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  • Robotlegs: Warning: Injector already has a rule for type

    - by MikeW
    I have a bunch of warning messages like this appear when using Robotlegs/Signals. Everytime this command class executes, which is every 2-3 seconds ..this message displays below If you have overwritten this mapping intentionally you can use "injector.unmap()" prior to your replacement mapping in order to avoid seeing this message. Warning: Injector already has a rule for type "mx.messaging.messages::IMessage", named "". The command functions fine otherwise but I think I'm doing something wrong anyhow. public class MessageReceivedCommand extends SignalCommand { [Inject] public var message:IMessage; ...etc.. do something with message.. } the application context doesnt map IMessage to this command, as I only see an option to mapSignalClass , besides the payload is received fine. Wonder if anyone knows how I might either fix or suppress this message. I've tried calling this as the warning suggests injector.unmap(IMessage, "") but I receive an error - no mapping found for ::IMessage named "". Thanks Edit: A bit more info about the error Here is the signal that I dispatch to the command public class GameMessageSignal extends Signal { public function GameMessageSignal() { super(IMessage); } } which is dispatched from a IPushDataService class gameMessage.dispatch(message.message); and the implementation is wired up in the app context via injector.mapClass(IPushDataService, PushDataService); along with the signal signalCommandMap.mapSignalClass(GameMessageSignal, MessageReceivedCommand); Edit #2: Probably good to point out also I inject an instance of GameMessageSignal into IPushDataService public class PushDataService extends BaseDataService implements IPushDataService { [Inject] public var gameMessage:GameMessageSignal; //then private function processMessage(message:MessageEvent):void { gameMessage.dispatch(message.message); } } Edit:3 The mappings i set up in the SignalContext: injector.mapSingleton(IPushDataService); injector.mapClass(IPushDataService, PushDataService);

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  • jQuery innerHTML does not work properly (!)

    - by Kayes
    I was trying to build an <a> tag and set it in a <td> of a table. The string is built perfectly but when I set this as the innerHTML using jQuery, the string gets broken. I can't figure out why this is happening? Any clues? Here's the string I want to set in the <td>: <a onclick='return EditIssueItemBatch('1c1e27a2-beac-4772-a26f-6a7e05529a65', '498ba483-ca06-4b23-b3a9-0085e4760ff1')'>Edit</a> But here is how it looks after setting as innerHTML: <A onclick="return EditIssueItemBatch(" ?498ba483-ca06-4b23-b3a9-0085e4760ff1?)? 1c1e27a2-beac-4772-a26f-6a7e05529a65?,>Edit</A> And the following is my code-snippet.. var tr = $("#itemIssueBatchListTable > tbody:last").children()[data.Index + 1]; ... ... var strBuff = []; strBuff.push("<a onclick='return EditIssueItemBatch('"); strBuff.push(data.ItemIssueBatch.ItemCode_FK); strBuff.push("', '"); strBuff.push(data.ItemIssueBatch.StockDetCode_FK); strBuff.push("')'>Edit</a>"); tr.cells[9].innerHTML = strBuff.join(""); ... ...

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  • Rails: Added new Action in Controller, but there is no path?

    - by Newbie
    Hello! I try to do following: A user is on his profile page. Now he edits his profile. He klicks on update and the data is saved. Now I want to redirect the user to another kind of profile-edit-page. I did the following in my users_controller.rb: def update @user = User.find(params[:id]) respond_to do |format| if @user.update_attributes(params[:user]) flash[:notice] = 'User was successfully updated.' if(@user.team_id != nil) format.html { redirect_to(@user) } else format.html { redirect_to choose_team_path } end format.xml { head :ok } else format.html { render :action => "edit" } format.xml { render :xml => @user.errors, :status => :unprocessable_entity } end end end def choose_team @user = User.find(params[:id]) end I created a view: /users/choose_team.html.erb Now I get the following error: undefined local variable or method `choose_team_path' for #<UsersController:0x1f56650> So I added choose_team to my routes.rb: map.choose_team 'choose-team', :controller => 'users', :action => 'choose_team' Now, after submitting my first edit form, it redirects me to http://localhost:3000/choose-team and I get following error: Couldn't find User without an ID What I want: If a user has no team_id, he should be redirected to my choose_team.html.erb for choosing a team, else he should be redirected to his profile/show. How to do this?

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  • WindowsFormsApplicationBase SplashScreen makes login form ignore keypresses until I click on it - how to debug?

    - by Tom Bushell
    My WinForms app has a simple modal login form, invoked at startup via ShowDialog(). When I run from inside Visual Studio, everything works fine. I can just type in my User ID, hit the Enter key, and get logged in. But when I run a release build directly, everything looks normal (the login form is active, there's a blinking cursor in the User ID MaskedEditBox), but all keypresses are ignored until I click somewhere on the login form. Very annoying if you are used to doing everything from the keyboard. I've tried to trace through the event handlers, and to set the focus directly with code, to no avail. Any suggestions how to debug this (outside of Visual Studio), or failing that - a possible workaround? Edit Here's the calling code, in my Main Form: private void OfeMainForm_Shown(object sender, EventArgs e) { OperatorLogon(); } private void OperatorLogon() { // Modal dialogs should be in a "using" block for proper disposal using (var logonForm = new C21CfrLogOnForm()) { var dr = logonForm.ShowDialog(this); if (dr == DialogResult.OK) SaveOperatorId(logonForm.OperatorId); else Application.Exit(); } } Edit 2 Didn't think this was relevant, but I'm using Microsoft.VisualBasic.ApplicationServices.WindowsFormsApplicationBase for it's splash screen and SingleInstanceController support. I just commented out the splash screen code, and the problem has disappeared. So that's opened up a whole new line of inquiry... Edit 3 Changed title to reflect better understanding of the problem

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  • "assignment makes integer from pointer without a cast " warning in c

    - by mekasperasky
    #include<stdio.h> /* this is a lexer which recognizes constants , variables ,symbols, identifiers , functions , comments and also header files . It stores the lexemes in 3 different files . One file contains all the headers and the comments . Another file will contain all the variables , another will contain all the symbols. */ int main() { int i=0,j; char a,b[20],c[30]; FILE *fp1,*fp2; c[0]='"if"; c[1]="then"; c[2]="else"; c[3]="switch"; c[4]="printf"; c[5]="scanf"; c[6]="NULL"; c[7]="int"; c[8]="char"; c[9]="float"; c[10]="long"; c[11]="double"; c[12]="char"; c[13]="const"; c[14]="continue"; c[15]="break"; c[16]="for"; c[17]="size of"; c[18]="register"; c[19]="short"; c[20]="auto"; c[21]="while"; c[22]="do"; c[23]="case"; fp1=fopen("source.txt","r"); //the source file is opened in read only mode which will passed through the lexer fp2=fopen("lext.txt","w"); //now lets remove all the white spaces and store the rest of the words in a file if(fp1==NULL) { perror("failed to open source.txt"); //return EXIT_FAILURE; } i=0; while(!feof(fp1)) { a=fgetc(fp1); if(a!=' ') { b[i]=a; } else { for (j=0;j<23;j++) { if(c[j]==b) { fprintf(fp2, "%.20s\n", c[j]); continue ; } b[i]='\0'; fprintf(fp2, "%.20s\n", b); i=0; continue; } //else if //{ i=i+1; /*Switch(a) { case EOF :return eof; case '+':sym=sym+1; case '-':sym=sym+1; case '*':sym=sym+1; case '/':sym=sym+1; case '%':sym=sym+1; case ' */ } fclose(fp1); fclose(fp2); return 0; } This is my c code for lexical analysis .. its giving warnings and also not writing anything into the lext file ..

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  • How can I introduce a regex action to match the first element in a Catalyst URI ?

    - by RET
    Background: I'm using a CRUD framework in Catalyst that auto-generates forms and lists for all tables in a given database. For example: /admin/list/person or /admin/add/person or /admin/edit/person/3 all dynamically generate pages or forms as appropriate for the table 'person'. (In other words, Admin.pm has actions edit, list, add, delete and so on that expect a table argument and possibly a row-identifying argument.) Question: In the particular application I'm building, the database will be used by multiple customers, so I want to introduce a URI scheme where the first element is the customer's identifier, followed by the administrative action/table etc: /cust1/admin/list/person /cust2/admin/add/person /cust2/admin/edit/person/3 This is for "branding" purposes, and also to ensure that bookmarks or URLs passed from one user to another do the expected thing. But I'm having a lot of trouble getting this to work. I would prefer not to have to modify the subs in the existing framework, so I've been trying variations on the following: sub customer : Regex('^(\w+)/(admin)$') { my ($self, $c, @args) = @_; #validation of captured arg snipped.. my $path = join('/', 'admin', @args); $c->request->path($path); $c->dispatcher->prepare_action($c); $c->forward($c->action, $c->req->args); } But it just will not behave. I've used regex matching actions many times, but putting one in the very first 'barrel' of a URI seems unusually traumatic. Any suggestions gratefully received.

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  • C#: HTTPWebResponse using application/x-www-form-urlencoded

    - by CSharpened
    So I sent an HTTPWebRequest using application/x-www-form-urlencoded as my content type. I assume that this means the reponse will be returned in a similar type? (EDIT: Have now been told this isn't the case) My question is this. How do I access the different key/value pairs returned in the response. My code so far looks like this. I can of course read the string but surely there is a better way to access the data other than ripping the string apart. HttpWebResponse response = SendPOSTRequest("https://site/page?Service=foo", content.ToString(), "", "", true); string responseCode = response.StatusCode.ToString(); string responseStatusDescription = response.StatusDescription; StreamReader sr = new StreamReader(response.GetResponseStream()); string result = sr.ReadToEnd(); I tried using XML/linq to read the elements into an XDocument but of course it is not being returned in XML form. Assume I have 3 or 4 different pieces of information in there how could I read them out? EDIT: I have just checked and the data is being returned as text/plain. How can this be processed easily? EDIT: The response string once retrieved via a streamreader is: VPSProtocol=2.23 Status=OK StatusDetail=Server transaction registered successfully. VPSTxId={FDC93F3D-FC64-400D-875F-0B7E855AD81F} SecurityKey=***** NextURL=https://foo.com/PaymentPage.asp?TransactionID={875F-0B7E855AD81F}

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  • How to model and handle presentation DTO's to abstract from complicated domain model?

    - by arrages
    Hi I am developing an application that needs to work with a complex domain model using Hibernate. This application uses Spring MVC and using the domain objects in the presentation layer is very messy so I think I should use DTO's that go to and from my service layer so that these match what I need in my views. Now lets assume I have a CarLease entity whose properties are not simple java primitives but it's composed with other entities like Make, Model, etc public class CarLease { private Make make; Private Model model; . . . } most properties are in this fashion and they are selectable using drop down selects on the jsp view, each will post back an ID to the controller. Now considering some standard use cases: create, edit, display How would you go about modeling the presentation DTO's to be used as form backing objects and communication between presentation and service layers?? Would you create a different DTO for each case (create, edit, display), would you make DTO's for the complex attributes? if so where would you translate the ID to entity? how and where would you handle validation, DTO/Domain assembly, what would you return from service layer methods? (create, edit, get) As you can see, I now I will benefit by separating my view from the domain objects (very complex with lots of stuff I don't need.) but I am having a hard time finding any real world examples and best practices for this. I need some architecture guidance from top to bottom, please keep in mind I will use Spring MVC in case that may leverage on your anwser. thanks in advance.

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  • How do I efficiently parse a CSV file in Perl?

    - by Mike
    I'm working on a project that involves parsing a large csv formatted file in Perl and am looking to make things more efficient. My approach has been to split() the file by lines first, and then split() each line again by commas to get the fields. But this suboptimal since at least two passes on the data are required. (once to split by lines, then once again for each line). This is a very large file, so cutting processing in half would be a significant improvement to the entire application. My question is, what is the most time efficient means of parsing a large CSV file using only built in tools? note: Each line has a varying number of tokens, so we can't just ignore lines and split by commas only. Also we can assume fields will contain only alphanumeric ascii data (no special characters or other tricks). Also, i don't want to get into parallel processing, although it might work effectively. edit It can only involve built-in tools that ship with Perl 5.8. For bureaucratic reasons, I cannot use any third party modules (even if hosted on cpan) another edit Let's assume that our solution is only allowed to deal with the file data once it is entirely loaded into memory. yet another edit I just grasped how stupid this question is. Sorry for wasting your time. Voting to close.

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  • PHP Form multiple buttons

    - by Ken
    I have a form with 2 buttons, that depending on which is selected will either be deleted or edited from the database. Those are each individual pages using SQL statements (questionedit and questiondelete). However, when i press a button, nothing happens...Any Ideas Here is my javascript <script type="text/javascript"> function SelectedButton(button) { if(button == 'edit') { document.testedit_questionform.action ="testedit_questionedit.php"; } else if(button == 'delete') { document.testedit_questionform.action ="testedit_questiondelete.php"; } document.forms[].testedit_questionform.submit(); } </script> Here is my form (being echoed from a loop) <form name=\"testedit_questionform\" action=\"SelectedButton\" method=\"POST\"> <span class=\"grid_11 prefix_1\" id=\"\" > Question:<input type=\"text\" name=\"QuestionText\" style=\"width:588px; margin-left:10px;\" value=\"$row[0]\"/> <input type=\"button\" value=\"Edit\" name=\"Operation\"onclick=\"submitForm(\'edit\')\" /> <input type=\"button\" value=\"Delete\" name=\"Operation\"onclick=\"submitForm(\'delete\')\" /> <input type=\"hidden\" name=\"QId\" value=\"$row[3]\" /><br />"); </form>

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  • Zend Framework: How to display multiple actions, each requiring different authorizations levels, on

    - by Iain
    Imagine I have 4 database tables, and an interface that presents forms for the management of the data in each of these tables on a single webpage (using the accordion design pattern to show only one form at a time). Each form is displayed with a list of rows in the table, allowing the user to insert a new row or select a row to edit or delete. AJAX is then used to send the request to the server. A different set of forms must be displayed to different users, based on the application ACL. My question is: In terms of controllers, actions, views, and layouts, what is the best architecture for this interface? For example, so far I have a controller with add, edit and delete actions for each table. There is an indexAction for each, but it's an empty function. I've also extended Zend_Form for each table. To display the forms, I then in the IndexController pass the Forms to it's view, and echo each form. Javascript then takes care of populating the form and sending requests to the appropraite add/edit/delete action of the appropriate controller. This however doesn't allow for ACL to control the display or not of Forms to different users. Would it be better to have the indexAction instantiate the form, and then use something like $this-render(); to render each view within the view of the indexAction of the IndexController? Would ACL then prevent certain views from being rendered? Cheers.

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  • Debug.Assert-s use the same error message. Should I promote it to a static variable?

    - by Hamish Grubijan
    I love Asserts and code readability but not code duplication, and in several places I use a Debug.Assert which checks for the same condition like so: Debug.Assert(kosherBaconList.SelectedIndex != -1, "An error message along the lines - you should not ever be able to click on edit button without selecting a kosher bacon first."); This is in response to an actual bug, although the actual list does not contain kosher bacon. Anyhow, I can think of two approaches: private static readonly mustSelectKosherBaconBeforeEditAssertMessage = "An error message along the lines - you should not ever be able to " + "click on edit button without selecting a something first."; ... Debug.Assert( kosherBaconList.SelectedIndex != -1, mustSelectKosherBaconBeforeEditAssertMessage) or: if (kosherBaconList.SelectedIndex == -1) { AssertMustSelectKosherBaconBeforeEdit(); } ... [Conditional("DEBUG")] private void AssertMustSelectKosherBaconBeforeEdit() { // Compiler will optimize away this variable. string errorMessage = "An error message along the lines - you should not ever be able to " + "click on edit button without selecting a something first."; Debug.Assert(false, errorMessage); } or is there a third way which sucks less than either one above? Please share. General helpful relevant tips are also welcome.

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  • Running game, leaving game and continuing animation

    - by Madrusec
    I have been trying to learn some Actionscript recently and have been trying to run an interactive story that at one point turns into an extremel simple shooter game. After the player either wins or looses, then he/she is taken to the rest of the animated story. So I have everything up to the point where the games runs (successfully) but for some reason I am unable to have flash run the rest of the frames, most of which have no code at all. This is the code for scene 1: stop (); import flash.display.MovieClip; import flash.events.MouseEvent; import flash.utils.Timer; import flash.events.TimerEvent; var stoneInGame:uint; var stoneMaker: Timer; var container_mc: MovieClip; var cursor:MovieClip; var score:int; var anxiety:int; var anxiety_mc :MovieClip = new mcAnxiety(); //stage.addChild( anxiety_mc ); function initializeGame():void { stoneInGame = 10; stoneMaker = new Timer(1000, stoneInGame); container_mc = new MovieClip(); addChild(container_mc); container_mc.addChild(anxiety_mc); anxiety_mc.x = 497; anxiety_mc.y = 360; stoneMaker.addEventListener(TimerEvent.TIMER, createStones); stoneMaker.start(); cursor = new Cursor(); addChild(cursor); cursor.enabled = false; Mouse.hide(); stage.addEventListener(MouseEvent.MOUSE_MOVE, dragCursor); score = 0; anxiety = anxiety_mc.totalFrames; anxiety_mc.gotoAndStop(anxiety); } function dragCursor(event:MouseEvent):void { cursor.x = this.mouseX; cursor.y = this.mouseY; } function createStones(event:TimerEvent):void { var stone:MovieClip; stone = new Stone(); stone.x = Math.random() * stage.stageWidth; stone.y = Math.random() * stage.stageHeight; container_mc.addChild(stone); } function increaseScore():void { score ++; if(score >= stoneInGame) { dragCursor.stop(); createStones.stop(); stoneMaker.stop(); trace("you wind!"); } } function decreaseAnxiety():void { anxiety--; if(anxiety <= 0) { stoneMaker.stop(); trace("you lose!"); } else { anxiety_mc.gotoAndStop(anxiety); } increaseScore(); } initializeGame(); So what I tried to do was adding gotoAndPlay() inside both the decreaseAnxiety and increaseScore functions after the trace statements and referenced a frame where I have more keyframes that continue a story. However, Flash just goes back to the beginning of the timeline and I even the functions that change and control the cursor seem to be running. This leads me to believe that I need to make sure that I tell flash o stup running certain functions before jumping to another frame. However, it seems to me that I would still have the same issue and not be able to continue in the timeline. Is there something I am missing? How can I jump out of all this code once the game finishes and simply continue playing the rest of the frames? Any pointers would be greatly appreciated. Thank you

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  • PUT-ing a form to update a row, but I can't find the id. Where is it?

    - by montooner
    How should I be passing in the ID? Error: Couldn't find Product without an ID Form: <% form_for :product, @product, :url => { :action => :update } do |f| %> <%= f.error_messages %> <p> <%= f.label :names %><br /> <%= f.text_field :names %> </p> <p> <%= f.submit 'Update' %> </p> <% end %> Controller (for /products/edit/1 view): def edit @product = Product.find(params[:id]) end Controller (to change the db): def update @product = Product.find(params[:id]) respond_to do |format| if @product.update_attributes(params[:product]) format.html { redirect_to(@product, :notice => 'Product was successfully updated.') } format.xml { head :ok } else format.html { render :action => "edit" } format.xml { render :xml => @product.errors, :status => :unprocessable_entity } end end end

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  • Does Spring MVC form submit data bind children objects automagically?

    - by predhme
    I have a data model that is something like this: public class Report { // report owner private User user; ... typical getter setter ... } public class User { ... omitted for clarity } What happens is when a report is created, the current user is set to the report user object. When the report is edited, the spring controller handling the POST request is receiving a report where the user object is null. Here is what my controller looks like: @Controller @RequestMapping("/report") public class ReportController { @RequestMapping(value = "/edit/{id}", method = RequestMethod.GET) public String editReport(@PathVariable Long id, Model model) { Report r = backend.getReport(id); // fully loads object model.addAttribute("report", report); return "report/edit"; } @RequestMapping(value = "/edit/{id}", method = RequestMethod.POST) public String process(@ModelAttribute("report") Report r) { backend.save(r); return "redirect:/report/show" + r.getId(); } } I ran things throw the debugger and it looks like in the editReport method the model object is storing the fully loaded report object (I can see the user inside the report). On the form jsp I can do the following: ${report.user.username} and the correct result is rendered. However, when I look at the debugger in the process method, the passed in Report r has a null user. I don't need to do any special data binding to ensure that information is retained do I?

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  • Dropdownlist value not being set when there is a default blank option

    - by uriDium
    I am using ASP.Net MVC. I have a partial view which has a form with dropdownlists. The dropdownlists are set via ViewData. The partial view is used in a Create and Edit page. The create works fine. I get the dropdownlists and the blank option is a "Please select", like so <%= Html.DropDownList("ContactNrType", ViewData["ContactNrType"] as SelectList, "Please Select") %> But this doesn't seem to work for my edit. If I have that extra "Please select" parameter then it does not select the value for the drop down. I am setting the value of the drop down in the controller like so ViewData["ContactNrType"] = new SelectList(new List<string> { "Mobile", "Home", "Work", "Friend" }, candidate.ContactNrType); Any idea as to what I am doing wrong? I want to share the partial view which contains the form between the two pages. So I need the "Please Select" option for the Create. And I need the value set for the Edit (I don't mind that it has an option that still says "Please Select").

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  • Images won't load if they are of high size

    - by Fahim Parkar
    I have created web-application using JSF 2.0 and mysql. I am storing images in DB using MEDIUMBLOB. When I try to load image, I am able to see those images. However if the image size is big (1 MB or more), I can see half or 3/4th image on the browser. Any idea how to overcome this issue? Do I need to set any variable in JSF or MySQL? I know I should have saved the images over disk instead of DB, however this was client requirement. Client wanted to backup data and provide it to someone else and client don't want to backup DB and images also. Edit 1 Do I need to set any variables on mysql like query_cache. Edit 2 When I download same image and put below code it works perfectly. <h:graphicImage value="images/myImage4.png" width="50%" /> Edit 3 code is as below. <h:graphicImage value="DisplayImage?mainID=drawing" /> DisplayImage.java String imgLen = rs1.getString(1); int len = imgLen.length(); byte[] rb = new byte[len]; InputStream readImg = rs1.getBinaryStream(1); InputStream inputStream = readImg; int index = readImg.read(rb, 0, len); response.reset(); response.setHeader("Content-Length", String.valueOf(len)); response.setHeader("Content-disposition", "inline;filename=/file.png"); response.setContentType("image/png"); response.getOutputStream().write(rb, 0, len); response.getOutputStream().flush(); When I print len I get value as len=1548432

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  • How can I break up long words instead of overflowing?

    - by ripper234
    How can I stop this text from overflowing? <html> <head> <style type="text/css"> .sticky { background-color: #FCFC80; margin: 5px; height: 100px; width: 135px; } .sticky .edit { vertical-align:middle; height: 100px; position:relative; color:Black; background-color:blue; height:90px; vertical-align:middle; width:90px; border-collapse:collapse; } </style> </head> <body> <div id="note44" class="sticky"> <div id="text44" class="edit" title="Click to edit" style="">A very long word: abcdefasdfasfasd</div> </div> </body> </html>

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  • a potentially dangerous request.form value was detected but validateinput(false) not working

    - by tonybolding
    I have installed VS2010 and MVC2 and testing a simple form using tinyMCE. When I post the contents of the textarea in tinyMCE I get the dreaded YSD and the message "a potentially dangerous....." No problem I thought - seen this before so I put the ValidateInput(false) on the controller but no joy - I still get the error. page code in edit.aspx is: <% using (Html.BeginForm()){ % <!-- Gets replaced with TinyMCE, remember HTML in a textarea should be encoded --> <textarea id="elm1" name="mceText" rows="15" cols="80" style="width: 80%"> &lt;p&gt; This is some example text that you can edit inside the &lt;strong&gt;TinyMCE editor&lt;/strong&gt;. </textarea> <br /> <input type="submit" name="save" value="Submit" /> <input type="reset" name="reset" value="Reset" /> <%} % and Controller action is: [AcceptVerbs(HttpVerbs.Post)] [ValidateInput(false)] public ActionResult Edit(string mceText) { return View(); } Any thoughts - (I know the code is not complete) been trying this for hours but everyone just says to use ValidateInput(false)

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  • Integration test for H1 text failing when it should be passing (Rspec and Capybara)

    - by rebec
    Below you can see my test for what happens when a user tries to access the page to edit a profile photo that they don't own. I've used the same test on the NEW action, where it worked fine, but it surprised me by failing when I copied it down to the EDIT action tests. I've used save_and_open_page to test what Capybara's seeing (as you can see below); the resulting page definitely has an h1 with the specified text in it. No spelling errors, and case is all the same as in the test. I've tried using both have_css and have_selector. Both fail. I'm still learning Ruby, Rails, Rspec and especially Capybara (was using webrat previously and recently switched over), and wonder if I'm misconceiving of something that's making me expect this to pass when it doesn't. Any thoughts? Thanks! describe "EDIT" do let(:user) { FactoryGirl.create(:user) } let(:different_user) { FactoryGirl.create(:user) } let(:admin_user) { FactoryGirl.create(:user, role: "admin") } let(:profile_photo1) { FactoryGirl.create(:profile_photo, user: user) } subject { page } context "when signed in as any member" do before { login different_user visit edit_user_profile_photo_path(:id => profile_photo1, :user_id => profile_photo1.user_id) save_and_open_page } # It should deny access with an Unauthorised/Forbidden message. it { should have_css('h1', text: "Unauthorised/Forbidden.") } end

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  • Joomla get plugin id

    - by Christian Sciberras
    I wrote a Joomla plugin which will eventually load a library. The path to library is a plugin parameter, as such when the path is incorrect, a message pops up in the backend, together with a link to edit the plugin parameters: /administrator/index.php?option=com_plugins&view=plugin&client=site&task=edit&cid[]=36 See the 36 at the end? That's my plugin's id in the database (table jos_plugins). My issue is that this id changes on installation, ie, on different installs, it would be something else. So I need to find this id programmatically. The problem is that I couldn't find this id from the plugin object itself (as to why not, that would be joomla's arguably short-sighted design decision). So unless you know about some neat trick, (I've checked and double checked JPlugin and JPluginHelper classes), I'll be using the DB. Edit; Some useful links: http://docs.joomla.org/Plugin_Developer_Overview http://api.joomla.org/Joomla-Framework/Plugin/JPlugin.html http://api.joomla.org/Joomla-Framework/Plugin/JPluginHelper.html http://forum.joomla.org/viewtopic.php?p=2227737 Guess I'll be using the wisdom from that last link...

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  • Real time content editing html5

    - by Mark Lauzon
    So I've seen things like WordPress and FCKEditor, and basically a bunch of stuff that uses external code that I can't see or edit. Whenever I ask about editing and saving the content of a page in real time I just get referenced to an API or I get handed code that only changes the page until it's reloaded. What I want to know is how do I code it myself? I want to add real time content editing to a page without the use of someone else's code. I've checked out code for various forums and wikipedia and whatnot, and all of it references code I don't have access to. Is this a thing? Can I edit a page in real time? I thought of writing the edited text to a file on the server, and then when they click save, reading it back into the code to the section they were editing, but I don't know how to do that or if it's even possible. As a side note, I'm very new to html, but not new to coding. EDIT: The structure can be very much like Wikipedia, it doesn't have to be real time, it just has to work

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  • Differentiate Between UITableView Editing States?

    - by Josh Kahane
    I have been looking at trying to differentiate between editing states in my UITableView. I need to call a method only when in editing mode after tapping the edit button, so when you get your cell slide in and you see the little circular delete icons but NOT when the user swipes to delete. Is there anyway I can differentiate between the two? Thanks. EDIT: Solution thanks to Rodrigo Both each cell and the entire tableview has an 'editing' BOOL value, so I loop through all the cells and if more than one of them is editing then we know the whole table is (the user tapped the edit button), however if only one is editing then we know that the user has swiped a cell, editing that individual one, this lets me deal with each editing state individually! - (void)setEditing:(BOOL)editing animated:(BOOL)animated { [super setEditing:editing animated:animated]; int i = 0; //When editing loop through cells and hide status image so it doesn't block delete controls. Fade back in when done editing. for (customGuestCell *cell in self.tableView.visibleCells) { if (cell.isEditing) { i += 1; } } if (i > 1) { for (customGuestCell *cell in self.tableView.visibleCells) { if (editing) { // loop through the visible cells and animate their imageViews [UIView beginAnimations:nil context:nil]; [UIView setAnimationDuration:0.4]; cell.statusImg.alpha = 0; [UIView commitAnimations]; } } } else if (!editing) { for (customGuestCell *cell in self.tableView.visibleCells) { [UIView beginAnimations:nil context:nil]; [UIView setAnimationDuration:0.4]; cell.statusImg.alpha = 1.0; [UIView commitAnimations]; } } }

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  • Run Windows in Ubuntu with VMware Player

    - by Matthew Guay
    Are you an enthusiast who loves their Ubuntu Linux experience but still needs to use Windows programs?  Here’s how you can get the full Windows experience on Ubuntu with the free VMware Player. Linux has become increasingly consumer friendly, but still, the wide majority of commercial software is only available for Windows and Macs.  Dual-booting between Windows and Linux has been a popular option for years, but this is a frustrating solution since you have to reboot into the other operating system each time you want to run a specific application.  With virtualization, you’ll never have to make this tradeoff.  VMware Player makes it quick and easy to install any edition of Windows in a virtual machine.  With VMware’s great integration tools, you can copy and paste between your Linux and Windows programs and even run native Windows applications side-by-side with Linux ones. Getting Started Download the latest version of VMware Player for Linux, and select either the 32-bit or 64-bit version, depending on your system.  VMware Player is a free download, but requires registration.  Sign in with your VMware account, or create a new one if you don’t already have one. VMware Player is fairly easy to install on Linux, but you will need to start out the installation from the terminal.  First, enter the following to make sure the installer is marked as executable, substituting version/build_number for the version number on the end of the file you downloaded. chmod +x ./VMware-Player-version/build_number.bundle Then, enter the following to start the install, again substituting your version number: gksudo bash ./VMware-Player-version/build_number.bundle You may have to enter your administrator password to start the installation, and then the VMware Player graphical installer will open.  Choose whether you want to check for product updates and submit usage data to VMware, and then proceed with the install as normal. VMware Player installed in only a few minutes in our tests, and was immediately ready to run, no reboot required.  You can now launch it from your Ubuntu menu: click Applications \ System Tools \ VMware Player. You’ll need to accept the license agreement the first time you run it. Welcome to VMware Player!  Now you can create new virtual machines and run pre-built ones on your Ubuntu desktop. Install Windows in VMware Player on Ubuntu Now that you’ve got VMware setup, it’s time to put it to work.  Click the Create a New Virtual Machine as above to start making a Windows virtual machine. In the dialog that opens, select your installer disk or ISO image file that you want to install Windows from.  In this example, we’re select a Windows 7 ISO.  VMware will automatically detect the operating system on the disk or image.  Click Next to continue. Enter your Windows product key, select the edition of Windows to install, and enter your name and password. You can leave the product key field blank and enter it later.  VMware will ask if you want to continue without a product key, so just click Yes to continue. Now enter a name for your virtual machine and select where you want to save it.  Note: This will take up at least 15Gb of space on your hard drive during the install, so make sure to save it on a drive with sufficient storage space. You can choose how large you want your virtual hard drive to be; the default is 40Gb, but you can choose a different size if you wish.  The entire amount will not be used up on your hard drive initially, but the virtual drive will increase in size up to your maximum as you add files.  Additionally, you can choose if you want the virtual disk stored as a single file or as multiple files.  You will see the best performance by keeping the virtual disk as one file, but the virtual machine will be more portable if it is broken into smaller files, so choose the option that will work best for your needs. Finally, review your settings, and if everything looks good, click Finish to create the virtual machine. VMware will take over now, and install Windows without any further input using its Easy Install.  This is one of VMware’s best features, and is the main reason we find it the easiest desktop virtualization solution to use.   Installing VMware Tools VMware Player doesn’t include the VMware Tools by default; instead, it automatically downloads them for the operating system you’re installing.  Once you’ve downloaded them, it will use those tools anytime you install that OS.  If this is your first Windows virtual machine to install, you may be prompted to download and install them while Windows is installing.  Click Download and Install so your Easy Install will finish successfully. VMware will then download and install the tools.  You may need to enter your administrative password to complete the install. Other than this, you can leave your Windows install unattended; VMware will get everything installed and running on its own. Our test setup took about 30 minutes, and when it was done we were greeted with the Windows desktop ready to use, complete with drivers and the VMware tools.  The only thing missing was the Aero glass feature.  VMware Player is supposed to support the Aero glass effects in virtual machines, and although this works every time when we use VMware Player on Windows, we could not get it to work in Linux.  Other than that, Windows is fully ready to use.  You can copy and paste text, images, or files between Ubuntu and Windows, or simply drag-and-drop files between the two. Unity Mode Using Windows in a window is awkward, and makes your Windows programs feel out of place and hard to use.  This is where Unity mode comes in.  Click Virtual Machine in VMware’s menu, and select Enter Unity. Your Windows desktop will now disappear, and you’ll see a new Windows menu underneath your Ubuntu menu.  This works the same as your Windows Start Menu, and you can open your Windows applications and files directly from it. By default, programs from Windows will have a colored border and a VMware badge in the corner.  You can turn this off from the VMware settings pane.  Click Virtual Machine in VMware’s menu and select Virtual Machine Settings.  Select Unity under the Options tab, and uncheck the Show borders and Show badges boxes if you don’t want them. Unity makes your Windows programs feel at home in Ubuntu.  Here we have Word 2010 and IE8 open beside the Ubuntu Help application.  Notice that the Windows applications show up in the taskbar on the bottom just like the Linux programs.  If you’re using the Compiz graphics effects in Ubuntu, your Windows programs will use them too, including the popular wobbly windows effect. You can switch back to running Windows inside VMware Player’s window by clicking the Exit Unity button in the VMware window. Now, whenever you want to run Windows applications in Linux, you can quickly launch it from VMware Player. Conclusion VMware Player is a great way to run Windows on your Linux computer.  It makes it extremely easy to get Windows installed and running, lets you run your Windows programs seamlessly alongside your Linux ones.  VMware products work great in our experience, and VMware Player on Linux was no exception. If you’re a Windows user and you’d like to run Ubuntu on Windows, check out our article on how to Run Ubuntu in Windows with VMware Player. Link Download VMware Player 3 (Registration required) Download Windows 7 Enterprise 90-day trial Similar Articles Productive Geek Tips Enable Copy and Paste from Ubuntu VMware GuestInstall VMware Tools on Ubuntu Edgy EftRestart the Ubuntu Gnome User Interface QuicklyHow to Add a Program to the Ubuntu Startup List (After Login)How To Run Ubuntu in Windows 7 with VMware Player TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Xobni Plus for Outlook All My Movies 5.9 CloudBerry Online Backup 1.5 for Windows Home Server Snagit 10 Get a free copy of WinUtilities Pro 2010 World Cup Schedule Boot Snooze – Reboot and then Standby or Hibernate Customize Everything Related to Dates, Times, Currency and Measurement in Windows 7 Google Earth replacement Icon (Icons we like) Build Great Charts in Excel with Chart Advisor

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  • Developing web apps using ASP.NET MVC 3, Razor and EF Code First - Part 1

    - by shiju
    In this post, I will demonstrate web application development using ASP. NET MVC 3, Razor and EF code First. This post will also cover Dependency Injection using Unity 2.0 and generic Repository and Unit of Work for EF Code First. The following frameworks will be used for this step by step tutorial. ASP.NET MVC 3 EF Code First CTP 5 Unity 2.0 Define Domain Model Let’s create domain model for our simple web application Category class public class Category {     public int CategoryId { get; set; }     [Required(ErrorMessage = "Name Required")]     [StringLength(25, ErrorMessage = "Must be less than 25 characters")]     public string Name { get; set;}     public string Description { get; set; }     public virtual ICollection<Expense> Expenses { get; set; } }   Expense class public class Expense {             public int ExpenseId { get; set; }            public string  Transaction { get; set; }     public DateTime Date { get; set; }     public double Amount { get; set; }     public int CategoryId { get; set; }     public virtual Category Category { get; set; } } We have two domain entities - Category and Expense. A single category contains a list of expense transactions and every expense transaction should have a Category. In this post, we will be focusing on CRUD operations for the entity Category and will be working on the Expense entity with a View Model object in the later post. And the source code for this application will be refactored over time. The above entities are very simple POCO (Plain Old CLR Object) classes and the entity Category is decorated with validation attributes in the System.ComponentModel.DataAnnotations namespace. Now we want to use these entities for defining model objects for the Entity Framework 4. Using the Code First approach of Entity Framework, we can first define the entities by simply writing POCO classes without any coupling with any API or database library. This approach lets you focus on domain model which will enable Domain-Driven Development for applications. EF code first support is currently enabled with a separate API that is runs on top of the Entity Framework 4. EF Code First is reached CTP 5 when I am writing this article. Creating Context Class for Entity Framework We have created our domain model and let’s create a class in order to working with Entity Framework Code First. For this, you have to download EF Code First CTP 5 and add reference to the assembly EntitFramework.dll. You can also use NuGet to download add reference to EEF Code First.    public class MyFinanceContext : DbContext {     public MyFinanceContext() : base("MyFinance") { }     public DbSet<Category> Categories { get; set; }     public DbSet<Expense> Expenses { get; set; }         }   The above class MyFinanceContext is derived from DbContext that can connect your model classes to a database. The MyFinanceContext class is mapping our Category and Expense class into database tables Categories and Expenses using DbSet<TEntity> where TEntity is any POCO class. When we are running the application at first time, it will automatically create the database. EF code-first look for a connection string in web.config or app.config that has the same name as the dbcontext class. If it is not find any connection string with the convention, it will automatically create database in local SQL Express database by default and the name of the database will be same name as the dbcontext class. You can also define the name of database in constructor of the the dbcontext class. Unlike NHibernate, we don’t have to use any XML based mapping files or Fluent interface for mapping between our model and database. The model classes of Code First are working on the basis of conventions and we can also use a fluent API to refine our model. The convention for primary key is ‘Id’ or ‘<class name>Id’.  If primary key properties are detected with type ‘int’, ‘long’ or ‘short’, they will automatically registered as identity columns in the database by default. Primary key detection is not case sensitive. We can define our model classes with validation attributes in the System.ComponentModel.DataAnnotations namespace and it automatically enforces validation rules when a model object is updated or saved. Generic Repository for EF Code First We have created model classes and dbcontext class. Now we have to create generic repository pattern for data persistence with EF code first. If you don’t know about the repository pattern, checkout Martin Fowler’s article on Repository Let’s create a generic repository to working with DbContext and DbSet generics. public interface IRepository<T> where T : class     {         void Add(T entity);         void Delete(T entity);         T GetById(long Id);         IEnumerable<T> All();     }   RepositoryBasse – Generic Repository class public abstract class RepositoryBase<T> where T : class { private MyFinanceContext database; private readonly IDbSet<T> dbset; protected RepositoryBase(IDatabaseFactory databaseFactory) {     DatabaseFactory = databaseFactory;     dbset = Database.Set<T>(); }   protected IDatabaseFactory DatabaseFactory {     get; private set; }   protected MyFinanceContext Database {     get { return database ?? (database = DatabaseFactory.Get()); } } public virtual void Add(T entity) {     dbset.Add(entity);            }        public virtual void Delete(T entity) {     dbset.Remove(entity); }   public virtual T GetById(long id) {     return dbset.Find(id); }   public virtual IEnumerable<T> All() {     return dbset.ToList(); } }   DatabaseFactory class public class DatabaseFactory : Disposable, IDatabaseFactory {     private MyFinanceContext database;     public MyFinanceContext Get()     {         return database ?? (database = new MyFinanceContext());     }     protected override void DisposeCore()     {         if (database != null)             database.Dispose();     } } Unit of Work If you are new to Unit of Work pattern, checkout Fowler’s article on Unit of Work . According to Martin Fowler, the Unit of Work pattern "maintains a list of objects affected by a business transaction and coordinates the writing out of changes and the resolution of concurrency problems." Let’s create a class for handling Unit of Work   public interface IUnitOfWork {     void Commit(); }   UniOfWork class public class UnitOfWork : IUnitOfWork {     private readonly IDatabaseFactory databaseFactory;     private MyFinanceContext dataContext;       public UnitOfWork(IDatabaseFactory databaseFactory)     {         this.databaseFactory = databaseFactory;     }       protected MyFinanceContext DataContext     {         get { return dataContext ?? (dataContext = databaseFactory.Get()); }     }       public void Commit()     {         DataContext.Commit();     } }   The Commit method of the UnitOfWork will call the commit method of MyFinanceContext class and it will execute the SaveChanges method of DbContext class.   Repository class for Category In this post, we will be focusing on the persistence against Category entity and will working on other entities in later post. Let’s create a repository for handling CRUD operations for Category using derive from a generic Repository RepositoryBase<T>.   public class CategoryRepository: RepositoryBase<Category>, ICategoryRepository     {     public CategoryRepository(IDatabaseFactory databaseFactory)         : base(databaseFactory)         {         }                } public interface ICategoryRepository : IRepository<Category> { } If we need additional methods than generic repository for the Category, we can define in the CategoryRepository. Dependency Injection using Unity 2.0 If you are new to Inversion of Control/ Dependency Injection or Unity, please have a look on my articles at http://weblogs.asp.net/shijuvarghese/archive/tags/IoC/default.aspx. I want to create a custom lifetime manager for Unity to store container in the current HttpContext.   public class HttpContextLifetimeManager<T> : LifetimeManager, IDisposable {     public override object GetValue()     {         return HttpContext.Current.Items[typeof(T).AssemblyQualifiedName];     }     public override void RemoveValue()     {         HttpContext.Current.Items.Remove(typeof(T).AssemblyQualifiedName);     }     public override void SetValue(object newValue)     {         HttpContext.Current.Items[typeof(T).AssemblyQualifiedName] = newValue;     }     public void Dispose()     {         RemoveValue();     } }   Let’s create controller factory for Unity in the ASP.NET MVC 3 application. public class UnityControllerFactory : DefaultControllerFactory { IUnityContainer container; public UnityControllerFactory(IUnityContainer container) {     this.container = container; } protected override IController GetControllerInstance(RequestContext reqContext, Type controllerType) {     IController controller;     if (controllerType == null)         throw new HttpException(                 404, String.Format(                     "The controller for path '{0}' could not be found" +     "or it does not implement IController.",                 reqContext.HttpContext.Request.Path));       if (!typeof(IController).IsAssignableFrom(controllerType))         throw new ArgumentException(                 string.Format(                     "Type requested is not a controller: {0}",                     controllerType.Name),                     "controllerType");     try     {         controller= container.Resolve(controllerType) as IController;     }     catch (Exception ex)     {         throw new InvalidOperationException(String.Format(                                 "Error resolving controller {0}",                                 controllerType.Name), ex);     }     return controller; }   }   Configure contract and concrete types in Unity Let’s configure our contract and concrete types in Unity for resolving our dependencies.   private void ConfigureUnity() {     //Create UnityContainer               IUnityContainer container = new UnityContainer()                 .RegisterType<IDatabaseFactory, DatabaseFactory>(new HttpContextLifetimeManager<IDatabaseFactory>())     .RegisterType<IUnitOfWork, UnitOfWork>(new HttpContextLifetimeManager<IUnitOfWork>())     .RegisterType<ICategoryRepository, CategoryRepository>(new HttpContextLifetimeManager<ICategoryRepository>());                 //Set container for Controller Factory                ControllerBuilder.Current.SetControllerFactory(             new UnityControllerFactory(container)); }   In the above ConfigureUnity method, we are registering our types onto Unity container with custom lifetime manager HttpContextLifetimeManager. Let’s call ConfigureUnity method in the Global.asax.cs for set controller factory for Unity and configuring the types with Unity.   protected void Application_Start() {     AreaRegistration.RegisterAllAreas();     RegisterGlobalFilters(GlobalFilters.Filters);     RegisterRoutes(RouteTable.Routes);     ConfigureUnity(); }   Developing web application using ASP.NET MVC 3 We have created our domain model for our web application and also have created repositories and configured dependencies with Unity container. Now we have to create controller classes and views for doing CRUD operations against the Category entity. Let’s create controller class for Category Category Controller   public class CategoryController : Controller {     private readonly ICategoryRepository categoryRepository;     private readonly IUnitOfWork unitOfWork;           public CategoryController(ICategoryRepository categoryRepository, IUnitOfWork unitOfWork)     {         this.categoryRepository = categoryRepository;         this.unitOfWork = unitOfWork;     }       public ActionResult Index()     {         var categories = categoryRepository.All();         return View(categories);     }     [HttpGet]     public ActionResult Edit(int id)     {         var category = categoryRepository.GetById(id);         return View(category);     }       [HttpPost]     public ActionResult Edit(int id, FormCollection collection)     {         var category = categoryRepository.GetById(id);         if (TryUpdateModel(category))         {             unitOfWork.Commit();             return RedirectToAction("Index");         }         else return View(category);                 }       [HttpGet]     public ActionResult Create()     {         var category = new Category();         return View(category);     }           [HttpPost]     public ActionResult Create(Category category)     {         if (!ModelState.IsValid)         {             return View("Create", category);         }                     categoryRepository.Add(category);         unitOfWork.Commit();         return RedirectToAction("Index");     }       [HttpPost]     public ActionResult Delete(int  id)     {         var category = categoryRepository.GetById(id);         categoryRepository.Delete(category);         unitOfWork.Commit();         var categories = categoryRepository.All();         return PartialView("CategoryList", categories);       }        }   Creating Views in Razor Now we are going to create views in Razor for our ASP.NET MVC 3 application.  Let’s create a partial view CategoryList.cshtml for listing category information and providing link for Edit and Delete operations. CategoryList.cshtml @using MyFinance.Helpers; @using MyFinance.Domain; @model IEnumerable<Category>      <table>         <tr>         <th>Actions</th>         <th>Name</th>          <th>Description</th>         </tr>     @foreach (var item in Model) {             <tr>             <td>                 @Html.ActionLink("Edit", "Edit",new { id = item.CategoryId })                 @Ajax.ActionLink("Delete", "Delete", new { id = item.CategoryId }, new AjaxOptions { Confirm = "Delete Expense?", HttpMethod = "Post", UpdateTargetId = "divCategoryList" })                           </td>             <td>                 @item.Name             </td>             <td>                 @item.Description             </td>         </tr>          }       </table>     <p>         @Html.ActionLink("Create New", "Create")     </p> The delete link is providing Ajax functionality using the Ajax.ActionLink. This will call an Ajax request for Delete action method in the CategoryCotroller class. In the Delete action method, it will return Partial View CategoryList after deleting the record. We are using CategoryList view for the Ajax functionality and also for Index view using for displaying list of category information. Let’s create Index view using partial view CategoryList  Index.chtml @model IEnumerable<MyFinance.Domain.Category> @{     ViewBag.Title = "Index"; }    <h2>Category List</h2>    <script src="@Url.Content("~/Scripts/jquery.unobtrusive-ajax.min.js")" type="text/javascript"></script>    <div id="divCategoryList">               @Html.Partial("CategoryList", Model) </div>   We can call the partial views using Html.Partial helper method. Now we are going to create View pages for insert and update functionality for the Category. Both view pages are sharing common user interface for entering the category information. So I want to create an EditorTemplate for the Category information. We have to create the EditorTemplate with the same name of entity object so that we can refer it on view pages using @Html.EditorFor(model => model) . So let’s create template with name Category. Let’s create view page for insert Category information   @model MyFinance.Domain.Category   @{     ViewBag.Title = "Save"; }   <h2>Create</h2>   <script src="@Url.Content("~/Scripts/jquery.validate.min.js")" type="text/javascript"></script> <script src="@Url.Content("~/Scripts/jquery.validate.unobtrusive.min.js")" type="text/javascript"></script>   @using (Html.BeginForm()) {     @Html.ValidationSummary(true)     <fieldset>         <legend>Category</legend>                @Html.EditorFor(model => model)               <p>             <input type="submit" value="Create" />         </p>     </fieldset> }   <div>     @Html.ActionLink("Back to List", "Index") </div> ViewStart file In Razor views, we can add a file named _viewstart.cshtml in the views directory  and this will be shared among the all views with in the Views directory. The below code in the _viewstart.cshtml, sets the Layout page for every Views in the Views folder.      @{     Layout = "~/Views/Shared/_Layout.cshtml"; }   Source Code You can download the source code from http://efmvc.codeplex.com/ . The source will be refactored on over time.   Summary In this post, we have created a simple web application using ASP.NET MVC 3 and EF Code First. We have discussed on technologies and practices such as ASP.NET MVC 3, Razor, EF Code First, Unity 2, generic Repository and Unit of Work. In my later posts, I will modify the application and will be discussed on more things. Stay tuned to my blog  for more posts on step by step application building.

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