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  • DataGridView live display of datatable using virtual mode

    - by Chris
    I have a DataGridView that will display records (log entries) from a database. The amount of records that can exist at a time is very large. I would like to use the virtual mode feature of the DataGridView to display a page of data, and to minimize the amount of data that has to be transferred across a network at a given time. Polling for data is out of the question. There will be several clients running at a time, all of which are on the same network and viewing the records. If they all poll for data, the network will run very slowly. The data is read-only to the user; they won't be able to edit any of it, just view it. I need to know when updates occur in the database, and I need to update the screen with those updates accordingly using virtual mode. If a page of data a user is viewing contains data that has change, he/she will see those updates on that page. If updates were made to data in the database, but not in the data the user is viewing, then not much really changes on the user screen (Maybe just the scroll bar if records were added or removed). My current approach is using SQL server change tracking with the sync framework. Each client has a local SQL Server CE instance and database file that is kept in sync with the main database server. I use the information from the synchronization event to see if any changes were made to the main database and were sync'ed to the client. I need to use the DataGridView virtual mode here because I can't have thousands of records loaded into the DataGridView at once, otherwise memory usage goes through the roof. The main challenge right now is knowing how to use virtual mode to provide a seamless experience to the user by allowing them to scroll up and down through the records, and also have records update on the fly without interfering with the user inappropriately. Has anybody dealt with this issue before, and if so, where I can see how they did it? I've gone through some of the MSDN documentation and examples on virtual mode. So far, I haven't found documentation and/or examples on their site that explains how to do what I am trying to accomplish.

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  • Why can't I call this function (javascript/jquery)

    - by Ankur
    This is driving me nuts .... I have written a function function seraliseQuery(){ for(var i=1; i<=variables;i++){ alert(queryPreds[i]+" - "+queryObjs[i]); } } I just want to be able to call it from my other function $(".object").click( function() { // code removed seraliseQuery(); }); The error I get is "the function serialiseQuery() is undefined". Everything is within $(document).ready( function() { // code goes here }

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  • how to call javascript from php

    - by Jayjitraj
    HI I want to execute one script within my php and that javascript will give me output as HTML and i want to display that output but i want to do this all within PHP so please tell me which function should i use Thanks in advance :)

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  • Ubuntu's file-roller problem 5010. "Cannot open display"

    - by Denis
    Hello everybody! I use "file-roller" to manage with archieves on my Ubuntu. But it fails on running without user interface(just teminal). The error is shown below. ** (file-roller:5453): CRITICAL **: Failed to parse arguments: Cannot open display: How can I prevent file-roller from using GUI or can you recommend me any other archieve manager I can use from terminal. It would be perfect, if this manager can handle as much formats as it is possible.

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  • Call RecognizerIntent from service

    - by Tobia Loschiavo
    Hi, I am working on an Android service. I need to call RecognizerIntent from a service in order to use in the service the recognized text. I have no startActivityForResult() method in Service class so I have problem understanding how to achieve this task. Is it possible? Many thanks

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  • call a jython file from another program

    - by kdev
    Hi everyone, can i call a jython file from another jython program and execute that . Also i know os.system(cmd.exe)get the system prompt . is it possible that i can trigger cmd.exe and cmd.exe gets poped up into the screen. Thanks

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  • Java return to position N in call stack.

    - by Finbarr
    Using the return keyword in Java code will return execution to the last piece of calling code in the call stack. If object foo calls baz.bar(), the return keyword in the bar method will continue code execution in foo. Let's say I have object foo that calls foofoo that calls foofoofoo in the above scenario, and foofoofoo calls baz.bar(). Is there anyway in Java to use the return keyword, or something else, so that the code in the bar method can return all the way back up to foo? (WITHOUT THROWING AN EXCEPTION)

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  • Display url in text box

    - by xrx215
    I have a textbox as follows: <asp:TextBox runat="server" ID="txtOtherApps" Height="400" Width="400" TextMode="MultiLine" ontextchanged="txtOtherApps_TextChanged" ></asp:TextBox> How to display link in this textbox?

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  • drawRect:rect how to call this method , I am using to draw a string

    - by user338322
    -(void)drawRect:(CGRect)rect { CGContextRef context = UIGraphicsGetCurrentContext(); CGContextSelectFont(context, "Arial", 24, kCGEncodingFontSpecific); CGContextSetTextPosition(context,80,80); CGContextShowText(context, "hello", 6); //not even this works CGContextShowTextAtPoint(context, 1,1, "hello", 6); } I want to kn ow how to call above method, i have paste above code in the implemntation file simply, but dont know why its not called when i execute the project, can some one

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  • Maximum number of records jquery grid can display?

    - by kumar
    can any body help me out this problem, I have jquery grid, i am trying to display 20k records or users on the grid? what i am doing is first using stored procrdure i am getting all 20k records, initially each page 100 records i am shoiwng in the jquery grid... on the top of the jquery grid i have GetAll button,,, if i click this button i need to see all 20k records on the grid in a single page.. is there any way we can handle this? thanks

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  • Unlock device, display a text, then lock again

    - by Waza_Be
    For the need of my application, I need to display a message on the screen even if the lockscreen is enabled, then wait 3 seconds, than I have to lock again the phone as I don't want it to make unwanted phone calls in your pockets. First part is easy: if (PreferenceManager.getDefaultSharedPreferences( getBaseContext()).getBoolean("wake", false)) { KeyguardManager kgm = (KeyguardManager) getSystemService(Context.KEYGUARD_SERVICE); boolean isKeyguardUp = kgm.inKeyguardRestrictedInputMode(); WakeLocker.acquire(ProtoBenService.this); Intent myIntent = new Intent(ProtoBenService.this,LockActivity.class); myIntent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK); if (isKeyguardUp) { ProtoBenService.this.startActivity(myIntent); } else Toast.makeText(ProtoBenService.this.getBaseContext(), intention, Toast.LENGTH_LONG).show(); WakeLocker.release(); } With this class: public abstract class WakeLocker { private static PowerManager.WakeLock wakeLock; public static void acquire(Context ctx) { if (wakeLock != null) wakeLock.release(); PowerManager pm = (PowerManager) ctx.getSystemService(Context.POWER_SERVICE); wakeLock = pm.newWakeLock(PowerManager.FULL_WAKE_LOCK | PowerManager.ACQUIRE_CAUSES_WAKEUP | PowerManager.ON_AFTER_RELEASE, "CobeIm"); wakeLock.acquire(); } public static void release() { if (wakeLock != null) wakeLock.release(); wakeLock = null; } } And the Activity: public class LockActivity extends Activity { @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); Window window = getWindow(); window.addFlags(WindowManager.LayoutParams.FLAG_DISMISS_KEYGUARD); window.addFlags(WindowManager.LayoutParams.FLAG_TURN_SCREEN_ON); window.addFlags(WindowManager.LayoutParams.FLAG_KEEP_SCREEN_ON); TextView tv = new TextView(this); tv.setText("This is working!"); tv.setTextSize(45); setContentView(tv); Runnable mRunnable; Handler mHandler = new Handler(); mRunnable = new Runnable() { @Override public void run() { LockActivity.this.finish(); } }; mHandler.postDelayed(mRunnable, 3 * 1000); } } So, this is nice, the phone can display my text! The only problem comes when I want to lock again the phone, it seems that locking the phone is protected by the system... Programmatically turning off the screen and locking the phone how to lock the android programatically I think that my users won't understand the Device Admin and won't be able to activate it. Is there any workaround to lock the screen without the Device Admin stuff?

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  • VB6 - View Code will not display code

    - by zSysop
    Hi all, This is probably a really dumb question but i'll ask anyway. I was wondering if there was any reason as to why a form wouldn't display its code when i click "view code" from the right click context menu in vb6? It was working awhile ago so i'm kind of stumped. Thanks

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  • CrystalReportViewer does not display Charts

    - by suzi167
    Hi, My CrystalReportViewer won't display the charts in my Crystal Report. I get a red X. I am using C# and MVC. I've read somewehre that I might need a virtual path to the image folder but I am not really sure what that means as my chart is embedded in the report....Maybe I am missing something. Plz can anyone elaborate. Thanks Susan

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  • Making a WCF call with AJAX

    - by DotnetDude
    Is it required to use a RESTful service to be able to make a ajax call to a wcf service (for example: by using WebInvoke attribute on Operation contracts) Once a service is made RESTful by adding a webHttp binding on the service host, can the host have other endpoints as well? (wsHttp or netTcp) Is it required that the aspNetCompatibilityEnabled be set to true for a service that has webHttp binding (and can this setting coexist for other endpoints) I understand I can use both JQuery and ScriptManager for making WCF calls on the client. Why should I use one over the other?

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  • django display m2m elements in a template

    - by dana
    if a have a declaration like theclass = Classroom.objects.get(classname = classname) members = theclass.members.all() and i want to display all the members(of a class) in a template, how should i do it?? if i write: {{theclass.members.all}} the output is an empty list(though the class has some members) How should the elements of a m2m table be displayed in a template? thanks!

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