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  • Hibernate database integrity with multiple java applications

    - by Austen
    We have 2 java web apps both are read/write and 3 standalone java read/write applications (one loads questions via email, one processes an xml feed, one sends email to subscribers) all use hibernate and share a common code base. The problem we have recently come across is that questions loaded via email sometimes overwrite questions created in one of the web apps. We originally thought this to be a caching issue. We've tried turning off the second level cache, but this doesn't make a difference. We are not explicitly opening and closing sessions, but rather let hibernate manage them via Util.getSessionFactory().getCurrentSession(), which thinking about it, may actually be the issue. We'd rather not setup a clustered 2nd level cache at this stage as this creates another layer of complexity and we're more than happy with the level of performance we get from the app as a whole. So does implementing a open-session-in-view pattern in the web apps and manually managing the sessions in the standalone apps sound like it would fix this? Or any other suggestions/ideas please? <property name="hibernate.transaction.factory_class">org.hibernate.transaction.JDBCTransactionFactory</property> <property name="hibernate.current_session_context_class">thread</property> <property name="hibernate.cache.use_second_level_cache">false</property>

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  • How do I set a flash object to open a url in a new window?

    - by Keith Donegan
    Hi Guys, I have this code: <object classid="clsid:D27CDB6E-AE6D-11cf-96B8-444553540000" codebase="http://download.macromedia.com/pub/shockwave/cabs/flash/swflash.cab#version=9,0,28,0" width="300" height="250"> <param name="movie" value="Spotify_premium_300x250.swf" /> <param name="quality" value="high" /> <embed src="Spotify_premium_300x250.swf" quality="high" pluginspage="http://www.adobe.com/shockwave/download/download.cgi?P1_Prod_Version=ShockwaveFlash" type="application/x-shockwave-flash" width="300" height="250"></embed> </object> EDIT: Code from Tom <object onclick="javascript: window.open('http://www.stackoverflow.com', _blank, 'width=1024, height=600, menubar=no, resizable=yes');" classid="clsid:D27CDB6E-AE6D-11cf-96B8-444553540000" codebase="http://download.macromedia.com/pub/shockwave/cabs/flash/swflash.cab#version=9,0,28,0" width="300" height="250"> <param name="movie" value="Spotify_premium_300x250.swf" /> <param name="quality" value="high" /> <embed src="Spotify_premium_300x250.swf" quality="high" pluginspage="http://www.adobe.com/shockwave/download/download.cgi?P1_Prod_Version=ShockwaveFlash" type="application/x-shockwave-flash" width="300" height="250"></embed> </object> I would like it as when a user clicks the flash object, it's opens a URL in a new window. How would I go about doing this? Cheers, Keith

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  • Auto complete from database using CodeIgniter (Active Record)

    - by Ralph David Abernathy
    I have a form on my website in which one is able to submit a cat. The form contains inputs such as "Name" and "Gender", but I am just trying to get the auto completion to work with the "Name" field. Here is what my jquery looks like : $(document).ready(function() { $( "#tags" ).autocomplete({ source: '/Anish/auto_cat' }); }); Here is what my model looks like: public function auto_cat($search_term) { $this->db->like('name', $search_term); $response = $this->db->get('anish_cats')->result_array(); // var_dump($response);die; return $response; } } Here is my controller: public function auto_cat(){ $search_term = $this->input->get('term'); $cats = $this->Anish_m->auto_cat($search_term); } And here is my view: <head> <link rel="stylesheet" href="http://code.jquery.com/ui/1.10.3/themes/smoothness/jquery-ui.css" /> <script src="http://code.jquery.com/jquery-1.9.1.js"></script> <script src="http://code.jquery.com/ui/1.10.3/jquery-ui.js"></script> <link rel="stylesheet" href="/resources/demos/style.css" /> </head> <h1>Anish's Page</h1> <form action="/Anish/create" method="POST"> <div class="ui-widget"> <label for="tags">Name</label><input id="tags" type="text" name="name"> </div> <div> <label>Age</label><input type="text" name="age"> </div> <div> <label>Gender</label><input type="text" name="gender"> </div> <div> <label>Species</label><input type="text" name="species"> </div> <div> <label>Eye Color</label><input type="text" name="eye_color"> </div> <div> <label>Color</label><input type="text" name="color"> </div> <div> <label>Description</label><input type="text" name="description"> </div> <div> <label>marital status</label><input type="text" name="marital_status"> </div> <br> <button type="submit" class="btn btn-block btn-primary span1">Add cat</button> </form> <br/><br/><br/><br/> <table class="table table-striped table-bordered table-hover"> <thead> <tr> <th>Name</th> <th>Gender</th> <th>Age</th> <th>Species</th> <th>Eye Color</th> <th>Color</th> <th>Description</th> <th>Marital Status</th> <th>Edit</th> <th>Delete</th> </tr> </thead> <tbody> <?php foreach ($cats as $cat):?> <tr> <td> <?php echo ($cat['name']);?><br/> </td> <td> <?php echo ($cat['gender']);?><br/> </td> <td> <?php echo ($cat['age']);?><br/> </td> <td> <?php echo ($cat['species']);?><br/> </td> <td> <?php echo ($cat['eye_color']);?><br/> </td> <td> <?php echo ($cat['color']);?><br/> </td> <td> <?php echo ($cat['description']);?><br/> </td> <td> <?php echo ($cat['marital_status']);?><br/> </td> <td> <form action="/Anish/edit" method="post"> <input type="hidden" value="<?php echo ($cat['id']);?>" name="Anish_id_edit"> <button class="btn btn-block btn-info">Edit</button> </form> </td> <td> <form action="/Anish/delete" method="post"> <input type="hidden" value="<?php echo ($cat['id']);?>" name="Anish_id"> <button class="btn btn-block btn-danger">Delete</button> </form> </td> </tr> <?php endforeach;?> </tbody> </table> I am stuck. In my console, I am able to see this output when I type the letter 'a' if I uncomment the var_dump in my model: array(4) { [0]=> array(9) { ["id"]=> string(2) "13" ["name"]=> string(5) "Anish" ["gender"]=> string(4) "Male" ["age"]=> string(2) "20" ["species"]=> string(3) "Cat" ["eye_color"]=> string(5) "Brown" ["color"]=> string(5) "Black" ["description"]=> string(7) "Awesome" ["marital_status"]=> string(1) "0" } [1]=> array(9) { ["id"]=> string(2) "16" ["name"]=> string(5) "Anish" ["gender"]=> string(2) "fe" ["age"]=> string(2) "23" ["species"]=> string(2) "fe" ["eye_color"]=> string(2) "fe" ["color"]=> string(2) "fe" ["description"]=> string(2) "fe" ["marital_status"]=> string(1) "1" } [2]=> array(9) { ["id"]=> string(2) "17" ["name"]=> string(1) "a" ["gender"]=> string(1) "a" ["age"]=> string(1) "4" ["species"]=> string(1) "a" ["eye_color"]=> string(1) "a" ["color"]=> string(1) "a" ["description"]=> string(1) "a" ["marital_status"]=> string(1) "0" } [3]=> array(9) { ["id"]=> string(2) "18" ["name"]=> string(4) "Matt" ["gender"]=> string(6) "Female" ["age"]=> string(2) "80" ["species"]=> string(6) "ferret" ["eye_color"]=> string(4) "blue" ["color"]=> string(4) "pink" ["description"]=> string(5) "Chill" ["marital_status"]=> string(1) "0" } }

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  • Optimal way to generate list of PHP object properties with delimiter character, implode()?

    - by Kris
    I am trying to find out if there is a more optimal way for creating a list of an object's sub object's properties. (Apologies for the crude wording, I am not really much of an OO expert) I have an object "event" that has a collection of "artists", each artist having an "artist_name". On my HTML output, I want a plain list of artist names delimited by a comma. PHP's implode() seems to be the best way to create a comma delimited list of values. I am currently iterating through the object and push values in a temporary array "artistlist" so I can use implode(). That is the shortest I could come up with. Is there a way to do this more elegant? $artistlist = array(); foreach ($event->artists as $artist) { $artistlist[] = $artist->artist_name; } echo implode(', ', $artistlist);

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  • How to implement Auto_Increment per User, on the same table?

    - by Jonas
    I would like to have multiple users that share the same tables in the database, but have one auto_increment value per user. I will use an embedded database, JavaDB and as what I know it doesn't support this functionality. How can I implement it? Should I implement a trigger on inserts that lookup the users last inserted row, and then add one, or are there any better alternative? Or is it better to implement this in the application code? Or is this just a bad idea? I think this is easier to maintain than creating new tables for every user. Example: table +----+-------------+---------+------+ | ID | ID_PER_USER | USER_ID | DATA | +----+-------------+---------+------+ | 1 | 1 | 2 | 3454 | | 2 | 2 | 2 | 6567 | | 3 | 1 | 3 | 6788 | | 4 | 3 | 2 | 1133 | | 5 | 4 | 2 | 4534 | | 6 | 2 | 3 | 4366 | | 7 | 3 | 3 | 7887 | +----+-------------+---------+------+ SELECT * FROM table WHERE USER_ID = 3 +----+-------------+---------+------+ | ID | ID_PER_USER | USER_ID | DATA | +----+-------------+---------+------+ | 3 | 1 | 3 | 6788 | | 6 | 2 | 3 | 4366 | | 7 | 3 | 3 | 7887 | +----+-------------+---------+------+ SELECT * FROM table WHERE USER_ID = 2 +----+-------------+---------+------+ | ID | ID_PER_USER | USER_ID | DATA | +----+-------------+---------+------+ | 1 | 1 | 2 | 3454 | | 2 | 2 | 2 | 6567 | | 4 | 3 | 2 | 1133 | | 5 | 4 | 2 | 4534 | +----+-------------+---------+------+

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  • database structure

    - by jindalsyogesh
    I have a table named ActivityRecording. This table currently has 500,000 records. I need to add a lot of new inputs that relates to activityrecording table. The relation of activityrecording with these new input fields is 1 to 0,1. So, what's going to happen on screen is when user fills the ActivityRecording data, he will then be taken to a new page and this page will show a form based on the user's input (from a dropdown named service) in activityrecording. There will 6 different kinds of form (each form will have 7-8 inputs which includes textareas of size 5kb, textboxes and checkboxes). So, for one activityrecording user will fill one out of 6 forms. There are two ways I know (there could be more), I can design the data structure: Add all the inputs from all these 6 forms into the activityrecording table. So, columns belonging to 5 of these forms will be null in this table, only columns belonging to one of the forms will have values The other way would be add 6 new tables (one for each form) and add 6 foreign key columns to activityrecording table. So, out of 6 foreign keys, 5 will be null and one will actually point to a table Which approach is a better data structure design? Please take into consideration that number of rows in this table are 500,000 and are expected to grow at a faster rate now.

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  • Rails: Auto-Detecting Database Adapter

    - by Dex
    The new version of the ar-extensions gem requires that you load the appropriate adapter yourself. On my development side I use mysql, however Heroku uses PostgreSQL. For example, on my development side I need to do this: require 'ar-extensions/adapters/mysql' require 'ar-extensions/import/mysql' How can I audo-detect which adapter to use?

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  • How to virtually delete data from multiple tables that are linked by a foreign key ?

    - by Shantanu Gupta
    I am using Sql Server 2005 This is a part of my database diagram. I want to perform deletion on my database which will start from tblDomain up tp tblSubTopics. Consider that each table has IsDeleted column which has to be marked true if request was made to delete data. But that data shoud remain their physically. Tables which will have IsDeleted Column are tblDomain tblSubject tblTopic tblSubTopic Now I want, if a user marks one domain as deleted then all the refrence field should also get marked as deleted. i.e. 1 domain is related to 5 subjects, those 5 subjects are related to 25 topics, those 25 topics are related to 500 subtopics and so on. Then how should i mark all these fileds as Deleted. ?

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  • php java in memory database

    - by msaif
    i need to load data as array to memory in PHP.but in PHP if i write $array= array("1","2"); in test.php then this $array variable is initialized every time user requests.if we request test.php 100 times by clicking 100 times browser refresh button then this $array variable will be executed 100 times. but i need to execute the $array variable only one time for first time request and subsequent request of test.php must not execute the $array variable.but only use that memory location.how can i do that in PHP. but in JAVA SEVRVLET it is easy to execute,just write the $array variable in one time execution of init() method of servlet lifecycle method and subsequent request of that servlet dont execute init() method but service() method but service() method always uses that $array memeory location. all i want to initilize $array variable once but use that memory loc from subsequent request in PHP.is there any possiblity in PHP?

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  • Database storage for high sample rate data in web app

    - by Jim
    I've got multiple sensors feeding data to my web app. Each channel is 5 samples per second and the data gets uploaded bundled together in 1 minute json messages (containing 300 samples). The data will be graphed using flot at multiple zoom levels from 1 day to 1 minute. I'm using Amazon SimpleDB and I'm currently storing the data in the 1 minute chunks that I receive it in. This works well for high zoom levels, but for full days there will be simply be too many rows to retrieve. The idea I've currently got is that every hour I can crawl through the data and collect together 300 samples for the last hour and store them in an hour Domain (table if you like). Does this sound like a reasonable solution? How have others implemented the same sort of systems?

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  • How do you test a command object in a grails controller integration test?

    - by egervari
    I'm new to grails. How do I test a form command object to make sure that it's working? Here's some setup code in a test. When I try to do it, I get the following exceptions: Error occurred creating command object. org.codehaus.groovy.grails.web.servlet.mvc.exceptions.ControllerExecutionException: Error occurred creating command object. at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method) .... Caused by: groovy.lang.MissingPropertyException: No such property: password for class: project.user.RegistrationForm Possible solutions: password Here is my test case. As you can see, I set "password" on the params map... void testSaveWhenDataIsCorrect() { controller.params.emailAddress = "[email protected]" controller.params.password = "secret" controller.params.confirmPassword = "secret" controller.save() assertEquals "success", redirectArgs.view ... } Here's the controller action, that adds the command object as a closure parameter: def save = { RegistrationForm form -> if(form.hasErrors()) { render view: "create", model: [form: form] } else { def user = new User(form.properties) user.password = form.encryptedPassword if(user.save()) { redirect(action: "success") } else { render view: "create", model: [form: form] } } } Here's the command object itself... and note that it DOES have a "password" field... class RegistrationForm { def springSecurityService String emailAddress String password String confirmPassword String getEncryptedPassword() { springSecurityService.encodePassword(password) } static constraints = { emailAddress(blank: false, email: true) password(blank: false, size:4..10) confirmPassword(blank: false, validator: { password != confirmPassword }) } } I'm totally lost in the non-intuitive way to do controllers... Please help.

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  • DataSet v/s Database

    - by Hemanshu Bhojak
    While designing applications it is a very good practice to have all the business logic in one place. So why then we sometimes have the business logic in stored procs? Can we fetch all data from the DB and store it in a DataSet and then process it? What would be the performance of the app in this scenario?

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  • Recreation of DB using "mysql mydb < mydb.sql" is really slow when the table has tens of millions of

    - by Jian Lin
    It seems that a MySQL database that has a table with tens of millions of records will get a big INSERT INTO statement when the following mysqldump some_db > some_db.sql is done to back up the database. (is it 1 insert statement that handles all the records?) So when reconstructing the DB using mysql some_db < some_db.sql then the CPU is hardly busy (about 1.8% usage by the mysql process... I don't see a mysqld either?) and also the hard disk doesn't seem to be too busy... Last time, the whole restore process took 5 hours. Is there a way to make it faster? Such as, when doing mysqldump, can it break the INSERT statement into shorter ones, so that the mysql doesn't need to parse the line so hard when restoring the DB?

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  • Database design: Using hundred of fields for little values

    - by user964260
    I'm planning to develop a PHP Web App, it will mainly be used by registered users(sessions) While thinking about the DB design, I was contemplating that in order to give the best user experience possible there would be lots of options for the user to activate, deactivate, specify, etc. For example: - Options for each layout elements, dialog boxes, dashboard, grid, etc. - color, size, stay visible, invisible, don't ask again, show everytime, advanced mode, simple mode, etc. This would get like 100s of fields ranging from simple Yes/No or 1 to N values..., for each user. So, is it having a field for each of these options the way to go? or how do those CRMs or CMS or other Web Apps do it to store lots of 1-2 char long values? Do they group them on Text fields separated by a special char and then "explode" them as an array for runtime usage? thank you

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  • Database strucure for versioning and multiple languages

    - by phobia
    Hi, I'm wondering how to best solve the issue of content existing in multiple versions and multiple languages. An image of my current structure can be seen here: http://i46.tinypic.com/72fx3k.png Each content can only have one active version in each language, and that's how I'm curious on how to best solve. Right now I have a column of the contentversions table, which means for each change of active version I have to run a update and set active=false on all version and then a update to set active=true for the piece of content in question. Any thoughts? :)

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  • ASP.Net 4.0 Database Created Pages

    - by Tyler
    I want to create asp.net 4.0 dynamic pages loaded from my MS SQL server. Basically, its a list of locations with informations. For example: Location1 would have the page www.site.com/location/location1.aspx Location44 would have the page www.site.com/location/location44.aspx I dont even know where to start with this, url writting maybe?

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  • Ruby on Rails and database associations

    - by Marco
    Hi to all, I'm new to the Ruby world, and there is something unclear to me in defining associations between models. The question is: where is the association saved? For example, if i create a Customer model by executing: generate model Customer name:string age:integer and then i create an Order model generate model Order description:text quantity:integer and then i set the association in the following way: class Customer < ActiveRecord::Base has_many :orders end class Order < ActiveRecord::Base belongs_to :customer end I think here is missing something, for example the foreign key between the two entities. How does it handle the associations created with the keywords "has_many" and "belongs_to" ? Thanks

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  • PHP - Select from database the same query

    - by How to PHP
    I created a table that contains the name of the user and his job, and created PHP page that shows me all the users that works doctor, I entered doctor into a variable then I selected from the table where Jobs equal to $doctor, that is great, but I need it to get the same Jobs into a table in the page and the other same jobs into a table in the same page. this is my code that shows only the users works doctor in one table, <html> <h1>Doctors</h1> </html> <?php mysql_connect('localhost','root',''); mysql_select_db('data'); $doctor='doctor'; $query= mysql_query("SELECT * FROM `users` WHERE `job` = '$doctor'")or die(mysql_error()); while ($arr = mysql_fetch_array($query)) $name= $arr['name']; echo $name; } ?> That shows me doctors when I put doctor in a variable I want to show all same Jobs in a table. Is there is a way to do this? Thanks :)

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