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  • is there a default back key(on device) listener in android???

    - by androidbase Praveen
    hi all, i am having two activities A and B. when i click the button in A that will shows B. when i click the Button in B it backs to A. i had set the overridePendingTransition method after the finish() method. it works properly. but in case the current Activity is B. on that time i click the default back button in the device. it shows the right to left transition to show the Activity A. how i can listen that Default back key on device.?????

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  • Delphi: How to set the default project in a project group?

    - by Ian Boyd
    i have two projects in a project group: ProjectA ProjectB Whenever i open the ProjectGroup.bpg in Delphi, it always starts with the 2nd project as the active one: ProjectA ProjectB And every time i have to flip it to the the "real" project: ProjectA ProjectB How can i make ProjectA the default project that opens with the project group? ProjectGroup.bpg #------------------------------------------------------------------------------ VERSION = BWS.01 #------------------------------------------------------------------------------ !ifndef ROOT ROOT = $(MAKEDIR)\.. !endif #------------------------------------------------------------------------------ MAKE = $(ROOT)\bin\make.exe -$(MAKEFLAGS) -f$** DCC = $(ROOT)\bin\dcc32.exe $** BRCC = $(ROOT)\bin\brcc32.exe $** #------------------------------------------------------------------------------ PROJECTS = ProjectA.exe ProjectB.exe #------------------------------------------------------------------------------ default: $(PROJECTS) #------------------------------------------------------------------------------ ProjectA.exe: ProjectA.dpr $(DCC) ProjectB.exe: childfolder\ProjectB.dpr $(DCC)

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  • Is there a way to specify a default property value in Spring XML?

    - by Rog
    We are using a PropertyPlaceholderConfigurer to use java properties in our Spring configuration (details here) eg: <foo name="port"> <value>${my.server.port}</value> </foo> We would like to add an additional property, but have a distributed system where existing instances could all use a default value. Is there a way to avoid updating all of our properties files, by indicating a default value in the Spring config for when there isn't an overriding property value defined?

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  • How Can I Populate Default Form Data with a ManyToMany Field?

    - by b14ck
    Ok, I've been crawling google and Django documentation for over 2 hours now (as well as the IRC channel on freenode), and haven't been able to figure this one out. Basically, I have a model called Room, which is displayed below: class Room(models.Model): """ A `Partyline` room. Rooms on the `Partyline`s are like mini-chatrooms. Each room has a variable amount of `Caller`s, and usually a moderator of some sort. Each `Partyline` has many rooms, and it is common for `Caller`s to join multiple rooms over the duration of their call. """ LIVE = 0 PRIVATE = 1 ONE_ON_ONE = 2 UNCENSORED = 3 BULLETIN_BOARD = 4 CHILL = 5 PHONE_BOOTH = 6 TYPE_CHOICES = ( ('LR', 'Live Room'), ('PR', 'Private Room'), ('UR', 'Uncensored Room'), ) type = models.CharField('Room Type', max_length=2, choices=TYPE_CHOICES) number = models.IntegerField('Room Number') partyline = models.ForeignKey(Partyline) owner = models.ForeignKey(User, blank=True, null=True) bans = models.ManyToManyField(Caller, blank=True, null=True) def __unicode__(self): return "%s - %s %d" % (self.partyline.name, self.type, self.number) I've also got a forms.py which has the following ModelForm to represent my Room model: from django.forms import ModelForm from partyline_portal.rooms.models import Room class RoomForm(ModelForm): class Meta: model = Room I'm creating a view which allows administrators to edit a given Room object. Here's my view (so far): def edit_room(request, id=None): """ Edit various attributes of a specific `Room`. Room owners do not have access to this page. They cannot edit the attributes of the `Room`(s) that they control. """ room = get_object_or_404(Room, id=id) if not room.is_owner(request.user): return HttpResponseForbidden('Forbidden.') if is_user_type(request.user, ['admin']): form_type = RoomForm elif is_user_type(request.user, ['lm']): form_type = LineManagerEditRoomForm elif is_user_type(request.user, ['lo']): form_type = LineOwnerEditRoomForm if request.method == 'POST': form = form_type(request.POST, instance=room) if form.is_valid(): if 'owner' in form.cleaned_data: room.owner = form.cleaned_data['owner'] room.save() else: defaults = {'type': room.type, 'number': room.number, 'partyline': room.partyline.id} if room.owner: defaults['owner'] = room.owner.id if room.bans: defaults['bans'] = room.bans.all() ### this does not work properly! form = form_type(defaults, instance=room) variables = RequestContext(request, {'form': form, 'room': room}) return render_to_response('portal/rooms/edit.html', variables) Now, this view works fine when I view the page. It shows all of the form attributes, and all of the default values are filled in (when users do a GET)... EXCEPT for the default values for the ManyToMany field 'bans'. Basically, if an admins clicks on a Room object to edit, the page they go to will show all of the Rooms default values except for the 'bans'. No matter what I do, I can't find a way to get Django to display the currently 'banned users' for the Room object. Here is the line of code that needs to be changed (from the view): defaults = {'type': room.type, 'number': room.number, 'partyline': room.partyline.id} if room.owner: defaults['owner'] = room.owner.id if room.bans: defaults['bans'] = room.bans.all() ### this does not work properly! There must be some other syntax I have to use to specify the default value for the 'bans' field. I've really been pulling my hair out on this one, and would definitely appreciate some help. Thanks!

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  • How to display default text "--Select Team --" in combo box on pageload in WPF?

    - by Aditya
    Hi, In a WPF app, in MVP app I have a combo box,for which I display the data fetched from Database. Before the items added to the Combo box, I want to display the default text such as " -- Select Team --" , so that on pageload it displays and on selecting it the text should be cleared and the items should be displayed. Selecting data from DB is happening. I need to display the default text until the user selects an item from combo box. Please guide me Thanks Ramm

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  • Scala: is it possible to override default case class constructor?

    - by adam77
    Just wondering if this is possible. What I would actually like to do is check and possibly modify one of the arguments before it is stored as a val. Alternatively, I could use an overload and make the default constructor private. In which case I would also like to make private the default factory constructor in the companion object, how would I do that? Many thanks. Adam

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  • How do I write JPA QL statements that hints to the runtime to use the DEFAULT value ?

    - by Jacques René Mesrine
    I have a table like so: mysql> show create table foo; CREATE TABLE foo ( network bigint NOT NULL, activeDate datetime NULL default '0000-00-00 00:00:00', ... ) In the domain object, FooVO the activeDate member is annotated as Temporal. If I don't set activeDate to a valid Date instance, a new record is inserted with NULLs. I want the default value to take effect if I don't set the activeDate member. Thanks.

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  • VWD 2008 Express : where can i set absolute positioning as a default?

    - by Justin
    So when I used Visual Web Developer 2005 Express edition, in the ribbon there was a menu option for "Layout", which you could go through and select positioning and set absolute to default. I am using Visual Web Developer 2008 Express now, and I see that you can select format from the menu bar, and set position absolute, for each individual control that you add to the design surface, but is there a place I can just set absolute as the default, like in 2005? Thanks, Justin

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  • [CakePHP] I am so confused. What should I write in the default.ctp

    - by kwokwai
    Hi all, I am learning cakePHP, everything seems alright except that I am very confused of how to make use of the default.ctp and what should be put inside the Elements folder. Here is the default.ctp file that I have been using since my very first lesson on learning cakePHP: (I copied from this URL http://book.cakephp.org/view/96/Layouts) <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title><?php echo $title_for_layout?></title> <link rel="shortcut icon" href="favicon.ico" type="image/x-icon"> <!-- Include external files and scripts here (See HTML helper for more info.) --> <?php echo $scripts_for_layout ?> </head> <body> <!-- If you'd like some sort of menu to show up on all of your views, include it here --> <div id="header"> <div id="menu">...</div> </div> <!-- Here's where I want my views to be displayed --> <?php echo $content_for_layout ?> <!-- Add a footer to each displayed page --> <div id="footer">...</div> </body> </html> But the problem is that the layout will take effect to all web pages that I have created. Let's see the case that I have recently encountered. In one of the .ctp files, I need to use JQuery function and I need to ass some and tags in the .ctp file. Here are the and tags I used: <Script language="javascript"> $(document).ready(function() { // some functions here }); </Script> <style type="text/css"> { #toppage{ width:800px; } But when I followed the default.ctp file, I noticed that these tags (i.e. and ) happened to appear below the tag. As far as I know, the and self-defined Javascript functions should be put inside the tag of the HTML instead. I have considered to add the and in the default.ctp file, but then these codes would appear in every web pages instead of just a particular web page. Please help.

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  • gnu screen - changing the default escape command key to ALT-X?

    - by Siva
    In GNU screen, I want to change the default command binding to Alt-s (by tweaking .screenrc) instead of the default C-a, the reason is I use emacs hence GNU screen binds the C-a key, sending "C-a" to the emacs becomes tedious (as @Nils said, to send "C-a" I should type "C-a a"), as well as "C-a" in bash shell, and I could change the escape to C- but some of them are already mapped in emacs and other combinations are not as easy as ALT-s . If anyone has already done a ALT key mapping, please do let me know.

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  • How to write UIWebView with default request address is like (192.168.1.1)..

    - by user323503
    i have implemented UIWebView in my application but i default address is "192.168.1.1" but it is not open default it and i have tried with "http://www.google.com" it is working fine. [iview loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:@"192.168.1.1"]]]; it doesn't working and it is working with [iview loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:@"http://www.google.com"]]];

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  • How can I automatically refactor my classes to use the default namespace for the folder they're in?

    - by Daniel Schaffer
    I've been playing around with the structure of my project, and I'd like to reset the namespaces of my classes to what the default would be. That is, the default namespace for the project, plus each of the folders in the hierarchy. It's not as simple as just find + replace, since I've both added and renamed some folders, and files from some namespaces were split into multiple other namespaces. I'm using VS 2010.

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  • Can't log in via SSH to any accounts set to use /bin/bash as a default shell

    - by Gui Ambros
    I'm trying to install bash as the default shell on a ARM Linux running on an embedded device (Synology DS212+ NAS). But there's something really wrong, and I can't figure out what it is. Symptoms: 1) Root has /bin/bash as default shell, and can log in normally via SSH: $ grep root /etc/passwd root:x:0:0:root:/root:/bin/bash $ ssh root@NAS root@NAS's password: Last login: Sun Dec 16 14:06:56 2012 from desktop # 2) joeuser has /bin/bash as default shell, and receives "Permission denied" when trying to log in via SSH: $ grep joeuser /etc/passwd joeuser:x:1029:100:Joe User:/home/joeuser:/bin/bash $ ssh joeuser@localhost joeuser@NAS's password: Last login: Sun Dec 16 14:07:22 2012 from desktop Permission denied, please try again. Connection to localhost closed. 3) changing joeuser's shell back to /bin/sh: $ grep joeuser /etc/passwd joeuser:x:1029:100:Joe User:/home/joeuser:/bin/sh $ ssh joeuser@localhost Last login: Sun Dec 16 15:50:52 2012 from localhost $ To make things even more strange, I can log in as joeuser using /bin/bash using the serial console (!). Also a su - joeuser as root works fine, so the bash binary itself is working fine. In an act of despair, I changed joeuser's uid to 0 on /etc/passwd, but also didn't work, so it doesn't seem to be anything permission related. Seems that bash is doing some extra checking that sshd didn't like, and blocking the connections for non-root users. Maybe some sort of sanity checking - or terminal emulation - that is triggering the SIGCHLD, but only when called via ssh. I already went through every single item on sshd_config, and also put SSHD in debug mode, but didn't find anything strange. Here's my /etc/ssh/sshd_config: LogLevel DEBUG LoginGraceTime 2m PermitRootLogin yes RSAAuthentication yes PubkeyAuthentication yes AuthorizedKeysFile %h/.ssh/authorized_keys ChallengeResponseAuthentication no UsePAM yes AllowTcpForwarding no ChrootDirectory none Subsystem sftp internal-sftp -f DAEMON -u 000 And here's the output from /usr/syno/sbin/sshd -d, showing the failed attempt of joeuser trying to log in, with /bin/bash as the shell: debug1: Config token is loglevel debug1: Config token is logingracetime debug1: Config token is permitrootlogin debug1: Config token is rsaauthentication debug1: Config token is pubkeyauthentication debug1: Config token is authorizedkeysfile debug1: Config token is challengeresponseauthentication debug1: Config token is usepam debug1: Config token is allowtcpforwarding debug1: Config token is chrootdirectory debug1: Config token is subsystem debug1: HPN Buffer Size: 87380 debug1: sshd version OpenSSH_5.8p1-hpn13v11 debug1: read PEM private key done: type RSA debug1: private host key: #0 type 1 RSA debug1: read PEM private key done: type DSA debug1: private host key: #1 type 2 DSA debug1: read PEM private key done: type ECDSA debug1: private host key: #2 type 3 ECDSA debug1: rexec_argv[0]='/usr/syno/sbin/sshd' debug1: rexec_argv[1]='-d' Set /proc/self/oom_adj from 0 to -17 debug1: Bind to port 22 on ::. debug1: Server TCP RWIN socket size: 87380 debug1: HPN Buffer Size: 87380 Server listening on :: port 22. debug1: Bind to port 22 on 0.0.0.0. debug1: Server TCP RWIN socket size: 87380 debug1: HPN Buffer Size: 87380 Server listening on 0.0.0.0 port 22. debug1: Server will not fork when running in debugging mode. debug1: rexec start in 6 out 6 newsock 6 pipe -1 sock 9 debug1: inetd sockets after dupping: 4, 4 Connection from 127.0.0.1 port 52212 debug1: HPN Disabled: 0, HPN Buffer Size: 87380 debug1: Client protocol version 2.0; client software version OpenSSH_5.8p1-hpn13v11 SSH: Server;Ltype: Version;Remote: 127.0.0.1-52212;Protocol: 2.0;Client: OpenSSH_5.8p1-hpn13v11 debug1: match: OpenSSH_5.8p1-hpn13v11 pat OpenSSH* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.8p1-hpn13v11 debug1: permanently_set_uid: 1024/100 debug1: MYFLAG IS 1 debug1: list_hostkey_types: ssh-rsa,ssh-dss,ecdsa-sha2-nistp256 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: AUTH STATE IS 0 debug1: REQUESTED ENC.NAME is 'aes128-ctr' debug1: kex: client->server aes128-ctr hmac-md5 none SSH: Server;Ltype: Kex;Remote: 127.0.0.1-52212;Enc: aes128-ctr;MAC: hmac-md5;Comp: none debug1: REQUESTED ENC.NAME is 'aes128-ctr' debug1: kex: server->client aes128-ctr hmac-md5 none debug1: expecting SSH2_MSG_KEX_ECDH_INIT debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: KEX done debug1: userauth-request for user joeuser service ssh-connection method none SSH: Server;Ltype: Authname;Remote: 127.0.0.1-52212;Name: joeuser debug1: attempt 0 failures 0 debug1: Config token is loglevel debug1: Config token is logingracetime debug1: Config token is permitrootlogin debug1: Config token is rsaauthentication debug1: Config token is pubkeyauthentication debug1: Config token is authorizedkeysfile debug1: Config token is challengeresponseauthentication debug1: Config token is usepam debug1: Config token is allowtcpforwarding debug1: Config token is chrootdirectory debug1: Config token is subsystem debug1: PAM: initializing for "joeuser" debug1: PAM: setting PAM_RHOST to "localhost" debug1: PAM: setting PAM_TTY to "ssh" debug1: userauth-request for user joeuser service ssh-connection method password debug1: attempt 1 failures 0 debug1: do_pam_account: called Accepted password for joeuser from 127.0.0.1 port 52212 ssh2 debug1: monitor_child_preauth: joeuser has been authenticated by privileged process debug1: PAM: establishing credentials User child is on pid 9129 debug1: Entering interactive session for SSH2. debug1: server_init_dispatch_20 debug1: server_input_channel_open: ctype session rchan 0 win 65536 max 16384 debug1: input_session_request debug1: channel 0: new [server-session] debug1: session_new: session 0 debug1: session_open: channel 0 debug1: session_open: session 0: link with channel 0 debug1: server_input_channel_open: confirm session debug1: server_input_global_request: rtype [email protected] want_reply 0 debug1: server_input_channel_req: channel 0 request pty-req reply 1 debug1: session_by_channel: session 0 channel 0 debug1: session_input_channel_req: session 0 req pty-req debug1: Allocating pty. debug1: session_new: session 0 debug1: session_pty_req: session 0 alloc /dev/pts/1 debug1: server_input_channel_req: channel 0 request shell reply 1 debug1: session_by_channel: session 0 channel 0 debug1: session_input_channel_req: session 0 req shell debug1: Setting controlling tty using TIOCSCTTY. debug1: Received SIGCHLD. debug1: session_by_pid: pid 9130 debug1: session_exit_message: session 0 channel 0 pid 9130 debug1: session_exit_message: release channel 0 debug1: session_by_tty: session 0 tty /dev/pts/1 debug1: session_pty_cleanup: session 0 release /dev/pts/1 Received disconnect from 127.0.0.1: 11: disconnected by user debug1: do_cleanup debug1: do_cleanup debug1: PAM: cleanup debug1: PAM: closing session debug1: PAM: deleting credentials Here you have the full output of sshd -dd, together with ssh -vv. Bash: # bash --version GNU bash, version 3.2.49(1)-release (arm-none-linux-gnueabi) Copyright (C) 2007 Free Software Foundation, Inc. The bash binary was cross compiled from source. I also tried using a pre-compiled binary from the Optware distribution, but had the exact same problem. I checked for missing shared libraries using objdump -x, but they're all there. Any ideas what could be causing this "Permission denied, please try again."? I'm almost diving in the bash source code to investigate, but trying to avoid hours chasing something that may be silly.

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  • How can I make this Route (ASP.Net MVC2) ?

    - by Felipe
    Hi All, I'm begginer in asp.net mvc and I have some doutbs about routes. Im' developing a system to manage documents and I need make an URL like this: routes.MapRoute("Documentos", "{controller}/{documentType}/{documento}/{action}/{id}", new { controller = "Home", documentType = "", documento = "", action = "Index", id = UrlParameter.Optional }); and the app working an URL like theses: "Document/Administrative/Contract" - (Index action by default to list documents of type 'Contract') "Document/Administrative/Contract/New" - (new action in controller) "Document/Administrative/Contract/10" - (detail action in controller) "Document/Administrative/Contract/Edit/10" - (edit action in controller) Document would be a Controller, and Administrative would be just a description in url to identify that documents of 'Contract' is Administrative... So, My doubts is about my controllers and actions, How should be the signature of the methods of controller ? Need I make an Area called Documents to do this more easy ? PS: Sorry for my english! Thanks a lot, Cheers! Felipe

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  • Zend Framework subdomain+subfolder router rewrite problem

    - by zf_novice
    I'm new to Zend Framwork and this is an issue I've been struggling for several hours already... I'm trying to chain Hostname and standard Route in order to get url with subdomain+subfolders ie.: http:// lang.mydomain.com/myapplication/public/controller http:// lang.mydomain.com/myapplication/public/controller/action (sorry for the empty space in the address, this site won't allow links) Basically what I have done in Bootstrap is: // add language to default route $routePath = new Zend_Controller_Router_Route( ':controller/:action/*', array('controller'=>'index','action' => 'index','module'=>'default') ); $routeHostname = new Zend_Controller_Router_Route_Hostname( ':lang.mydomain.com', array('lang'=>$lang) ); $frontController = $this->getResource('FrontController'); $router = $frontController->getRouter(); $router->addRoute('default', $routeHostname->chain($routePath)) $frontController->setRouter($router); it finds the route ok, but every time I generate url in view or layout by $this-url() <?php echo $this->url( array( 'controller'=> 'guestbook', 'action' => 'sign', 'lang' => Zend_Registry::get('lang'), ), 'default', true) ?>"> I get http:// lang.mydomain.com/controller instead of http:// lang.mydomain.com/myapplication/public/controller I've been trying to set baseUrl on front controller but no luck... Also I've tried the static route with myapplication/public or following standard route: 'myapplication/public/:controller/:action/*' - it result with "An error occurred Page not found Exception information: Message: No route matched the request" and empty request Is there any way to assembly subdomain with subfolder in Zend Framwork?? EDIT: I changed above to: $frontController->setBaseUrl('.'); // add language to default route $routePath = new Zend_Controller_Router_Route( 'quickstart/public/:controller/:action/*', array( 'controller'=>'index', 'action' => 'index', 'module'=>'default', ) ); and it works form me, although I'm not sure whether it's been correct approach...

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