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  • Clarification of the difference between PCI memory addressing and I/O addressing?

    - by KevinM
    Could someone please clarify the difference between memory and I/O addresses on the PCI/PCIe bus? I understand that I/O addresses are 32-bit, limited to the range 0 to 4GB, and do not map onto system memory (RAM), and that memory addresses are either 32-bit or 64-bit. I get the impression that memory addressing must map onto available RAM, is this true? That if a PCI device wishes to transfer data to a memory address, that address must exist in actual system RAM (and is allocated during PCI configuration) and not virtual memory. So if a PCI device only needs to transfer a small amount of data at a time, where there is no advantage to putting it into RAM or using DMA, then I/O addressing is fine (e.g. a parallel port implemented on a PCI card). And why do I keep reading that PCI/PCIe I/O addressing is being deprecated in favour of memory addressing? Thanks!

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  • Portable VirtualBox with Ubuntu on two machines

    - by eactor
    I have VirtualBox Portable installed from vbox.me. I moved it on a USB drive and added a virtual Ubuntu. It works fine on the computer I created it, but moving the usb drive to a different the Ubuntu does not start any more. I already changed location descriptions in <machine>.vbox and the VirtualBox.xml. When pressing Shift while starting the GRUB loader comes up, so I tried the recovery mode. Same here – startup freezes and nothing happens. Any hints for me? Last to happen in log file: 00:00:54.986 Display::handleDisplayResize(): uScreenId = 0, pvVRAM=06aac000 w=640 h=480 bpp=32 cbLine=0xA00, flags=0x1 00:01:06.361 Display::handleDisplayResize(): uScreenId = 0, pvVRAM=00000000 w=720 h=400 bpp=0 cbLine=0x0, flags=0x1

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  • Restore open applications, documents, and window state

    - by rfeague
    When working on a project, I generally have a couple of Explorer windows open to relevant folders and a couple of applications (e.g. Eclipse and a form development tool) open to specific project-related documents. There's a lot of value in that context, and I'd like to find a way to save a set of open apps under a project name, then restore that state at a later date. Thus far all of the utilities I've found are virtual desktop products that don't save/restore state. I'm specifically looking for something that will run the applications I had running, open the documents I had open, and position the windows as they were. I'm amazed that such a seemingly simple concept as "Save my workspace state" doesn't seem to be available. I'm on Windows 7. Any suggestions?

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  • Queued Loadtest to remove Concurrency issues using Shared Data Service in OpenScript

    - by stefan.thieme(at)oracle.com
    Queued Processing to remove Concurrency issues in Loadtest ScriptsSome scripts act on information returned by the server, e.g. act on first item in the returned list of pending tasks/actions. This may lead to concurrency issues if the virtual users simulated in a load test scenario are not synchronized in some way.As the load test cases should be carried out in a comparable and straight forward manner simply cancel a transaction in case a collision occurs is clearly not an option. In case you increase the number of virtual users this approach would lead to a high number of requests for the early steps in your transaction (e.g. login, retrieve list of action points, assign an action point to the virtual user) but later steps would be rarely visited successfully or at all, depending on the application logic.A way to tackle this problem is to enqueue the virtual users in a Shared Data Service queue. Only the first virtual user in this queue will be allowed to carry out the critical steps (retrieve list of action points, assign an action point to the virtual user) in your transaction at any one time.Once a virtual user has passed the critical path it will dequeue himself from the head of the queue and continue with his actions. This does theoretically allow virtual users to run in parallel all steps of the transaction which are not part of the critical path.In practice it has been seen this is rarely the case, though it does not allow adding more than N users to perform a transaction without causing delays due to virtual users waiting in the queue. N being the time of the total transaction divided by the sum of the time of all critical steps in this transaction.While this problem can be circumvented by allowing multiple queues to act on individual segments of the list of actions, e.g. per country filter, ends with 0..9 filter, etc.This would require additional handling of these additional queues of slots for the virtual users at the head of the queue in order to maintain the mutually exclusive access to the first element in the list returned by the server at any one time of the load test. Such an improved handling of multiple queues and/or multiple slots is above the subject of this paper.Shared Data Services Pre-RequisitesStart WebLogic Server to host Shared Data ServicesYou will have to make sure that your WebLogic server is installed and started. Shared Data Services may not work if you installed only the minimal installation package for OpenScript. If however you installed the default package including OLT and OTM, you may follow the instructions below to start and verify WebLogic installation.To start the WebLogic Server deployed underneath of Oracle Load Testing and/or Oracle Test Manager you can go to your Start menu, Oracle Application Testing Suite and select the Restart Oracle Application Testing Suite Application Service entry from the Tools submenu.To verify the service has been started you can run the Microsoft Management Console for Services by Selecting Run from the Start Menu and entering services.msc. Look for the entry that reads Oracle Application Testing Suite Application Service, once it has changed it status from Starting to Started you can proceed to verify the login. Please note that this may take several minutes, I would say up to 10 minutes depending on the strength of your CPU horse-power.Verify WebLogic Server user credentialsYou will have to make sure that your WebLogic Server is installed and started. Next open the Oracle WebLogic Server Adminstration Console on http://localhost:8088/console.It may take a while until the application is deployed and started. It may display the following until the Administration Console has been deployed on the fly.Afterwards you can login using the username oats and the password that you selected during install time for your Application Testing Suite administrative purposes.This will bring up the Home page of you WebLogic Server. You have actually verified that you are able to login with these credentials already. However if you want to check the details, navigate to Security Realms, myrealm, Users and Groups tab.Here you could add users to your WebLogic Server which could be used in the later steps. Details on the Groups required for such a custom user to work are exceeding this quick overview and have to be selected with the WebLogic Server Adminstration Guide in mind.Shared Data Services pre-requisites for Load testingOpenScript Preferences have to be set to enable Encryption and provide a default Shared Data Service Connection for Playback.These are pre-requisites you want to use for load testing with Shared Data Services.Please note that the usage of the Connection Parameters (individual directive in the script) for Shared Data Services did not playback reliably in the current version 9.20.0370 of Oracle Load Testing (OLT) and encryption of credentials still seemed to be mandatory as well.General Encryption settingsSelect OpenScript Preferences from the View menu and navigate to the General, Encryption entry in the tree on the left. Select the Encrypt script data option from the list and enter the same password that you used for securing your WebLogic Server Administration Console.Enable global shared data access credentialsSelect OpenScript Preferences from the View menu and navigate to the Playback, Shared Data entry in the tree on the left. Enable the global shared data access credentials and enter the Address, User name and Password determined for your WebLogic Server to host Shared Data Services.Please note, that you may want to replace the localhost in Address with the hosts realname in case you plan to run load tests with Loadtest Agents running on remote systems.Queued Processing of TransactionsEnable Shared Data Services Module in Script PropertiesThe Shared Data Services Module has to be enabled for each Script that wants to employ the Shared Data Service Queue functionality in OpenScript. It can be enabled under the Script menu selecting Script Properties. On the Script Properties Dialog select the Modules section and check Shared Data to enable Shared Data Service Module for your script. Checking the Shared Data Services option will effectively add a line to your script code that adds the sharedData ScriptService to your script class of IteratingVUserScript.@ScriptService oracle.oats.scripting.modules.sharedData.api.SharedDataService sharedData;Record your scriptRecord your script as usual and then add the following things for Queue handling in the Initialize code block, before the first step and after the last step of your critical path and in the Finalize code block.The java code to be added at individual locations is explained in the following sections in full detail.Create a Shared Data Queue in InitializeTo create a Shared Data Queue go to the Java view of your script and enter the following statements to the initialize() code block.info("Create queueA with life time of 120 minutes");sharedData.createQueue("queueA", 120);This will create an instantiation of the Shared Data Queue object named queueA which is maintained for upto 120 minutes.If you want to use the code for multiple scripts, make sure to use a different queue name for each one here and in the subsequent steps. You may even consider to use a dynamic queueName based on filters of your result list being concurrently accessed.Prepare a unique id for each IterationIn order to keep track of individual virtual users in our queue we need to create a unique identifier from the virtual user id and the used username right after retrieving the next record from our databank file.getDatabank("Usernames").getNextDatabankRecord();getVariables().set("usernameValue1","VU_{{@vuid}}_{{@iterationnum}}_{{db.Usernames.Username}}_{{@timestamp}}_{{@random(10000)}}");String usernameValue = getVariables().get("usernameValue1");info("Now running virtual user " + usernameValue);As you can see from the above code block, we have set the OpenScript variable usernameValue1 to VU_{{@vuid}}_{{@iterationnum}}_{{db.Usernames.Username}}_{{@timestamp}}_{{@random(10000)}} which is a concatenation of the virtual user id and the iterationnumber for general uniqueness; as well as the username from our databank, the timestamp and a random number for making it further unique and ease spotting of errors.Not all of these fields are actually required to make it really unique, but adding the queue name may also be considered to help troubleshoot multiple queues.The value is then retrieved with the getVariables.get() method call and assigned to the usernameValue String used throughout the script.Please note that moving the getDatabank("Usernames").getNextDatabankRecord(); call to the initialize block was later considered to remove concurrency of multiple virtual users running with the same userid and therefor accessing the same "My Inbox" in step 6. This will effectively give each virtual user a userid from the databank file. Make sure you have enough userids to remove this second hurdle.Enqueue and attend Queue before Critical PathTo maintain the right order of virtual users being allowed into the critical path of the transaction the following pseudo step has to be added in front of the first critical step. In the case of this example this is right in front of the step where we retrieve the list of actions from which we select the first to be assigned to us.beginStep("[0] Waiting in the Queue", 0);{info("Enqueued virtual user " + usernameValue + " at the end of queueA");sharedData.offerLast("queueA", usernameValue);info("Wait until the user is the first in queueA");String queueValue1 = null;do {// we wait for at least 0.7 seconds before we check the head of the// queue. This is the time it takes one user to move through the// critical path, i.e. pass steps [5] Enter country and [6] Assign// to meThread.sleep(700);queueValue1 = (String) sharedData.peekFirst("queueA");info("The first user in queueA is currently: '" + queueValue1 + "' " + queueValue1.getClass() + " length " + queueValue1.length() );info("The current user is '"+ usernameValue + "' " + usernameValue.getClass() + " length " + usernameValue.length() + ": indexOf " + usernameValue.indexOf(queueValue1) + " equals " + usernameValue.equals(queueValue1) );} while ( queueValue1.indexOf(usernameValue) < 0 );info("Now the user is the first in queueA");}endStep();This will enqueue the username to the tail of our Queue. It will will wait for at least 700 milliseconds, the time it takes for one user to exit the critical path and then compare the head of our queue with it's username. This last step will be repeated while the two are not equal (indexOf less than zero). If they are equal the indexOf will yield a value of zero or larger and we will perform the critical steps.Dequeue after Critical PathAfter the virtual user has left the critical path and complete its last step the following code block needs to dequeue the virtual user. In the case of our example this is right after the action has been actually assigned to the virtual user. This will allow the next virtual user to retrieve the list of actions still available and in turn let him make his selection/assignment.info("Get and remove the current user from the head of queueA");String pollValue1 = (String) sharedData.pollFirst("queueA");The current user is removed from the head of the queue. The next one will now be able to match his username against the head of the queue.Clear and Destroy Queue for FinishWhen the script has completed, it should clear and destroy the queue. This code block can be put in the finish block of your script and/or in a separate script in order to clear and remove the queue in case you have spotted an error or want to reset the queue for some reason.info("Clear queueA");sharedData.clearQueue("queueA");info("Destroy queueA");sharedData.destroyQueue("queueA");The users waiting in queueA are cleared and the queue is destroyed. If you have scripts still executing they will be caught in a loop.I found it better to maintain a separate Reset Queue script which contained only the following code in the initialize() block. I use to call this script to make sure the queue is cleared in between multiple Loadtest runs. This script could also even be added as the first in a larger scenario, which would execute it only once at very start of the Loadtest and make sure the queues do not contain any stale entries.info("Create queueA with life time of 120 minutes");sharedData.createQueue("queueA", 120);info("Clear queueA");sharedData.clearQueue("queueA");This will create a Shared Data Queue instance of queueA and clear all entries from this queue.Monitoring QueueWhile creating the scripts it was useful to monitor the contents, i.e. the current first user in the Queue. The following code block will make sure the Shared Data Queue is accessible in the initialize() block.info("Create queueA with life time of 120 minutes");sharedData.createQueue("queueA", 120);In the run() block the following code will continuously monitor the first element of the Queue and write an informational message with the current username Value to the Result window.info("Monitor the first users in queueA");String queueValue1 = null;do {queueValue1 = (String) sharedData.peekFirst("queueA");if (queueValue1 != null)info("The first user in queueA is currently: '" + queueValue1 + "' " + queueValue1.getClass() + " length " + queueValue1.length() );} while ( true );This script can be run from OpenScript parallel to a loadtest performed by the Oracle Load Test.However it is not recommend to run this in a production loadtest as the performance impact is unknown. Accessing the Queue's head with the peekFirst() method has been reported with about 2 seconds response time by both OpenScript and OTL. It is advised to log a Service Request to see if this could be lowered in future releases of Application Testing Suite, as the pollFirst() and even offerLast() writing to the tail of the Queue usually returned after an average 0.1 seconds.Debugging QueueWhile debugging the scripts the following was useful to remove single entries from its head, i.e. the current first user in the Queue. The following code block will make sure the Shared Data Queue is accessible in the initialize() block.info("Create queueA with life time of 120 minutes");sharedData.createQueue("queueA", 120);In the run() block the following code will remove the first element of the Queue and write an informational message with the current username Value to the Result window.info("Get and remove the current user from the head of queueA");String pollValue1 = (String) sharedData.pollFirst("queueA");info("The first user in queueA was currently: '" + pollValue1 + "' " + pollValue1.getClass() + " length " + pollValue1.length() );ReferencesOracle Functional Testing OpenScript User's Guide Version 9.20 [E15488-05]Chapter 17 Using the Shared Data Modulehttp://download.oracle.com/otn/nt/apptesting/oats-docs-9.21.0030.zipOracle Fusion Middleware Oracle WebLogic Server Administration Console Online Help 11g Release 1 (10.3.4) [E13952-04]Administration Console Online Help - Manage users and groupshttp://download.oracle.com/docs/cd/E17904_01/apirefs.1111/e13952/taskhelp/security/ManageUsersAndGroups.htm

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  • How to Create a New Signature in Outlook 2013

    - by Lori Kaufman
    If you sign your emails the same way most of the time, you can create signatures in Outlook that you can attach to your emails. Easily create a signature for business emails and a different one for personal emails. To create a new signature, open Outlook and click the File tab. Click Options in the menu list on the left side of the Account Information screen. On the Outlook Options dialog box, click Mail in the list of options on the left side of the dialog box. On the Mail screen, click Signatures in the Compose messages section. Click New under the Select signature to edit box on the Signatures and Stationery dialog box. A dialog box displays asking for a name for this signature. Enter a descriptive name in the edit box and click OK. You are returned to the Signatures and Stationery dialog box and the name you entered displays in the Select signature to edit box. If it’s the only signature, it will be automatically selected. Enter the text for your signature in the Edit signature box. Select the text and apply font, size, and other character and paragraph formatting as desired. Click OK to accept your changes and close the dialog box. Click OK on the Outlook Options dialog box to close it. Now, when you create a new email message, the default signature is added to the body of your email automatically. If you only have one signature set up, that will be the default signature. Stay tuned for information about setting the default signature, using the signature editor, inserting and changing signatures manually, backing up and restoring your signatures, and modifying a signature for plain text emails, in future articles.     

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  • Rails & combo box change event: Help make this obtrusive javascript unobtrusive

    - by DJTripleThreat
    Ok so a friend of mine gave some help with a prototype/obtrusive solution to this but its not quite there. Also, I want to make this unobtrusive instead of using the observe_field function that rails gives me. I don't want to use prototype either because I'm more familiar with JQuery. Here's my problem: I have an Event that can have multiple ServiceTypes and a ServiceType can belong to many Events. A many-to-many relationship between these two exists as an OfferedService. When creating an event, I have a drop down with a list of TimeAllotments that are something like 10 minutes, 12 minutes, 15 minutes, 20 minutes, 30 minutes etc. When the user selects one of these choices, I want a div tag to be filled with a list of ServiceTypes that are associated with this TimeAllotment. So for example, the user selects "10 minutes" and then the div repopulates with services that last 10 minutes. Here is what I have so far: ... some erb code etc and then <fieldset> <legend><%= f.label :time_allotment, "Size of the Appointment Slots:" %></legend> <div> <span class="field-group"> <div> <!-- TimeAllotment is a tabless model which is why this is done like so... --> <%= select("event_service", "time_allotment", TimeAllotment.all.collect {|ta| [ta.title, ta.value]}, {:prompt => true}) %> </div> </span> </div> <div style="clear:both;"></div> Services: <div> <span class="field-group"> <!-- this div right here needs to be repopulated when the above select changes. --> <div id="services"> <% for service_type in ServiceType.all %> <div> <%= check_box_tag "event_service[service_type_ids][]", service_type.id, false %> <%=h service_type.title %> </div> <% end %> </div> </span> </div> <div class="clear"></div> </fieldset> ok so right now ALL of the services are there to be chosen from. I want them to change based on what is selected in the combobox event_service_time_allotment. Can someone help me get pointed in the right direction? I have looked at Ryan's rails casts for using JQuery but its not helpful because he deals with ajax calls for the create action. This would be for the new or edit action. I have a new.js.erb but it doesn't get loaded when calling the new action. I'm super lost as far as getting JQuery to work with my application. I think that if someone can just show me how to make an alert pop up when I change the combo box, and how to return a dataset using ajax the right now, I think I can figure out the rest. Thanks, I know this is super complicated so any helpful answers will get an upvote.

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  • Delete one row in html table marqued by a check box with javascript

    - by kawtousse
    Hi everyone, I build dynamically my HTML table from database like that: for(i=0;i< nomCols.length;i++) { retour.append(("<td bgcolor=#0066CC>")+ nomCols[i] + "</td>"); } retour.append("</tr>"); retour.append("<tr>"); try { s= HibernateUtil.currentSession(); tx=s.beginTransaction(); Query query = s.createQuery(HQL_QUERY); // inner join projecttasks.ProjectTypeCode as projects");// inner join projecttasks.taskCode as task inner join projects.projectCode as wa;"); for(Iterator it=query.iterate();it.hasNext();) { if(it.hasNext()){ Dailytimesheet object=(Dailytimesheet)it.next(); retour.append("<td><input type=checkbox name=cb id=cb /> </td>"); retour.append("<td>" +object.getTrackingDate() + "</td>"); retour.append("<td>" +object.getActivity() + "</td>"); retour.append("<td>" +object.getProjectCode() + "</td>"); retour.append("<td>" +object.getWAName() + "</td>"); retour.append("<td>" +object.getTaskCode() +"</td>"); retour.append("<td>" +object.getTimeSpent() + "</td>"); retour.append("<td>" +object.getPercentTaskComplete() + "</td>"); } retour.append("</tr>"); } //terminer la table. retour.append (""); tx.commit(); } catch (HibernateException e) { retour.append ("</table><H1>ERREUR:</H1>" +e.getMessage()); e.printStackTrace(); } return retour; } so I want that all check boxes having the same id. When trying to delete one row in my table witch have the check box checked i found a problem with that. Iam using simple javascript like this: function DeleteARow() { //var Rows = document.getElementById('sheet').getElementsByTagName('tr'); //var RowsCount = Rows.length; //alert('Your table has ' + RowsCount + ' rows.'); if (document.getElementById('cb').checked==true) { document.getElementById('cb').parentNode('td').parentNode('tr').remove(); }} It doesn't work approperly and only the first row have the id 'cb'. Many thanks for your help.

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  • Re-opening closed dialog puts it in the start position after moving it

    - by semmelbroesel
    I'm using multiple instances of the JQuery-UI dialog along with draggable and resizable. Whenever I drag or resize one of the dialog boxes, the position and dimensions of the current box are saved to a database and then loaded the next time the page opens. This is working well. However, when I close a dialog box and re-open it using a button, jQuery sets the position of the box back to its original location in the center of the screen. Furthermore, I use a show effect to slide the box off to the left on closing and in from the left on re-opening. I found two ways to update its position when the slide in animation is done, however, it still slides into the center of the screen, and I have yet to find a way to get it to slide in towards the location it is supposed to have. Here are the parts of the code that play a part in this: $('.box').dialog({ closeOnEscape: false, hide: { effect: "drop", direction: 'left' }, beforeClose: function (evt, ui){ var $this = $(this); SavePos($this); // saves the dimensions to db }, dragStop: function() { var $this = $(this); SavePos($this); }, resizeStop: function() { var $this = $(this); SavePos($this); }, open: function() { var $this = $(this); $this.dialog('option', { show: { effect: "drop", direction: 'left'} } ); if (init) // meaning only load this code when the page has finished initializing { // tried it both ways - set the position before and after the effect - no success UpdatePos($this.attr('id')); // I tried this section with promise() and effect / complete - I found no difference $this.parent().promise().done(function() { UpdatePos($this.attr('id')); }); } } }); function UpdatePos(key) { // boxpos is an object holding the position for each box by the box's id var $this = $('#' + key); //console.log('updating pos for box ' + boxid); if ($this && $this.hasClass('ui-dialog-content')) { //console.log($this.dialog('widget').css('left')); $this.dialog('option', { width: boxpos[key].width, height: boxpos[key].height }); $this.dialog('widget').css({ left: boxpos[key].left + 'px', top: boxpos[key].top + 'px' }); //console.log('finished updating pos'); //console.log($this.dialog('widget').css('left')); } } The button that re-opens the box has this code on it to make that happen: var $box = $('#boxid'); if ($box) { if ($box.dialog('isOpen')) { $box.dialog('moveToTop'); } else { $box.dialog("open") } } I don't know what jQuery-UI does to the box as it hides it (other than display:none) or to make it slide in, so maybe there's something I'm missing here that might help... Basically, I need JQuery to remember the box' position and put the box back into that location when it is re-opened. It took me days to make it this far, but this is one obstacle I have yet to overcome. Maybe there's a different way I can re-open the box? Thanks! EDIT: Forgot - this issue ONLY happens when I use my UpdatePos function to set the location of a box (i.e. on page load). When I drag a box with my mouse, close it, and re-open it, everything works. So I'm guessing there's one more storage location for the box' position that I'm missing here... EDIT2: After more messing with it, my code for debugging now looks like this: open: function() { var $this = $(this); console.log('box open'); console.log($this.dialog('widget').position()); // { top=0, left=-78.5} console.log($this.dialog('widget').css('left')); $this.dialog('option', { show: { effect: "drop", direction: 'left'} } ); if (init) { UpdatePos($this.attr('id')); $this.parent().promise().done(function() { console.log($this.dialog('widget').position()); // { top=313, left=641.5} console.log($this.dialog('widget').css('left')); UpdatePos($this.attr('id')); console.log($this.dialog('widget').position()); // { top=121, left=107} console.log($this.dialog('widget').css('left')); }); } The results I'm getting are: box open Object { top=0, left=-78.5} -78.5px Object { top=313, left=641.5} 641.5px Object { top=121, left=107} 107px So looks to me as if the widget is being moved off screen (left=-78.5) and then moved for the animation, and then my code moves it into the location that it should be in (121/107). The position() results for $box.position() or $box.dialog().position() do not change during this debugging section. Maybe this will help someone here - I'm still out of ideas here... ... and I just discovered that when I drag the item around myself, then close and re-open it, it is very unpredictable. Sometimes, it will end up in the correct location horizontally, but not vertically. Sometimes, it will end up back in the center of the screen...

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  • How do I add a VMware ESXi Host to Microsoft Virtual Machine Manager?

    - by user63250
    I am trying to manage virtual machines running on a VMware ESXi host using Microsoft System Center Virtual Machine Manager. I was able to add the ESXi machine using the "Add VMware VirtualCenter server" option, but can't access any of the VMs on the datastore associated with this ESXi server. The datastore of the ESXi box is showing up with the correct name, but it won't let me see any of the VMs that have already been created; I get "There are no virtual machines on this host." Because I couldn't get any of the existing virtual machines to show up, I tried creating some new ones. When using VMM to connect to ESXi and create new VMs, I get the following error messages in the "rating explanation" section: The virtualization software on the selected host does not support virtual hard disks on an IDE bus. and The virtualization software on the host XXXXXX does not support the creation of dynamic virtual hard disk. Any ideas on why I can't manage existing machines and why I can't create new ones? The existing machines were created in vSphere. I should note that the ESXi server and the server running SCVMM are both on the same domain. I should also note that although the ESXi box has been added as a VirtualCetner server, when I try to add it through the "Add Host" option, I get an error message saying "Virtual Machine Manager cannot complete the VirtualCenter action on server EXSi because of the following error: The operation is not supported on the object."

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  • How to connect the virtual networks of vmware guests running on different hosts?

    - by gyrolf
    In a test setup, we are running several virtual machines on a single vmware workstation host. All virtual machines are connected via a "host only" network. This runs fine up to 2 or 3 virtual machines (depending on the host hardware). To allow more virtual machines, we want to use more host machines. Details about the environment and applications: Host PCs are running Windows XP in a corporate intranet. VMware used is Workstation 6.5 Guests are running Windows Server 2003 All guests act as Web Servers One of the guests additionally acts as Windows File server, offering shared folders for the other guests to connect to. Restrictions: VMware guests shall not be visible from the intranet. Changes to the host PC are restricted by corporate policy. In the virtual network, no domain controller exists. All virtual machines are member of the same workgroup. Running the virtual network as NAT is possible. Port forwarding might be used if it does not conflict with ports used by the host PC. Looking for a solution, I found hints about using router or vpn software on the hosts, but without any details how to setup. (I found a similar question Sharing the network between 2 VMware hosts, but the answer was not sufficient for me.)

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  • How do I add a WMware ESXi Host to Microsoft Virtual Machine Manager?

    - by user63250
    I am trying to manage virtual machines running on a VMware ESXi host using Microsoft System Center Virtual Machine Manager. I was able to add the ESXi machine using the "Add VMware VirtualCenter server" option, but can't access any of the VMs on the datastore associated with this ESXi server. The datastore of the ESXi box is showing up with the correct name, but it won't let me see any of the VMs that have already been created; I get "There are no virtual machines on this host." Because I couldn't get any of the existing virtual machines to show up, I tried creating some new ones. When using VMM to connect to ESXi and create new VMs, I get the following error messages in the "rating explanation" section: The virtualization software on the selected host does not support virtual hard disks on an IDE bus. and The virtualization software on the host XXXXXX does not support the creation of dynamic virtual hard disk. Any ideas on why I can't manage existing machines and why I can't create new ones? The existing machines were created in vSphere. I should note that the ESXi server and the server running SCVMM are both on the same domain. I should also note that although the ESXi box has been added as a VirtualCetner server, when I try to add it through the "Add Host" option, I get an error message saying "Virtual Machine Manager cannot complete the VirtualCenter action on server EXSi because of the following error: The operation is not supported on the object."

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  • How to connect the virtual networks of vmware guests running on different hosts?

    - by gyrolf
    In a test setup, we are running several virtual machines on a single vmware workstation host. All virtual machines are connected via a "host only" network. This runs fine up to 2 or 3 virtual machines (depending on the host hardware). To allow more virtual machines, we want to use more host machines. Details about the environment and applications: Host PCs are running Windows XP in a corporate intranet. VMware used is Workstation 6.5 Guests are running Windows Server 2003 All guests act as Web Servers One of the guests additionally acts as Windows File server, offering shared folders for the other guests to connect to. Restrictions: VMware guests shall not be visible from the intranet. Changes to the host PC are restricted by corporate policy. In the virtual network, no domain controller exists. All virtual machines are member of the same workgroup. Running the virtual network as NAT is possible. Port forwarding might be used if it does not conflict with ports used by the host PC. Looking for a solution, I found hints about using router or vpn software on the hosts, but without any details how to setup. (I found a similar question Sharing the network between 2 VMware hosts, but the answer was not sufficient for me.)

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  • Is it possible to overlay EditText box on a GLSurfaceView on Android?

    - by Ash McConnell
    I am trying to add a "PlayerName" box on top of a opengl menu background, is this possible? I've tried various layouts, but they don't seem to allow an EditText box to appear on top What is the typical way of doing something like this? Do I need to manually render the text and handle input or is there a better way? It seems like it should be possible to show the EditText on top of the GLSurfaceView somehow.

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  • How to Create a Send/Receive Group for RSS Feeds in Outlook 2013

    - by Lori Kaufman
    If you choose to manually update your RSS feeds on demand, there is a way to do this without having to send and receive your email at the same time. You can create a special Send/Receive Group for your RSS feeds. NOTE: If you choose to not have your RSS feeds updated automatically, creating a separate Send/Receive Group for your RSS feeds is useful so you can update them when you want to. To begin creating a new Send/Receive Group, click the File tab. Click Options in the menu on the left side of the Account Information screen. On the Outlook Options dialog box, click Advanced in the left pane list of menu options. In the right pane, scroll down to the Send and receive section and click the Send/Receive button. On the Send/Receive Groups dialog box, click New next to the list of groups. On the Send/Receive Group Name dialog box, enter a name, such as “RSS Feeds On Demand Only,” in the edit box and click OK. For all the other Accounts, except RSS, in the list on the left, de-select the Include RSS Feeds in this Send/Receive group check box so there is NO check mark in the box. Click RSS under Accounts, and make sure the Include RSS Feeds in this Send/Receive group check box is selected. NOTE: If you want to have a separate Send/Receive group for each RSS Feed or group certain RSS feeds together, you can turn on and off specific feeds in the lower half of the Send/Receive Settings dialog box. If you decide to do this, you might specify a more appropriate name for each Send/Receive group for the RSS feeds. Click OK to accept your changes and close the Send/Receive dialog box. Make sure your new Send/Receive group is selected in the list of groups on the Send/Receive Groups dialog box. De-select all the options under Setting for group section at the bottom of the dialog box and click Close. This prevents this group from being updated when you click the general Send/Receive button to retrieve your email. Click OK on the Outlook Options dialog box. To manually update your RSS feeds, click the Send / Receive tab. Click Send/Receive Groups and select your new group from the drop-down list. You can change, rename, or remove any Send/Receive Groups you create by accessing the Send/Receive Groups dialog box again.     

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  • preview form using javascript in popup

    - by user1015309
    please I need some help in previewing a form in popup. I have a form, quite big, so I added the option of preview to show as popup. The lightbox form popup works well, but the problem I now have is function passform ()passing the inputs(textfield, select, checkbox, radio) into the popup page for preview on Click(). Below are my javascript and html codes. I left the css and some html out, because I think they're not needed. I will appreciate your help. Thank you The Javascript function gradient(id, level) { var box = document.getElementById(id); box.style.opacity = level; box.style.MozOpacity = level; box.style.KhtmlOpacity = level; box.style.filter = "alpha(opacity=" + level * 100 + ")"; box.style.display="block"; return; } function fadein(id) { var level = 0; while(level <= 1) { setTimeout( "gradient('" + id + "'," + level + ")", (level* 1000) + 10); level += 0.01; } } // Open the lightbox function openbox(formtitle, fadin) { var box = document.getElementById('box'); document.getElementById('shadowing').style.display='block'; var btitle = document.getElementById('boxtitle'); btitle.innerHTML = formtitle; if(fadin) { gradient("box", 0); fadein("box"); } else { box.style.display='block'; } } // Close the lightbox function closebox() { document.getElementById('box').style.display='none'; document.getElementById('shadowing').style.display='none'; } //pass form fields into variables var divexugsotherugsexams1 = document.getElementById('divexugsotherugsexams1'); var exugsotherugsexams1 = document.form4.exugsotherugsexams1.value; function passform() { divexugsotherugsexams1.innerHTML = document.form4.exugsotherugsexams1.value; } The HTML(with just one text field try): <p><input name="submit4" type="submit" class="button2" id="submit4" value="Preview Note" onClick="openbox('Preview Note', 1)"/> </p> <div id="shadowing"></div> <div id="box"> <span id="boxtitle"></span> <div id="divexugsotherugsexams1"></div> <script>document.write('<PARAM name="SRC" VALUE="'+exugsotherugsexams1+'">')</script> <a href="#" onClick="closebox()">Close</a> </div>

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  • getting base url of web site's root (absolute/relative url)

    - by uzay95
    I want to completely understand how to use relative and absolute url address in static and dynamic files. ~ : / : .. : in a relative URL indicates the parent directory . : refers to the current directory / : always replaces the entire pathname of the base URL // : always replaces everything from the hostname onwards This example is easy when you are working without virtual directory. But i am working on virtual directory. Relative URI Absolute URI about.html http://WebReference.com/html/about.html tutorial1/ http://WebReference.com/html/tutorial1/ tutorial1/2.html http://WebReference.com/html/tutorial1/2.html / http://WebReference.com/ //www.internet.com/ http://www.internet.com/ /experts/ http://WebReference.com/experts/ ../ http://WebReference.com/ ../experts/ http://WebReference.com/experts/ ../../../ http://WebReference.com/ ./ http://WebReference.com/html/ ./about.html http://WebReference.com/html/about.html I want to simulate a site below, like my project which is working on virtual directory. These are my aspx and ascx folder http://hostAddress:port/virtualDirectory/MainSite/ASPX/default.aspx http://hostAddress:port/virtualDirectory/MainSite/ASCX/UserCtrl/login.ascx http://hostAddress:port/virtualDirectory/AdminSite/ASPX/ASCX/default.aspx These are my JS Files(which will be use both with the aspx and ascx files): http://hostAddress:port/virtualDirectory/MainSite/JavascriptFolder/jsFile.js http://hostAddress:port/virtualDirectory/AdminSite/JavascriptFolder/jsFile.js this is my static web page address(I want to show some pictures and run inside some js functions): http://hostAddress:port/virtualDirectory/HTMLFiles/page.html this is my image folder http://hostAddress:port/virtualDirectory/Images/PNG/arrow.png http://hostAddress:port/virtualDirectory/Images/GIF/arrow.png if i want to write and image file's link in my ASPX file i should write aspxImgCtrl.ImageUrl = Server.MapPath("~")+"/Images/GIF/arrow.png"; But if i want to write the path hard coded or from javascript file, what kind of url address it should be?

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  • Solutions for working with multiple branches in ASP.Net

    - by Corey McKinnon
    At work, we are often working on multiple branches of our product at one time. For example, right now, we have a maintenance branch, a branch with code just going to QA, and a branch for a new major initiative, that won't be merged for some time now. Our web project is set up to use IIS, so every time we switch to a different branch, we have to go in to IIS Admin and change the path on the virtual directory, then reset IIS, and sometimes even restart Visual Studio, to avoid getting build errors. Is there any way to simplify this, other than not having our web project set up as a virtual directory? I'm not sure we want to make that change at this point. What do you do to make this easier, assuming you do this? Corey @RedWolves, virtual machines would definitely work, but I'm not sure it would be any simpler, especially for some of the other developers on my team, which is partly why I'm looking for more simplicity. @Dan, we're not able to change source control providers, unfortunately. @pix0r, that's something I'll try when I get back to work. Thanks for the suggestion. @Haacked, I'll have to give that a try too, but I think we have some issues with why that won't work (I can't remember exactly why right now; this application was originally written in .Net 1.1, pre-Cassini, and I can't remember if we tried it when we upgraded to 2.0 or not). Thanks all for the responses so far.

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  • What is my HttpContext.GetLocalResourceObject Method Virtual Path?

    - by ARUNRAJ
    I have read http://msdn.microsoft.com/en-us/library/ms149953.aspx and need to verify what is my GetLocalResourceObject virtual path. My local resource files are located on my pc at: C:\inetpub\wwwroot\GlobalX\Input\App_LocalResources Within this folder are my resource files for all the languages that site handles (InputContactDetails.aspx.ro.resx, InputContactDetails.aspx.hi.resx, etc.), as well as the default resource file (InputContactDetails.aspx.resx). I am receiving an error when I attempt to implement the virtual path string. Below is my line of offending code: return '<%= HttpContext.GetLocalResourceObject("~/GlobalX/Input/App_LocalResources/InputContactDetails.aspx.resx", "ContactDetails.Text", new System.Globalization.CultureInfo("ro")) %>'; I have tried ~/GlobalX/Input/App_LocalResources as the virtual path, and several other permutations, but I get the same error. If someone could show what I am doing wrong, I would appreciate it greatly. Here is the error message I am getting: The resource class for this page was not found. Please check if the resource file exists and try again. Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.InvalidOperationException: The resource class for this page was not found. Please check if the resource file exists and try again. Source Error: Line 410: function languageContactPromptPhone(var_lcs) { Line 411: if (var_lcs == "af") { Line 412: return '<%= HttpContext.GetLocalResourceObject("~/GlobalX/Input/App_LocalResources/InputContactDetails.aspx.resx", "ContactDetails.Text", new System.Globalization.CultureInfo("ro")) %'; Line 413: } Line 414: else if (var_lcs == "sq") { Source File: c:\inetpub\wwwroot\GlobalX\Input\InputContactDetails.aspx Line: 412 Stack Trace: [InvalidOperationException: The resource class for this page was not found. Please check if the resource file exists and try again.] System.Web.Compilation.LocalResXResourceProvider.CreateResourceManager() +2785818 System.Web.Compilation.BaseResXResourceProvider.EnsureResourceManager() +24 System.Web.Compilation.BaseResXResourceProvider.GetObject(String resourceKey, CultureInfo culture) +15 System.Web.Compilation.ResourceExpressionBuilder.GetResourceObject(IResourceProvider resourceProvider, String resourceKey, CultureInfo culture, Type objType, String propName) +23 System.Web.HttpContext.GetLocalResourceObject(String virtualPath, String resourceKey, CultureInfo culture) +38 ASP.input_inputcontactdetails_aspx.__RenderContentInputContactDetails(HtmlTextWriter __w, Control parameterContainer) in c:\inetpub\wwwroot\GlobalX\Input\InputContactDetails.aspx:412 System.Web.UI.Control.RenderChildrenInternal(HtmlTextWriter writer, ICollection children) +109 System.Web.UI.Control.RenderChildren(HtmlTextWriter writer) +8 System.Web.UI.Control.Render(HtmlTextWriter writer) +10 System.Web.UI.Control.RenderControlInternal(HtmlTextWriter writer, ControlAdapter adapter) +27 System.Web.UI.Control.RenderControl(HtmlTextWriter writer, ControlAdapter adapter) +8991378 System.Web.UI.Control.RenderControl(HtmlTextWriter writer) +25 System.Web.UI.Control.RenderChildrenInternal(HtmlTextWriter writer, ICollection children) +208 System.Web.UI.Control.RenderChildren(HtmlTextWriter writer) +8 System.Web.UI.Control.Render(HtmlTextWriter writer) +10 System.Web.UI.Control.RenderControlInternal(HtmlTextWriter writer, ControlAdapter adapter) +27 System.Web.UI.Control.RenderControl(HtmlTextWriter writer, ControlAdapter adapter) +8991378 System.Web.UI.Control.RenderControl(HtmlTextWriter writer) +25 System.Web.UI.Control.RenderChildrenInternal(HtmlTextWriter writer, ICollection children) +208 System.Web.UI.UpdatePanel.RenderChildren(HtmlTextWriter writer) +256 System.Web.UI.UpdatePanel.Render(HtmlTextWriter writer) +37 System.Web.UI.Control.RenderControlInternal(HtmlTextWriter writer, ControlAdapter adapter) +27 System.Web.UI.Control.RenderControl(HtmlTextWriter writer, ControlAdapter adapter) +8991378 System.Web.UI.Control.RenderControl(HtmlTextWriter writer) +25 ASP.masterpages_masterinput_master.__RenderformMasterInput(HtmlTextWriter __w, Control parameterContainer) in c:\inetpub\wwwroot\GlobalX\MasterPages\MasterInput.master:140 System.Web.UI.Control.RenderChildrenInternal(HtmlTextWriter writer, ICollection children) +109 System.Web.UI.HtmlControls.HtmlForm.RenderChildren(HtmlTextWriter writer) +173 System.Web.UI.HtmlControls.HtmlContainerControl.Render(HtmlTextWriter writer) +31 System.Web.UI.HtmlControls.HtmlForm.Render(HtmlTextWriter output) +53 System.Web.UI.Control.RenderControlInternal(HtmlTextWriter writer, ControlAdapter adapter) +27 System.Web.UI.Control.RenderControl(HtmlTextWriter writer, ControlAdapter adapter) +8991378 System.Web.UI.HtmlControls.HtmlForm.RenderControl(HtmlTextWriter writer) +40 System.Web.UI.Control.RenderChildrenInternal(HtmlTextWriter writer, ICollection children) +208 System.Web.UI.Control.RenderChildren(HtmlTextWriter writer) +8 System.Web.UI.Control.Render(HtmlTextWriter writer) +10 System.Web.UI.Control.RenderControlInternal(HtmlTextWriter writer, ControlAdapter adapter) +27 System.Web.UI.Control.RenderControl(HtmlTextWriter writer, ControlAdapter adapter) +8991378 System.Web.UI.Control.RenderControl(HtmlTextWriter writer) +25 System.Web.UI.Control.RenderChildrenInternal(HtmlTextWriter writer, ICollection children) +208 System.Web.UI.Control.RenderChildren(HtmlTextWriter writer) +8 System.Web.UI.Page.Render(HtmlTextWriter writer) +29 System.Web.UI.Control.RenderControlInternal(HtmlTextWriter writer, ControlAdapter adapter) +27 System.Web.UI.Control.RenderControl(HtmlTextWriter writer, ControlAdapter adapter) +8991378 System.Web.UI.Control.RenderControl(HtmlTextWriter writer) +25 System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) +3060

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  • How to disable the drop down function of combo box on certain conditions?

    - by Angeline Aarthi
    Hi, I have a combo box in my application. I also have a variable called "Status". I want the combo box to be enabled only when the value of the Status variable is 5 or 6. Otherwise, I should not be able to change the value in the combo box. It should have the previous value only.. I had written a click event to disable the combo box. But even though the combo box is disabled, I get the drop down list of the combo box, and If I select some othe value in the drop down,it changes..Only after that it gets disabled.. How to avoid this? I want the drop down function itself to be disabled. This is the code I have written. Someone guide me. <mx:FormItem label="Review Status:" width="100%" horizontalAlign="right"> <mx:HBox> <mx:Label width="30"/> <mx:ComboBox id="reviewStatus" dataProvider="{Status}" width="150" click="onStatusChange(event)"/> </mx:HBox> Action Script part: private function onStatusChange(event:Event):void { var i:int; for(i=0;i<defectDetails.length;i++) { var defStatusId:String=defectDetails.getItemAt(i).DefectStatusId; if(defStatusId=="5"){ reviewStatus.enabled=true; } else if(defStatusId=="6"){ reviewStatus.enabled=true; } else{ reviewStatus.enabled=false; //reviewStatus.selectedItem.label="Review"; reviewStatus.toolTip="Status can be changed only if Defect Status is Verified or Deferred."; //Alert.show("Status can be changed only if defect status is verified or deferred"); } } } If I use Change event also, for the first time the value is changed. Only after that,the combo box is disabled. How to retain the same value and disable the combo box when the status is not 5 or 6?

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  • Squid on an Azure VM

    - by LantisGaius
    I can't get it to work. Here's exactly what I did: Create a new Azure VM, Windows Server 2012. RDP to the new VM Download & Extract Squid for Windows (2.7.STABLE8) Rename the conf files (squid, mime & cachemgr) Add the following lines on the end of squid.conf auth_param basic program c:/squid/libexec/ncsa_auth.exe c:/squid/etc/passwd.txt auth_param basic children 5 auth_param basic realm Welcome to http://abcde.fg Squid Proxy! auth_param basic credentialsttl 12 hours auth_param basic casesensitive off acl ncsa_users proxy_auth REQUIRED http_access allow ncsa_users Use http://www.htaccesstools.com/htpasswd-generator-windows/ to create passwd.txt Test passwd.txt via c:/squid/libexec/ncsa_auth.exe c:/squid/etc/passwd.txt (success) squid -z squid -i net start squid (No errors so far). go to https://manage.windowsazure.com, Virtual Machines - myVM - Endpoints Add Endpoint: Name: Squid Protocol: TCP Public Port: 80 Private Port: 3128 That's it. Unfortunately, it doesn't work. I think I screwed something up at the endpoint? I'm not sure.. help? EDIT: I'm testing it via Firefox - Options - Advanced - Network, and the exact error is "The Proxy Server is refusing connections." I'm using my DNS as the Proxy server "abcdef.cloudapp.net" and port 80 (since that's my public endpoint).

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  • One host on a network can't connect to one other host

    - by Max Williams
    I'm on a local network with a few other people. On of the hosts is a virtual machine running in virtualbox on a mac, which has the ip address 192.168.0.35 (the VM that is, not the mac host). Everyone except one guy can connect (ie ping, ssh etc) to that machine. When that one guy tries to ping it he gets Request timeout for icmp_seq 0 Request timeout for icmp_seq 1 Request timeout for icmp_seq 2 which i understand is just how certain mac os's report an unreachable connection. He can ping all the other hosts on the network, ie our computers, and we can all ping the VM fine and connect to it with no problems etc. His ip is 192.168.0.17. I ssh'd onto his machine (as a new user 'anon') and saw the same problems. I can ssh onto the 192.168.0.35 VM as well. From there, i can ping other users, but when i ping the problem guy, it's unreachable that way round as well. He restarted his mac, and was fine for a while. Then, just stopped working again. He's got a different IP to before. Any ideas, anyone? Don't know enough about this stuff to even diagnose the problem. thanks, max

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  • Multiple SVN repos on Debian HTTPd vhost setup

    - by Jonathon Reinhart
    I would like to have my svn/http server setup so I can access multiple repositories via a "svn" subdomain: https://svn.example.com/repo1 https://svn.example.com/repo2 I am using Debian 6, and already have multiple vhosts set up via the standard sites-available method. Resources and their problems: How To: subversion SVN with Apache2 and DAV This one doesn't deal with a server with multiple vhosts. Installing and Configuring Subversion This one only considers one subversion repository. This one does show putting the SVN DAV <Location> in the svn vhost file. However, it doesn't say whether to put it inside or outside the <VirtualHost> tag. Does this really limit the subversion access to just that vhost? I just tried, and can access /foorepo from any subdomain. Setting Up Subversion And Trac As Virtual Hosts On An Ubuntu Server This one appears to be very close, but I can still access repos from any vhost. In other words, it doesn't matter what subdomain I specify, as long as the path matches the repo name. Doesn't make any sense. And yes, my <Location> tag is inside the <VirtualHost>. A lot of these articles seem to have been written in 2006 or earlier, and don't necessarily conform to the configuration methods that newer distros are using. Can anyone guide me in the right direction?

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  • Can't connect to a Hyper-V VM from anywhere but the host OS

    - by Elbelcho
    I have an unusual situation on hand where I'm able to connect to a Hyper-V guest VM from the HOST, but not from anywhere but the host. The VM is running WIn2k8R2 and has IIS installed and Remote Desktop enabled. If I browse to the IP from the host OS, the IIS7 page displays. I can also RDP into the guest OS from the host as well as ping. From OFF the host, RDP, web and ping all fail. If I completely shut off the guest VM's firewall, ping will then start to respond, but all RDP and port 80 still don't. The physical host machine has 2 nics installed, but only one is plugged in. The one plugged in has a static IP. I have one Hyper-V virtual network and it's set to external. The guest VM has one NIC with a different static IP than the host, but both are on the same subnet. The host machine is joined to the domain, the guest VM is not. Any sugestions? Thanks so much for any help you may be able to provide!

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  • CD-ROM Cant Be Accessed After Installing VMware Tools on VMware Server 2.0.2

    - by Optimal Solutions
    Using VMware Server 2.02, I set up a new VM (Windows XP Pro) applied all of the updates, added Windows addons from the install CD, etc... I got it to a stable point and up through that point I was able to access the CD-ROM drive (E: on my host). What I never did before was install "VMware Tools" and since it claims to give better mouse and video support, I gave it a shot. What it does is it places the install package in a virtual CD-ROM drive. I ran the install, no errors and it wants a reboot. I log back in after reboot and pop in the install CD for Microsoft Office 2003 and I receive the message "Please Insert A Disc Into Drive D:". Drive D: would be the next logical drive after the C: drive where I chose to install the OS. The message box sits there and if I click "Cancel", to return to Windows Explorer, the status bar seems to blink ever 1/2 second - as if its polling for a CD-ROM drive or something. No bangs or exclamations in the Device Manager for any hardware. I had taken a snapshot prior to the VMware Tools install and upon restoring it, the CD-ROM is back. I made copies of two other VMs, installed the VMware Tools on those VMs and both experienced the same issues: Windows 2003 Server and Windows 7 (32-bit). Has anyone seen this issue and know of a fix for this? It would be nice to have the better graphics and better mouse control AND use my CD-ROM drive as well! Thank you.

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  • VMWare Newbie - looking for hardware recommendations and help :) [closed]

    - by Dan
    I am looking for some hardware recommendations on an upcoming virtualization project. We are a small company (80 users - 25 in site 1, 55 in site 2) currently using Windows Server 2003 - no VM servers yet. Our AD is setup where site 1 is the root domain and site 2 is a subdomain/subnet - connected by T1 and VPN for failover. The current DC's also server as file servers, print servers, AntiVirus servers. Email is in the cloud. Additionally then in site 1 we have 3 additional member servers - one running IBM Websphere for a customer specific app, one running Infor PowerLink (no real heavy load) and another that we use for Virtual Studio apps and also runs DirSync for Exchange Online. No heavy workloads on any of these machines really. We also have an AS400 box that we run ERP/CRM software on that site 2 connects to over the WAN link. In site 2 we also have a SQL machine that runs on Win2K server. Database files are not large less than 5 GB. Light to Medium workload on this machine. File servers in each site store less than 500 GB data and probably won't grow to more than 1TB in the next 5 years. I am looking to go to VMWare in both sites and virtualize all servers. What recommendations do you have for server, storage hardware? Is it safe to virtualize all of your DC's? Any help or advice would be greatly appreciated. Thanks.

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