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  • How can one connect to an RFCOMM device other than another phone in Android?

    - by Charles Duffy
    The Android API provides examples of using listenUsingRfcommWithServiceRecord() to set up a socket and createRfcommSocketToServiceRecord() to connect to that socket. I'm trying to connect to an embedded device with a BlueSMiRF Gold chip. My working Python code (using the PyBluez library), which I'd like to port to Android, is as follows: sock = bluetooth.BluetoothSocket(proto=bluetooth.RFCOMM) sock.connect((device_addr, 1)) return sock.makefile() ...so the service to connect to is simply defined as channel 1, without any SDP lookup. As the only documented mechanism I see in the Android API does SDP lookup of a UUID, I'm slightly at a loss.

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  • Zend Layout and Bootstrapping

    - by emeraldjava
    So i'm using the standard Zend Layout for my site. I have a number of custom controllers and views, and the content of these pages is displayed, but the details in the head element of the layout.phtml are not shown. Do i need to manually associate the Zend_Layout with each specific controller?. I expected since the layout is loaded via the bootstrap this should be available for free. My app.ini file has # layout resources.layout.layoutPath = APPLICATION_PATH "/layouts/scripts" resources.layout.layout = "layout" #resources.view[] = # Views resources.view.encoding = "UTF-8" resources.view.basePath = APPLICATION_PATH "/views/" my layout.phtml <?php echo $this->doctype() ?> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <?php echo $this->headTitle() ?> <?php echo $this->jQuery();?> </head> <!-- application/layouts/scripts/layout.phtml --> <body> <div id="content"> <?php echo $this->layout()->content ?> </div> </body>

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  • Coda Slider and Fancybox Conflict

    - by Jings
    Hey there, i have some issues with Coda Slider and Fancybox. I use Fancybox to load an external Site within an Iframe and Coda Slider is for the Content Slider on the Startpage. If i have the jquery-easing Plugin called in my Head fpr the Coda Slider, the Fancybox doesn't work. When i delete the link to jquery-easing-1.3 the Coda Slider throws an Exception but the Fancybox works perfectly Here is some Code: <script type="text/javascript" src="<?php bloginfo('template_directory') ?>/js/jquery.js"></script> <script type="text/javascript" src="<?php bloginfo('template_directory') ?>/fancybox/jquery.fancybox-1.3.4.pack.js"></script> <script type="text/javascript" src="<?php bloginfo('template_directory') ?>/js/coda-slider.js"></script> <script type="text/javascript" src="<?php bloginfo('template_directory') ?>/js/jquery.easing.1.3.js"></script> <script> $(document).ready(function(){ $(".book a").fancybox({ 'width' : '75%', 'height' : '75%', 'speedIn' : 600, 'speedOut' : 200, 'overlayShow' : true, 'type' : 'iframe', 'autoscale' : false, 'hideOnOverlayClick' : true }); $('#coda-slider').codaSlider({ autoSlide: true, autoSlideInterval: 5500, autoHeightEaseDuration: 2500, autoHeightEaseFunction: "easeInOutElastic", slideEaseDuration: 2500, slideEaseFunction: "easeInOutElastic", dynamicArrows: false, dynamicTabs: false }); }); </script> Don't know why this doesn't work as it should :) Hope you Guys know =)

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  • Why can't I get Python's urlopen() method to work?

    - by froadie
    Why isn't this simple Python code working? import urllib file = urllib.urlopen('http://www.google.com') print file.read() This is the error that I get: Traceback (most recent call last): File "C:\workspace\GarchUpdate\src\Practice.py", line 26, in <module> file = urllib.urlopen('http://www.google.com') File "C:\Python26\lib\urllib.py", line 87, in urlopen return opener.open(url) File "C:\Python26\lib\urllib.py", line 206, in open return getattr(self, name)(url) File "C:\Python26\lib\urllib.py", line 345, in open_http h.endheaders() File "C:\Python26\lib\httplib.py", line 892, in endheaders self._send_output() File "C:\Python26\lib\httplib.py", line 764, in _send_output self.send(msg) File "C:\Python26\lib\httplib.py", line 723, in send self.connect() File "C:\Python26\lib\httplib.py", line 704, in connect self.timeout) File "C:\Python26\lib\socket.py", line 514, in create_connection raise error, msg IOError: [Errno socket error] [Errno 10060] A connection attempt failed because the connected party did not properly respond after a period of time, or established connection failed because connected host has failed to respond I've tried it with several different pages but I can never get the urlopen method to execute correctly.

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  • Problem requesting a HTTPS with TCL

    - by Javier
    Hi Everybody, I'm trying to do the following request using TCL (OpenACS) http::register https 443 tls::socket set url "https://encrypted.google.com" set token [http::geturl $url -timeout 30000] set status [http::status $token] set answer [http::data $token] http::cleanup $token http::unregister https The problem is that when I read the $status variable I get "eof" and the $answer variable becomes empty. I tried enabling tls V.1 http::register https 443 [list tls::socket -tls1 1] and it works only for the site https://www.galileo.edu, but not for https://encrypted.google.com. The site what I'm trying to connect is https://graph.facebook.com/me/feed?access_token=... but it doesn't work. I used curl to retrieve the contents of the pages in HTTPS and it works, I have installed OpenSSL, so I can't see the problem, there is another way to do HTTPS connections with TCL?. I can't see if this is a problem of coding (maybe I'm registered wrong the https protocol) or maybe It is a bad configuration of my server. Hope somebody helps!! Thanks!

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  • How do I recieve byteArray send from Server and read 4 single bytes at a time.

    - by k80sg
    I need to receive 320 bytes of data from a server which consist of 80 4 bytes int fields. How do I receive them in bytes of 4 and display their respective int values? Thanks. Not sure if this is right for the receiving part: //for reading the data from the socket BufferedInputStream bufferinput=new BufferedInputStream(NewSocket.getInputStream()); DataInputStream datainput=new DataInputStream(bufferinput); byte[] handsize=new byte[32]; // The control will halt at the below statement till all the 32 bytes are not read from the socket. datainput.readFully(handsize);

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  • How to set timeout with python-mechanize?

    - by Michal Cihar
    I'm using python-mechanize to scrape some web sites, which sometime simply don't respond to requests and these requests stay open too long, so I need to limit timeout for these requests. While using urlopen method, the timeout can be set using timeout parameter, but I have not found easy way for doing it with high level API such as submit or click methods. Ideally the timeout would be set just once for whole browser class and all calls would honor that. It would be probably possible to customize this by passing custom request_class to every click and submit call, but this would just pollute the code, so I'm looking for nicer solution for setting timeout for mechanize's browser class (and no, I don't want to change default socket timeout using socket.setdefaulttimeout).

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  • Getting Started with Ruby & Ruby on Rails

    - by JakeTheSnake
    Some background: I'm a jack-of-all traits, one of which is programming. I learned VB6 through Excel and PHP for creating websites and so far it's worked out just fine for me. I'm not CS major or even mathematically inclined - logic is what interests me. Current status: I'm willing to learn new and more powerful languages; my first foray into such a route is learning Ruby. I went to the main Ruby website and did the interactive intro. (by the way, I'm currently getting redirected to google.com when I try the link...it's happening to other websites as well...is my computer infected?) I liked what I learned and wanted to get started using Ruby to create websites. I downloaded InstantRails and installed it; everything so far has been fine - the program starts up just fine, and I can test some Ruby code in the console. However my troubles begin when I try and view a web page with Ruby code present. Lastly, my problem: As in PHP, I can browse to the .php file directly and through using PHP tags and some simple 'echo' statements I can be on my way in making dynamic web pages. However with the InstantRails app working, accessing a .rb or .rhtml page doesn't produce similar results. I made a simple text file named 'test.rb' and put basic HTML tags in there (html, head, body) and the Ruby tags <%= and % with some ruby code inside. The web page actually shows the tags and the code - as if it's all just plain HTML. I take it Ruby isn't parsing the page before it is displayed to the user, but this is where my lack of understanding of the Ruby environment stops me short. Where do I go from here?

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  • Examples of networked Flash games

    - by videodnd
    Maybe I am asking the wrong questions, because I don't see any sample projects out there. I know Flash developers have done Kiosks and renovated arcade games. "Come on, we see Flash everywhere." Is there a sample project I could be pointed towards, it would be an ass-saver. Can I prepare my swf files like an image gallery and receive XML commands to load it? Where do I start? Flash/After Effects skills have got me through so far, but I need help!!! It would be fun if it wasn't so stressful. Criteria TCP/IP socket connection Flash package XML commands load swf file in to a container Additional Questions How do I prepare my Flash files and XML sheet to receive commands "any sample out there"? What about e.data, urlLoad, xmlSocket Class, XMLCP/IP XML socket connection to load Is binary or XML method better for loading and reloading swf files? Do I need Red5 or a media server? videoDnd, Ambitious Development Noob

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  • Convert JavaScript to jQuery

    - by bloggerious
    I have the following JavaScript code which I like to convert to jQuery but has no luck. I would like to convert it to jQuery specifically beginning from this: <?php if(Voting_Method == 2){ if (mnmxmlhttp[htmlid].readyState == 4) { xvotesString[htmlid] = mnmxmlhttp[htmlid].responseText; if (xvotesString[htmlid].match (errormatch)) { xvotesString[htmlid] = xvotesString[htmlid].substring (6, xvotesString[htmlid].length); <?php if(Voting_Method == 1){ echo "changemnmvalues (htmlid, value, true);"; }?> } else { <?php if(Voting_Method == 2){ echo "var mySplitResult = xvotesString[htmlid].split('~');\n"; echo "target3 = document.getElementById ('xvote-' + htmlid);\n"; echo "target3.style.width = mySplitResult[0] + 'px';\n"; echo "if (target4 = document.getElementById ('mnma-' + htmlid))"; echo " target4.innerHTML = mySplitResult[1];\n"; echo "if (target5 = document.getElementById ('mnmb-' + htmlid))"; echo " target5.innerHTML = mySplitResult[2];\n"; echo "if (target6 = document.getElementById ('mnmc-' + htmlid))"; echo " target6.style.display='none'; \n"; echo "if (target6 = document.getElementById ('mnmd-' + htmlid))"; echo " target6.style.display='block'; \n"; echo "target7 = document.getElementById ('xvotes-' + htmlid);\n"; echo "target7.className = 'star-rating-noh';\n"; }?> <?php if(Voting_Method == 1){ echo 'if (xvotesString[htmlid].substring (1, 6) == "ERROR") { '; echo "alert(xvotesString[htmlid]); } else {"; echo "changemnmvalues (htmlid, value, false); } "; }?> } Any help is greatly appreciated.

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  • I installed XAMPP in a virtual drive and now I can't run its services. Why?

    - by Haris
    Hi, The description is quite long. Please spend some time to read it. ^:)^ I have an old PHP application and I'm trying to test and debug it. Unfortunately, the application uses important data so I can't just click this and that. Now, what I'm trying to do is create a copy of the application in a different computer. From now on, I will call the computer running my original PHP application as 'Computer A' and the computer which I'm going to use to run the copy of the application as 'Computer B'. To prevent missing link problems since the application contains static paths, such in images or tags, I have to copy all files and folder related to my PHP application from Computer A to the same path in Computer B. Unfortunately, Computer B only has drive C while Computer A has drive D and the files of my PHP application is located in 'D:\xampp\htdocs' in Computer A. OK, now I have to create drive D in computer B. At first, I tried to create a second partition in Computer B by using PowerQuest Partition Magic 8, but somehow Partition Magic doesn't run in Computer B. I have tried to reinstall it but it still doesn't run. So, another alternative is to create a virtual drive. That is what I did. I created a virtual drive by running the 'subst' command in Command Prompt. The virtual drive is D and it refers to a directory, which is 'C:\Virtual'. After I have drive D in Computer B, I installed XAMPP there. The installation was successful. Now, I also have 'D:\xampp\htdocs' in Computer B. However, when I ran the Apache, MySQL, or Filezilla service, I receive an error message "Error 3: The system cannot find the file specified.". In Computer B, there is no IIS or process using the port 80. What should I do? Please help me. Many thanks in advance, Haris

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  • Android - Connectivity Questions

    - by Donal Rafferty
    I have a couple of questions about connectivity on Android, if anyone has any insight it would be great. What is the default when an application wants to wirelessly connect? Is it wlan? And if wlan is switched off or there is no access points around is it 3g or gprs? Is a device always ip connected? Or when its disabled from wlan or 3g does it lose its ip address? Is an application, for example the browser only ever connected to one ip address? Or can it be connected to multiple addresses for each radio such as gprs or wifi (wlan)? Can an application decide which connection to open a socket to? For example can I create an application and decide whether to connect the socket to the wlan or gprs? Or does the OS decide? Finally how do native applications handle connectivity? In the same manner?

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  • modx friendly urls nginx FPM php5.3 - friendly url's not working

    - by okdan
    Hi, Im using php5.3 on nginx 0.8.53 with FPM on Modx revolution. Im trying to get "friendly url's" to work, but all I get is 404's. In modx config, friendly url's is set to yes, friendly aliases is set to no (so it drops the suffix) My config file: server { listen 80; server_name .mydomain.net; # index index.php; root /home/mylogin/htdocs; location / { index index.php index.html; if (!-e $request_filename) { rewrite ^/(.*)$ /index.php?q=$1 last; } } # serve static files directly location ~* ^.+\.(jpg|jpeg|gif|css|png|js|ico)$ { root /home/mylogin/htdocs; access_log off; expires 30d; break; } } Fast CGI modx file: fastcgi_connect_timeout 60; fastcgi_send_timeout 300; fastcgi_buffers 4 32k; fastcgi_busy_buffers_size 32k; fastcgi_temp_file_write_size 32k; fastcgi_pass 127.0.0.1:9000; fastcgi_index index.php; fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name; fastcgi_ignore_client_abort on; fastcgi_intercept_errors on; fastcgi_read_timeout 300; fastcgi_param QUERY_STRING $query_string; fastcgi_param REQUEST_METHOD $request_method; fastcgi_param CONTENT_TYPE $content_type; fastcgi_param CONTENT_LENGTH $content_length; fastcgi_param SCRIPT_NAME $fastcgi_script_name; fastcgi_param REQUEST_URI $request_uri; fastcgi_param DOCUMENT_URI $document_uri; fastcgi_param DOCUMENT_ROOT $document_root; fastcgi_param SERVER_PROTOCOL $server_protocol; fastcgi_param GATEWAY_INTERFACE CGI/1.1; fastcgi_param SERVER_SOFTWARE nginx/$nginx_version; fastcgi_param REMOTE_ADDR $remote_addr; fastcgi_param REMOTE_PORT $remote_port; fastcgi_param SERVER_ADDR $server_addr; fastcgi_param SERVER_PORT $server_port; fastcgi_param SERVER_NAME $server_name; fastcgi_param REDIRECT_STATUS 200;

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  • How do programming languages bind identifiers to functions

    - by sub
    I'm talking about C and/or C++ here as this are the only languages I know used for interpreters where the following could be a problem: If we have an interpreted language X how can a library written for it add functions to the language which can then be called from within programs written in the language? PHP example: substr( $str, 5, 10 ); How is the function substr added to the "function pool" of PHP so it can be called from within scripts? It is easy for PHP storing all registered function names in an array and searching through it as a function is called in a script. However, as there obviously is no eval in C(++), how can the function then be called? I assume PHP doesn't have 100MB of code like: if( identifier == "substr" ) { return PHP_SUBSTR(...); } else if( ... ) { ... } Ha ha, that would be pretty funny. I hope you have understood my question so far. How do interpreters solve this problem? How can I solve this for my own experimental toy interpreter?

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  • Problem with starting OpenOffice service (soffice) from Java (command working in commandline, but no

    - by Shervin
    I want to exceute a simple command which works from the shell but doesn't work from Java. This is the command I want to execute, which works fine: soffice -headless "-accept=socket,host=localhost,port=8100;urp;" This is the code I am excecuting from Java trying to run this command: String[] commands = new String[] {"soffice","-headless","\"-accept=socket,host=localhost,port=8100;urp;\""}; Process process = Runtime.getRuntime().exec(commands) int code = process.waitFor(); if(code == 0) System.out.println("Commands executed successfully"); When I run this program I get "Commands executed successfully". However the process is not running when the program finishes. Is it possible that the JVM kills the program after it has run? Why doesn't this work?

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  • Rails 3.o MYSQL connection problem

    - by palani
    Hi I have installed RVM in my ubunut linux box and configured the Rails 3 app in that ... i can able to start app server... my problem is when i invoke http://localhost:3000 . i getting the follwing error Mysql::Error (Can't connect to local MySQL server through socket '/var/run/mysqld/mysqld.sock' (2)): I checked mysqld service is running well. I checked my database.yml file .... the defined well development: adapter: mysql encoding: utf8 reconnect: false database: test_development username: root password: admin socket: /var/run/mysqld/mysqld.sock my installed mysql gem version is 2.8.1.... I really don't know what is the problem here....

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  • PHPUnit: Testing if a protected method was called

    - by Luiz Damim
    I´m trying to test if a protected method is called in a public interface. <?php abstract class SomeClassAbstract { abstract public foo(); public function doStuff() { $this->_protectedMethod(); } protected function _protectedMethod(); { // implementation is irrelevant } } <?php class MyTest extends PHPUnit_Framework_TestCase { public function testCalled() { $mock = $this->getMockForAbstractClass('SomeClass'); $mock->expects($this->once()) ->method('_protectedMethod'); $mock->doStuff(); } } I know it is called correctly, but PHPUnit says its never called. The same happens when I test the other way, when a method is never called: <?php abstract class AnotherClassAbstract { abstract public foo(); public function doAnotherStuff() { $this->_loadCache(); } protected function _loadCache(); { // implementation is irrelevant } } <?php class MyTest extends PHPUnit_Framework_TestCase { public function testCalled() { $mock = $this->getMockForAbstractClass('AnotherClass'); $mock->expects($this->once()) ->method('_loadCache'); $mock->doAnotherStuff(); } } The method is called but PHPUnit says that it is not. What I´m doing wrong? Edit I wasn´t declaring my methods with double colons, it was just for denoting that it was a public method (interface). Updated to full class/methods declarations. Edit 2 I should have said that I´m testing some method implementations in an abstract class (edited the code to reflect this). Since I can not instantiate the class, how can I test this? I´m thinking in creating an SomeClassSimple extending SomeClassAbstract and testing this one instead. Is it the right approach?

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  • Fast CGI, Lighttpd, Ubuntu

    - by Gosh
    Is this log file familiar to someone of UBUNTU users? Lighttpd log file: > 2009-08-30 21:37:45: (log.c.75) server started > 2009-08-30 21:37:45: (mod_fastcgi.c.1029) the fastcgi-backend php5-cgi *failed* to start: > 2009-08-30 21:37:45: (mod_fastcgi.c.1033) *child exited with status 9 php5-cgi* > 2009-08-30 21:37:45: (mod_fastcgi.c.1036) If you're trying to run PHP as a FastCGI backend, make sure you're using the FastCGI-enabled version. > You can find out if it is the right one by executing 'php -v' and it should display '(cgi-fcgi)' in the output, NOT '(cgi)' NOR '(cli)'. > For more information, check http://trac.lighttpd.net/trac/wiki/Docs%3AModFastCGI#preparing-php-as-a-fastcgi-programIf this is PHP on Gentoo, add 'fastcgi' to the USE flags. > 2009-08-30 21:37:45: (mod_fastcgi.c.1340) [ERROR]: *spawning fcgi failed*. > 2009-08-30 21:37:45: (server.c.908) Configuration of plugins failed. Going down. Please open a secret how did you solved fcgi problem and made lighttpd to start, if you did. Thx, Gosh.

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  • How should I handle incomplete packet buffers?

    - by Benjamin Manns
    I am writing a client for a server that typically sends data as strings in 500 or less bytes. However, the data will occasionally exceed that, and a single set of data could contain 200,000 bytes, for all the client knows (on initialization or significant events). However, I would like to not have to have each client running with a 50 MB socket buffer (if it's even possible). Each set of data is delimited by a null \0 character. What kind of structure should I look at for storing partially sent data sets? For example, the server may send ABCDEFGHIJKLMNOPQRSTUV\0WXYZ\0123!\0. I would want to process ABCDEFGHIJKLMNOPQRSTUV, WXYZ, and 123! independently. Also, the server could send ABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890LOL123HAHATHISISREALLYLONG without the terminating character. I would want that data set stored somewhere for later appending and processing. Also, I'm using asynchronous socket methods (BeginSend, EndSend, BeginReceive, EndReceive) if that matters.

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  • Form submitted via dialog opens dialog again

    - by VikingGoat
    I have a form in a jquerymobile dialog box that I am submitting via jQuery Ajax. Currently my problem is that once the form is submitted the same dialog box is opened again on top of the original dialogbox. So that my url reads before submission: url/index.php#&ui-state=dialog and then after submission: url/index.php#&ui-state=dialog#&ui-state=dialog&ui-state=dialog Has anyone ever encountered something like this before? [edit added code example] $(function(){ $("#form").submit(function(e){ e.preventDefault(); var dataString = $("#form").serialize(); errorInput = $("input[name=valOne]#valOne").val(); $.ajax({ type: "GET", url: "formHandler.php", data: dataString, dataType: "text", success: function(data){ if(data.toLowerCase().indexOf("error") >= 0){ alert(data); $(".ui-dialog").dialog("close"); $("#valOne").val(errorInput); //the reentering info so user doesn't have to }else{ $(".ui-dialog").dialog("close"); location.href="index.php"; } }, error:function (xhr, ajaxOptions, thrownError){ alert(thrownError); } }); }); });

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  • C# Detect Localhost Port Usage

    - by ThaKidd
    In advance, thank you for your advice. I am currently working on a program which uses Putty to create a SSH connection with a server that uses local port forwarding to enable a client, running my software, to access the service behind the SSH server via localhost. IE: client:20100 - Internet - Remote SSH server exposed via router/firewall - Local Intranet - Intranet Web POP3 Server:110. Cmd Line: "putty -ssh -2 -P 22 -C -L 20100:intranteIP:110 -pw sshpassword sshusername@sshserver" Client would use putty to create a SSH connection with the SSH server specifying in the connection string that it would like to tie port 110 of the Intranet POP3 Server to port 20100 on the client system. Therefore the client would be able to open up a mail client to localhost:20100 and interact with the Internal POP3 server over the SSH tunnel. The above is a general description. I already know what I am trying to do will work without a problem so am not looking for debate on the above. The question is this...How can I ensure the local port (I cannot use dynamic ports, so it must be static) on localhost is not being used or listened to by any other application? I am currently executing this code in my C# app: private bool checkPort(int port) { try { //Create a socket on the current IPv4 address Socket TestSocket = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp); // Create an IP end point IPEndPoint localIP = new IPEndPoint(IPAddress.Parse("127.0.0.1"), port); // Bind that port TestSocket.Bind(localIP); // Cleanup TestSocket.Close(); return false; } catch (Exception e) { // Exception occurred. Port is already bound. return true; } } I am currently calling this function starting with a specific port in a for loop to get the 'false' return at the first available port. The first port I try is actually being listened to by uTorrent. The above code does not catch this and my connection fails. What is the best method to ensure a port is truly free? I do understand some other program may grab the port during/after I have tested it. I just need to find something that will ensure it is not currently in use AT ALL when the test is executed. If there is a way to truly reserve the localhost port during the test, I would love to hear about it.

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  • Google Maps inside custom PODS page

    - by Sharath
    I have a custom pods page called addstory.php which uses a public form to display some input fields. For one of the fields, i have a input helper that displays a google map location which I can use to pick out a location which is stored in comma separated variable. Here is the input helper code... <div class="form pick <?php echo $location; ?>"> <div id="map" style="width:500; height:500"> </div> <script type="text/javascript"> $(function() { map=new GMap(document.getElementById("map")); map.centerAndZoom(new GPoint(77.595062,13.043359),6); map.setUIToDefault(); GEvent.addListener(map,"click",function(overlay,latlng) { map.clearOverlays(); var marker = new GMarker(latlng); map.addOverlay(marker); //Extra stuff here.. } ); }); </script> </div> And this is the code inside my addstory.php <?php get_header(); $rw = new Pod('rainwater'); $fields=array( 'name', 'email', 'location'=>array('input_helper'=>'gmap_location'), ); echo $rw->publicForm($fields); ?> I get the following error...and the google map doesn't load. a is null error source line: [Break on this error] function Qd(a){for(var b;b=a.firstChild;){Rg(b);a.removeChild(b)}}

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  • Django + WebKit = Broken pipe

    - by Saosin
    I'm running the Django 1.2 development server and I get these Broken Pipe error messages whenever I load a page from it with Chrome or Safari. My co-worker is getting the error as well when he loads a page from his dev server. We don't have these errors when using Opera or Firefox. Traceback (most recent call last): File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/core/servers/basehttp.py", line 281, in run self.finish_response() File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/core/servers/basehttp.py", line 321, in finish_response self.write(data) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/core/servers/basehttp.py", line 417, in write self._write(data) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/socket.py", line 300, in write self.flush() File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/socket.py", line 286, in flush self._sock.sendall(buffer) error: [Errno 32] Broken pipe Can anyone help me out? I'm going crazy over this!

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  • Magic Methods in Python

    - by dArignac
    Howdy, I'm kind of new to Python and I wonder if there is a way to create something like the magic methods in PHP (http://www.php.net/manual/en/language.oop5.overloading.php#language.oop5.overloading.methods) My aim is to ease the access of child classes in my model. I basically have a parent class that has n child classes. These classes have three values, a language key, a translation key and a translation value. The are describing a kind of generic translation handling. The parent class can have translations for different translation key each in different languages. E.g. the key "title" can be translated into german and english and the key "description" too (and so far and so on) I don't want to get the child classes and filter by the set values (at least I want but not explicitly, the concrete implementation behind the magic method would do this). I want to call parent_class.title['de'] # or also possible maybe parent_class.title('de') for getting the translation of title in german (de). So there has to be a magic method that takes the name of the called method and their params (as in PHP). As far as I dug into Python this is only possible with simple attributes (_getattr_, _setattr_) or with setting/getting directly within the class (_getitem_, _setitem_) which both do not fit my needs. Maybe there is a solution for this? Please help! Thanks in advance!

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  • How could I send live video stream to remote server from my phone !!!

    - by poc
    Hello , I have a problem about streaming my video to server in real-time from my phone. that is , let my phone be a IP Camera , and server can watch the live video from my phone I have googled many many solutions, but there is no one can solve my problem. I use MediaRecorder to record . it can save video file in the SD card correctly. then , I refered this page and used some method as followings skt = new Socket(InetAddress.getByName(hostname),port); pfd =ParcelFileDescriptor.fromSocket(skt); mediaRecorder.setOutputFile(pfd.getFileDescriptor()); now it seems I can send the video stream while recording however, I wrote a receiver-side program to receive the video stream from Android , but it doesn't work . is there any error? I can receive file , but I can not open the video file . I guess the problem may caused by file format ? there are outline of my code. in android side Socket skt = new Socket(hostIP,port); ParcelFileDescriptor pfd =ParcelFileDescriptor.fromSocket(skt); .... .... mediaRecorder.setAudioSource(MediaRecorder.AudioSource.MIC); mediaRecorder.setVideoSource(MediaRecorder.VideoSource.DEFAULT); mediaRecorder.setOutputFormat(MediaRecorder.OutputFormat.MPEG_4); mediaRecorder.setOutputFile(pfd.getFileDescriptor()); ..... mediaRecorder.setAudioEncoder(MediaRecorder.AudioEncoder.DEFAULT); mediaRecorder.setVideoEncoder(MediaRecorder.VideoEncoder.MPEG_4_SP); ..... mediaRecorder.start(); in receiver side (my ACER notebook) // anyway , I don't think the file extentions will do any effect File video = new File (strDate+".3gpp"); FileOutputStream fos; try { fos = new FileOutputStream(video); byte[] data = new byte[1024]; int count =-1; while( (count = fin.read(data,0,1024) ) !=-1) { fos.write(data,0,count); fos.flush(); } fos.close(); fin.close(); I confused a long time.... thanks in advance

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