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  • Prime Numbers Code Help

    - by andrew
    Hello Everybody, I am suppose to "write a Java program that reads a positive integer n from standard input, then prints out the first n prime number." It's divided into 3 parts. 1st: This function will return true or false according to whether m is prime or composite. The array argument P will contain a sufficient number of primes to do the testing. Specifically, at the time isPrime() is called, array P must contain (at least) all primes p in the range 2 p m . For instance, to test m = 53 for primality, one must do successive trial divisions by 2, 3, 5, and 7. We go no further since 11 53 . Thus a precondition for the function call isPrime(53, P) is that P[0] = 2 , P[1] = 3 , P[2] = 5, and P[3] = 7 . The return value in this case would be true since all these divisions fail. Similarly to test m =143 , one must do trial divisions by 2, 3, 5, 7, and 11 (since 13 143 ). The precondition for the function call isPrime(143, P) is therefore P[0] = 2 , P[1] = 3 , P[2] = 5, P[3] = 7 , and P[4] =11. The return value in this case would be false since 11 divides 143. Function isPrime() should contain a loop that steps through array P, doing trial divisions. This loop should terminate when 2 either a trial division succeeds, in which case false is returned, or until the next prime in P is greater than m , in which case true is returned. Then there is the "main function" • Check that the user supplied exactly one command line argument which can be interpreted as a positive integer n. If the command line argument is not a single positive integer, your program will print a usage message as specified in the examples below, then exit. • Allocate array Primes[] of length n and initialize Primes[0] = 2 . • Enter a loop which will discover subsequent primes and store them as Primes[1] , Primes[2], Primes[3] , ……, Primes[n -1] . This loop should contain an inner loop which walks through successive integers and tests them for primality by calling function isPrime() with appropriate arguments. • Print the contents of array Primes[] to stdout, 10 to a line separated by single spaces. In other words Primes[0] through Primes[9] will go on line 1, Primes[10] though Primes[19] will go on line 2, and so on. Note that if n is not a multiple of 10, then the last line of output will contain fewer than 10 primes. The last function is called "usage" which I am not sure how to execute this! Your program will include a function called Usage() having signature static void Usage() that prints this message to stderr, then exits. Thus your program will contain three functions in all: main(), isPrime(), and Usage(). Each should be preceded by a comment block giving it’s name, a short description of it’s operation, and any necessary preconditions (such as those for isPrime().) And hear is my code, but I am having a bit of a problem and could you guys help me fix it? If I enter the number "5" it gives me the prime numbers which are "6,7,8,9" which doesn't make much sense. import java.util.; import java.io.; import java.lang.*; public class PrimeNumber { static boolean isPrime(int m, int[] P){ int squarert = Math.round( (float)Math.sqrt(m) ); int i = 2; boolean ans=false; while ((i<=squarert) & (ans==false)) { int c= P[i]; if (m%c==0) ans= true; else ans= false; i++; } /* if(ans ==true) ans=false; else ans=true; return ans; } ///****main public static void main(String[] args ) { Scanner in= new Scanner(System.in); int input= in.nextInt(); int i, j; int squarert; boolean ans = false; int userNum; int remander = 0; System.out.println("input: " + input); int[] prime = new int[input]; prime[0]= 2; for(i=1; i ans = isPrime(j,prime); j++;} prime[i] = j; } //prnt prime System.out.println("The first " + input + " prime number(s) are: "); for(int r=0; r }//end of main } Thanks for the help

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  • Checking if an int is prime more efficiently

    - by SipSop
    I recently was part of a small java programming competition at my school. My partner and I have just finished our first pure oop class and most of the questions were out of our league so we settled on this one (and I am paraphrasing somewhat): "given an input integer n return the next int that is prime and its reverse is also prime for example if n = 18 your program should print 31" because 31 and 13 are both prime. Your .class file would then have a test case of all the possible numbers from 1-2,000,000,000 passed to it and it had to return the correct answer within 10 seconds to be considered valid. We found a solution but with larger test cases it would take longer than 10 seconds. I am fairly certain there is a way to move the range of looping from n,..2,000,000,000 down as the likely hood of needing to loop that far when n is a low number is small, but either way we broke the loop when a number is prime under both conditions is found. At first we were looping from 2,..n no matter how large it was then i remembered the rule about only looping to the square root of n. Any suggestions on how to make my program more efficient? I have had no classes dealing with complexity analysis of algorithms. Here is our attempt. public class P3 { public static void main(String[] args){ long loop = 2000000000; long n = Integer.parseInt(args[0]); for(long i = n; i<loop; i++) { String s = i +""; String r = ""; for(int j = s.length()-1; j>=0; j--) r = r + s.charAt(j); if(prime(i) && prime(Long.parseLong(r))) { System.out.println(i); break; } } System.out.println("#"); } public static boolean prime(long p){ for(int i = 2; i<(int)Math.sqrt(p); i++) { if(p%i==0) return false; } return true; } } ps sorry if i did the formatting for code wrong this is my first time posting here. Also the output had to have a '#' after each line thats what the line after the loop is about Thanks for any help you guys offer!!!

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  • Webcast: Introduction To Causal Factors

    - by ChristineS-Oracle
    Webcast: Introduction To Causal Factors Date: June 11, 2014 at 11:00 am ET, 10:00 am CT, 9:00 am MT, 8:00 am PT, 8:30 pm, India Time (Mumbai, GMT+05:30) This one hour advisor webcast will provide an introduction to causal factors for Demand Management and AFDM. Pre-seeded causal factors will be discussed as well as when they are not appropriate. Scenarios of when to add causal factors will be covered and best practice method of adding and using. Topics will include: Causal factors in DM and AFDM Pre-seeded causal factors When to modify causal factor settings Best practice when working with causal factors Details & Registration: Doc ID 1664606.1

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  • Python - Check if numbers in list are factors of a number

    - by Zach
    Hey, I have a list of numbers (integers) (say, from 1 to 10). They're not necessarily consecutive, but they are in ascending order. I've prompted the user multiple times to enter a choice of the available numbers. When that number is entered, it is removed from the list along with any of its factors that may be there. I've prevented the user from selecting prime numbers. However, at some point in time, there may be non-prime numbers there, which have no factors remaining. I'm relatively new to Python, so I'm having trouble implementing: Checking if the number selected has no factors remaining (even if it is not prime). Checking if only prime numbers remain, or numbers without factors. I'm thinking of using for statements, but I'm not sure exactly how to implement them. Can anyone offer advice, or code? Thanks in advance... PS. In case anyone's wondering, I'm doing an implementation of the game of Taxman in Python.

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  • C++ question on prime numbers.

    - by user278330
    Hello. I am trying to make a program that determines if the number is prime or composite. I have gotten thus far. Could you give me any ideas so that it will work? All primes will , however, because composites have values that are both r0 and r==0, they will always be classified as prime. How can I fix this? int main() { int pNumber, limit, x, r; limit = 0; x = 2; cout << "Please enter any positive integer: " ; cin >> pNumber; if (pNumber < 0) { cout << "Invalid. Negative Number. " << endl; return 0; } else if (pNumber == 0) { cout << "Invalid. Zero has an infinite number of divisors, and therefore neither composite nor prime." << endl; return 0; } else if (pNumber == 1) { cout << "Valid. However, one is neither prime nor composite" << endl; return 0; } else { while (limit < pNumber) { r = pNumber % x; x++; limit++; } if (r == 0) cout << "Your number is composite" << endl; else cout << "Your number is prime" << endl; } return 0; }

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  • C++ question on prime numbers.

    - by user278330
    Hello. I am trying to make a program that determines if the number is prime or composite. I have gotten thus far. Could you give me any ideas so that it will work? All primes will , however, because composites have values that are both r0 and r==0, they will always be classified as prime. How can I fix this? int main() { int pNumber, limit, x, r; limit = 0; x = 2; cout << "Please enter any positive integer: " ; cin >> pNumber; if (pNumber < 0) { cout << "Invalid. Negative Number. " << endl; return 0; } else if (pNumber == 0) { cout << "Invalid. Zero has an infinite number of divisors, and therefore neither composite nor prime." << endl; return 0; } else if (pNumber == 1) { cout << "Valid. However, one is neither prime nor composite" << endl; return 0; } else { while (limit < pNumber) { r = pNumber % x; x++; limit++; } if (r == 0) cout << "Your number is composite" << endl; else cout << "Your number is prime" << endl; } return 0; }

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  • Generating exactly prime number with Java

    - by Viet
    Hi, I'm aware of the function BigInteger.probablePrime(int bitLength, Random rnd) that outputs probably prime number of any bit length. I want a REAL prime number in Java. Is there any FOSS library to do so with acceptable performance? Thanks in advance!

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  • fastest calculation of largest prime factor of 512 bit number in python

    - by miraclesoul
    dear all, i am simulating my crypto scheme in python, i am a new user to it. p = 512 bit number and i need to calculate largest prime factor for it, i am looking for two things: Fastest code to process this large prime factorization Code that can take 512 bit of number as input and can handle it. I have seen different implementations in other languages, my whole code is in python and this is last point where i am stuck. So let me know if there is any implementation in python. Kindly explain in simple as i am new user to python sorry for bad english.

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  • Help with Java Program for Prime numbers

    - by Ben
    Hello everyone, I was wondering if you can help me with this program. I have been struggling with it for hours and have just trashed my code because the TA doesn't like how I executed it. I am completely hopeless and if anyone can help me out step by step, I would greatly appreciate it. In this project you will write a Java program that reads a positive integer n from standard input, then prints out the first n prime numbers. We say that an integer m is divisible by a non-zero integer d if there exists an integer k such that m = k d , i.e. if d divides evenly into m. Equivalently, m is divisible by d if the remainder of m upon (integer) division by d is zero. We would also express this by saying that d is a divisor of m. A positive integer p is called prime if its only positive divisors are 1 and p. The one exception to this rule is the number 1 itself, which is considered to be non-prime. A positive integer that is not prime is called composite. Euclid showed that there are infinitely many prime numbers. The prime and composite sequences begin as follows: Primes: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, … Composites: 1, 4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 22, 24, 25, 26, 27, 28, … There are many ways to test a number for primality, but perhaps the simplest is to simply do trial divisions. Begin by dividing m by 2, and if it divides evenly, then m is not prime. Otherwise, divide by 3, then 4, then 5, etc. If at any point m is found to be divisible by a number d in the range 2 d m-1, then halt, and conclude that m is composite. Otherwise, conclude that m is prime. A moment’s thought shows that one need not do any trial divisions by numbers d which are themselves composite. For instance, if a trial division by 2 fails (i.e. has non-zero remainder, so m is odd), then a trial division by 4, 6, or 8, or any even number, must also fail. Thus to test a number m for primality, one need only do trial divisions by prime numbers less than m. Furthermore, it is not necessary to go all the way up to m-1. One need only do trial divisions of m by primes p in the range 2 p m . To see this, suppose m 1 is composite. Then there exist positive integers a and b such that 1 < a < m, 1 < b < m, and m = ab . But if both a m and b m , then ab m, contradicting that m = ab . Hence one of a or b must be less than or equal to m . To implement this process in java you will write a function called isPrime() with the following signature: static boolean isPrime(int m, int[] P) This function will return true or false according to whether m is prime or composite. The array argument P will contain a sufficient number of primes to do the testing. Specifically, at the time isPrime() is called, array P must contain (at least) all primes p in the range 2 p m . For instance, to test m = 53 for primality, one must do successive trial divisions by 2, 3, 5, and 7. We go no further since 11 53 . Thus a precondition for the function call isPrime(53, P) is that P[0] = 2 , P[1] = 3 , P[2] = 5, and P[3] = 7 . The return value in this case would be true since all these divisions fail. Similarly to test m =143 , one must do trial divisions by 2, 3, 5, 7, and 11 (since 13 143 ). The precondition for the function call isPrime(143, P) is therefore P[0] = 2 , P[1] = 3 , P[2] = 5, P[3] = 7 , and P[4] =11. The return value in this case would be false since 11 divides 143. Function isPrime() should contain a loop that steps through array P, doing trial divisions. This loop should terminate when 2 either a trial division succeeds, in which case false is returned, or until the next prime in P is greater than m , in which case true is returned. Function main() in this project will read the command line argument n, allocate an int array of length n, fill the array with primes, then print the contents of the array to stdout according to the format described below. In the context of function main(), we will refer to this array as Primes[]. Thus array Primes[] plays a dual role in this project. On the one hand, it is used to collect, store, and print the output data. On the other hand, it is passed to function isPrime() to test new integers for primality. Whenever isPrime() returns true, the newly discovered prime will be placed at the appropriate position in array Primes[]. This process works since, as explained above, the primes needed to test an integer m range only up to m , and all of these primes (and more) will already be stored in array Primes[] when m is tested. Of course it will be necessary to initialize Primes[0] = 2 manually, then proceed to test 3, 4, … for primality using function isPrime(). The following is an outline of the steps to be performed in function main(). • Check that the user supplied exactly one command line argument which can be interpreted as a positive integer n. If the command line argument is not a single positive integer, your program will print a usage message as specified in the examples below, then exit. • Allocate array Primes[] of length n and initialize Primes[0] = 2 . • Enter a loop which will discover subsequent primes and store them as Primes[1] , Primes[2], Primes[3] , ……, Primes[n -1] . This loop should contain an inner loop which walks through successive integers and tests them for primality by calling function isPrime() with appropriate arguments. • Print the contents of array Primes[] to stdout, 10 to a line separated by single spaces. In other words Primes[0] through Primes[9] will go on line 1, Primes[10] though Primes[19] will go on line 2, and so on. Note that if n is not a multiple of 10, then the last line of output will contain fewer than 10 primes. Your program, which will be called Prime.java, will produce output identical to that of the sample runs below. (As usual % signifies the unix prompt.) % java Prime Usage: java Prime [PositiveInteger] % java Prime xyz Usage: java Prime [PositiveInteger] % java Prime 10 20 Usage: java Prime [PositiveInteger] % java Prime 75 2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97 101 103 107 109 113 127 131 137 139 149 151 157 163 167 173 179 181 191 193 197 199 211 223 227 229 233 239 241 251 257 263 269 271 277 281 283 293 307 311 313 317 331 337 347 349 353 359 367 373 379 % 3 As you can see, inappropriate command line argument(s) generate a usage message which is similar to that of many unix commands. (Try doing the more command with no arguments to see such a message.) Your program will include a function called Usage() having signature static void Usage() that prints this message to stderr, then exits. Thus your program will contain three functions in all: main(), isPrime(), and Usage(). Each should be preceded by a comment block giving it’s name, a short description of it’s operation, and any necessary preconditions (such as those for isPrime().) See examples on the webpage.

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  • Off-Page Factors That Affect Search Optimization

    Following the discussion of the on-page factors that affect search engine optimization in one of my recent writings, I deem it fit to also discuss the off-page factors that can be of great importance to your search engine optimization campaign. Though many people will not readily agree that something like these exist; but I want to make it known categorically that these less considered factors are also very vital to achieving result in your internet marketing business.

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  • Quickly determine if a number is prime in Python for numbers < 1 billion

    - by Frór
    Hi, My current algorithm to check the primality of numbers in python is way to slow for numbers between 10 million and 1 billion. I want it to be improved knowing that I will never get numbers bigger than 1 billion. The context is that I can't get an implementation that is quick enough for solving problem 60 of project Euler: I'm getting the answer to the problem in 75 seconds where I need it in 60 seconds. http://projecteuler.net/index.php?section=problems&id=60 I have very few memory at my disposal so I can't store all the prime numbers below 1 billion. I'm currently using the standard trial division tuned with 6k±1. Is there anything better than this? Do I already need to get the Rabin-Miller method for numbers that are this large. primes_under_100 = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97] def isprime(n): if n <= 100: return n in primes_under_100 if n % 2 == 0 or n % 3 == 0: return False for f in range(5, int(n ** .5), 6): if n % f == 0 or n % (f + 2) == 0: return False return True How can I improve this algorithm?

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  • Ubuntu for Android on the ASUS Transformer Prime

    - by sola
    I would like to use Ubuntu on my Transformer Prime in parallel with Android (not as a dual booting solution, I want to be able to switch between them instantaniously). I am aware of the traditional chrooting/VNC solution but I heard that it performs very poorly so I would like to use Ubuntu For Android (UFA) which has been announced recently by Canonical. That looks like a polished, highly integrated solution for Android devices. The Prime would be the ideal device for Ubuntu For Android since it has a powerful processor (Tegra3) capable of running a lot of processes in parallel on its 4 cores. Does anyone know if Canonical or anybody else is working on supporting UFA on the ASUS Transformer Prime? As far as I understand, the X11 driver is available for Tegra3 so, the biggest hurdle may be easily overcome.

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  • Multiple Monitors using nvidia-prime or bumblebee on Ubuntu 13.10

    - by user205626
    I've been unable to get multiple monitors to work with Ubuntu 13.10 using nvidia-prime or bumblebee. Could someone point me in the right direction? With nvidia-prime, I've tried the xorg.conf here http://us.download.nvidia.com/XFree86/Linux-x86/319.12/README/randr14.html, but I boot into "low graphics" mode and have to revert to get a desktop back. Any suggestions would be appreciated. Thanks. Edit: I've given up on nvidia-prime; I missed the fact that it never turns off the discrete card... So, I'm back to trying to get VIRTUAL displays working with Bumblebee.

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  • Does Ubuntu run on current Asus Transformer Prime?

    - by Ubuntu User
    I've read instructions about dual boot Android / Transformer Prime (a significant factor in ordering one). Also about not working with /latest/ Transformer Prime (firmware / BIOS?) Also about imminent Ubuntu ARM support. Will I be able to run Ubuntu in a day or two when Transformer arrives? Also, am I right to assume I can restore Transformer to factory status if I break something in the attempt?

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  • Protected Videos not Playing Ubuntu 13.10 (Amazon Prime)

    - by Radeesh Koonichere
    Unable to play amazon prime videos with Chrome/Firefox browser. Tried deleting the Flash folder, re-installed OS. Ubuntu 13.10 Flash Version: flashplugin-installer 11.2.202.310ubuntu1 Youtube works but not Amazon Prime. Try 1 Clear Cache Flash cd ~/.adobe/Flash_Player rm -rf NativeCache AssetCache APSPrivateData2 Try 2 Install Older version of Flash /usr/lib/flashplugin-installer/Flashplayer.so Some other sites have installing HAL and running hald but that was not working either as it seems to be a deprecated. sudo apt-get install hal

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  • Euler Project Help (Problem 12) - Prime Factors and the like

    - by Richie_W
    I hate to have to ask, but I'm pretty stuck here. I need to test a sequence of numbers to find the first which has over 500 factors: http://projecteuler.net/index.php?section=problems&id=12 -At first I attempted to brute force the answer (finding a number with 480 after a LONG time) -I am now looking at determining the prime factors of a number and then use them to find all other factors. I am currently at the stage where I can get an array of prime factors for any number I input - i.e 300 has the prime factors 2 2 3 5 5 Using this array of prime factors I need to be able to calculate the remaining factors - This is the part I am stuck on. Basically, as I understand it, I need to calculate ALL possible combinations of the numbers in the array... i.e 2 * 2 2 * 2 * 3 2 * 2 * 3 * 5 2 * 3 2 * 3 * 3 ...and so forth - But where it gets interesting is with things like... 2 * 5 2 * 3 * 5 ...i.e Numbers which are not adjacent to each other in the array I can't think of a way to code this in a generic fashion for any length array... I need help! P.S - I am working in Java EDIT: My brute force code - As it has been suggested brute forcing the problem will work and so there may be an error in my code :( package euler.problem12; public class Solution { public static void main(String[] args) { int next = 1; int triangle = 0; int maxFactors = 0; while(true) { triangle = triangle + next; int factors = 1; int max = (int) triangle / 2; for(int i = 1; i <= max; ++i) { if(triangle % i == 0) { factors ++; } } if(factors > maxFactors) { maxFactors = factors; System.out.println(triangle + "\t" + factors); } next++; } } }

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  • Reshape data frame to convert factors into columns in R

    - by Alexander L. Belikoff
    I have a data frame where one particular column has a set of specific values (let's say, 1, 2, ..., 23). What I would like to do is to convert from this layout to the one, where the frame would have extra 23 (in this case) columns, each one representing one of the factor values. The data in these columns would be booleans indicating whether a particular row had a given factor value... To show a specific example: Source frame: ID DATE SECTOR 123 2008-01-01 1 456 2008-01-01 3 789 2008-01-02 5 ... <more records with SECTOR values from 1 to 5> Desired format: ID DATE SECTOR.1 SECTOR.2 SECTOR.3 SECTOR.4 SECTOR.5 123 2008-01-01 T F F F F 456 2008-01-01 F F T F F 789 2008-01-02 F F F F T I have no problem doing it in a loop but I hoped there would be a better way. So far reshape() didn't yield the desired result. Help would be much appreciated.

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  • program logic of printing the prime numbers

    - by Vignesh Vicky
    can any body help to understand this java program it just print prime n.o ,as you enter how many you want and it works good class PrimeNumbers { public static void main(String args[]) { int n, status = 1, num = 3; Scanner in = new Scanner(System.in); System.out.println("Enter the number of prime numbers you want"); n = in.nextInt(); if (n >= 1) { System.out.println("First "+n+" prime numbers are :-"); System.out.println(2); } for ( int count = 2 ; count <=n ; ) { for ( int j = 2 ; j <= Math.sqrt(num) ; j++ ) { if ( num%j == 0 ) { status = 0; break; } } if ( status != 0 ) { System.out.println(num); count++; } status = 1; num++; } } } i dont understand this for loop condition for ( int j = 2 ; j <= Math.sqrt(num) ; j++ ) why we are taking sqrt of num...which is 3....why we assumed it as 3?

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  • Can you tell me why this generates time limit exceeded in spoj(Prime Number Generator)

    - by magiix
    #include<iostream> #include<string.h> #include<math.h> using namespace std; bool prime[1000000500]; void generate(long long end) { memset(prime,true,sizeof(prime)); prime[0]=false; prime[1]=false; for(long long i=0;i<=sqrt(end);i++) { if(prime[i]==true) { for(long long y=i*i;y<=end;y+=i) { prime[y]=false; } } } } int main() { int n; long long b,e; scanf("%d",&n); while(n--) { cin>>b>>e; generate(e); for(int i=b;i<e;i++) { if(prime[i]) printf("%d\n",i); } } return 0; } That's my code for spoj prime generator. Altought it generates the same output as another accepted code ..

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  • Top Three Factors in New E-Business Setup

    If you are trying to establish a website or e-commerce store, there are three primary factors one must take into consideration. These factors are: acquiring a good domain name and finding affordable hosting, the ability to accept payment, and providing security for your site and your customers.

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  • On-Site Factors that Affect CPC

    - by ashes999
    I have a few websites on various niche topics, all running Adsense. The most promising one currently has a CPC that hovers around $1; the rest have CPCs of $0.25-$0.50. I'm curious to know what on-site factors affect CPC. That is to say, what I can do, legally (in white-hat compliance) to increase my CPC? Some factors that affect CPC but are not within my control (and therefore, beyond the scope of my question -- they're just examples) include: What advertisers are paying for keywords on my site What pages people are landing on etc.

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  • printing out prime numbers from array

    - by landscape
    I'd like to print out all prime numbers from an array with method. I can do it with one int but don't know how to return certain numbers from array. Thanks for help! public static boolean isPrime(int [] tab) { boolean prime = true; for (int i = 3; i <= Math.sqrt(tab[i]); i += 2) if (tab[i] % i == 0) { prime = false; break; } for(int i=0; i<tab.length; i++) if (( tab[i]%2 !=0 && prime && tab[i] > 2) || tab[i] == 2) { return true; } else { return false; } //return prime; } thanks both of you. Seems like its solved: public static void isPrime(int[] tab) { for (int i = 0; i < tab.length; i++) { if (isPrimeNum(tab[i])) { System.out.println(tab[i]); } } } public static boolean isPrimeNum(int n) { boolean prime = true; for (long i = 3; i <= Math.sqrt(n); i += 2) { if (n % i == 0) { prime = false; break; } } if ((n % 2 != 0 && prime && n > 2) || n == 2) { return true; } else { return false; } }

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