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  • how to dispose a incoming email and then send some words back using googe-app-engine..

    - by zjm1126
    from google.appengine.api import mail i read the doc: mail.send_mail(sender="[email protected]", to="Albert Johnson <[email protected]>", subject="Your account has been approved", body=""" Dear Albert: Your example.com account has been approved. You can now visit http://www.example.com/ and sign in using your Google Account to access new features. Please let us know if you have any questions. The example.com Team """) and i know hwo to send a email using gae ,but how to check a email incoming, and then do something thanks

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  • Serve static media on "nginx"

    - by MMRUSer
    My django application hosted on Apache, and now I want to serve its static media through nginx, I don't have any prior experience in nginx...plus currently the static media is serve through Apache.. expecting some helping hand. Apache 2.2 mod_wsgi nignx-0.7.65 Django 1.1.1 Thanks..

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  • Django form linking 2 models by many to many field.

    - by Ed
    I have two models: class Actor(models.Model): name = models.CharField(max_length=30, unique = True) event = models.ManyToManyField(Event, blank=True, null=True) class Event(models.Model): name = models.CharField(max_length=30, unique = True) long_description = models.TextField(blank=True, null=True) I want to create a form that allows me to identify the link between the two models when I add a new entry. This works: class ActorForm(forms.ModelForm): class Meta: model = Actor The form includes both name and event, allowing me to create a new Actor and simultaneous link it to an existing Event. On the flipside, class EventForm(forms.ModelForm): class Meta: model = Event This form does not include an actor association. So I am only able to create a new Event. I can't simultaneously link it to an existing Actor. I tried to create an inline formset: EventFormSet = forms.models.inlineformset_factory(Event, Actor, can_delete = False, extra = 2, form = ActorForm) but I get an error <'class ctg.dtb.models.Actor'> has no ForeignKey to <'class ctg.dtb.models.Event'> This isn't too surprising. The inlineformset worked for another set of models I had, but this is a different example. I think I'm going about it entirely wrong. Overall question: How can I create a form that allows me to create a new Event and link it to an existing Actor?

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  • is there a way to generate pdf containing non-ascii symbols with pisa from django template?

    - by mihailt
    Hi. i'm trying to generate a pdf from template using this snippet: def write_pdf(template_src, context_dict): template = get_template(template_src) context = Context(context_dict) html = template.render(context) result = StringIO.StringIO() pdf = pisa.pisaDocument(StringIO.StringIO(html.encode("UTF-8")), result) if not pdf.err: return http.HttpResponse(result.getvalue(), mimetype='application/pdf') except Exception('PDF error') but all non-latin symbols are not showing correctly, the template and view are saved using utf-8 encoding. i've tried saving view as ANSI and then to user unicode(html,"UTF-8"), but it throws TypeError. Also i thought that maybe it's because the default fonts somehow do not support utf-8 so according to pisa documentation i tried to set fontface in template body in style section. that still gave no results. Does any one have some ideas how to solve this issue?

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  • How do you set the initial value for a ManyToMany field in django?

    - by mlissner
    I am using a ModelForm to create a form, and I have gotten the initial values set for every field in the form except for the one that is a ManyToMany field. I understand that I need to give it a list, but I can't get it to work. My code right now is roughly: contacts = userProfile.contact.all() initial = {'contacts': contacts} But that doesn't work. Am I missing something here?

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  • Django date filter: how come the format used is different from the one in datetime library ???

    - by Sébastien Piquemal
    Hello ! For formatting a date using date filter you must use the following format : {{ my_date|date:"Y-m-d" }} If you use strftime from the standard datetime, you have to use the following : my_date.strftime("%Y-%m-%d") So my question is ... isn't it ugly (I guess it is because of the % that is used also for tags, and therefore is escaped or something) ? But that's not the main question ... I would like to use the same DATE_FORMAT parametrized in settings.py all over the project, but it therefore seems that I cannot ! Is there a work around (for example a filter that removes the % after the date has been formatted like {{ my_date|date|dream_filter }}, because if I just use DATE_FORMAT = "%Y-%m-%d" I got something like %2001-%6-%12)?

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  • How can I use Django with MySQL in MAMP stack?

    - by Robert A Henru
    Hi all, I have difficulty especially in installing MySQLdb module (MySQL-python-1.2.3c1), to connect to the MySQL in MAMP stack. I've done a number of things such as copying the mysql include directory and library (including plugin) from a fresh installation of mysql (version 5.1.47) to the one inside MAMP (version 5.1.37). Now, the MySQLdb module build and install doesnt give me error. The error happens when I'm calling 'import MySQLdb' from python shell (version 2.6). Traceback (most recent call last): File "<stdin>", line 1, in <module> File "build/bdist.macosx-10.6-universal/egg/MySQLdb/__init__.py", line 19, in <module> File "build/bdist.macosx-10.6-universal/egg/_mysql.py", line 7, in <module> File "build/bdist.macosx-10.6-universal/egg/_mysql.py", line 6, in __bootstrap__ ImportError: dlopen(/Users/rhenru/.python-eggs/MySQL_python-1.2.3c1-py2.6-macosx-10.6-universal.egg-tmp/_mysql.so, 2): Symbol not found: _mysql_affected_rows Referenced from: /Users/rhenru/.python-eggs/MySQL_python-1.2.3c1-py2.6-macosx-10.6-universal.egg-tmp/_mysql.so Expected in: flat namespace in /Users/rhenru/.python-eggs/MySQL_python-1.2.3c1-py2.6-macosx-10.6-universal.egg-tmp/_mysql.so Any idea, what else do I need to do to make it works? Thanks a bunch, Robert

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  • I can't load the css files

    - by mfalcon
    I want to load some .css files to my Django project but I don't know why they aren't loaded. The css files are located at "/myproject/media/css". settings.py: import os.path PROJECT_DIR = os.path.dirname(__file__) MEDIA_ROOT = os.path.join(PROJECT_DIR, 'media') urls.py: from django.conf import settings ... (r'^media/(?P<path>.*)$', 'django.views.static.serve', {'document_root': settings.MEDIA_ROOT, 'show_indexes': True}), ) base.html: <link rel="stylesheet" type="text/css" media="all" href="{{ MEDIA_ROOT }}css/myStyle.css" />

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  • Wrong sessionID being used in callback, but only on one particular computer

    - by user210119
    I am writing a Python/Django web application that uses OAuth (for the TwitterAPI, not that it should matter). I am storing a session ID in my login function, and then after using OAuth to get the user's token, I try to retrieve the sessionID in my callback function. The callback function then always fails(throws an exception) because it can't find the OAuth token in the session. Through the debugger, I am able to determine that the session ID that the server is using is incorrect - it does not match the session ID that was stored in the login function. It's therefore unsurprising that the Oauth tokens were not there. The session that appears in the callback was the same one each time (until I tried deleting it - see "things I've tried below"), and it started out as an old session, with some data in it that is from a different django app running on the same server that I hadn't touched in a couple weeks. Here's the kicker: everything I described is an issue only on our production server, and only when connecting to it from my computer. Let me clarify: this only happens with my particular laptop. I can connect to the app just fine from someone else's computer. Other people cannot connect with their accounts on my computer. Furthmore, I can connect just fine to the app when it is running on my localhost using the built-in django webserver, just not to the production server. My setup: my server and local box are running= Django 1.2.0 and Python 2.6.5. My local box is running Snow Leopard and the Django webserver, the server is running Ubuntu, Apache2, and mod-wsgi. For sessions, I am using Django's default session backend (DB). Things I have tried, all to no avail: logging in with a different account, including new accounts that have never OAuthed to this app before Clearing cookies, using incognito mode, using a different web browser on my same computer. Each time, upon inspecting my cookies, the sessionID matched the sessionID in the login function and was different from the sessionID in the callback. deleting the session in the database that appears in the callback function, (the one that appeared to be old data). The callback function still fails, and the sessionID it appears to be using is now a new one using a different session backend (DB-cache, flat file, etc...) restarting the server, my computer, etc. My first question on StackOverflow, so bear with me if I didn't quite follow local conventions. I am just at a loss as to what to even look for - what are the things that could possibly be causing sessions to not work on my particular computer, and (so far!) only my particular computer?

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  • Would this hack for per-object permissions in django work?

    - by Edward
    According to the documentation, a class can have the meta option permissions, described as such: Options.permissions Extra permissions to enter into the permissions table when creating this object. Add, delete and change permissions are automatically created for each object that has admin set. This example specifies an extra permission, can_deliver_pizzas: permissions = (("can_deliver_pizzas", "Can deliver pizzas"),) This is a list or tuple of 2-tuples in the format (permission_code, human_readable_permission_name). Would it be possible to define permissions at run time by: permissions = (("can_access_%s" % self.pk, / "Has access to object %s of type %s" % (self.pk,self.__name__)),) ?

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  • Why can't I save my model with a generic relation twice in Django?

    - by e-satis
    I got a model TrackedItem with a generic relation linking to any model it is supposed to track. If I do that: t = TrackedItem(content_object=MyModel) t.save() t.save() I get : IntegrityError: (1062, "Duplicate entry '1' for key 'PRIMARY'") Indeed, the first save has created an entry with "1" as a PK. But the second save should not insert, it should update. How am I suppose to update a model I can't save twice? With an ordinary model I can save as much as I want.

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  • What is the best way to format Django urls for two parameters, either of which are optional?

    - by Parker
    I'm designing a gallery application for viewing vehicle pictures and there are two parameters: Manufacturer Vehicle type Right now you can view either, but not both. Urls go like so: /manufacturer/# /type/# Where # is an ID number. How/can I format my URLs so it can accept both? My current solution is to do: /both/#/# but this requires some retooling since the application doesn't know when you want to filter by both. Any insight would be appreciated.

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  • Why is django admin not accepting Nullable foreign keys?

    - by p.g.l.hall
    Here is a simplified version of one of my models: class ImportRule(models.Model): feed = models.ForeignKey(Feed) name = models.CharField(max_length=255) feed_provider_category = models.ForeignKey(FeedProviderCategory, null=True) target_subcategories = models.ManyToManyField(Subcategory) This class manages a rule for importing a list of items from a feed into the database. The admin system won't let me add an ImportRule without selecting a feed_provider_category despite it being declared in the model as nullable. The database (SQLite at the moment) even checks out ok: >>> .schema ... CREATE TABLE "someapp_importrule" ( "id" integer NOT NULL PRIMARY KEY, "feed_id" integer NOT NULL REFERENCES "someapp_feed" ("id"), "name" varchar(255) NOT NULL, "feed_provider_category_id" integer REFERENCES "someapp_feedprovidercategory" ("id"), ); ... I can create the object in the python shell easily enough: f = Feed.objects.get(pk=1) i = ImportRule(name='test', feed=f) i.save() ...but the admin system won't let me edit it, of course. How can I get the admin to let me edit/create objects without specifying that foreign key?

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  • how to read a static file in .py file using django ..

    - by zjm1126
    this is my error code: text = open('/media/a.txt', 'rb').read() and my perplexed is: when i use this : text = open('a.txt', 'rb').read() it can be running but when i put the 'a.txt' to the 'media' folder, i can't running , why ? thanks IOError at / [Errno 13] file not accessible: '/media/a.txt'

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  • How do I use Django to insert a Geometry Field into the database?

    - by alex
    class LocationLog(models.Model): user = models.ForeignKey(User) utm = models.GeometryField(spatial_index=True) This is my database model. I would like to insert a row. I want to insert a circle at point -55, 333. With a radius of 10. How can I put this circle into the geometry field? Of course, then I would want to check which circles overlap a given circle. (my select statement)

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  • Django: way to test what class a generic relation content_object is?

    - by bitbutter
    In my project I have a class, NewsItem. Instances of NewsItem act like a wrapper. They can be associated with either an ArtWork instance, or an Announcement instance. Here's how the NewsItem model looks: class NewsItem(models.Model): content_type = models.ForeignKey(ContentType) object_id = models.PositiveIntegerField() content_object = generic.GenericForeignKey('content_type', 'object_id') date = models.DateTimeField(default=datetime.datetime.now,) class Meta: ordering = ('-date',) def __unicode__(self): return (self.title()) In a template I'm dealing with a NewsItem instance, and would like to output a certain bunch of html it it's 'wrapping' an Artwork instance, and a different bunch of html if it's wrapping an Announcement instance. Could someone explain how I can write a conditional to test for this? My first naive try looked like this: {% if news_item.content_object.type=='Artwork' %}do this{% else %}do that{% endif %}

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