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  • How do I force a Coldfusion cfc to output numeric data over JSON as a string?

    - by Dan Sorensen
    I'm calling a Coldfusion component (cfc) using jQuery.post(). I need an integer or string representation of the number returned for use in a URL. {"PAGE":"My Page Title","ID":19382} or {"PAGE":"My Page Title","ID":"19382"} Instead what I get back is a decimal: {"PAGE":"My Page Title","ID":19382.0} Needed to update the following HTML: <a href="page.cfm?id=19382" id="pagelink">My Page Title</a> Conceptually, I suppose there are multiple answers: 1) I could use jQuery to grab the number left of the decimal point. 2) I could force Coldfusion to send the number as a string. 3) I could generate the whole link server side and just replace the whole link tag HTML (not the preferred answer, but maybe it is the best) Does anyone know how to do 1 or 2? Is 3 better? Relevant Javascript: (Not optimized) $(".link").live('click', function () { var $linkID, serviceUrl; serviceUrl = "mycfc.cfc?method=getPage"; $linkID = $(this).attr("rel"); $.post(serviceUrl, { linkid: $linkID }, function (result) { $('#pagelink').val(result.TITLE); if (result.FMKEY.length) { // NEED the ID number WITHOUT the .0 at the end $('#pagelink').attr("href") = "page.cfm?id=" + result.ID; $('#pagelink').text(result.TITLE); } }, "json"); }); My CFC: <component output="no"> <cfsetting showdebugoutput="no"> <cffunction name="getPage" access="remote" returnFormat="JSON" output="no" hint="Looks up a Page Title and ID"> <cfargument name="linkID" type="string" required="yes"> <cfset var page = queryNew("id,title")> <cfset var result = structNew()> <cfquery datasource="myDatasource" name="page"> SELECT TOP 1 id, title FROM pages WHERE linkID = <cfqueryparam cfsqltype="cf_sql_integer" value="#arguments.linkID#"> </cfquery> <cfif page.recordcount> <cfset result.id = page.id> <cfset result.title = page.title> </cfif> <cfreturn result> </cffunction> </component>

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  • How to display the output of command which run in machine Y.and program is written in machine X?

    - by Rahul
    *I have two Linux Machine,1st is machine X ,other is machine Y i want to write a java program which will run in machine X..eq test.java ..and when i run that java program it should ask for login credential of machine Y and will execute some command for example ls -l in machine Y automatically after login. and it should display the output of ls -l in machine X. How to do it please help me????*

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  • php function output ina table row... how?

    - by user352868
    I want to run this function but show the result in a table row strlen($cat_row['sms'] This is what i came up with but it is not working: echo "<tr><td bgcolor=#626E7A>".**strlen($cat_row['cars']**."</td></tr>"; How do you show result of a php function in a table row? i am trying to format the output some how. please help

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  • How do I output installation status using gtk in c?

    - by Runner
    int main( int argc, char *argv[] ) { GtkWidget *window; gtk_init (&argc, &argv); window = gtk_window_new (GTK_WINDOW_TOPLEVEL); gtk_widget_show (window); gtk_main (); return 0; } The above is just a empty winform,I want to output dynamic information in it(not editable), how should I do that?

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  • having an issue about the output in c programming ..

    - by user2985811
    i'm having a problem on running the output after putting the input.. the output doesn't show after i put the variables and i don't know how to set the code .. so if you guys could help me with this, that would be grateful.. #include <stdio.h> #include <conio.h> int read_temps (float temps[]); int hot_days (int numOfTemp, float temps[]); int printf_temps (int numOfTemp, float temps[], int numOfHotDays); int main (void) { int index = 0; float tempVal; float temps[31]; int numOfTemp, numOfHotDays; do { printf ("Enter the temperature:"); scanf ("%f", &tempVal); if (tempVal!=-500.0) { temps[index] = tempVal; index++; } } while (tempVal != -500.0); return ; { int i; int count = 0; for (i = 0; i < numOfTemp; i++) { if (temps[i] > 32.0) count++; } return count; } { float sum = 0.0; int i; printf ("\nInput Temperatures:"); printf ("\n-------------------------"); for (i = 0;i < numOfTemp; i++) { printf ("\nDay %d : %.2fF", i+1, temps[i]); sum = sum + temps[i]; } printf ("\nNumber of Hot Days : %d", numOfHotDays); printf ("\nAverage Temperature: %.2f", sum/numOfTemp); } { clrscr (); numOfTemp = read_temps (temps); numOfHotDays = hot_days (numOfTemp, temps); clrscr (); printf_temps (numOfTemp, temps, numOfHotDays); getch (); } }

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  • Sudden issues reading uncompressed video using opencv

    - by JohnSavage
    I have been using a particular pipeline to process video using opencv to encode uncompressed video (fourcc = 0), and opencv python bindings to then open and work on these files. This has been working fine for me on OpenCV 2.3.1a on Ubuntu 11.10 until just a few days ago. For some reason it currently is only allowing me to read the first frame of a given file the first time I open that file. Further frames are not read, and once I touch the file once with my program, it then cannot even read the first frame. More detail: I created the uncompressed video files as follows: out_video.open(out_vid_name, 0, // FOURCC = 0 means record raw fps, Size(640, 480)) Again, these videos worked fine for me until about a week ago. Now, when I try to open one of these I get the following message (from what I think is ffmpeg): Processing video.avi Using network protocols without global network initialization. Please use avformat_network_init(), this will become mandatory later. [avi @ 0x29251e0] parser not found for codec rawvideo, packets or times may be invalid. It reads and displays the first frame fine, but then fails to read the next frame. Then, when I try to run my code on the same video, the capture still opens with the same message as above. However, it cannot even read the very first frame. Here is the code to open the capture: self.capture = cv2.VideoCapture(filename) if not self.capture.isOpened() print "Error: could not open capture" sys.exit() Again, this part is passed without any issue, but then the break happens at: success, rgb = self.capture.read() if not success: print "error: could not read frame" return False This part breaks at the second frame on the first run of the video file, and then on the first frame on subsequent runs. I really don't know where to even begin debugging this. Please help!

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  • How to html encode the output of an NHaml view (or any MVC view)?

    - by jessegavin
    I have several views written in NHaml that I would like to render as encoded html. Here's one. %table.data %thead %tr %th Country Name %th ISO 2 %th ISO 3 %th ISO # %tbody - foreach(var c in ViewData.Model.Countries) %tr %td =c.Name %td =c.Alpha2 %td =c.Alpha3 %td =c.Number I know that NHaml provides syntax to Html encode the output for given lines using &=. However, in order to encode the entire view, I would essentially lose the benefit of writing my view in NHaml since it would have to look like this.... &= "<table class='data'> &= " <thead> So I was wondering if there was any cool way to be able to capture the rendered view as a string, then to html encode that string. Maybe something like the following??? public ContentResult HtmlTable(string format) { var m = new CountryViewModel(); m.Countries = _countryService.GetAll(); // Somehow render the view and store it as a string? // Not sure how to achieve this. var viewHtml = View("HtmlTable", m); // ??? return Content(viewHtml); } This question may actually have no particular relevance to the View engine that I am using I guess. Any help or thoughts would be appreciated.

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  • Creating 1 page PDF of iPad Screen view - How?

    - by user314695
    Hi All, I've asked this question on a couple other forums and have had zero response, so I'm hoping someone here can help point me in the right direction. I have a pretty simple one screen application for my work. It's basically just a recreation of a 1 page paper report that has a company logo, some labels, a few text boxes and a scroll text box for the report. I need to be able to fill out the report then click a button to save it in a graphical form so I can fax, print or email it later. Currently, I'm just programmatically taking a screen capture and saving it to the photo's library (default for screen capture). Then I can just email it from photo's. This works ok, but is kind of hacky, at best. I've read through the new iPad 3.2 guide for creating PDF's (apparently it's supposed to be much easier than before) but I can not get it to work and I've spent countless hours on it now. I'm hoping someone has the answer for me. Alternatively, if anyone knows how I can redirect where the screen capture is stored (default is in the photo album) then maybe I can make that function work. If I could redirect the screen capture to store in my applications document folder, then I can use MFMailCompose to attach it to an email. Lastly, on a side note, does anyone know of a good way to capture a digital signature via touch. For instance, I'd love to have my users be able to just sign their name via touch at the bottom of the document before I convert to PDF or take a screen capture. Thanks in advance for your help. -Ray

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  • Unix sort keys cause performance problems

    - by KenFar
    My data: It's a 71 MB file with 1.5 million rows. It has 6 fields All six fields combine to form a unique key - so that's what I need to sort on. Sort statement: sort -t ',' -k1,1 -k2,2 -k3,3 -k4,4 -k5,5 -k6,6 -o output.csv input.csv The problem: If I sort without keys, it takes 30 seconds. If I sort with keys, it takes 660 seconds. I need to sort with keys to keep this generic and useful for other files that have non-key fields as well. The 30 second timing is fine, but the 660 is a killer. More details using unix time: sort input.csv -o output.csv = 28 seconds sort -t ',' -k1 input.csv -o output.csv = 28 seconds sort -t ',' -k1,1 input.csv -o output.csv = 64 seconds sort -t ',' -k1,1 -k2,2 input.csv -o output.csv = 194 seconds sort -t ',' -k1,1 -k2,2 -k3,3 input.csv -o output.csv = 328 seconds sort -t ',' -k1,1 -k2,2 -k3,3 -k4,4 input.csv -o output.csv = 483 seconds sort -t ',' -k1,1 -k2,2 -k3,3 -k4,4 -k5,5 input.csv -o output.csv = 561 seconds sort -t ',' -k1,1 -k2,2 -k3,3 -k4,4 -k5,5 -k6,6 input.csv -o output.csv = 660 seconds I could theoretically move the temp directory to SSD, and/or split the file into 4 parts, sort them separately (in parallel) then merge the results, etc. But I'm hoping for something simpler since looks like sort is just picking a bad algorithm. Any suggestions? Testing Improvements using buffer-size: With 2 keys I got a 5% improvement with 8, 20, 24 MB and best performance of 8% improvement with 16MB, but 6% worse with 128MB With 6 keys I got a 5% improvement with 8, 20, 24 MB and best performance of 9% improvement with 16MB. Testing improvements using dictionary order (just 1 run each): sort -d --buffer-size=8M -t ',' -k1,1 -k2,2 input.csv -o output.csv = 235 seconds (21% worse) sort -d --buffer-size=8M -t ',' -k1,1 -k2,2 input.csv -o ouput.csv = 232 seconds (21% worse) conclusion: it makes sense that this would slow the process down, not useful Testing with different file system on SSD - I can't do this on this server now. Testing with code to consolidate adjacent keys: def consolidate_keys(key_fields, key_types): """ Inputs: - key_fields - a list of numbers in quotes: ['1','2','3'] - key_types - a list of types of the key_fields: ['integer','string','integer'] Outputs: - key_fields - a consolidated list: ['1,2','3'] - key_types - a list of types of the consolidated list: ['string','integer'] """ assert(len(key_fields) == len(key_types)) def get_min(val): vals = val.split(',') assert(len(vals) <= 2) return vals[0] def get_max(val): vals = val.split(',') assert(len(vals) <= 2) return vals[len(vals)-1] i = 0 while True: try: if ( (int(get_max(key_fields[i])) + 1) == int(key_fields[i+1]) and key_types[i] == key_types[i+1]): key_fields[i] = '%s,%s' % (get_min(key_fields[i]), key_fields[i+1]) key_types[i] = key_types[i] key_fields.pop(i+1) key_types.pop(i+1) continue i = i+1 except IndexError: break # last entry return key_fields, key_types While this code is just a work-around that'll only apply to cases in which I've got a contiguous set of keys - it speeds up the code by 95% in my worst case scenario.

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