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  • List of dict in Python

    - by plalex
    Hi everybody, I've got a list of dict in Python: dico_cfg = {'name': entry_name, 'ip': entry_ip, 'vendor': combo_vendor, 'stream': combo_stream} self.list_cfg.append(dico_cfg) I append to my list a lot of dict in the same way. Now I would like to delete one dict and only one dict in this list? What is the best way to proceed? I've try with the index of the list, but when I remove a dict from the list, the index is modify, so after some random remove my index doesn't correspond anymore to the dict I want to remove in my list. I hope that is clear. Maybe I can add an "id" row in my dict, so I can ask to remove more preciously the dict I want. I'll ask to remove the dict where id is equal to the id's dict I want to remove. How can I do that? I hope I'm enough clear. Sorry but I'm a newbie in Python.

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  • what would be a frozen dict ?

    - by dugres
    A frozen set is a frozenset. A frozen list could be a tuple. What would be a frozen dict ? An immutable, hashable dict. I guess it could be something like collections.namedtuple, but namedtuple is more like a frozenkeys dict (an half-frozen dict). No ?

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  • Can't remove libreoffice3.5-dict-de package

    - by Aaron Digulla
    I just installed the wrong version of LibreOffice (x86 instead of 64bit). So I tried to remove it but I get this error: > aptitude remove libreoffice3.5-dict-de Couldn't find package "libreoffice3.5-dict-de". However, the following packages contain "libreoffice3.5-dict-de" in their name: libreoffice3.5-dict-de Couldn't find package "libreoffice3.5-dict-de". However, the following packages contain "libreoffice3.5-dict-de" in their name: libreoffice3.5-dict-de No packages will be installed, upgraded, or removed. 0 packages upgraded, 0 newly installed, 0 to remove and 2 not upgraded. Need to get 0 B of archives. After unpacking 0 B will be used. The same happens when I try to use "Software Management". What's going on? aptitude: 0.6.4-1ubuntu2 Ubuntu 11.10 oneiric

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  • Converting JSON into Python dict

    - by GrumpyCanuck
    I've been searching around trying to find an answer to this question, and I can't seem to track it down. Maybe it's too late in the evening to figure the answer out, so I turn to the excellent readers here. I have the following bit of JSON data that I am pulling out of a CouchDB record: "{\"description\":\"fdsafsa\",\"order\":\"1\",\"place\":\"22 Plainsman Rd, Mississauga, ON, Canada\",\"lat\":43.5969175,\"lng\":-79.7248744,\"locationDate\":\"03/24/2010\"},{\"description\":\"sadfdsa\",\"order\":\"2\",\"place\":\"50 Dawnridge Trail, Brampton, ON, Canada\",\"lat\":43.7304774,\"lng\":-79.8055435,\"locationDate\":\"03/26/2010\"}," This data is stored inside a Python dict under the key 'locations' in a dict called 'my_plan'. I want to covert this data from CouchDB into a Python dict so I can do the following in a Django template: {% for location in my_plan.locations %} <tr> <td>{{ location.place }}</td> <td>{{ location.locationDate }}</td> </tr> {% endfor %} I've found lots of info on converting dicts to JSON, but nothing on going back the other way Thanks in advance for the help!

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  • Is it possible to give a python dict an initial capacity (and is it usefull)

    - by Peter Smit
    I am filling a python dict with around 10,000,000 items. My understanding of dict (or hashtables) is that when too much elements get in them, the need to resize, an operation that cost quite some time. Is there a way to say to a python dict that you will be storing at least n items in it, so that it can allocate memory from the start? Or will this optimization not do any good to my running speed? (And no, I have not checked that the slowness of my small script is because of this, I actually wouldn't now how to do that. This is however something I would do in Java, set the initial capacity of the HashSet right)

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  • What is the structure of network managers system-connections files?

    - by Oyks Livede
    could anyone list the complete structure of the configuration files, which network manager stores for known networks in /etc/NetworkManager/system-connections for known networks? Sample (filename askUbuntu): [connection] id=askUbuntu uuid=81255b2e-bdf1-4bdb-b6f5-b94ef16550cd type=802-11-wireless [802-11-wireless] ssid=askUbuntu mode=infrastructure mac-address=00:08:CA:E6:76:D8 [ipv6] method=auto [ipv4] method=auto I would like to create some of them by my own using a script. However, before doing so I would like to know every possible option. Furthermore, this structure seems somehow to resemble the information you can get using the dbus for active connections. dbus-send --system --print-reply \ --dest=org.freedesktop.NetworkManager \ "$active_setting_path" \ # /org/freedesktop/NetworkManager/Settings/2 org.freedesktop.NetworkManager.Settings.Connection.GetSettings Will tell you: array [ dict entry( string "802-11-wireless" array [ dict entry( string "ssid" variant array of bytes "askUbuntu" ) dict entry( string "mode" variant string "infrastructure" ) dict entry( string "mac-address" variant array of bytes [ 00 08 ca e6 76 d8 ] ) dict entry( string "seen-bssids" variant array [ string "02:1A:11:F8:C5:64" string "02:1A:11:FD:1F:EA" ] ) ] ) dict entry( string "connection" array [ dict entry( string "id" variant string "askUbuntu" ) dict entry( string "uuid" variant string "81255b2e-bdf1-4bdb-b6f5-b94ef16550cd" ) dict entry( string "timestamp" variant uint64 1383146668 ) dict entry( string "type" variant string "802-11-wireless" ) ] ) dict entry( string "ipv4" array [ dict entry( string "addresses" variant array [ ] ) dict entry( string "dns" variant array [ ] ) dict entry( string "method" variant string "auto" ) dict entry( string "routes" variant array [ ] ) ] ) dict entry( string "ipv6" array [ dict entry( string "addresses" variant array [ ] ) dict entry( string "dns" variant array [ ] ) dict entry( string "method" variant string "auto" ) dict entry( string "routes" variant array [ ] ) ] ) ] I can create new setting files using the dbus (AddSettings() in /org/freedesktop/NetworkManager/Settings) passing this type of input, so explaining me this structure and telling me all possible options will also help. Afaik, this is a Dictionary{String, Dictionary{String, Variant}}. Will there be any difference creating config files directly or using the dbus?

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  • How to synchronize a python dict with multiprocessing

    - by Peter Smit
    I am using Python 2.6 and the multiprocessing module for multi-threading. Now I would like to have a synchronized dict (where the only atomic operation I really need is the += operator on a value). Should I wrap the dict with a multiprocessing.sharedctypes.synchronized() call? Or is another way the way to go?

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  • gen_server with a dict vs mnesia table vs ets

    - by pablo
    Hi, I'm building an erlang server. Users sends http requests to the server to update their status. The http request process on the server saves the user status message in memory. Every minute the server sends all messages to a remote server and clear the memory. If a user update his status several times in a minute, the last message overrides the previous one. It is important that between reading all the messages and clearing them no other process will be able to write a status message. What is the best way to implement it? gen_server with a dict. The key will be the userid. dict:store/3 will update or create the status. The gen_server solves the 'transaction' issue. mnesia table with ram_copies. Handle transactions and I don't need to implement a gen_server. Is there too much overhead with this solution? ETS table which is more light weight and have a gen_server. Is it possible to do the transaction in ETS? To lock the table between reading all the messages and clearing them? Thanks

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  • python dict update diff

    - by adam
    Does python have any sort of built in functionality of notifying what dictionary elements changed upon dict update? For example I am looking for some functionality like this: >>> a = {'a':'hamburger', 'b':'fries', 'c':'coke'} >>> b = {'b':'fries', 'c':'pepsi', 'd':'ice cream'} >>> a.diff(b) {'c':'pepsi', 'd':'ice cream'} >>> a.update(b) >>> a {'a':'hamburger', 'b':'fries', 'c':'pepsi', 'd':'ice cream'} I am looking to get a dictionary of the changed values as shown in the result of a.diff(b)

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  • python dict.fromkeys() returns empty

    - by slooow
    I wrote the following function. It returns an empty dictionary when it should not. The code works on the command line without function. However I cannot see what is wrong with the function, so I have to appeal to your collective intelligence. def enter_users_into_dict(userlist): newusr = {} newusr.fromkeys(userlist, 0) return newusr ul = ['john', 'mabel'] nd = enter_users_into_dict(ul) print nd It returns an empty dict {} where I would expect {'john': 0, 'mabel': 0}. It is probably very simply but I don't see the solution.

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  • Comparing dicts and update a list of result

    - by lmnt
    Hello, I have a list of dicts and I want to compare each dict in that list with a dict in a resulting list, add it to the result list if it's not there, and if it's there, update a counter associated with that dict. At first I wanted to use the solution described at http://stackoverflow.com/questions/1692388/python-list-of-dict-if-exists-increment-a-dict-value-if-not-append-a-new-dict but I got an error where one dict can not be used as a key to another dict. So the data structure I opted for is a list where each entry is a dict and an int: r = [[{'src': '', 'dst': '', 'cmd': ''}, 0]] The original dataset (that should be compared to the resulting dataset) is a list of dicts: d1 = {'src': '192.168.0.1', 'dst': '192.168.0.2', 'cmd': 'cmd1'} d2 = {'src': '192.168.0.1', 'dst': '192.168.0.2', 'cmd': 'cmd2'} d3 = {'src': '192.168.0.2', 'dst': '192.168.0.1', 'cmd': 'cmd1'} d4 = {'src': '192.168.0.1', 'dst': '192.168.0.2', 'cmd': 'cmd1'} o = [d1, d2, d3, d4] The result should be: r = [[{'src': '192.168.0.1', 'dst': '192.168.0.2', 'cmd': 'cmd1'}, 2], [{'src': '192.168.0.1', 'dst': '192.168.0.2', 'cmd': 'cmd2'}, 1], [{'src': '192.168.0.2', 'dst': '192.168.0.1', 'cmd': 'cmd1'}, 1]] What is the best way to accomplish this? I have a few code examples but none is really good and most is not working correctly. Thanks for any input on this! UPDATE The final code after Tamås comments is: from collections import namedtuple, defaultdict DataClass = namedtuple("DataClass", "src dst cmd") d1 = DataClass(src='192.168.0.1', dst='192.168.0.2', cmd='cmd1') d2 = DataClass(src='192.168.0.1', dst='192.168.0.2', cmd='cmd2') d3 = DataClass(src='192.168.0.2', dst='192.168.0.1', cmd='cmd1') d4 = DataClass(src='192.168.0.1', dst='192.168.0.2', cmd='cmd1') ds = d1, d2, d3, d4 r = defaultdict(int) for d in ds: r[d] += 1 print "list to compare" for d in ds: print d print "result after merge" for k, v in r.iteritems(): print("%s: %s" % (k, v))

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  • Assessing elements in plist iphone sdk

    - by quky
    ok i have a plist like this ` <dict> <key>Rows</key> <array> <dict> <key>WireSize</key> <string>16 AWG</string> <key>Children</key> <array> <dict> <key>Cooper 60°C (140°F)</key> <string>0</string> </dict> <dict> <key>Cooper 75°C (167°F)</key> <string>0</string> </dict> <dict> <key>Cooper 90°C (194°F)</key> <string>14</string> </dict> <dict> <key>Aluminum 60°C (140°F)</key> <string>0</string> </dict> <dict> <key>Aluminum 75°C (167°F)</key> <string>0</string> </dict> <dict> <key>Aluminum 90°C (194°F)</key> <string>0</string> </dict> </array> </dict> <dict> <key>WireSize</key> <string>16 AWG</string> <key>Children</key> <array> <dict> <key>Cooper 60°C (140°F)</key> <string>0</string> </dict> <dict> <key>Cooper 75°C (167°F)</key> <string>0</string> </dict> <dict> <key>Cooper 90°C (194°F)</key> <string>14</string> </dict> <dict> <key>Aluminum 60°C (140°F)</key> <string>0</string> </dict> <dict> <key>Aluminum 75°C (167°F)</key> <string>0</string> </dict> <dict> <key>Aluminum 90°C (194°F)</key> <string>0</string> </dict> </array> </dict> </array> ` and been trying to read the values from it but not success i am using this code enter NSBundle *bundle = [NSBundle mainBundle]; NSString *plistPath = [bundle pathForResource:@"Table 310-16" ofType:@"plist"]; NSDictionary *dictionary = [[NSDictionary alloc] initWithContentsOfFile:plistPath]; for (id key in dictionary) { NSArray *array = [dictionary objectForKey:key]; NSLog(@"key: %@, value: %@", key, [array objectAtIndex:0]); } here and the results are key: Rows, value: { Children = ( { "Cooper 60\U00b0C (140\U00b0F)" = 0; }, { "Cooper 75\U00b0C (167\U00b0F)" = 0; }, { "Cooper 90\U00b0C (194\U00b0F)" = 14; }, { "Aluminum 60\U00b0C (140\U00b0F)" = 0; }, { "Aluminum 75\U00b0C (167\U00b0F)" = 0; }, { "Aluminum 90\U00b0C (194\U00b0F)" = 0; } ); WireSize = "16 AWG"; } but still don't know how to get and specific value for example Aluminum 60°C (140°F) or 14 or 16 AWG any help would be appresiated HP

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  • Convert sqlalchemy row object to python dict

    - by Anurag Uniyal
    or a simple way to iterate over columnName, value pairs? My version of sqlalchemy is 0.5.6 Here is the sample code where I tried using dict(row), but it throws exception , TypeError: 'User' object is not iterable import sqlalchemy from sqlalchemy import * from sqlalchemy.ext.declarative import declarative_base from sqlalchemy.orm import sessionmaker print "sqlalchemy version:",sqlalchemy.__version__ engine = create_engine('sqlite:///:memory:', echo=False) metadata = MetaData() users_table = Table('users', metadata, Column('id', Integer, primary_key=True), Column('name', String), ) metadata.create_all(engine) class User(declarative_base()): __tablename__ = 'users' id = Column(Integer, primary_key=True) name = Column(String) def __init__(self, name): self.name = name Session = sessionmaker(bind=engine) session = Session() user1 = User("anurag") session.add(user1) session.commit() # uncommenting next line throws exception 'TypeError: 'User' object is not iterable' #print dict(user1) # this one also throws 'TypeError: 'User' object is not iterable' for u in session.query(User).all(): print dict(u) Running this code on my system outputs: sqlalchemy version: 0.5.6 Traceback (most recent call last): File "untitled-1.py", line 37, in <module> print dict(u) TypeError: 'User' object is not iterable

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  • class, dict, self, init, args ?

    - by kame
    class attrdict(dict): def __init__(self, *args, **kwargs): dict.__init__(self, *args, **kwargs) self.__dict__ = self a = attrdict(x=1, y=2) print a.x, a.y b = attrdict() b.x, b.y = 1, 2 print b.x, b.y Could somebody explain the first four lines in words? I read about classes and methods. But here it seems very confusing.

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  • Pythonic / itertools way to go through a dict?

    - by dmd
    def reportCSV(t): ret = '' for ev in t: for p in t[ev]: for w in t[ev][p]: ret += ','.join((ev, p, w, t[ev][p][w])) + '\n' return ret What is a more pythonic way to do this, e.g. using itertools or the like? In this case I'm just writing it out to a CSV file. t is a dict t[ev] is a dict t[ev][p] is a dict t[ev][p][w] is a float I'm not sure how I'd use itertools.product in this case.

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  • Can't iterate over nestled dict in django

    - by fredrik
    Hi, Im trying to iterate over a nestled dict list. The first level works fine. But the second level is treated like a string not dict. In my template I have this: {% for product in Products %} <li> <p>{{ product }}</p> {% for partType in product.parts %} <p>{{ partType }}</p> {% for part in partType %} <p>{{ part }}</p> {% endfor %} {% endfor %} </li> {% endfor %} It's the {{ part }} that just list 1 char at the time based on partType. And it seams that it's treated like a string. I can however via dot notation reach all dict but not with a for loop. The current output looks like this: Color C o l o r Style S ..... The Products object looks like this in the log: [{'product': <models.Products.Product object at 0x1076ac9d0>, 'parts': {u'Color': {'default': u'Red', 'optional': [u'Red', u'Blue']}, u'Style': {'default': u'Nice', 'optional': [u'Nice']}, u'Size': {'default': u'8', 'optional': [u'8', u'8.5']}}}] What I trying to do is to pair together a dict/list for a product from a number of different SQL queries. The web handler looks like this: typeData = Products.ProductPartTypes.all() productData = Products.Product.all() langCode = 'en' productList = [] for product in productData: typeDict = {} productDict = {} for type in typeData: typeDict[type.typeId] = { 'default' : '', 'optional' : [] } productDict['product'] = product productDict['parts'] = typeDict defaultPartsData = Products.ProductParts.gql('WHERE __key__ IN :key', key = product.defaultParts) optionalPartsData = Products.ProductParts.gql('WHERE __key__ IN :key', key = product.optionalParts) for defaultPart in defaultPartsData: label = Products.ProductPartLabels.gql('WHERE __key__ IN :key AND partLangCode = :langCode', key = defaultPart.partLabelList, langCode = langCode).get() productDict['parts'][defaultPart.type.typeId]['default'] = label.partLangLabel for optionalPart in optionalPartsData: label = Products.ProductPartLabels.gql('WHERE __key__ IN :key AND partLangCode = :langCode', key = optionalPart.partLabelList, langCode = langCode).get() productDict['parts'][optionalPart.type.typeId]['optional'].append(label.partLangLabel) productList.append(productDict) logging.info(productList) templateData = { 'Languages' : Settings.Languges.all().order('langCode'), 'ProductPartTypes' : typeData, 'Products' : productList } I've tried making the dict in a number of different ways. Like first making a list, then a dict, used tulpes anything I could think of. Any help is welcome! Bouns: If someone have an other approach to the SQL quires, that is more then welcome. I feel that it kinda stupid to run that amount of quires. What is happening that each product part has a different label base on langCode. ..fredrik

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  • Python - Checking for membership inside nested dict

    - by victorhooi
    heya, This is a followup questions to this one: http://stackoverflow.com/questions/2901422/python-dictreader-skipping-rows-with-missing-columns Turns out I was being silly, and using the wrong ID field. I'm using Python 3.x here. I have a dict of employees, indexed by a string, "directory_id". Each value is a nested dict with employee attributes (phone number, surname etc.). One of these values is a secondary ID, say "internal_id", and another is their manager, call it "manager_internal_id". The "internal_id" field is non-mandatory, and not every employee has one. (I've simplified the fields a little, both to make it easier to read, and also for privacy/compliance reasons). The issue here is that we index (key) each employee by their directory_id, but when we lookup their manager, we need to find managers by their "internal_id". Before, when employee.keys() was a list of internal_ids, I was using a membership check on this. Now, the last part of my if statement won't work, since the internal_ids is part of the dict values, instead of the key itself. def lookup_supervisor(manager_internal_id, employees): if manager_internal_idis not None and manager_internal_id!= "" and manager_internal_id in employees.keys(): return (employees[manager_internal_id]['mail'], employees[manager_internal_id]['givenName'], employees[manager_internal_id]['sn']) else: return ('Supervisor Not Found', 'Supervisor Not Found', 'Supervisor Not Found') So the first question is, how do I check whether the manager_internal_id is present in the dict's values. I've tried substituting employee.keys() with employee.values(), that didn't work. Also, I'm hoping for something a little more efficient, not sure if there's a way to get a subset of the values, specifically, all the entries for employees[directory_id]['internal_id']. Hopefully there's some Pythonic way of doing this, without using a massive heap of nested for/if loops. My second question is, how do I then cleanly return the required employee attributes (mail, givenname, surname etc.). My for loop is iterating over each employee, and calling lookup_supervisor. I'm feeling a bit stupid/stumped here. def tidy_data(employees): for directory_id, data in employees.items(): # We really shouldnt' be passing employees back and forth like this - hmm, classes? data['SupervisorEmail'], data['SupervisorFirstName'], data['SupervisorSurname'] = lookup_supervisor(data['manager_internal_id'], employees) Thanks in advance =), Victor

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  • Python nested dict comprehension with sets

    - by Jasie
    Can someone explain how to do nested dict comprehensions? >> l = [set([1, 2, 3]), set([4, 5, 6])] >> j = dict((a, i) for a in s for i, s in enumerate(l)) >> NameError: name 's' is not defined I would have liked: >> j >> {1:0, 2:0, 3:0, 4: 1, 5: 1, 6: 1} I just asked a previous question about a simpler dict comprehension where the parentheses in the generator function were reduced. How come the s in the leftmost comprehension is not recognized?

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  • Iterate over a dict or list in Python

    - by Chris Dutrow
    Just wrote some nasty code that iterates over a dict or a list in Python. I have a feeling this was not the best way to go about it. The problem is that in order to iterate over a dict, this is the convention: for key in dict_object: dict_object[key] = 1 But modifying the object properties by key does not work if the same thing is done on a list: # Throws an error because the value of key is the property value, not # the list index: for key in list_object: list_object[key] = 1 The way I solved this problem was to write this nasty code: if isinstance(obj, dict): for key in obj: do_loop_contents(obj, key) elif isinstance(obj, list): for i in xrange(0, len(obj)): do_loop_contents(obj, i) def do_loop_contents(obj, key): obj[key] = 1 Is there a better way to do this? Thanks!

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  • Memory efficient int-int dict in Python

    - by Bolo
    Hi, I need a memory efficient int-int dict in Python that would support the following operations in O(log n) time: d[k] = v # replace if present v = d[k] # None or a negative number if not present I need to hold ~250M pairs, so it really has to be tight. Do you happen to know a suitable implementation (Python 2.7)? EDIT Removed impossible requirement and other nonsense. Thanks, Craig and Kylotan! To rephrase. Here's a trivial int-int dictionary with 1M pairs: >>> import random, sys >>> from guppy import hpy >>> h = hpy() >>> h.setrelheap() >>> d = {} >>> for _ in xrange(1000000): ... d[random.randint(0, sys.maxint)] = random.randint(0, sys.maxint) ... >>> h.heap() Partition of a set of 1999530 objects. Total size = 49161112 bytes. Index Count % Size % Cumulative % Kind (class / dict of class) 0 1 0 25165960 51 25165960 51 dict (no owner) 1 1999521 100 23994252 49 49160212 100 int On average, a pair of integers uses 49 bytes. Here's an array of 2M integers: >>> import array, random, sys >>> from guppy import hpy >>> h = hpy() >>> h.setrelheap() >>> a = array.array('i') >>> for _ in xrange(2000000): ... a.append(random.randint(0, sys.maxint)) ... >>> h.heap() Partition of a set of 14 objects. Total size = 8001108 bytes. Index Count % Size % Cumulative % Kind (class / dict of class) 0 1 7 8000028 100 8000028 100 array.array On average, a pair of integers uses 8 bytes. I accept that 8 bytes/pair in a dictionary is rather hard to achieve in general. Rephrased question: is there a memory-efficient implementation of int-int dictionary that uses considerably less than 49 bytes/pair?

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