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  • How accurate is "Business logic should be in a service, not in a model"?

    - by Jeroen Vannevel
    Situation Earlier this evening I gave an answer to a question on StackOverflow. The question: Editing of an existing object should be done in repository layer or in service? For example if I have a User that has debt. I want to change his debt. Should I do it in UserRepository or in service for example BuyingService by getting an object, editing it and saving it ? My answer: You should leave the responsibility of mutating an object to that same object and use the repository to retrieve this object. Example situation: class User { private int debt; // debt in cents private string name; // getters public void makePayment(int cents){ debt -= cents; } } class UserRepository { public User GetUserByName(string name){ // Get appropriate user from database } } A comment I received: Business logic should really be in a service. Not in a model. What does the internet say? So, this got me searching since I've never really (consciously) used a service layer. I started reading up on the Service Layer pattern and the Unit Of Work pattern but so far I can't say I'm convinced a service layer has to be used. Take for example this article by Martin Fowler on the anti-pattern of an Anemic Domain Model: There are objects, many named after the nouns in the domain space, and these objects are connected with the rich relationships and structure that true domain models have. The catch comes when you look at the behavior, and you realize that there is hardly any behavior on these objects, making them little more than bags of getters and setters. Indeed often these models come with design rules that say that you are not to put any domain logic in the the domain objects. Instead there are a set of service objects which capture all the domain logic. These services live on top of the domain model and use the domain model for data. (...) The logic that should be in a domain object is domain logic - validations, calculations, business rules - whatever you like to call it. To me, this seemed exactly what the situation was about: I advocated the manipulation of an object's data by introducing methods inside that class that do just that. However I realize that this should be a given either way, and it probably has more to do with how these methods are invoked (using a repository). I also had the feeling that in that article (see below), a Service Layer is more considered as a façade that delegates work to the underlying model, than an actual work-intensive layer. Application Layer [his name for Service Layer]: Defines the jobs the software is supposed to do and directs the expressive domain objects to work out problems. The tasks this layer is responsible for are meaningful to the business or necessary for interaction with the application layers of other systems. This layer is kept thin. It does not contain business rules or knowledge, but only coordinates tasks and delegates work to collaborations of domain objects in the next layer down. It does not have state reflecting the business situation, but it can have state that reflects the progress of a task for the user or the program. Which is reinforced here: Service interfaces. Services expose a service interface to which all inbound messages are sent. You can think of a service interface as a façade that exposes the business logic implemented in the application (typically, logic in the business layer) to potential consumers. And here: The service layer should be devoid of any application or business logic and should focus primarily on a few concerns. It should wrap Business Layer calls, translate your Domain in a common language that your clients can understand, and handle the communication medium between server and requesting client. This is a serious contrast to other resources that talk about the Service Layer: The service layer should consist of classes with methods that are units of work with actions that belong in the same transaction. Or the second answer to a question I've already linked: At some point, your application will want some business logic. Also, you might want to validate the input to make sure that there isn't something evil or nonperforming being requested. This logic belongs in your service layer. "Solution"? Following the guidelines in this answer, I came up with the following approach that uses a Service Layer: class UserController : Controller { private UserService _userService; public UserController(UserService userService){ _userService = userService; } public ActionResult MakeHimPay(string username, int amount) { _userService.MakeHimPay(username, amount); return RedirectToAction("ShowUserOverview"); } public ActionResult ShowUserOverview() { return View(); } } class UserService { private IUserRepository _userRepository; public UserService(IUserRepository userRepository) { _userRepository = userRepository; } public void MakeHimPay(username, amount) { _userRepository.GetUserByName(username).makePayment(amount); } } class UserRepository { public User GetUserByName(string name){ // Get appropriate user from database } } class User { private int debt; // debt in cents private string name; // getters public void makePayment(int cents){ debt -= cents; } } Conclusion All together not much has changed here: code from the controller has moved to the service layer (which is a good thing, so there is an upside to this approach). However this doesn't look like it had anything to do with my original answer. I realize design patterns are guidelines, not rules set in stone to be implemented whenever possible. Yet I have not found a definitive explanation of the service layer and how it should be regarded. Is it a means to simply extract logic from the controller and put it inside a service instead? Is it supposed to form a contract between the controller and the domain? Should there be a layer between the domain and the service layer? And, last but not least: following the original comment Business logic should really be in a service. Not in a model. Is this correct? How would I introduce my business logic in a service instead of the model?

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  • Android 1.6: "android.view.WindowManager$BadTokenException: Unable to add window -- token null is no

    - by Dan Monego
    I'm trying to open a dialog window, but every time I try to open it it throws this exception: E/AndroidRuntime( 206): Uncaught handler: thread main exiting due to uncaught exception E/AndroidRuntime( 206): android.view.WindowManager$BadTokenException: Unable to add window -- token null is not for an application E/AndroidRuntime( 206): at android.view.ViewRoot.setView(ViewRoot.java:460) E/AndroidRuntime( 206): at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:177) E/AndroidRuntime( 206): at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:91) E/AndroidRuntime( 206): at android.app.Dialog.show(Dialog.java:238) E/AndroidRuntime( 206): at android.app.Activity.showDialog(Activity.java:2413) I'm creating it by calling showDialog with the display's id. The onCreateDialog handler logs fine and I can step through it without an issue, but I've attached since it seems like I'm missing something in it: @Override public Dialog onCreateDialog(int id) { Dialog dialog; Context appContext = this.getApplicationContext(); switch(id) { case RENAME_DIALOG_ID: Log.i("Edit", "Creating rename dialog..."); dialog = new Dialog(appContext); dialog.setContentView(R.layout.rename); dialog.setTitle("Rename " + noteName); break; default: dialog = null; break; } return dialog; } Is there something missing from this? Some questions have talked about having this problem when creating a dialog from onCreate, which happen because the activity isn't created yet, but this is coming from a call from a menu object, and the appContext variable seems like it is correctly populated in the debugger.

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  • In an iPad SplitView, how do I add a Date Picker control to the Root View?

    - by Dr Dork
    I'm diving into iPhone OS development on the iPad and one of the things I'm playing with is the SplitView template. The template provides a window with a UISplitView view, containing the Root View (on the left of the window) and the Detail View (on the right of the window). The Root View is a subclass of a TableView. Rather than having the entire Root View consist of a TableView, I'd like it to contain a DatePicker view along with the TableView under it. When I go into IB and try and drop a DatePicker into the Root View, it won't let me. It will only let me add a DatePicker view to the Detail View. Why wont IB let me drop a DatePicker view into the Root View? How can I add a DatePicker to the RootView in addition to the TableView? I'm still learning this new platform, so I apologize if these questions are absurd in any way. Thanks so much in advance for your help, I'm going to continue researching these questions right now.

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  • In the Xcode SplitView template for an iPad app, how do I add a Date Picker control to the Root View

    - by Dr Dork
    I'm diving into iPhone OS development on the iPad and one of the things I'm playing with is the SplitView template. The template provides a window with a UISplitView view, containing the Root View (on the left of the window) and the Detail View (on the right of the window). The Root View is a subclass of a TableView. Rather than having the entire Root View consist of a TableView, I'd like it to contain a DatePicker view along with the TableView under it. When I go into IB and try and drop a DatePicker into the Root View, it won't let me. It will only let me add a DatePicker view to the Detail View. Why wont IB let me drop a DatePicker view into the Root View? How can I add a DatePicker to the RootView in addition to the TableView? I'm still learning this new platform, so I apologize if these questions are absurd in any way. Thanks so much in advance for your help, I'm going to continue researching these questions right now.

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  • Iphone xCode - Navigation Controller on second xib view?

    - by Frames84
    Everything is fine, my navigation controller display's my 'Menu 1' item, but when i click it there appears to be a problem with the: [self.navigationController pushViewController:c animated:YES]; line it doesn't connect to the break point in the myClass file. so I think i've not joined something? but unsure what? my second view with the navigation controller doesn't have direct access to the AppDelegate so can't join it like i see in some tutorials. 1st view is just a button when clicked calls: [self presentModalViewController:mainViewController animated:YES]; my second View 'MainViewController' header looks like: @interface MainViewController :UITableViewController <UITableViewDelegate, UITableViewDataSource> { NSArray *controllers; UINavigationController *navController; } @property (nonatomic, retain) IBOutlet UINavigationController *navControllers; @property (nonatomic, retain) NSArray *controller; Then I have my MainViewController.m @synthesize controllers; @synthesize navController; - (void) viewDidLoad { NSMutableArray *array = [[NSMutaleArray alloc] init]; myClass *c = [[myClass alloc] initWithStyle:UITableViewStylePlain]; c.Title = @"Menu 1"; [array addObject:c]; self.Controllers = array; [array release]; } implemented numberOfRowsInSection and cellForRowAtIndexPath - (void) tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { NSUInteger row = [indexPath row]; myClass *c = [self.controllers objectAtIndex:row]; [self.navigationController pushViewController:c animated:YES]; // doesn't load myClass c // [self.navController pushViewController:c animated:YES]; } Also in interface designer I dragged a Navigation Controller onto my new XIB and changed the Root View Controller class to MainViewController and also connected the File Owner connector to the Navigation Controller to connect the navController Outlet. Thanks for you time.

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  • What is the standard convention for defining nested view:viewmodel mapping in MVVM Light

    - by firoso
    so in classic MVVM examples ive seen DataTemplate definitions are used to map up View Models to Views, what is the standard way to do this in MVVM Light framework, and where should the mappings be located? Following are examples of what I'm doing now and what I'm talking about, blendability is important to me! Main Window: <Window xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" mc:Ignorable="d" x:Class="STS2Editor.MainWindow" Title="{Binding ApplicationTitle, Mode=OneWay}" DataContext="{Binding RootViewModel, Source={StaticResource Locator}}"> <Window.Resources> <ResourceDictionary> <ResourceDictionary.MergedDictionaries> <ResourceDictionary Source="Skins/ApplicationSkin.xaml" /> <ResourceDictionary Source="Resources/ViewMappings.xaml" /> </ResourceDictionary.MergedDictionaries> </ResourceDictionary> </Window.Resources> <Grid> <ContentControl Content="{Binding ApplicationManagementViewModel}" HorizontalAlignment="Left" VerticalAlignment="Top"/> </Grid> </Window> In the above code, my RootViewModel class has an instance of the class ApplicationManagementViewModel with the same property name: public ApplicationManagementViewModel ApplicationManagementViewModel {get {...} set {...} } I reference the ResourceDictionary "ViewMappings.xaml" to specify how my view model is represented as a view. <ResourceDictionary xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:local="clr-namespace:STS2Editor.ViewModel"> <DataTemplate DataType="{x:Type local:ApplicationManagementViewModel}"> <local:ApplicationManagementView/> </DataTemplate> </ResourceDictionary> should I be doing things like this using ViewModelLocator? what about collections of view models?

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  • rspec & rails 3 cannot find model object

    - by Ceilingfish
    I'm trying to put some specs around a new rails 3 project I am working on, and my first test doesn't seem to be able to find a model. I've installed rspec from the command line using: sudo gem install rspec --pre and then I put the following in my Gemfile gem "rspec-rails", ">= 2.0.0.beta.1" But when I run my test I get ./spec/models/world_spec.rb:1: uninitialized constant World (NameError) rake aborted! Command /opt/local/bin/ruby -Ilib -Ispec "./spec/models/world_spec.rb" failed /opt/local/lib/ruby/gems/1.8/gems/rspec-core-2.0.0.beta.4/lib/rspec/core/rake_task.rb:71:in `define' /opt/local/lib/ruby/gems/1.8/gems/rake-0.8.7/lib/rake.rb:1112:in `verbose' /opt/local/lib/ruby/gems/1.8/gems/rspec-core-2.0.0.beta.4/lib/rspec/core/rake_task.rb:57:in `send' /opt/local/lib/ruby/gems/1.8/gems/rspec-core-2.0.0.beta.4/lib/rspec/core/rake_task.rb:57:in `define' /opt/local/lib/ruby/gems/1.8/gems/rake-0.8.7/lib/rake.rb:636:in `call' /opt/local/lib/ruby/gems/1.8/gems/rake-0.8.7/lib/rake.rb:636:in `execute' /opt/local/lib/ruby/gems/1.8/gems/rake-0.8.7/lib/rake.rb:631:in `each' /opt/local/lib/ruby/gems/1.8/gems/rake-0.8.7/lib/rake.rb:631:in `execute' /opt/local/lib/ruby/gems/1.8/gems/rake-0.8.7/lib/rake.rb:597:in `invoke_with_call_chain' /opt/local/lib/ruby/1.8/monitor.rb:242:in `synchronize' /opt/local/lib/ruby/gems/1.8/gems/rake-0.8.7/lib/rake.rb:590:in `invoke_with_call_chain' /opt/local/lib/ruby/gems/1.8/gems/rake-0.8.7/lib/rake.rb:583:in `invoke' /opt/local/lib/ruby/gems/1.8/gems/rake-0.8.7/lib/rake.rb:2051:in `invoke_task' /opt/local/lib/ruby/gems/1.8/gems/rake-0.8.7/lib/rake.rb:2029:in `top_level' /opt/local/lib/ruby/gems/1.8/gems/rake-0.8.7/lib/rake.rb:2029:in `each' /opt/local/lib/ruby/gems/1.8/gems/rake-0.8.7/lib/rake.rb:2029:in `top_level' /opt/local/lib/ruby/gems/1.8/gems/rake-0.8.7/lib/rake.rb:2068:in `standard_exception_handling' /opt/local/lib/ruby/gems/1.8/gems/rake-0.8.7/lib/rake.rb:2023:in `top_level' /opt/local/lib/ruby/gems/1.8/gems/rake-0.8.7/lib/rake.rb:2001:in `run' /opt/local/lib/ruby/gems/1.8/gems/rake-0.8.7/lib/rake.rb:2068:in `standard_exception_handling' /opt/local/lib/ruby/gems/1.8/gems/rake-0.8.7/lib/rake.rb:1998:in `run' /opt/local/lib/ruby/gems/1.8/gems/rake-0.8.7/bin/rake:31 /opt/local/bin/rake:19:in `load' /opt/local/bin/rake:19 My spec is in spec/models/world_spec.rb, and looks like describe World, "#hello" do it "should be invalid" do World.new.should be_invalid? end end I tried adding a line like require "app/model/world" and require "world" but to no success. Does anyone know what I'm doing wrong?

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  • Notifying view controller when subview touch events occur.

    - by Nebs
    I have a UIViewController whose view has a custom subview. This custom subview needs to track touch events and report swipe gestures. Currently I put touchesBegan, touchesMoved, touchesEnded and touchesCancelled in the subview class. With some extra logic I am able to get swipe gestures and call my handleRightSwipe and handleLeftSwipe methods. So now when I swipe within the subview it calls its local swipe handling methods. This all works fine. But what I really need is for the handleRightSwipe and handleLeftSwipe methods to be in the view controller. I could leave them in the subview class but then I'd have to bring in all the logic and data as well and that kind of breaks the MVC idea. So my question is is there a clean way to handle this? Essentially I want to keep my touch event methods in the subview so that they only trigger for that specific view. But I also want the view controller to be informed when these touch events (or in this case swipe gestures) occur. Any ideas? Thanks.

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  • How to Put Javascript into an ASP.NET MVC View

    - by Maxim Z.
    I'm really new to ASP.NET MVC, and I'm trying to integrate some Javascript into a website I'm making as a test of this technology. My question is this: how can I insert Javascript code into a View? Let's say that I start out with the default ASP.NET MVC template. In terms of Views, this creates a Master page, a "Home" View, and an "About" view. The "Home" View, called Index.aspx, looks like this: <%@ Page Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage" %> <asp:Content ID="indexTitle" ContentPlaceHolderID="TitleContent" runat="server"> Home Page </asp:Content> <asp:Content ID="indexContent" ContentPlaceHolderID="MainContent" runat="server"> <h2><%= Html.Encode(ViewData["Message"]) %></h2> <p> To learn more about ASP.NET MVC visit <a href="http://asp.net/mvc" title="ASP.NET MVC Website">http://asp.net/mvc</a>. </p> <p>Welcome to this testing site!</p> </asp:Content> Adding a <script> tag here didn't work. Where and how should I do it? P.S.: I have a feeling I'm missing something very basic... Thanks in advance!

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  • Django and ImageField Question

    - by Hellnar
    Hello I have a such model: Foo (models.Model): slug = models.SlugField(unique=True) image = models.ImageField(upload_to='uploads/') I want to do two things with this: First of all, I want my image to be forced to resize to a specific width and height after the upload. I have tried this reading the documentation but seems to getting error: image = models.ImageField(upload_to='uploads/', height_field=258, width_field=425) Secondly, when adding an item via admin panel, I want my image's file name to be renamed as same as slug, if any issue arises (like if such named image already exists, add "_" to the end as it used to do. IE: My slug is i-love-you-guys , uploaded image such have i-love-you-guys.png at the end.

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  • Django disable editing (but allow adding) in TabularInline view

    - by VoteyDisciple
    I want to disable editing ALL objects within a particular TabularInline instance, while still allowing additions and while still allowing editing of the parent model. I have this trivial setup: class SuperviseeAdmin(admin.TabularInline): model = Supervisee class SupervisorAdmin(admin.ModelAdmin): inlines = [SuperviseeAdmin] admin.site.register(Supervisor, SupervisorAdmin) I have tried adding a has_change_permission function to SuperviseeAdmin that returns False unconditionally, but it had no effect. I have tried setting actions = None in SuperviseeAdmin but it had no effect. What might I be overlooking that could get this to work?

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  • iphone app scroll view is horizontal but i want it vertical - how do i change this?

    - by Billy Jones
    Hi Folks, Got this code for a viewscroller from the apple developers site. @synthesize scrollView1, scrollView2; const CGFloat kScrollObjHeight = 467.0; const CGFloat kScrollObjWidth = 320.0; const NSUInteger kNumImages = 6; (void)layoutScrollImages { UIImageView *view = nil; NSArray *subviews = [scrollView1 subviews]; // reposition all image subviews in a horizontal serial fashion CGFloat curXLoc = 0; for (view in subviews) { if ([view isKindOfClass:[UIImageView class]] && view.tag 0) { CGRect frame = view.frame; frame.origin = CGPointMake(curXLoc, 0); view.frame = frame; curXLoc += (kScrollObjWidth); } } // set the content size so it can be scrollable [scrollView1 setContentSize:CGSizeMake((kNumImages * kScrollObjWidth), [scrollView1 bounds].size.height)]; } it works brilliantly the images are rotated by pulling them left or right. but I want to pull the images up and down to change them. Can anyone help me out with this? this part in the code looks as if it controls the direction but i'm not sure how to change it. // reposition all image subviews in a horizontal serial fashion CGFloat curXLoc = 0; for (view in subviews) { if ([view isKindOfClass:[UIImageView class]] && view.tag 0) { CGRect frame = view.frame; frame.origin = CGPointMake(curXLoc, 0); view.frame = frame; curXLoc += (kScrollObjWidth); } } Any help most appreciated, thanks! Billy

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  • Presenting UINavigationController modally -- problem setting up tool and nav bar items in root view controller viewDidLoad

    - by Bogatyr
    In my iOS app I'm creating and presenting a UINavigationController modally like so: MyViewController *myvc = [[[MyViewController alloc] initWithNibName:@"MyViewController" bundle:nil] autorelease]; UINavigationController *navVC = [[[UINavigationController alloc] initWithRootViewController:myvc] autorelease]; [self presentModalViewController:navVC animated:YES]; In the MyViewController viewDidLoad I'm creating and setting toolbar items for the navigation controller's toolbar, like so: self.navigationController.toolbar.items = [NSArray arrayWithObjects:(items...), nil]; the problem I'm having is that the items don't show up. If instead I call a method from MyViewController's viewDidLoad method that adds the toolbar items via performSelector:withObject:afterDelay:0, then it works perfectly. So there's obviously some race condition going on here with the initial presentation of the UINavigationController, initialization of its toolbar/navbar, and the initialization of the nav bar's specified initial root view controller. I verified in the debugger that the root view controller's viewDidLoad is called after the UINavigationController's viewDidLoad method. In fact, the root view controller's viewDidLoad method is not called until presentModalViewController: is called, and the UINavigationController's viewDidLoad is called within initWithRootViewController, so doesn't that imply that the UINavigationController object should be "all ready to go", including its nav bar and toolbars? I thought at first that the navigation controller's toolbar object may not exist yet at MyViewController's viewDidLoad time, but it clearly does. At least, NSLog shows that it is not nil during MyViewController's viewDidLoad method. In fact, the UINavigationController's toolbar object is identical at both times: in the root view controller's viewDidLoad, and in the "setupToolbar" method that I called with performSelector:withObject:afterDelay, so it's not getting "re-initialized" somehow. So, what's going on here? Why aren't my toolbar modifications "sticking" in MyViewController's viewDidLoad, and why does performing them in the next iteration of the runloop (performSelector:withObject:afterDelay:0) make it work? What is the "right" way of setting up initial navbar / toolbar items in code from the rootViewController of the UINavigationController?

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  • django ManyToMany through help

    - by dotty
    Hay I've got a question about relationships. I want to Users to have Friendships. So a User can be a friend with another User. I'm assuming i'll need to use the ManyToManyField, through a Friendship table. But i cannot get it to work. Any ideas? Here are my models. class User(models.Model): username = models.CharField(max_length=999) password = models.CharField(max_length=999) created_on = models.DateField(auto_now = False, auto_now_add = True) updated_on = models.DateField(auto_now = True, auto_now_add = False) friends = models.ManyToManyField('User', through='Friendship') class Friendship(models.Model): user = models.ForeignKey('User') friend = models.ForeignKey('User') Thanks

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  • Best Role-Based Access Control (RBAC) database model

    - by jhs
    What is the best database schema to track role-based access controls for a web application? I am using Rails, but the RBAC plugin linked by Google looks unmaintained (only 300 commits to SVN; latest was almost a year ago). The concept is simple enough to implement from scratch, yet complex and important enough that it's worth getting right. So how do others architect and implement their RBAC model?

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  • WPF Usercontrol interaction with parent view / viewmodel

    - by obaylis
    Hi I have a mainView window which has its dataContext set to it's own viewModel. On that viewModel is a DateTime property which in turn is bound to a datepicker on my main view using 2 way binding. <toolkit:DatePicker DateSelected="{Binding mainDateTimeProperty, Mode=TwoWay}" /> This is all fine so far. On the change of my datetime property I create a list which is then bound to a datagrid elsewhere on the mainview. This all works fine. My question is to do with a usercontrol I want to add to the main view. I want this usercontrol to be self contained so have created it with it's own viewmodel but it does also need access to mainDateTimeProperty I thought that best way to go would be to create a dependencyProperty on the usercontrol and when I create my control in the main view I bind the dp to the datetime as follows. <uc:MyNewUserControl DateProperty="{Binding mainDateTimeProperty}" /> Trouble is how do I have the usercontrol maintain datacontext with it's viewmodel and yet still have the dependency property bound to a property on the main view model? Hope this is clear. Can post some more code if necessary. Looking for a best practice approach if possible. Thanks very much for any advice.

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  • Strange UIKit bug, table view row stays selected

    - by Can Berk Güder
    I'm facing what appears to be a UIKit bug, and it takes the combination of two less commonly used features to reproduce it, so please bear with me here. I have quite the common view hierarchy: UITabBarController -> UINavigationController -> UITableViewController and the table view controller pushes another table view controller onto the navigation controller's stack when a row is selected. There's absolutely nothing special or fancy in the code here. However, the second UITableViewController, the "detail view controller" if you will, does two things: It sets hidesBottomBarWhenPushed to YES in its init method, so the tab bar is hidden when this controller is pushed: - (id)initWithStyle:(UITableViewStyle)style { if(self = [super initWithStyle:style]) { self.hidesBottomBarWhenPushed = YES; } return self; } It calls setToolbarHidden:NO animated:YES and setToolbarHidden:YES animated:YES on self.navigationController in viewWillAppear: and viewWillDisappear: respectively, causing the UIToolbar provided by UINavigationController to be displayed and hidden with animations: - (void)viewWillAppear:(BOOL)animated { [super viewWillAppear:animated]; [self.navigationController setToolbarHidden:NO animated:YES]; } - (void)viewWillDisappear:(BOOL)animated { [super viewWillDisappear:animated]; [self.navigationController setToolbarHidden:YES animated:YES]; } Now, if the second UITableViewController was pushed by selecting the row at the bottom of the screen (it doesn't have to be the last row) in the first controller, this row does not automatically get deselected when the user immediately or eventually returns to the first controller. Further, the row cannot be deselected by calling deselectRowAtIndexPath:animated: on self.tableView in viewWillAppear: or viewDidAppear: in the first controller. I'm guessing this is a bug in UITableViewController's drawing code which of course only draws visible rows, but unfortunately fails to determine correctly if the bottommost row will be visible in this case. I failed to find anything on this on Google or OpenRadar, and was wondering if anyone else on SO had this problem or knew a solution/workaround.

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  • django error:The model Tribe is already registered

    - by zjm1126
    when i python manage.py syncdb,it show this: The following content types are stale and need to be deleted: maps | tribe Any objects related to these content types by a foreign key will also be deleted. Are you sure you want to delete these content types? If you're unsure, answer 'no'. Type 'yes' to continue, or 'no' to cancel: no when i put 'no' ,and then python manage runserver: AlreadyRegistered at / The model Tribe is already registered what should i do ? thanks

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  • Examples of Hierarchical-Model-View-Controller (HMVC)?

    - by Stephen
    Hi, I'm interested in the Presentation-Abstraction-Control? (aka Hierarchical-Model-View-Controller (HMVC)) Architectural Pattern for constructing complex user interfaces (GUI or web) and was wondering if anyone was aware of any examples in the wild where I could read the code? My list so far; Cairngorm framework for Adobe Flex any others I'm aware of the JavaWorld article and associated letters cited in the wikipedia article http://en.wikipedia.org/wiki/Presentation-abstraction-control

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  • Limiting choices from an intermediary ManyToMany junction table in Django

    - by Matthew Rankin
    Background I've created three Django models—Inventory, SalesOrder, and Invoice—to model items in inventory, sales orders for those items, and invoices for a particular sales order. Each sales order can have multiple items, so I've used an intermediary junction table—SalesOrderItems—using the through argument for the ManyToManyField. Also, partial billing of a sales orders is allowed, so I've created a ForeignKey in the Invoice model related to the SalesOrder model, so that a particular sales order can have multiple invoices. Here's where I deviate from what I've normally seen. Instead of relating the Invoice model to the Item model via a ManyToManyField, I've related the Invoice model to the SalesOrderItem intermediary junction table through the intermediary junction table InvoiceItem. I've done this because it better models reality—our invoices are tied to sales orders and can only include items that are tied to that sales order as opposed to any item in inventory. I will admit that it does seem strange having the intermediary junction table of a ManyToManyField related to the intermediary junction table of another ManyToManyField. Question How can I limit the choices available for the invoice_items in the Invoice model to just the sales_order_items of the SalesOrder model for that particular Invoice? (I tried using limit_choices_to= {'sales_order': self.invoice.sales_order}) as part of the item = models.ForeignKey(SalesOrderItem) in the InvoiceItem model, but that didn't work. Am I correct in thinking that limiting the choices for the invoice_items should be handled in the model instead of in a form? Code class Item(models.Model): item_num = models.SlugField(unique=True) default_price = models.DecimalField(max_digits=10, decimal_places=2, blank=True, null=True) class SalesOrderItem(models.Model): item = models.ForeignKey(Item) sales_order = models.ForeignKey('SalesOrder') unit_price = models.DecimalField(max_digits=10, decimal_places=2) quantity = models.DecimalField(max_digits=10, decimal_places=4) class SalesOrder(models.Model): customer = models.ForeignKey(Party) so_num = models.SlugField(max_length=40, unique=True) sales_order_items = models.ManyToManyField(Item, through=SalesOrderItem) class InvoiceItem(models.Model): item = models.ForeignKey(SalesOrderItem) invoice = models.ForeignKey('Invoice') unit_price = models.DecimalField(max_digits=10, decimal_places=2) quantity = models.DecimalField(max_digits=10, decimal_places=4) class Invoice(models.Model): invoice_num = models.SlugField(max_length=25) sales_order = models.ForeignKey(SalesOrder) invoice_items = models.ManyToManyField(SalesOrderItem, through='InvoiceItem')

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  • doctrine regenerating models from yml only the base models?

    - by TaMeR
    I am wondering if there is a way to handle this more elegantly. After generating the "main" models and base models from yml files the first time I have to add at the very leased an include for the base model to the "main" model like so: include_once 'generated/BaseBlog.php'; At the moment before I regenerate the models I move my changed main models, which is mostly way more then just the include path, in to a tmp folder then I delete all the models. And after regenerating I move my modified models back overwriting the generated main models. isn't there a way to just create the base models and not touch the main models? Or how do you guys handle this?

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