How do I write this URL in Django?
- by alex
(r'^/(?P<the_param>[a-zA-z0-9_-]+)/$','myproject.myapp.views.myview'),
How can I change this so that "the_param" accepts a URL(encoded) as a parameter?
So, I want to pass a URL to it.
mydomain.com/http%3A//google.com