Search Results

Search found 31657 results on 1267 pages for 'php 5 3'.

Page 97/1267 | < Previous Page | 93 94 95 96 97 98 99 100 101 102 103 104  | Next Page >

  • How should I architect JasperReports with a PHP front+backend system

    - by Itay Moav
    Our system is written completely in PHP. For various business reasons (which are a given) I need to build the reports of the system using JasperReports. What architecture should I use? Should I put the Jasper as a stand alone server (if possible) and let the php query against it, should I have it generate the reports with a cron, and then let the PHP scoop up the files and send them to the web client/browser...

    Read the article

  • where are wrong in my php code ????

    - by user318068
    hi all, <td align="center" bgcolor="#FFFFFF"><?php echo '<label onclick="window.open('profilephp.php?member=$row['MemberID']','mywindow')">'.{$row['MemberName']}.'</label>';?><br /> <?php echo "<p align='center'><img width='100' height='100' src={$row['MemberImg']} alt='' /></p>";?></td></tr> Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in C:\xampp\htdocs\home - Copy\membercopy.php on line 141 I really don't know where it went wrong. Please help,

    Read the article

  • php Dollar amount Regular Expression

    - by Thildemar
    I am have completed javascript validation of a form using Regular Expressions and am now working on redundant verification server-side using PHP. I have copied this regular expression from my jscript code that finds dollar values, and reformed it to a PHP friendly format: /\$?((\d{1,3}(,\d{3})*)|(\d+))(\.\d{2})?$/ Specifically: if (preg_match("/\$?((\d{1,3}(,\d{3})*)|(\d+))(\.\d{2})?$/", $_POST["cost"])){} While the expression works great in javascript I get : Warning: preg_match() [function.preg-match]: Compilation failed: nothing to repeat at offset 1 when I run it in PHP. Anyone have a clue why this error is coming up?

    Read the article

  • jQuery ajax request to php, how to return plain text only

    - by jyoseph
    I am making an ajax request to a php page and I cannot for the life of me get it to just return plain text. $.ajax({ type: 'GET', url: '/shipping/test.php', cache: false, dataType: 'text', data: myData, success: function(data){ console.log(data) } }); in test.php I am including this script to get UPS rates. I am then calling the function with $rate = ups($dest_zip,$service,$weight,$length,$width,$height); I am doing echo $rate; at the bottom of test.php. When viewed in a browser shows the rate, that's great. But when I request the page via ajax I get a bunch of XML. Pastie here: http://pastie.org/1416142 My question is, how do I get it so I can just return the plain text string from the ajax call, where the result data will be a number? Edit, here's what I see in Firebug- Response tab: HTML tab:

    Read the article

  • PHP - Read TXT from specific position

    - by user1466766
    I'm having trouble with PHP text parsing I have a txt file which has this kind of information: sometext::sometext.0 = INTEGER: 254 What i need is to get the last value of 254 as variable in PHP. in this txt file this last value can change from 0 to 255 "sometext::sometext.0 = INTEGER: " this part doesn't change at all. It has a length of 36 symbols, so i need get with PHP what is after 36 symbol into variable. Thank you.

    Read the article

  • Nginx: Loopback connection via PHP's getimage size crashes server (Magento's CMS)

    - by Alex
    We were able to trace down a problem that is crashing our NGINX server running Magento until the following point: Background info: Magento Backend has a CMS function with a WYSIWYG editor. This editor loads some pictures via a controller in magento (cms/directive). When we set the NGINX error_log level to info, we get the following lines (line break inserted for better readability): 2012/10/22 18:05:40 [info] 14105#0: *1 client closed prematurely connection, so upstream connection is closed too while sending request to upstream, client: XXXXXXXXX, server: test.local, request: "GET index.php/admin/cms_wysiwyg/directive/___directive/BASEENCODEDIMAGEURL,,/ HTTP/1.1", upstream: "fastcgi://127.0.0.1:9024", host: "test.local" When checking the code in the debugger, the following call does never return (in ´Varien_Image_Adapter_Abstract::getMimeType()` # $this->_fileName is http://test.local/skin/adminhtml/base/default/images/demo-image-not-existing.gif` # $_SERVER['REQUEST_URI'] = http://test.local/admin/cms_wysiwyg/directive/___directive/BASEENCODEDIMAGEURL list($this->_imageSrcWidth, $this->_imageSrcHeight, $this->_fileType, ) = getimagesize($this->_fileName); The filename requests is an URL to the same server which is requesting the script a link to a static .gif that is not existing. Sample URL: http://test.local/skin/adminhtml/base/default/images/demo-image-not-existing.gif When the above line executed, any subsequent request to the NGNIX server does not respond any more. After waiting for around 10 minutes, the NGINX server starts answering requests again. I tried to reproduce the error with a simple test script that only calls getimagesize() with the given URL - but this not crash. It simple leads to an exception saying that the URL could not be loaded (which is fine as the URL is wrong)

    Read the article

  • PHP getting blank pages after submit a form + signal Segmentation fault (11)

    - by Ole Media
    I few days ago I update my macbook pro to snow leopard, and since then some php files are not showing. This is what happens: I created a php form, when going to 'http://localhost/webform.php' I can see the form just fine. Then, once I submit the form, I just get a blank page. I enable error and warnings reporting under php.ini to make sure I'm not missing something, but still I'm not getting anything, just the blank page. Then I checked under apache log files, and what I notice is that every time I submit the form I see the following line coming up under the apache logs: [Wed Apr 07 21:40:28 2010] [notice] child pid 70223 exit signal Segmentation fault (11) I'm clueless on this one. Any ideas on how to fix it?

    Read the article

  • How to get session variables from php server with Ajax function? (PHP HTML JS Ajax)

    - by Ole Jak
    so in my php I have something like this $_SESSION['opened'] = true; But It will not be set to true until user will perform some actions with some other html\php pages So I need on some Ajax function to be able get this session variable. And some PHP sample of function to get variable in form ready for Ajax to get it. so I need something to AJAX requesting to an action (to some simple php code) which will return a value from $_SESSION. How to do such thing?

    Read the article

  • Druapl & Regular PHP Integration

    - by user333128
    I'm building a new website which has one core application and many content pages. Content pages are mostly dynamic and I require a way to manage this dynamic content on a regular basis. The core application's main functionality is a 3 step process or reading user data (input page), reading data from MySQL (product page) and submitting an application to an email address (application page). Ideally I would like to build the core application in regular PHP and leverage Drupal for its content management capabilities. Can Drupal and regular PHP be integrated as I suggest easily? My feeling is that coding the core application as a Drupal module(s) will add layers of complexity that could be difficult to code from the outset and maintain later on as the system matures - so I would really like to just use regular PHP. Let me explain where dynamic content (managed by the CMS) intersects with the core application: Dynamic content such as FAQ data is used both on the 'normal' help pages and also within a mini-feed displayed within core application pages down a right hand side column. In this column, 3 random questions are pulled from the database and displayed as a feed. When users click on FAQ question they are not taken away from the core application product page but are instead shown data in a pop-up window displaying the question and answer. In addition, users can browse other questions and answers through a simple navigation menu within this popup. There are 3 such like feeds as I describe above that I require on the core application product page. So, what is the ideal solution here in terms of 'keeping things simple' for both the management of dynamic content and the ease of coding the core application? Can 'regular PHP' and Drupal co-exist 'peacefully'? If so, how is this technically possible? Because there is some content managed by Drupal contained within core application pages, can the core application still be coded in regular PHP? Any advice / suggestions? Thank you! Jim.

    Read the article

  • Will php code exit after echo for ajax?

    - by Steve
    I am running a typical php-engined ajax webpage. I use echo to return a html string from the php code. My question is, if I have some other code after the echo, will those code get executed? Or echo behaves similar to exit, which immediately return and stop running the php code? Thanks.

    Read the article

  • Launch a new page in Zend/php on button click

    - by BlueMonster
    PHP & Zend Noob here I've downloaded the skeleton project from here: https://github.com/zendframework/ZendSkeletonApplication Say i want to open a new page that simply displays "hello world" text if click on the "ZF2 Development Portal" button(bottom left green button) on the page that launches --- how do i do this? See image: I've read through this tutorial, but i'm not sure how the model, view, or controller are actually launched? See tutorial: http://blog.wilgucki.pl/2012/07/tworzenie-modulw-w-zend-framework-2.html From looking at the code, i know that i will have to change this line of code: <div class="span4"> <h2><?php echo $this->translate('Follow Development') ?></h2> <p><?php echo sprintf($this->translate('Zend Framework 2 is under active development. If you are interested in following the development of ZF2, there is a special ZF2 portal on the official Zend Framework website which provides links to the ZF2 %swiki%s, %sdev blog%s, %sissue tracker%s, and much more. This is a great resource for staying up to date with the latest developments!'), '<a href="http://framework.zend.com/wiki/display/ZFDEV2/Home">', '</a>', '<a href="http://framework.zend.com/zf2/blog">', '</a>', '<a href="http://framework.zend.com/issues/browse/ZF2">', '</a>') ?></p> <p><a class="btn btn-success" href="http://framework.zend.com/zf2" target="_blank"><?php echo $this->translate('ZF2 Development Portal') ?> &raquo;</a></p> </div> More specifically this line: <p><a class="btn btn-success" href="http://framework.zend.com/zf2" target="_blank"><?php echo $this->translate('ZF2 Development Portal') ?> &raquo;</a></p> but i'm really confused as to what i'm supposed to change it to in order to launch a new page. Any ideas? Thanks in advance!

    Read the article

  • PHP if statement - select two different get variables?

    - by arsoneffect
    Below is my example script: <li><a <?php if ($_GET['page']=='photos' && $_GET['view']!=="projects"||!=="forsale") { echo ("href=\"#\" class=\"active\""); } else { echo ("href=\"/?page=photos\""); } ?>>Photos</a></li> <li><a <?php if ($_GET['view']=='projects') { echo ("href=\"#\" class=\"active\""); } else { echo ("href=\"/?page=photos&view=projects\""); } ?>>Projects</a></li> <li><a <?php if ($_GET['view']=='forsale') { echo ("href=\"#\" class=\"active\""); } else { echo ("href=\"/?page=photos&view=forsale\""); } ?>>For Sale</a></li> I want the PHP to echo the "href="#" class="active" only when it is not on the two pages: ?page=photos&view=forsale or ?page=photos&view=projects

    Read the article

  • Can't serve HTML5 video through PHP on Safari/Mac (5.0)

    - by JKS
    I'm encountering a strange bug in Safari where, when I serve MP4 video through PHP (to obfuscate the file beneath the document root with a token-based authentication system), Safari for some reason fires the <video>'s onerror event, and the video never loads (I can't get any useful information out of the event object sent to onerror — everything is undefined). When I access the PHP script directly (i.e., the video is not embedded in a page), the video controls appear momentarily before flashing to a QuickTime question mark. When I access the MP4 file directly, it works as expected. What's bizarre is that the embedded video works perfectly in the latest version of Chrome for Mac. Here are the headers when accessed through PHP: Connection:Keep-Alive Content-Disposition:inline; filename="test.mp4" Content-Length:5558749 Content-Type:video/mp4 Date:Tue, 22 Jun 2010 01:24:25 GMT Keep-Alive:timeout=10, max=29 Server:Apache/2.2.15 (CentOS) mod_ssl/2.2.15 0.9.8l DAV/2 mod_auth_passthrough/2.1 FrontPage/5.0.2.2635 X-Powered-By:PHP/5.2.13 And here are the headers when test.mp4 is accessed directly: Accept-Ranges:bytes Connection:Keep-Alive Content-Length:5558749 Content-Type:video/mp4 Date:Tue, 22 Jun 2010 01:26:45 GMT Etag:"1c04757-54d1dd-489944c5a6400" Keep-Alive:timeout=10, max=30 Last-Modified:Tue, 22 Jun 2010 01:25:36 GMT Server:Apache/2.2.15 (CentOS) mod_ssl/2.2.15 0.9.8l DAV/2 mod_auth_passthrough/2.1 FrontPage/5.0.2.2635 The only differing headers are: Accept-Ranges (which I don't think is necessary), Etag, Last-Modified, Content-Disposition, and X-Powered-By. Not only can Chrome handle the PHP-served video fine, but when I use the same script to load the MP4 through a Flash player, it also works fine. I just can't figure out what Safari is choking on. EDIT: Also, when I change the content disposition to "attachment", Safari will download the MP4 file just fine.

    Read the article

  • PHP & WP: Render Certain Markup Based on True False Condition

    - by rob
    So, I'm working on a site where on the top of certain pages I'd like to display a static graphic and on some pages I would like to display an scrolling banner. So far I set up the condition as follows: <?php $regBanner = true; $regBannerURL = get_bloginfo('stylesheet_directory'); //grabbing WP site URL ?> and in my markup: <div id="banner"> <?php if ($regBanner) { echo "<img src='" . $regBannerURL . "/style/images/main_site/home_page/mock_banner.jpg' />"; } else { echo 'Slider!'; } ?> </div><!-- end banner --> In my else statement, where I'm echoing 'Slider!' I would like to output the markup for my slider: <div id="slider"> <img src="<?php bloginfo('stylesheet_directory') ?>/style/images/main_site/banners/services_banners/1.jpg" alt="" /> <img src="<?php bloginfo('stylesheet_directory') ?>/style/images/main_site/banners/services_banners/2.jpg" alt="" /> <img src="<?php bloginfo('stylesheet_directory') ?>/style/images/main_site/banners/services_banners/3.jpg" alt="" /> ............. </div> My question is how can I throw the div and all those images into my else echo statement? I'm having trouble escaping the quotes and my slider markup isn't rendering.

    Read the article

  • PHP Include and sort by variable within file

    - by Jason Hoax
    I have written this PHP include-script but now I'm trying to sort the included files out by variables WITHIN the included php's. In other words, in each included PHP file there is a rating, now I want the ratings to be read so that when they are included they will be sorted out from highest to lowest. (scores are like 6.0 to 9.0) Kind Regards! $location = 'experiments/visualizations'; foreach (glob("$location/*.php") as $filename) { include $filename; } The included files are named randomly like: File1: $filename = "AAAA"; $projecttitle = "Project Name"; $description = "This totally explains the product"; $score = "7.6"; File 2: $filename = "BBBB"; $projecttitle = "Project Name2" $description = "This totally explains the product"; $score = "9.6"; As you can see 9.6 is higher than 7.6 but PHP sorts the includes out by name instead of variables within the file. I tried sorting, but I can't get it fixed. Help!

    Read the article

  • INSERT DELAYED on locked tables blocks PHP processes to continue

    - by sw0x2A
    Our webservers write some tracking information into a MySQL database (using INSERT DELAYED into MyISAM table). When a huge SELECT query is executed on this table or when it is locked for another reason, the webserver processes (with INSERT DELAYED) are waiting for the database and in some cases the MaxServer limit is reached in Apaches, so they will stop serving requests. We use INSERT DELAYED because The DELAYED option for the INSERT statement is a MySQL extension to standard SQL that is very useful if you have clients that cannot or need not wait for the INSERT to complete. This is a common situation when you use MySQL for logging and you also periodically run SELECT and UPDATE statements that take a long time to complete. Quote from MySQL documentation. I am wondering why the Apache processes are waiting for the INSERT DELAYED to finish. And what can I do to just send the data and forget about it. (Since this is logging data, I do not care if we lose some entries.) Even when the table is locked the PHP script should just go on and should not wait for an answer of MySQL. (We do not want to setup Master-slave for this table but we are thinking about move this data to some NoSQL database. But for now I would like to know why INSERT DELAYED is not working as expected.)

    Read the article

  • php database image show problem

    - by Termedi
    here is the code <?php session_start(); if(!isset($_SESSION['user_name'])) { header('Location: login.php'); } $conn = mysql_connect("localhost", "root", "") or die("Can no connect to Database Server"); ?> <html> <head> </head> <body> <center> <div id="ser"> <form action="" method="post"> <label for="file">Card No:</label> <input type="text" name="card_no" id="card_no" class="fil" onKeyUp="CardNoLength()" onKeyDown="CardNoLength()" onKeyPress="CardNoLength()"/> <input type="submit" name="search" value="Search" class="btn" onClick="return CardNoLengthMIN()"/> </form> </div> </center> <br/><hr style="border: 1px solid #606060 ;" /> <center><a href="index.php">Home</a></center> <br/> <center> <?php if(isset($_POST['card_no'])) { if($conn) { if(mysql_select_db("img_mgmt", $conn)) { $sql = "select * from temp_images where card_no='".trim($_POST['card_no'])."'"; $result = mysql_query($sql); $image = mysql_fetch_array($result); if(isset($image['card_no'])) { //echo "<img src=\"".$image['file_path']."\" alt=\"".$image['card_no']."\" width=\"250\" height=\"280\"/>"; header("Content-type: image/jpeg"); echo $image['img_content']; } else { echo "<p style=\"color:red;\">Sorry, Your search came with no results ! <br/> Try with different card number"; } } else { echo "Database selection error: ".mysql_error(); } } else { echo "Could not connect: ".mysql_error(); } } ?> </center> </body> </html> But it after executing the script it shows: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\img\search.php:61) in C:\xampp\htdocs\img\search.php on line 77

    Read the article

  • Validate Form with PHP AND Javascriipt?

    - by J M 4
    Is it possible to validate a form with PHP AND Javascript? I am currently able to do both using my existing form but only on an individual basis. My overall goal is this: Validate form using javascript client side and present any errors to the user immediately If javascript validation passes, a flag is created and then the PHP script can begin. When doing my javascript validation, i use the following code within the form tag: <form id="Enroll_Form" action="review.php" method="post" name="Enroll_Form" onsubmit="return Enroll_Form_Validator(this)" language="javascript"> if I want to process the PHP validation, I am forced to rename the action to the PHP_SELF file (or simply the same file name i'm using) and remove the 'onsubmit' function. Any ideas?

    Read the article

  • Providing updating suggestions list with javascript, php and ajax

    - by user1104854
    I'm trying to modify this example on making a live updating list to integrate it with my API. So, instead of using GET on the page with the form, I'd like to send it to that page via a function call. So, here's my form // message.php //function to display the hint sent from gethint.php function message_hint($hint){ echo $hint; } //displays the form for sending messages function send_message_form($to_user,$title,$message){ include 'gethint.php'; ?> <table> <form name = "send_message" method="post"> <td>Send A Message</td> <tr><td>To:</td><td><input type = "text" size="50" name="to_user" id = "to_user" value ="<? echo $to_user; ?>" onkeyup="showHint(this.value)"></td></tr> <tr><td>Title:</td><td><input type = "text" size="50" name="message_title"></td></tr> <tr><td>Message:</td><td><textarea rows="4" cols="50" name="message_details"></textarea></td></tr> <tr><td><input type="submit" name="submit_message"></td></tr> </table> </form> <? } Here's the head of message.php <head> <script> function showHint(str){ var to_user = document.getElementById("to_user").value //to_user is the id of the textbox if (str.length==0){ to_user.innerHTML=""; return; } if (window.XMLHttpRequest){// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); }else{// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function(){ if (xmlhttp.readyState==4 && xmlhttp.status==200){ alert(to_user) //properly displays the name via alert box to_user.innerHTML=xmlhttp.responseText; } } xmlhttp.open("GET","gethint.php?q="+to_user,true); xmlhttp.send(); } </script> </head> The page gethint.php is exactly the same, aside from this at the bottom. //echo $response //this was the original output $message = new messages; $message->message_hint($response);

    Read the article

  • Multiple XML/XSLT files in PHP, transform one with XSLT and add others but process it first with PHP

    - by ipalaus
    I am processing XML files transformations with XSLT in PHP correctly. Actually I use this code: $xml = new DOMDocument; $xml->LoadXML($xml_contents); $xsl = new DOMDocument; $xsl->load($xsl_file); $proc = new XSLTProcesoor; $proc->importStyleSheet($xsl); echo $proc->transformToXml($xml); $xml_contents is the XML processed with PHP, this is done by including the XML file first and then assigning $xml_contents = ob_get_contents(); ob_end_clean();. This forces to process the PHP code on the XML, and it works perfectly. My problem is that I use more than one XML file and this XML files has PHP code on it that need to be processed AND have a XSLT file associated to process the data. Actually I'm including this files in XSLT with the next code: <!-- First I add the XML file --> <xsl:param name="menu" select="document('menu.xml')" /> <!-- Next I add the transformations for menu.xml file --> <xsl:include href="menu.xsl" /> <!-- Finally, I process it on the actual ("parent") XML --> <xsl:apply-templates select="$menu/menu" /> My questiion is how I can handle this. I need to add mutiple XML(+XSLT) files to my first XML file that will containt PHP so it needs to be processed. Thank you in advance!

    Read the article

< Previous Page | 93 94 95 96 97 98 99 100 101 102 103 104  | Next Page >