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  • Returning a CSS element

    - by TMP
    Is there a way to return a CSS element? I was using Adobe Edge and adding some of my own code in their code tab, but in order to create boundaries I would need to keep track of margin-top or margin-left. The following code works to move the element "woo" but I'm not sure how to call the elements to add something like "|| sym.$("woo").css({"margin-left"0px"}) to the move left code. //Move RIGHT if (e.which == 39) { sym.$("woo").css({"margin-left":"+=10px"}); } //Move UP else if (e.which == 38) { sym.$("woo").css({"margin-top":"-=10px"}); } //Move Left else if (e.which == 37) { sym.$("woo").css({"margin-left":"-=10px"}); } //Move DOWN else if (e.which == 40) { sym.$("woo").css({"margin-top":"+=10px"}); } EDIT: I changed the Left if statement to the following: else if (e.which == 37 && ($("woo").css("margin-left")>0)) { It seems to be working to some extent except for now it won't move left at all! I tried doing <0 too in case I was screwing up a sign but it won't let me move the element left either.

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  • How to detect if breaking an edge will make a graph disjoint?

    - by the_graph_guy
    I have a graph that starts off with a single, root node. Nodes are added one by one to the graph. At node creation time, they have to be linked either to the root node, or to another node, by a single edge. Edges can also be created and deleted (one by one, between any two nodes). Nodes can be deleted one at a time. Node and edge creation, deletion operations can happen in any arbitrary order. OK, so here's my question: When an edge is deleted, is it possible do determine, in constant time (i.e. with an O(1) algorithm), if doing this will divide the graph into two disjoint subgraphs? If it will, then which side of the edge will the root node belong? I'm willing to maintain, within reasonable limits, any additional data structure that can facilitate the derivation of this information. Maybe it is not possible to do it in O(1), if so any pointers to literature will be appreciated.

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  • output image is not displayed

    - by gerry chocolatos
    so, im doing an image detection which i have to process on each red, green, n blue element to get the edge map and combine them become one to show the output. but it doesnt show my output image would anyone pls be kind enough to help me? here is my code so far. //get the red element process_red = new int[width * height]; counter = 0; for(int i = 0; i < 256; i++) { for(int j = 0; j < 256; j++) { int clr = buff_red.getRGB(j, i); int red = (clr & 0x00ff0000) >> 16; red = (0xFF<<24)|(red<<16)|(red<<8)|red; process_red[counter] = red; counter++; } } //set threshold value for red element int threshold = 100; for (int x = 0; x < width; x++) { for (int y = 0; y < height; y++) { int bin = (buff_red.getRGB(x, y) & 0x000000ff); if (bin < threshold) bin = 0; else bin = 255; buff_red.setRGB(x,y, 0xff000000 | bin << 16 | bin << 8 | bin); } } and i do the same way for my green n blue elements. and then i wanted to get to combination of the three by doing it this way: //combine the three elements process_combine = new int[width * height]; counter = 0; for(int i = 0; i < 256; i++) { for(int j = 0; j < 256; j++) { int clr_a = buff_red.getRGB(j, i); int ar = clr_a & 0x000000ff; int clr_b = buff_green.getRGB(j, i); int bg = clr_b & 0x000000ff; int clr_c = buff_blue.getRGB(j, i); int cb = clr_b & 0x000000ff; int alpha = 0xff000000; int combine = alpha|(ar<<16)|(bg<<8)|cb; process_combine[counter] = combine; counter++; } } buff_rgb = new BufferedImage(width,height, BufferedImage.TYPE_INT_ARGB); Graphics rgb; rgb = buff_rgb.getGraphics(); rgb.drawImage(output_rgb, 0, 0, null); rgb.dispose(); repaint(); and to show the output whic is from the combining process, i use a draw method: g.drawImage(buff_rgb,800,100,this); but still it doesnt show the image. can anyone pls help me? ur help is really appreciated. thanks.

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  • Redirect email based on Source IP / Hostname

    - by PostMan
    So, we have a situation where we would like to be able to redirect (ignoring original destination) emails coming through out exchange server (locally sent) to a different email address. The situation is as follows: Testing a new server, this hosts a lot of our custom applications / scheduled tasks (as does the production version of this server). Instead of changing config files / parameters for these applications we'd rather leave them as they are, as we want to be as close to production as possible, however we don't want the emails go to the staff they would normally go to, we'd rather they were sent to a test email address where we are able to confirm the results. The emails look exactly like the production emails (same from / to / cc / bcc) except their source, hence why we'd like to know if the ability to redirect based on hostname exists. Cheers.

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  • evaluating a code of a graph [migrated]

    - by mazen.r.f
    This is relatively a long code,if you have the tolerance and the will to find out how to make this code work then take a look please, i will appreciate your feed back. i have spent two days trying to come up with a code to represent a graph , then calculate the shortest path using dijkastra algorithm , but i am not able to get the right result , even the code runs without errors , but the result is not correct , always i am getting 0. briefly,i have three classes , Vertex, Edge, Graph , the Vertex class represents the nodes in the graph and it has id and carried ( which carry the weight of the links connected to it while using dijkastra algorithm ) and a vector of the ids belong to other nodes the path will go through before arriving to the node itself , this vector is named previous_nodes. the Edge class represents the edges in the graph it has two vertices ( one in each side ) and a wight ( the distance between the two vertices ). the Graph class represents the graph , it has two vectors one is the vertices included in this graph , and the other is the edges included in the graph. inside the class Graph there is a method its name shortest takes the sources node id and the destination and calculates the shortest path using dijkastra algorithm, and i think that it is the most important part of the code. my theory about the code is that i will create two vectors one for the vertices in the graph i will name it vertices and another vector its name is ver_out it will include the vertices out of calculation in the graph, also i will have two vectors of type Edge , one its name edges for all the edges in the graph and the other its name is track to contain temporarily the edges linked to the temporarily source node in every round , after the calculation of every round the vector track will be cleared. in main() i created five vertices and 10 edges to simulate a graph , the result of the shortest path supposedly to be 4 , but i am always getting 0 , that means i am having something wrong in my code , so if you are interesting in helping me find my mistake and how to make the code work , please take a look. the way shortest work is as follow at the beginning all the edges will be included in the vector edges , we select the edges related to the source and put them in the vector track , then we iterate through track and add the wight of every edge to the vertex (node ) related to it ( not the source vertex ) , then after we clear track and remove the source vertex from the vector vertices and select a new source , and start over again select the edges related to the new source , put them in track , iterate over edges in tack , adding the weights to the corresponding vertices then remove this vertex from the vector vertices, and clear track , and select a new source , and so on . here is the code. #include<iostream> #include<vector> #include <stdlib.h> // for rand() using namespace std; class Vertex { private: unsigned int id; // the name of the vertex unsigned int carried; // the weight a vertex may carry when calculating shortest path vector<unsigned int> previous_nodes; public: unsigned int get_id(){return id;}; unsigned int get_carried(){return carried;}; void set_id(unsigned int value) {id = value;}; void set_carried(unsigned int value) {carried = value;}; void previous_nodes_update(unsigned int val){previous_nodes.push_back(val);}; void previous_nodes_erase(unsigned int val){previous_nodes.erase(previous_nodes.begin() + val);}; Vertex(unsigned int init_val = 0, unsigned int init_carried = 0) :id (init_val), carried(init_carried) // constructor { } ~Vertex() {}; // destructor }; class Edge { private: Vertex first_vertex; // a vertex on one side of the edge Vertex second_vertex; // a vertex on the other side of the edge unsigned int weight; // the value of the edge ( or its weight ) public: unsigned int get_weight() {return weight;}; void set_weight(unsigned int value) {weight = value;}; Vertex get_ver_1(){return first_vertex;}; Vertex get_ver_2(){return second_vertex;}; void set_first_vertex(Vertex v1) {first_vertex = v1;}; void set_second_vertex(Vertex v2) {second_vertex = v2;}; Edge(const Vertex& vertex_1 = 0, const Vertex& vertex_2 = 0, unsigned int init_weight = 0) : first_vertex(vertex_1), second_vertex(vertex_2), weight(init_weight) { } ~Edge() {} ; // destructor }; class Graph { private: std::vector<Vertex> vertices; std::vector<Edge> edges; public: Graph(vector<Vertex> ver_vector, vector<Edge> edg_vector) : vertices(ver_vector), edges(edg_vector) { } ~Graph() {}; vector<Vertex> get_vertices(){return vertices;}; vector<Edge> get_edges(){return edges;}; void set_vertices(vector<Vertex> vector_value) {vertices = vector_value;}; void set_edges(vector<Edge> vector_ed_value) {edges = vector_ed_value;}; unsigned int shortest(unsigned int src, unsigned int dis) { vector<Vertex> ver_out; vector<Edge> track; for(unsigned int i = 0; i < edges.size(); ++i) { if((edges[i].get_ver_1().get_id() == vertices[src].get_id()) || (edges[i].get_ver_2().get_id() == vertices[src].get_id())) { track.push_back (edges[i]); edges.erase(edges.begin()+i); } }; for(unsigned int i = 0; i < track.size(); ++i) { if(track[i].get_ver_1().get_id() != vertices[src].get_id()) { track[i].get_ver_1().set_carried((track[i].get_weight()) + track[i].get_ver_2().get_carried()); track[i].get_ver_1().previous_nodes_update(vertices[src].get_id()); } else { track[i].get_ver_2().set_carried((track[i].get_weight()) + track[i].get_ver_1().get_carried()); track[i].get_ver_2().previous_nodes_update(vertices[src].get_id()); } } for(unsigned int i = 0; i < vertices.size(); ++i) if(vertices[i].get_id() == src) vertices.erase(vertices.begin() + i); // removing the sources vertex from the vertices vector ver_out.push_back (vertices[src]); track.clear(); if(vertices[0].get_id() != dis) {src = vertices[0].get_id();} else {src = vertices[1].get_id();} for(unsigned int i = 0; i < vertices.size(); ++i) if((vertices[i].get_carried() < vertices[src].get_carried()) && (vertices[i].get_id() != dis)) src = vertices[i].get_id(); //while(!edges.empty()) for(unsigned int round = 0; round < vertices.size(); ++round) { for(unsigned int k = 0; k < edges.size(); ++k) { if((edges[k].get_ver_1().get_id() == vertices[src].get_id()) || (edges[k].get_ver_2().get_id() == vertices[src].get_id())) { track.push_back (edges[k]); edges.erase(edges.begin()+k); } }; for(unsigned int n = 0; n < track.size(); ++n) if((track[n].get_ver_1().get_id() != vertices[src].get_id()) && (track[n].get_ver_1().get_carried() > (track[n].get_ver_2().get_carried() + track[n].get_weight()))) { track[n].get_ver_1().set_carried((track[n].get_weight()) + track[n].get_ver_2().get_carried()); track[n].get_ver_1().previous_nodes_update(vertices[src].get_id()); } else if(track[n].get_ver_2().get_carried() > (track[n].get_ver_1().get_carried() + track[n].get_weight())) { track[n].get_ver_2().set_carried((track[n].get_weight()) + track[n].get_ver_1().get_carried()); track[n].get_ver_2().previous_nodes_update(vertices[src].get_id()); } for(unsigned int t = 0; t < vertices.size(); ++t) if(vertices[t].get_id() == src) vertices.erase(vertices.begin() + t); track.clear(); if(vertices[0].get_id() != dis) {src = vertices[0].get_id();} else {src = vertices[1].get_id();} for(unsigned int tt = 0; tt < edges.size(); ++tt) { if(vertices[tt].get_carried() < vertices[src].get_carried()) { src = vertices[tt].get_id(); } } } return vertices[dis].get_carried(); } }; int main() { cout<< "Hello, This is a graph"<< endl; vector<Vertex> vers(5); vers[0].set_id(0); vers[1].set_id(1); vers[2].set_id(2); vers[3].set_id(3); vers[4].set_id(4); vector<Edge> eds(10); eds[0].set_first_vertex(vers[0]); eds[0].set_second_vertex(vers[1]); eds[0].set_weight(5); eds[1].set_first_vertex(vers[0]); eds[1].set_second_vertex(vers[2]); eds[1].set_weight(9); eds[2].set_first_vertex(vers[0]); eds[2].set_second_vertex(vers[3]); eds[2].set_weight(4); eds[3].set_first_vertex(vers[0]); eds[3].set_second_vertex(vers[4]); eds[3].set_weight(6); eds[4].set_first_vertex(vers[1]); eds[4].set_second_vertex(vers[2]); eds[4].set_weight(2); eds[5].set_first_vertex(vers[1]); eds[5].set_second_vertex(vers[3]); eds[5].set_weight(5); eds[6].set_first_vertex(vers[1]); eds[6].set_second_vertex(vers[4]); eds[6].set_weight(7); eds[7].set_first_vertex(vers[2]); eds[7].set_second_vertex(vers[3]); eds[7].set_weight(1); eds[8].set_first_vertex(vers[2]); eds[8].set_second_vertex(vers[4]); eds[8].set_weight(8); eds[9].set_first_vertex(vers[3]); eds[9].set_second_vertex(vers[4]); eds[9].set_weight(3); unsigned int path; Graph graf(vers, eds); path = graf.shortest(2, 4); cout<< path << endl; return 0; }

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  • Evaluating code for a graph [migrated]

    - by mazen.r.f
    This is relatively long code. Please take a look at this code if you are still willing to do so. I will appreciate your feedback. I have spent two days trying to come up with code to represent a graph, calculating the shortest path using Dijkstra's algorithm. But I am not able to get the right result, even though the code runs without errors. The result is not correct and I am always getting 0. I have three classes: Vertex, Edge, and Graph. The Vertex class represents the nodes in the graph and it has id and carried (which carry the weight of the links connected to it while using Dijkstra's algorithm) and a vector of the ids belong to other nodes the path will go through before arriving to the node itself. This vector is named previous_nodes. The Edge class represents the edges in the graph and has two vertices (one in each side) and a width (the distance between the two vertices). The Graph class represents the graph. It has two vectors, where one is the vertices included in this graph, and the other is the edges included in the graph. Inside the class Graph, there is a method named shortest() that takes the sources node id and the destination and calculates the shortest path using Dijkstra's algorithm. I think that it is the most important part of the code. My theory about the code is that I will create two vectors, one for the vertices in the graph named vertices, and another vector named ver_out (it will include the vertices out of calculation in the graph). I will also have two vectors of type Edge, where one is named edges (for all the edges in the graph), and the other is named track (to temporarily contain the edges linked to the temporary source node in every round). After the calculation of every round, the vector track will be cleared. In main(), I've created five vertices and 10 edges to simulate a graph. The result of the shortest path supposedly is 4, but I am always getting 0. That means I have something wrong in my code. If you are interesting in helping me find my mistake and making the code work, please take a look. The way shortest work is as follow: at the beginning, all the edges will be included in the vector edges. We select the edges related to the source and put them in the vector track, then we iterate through track and add the width of every edge to the vertex (node) related to it (not the source vertex). After that, we clear track and remove the source vertex from the vector vertices and select a new source. Then we start over again and select the edges related to the new source, put them in track, iterate over edges in track, adding the weights to the corresponding vertices, then remove this vertex from the vector vertices. Then clear track, and select a new source, and so on. #include<iostream> #include<vector> #include <stdlib.h> // for rand() using namespace std; class Vertex { private: unsigned int id; // the name of the vertex unsigned int carried; // the weight a vertex may carry when calculating shortest path vector<unsigned int> previous_nodes; public: unsigned int get_id(){return id;}; unsigned int get_carried(){return carried;}; void set_id(unsigned int value) {id = value;}; void set_carried(unsigned int value) {carried = value;}; void previous_nodes_update(unsigned int val){previous_nodes.push_back(val);}; void previous_nodes_erase(unsigned int val){previous_nodes.erase(previous_nodes.begin() + val);}; Vertex(unsigned int init_val = 0, unsigned int init_carried = 0) :id (init_val), carried(init_carried) // constructor { } ~Vertex() {}; // destructor }; class Edge { private: Vertex first_vertex; // a vertex on one side of the edge Vertex second_vertex; // a vertex on the other side of the edge unsigned int weight; // the value of the edge ( or its weight ) public: unsigned int get_weight() {return weight;}; void set_weight(unsigned int value) {weight = value;}; Vertex get_ver_1(){return first_vertex;}; Vertex get_ver_2(){return second_vertex;}; void set_first_vertex(Vertex v1) {first_vertex = v1;}; void set_second_vertex(Vertex v2) {second_vertex = v2;}; Edge(const Vertex& vertex_1 = 0, const Vertex& vertex_2 = 0, unsigned int init_weight = 0) : first_vertex(vertex_1), second_vertex(vertex_2), weight(init_weight) { } ~Edge() {} ; // destructor }; class Graph { private: std::vector<Vertex> vertices; std::vector<Edge> edges; public: Graph(vector<Vertex> ver_vector, vector<Edge> edg_vector) : vertices(ver_vector), edges(edg_vector) { } ~Graph() {}; vector<Vertex> get_vertices(){return vertices;}; vector<Edge> get_edges(){return edges;}; void set_vertices(vector<Vertex> vector_value) {vertices = vector_value;}; void set_edges(vector<Edge> vector_ed_value) {edges = vector_ed_value;}; unsigned int shortest(unsigned int src, unsigned int dis) { vector<Vertex> ver_out; vector<Edge> track; for(unsigned int i = 0; i < edges.size(); ++i) { if((edges[i].get_ver_1().get_id() == vertices[src].get_id()) || (edges[i].get_ver_2().get_id() == vertices[src].get_id())) { track.push_back (edges[i]); edges.erase(edges.begin()+i); } }; for(unsigned int i = 0; i < track.size(); ++i) { if(track[i].get_ver_1().get_id() != vertices[src].get_id()) { track[i].get_ver_1().set_carried((track[i].get_weight()) + track[i].get_ver_2().get_carried()); track[i].get_ver_1().previous_nodes_update(vertices[src].get_id()); } else { track[i].get_ver_2().set_carried((track[i].get_weight()) + track[i].get_ver_1().get_carried()); track[i].get_ver_2().previous_nodes_update(vertices[src].get_id()); } } for(unsigned int i = 0; i < vertices.size(); ++i) if(vertices[i].get_id() == src) vertices.erase(vertices.begin() + i); // removing the sources vertex from the vertices vector ver_out.push_back (vertices[src]); track.clear(); if(vertices[0].get_id() != dis) {src = vertices[0].get_id();} else {src = vertices[1].get_id();} for(unsigned int i = 0; i < vertices.size(); ++i) if((vertices[i].get_carried() < vertices[src].get_carried()) && (vertices[i].get_id() != dis)) src = vertices[i].get_id(); //while(!edges.empty()) for(unsigned int round = 0; round < vertices.size(); ++round) { for(unsigned int k = 0; k < edges.size(); ++k) { if((edges[k].get_ver_1().get_id() == vertices[src].get_id()) || (edges[k].get_ver_2().get_id() == vertices[src].get_id())) { track.push_back (edges[k]); edges.erase(edges.begin()+k); } }; for(unsigned int n = 0; n < track.size(); ++n) if((track[n].get_ver_1().get_id() != vertices[src].get_id()) && (track[n].get_ver_1().get_carried() > (track[n].get_ver_2().get_carried() + track[n].get_weight()))) { track[n].get_ver_1().set_carried((track[n].get_weight()) + track[n].get_ver_2().get_carried()); track[n].get_ver_1().previous_nodes_update(vertices[src].get_id()); } else if(track[n].get_ver_2().get_carried() > (track[n].get_ver_1().get_carried() + track[n].get_weight())) { track[n].get_ver_2().set_carried((track[n].get_weight()) + track[n].get_ver_1().get_carried()); track[n].get_ver_2().previous_nodes_update(vertices[src].get_id()); } for(unsigned int t = 0; t < vertices.size(); ++t) if(vertices[t].get_id() == src) vertices.erase(vertices.begin() + t); track.clear(); if(vertices[0].get_id() != dis) {src = vertices[0].get_id();} else {src = vertices[1].get_id();} for(unsigned int tt = 0; tt < edges.size(); ++tt) { if(vertices[tt].get_carried() < vertices[src].get_carried()) { src = vertices[tt].get_id(); } } } return vertices[dis].get_carried(); } }; int main() { cout<< "Hello, This is a graph"<< endl; vector<Vertex> vers(5); vers[0].set_id(0); vers[1].set_id(1); vers[2].set_id(2); vers[3].set_id(3); vers[4].set_id(4); vector<Edge> eds(10); eds[0].set_first_vertex(vers[0]); eds[0].set_second_vertex(vers[1]); eds[0].set_weight(5); eds[1].set_first_vertex(vers[0]); eds[1].set_second_vertex(vers[2]); eds[1].set_weight(9); eds[2].set_first_vertex(vers[0]); eds[2].set_second_vertex(vers[3]); eds[2].set_weight(4); eds[3].set_first_vertex(vers[0]); eds[3].set_second_vertex(vers[4]); eds[3].set_weight(6); eds[4].set_first_vertex(vers[1]); eds[4].set_second_vertex(vers[2]); eds[4].set_weight(2); eds[5].set_first_vertex(vers[1]); eds[5].set_second_vertex(vers[3]); eds[5].set_weight(5); eds[6].set_first_vertex(vers[1]); eds[6].set_second_vertex(vers[4]); eds[6].set_weight(7); eds[7].set_first_vertex(vers[2]); eds[7].set_second_vertex(vers[3]); eds[7].set_weight(1); eds[8].set_first_vertex(vers[2]); eds[8].set_second_vertex(vers[4]); eds[8].set_weight(8); eds[9].set_first_vertex(vers[3]); eds[9].set_second_vertex(vers[4]); eds[9].set_weight(3); unsigned int path; Graph graf(vers, eds); path = graf.shortest(2, 4); cout<< path << endl; return 0; }

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  • Showing Egde Shaped Event Duration in StreamInsight using Debugger

    Whilst writing some courseware I wanted to be able to see the start and end times of Edge shaped events from within the debugger.  A quick recap on Edge events At the start of the event you do not know the end time and most probably cannot work it out or you should be using one of the other shapes. You enqueue an event (Start Edge) with the start time and payload of the event.  The end time of the event is set to infinity When you see the end edge come through, you enqueue another event (End Edge) with the previous start time and payload and restate the event’s end time.  This is the Retract Event All seems simple enough.  The problem is the debugger is a little shy about showing you what you need but you can get it to show you everything by also reading this article Here’s what I mean. Here is what the Event Debugger looks like by default when viewing 2 complete edge events.  Notice how all the end times are set to infinity   The above does not tell you for how long an event was valid.  I then add the “NewEndTime” column to the debugger output and there I can now see the duration of events.  You will see the Retract events (End Edge) have the same start time and payload as their respective start events (Start Edge)   You can follow the exact same logic when looking at Interval shape events.  They look a little different on the output adapter but using this article you can easily see what is happening.

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  • XNA Diffuse Shader Issue. Edge lighting problem. Image Attached

    - by adtither
    As you can see in this image the diffuse shading is working correctly in some places but in other places such as the the bottom of the sphere you can see the squares/triangles of the mesh. Any idea what would be causing this? Let me know if you need anymore information related to code. I can upload my normals calculations and shader effect if required. EDIT: Here's a link to the shader I'm using http://pastebin.com/gymVc7CP Link to normals calculations: http://pastebin.com/KnMGdzHP Seems to be an issue with edge lighting. Can't seem to see where I'm going wrong with the normals calculations though.

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  • How to adjust TouchPad edge scroll area in Ubuntu?

    - by MikeVB
    I have an Acer Aspire that I have dual booting XP and Ubuntu. On the Windows side, the driver allows you to set how close your finger has to be to the edge of the TouchPad before it goes into scroll mode. In Ubuntu I don't have the option (at least in the GUI) to change the scroll area on the pad. Is there a conf file or other way to change this? I'm constantly getting into the scroll area during normal usage. I would like to leave it on without losing so much pad area to the scroll feature.

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  • Is there anyone with an Thinkpad Edge E320 with working Fn-Keys?

    - by Wauzl
    I recently bought a new Lenovo ThinkPad Edge E320. I'm having trouble with my Fn-Keys. The ones for Sound, Brightness and MUltimedia work but those that toggle Wifi/Bluetooth, Webcam and Microphone on and off won't. Fortunately the Wifi, Webcam and Mic are enabled by default. My problem is that I can't disable them (which would be nice to know that this works) and that I can't enable Bluetooth. (I checked that my machine has bluetooth support) Can't say if it would work in Windows as I purchased a machine without Windows. Here is my dmesg: http://pastebin.com/gAgYeDG7 Thanks for reading :)

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  • How to find optimal path visit every node with parallel workers complicated by dynamic edge costs?

    - by Aaron Anodide
    Say you have an acyclic directed graph with weighted edges and create N workers. My goal is to calculate the optimal way those workers can traverse the entire graph in parralel. However, edge costs may change along the way. Example: A -1-> B A -2-> C B -3-> C (if A has already been visited) B -5-> C (if A has not already been visited) Does what I describe lend itself to a standard algorithmic approach, or alternately can someone suggest if I'm looking at this in an inherently flawed way (i have an intuition I might be)?

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  • How to configure catch-all in Exchange2010 hub-transport environment?

    - by Itay Levin
    Im getting the delivery failed from the post master reply. i don't want it. because then poeple can find out all my real users on the exchange. also, i have a lot of users (10K) in my application - and i don't want to create a mailbox for each user. is it possible to get this done in ex2010 sp1. hub-transport configuration? or i must use edge-transport as indicated in http://technet.microsoft.com/en-us/library/bb691132(EXCHG.80).aspx

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  • INDY WebService over SSL contains link with HTTP protocol instead of HTTPS in WSDL

    - by user1437820
    When creating new SOAP WebService server project using Delphi XE2 the wizard allows to set change port and HTTPS properties. Port is set to 443, HTTPS flag is checked, but when trying to connect to created server it returns incorrect transport (HTTP instead of HTTPS) in WSDL and generates HTTP links on the Service Info Page. The auto-generated page is not so important, but wrong information in WSDL file is a problem. Below you can see the returned WSDL - there are no HTTPS: <?xml version="1.0"?> <definitions xmlns="http://schemas.xmlsoap.org/wsdl/" xmlns:xs="http://www.w3.org/2001/XMLSchema" name="Itest123service" targetNamespace="http://tempuri.org/" xmlns:tns="http://tempuri.org/" xmlns:soap="http://schemas.xmlsoap.org/wsdl/soap/" xmlns:soapenc="http://schemas.xmlsoap.org/soap/encoding/" xmlns:mime="http://schemas.xmlsoap.org/wsdl/mime/" xmlns:ns1="urn:test123Intf"> <types> <schema xmlns="http://www.w3.org/2001/XMLSchema" targetNamespace="urn:test123Intf"> <simpleType name="TEnumTest"> <restriction base="string"> <enumeration value="etNone"/> <enumeration value="etAFew"/> <enumeration value="etSome"/> <enumeration value="etAlot"/> </restriction> </simpleType> <complexType name="TDoubleArray"> <complexContent> <restriction base="soapenc:Array"> <sequence/> <attribute ref="soapenc:arrayType" n1:arrayType="xs:double[]" xmlns:n1="http://schemas.xmlsoap.org/wsdl/"/> </restriction> </complexContent> </complexType> <complexType name="TMyEmployee"> <sequence> <element name="LastName" type="xs:string"/> <element name="FirstName" type="xs:string"/> <element name="Salary" type="xs:double"/> </sequence> </complexType> </schema> </types> <message name="echoEnum0Request"> <part name="Value" type="ns1:TEnumTest"/> </message> <message name="echoEnum0Response"> <part name="return" type="ns1:TEnumTest"/> </message> <message name="echoDoubleArray1Request"> <part name="Value" type="ns1:TDoubleArray"/> </message> <message name="echoDoubleArray1Response"> <part name="return" type="ns1:TDoubleArray"/> </message> <message name="echoMyEmployee2Request"> <part name="Value" type="ns1:TMyEmployee"/> </message> <message name="echoMyEmployee2Response"> <part name="return" type="ns1:TMyEmployee"/> </message> <message name="echoDouble3Request"> <part name="Value" type="xs:double"/> </message> <message name="echoDouble3Response"> <part name="return" type="xs:double"/> </message> <portType name="Itest123"> <operation name="echoEnum"> <input message="tns:echoEnum0Request"/> <output message="tns:echoEnum0Response"/> </operation> <operation name="echoDoubleArray"> <input message="tns:echoDoubleArray1Request"/> <output message="tns:echoDoubleArray1Response"/> </operation> <operation name="echoMyEmployee"> <input message="tns:echoMyEmployee2Request"/> <output message="tns:echoMyEmployee2Response"/> </operation> <operation name="echoDouble"> <input message="tns:echoDouble3Request"/> <output message="tns:echoDouble3Response"/> </operation> </portType> <binding name="Itest123binding" type="tns:Itest123"> <binding xmlns="http://schemas.xmlsoap.org/wsdl/soap/" style="rpc" transport="http://schemas.xmlsoap.org/soap/http"/> <operation name="echoEnum"> <operation xmlns="http://schemas.xmlsoap.org/wsdl/soap/" soapAction="urn:test123Intf-Itest123#echoEnum" style="rpc"/> <input> <body xmlns="http://schemas.xmlsoap.org/wsdl/soap/" use="encoded" encodingStyle="http://schemas.xmlsoap.org/soap/encoding/" namespace="urn:test123Intf-Itest123"/> </input> <output> <body xmlns="http://schemas.xmlsoap.org/wsdl/soap/" use="encoded" encodingStyle="http://schemas.xmlsoap.org/soap/encoding/" namespace="urn:test123Intf-Itest123"/> </output> </operation> <operation name="echoDoubleArray"> <operation xmlns="http://schemas.xmlsoap.org/wsdl/soap/" soapAction="urn:test123Intf-Itest123#echoDoubleArray" style="rpc"/> <input> <body xmlns="http://schemas.xmlsoap.org/wsdl/soap/" use="encoded" encodingStyle="http://schemas.xmlsoap.org/soap/encoding/" namespace="urn:test123Intf-Itest123"/> </input> <output> <body xmlns="http://schemas.xmlsoap.org/wsdl/soap/" use="encoded" encodingStyle="http://schemas.xmlsoap.org/soap/encoding/" namespace="urn:test123Intf-Itest123"/> </output> </operation> <operation name="echoMyEmployee"> <operation xmlns="http://schemas.xmlsoap.org/wsdl/soap/" soapAction="urn:test123Intf-Itest123#echoMyEmployee" style="rpc"/> <input> <body xmlns="http://schemas.xmlsoap.org/wsdl/soap/" use="encoded" encodingStyle="http://schemas.xmlsoap.org/soap/encoding/" namespace="urn:test123Intf-Itest123"/> </input> <output> <body xmlns="http://schemas.xmlsoap.org/wsdl/soap/" use="encoded" encodingStyle="http://schemas.xmlsoap.org/soap/encoding/" namespace="urn:test123Intf-Itest123"/> </output> </operation> <operation name="echoDouble"> <operation xmlns="http://schemas.xmlsoap.org/wsdl/soap/" soapAction="urn:test123Intf-Itest123#echoDouble" style="rpc"/> <input> <body xmlns="http://schemas.xmlsoap.org/wsdl/soap/" use="encoded" encodingStyle="http://schemas.xmlsoap.org/soap/encoding/" namespace="urn:test123Intf-Itest123"/> </input> <output> <body xmlns="http://schemas.xmlsoap.org/wsdl/soap/" use="encoded" encodingStyle="http://schemas.xmlsoap.org/soap/encoding/" namespace="urn:test123Intf-Itest123"/> </output> </operation> </binding> <service name="Itest123service"> <port name="Itest123Port" binding="tns:Itest123binding"> <address xmlns="http://schemas.xmlsoap.org/wsdl/soap/" location="http://localhost:443/soap/Itest123"/> </port> </service> </definitions> When I'm trying to import WSDL to soapUI tool to check WebService work I need to change manually binding link to "https://" and only then RPCs will work. I will be very grateful for any idea how to force INDY to return links in WSDL with HTTPS protocol. Thanks in advance!

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  • Custom Transport Agent: How do I collect NDRs and all other undeliverables in Exchange 2010 from the Postmaster?

    - by makerofthings7
    I'm trying to collect all NDRs in a single mailbox for all invalid recipients, and anything that fails for any reason. I have a custom transport agent, that I've written myself that appears here: [PS] C:\Windows\system32>Get-TransportAgent Identity Enabled Priority -------- ------- -------- Transport Rule Agent True 1 Text Messaging Routing Agent True 2 Text Messaging Delivery Agent True 3 Routing Rule Agent True 4 **** Sometimes when I run get-messagetrackinglog I get failures like this below RunspaceId : 4ecc61fb-13b9-4506-b680-577222c9bf21 Timestamp : 10/14/2013 12:42:42 PM ClientIp : ClientHostname : Exchange1 ServerIp : ServerHostname : SourceContext : Routing Rule Agent ConnectorId : Source : AGENT EventId : FAIL InternalMessageId : 4416 MessageId : <[email protected]> Recipients : {[email protected]} RecipientStatus : {} TotalBytes : 4542 RecipientCount : 1 RelatedRecipientAddress : Reference : MessageSubject : review CGRC due diligence. Sender : [email protected] ReturnPath : [email protected] MessageInfo : MessageLatency : MessageLatencyType : None EventData : How can I collect the NDRs in a single mailbox for review? I have already set the following command but it is of no effect [PS] C:\>set-TransportConfig -JournalingReportNdrTo [email protected] -ExternalPostmasterAddress [email protected]

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  • Creating an adjacency List for DFS

    - by user200081
    I'm having trouble creating a Depth First Search for my program. So far I have a class of edges and a class of regions. I want to store all the connected edges inside one node of my region. I can tell if something is connected by the getKey() function I have already implemented. If two edges have the same key, then they are connected. For the next region, I want to store another set of connected edges inside that region, etc etc. However, I am not fully understanding DFS and I'm having some trouble implementing it. I'm not sure when/where to call DFS again. Any help would be appreciated! class edge { private: int source, destination, length; int key; edge *next; public: getKey(){ return key; } } class region { edge *data; edge *next; region() { data = new edge(); next = NULL; } }; void runDFS(int i, edge **edge, int a) { region *head = new region(); aa[i]->visited == true;//mark the first vertex as true for(int v = 0; v < a; v++) { if(tem->edge[i].getKey() == tem->edge[v].getKey()) //if the edges of the vertex have the same root { if(head->data == NULL) { head->data = aa[i]; head->data->next == NULL; } //create an edge if(head->data) { head->data->next = aa[i]; head->data->next->next == NULL; }//if there is already a node connected to ti } if(aa[v]->visited == false) runDFS(v, edge, a); //call the DFS again } //for loop }

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  • How can I calculate a vertex normal for a hard edge?

    - by K.G.
    Here is a picture of a lovely polygon: Circled is a vertex, and numbered are its adjacent faces. I have calculated the normals of those faces as such (not yet normalized, 0-indexed): Vertex 1 normal 0: 0.000000 0.000000 -0.250000 Vertex 1 normal 1: 0.000000 0.000000 -0.250000 Vertex 1 normal 2: -0.250000 0.000000 0.000000 Vertex 1 normal 3: -0.250000 0.000000 0.000000 Vertex 1 normal 4: 0.250000 0.000000 0.000000 What I'm wondering is, how can I determine, taken as given that I want this vertex to represent a hard edge, whether its normal should be the normal of 1/2 or 3/4? My plan after I glanced at the sketch I used to put this together was "Ha! I'll just use whichever two faces have the same normal!" and now I see that there are two sets of two faces for which this is true. Is there a rule I can apply based on the face winding, angle of the adjacent edges, moon phase, coin flip, to consistently choose a normal direction for this box? For the record, all of the other polygons I plan to use will have their normals dictated in Maya, but after encountering this problem, it made me really curious.

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  • Black screen with thinkpad edge e525, AMD radeon HD before and after installation, plymouth?

    - by carolien
    I have a new thinkpad edge e525 (which should work) and wanted to try ubuntu (first linux experience). With the ubuntu desktop-cd I had a blackscreen before installation, I could fix that with nomodeset. After the installation, when rebooting I got the black screen again. First I see some ubuntu colour with a green busted stripe. I have the same problem with the live boot, also tried mint live, the stripe gets pink. I installed xubuntu 64bit from an alternate cd and I didnt have problems until de reboot after the installation. Same problem, just a black screen with the green stripe than blackscreen. I tried several things: adding nomodeset to the bootmenu, but than I get: No connection to plymouth and it is stuck at checking the battery status. I tried to replace quiet splash with text. Didnt work either. actually one time I saw a blue booting image before that. I managed to get a root command though via the recovery boot. I didnt dare to just remove the plymouth package. Can I just delete plymouth or do I have to deinstall it as described in several ways. (Problem is, right now the notebook doesnt have a internet connection. And I dont know how to manage it with a usb stick?) Or do I have to install the AMD catalyst driver manually? (Again, how can I do that with an usb stick) I also tried this: Ubuntu hits a black screen after boot. Is there any solution without internet? And if I need internet which is the right one? Please explain step by step what I have to write and so on! Thank you! also tried: set gfxpayload=text and: just remove splash and adding vesafb.nonsense=1 to the grub editor, because I couldnt find it anywhere

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  • How to determine edges in an images optimally?

    - by SorinA.
    I recently was put in front of the problem of cropping and resizing images. I needed to crop the 'main content' of an image for example if i had an image similar to this: the result should be an image with the msn content without the white margins(left& right). I search on the X axis for the first and last color change and on the Y axis the same thing. The problem is that traversing the image line by line takes a while..for an image that is 2000x1600px it takes up to 2 seconds to return the CropRect = x1,y1,x2,y2 data. I tried to make for each coordinate a traversal and stop on the first value found but it didn't work in all test cases..sometimes the returned data wasn't the expected one and the duration of the operations was similar.. Any idea how to cut down the traversal time and discovery of the rectangle round the 'main content'? public static CropRect EdgeDetection(Bitmap Image, float Threshold) { CropRect cropRectangle = new CropRect(); int lowestX = 0; int lowestY = 0; int largestX = 0; int largestY = 0; lowestX = Image.Width; lowestY = Image.Height; //find the lowest X bound; for (int y = 0; y < Image.Height - 1; ++y) { for (int x = 0; x < Image.Width - 1; ++x) { Color currentColor = Image.GetPixel(x, y); Color tempXcolor = Image.GetPixel(x + 1, y); Color tempYColor = Image.GetPixel(x, y + 1); if ((Math.Sqrt(((currentColor.R - tempXcolor.R) * (currentColor.R - tempXcolor.R)) + ((currentColor.G - tempXcolor.G) * (currentColor.G - tempXcolor.G)) + ((currentColor.B - tempXcolor.B) * (currentColor.B - tempXcolor.B))) > Threshold)) { if (lowestX > x) lowestX = x; if (largestX < x) largestX = x; } if ((Math.Sqrt(((currentColor.R - tempYColor.R) * (currentColor.R - tempYColor.R)) + ((currentColor.G - tempYColor.G) * (currentColor.G - tempYColor.G)) + ((currentColor.B - tempYColor.B) * (currentColor.B - tempYColor.B))) > Threshold)) { if (lowestY > y) lowestY = y; if (largestY < y) largestY = y; } } } if (lowestX < Image.Width / 4) cropRectangle.X = lowestX - 3 > 0 ? lowestX - 3 : 0; else cropRectangle.X = 0; if (lowestY < Image.Height / 4) cropRectangle.Y = lowestY - 3 > 0 ? lowestY - 3 : 0; else cropRectangle.Y = 0; cropRectangle.Width = largestX - lowestX + 8 > Image.Width ? Image.Width : largestX - lowestX + 8; cropRectangle.Height = largestY + 8 > Image.Height ? Image.Height - lowestY : largestY - lowestY + 8; return cropRectangle; } }

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  • How to determine edges in an image optimally?

    - by SorinA.
    I recently was put in front of the problem of cropping and resizing images. I needed to crop the 'main content' of an image for example if i had an image similar to this: the result should be an image with the msn content without the white margins(left& right). I search on the X axis for the first and last color change and on the Y axis the same thing. The problem is that traversing the image line by line takes a while..for an image that is 2000x1600px it takes up to 2 seconds to return the CropRect = x1,y1,x2,y2 data. I tried to make for each coordinate a traversal and stop on the first value found but it didn't work in all test cases..sometimes the returned data wasn't the expected one and the duration of the operations was similar.. Any idea how to cut down the traversal time and discovery of the rectangle round the 'main content'? public static CropRect EdgeDetection(Bitmap Image, float Threshold) { CropRect cropRectangle = new CropRect(); int lowestX = 0; int lowestY = 0; int largestX = 0; int largestY = 0; lowestX = Image.Width; lowestY = Image.Height; //find the lowest X bound; for (int y = 0; y < Image.Height - 1; ++y) { for (int x = 0; x < Image.Width - 1; ++x) { Color currentColor = Image.GetPixel(x, y); Color tempXcolor = Image.GetPixel(x + 1, y); Color tempYColor = Image.GetPixel(x, y + 1); if ((Math.Sqrt(((currentColor.R - tempXcolor.R) * (currentColor.R - tempXcolor.R)) + ((currentColor.G - tempXcolor.G) * (currentColor.G - tempXcolor.G)) + ((currentColor.B - tempXcolor.B) * (currentColor.B - tempXcolor.B))) > Threshold)) { if (lowestX > x) lowestX = x; if (largestX < x) largestX = x; } if ((Math.Sqrt(((currentColor.R - tempYColor.R) * (currentColor.R - tempYColor.R)) + ((currentColor.G - tempYColor.G) * (currentColor.G - tempYColor.G)) + ((currentColor.B - tempYColor.B) * (currentColor.B - tempYColor.B))) > Threshold)) { if (lowestY > y) lowestY = y; if (largestY < y) largestY = y; } } } if (lowestX < Image.Width / 4) cropRectangle.X = lowestX - 3 > 0 ? lowestX - 3 : 0; else cropRectangle.X = 0; if (lowestY < Image.Height / 4) cropRectangle.Y = lowestY - 3 > 0 ? lowestY - 3 : 0; else cropRectangle.Y = 0; cropRectangle.Width = largestX - lowestX + 8 > Image.Width ? Image.Width : largestX - lowestX + 8; cropRectangle.Height = largestY + 8 > Image.Height ? Image.Height - lowestY : largestY - lowestY + 8; return cropRectangle; } }

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  • Java multiple class compositing and boiler plate reduction

    - by h2g2java
    We all know why Java does/should not have multiple inheritance. So this is not questioning about what has already been debated till-cows-come-home. This discusses what we would do when we wish to create a class that has the characteristics of two or more other classes. Probably, most of us would do this to "inherit" from three classes. For simplicity, I left out the constructor.: class Car extends Vehicle { final public Transport transport; final public Machine machine; } So that, Car class directly inherits methods and objects of Vehicle class, but would have to refer to transport and machine explicitly to refer to objects instantiated in Transport and Machine. Car car = new Car(); car.drive(); // from Vehicle car.transport.isAmphibious(); // from Transport car.machine.getCO2Footprint(); // from Machine I thought this was a good idea until when I encounter frameworks that require setter and getter methods. For example, the XML <Car amphibious='false' footPrint='1000' model='Fordstatic999'/> would look for the methods setAmphibious(..), setFootPrint(..) and setModel(..). Therefore, I have to project the methods from Transport and Machine classes class Car extends Vehicle { final public Transport transport; final public Machine machine; public void setAmphibious(boolean b){ this.transport.setAmphibious(b); } public void setFootPrint(String fp){ this.machine.setFootPrint(fp); } } This is OK, if there were just a few characteristics. Right now, I am trying to adapt all of SmartGWT into GWT UIBinder, especially those classes that are not a GWT widget. There are lots of characteristics to project. Wouldn't it be nice if there exists some form of annotation framework that is like this: class Car extends Vehicle @projects {Transport @projects{Machine @projects Guzzler}} { /* No need to explicitly instantiate Transport, Machine or Guzzler */ .... } Where, in case of common names of characteristics exist, the characteristics of Machine would take precedence Guzzler's, and Transport's would have precedence over Machine's, and Vehicle's would have precedence over Transport's. The annotation framework would then instantiate Transport, Machine and Guzzler as hidden members of Car and expand to break-out the protected/public characteristics, in the precedence dictated by the @project annotation sequence, into actual source code or into byte-code. Preferably into byte-code. So that the setFootPrint method is found in both Machine and Guzzler, only that of Machine's would be projected. Questions: Don't you think this is a good idea to have such a framework? Does such a framework already exist? Tell me where/what. Is there an eclipse plugin that does it? Is there a proposal or plan anywhere that you know about such an annotation framework? It would be wonderful too, if the annotation/plugin framework lets me specify that boolean, int, or whatever else needs to be converted from String and does the conversion/parsing for me too. Please advise, somebody. I hope wording of my question was clear enough. Thx. Edited: To avoid OO enthusiasts jumping to conclusion, I have renamed the title of this question.

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  • What is the practical difference between transport and message reliability in WCF?

    - by mrlane
    I am looking at differences between using WPF in .NET or using Silverlight 4 for the GUI front end of an app that connects to WCF services. I have read that net.tcp binding in Silverlight 4 only supports transport level reliability. With a WPF desktop app we can use message level reliability. What is the actual difference? If transport level reliability ensures that all TCP packets get through, doesnt that also mean that all WCF SOAP messages will also get through?

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  • Cutting Edge versus Just Average? Your SOA, Got BPM? by Mala Ramakrishnan

    - by JuergenKress
    Service Oriented Architecture (SOA) has completely transformed IT from the time it was introduced well over a decade ago. Organizations have been re-plumbing their infrastructure for reusability, efficiency and gain and succeeding with it. Best practices have emerged and people and technology have matured. We have got better at delivering on a stable platform on mission critical applications and services. Yet, there is this one secret that sets some SOA customers apart from the others. These companies grow and revolutionize their business and not just transform their IT infrastructure. The differences seem subtle for an untrained eye examining these organizations externally. And from within the company, it’s a bit like an ant sitting on an elephant, hard to differentiate between the IT trunk and business tail. What is it that some organizations do differently that makes them succeed beyond SOA? These organizations pull in business people more and more to weigh into their IT decisions. They wrench understanding process over services. They don’t settle easily when bridging business metrics and IT performance. They anguish over business requirements not translating seamlessly and quickly into IT. IT is not just an enabler but a pillar that revolutionizes their business. Okay, I’ll give it to you. These organizations layer Business Process Management (BPM) on top of their SOA. Think about lifeblood business processes in your own organizations. If you are Fedex, this would be shipping and handling. If you are Stanford Hospital, this would be patient case-management: from on-boarding through discharge and follow-up care. If you are Wells Fargo, this would be loan origination. Now think about how your SOA ties into your business process. Can you decouple your business processes from your SOA so that the two can transform and change independent of each other? Can you forecast success metrics for your business process, make the changes across the board and then look back over different periods of time to see if you are on track? Are your critical business processes entrenched in the minds of few experts in your organization or does everyone from the receptionist to your enterprise architect to your CEO understand what they can do to revolutionize it? Business Process Management is a superset of SOA. It is the process of getting your business to articulate business value and metrics and have it implemented in IT without any loss in translation. It is the act of extracting the business process from the minds of experts and IT applications in your organization and valuing them as assets for performance and gain. BPM is stepping outside your SOA and moving your organization to the next level of innovation. Oracle is accelerating BPM across industries with the latest launch. Join us to understand how BPM can give your organization a cutting edge over your SOA. SOA & BPM Partner Community For regular information on Oracle SOA Suite become a member in the SOA & BPM Partner Community for registration please visit www.oracle.com/goto/emea/soa (OPN account required) If you need support with your account please contact the Oracle Partner Business Center. Blog Twitter LinkedIn Facebook Wiki Mix Forum Technorati Tags: SOA,BPM,SOA Community,Oracle SOA,Oracle BPM,Community,OPN,Jürgen Kress

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  • How can I draw an arrow at the edge of the screen pointing to an object that is off screen?

    - by Adam Henderson
    I am wishing to do what is described in this topic: http://www.allegro.cc/forums/print-thread/283220 I have attempted a variety of the methods mentioned here. First I tried to use the method described by Carrus85: Just take the ratio of the two triangle hypontenuses (doesn't matter which triagle you use for the other, I suggest point 1 and point 2 as the distance you calculate). This will give you the aspect ratio percentage of the triangle in the corner from the larger triangle. Then you simply multiply deltax by that value to get the x-coordinate offset, and deltay by that value to get the y-coordinate offset. But I could not find a way to calculate how far the object is away from the edge of the screen. I then tried using ray casting (which I have never done before) suggested by 23yrold3yrold: Fire a ray from the center of the screen to the offscreen object. Calculate where on the rectangle the ray intersects. There's your coordinates. I first calculated the hypotenuse of the triangle formed by the difference in x and y positions of the two points. I used this to create a unit vector along that line. I looped through that vector until either the x coordinate or the y coordinate was off the screen. The two current x and y values then form the x and y of the arrow. Here is the code for my ray casting method (written in C++ and Allegro 5) void renderArrows(Object* i) { float x1 = i->getX() + (i->getWidth() / 2); float y1 = i->getY() + (i->getHeight() / 2); float x2 = screenCentreX; float y2 = ScreenCentreY; float dx = x2 - x1; float dy = y2 - y1; float hypotSquared = (dx * dx) + (dy * dy); float hypot = sqrt(hypotSquared); float unitX = dx / hypot; float unitY = dy / hypot; float rayX = x2 - view->getViewportX(); float rayY = y2 - view->getViewportY(); float arrowX = 0; float arrowY = 0; bool posFound = false; while(posFound == false) { rayX += unitX; rayY += unitY; if(rayX <= 0 || rayX >= screenWidth || rayY <= 0 || rayY >= screenHeight) { arrowX = rayX; arrowY = rayY; posFound = true; } } al_draw_bitmap(sprite, arrowX - spriteWidth, arrowY - spriteHeight, 0); } This was relatively successful. Arrows are displayed in the bottom right section of the screen when objects are located above and left of the screen as if the locations of the where the arrows are drawn have been rotated 180 degrees around the center of the screen. I assumed this was due to the fact that when I was calculating the hypotenuse of the triangle, it would always be positive regardless of whether or not the difference in x or difference in y is negative. Thinking about it, ray casting does not seem like a good way of solving the problem (due to the fact that it involves using sqrt() and a large for loop). Any help finding a suitable solution would be greatly appreciated, Thanks Adam

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  • Cutting edge technology, a lone Movember ranger and a 5-a-side football club ...meet the team at Oracle’s Belfast Offices.

    - by user10729410
    Normal 0 false false false EN-IE X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} Normal 0 false false false EN-IE X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} By Olivia O’Connell To see what’s in store at Oracle’s next Open Day which comes to Belfast this week, I visited the offices with some colleagues to meet the team and get a feel for what‘s in store on November 29th. After being warmly greeted by Frances and Francesca, who make sure Front of House and Facilities run smoothly, we embarked on a quick tour of the 2 floors Oracle occupies, led by VP Bo, it was time to seek out some willing volunteers to be interviewed/photographed - what a shy bunch! A bit of coaxing from the social media team was needed here! In a male-dominated environment, the few women on the team caught my eye immediately. I got chatting to Susan, a business analyst and Bronagh, a tech writer. It becomes clear during our chat that the male/female divide is not an issue – “everyone here just gets on with the job,” says Suzanne, “We’re all around the same age and have similar priorities and luckily everyone is really friendly so there are no problems. ” A graduate of Queen’s University in Belfast majoring in maths & computer science, Susan works closely with product management and the development teams to ensure that the final project delivered to clients meets and exceeds their expectations. Bronagh, who joined us following working for a tech company in Montreal and gaining her post-grad degree at University of Ulster agrees that the work is challenging but “the environment is so relaxed and friendly”. Normal 0 false false false EN-IE X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} Software developer David is taking the Movember challenge for the first time to raise vital funds and awareness for men’s health. Like other colleagues in the office, he is a University of Ulster graduate and works on Reference applications and Merchandising Tools which enable customers to establish e-shops using Oracle technologies. The social activities are headed up by Gordon, a software engineer on the commerce team who joined the team 4 years ago after graduating from the University of Strathclyde at Glasgow with a degree in Computer Science. Everyone is unanimous that the best things about working at Oracle’s Belfast offices are the casual friendly environment and the opportunity to be at the cutting edge of technology. We’re looking forward to our next trip to Belfast for some cool demos and meet candidates. And as for the camera-shyness? Look who came out to have their picture taken at the end of the day! Normal 0 false false false EN-IE X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} The Oracle offices in Belfast are located on the 6th floor, Victoria House, Gloucester Street, Belfast BT1 4LS, UK View Larger Map Normal 0 false false false EN-IE X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} Open day takes place on Thursday, 29th November 4pm – 8pm. Visit the 5 Demo Stations to find out more about each teams' activities and projects to date. See live demos including "Engaging the Customer", "Managing Your Store", "Helping the Customer", "Shopping on-line" and "The Commerce Experience" processes. The "Working @Oracle" stand will give you the chance to connect with our recruitment team and get information about the Recruitment process and making your career path in Oracle. Register here.

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