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  • How to make multiple wires quickly in Verilog?

    - by user1334858
    I am trying to make 24 wires in total very quickly but I keep getting the error: Error (10170): Verilog HDL syntax error at your_ALU_mux.v(81) near text "="; expecting ".", or an identifier Here is my code: module your_ALU_mux(your_out, operandA, operandB, opcode, switches, address); input [7:0] operandA, operandB, address; input [3:0] opcode, switches; output [7:0] your_out; wire [0:7] Bnot, newb, newa; wire Cin, Cout; not (Bnot[0], operandB[0]), (Bnot[1], operandB[1]), (Bnot[2], operandB[2]), (Bnot[3], operandB[3]), (Bnot[4], operandB[4]), (Bnot[5], operandB[5]), (Bnot[6], operandB[6]), (Bnot[7], operandB[7]); // Getting A' and B' if (address == 16'h00 || address == 16'h01) // Add A + B if (address == 16'h00) // newa = A newa[0] = operandA[0]; newa[1] = operandA[1]; newa[2] = operandA[2]; newa[3] = operandA[3]; newa[4] = operandA[4]; newa[5] = operandA[5]; newa[6] = operandA[6]; newa[7] = operandA[7]; // newb = B' newb[0] = Bnot[0]; newb[1] = Bnot[1]; newb[2] = Bnot[2]; newb[3] = Bnot[3]; newb[4] = Bnot[4]; newb[5] = Bnot[5]; newb[6] = Bnot[6]; newb[7] = Bnot[7]; // Carry in = 1 Cin = 1; // A-B else if (address == 16'h01) // newb = B newb[0] = operandB[0]; newb[1] = operandB[1]; newb[2] = operandB[2]; newb[3] = operandB[3]; newb[4] = operandB[4]; newb[5] = operandB[5]; newb[6] = operandB[6]; newb[7] = operandB[7]; // newa = A newa[0] = operandA[0]; newa[1] = operandA[1]; newa[2] = operandA[2]; newa[3] = operandA[3]; newa[4] = operandA[4]; newa[5] = operandA[5]; newa[6] = operandA[6]; newa[7] = operandA[7]; // Carry in = 0 Cin = 0; end RippleCarryAdd A+B(.S0(your_out[0]), .S1(your_out[1],.S2(your_out[2],.S3(your_out[3],.S4(your_out[4],.S5(your_out[5] S6.(your_out[6]), S7.(your_out[7], .Cout(Cout),.Cin(Cin), .A0(newa[0]),.A1(newa[1]),.A2(newa[2]),.A3(newa[3]),.A4(newa[4]),.A5(newa[5]), .A6(newa[6]),.A7(newa[7]), .B0(newb[0]),.B1(newb[1]),.B2(newb[2]),.B3(newb[3]),.B4(newb[4]), .B5(newb[5]),.B6(newb[6]),.B7(newb[7])); endmodule I also get in error saying: Error (10170): Verilog HDL syntax error at your_ALU_mux.v(66) near text "if"; expecting "endmodule" And the it brings me to my first if statement. Is this the wrong way of going about creating wires and them using them?

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