I don't know how to move on for I found the Line ended with the forward slash / .Thank you.

    Read the article

  • .Net xsd.exe tool doesn't generate all types

    - by Mrchief
    For some reason, MS .Net (v3.5) tool - xsd.exe doesn't generate types when they are not used inside any element. e.g. XSD File (I threw in the complex element to avoid this warning - "Warning: cannot generate classes because no top-level elements with complex type were found."): <?xml version="1.0" encoding="utf-8"?> <xs:schema targetNamespace="http://tempuri.org/XMLSchema.xsd" elementFormDefault="qualified" xmlns="http://tempuri.org/XMLSchema.xsd" xmlns:mstns="http://tempuri.org/XMLSchema.xsd" xmlns:xs="http://www.w3.org/2001/XMLSchema" > <xs:simpleType name="EnumTest"> <xs:restriction base="xs:string"> <xs:enumeration value="item1" /> <xs:enumeration value="item2" /> <xs:enumeration value="item3" /> </xs:restriction> </xs:simpleType> <xs:complexType name="myComplexType"> <xs:attribute name="Name" use="required" type="xs:string"/> </xs:complexType> <xs:element name="myElem" type="myComplexType"></xs:element> </xs:schema> When i run this thru xsd.exe using xsd /c xsdfile.xsd I don't see EnumTest in the generated cs file. Note; Even though I don't use the enum here, but in my actual project, I have cases like this where we send enum's string value as output. How can I force the xsd tool to include these? Or should I switch to some other tool? I work in Visual Studio 2008.

    Read the article

  • Problem with DSL and Business Rules creation in Drools

    - by jillika iyer
    Hi, I am using Eclipse with the Drools plugin to create rules. I want to create business rules and main aim is to try and provide the user a set of options which he can use to create rules. For eg:If an Apple can have only 3 colors: I want to provide an option like a drop down so that the user can know before hand which are the options he can use in his rules. Is it possible? I am creating a dsl but unable to still provide the above functionality for a business rule. I am having an error implementing a basic dsl also. The code to add the dsl is as follows in my RuleRunner class() InputStream ruleSource = RuleRunner.class.getClassLoader().getResourceAsStream("/Rule1.dslr"); InputStream dslSource = RuleRunner.class.getClassLoader().getResourceAsStream("/sample-dsl.dsl"); //Load the rules , using DSL addRulesToThisPackage.addPackageFromDrl( new InputStreamReader(ruleSource),new InputStreamReader(dslSource)); I have both the sample-dsl .dsl and Rule1.dslr in my working directory. Error encountered at adding the dsl to the package (last line) Error stack: Exception in thread "main" java.lang.NullPointerException at java.io.Reader.<init>(Unknown Source) at java.io.InputStreamReader.<init>(Unknown Source) at com.org.RuleRunner.loadRuleFile(RuleRunner.java:96) at com.org.RuleRunner.loadRules(RuleRunner.java:48) at com.org.RuleRunner.runStatelessRules(RuleRunner.java:109) at com.org.RulesTest.main(RulesTest.java:41) my dsl file has basic mapping as per the online documentations. The dsl rule I created is: expander sample-dsl.dsl rule "A status changes B status" when There is an A - has an address There is a B - has name then - print updated A and Aaddress End I have created DSL in eclipse. Is the code I added for it to be loaded to my package correct?? Or am I missing something???? It seems like my program is unable to find the dsl? Please help. Can you point me towards the right direction to create a user friendly business rule ?? Thanks. J

    Read the article

  • XmlSerialize a custom collection with an Attribute

    - by roomaroo
    I've got a simple class that inherits from Collection and adds a couple of properties. I need to serialize this class to XML, but the XMLSerializer ignores my additional properties. I assume this is because of the special treatment that XMLSerializer gives ICollection and IEnumerable objects. What's the best way around this? Here's some sample code: using System.Collections.ObjectModel; using System.IO; using System.Xml.Serialization; namespace SerialiseCollection { class Program { static void Main(string[] args) { var c = new MyCollection(); c.Add("Hello"); c.Add("Goodbye"); var serializer = new XmlSerializer(typeof(MyCollection)); using (var writer = new StreamWriter("test.xml")) serializer.Serialize(writer, c); } } [XmlRoot("MyCollection")] public class MyCollection : Collection<string> { [XmlAttribute()] public string MyAttribute { get; set; } public MyCollection() { this.MyAttribute = "SerializeThis"; } } } This outputs the following XML (note MyAttribute is missing in the MyCollection element): <?xml version="1.0" encoding="utf-8"?> <MyCollection xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <string>Hello</string> <string>Goodbye</string> </MyCollection> What I want is <MyCollection MyAttribute="SerializeThis" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <string>Hello</string> <string>Goodbye</string> </MyCollection> Any ideas? The simpler the better. Thanks.

    Read the article

  • How to create a log file in the folder which will be created at run time

    - by swati
    Hello Everyone, I new to apache logger.I am using apache log4j for my application. I am using the following configuration file configure the root logger log4j.rootLogger=INFO, STDOUT, DAILY configure the console appender log4j.appender.STDOUT=org.apache.log4j.ConsoleAppender log4j.appender.STDOUT.Target=System.out log4j.appender.STDOUT.layout=org.apache.log4j.PatternLayout log4j.appender.STDOUT.layout.conversionPattern=%d{yyyy-MM-dd HH:mm:ss.SSS} [%p] %c:%L - %m%n configure the daily rolling file appender log4j.appender.DAILY=org.apache.log4j.DailyRollingFileAppender log4j.appender.DAILY.File=log4jtest.log log4j.appender.DAILY.DatePattern='.'yyyy-MM-dd-HH-mm log4j.appender.DAILY.layout=org.apache.log4j.PatternLayout log4j.appender.DAILY.layout.conversionPattern=%d{yyyy-MM-dd HH:mm:ss.SSS} [%p] %c:%L - %m%n So when my application runs it creates a folder called somename_2010-04-09-23-09 . My log file has to be created inside of this somename_2010-04-09-23-09 folder.(Which created at run time..). Is there anyway to do that.. Is there anyway we can specify in the configuration file so that it will create at run time the log file inside of the folder somename_2010-04-09-23-03 folder..? I would really appreciate if some one can answer to my questions. Thanks, Swati

    Read the article

  • How to post a SOAP request from a browser?

    - by understack
    Is it possible to send a SOAP request directly from a browser to service provider? And then parse the output in javascript to show the result? For example, if I've a SOAP request like this : POST /InStock HTTP/1.1 Host: www.example.org Content-Type: application/soap+xml; charset=utf-8 Content-Length: nnn <?xml version="1.0"?> <soap:Envelope xmlns:soap="http://www.w3.org/2001/12/soap-envelope" soap:encodingStyle="http://www.w3.org/2001/12/soap-encoding"> <soap:Body xmlns:m="http://www.example.org/stock"> <m:GetStockPrice> <m:StockName>IBM</m:StockName> </m:GetStockPrice> </soap:Body> </soap:Envelope> Then can I get the 'IBM stock price' by clicking on a link on a web page? And show result after xml processing. EDIT Can I send the whole envelope as POST data?

    Read the article

  • Is it legal to have different SOAP namespaces/versions between the request and response?

    - by Lord Torgamus
    THIRD EDIT: I now believe that this problem is due to a SOAP version mismatch (1.1 request, 1.2 response) masquerading as a namespace problem. Is it illegal to mix versions, or just bad style? Am I completely out of luck if I can't change my SOAP version or the service's? SECOND EDIT: Clarified error message, and tried to reduce "tl;dr"-ness. EDIT: [Link deleted, not related] Using soapUI, I'm sending a request that starts with: <soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" ... and getting a response that starts with: <soap:Envelope xmlns:soap="http://www.w3.org/2003/05/soap-envelope" ... I know the service is getting the info, because processes down the line are working. However, my soapUI teststep fails. It has two active assertions: "SOAP Response" and "Not SOAP Fault." The failure marker is next to "SOAP Response," with the following message: line -1: Element Envelope@http://www.w3.org/2003/05/soap-envelope is not a valid Envelope@http://schemas.xmlsoap.org/soap/envelope/ document or a valid substitution. I have tried mixing and matching the namespace prefixes and schema URLs. Changing prefixes seems to have no effect; changing URLs causes a VersionMismatch error. I have also tried to use a substitution group, but that doesn't seem to be legal.

    Read the article

  • Using BWSAL with BWAPI JBridge

    - by pek
    I've been busting my head to find out how to use BWSAL with JBridge... I just can't figure it out.. I'm not that good in C++.. The best I could do is compile the latest JBridge from the repo... But I can't seem to get BSWAL working... What do I need? Compiling JBrigde doesn't seem to have BWSAL in.. I found the directory that BWSAL exists but there is no solution file to build.. I downloaded the latest BWSAL, found the solution file, but have no idea what to do... Compiling it will create an AIModule.dll but if I use this, the JBridge won't work... What I'm trying to do is to simply use BuildingPlacer.getBuildLocationNear... Whenever I call this method a NullPointerException is thrown: java.lang.NullPointerException at org.bwapi.bridge.model.Game.canBuildHere(Game.java:286) at org.bwapi.bridge.sal.BuildingPlacer.canBuildHere(BuildingPlacer.java: 46) at org.bwapi.bridge.sal.BuildingPlacer.canBuildHereWithSpace(BuildingPlacer.java: 60) at org.bwapi.bridge.sal.BuildingPlacer.getBuildLocationNear(BuildingPlacer.java: 121) at com.pekalicious.starplanner.ResourceManager.isInitialReady(ResourceManager.java: 87) at com.pekalicious.starplanner.ResourceManager.update(ResourceManager.java: 37) at com.pekalicious.starplanner.StrategicManager.update(StrategicManager.java: 51) at com.pekalicious.starplanner.StarPlannerBridgeBot.onFrame(StarPlannerBridgeBot.java: 36) How do I make this work? I really need this.. Please. Thank you.

    Read the article

  • How can I get the name of the namespace from a SOAP message?

    - by olly
    Hi I have a SOAP message (see below). Using Xpath, how can I extract the name of the namespace from this message? In other words, is there an Xpath routine that will return the text "validateNewOrder"? Any suggestions or help would be invaluable. I have been searching everywhere but not found an solution. It is driving me crazy... Thanks! <?xml version='1.0' encoding='UTF-8'?> <SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <SOAP-ENV:Body> <ns1:validateNewOrder xmlns:ns1="http://sire.rabobank.nl/" SOAP-ENV:encodingStyle="http://schemas.xmlsoap.org/soap/encoding/"> <sireheader xmlns="http://sire.rabobank.nl/"> <sender> <compid>TEST</compid> </sender> </sireheader> <order xmlns="http://sire.rabobank.nl/"> <account>123456789</account> </order> </ns1:validateNewOrder> </SOAP-ENV:Body> </SOAP-ENV:Envelope>

    Read the article

  • How do I include the proper XML / HTML definitions in a file generated by XSL?

    - by Colen
    As I understand it, you need to include the following code at the top of your HTML files to make sure they're parsed properly: <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en"> ... I'm generating an html file by transforming an XML file using an XSL file. This is going to be done using the MSXML tool, which produces a standard HTML file as output. If I just do this: <xsl:template match="/"> <html> ... Everything is fine. But if I do this: <xsl:template match="/"> <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en"> ... I get the error XML Parsing Error: XML or text declaration not at start of entity in Firefox, or Cannot have a DOCTYPE declaration outside of a prolog. in IE. Presumably this is because the parser is finding two How do I make the browser a) understand that I am using proper strict HTML, and b) make sure those declarations are put into the HTML output file that MSXML generates?

    Read the article

  • SOAP Messages on iPhone

    - by CocoaNewBee
    Hello everyone !! I have to use several SOAP messages to get data from a web service. I got some examples how to do that but they all have the XML (http://icodeblog.com/2008/11/03/iphone-programming-tutorial-intro-to-soap-web-services/) // ---- LOGIN ----- NSString *soapMessage = [NSString stringWithFormat: @"<?xml version=\"1.0\" encoding=\"utf-8\"?>\n" "<soap12:Envelope xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" xmlns:soap12=\"http://www.w3.org/2003/05/soap-envelope\">\n" "<soap12:Body>\n" "<Login xmlns=\"http://tempuri.org/\">\n" "<sUserID>USER</sUserID>\n" "<sUserPw>PASSWORD</sUserPw>\n" "<sDomain>SERVER</sDomain>\n" "</Login>\n" "</soap12:Body>\n" "</soap12:Envelope>\n" ]; NSString *urlToSend = [[NSString alloc] initWithString:@"http://SERVER/DIRECTORY/WSDL_FILE.ASMX"]; NSString *callTOMake = [[NSString alloc] initWithString:@"http://WEBSERVER/Login"]; TWO questions: 1) Does it make sense to read the SOAP Message from a class or a file into xcode?? or sould I just define them thru the code ?? 2) I used SOAPUI & .NET to query the service. It works fine... but when I do it from the iphone simulator it returns the following: 2010-03-10 15:13:54.773 Hello_SOAP[91204:207] soap:ClientServer did not recognize the value of HTTP Header SOAPAction: http://WEBSERVER/DIRECTORY/Login How can I figure out what the issue is that's causing the said error on the simulator??

    Read the article

< Previous Page | 93 94 95 96 97 98 99 100 101 102 103 104  | Next Page >