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  • IE or Firefox,which one has a more logical CSS handling ?

    - by Najm
    hello there , i know that there is some rules and standards in css handling but i mean which one is closer to a human thinking. for example : when i give a DIV tag a height property of 100px i just want it to be 100px! but in Firefox i should work on min-height or max-width and so on ! there is many like this examlpe , i think IE read css more humanestic against Firefox. i have several experiences in this case , your final nice design in IE can be a mess in Firefox thats because of the way they handle css. Firefox act as a robot but IE act as a human-half robot ! its just my idea. i will be glad to hear and learn from you proffesionals and other friends here. thank you.

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  • I can I separate multiple logical pages in a text file I create in Perl?

    - by Micah
    So far, I've been successful with generating output to individual files by opening a file for output as part of outer loop and closing it after all output is written. I had used a counting variable ($x) and appended .txt onto it to create a filename, and had written it to the same directory as my perl script. I want to step the code up a bit, prompt for a file name from the user, open that file once and only once, and write my output one "printed letter" per page. Is this possible in plain text? From what I understand, chr(12) is an ascii line feed character and will get me close to what I want, but is there a better way? Thanks in advance, guys. :) sub PersonalizeLetters{ print "\n\n Beginning finalization of letters..."; print "\n\n I need a filename to save these letters to."; print "\n Filename > "; $OutFileName = <stdin>; chomp ($OutFileName); open(OutFile, ">$OutFileName"); for ($x=0; $x<$NumRecords; $x++){ $xIndex = (6 * $x); $clTitle = @ClientAoA[$xIndex]; $clName = @ClientAoA[$xIndex+1]; #I use this 6x multiplier because my records have 6 elements. #For this routine I'm only interested in name and title. #Reset OutLetter array #Midletter has other merged fields that aren't specific to who's receiving the letter. @OutLetter = @MiddleLetter; for ($y=0; $y<=$ifLength; $y++){ #Step through line by line and insert the name. $WorkLine = @OutLetter[$y]; $WorkLine =~ s/\[ClientTitle\]/$clTitle/; $WorkLine =~ s/\[ClientName\]/$clName/; @OutLetter[$y] = $WorkLine; } print OutFile "@OutLetter"; #Will chr(12) work here, or is there something better? print OutFile chr(12); $StatusX = $x+1; print "Writing output $StatusX of $NumRecords... \n\n"; } close(OutFile); }

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  • Where can I find a compact programming keyboard with logical key placement?

    - by Lefler
    I recently, at the order of my chiropractor, bought a laptop stand to elevate my screen. A result of this is that I need a standalone keyboard. Normal keyboards have numeric keypads on the right side, which moves my mouse further to the right... not an optimal position chiropractically speaking. I don't use the numeric keypad, but all the compact keyboards I can find use some random placement algorithm on the arrow, page up/down, and most importantly -- the insert,delete,home and end keys. Those misplaced keys are crippling my code entry. Does anyone know of a keyboard that is minus the keypad, but places those VERY IMPORTANT keys in a more standard position?

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  • SQL Server 2008 uses half the CPU’s

    - by ACALVETT
    I recently got my hands on a couple of 4 socket servers with Intel E7-4870's (10 cores per cpu) and with hyper threading enabled that gave me 80 logical CPU's. The server has Windows 2008 R2 SP1 along with SQL 2008 (Currently we can not deploy SQL 2008 R2 for the application being hosted). When SQL Server started I noticed only 2 NUMA nodes were configured and 40 logical cores where there should have been 4 NUMA nodes and 80 logical cores (see below). The problem is caused by that fact that...(read more)

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  • SQL Server Split() Function

    - by HighAltitudeCoder
    Title goes here   Ever wanted a dbo.Split() function, but not had the time to debug it completely?  Let me guess - you are probably working on a stored procedure with 50 or more parameters; two or three of them are parameters of differing types, while the other 47 or so all of the same type (id1, id2, id3, id4, id5...).  Worse, you've found several other similar stored procedures with the ONLY DIFFERENCE being the number of like parameters taped to the end of the parameter list. If this is the situation you find yourself in now, you may be wondering, "why am I working with three different copies of what is basically the same stored procedure, and why am I having to maintain changes in three different places?  Can't I have one stored procedure that accomplishes the job of all three? My answer to you: YES!  Here is the Split() function I've created.    /******************************************************************************                                       Split.sql   ******************************************************************************/ /******************************************************************************   Split a delimited string into sub-components and return them as a table.   Parameter 1: Input string which is to be split into parts. Parameter 2: Delimiter which determines the split points in input string. Works with space or spaces as delimiter. Split() is apostrophe-safe.   SYNTAX: SELECT * FROM Split('Dvorak,Debussy,Chopin,Holst', ',') SELECT * FROM Split('Denver|Seattle|San Diego|New York', '|') SELECT * FROM Split('Denver is the super-awesomest city of them all.', ' ')   ******************************************************************************/ USE AdventureWorks GO   IF EXISTS       (SELECT *       FROM sysobjects       WHERE xtype = 'TF'       AND name = 'Split'       ) BEGIN       DROP FUNCTION Split END GO   CREATE FUNCTION Split (       @InputString                  VARCHAR(8000),       @Delimiter                    VARCHAR(50) )   RETURNS @Items TABLE (       Item                          VARCHAR(8000) )   AS BEGIN       IF @Delimiter = ' '       BEGIN             SET @Delimiter = ','             SET @InputString = REPLACE(@InputString, ' ', @Delimiter)       END         IF (@Delimiter IS NULL OR @Delimiter = '')             SET @Delimiter = ','   --INSERT INTO @Items VALUES (@Delimiter) -- Diagnostic --INSERT INTO @Items VALUES (@InputString) -- Diagnostic         DECLARE @Item                 VARCHAR(8000)       DECLARE @ItemList       VARCHAR(8000)       DECLARE @DelimIndex     INT         SET @ItemList = @InputString       SET @DelimIndex = CHARINDEX(@Delimiter, @ItemList, 0)       WHILE (@DelimIndex != 0)       BEGIN             SET @Item = SUBSTRING(@ItemList, 0, @DelimIndex)             INSERT INTO @Items VALUES (@Item)               -- Set @ItemList = @ItemList minus one less item             SET @ItemList = SUBSTRING(@ItemList, @DelimIndex+1, LEN(@ItemList)-@DelimIndex)             SET @DelimIndex = CHARINDEX(@Delimiter, @ItemList, 0)       END -- End WHILE         IF @Item IS NOT NULL -- At least one delimiter was encountered in @InputString       BEGIN             SET @Item = @ItemList             INSERT INTO @Items VALUES (@Item)       END         -- No delimiters were encountered in @InputString, so just return @InputString       ELSE INSERT INTO @Items VALUES (@InputString)         RETURN   END -- End Function GO   ---- Set Permissions --GRANT SELECT ON Split TO UserRole1 --GRANT SELECT ON Split TO UserRole2 --GO   The syntax is basically as follows: SELECT <fields> FROM Table 1 JOIN Table 2 ON ... JOIN Table 3 ON ... WHERE LOGICAL CONDITION A AND LOGICAL CONDITION B AND LOGICAL CONDITION C AND TABLE2.Id IN (SELECT * FROM Split(@IdList, ',')) @IdList is a parameter passed into the stored procedure, and the comma (',') is the delimiter you have chosen to split the parameter list on. You can also use it like this: SELECT <fields> FROM Table 1 JOIN Table 2 ON ... JOIN Table 3 ON ... WHERE LOGICAL CONDITION A AND LOGICAL CONDITION B AND LOGICAL CONDITION C HAVING COUNT(SELECT * FROM Split(@IdList, ',') Similarly, it can be used in other aggregate functions at run-time: SELECT MIN(SELECT * FROM Split(@IdList, ','), <fields> FROM Table 1 JOIN Table 2 ON ... JOIN Table 3 ON ... WHERE LOGICAL CONDITION A AND LOGICAL CONDITION B AND LOGICAL CONDITION C GROUP BY <fields> Now that I've (hopefully effectively) explained the benefits to using this function and implementing it in one or more of your database objects, let me warn you of a caveat that you are likely to encounter.  You may have a team member who waits until the right moment to ask you a pointed question: "Doesn't this function just do the same thing as using the IN function?  Why didn't you just use that instead?  In other words, why bother with this function?" What's happening is, one or more team members has failed to understand the reason for implementing this kind of function in the first place.  (Note: this is THE MOST IMPORTANT ASPECT OF THIS POST). Allow me to outline a few pros to implementing this function, so you may effectively parry this question.  Touche. 1) Code consolidation.  You don't have to maintain what is basically the same code and logic, but with varying numbers of the same parameter in several SQL objects.  I'm not going to go into the cons related to using this function, because the afore mentioned team member is probably more than adept at pointing these out.  Remember, the real positive contribution is ou are decreasing the liklihood that your team fails to update all (x) duplicate copies of what are basically the same stored procedure, and so on...  This is the classic downside to duplicate code.  It is a virus, and you should kill it. You might be better off rejecting your team member's question, and responding with your own: "Would you rather maintain the same logic in multiple different stored procedures, and hope that the team doesn't forget to always update all of them at the same time?".  In his head, he might be thinking "yes, I would like to maintain several different copies of the same stored procedure", although you probably will not get such a direct response.  2) Added flexibility - you can use the Split function elsewhere, and for splitting your data in different ways.  Plus, you can use any kind of delimiter you wish.  How can you know today the ways in which you might want to examine your data tomorrow?  Segue to my next point. 3) Because the function takes a delimiter parameter, you can split the data in any number of ways.  This greatly increases the utility of such a function and enables your team to work with the data in a variety of different ways in the future.  You can split on a single char, symbol, word, or group of words.  You can split on spaces.  (The list goes on... test it out). Finally, you can dynamically define the behavior of a stored procedure (or other SQL object) at run time, through the use of this function.  Rather than have several objects that accomplish almost the same thing, why not have only one instead?

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  • External USB Drive

    - by ErocM
    I have a server that I hooked up an external USB drive. It was formatted in windows and has files on it already. I'm new to Ubuntu so please be patient... I have two questions: Will Ubuntu see the drive since it was formatted in windows? How do I mount this drive or rather, how do I know it's seen by Ubuntu? Thanks! I did fdisk -l and this is what I have but I don't see it. It's a 1tb drive: Disk /dev/sda: 320.1 GB, 320072933376 bytes 255 heads, 63 sectors/track, 38913 cylinders, total 625142448 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x0001eb47 Device Boot Start End Blocks Id System /dev/sda1 * 2048 499711 248832 83 Linux /dev/sda2 501758 625141759 312320001 5 Extended /dev/sda5 501760 625141759 312320000 8e Linux LVM Disk /dev/sdc: 160.0 GB, 160041885696 bytes 255 heads, 63 sectors/track, 19457 cylinders, total 312581808 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/sdc doesn't contain a valid partition table Disk /dev/sdb: 160.0 GB, 160041885696 bytes 255 heads, 63 sectors/track, 19457 cylinders, total 312581808 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/sdb doesn't contain a valid partition table Disk /dev/mapper/ubuntu-root: 316.6 GB, 316577677312 bytes 255 heads, 63 sectors/track, 38488 cylinders, total 618315776 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/mapper/ubuntu-root doesn't contain a valid partition table Disk /dev/mapper/ubuntu-swap_1: 3217 MB, 3217031168 bytes 255 heads, 63 sectors/track, 391 cylinders, total 6283264 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 this is an external USB hard drive not a thumb drive :)

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  • format/build raid 5 with one 4k drive, three 512b

    - by skidawgz
    I have 4 WD 1TB drives which I want to 4x1TB Raid5. I am not sure what course of action to take next. How do I configure my 4th drive (sde) to align with the rest? Will this affect performance? I rcv this msg (which brings me here to ask these question): The device presents a logical sector size that is smaller than the physical sector size. Aligning to a physical sector (or optimal I/O) size boundary is recommended, or performance may be impacted. fdisk -l shows: Disk /dev/sdb: 1000.2 GB, 1000204886016 bytes 81 heads, 63 sectors/track, 382818 cylinders, total 1953525168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0xf324ba09 Device Boot Start End Blocks Id System /dev/sdb1 2048 1953525167 976761560 fd Linux raid autodetect Disk /dev/sdc: 1000.2 GB, 1000204886016 bytes 81 heads, 63 sectors/track, 382818 cylinders, total 1953525168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x38bcc1f0 Device Boot Start End Blocks Id System /dev/sdc1 2048 1953525167 976761560 fd Linux raid autodetect Disk /dev/sdd: 1000.2 GB, 1000204886016 bytes 81 heads, 63 sectors/track, 382818 cylinders, total 1953525168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x570f77e7 Device Boot Start End Blocks Id System /dev/sdd1 2048 1953525167 976761560 fd Linux raid autodetect Disk /dev/sde: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders, total 1953525168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0xeb665e7b Device Boot Start End Blocks Id System

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  • How are Reads Distributed in a Workload

    - by Bill Graziano
    People have uploaded nearly one millions rows of trace data to TraceTune.  That’s enough data to start to look at the results in aggregate.  The first thing I want to look at is logical reads.  This is the easiest metric to identify and fix. When you upload a trace, I rank each statement based on the total number of logical reads.  I also calculate each statement’s percentage of the total logical reads.  I do the same thing for CPU, duration and logical writes.  When you view a statement you can see all the details like this: This single statement consumed 61.4% of the total logical reads on the system while we were tracing it.  I also wanted to see the distribution of reads across statements.  That graph looks like this: On average, the highest ranked statement consumed just under 50% of the reads on the system.  When I tune a system, I’m usually starting in one of two modes: this “piece” is slow or the whole system is slow.  If a given piece (screen, report, query, etc.) is slow you can usually find the specific statements behind it and tune it.  You can make that individual piece faster but you may not affect the whole system. When you’re trying to speed up an entire server you need to identity those queries that are using the most disk resources in aggregate.  Fixing those will make them faster and it will leave more disk throughput for the rest of the queries. Here are some of the things I’ve learned querying this data: The highest ranked query averages just under 50% of the total reads on the system. The top 3 ranked queries average 73% of the total reads on the system. The top 10 ranked queries average 91% of the total reads on the system. Remember these are averages across all the traces that have been uploaded.  And I’m guessing that people mainly upload traces where there are performance problems so your mileage may vary. I also learned that slow queries aren’t the problem.  Before I wrote ClearTrace I used to identify queries by filtering on high logical reads using Profiler.  That picked out individual queries but those rarely ran often enough to put a large load on the system. If you look at the execution count by rank you’d see that the highest ranked queries also have the highest execution counts.  The graph would look very similar to the one above but flatter.  These queries don’t look that bad individually but run so often that they hog the disk capacity. The take away from all this is that you really should be tuning the top 10 queries if you want to make your system faster.  Tuning individually slow queries will help those specific queries but won’t have much impact on the system as a whole.

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  • Can't mount data DVD using 12.04

    - by dash2
    I cannot mount a data DVD using Ubuntu 12.04. I can read the DVD using a different OS, so the DVD is not the problem. I can read other CDs using Ubuntu. The error I get is: $ sudo mount /dev/dvd /cdrom mount: no medium found on /dev/sr0 The relevant output from lshw is: *-cdrom description: DVD reader product: DVD/CDRW UJDA775 vendor: MATSHITA physical id: 0.0.0 bus info: scsi@4:0.0.0 logical name: /dev/cdrom logical name: /dev/cdrw logical name: /dev/dvd logical name: /dev/sr0 version: CB03 capabilities: removable audio cd-r cd-rw dvd configuration: ansiversion=5 status=nodisc I have installed ubuntu-restricted-extras and run /usr/share/doc/libdvdread4/install-css.sh.

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  • "The volume filesystem root has only..."

    - by jcslzr
    I am having this problem in ubuntu 12.04, but I fin strange that when I go to /tmp it wont allow me to delete some files, with message "Operation not permitted" or "this file could not be handled because you dont have permissions to read it". It is only a PC and I have the root password. I was trying to get at least 2000 MB of free space on the root file system to upgrade to 12.10 and see if that resolved the problem. Currently free space on root file system is 190 MB. This is my output: root@jcsalazar-Vostro-3550:~# df Filesystem 1K-blocks Used Available Use% Mounted on /dev/sda6 7688360 7112824 184984 98% / udev 2009288 4 2009284 1% /dev tmpfs 806636 1024 805612 1% /run none 5120 0 5120 0% /run/lock none 2016584 5316 2011268 1% /run/shm /dev/sda5 472036 255920 191745 58% /boot /dev/sda7 30758848 7085480 22110900 25% /home root@jcsalazar-Vostro-3550:~# sudo parted -l Model: ATA TOSHIBA MK3261GS (scsi) Disk /dev/sda: 320GB Sector size (logical/physical): 512B/512B Partition Table: msdos Number Start End Size Type File system Flags 1 1049kB 106MB 105MB primary fat16 2 106MB 15.8GB 15.7GB primary ntfs boot 3 15.8GB 278GB 262GB primary ntfs 4 278GB 320GB 41.9GB extended 5 278GB 279GB 499MB logical ext4 6 279GB 287GB 7999MB logical ext4 7 287GB 319GB 32.0GB logical ext4 8 319GB 320GB 1443MB logical linux-swap(v1) I apprecciate any new ideas that can help me. Thnx Carlos

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  • Partition does not start on physical sector boundary?

    - by jasmines
    I've one HD on my laptop, with two partitions (one ext3 with Ubuntu 12.04 installed and one swap). fdisk is giving me a Partition 1 does not start on physical sector boundary warning. What is the cause and do I need to fix it? If so, how? This is sudo fdisk -l: Disk /dev/sda: 750.2 GB, 750156374016 bytes 255 testine, 63 settori/tracce, 91201 cilindri, totale 1465149168 settori Unità = settori di 1 * 512 = 512 byte Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Identificativo disco: 0x5a25087f Dispositivo Boot Start End Blocks Id System /dev/sda1 * 63 1448577023 724288480+ 83 Linux Partition 1 does not start on physical sector boundary. /dev/sda2 1448577024 1465147391 8285184 82 Linux swap / Solaris This is sudo lshw related result: *-disk description: ATA Disk product: WDC WD7500BPKT-0 vendor: Western Digital physical id: 0 bus info: scsi@0:0.0.0 logical name: /dev/sda version: 01.0 serial: WD-WX21CC1T0847 size: 698GiB (750GB) capabilities: partitioned partitioned:dos configuration: ansiversion=5 signature=5a25087f *-volume:0 description: EXT3 volume vendor: Linux physical id: 1 bus info: scsi@0:0.0.0,1 logical name: /dev/sda1 logical name: / version: 1.0 serial: cc5c562a-bc59-4a37-b589-805b27b2cbd7 size: 690GiB capacity: 690GiB capabilities: primary bootable journaled extended_attributes large_files recover ext3 ext2 initialized configuration: created=2010-02-27 09:18:28 filesystem=ext3 modified=2012-06-23 18:33:59 mount.fstype=ext3 mount.options=rw,relatime,errors=remount-ro,user_xattr,barrier=1,data=ordered mounted=2012-06-28 00:20:47 state=mounted *-volume:1 description: Linux swap volume physical id: 2 bus info: scsi@0:0.0.0,2 logical name: /dev/sda2 version: 1 serial: 16a7fee0-be9e-4e34-9dc3-28f4eeb61bf6 size: 8091MiB capacity: 8091MiB capabilities: primary nofs swap initialized configuration: filesystem=swap pagesize=4096 These are related /etc/fstab lines: UUID=cc5c562a-bc59-4a37-b589-805b27b2cbd7 / ext3 errors=remount-ro,user_xattr 0 1 UUID=16a7fee0-be9e-4e34-9dc3-28f4eeb61bf6 none swap sw 0 0

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  • Is there any professional way to illustrate difference between 2 diagrams?

    - by lamwaiman1988
    I made a documented which is to describe the difference between the same logical structure from different version ( e.g Structure A from version 8 and Structure A from version 9 ). Luckily I've got the logical structure diagram from the 2 functional specification. I've managed to copy the image of each logical structure and paste them in MS Word and compare the 2 version side by side. I don't know if there is a standard way to illustrate the difference. I simply draw a cross over the removed logical member from the previous version and draw a rectangle around the new logical member of the next version. I know my way is kinda childish. I am wondering how to present them professionally. In addition, You won't believe this, but MS Word doesn't have a shape of CROSS, so I am actually using a multiplication sign that look like a giant monster: This is why I hate myself. Unlike 2 separated lines, this shape is easy to use, draw and resize. I am wondering if MS Word would care about a normal cross.

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  • Ubuntu 12.04 boot degraded raid

    - by beacon_bonanza
    I've installed Ubuntu 12.04.1 in a new server and set up the 4 hard drives with 3 RAID 1 devices, the configuration is such that the first two drives have md0 (swap space) and md1 (/) with the third and fourth drives having md2 (/var). I've been testing the operation under a drive failure and found that the system boots fine if I remove disk two but if I remove disk one then the system gets to grub and then just restarts. I'm confused as to why grub appears to be loading properly from disk two but then the boot fails. I've tried to copy the MBR from disk 1 to 2: dd if=/dev/sda of=/dev/sdb bs=512 count=1 but this didn't make a difference. Any ideas how to get it to boot from just the second disk? fdisk -l Disk /dev/sda: 2000.4 GB, 2000398934016 bytes 255 heads, 63 sectors/track, 243201 cylinders, total 3907029168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000ccfa5 Device Boot Start End Blocks Id System /dev/sda1 2048 31250431 15624192 fd Linux RAID autodetect /dev/sda2 * 31250432 3907028991 1937889280 fd Linux RAID autodetect Disk /dev/sdb: 2000.4 GB, 2000398934016 bytes 255 heads, 63 sectors/track, 243201 cylinders, total 3907029168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000ccfa5 Device Boot Start End Blocks Id System /dev/sdb1 2048 31250431 15624192 fd Linux RAID autodetect /dev/sdb2 * 31250432 3907028991 1937889280 fd Linux RAID autodetect Disk /dev/sdd: 2000.4 GB, 2000398934016 bytes 255 heads, 63 sectors/track, 243201 cylinders, total 3907029168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00035b05 Device Boot Start End Blocks Id System /dev/sdd1 2048 3907028991 1953513472 fd Linux RAID autodetect Disk /dev/sdc: 2000.4 GB, 2000398934016 bytes 255 heads, 63 sectors/track, 243201 cylinders, total 3907029168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000c73aa Device Boot Start End Blocks Id System /dev/sdc1 2048 3907028991 1953513472 fd Linux RAID autodetect Disk /dev/md1: 1984.3 GB, 1984264208384 bytes 2 heads, 4 sectors/track, 484439504 cylinders, total 3875516032 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/md2: 2000.3 GB, 2000263380992 bytes 2 heads, 4 sectors/track, 488345552 cylinders, total 3906764416 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/md0: 16.0 GB, 15990652928 bytes 2 heads, 4 sectors/track, 3903968 cylinders, total 31231744 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000

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  • Oracle Flashback Technologies - Overview

    - by Sridhar_R-Oracle
    Oracle Flashback Technologies - IntroductionIn his May 29th 2014 blog, my colleague Joe Meeks introduced Oracle Maximum Availability Architecture (MAA) and discussed both planned and unplanned outages. Let’s take a closer look at unplanned outages. These can be caused by physical failures (e.g., server, storage, network, file deletion, physical corruption, site failures) or by logical failures – cases where all components and files are physically available, but data is incorrect or corrupt. These logical failures are usually caused by human errors or application logic errors. This blog series focuses on these logical errors – what causes them and how to address and recover from them using Oracle Database Flashback. In this introductory blog post, I’ll provide an overview of the Oracle Database Flashback technologies and will discuss the features in detail in future blog posts. Let’s get started. We are all human beings (unless a machine is reading this), and making mistakes is a part of what we do…often what we do best!  We “fat finger”, we spill drinks on keyboards, unplug the wrong cables, etc.  In addition, many of us, in our lives as DBAs or developers, must have observed, caused, or corrected one or more of the following unpleasant events: Accidentally updated a table with wrong values !! Performed a batch update that went wrong - due to logical errors in the code !! Dropped a table !! How do DBAs typically recover from these types of errors? First, data needs to be restored and recovered to the point-in-time when the error occurred (incomplete or point-in-time recovery).  Moreover, depending on the type of fault, it’s possible that some services – or even the entire database – would have to be taken down during the recovery process.Apart from error conditions, there are other questions that need to be addressed as part of the investigation. For example, what did the data look like in the morning, prior to the error? What were the various changes to the row(s) between two timestamps? Who performed the transaction and how can it be reversed?  Oracle Database includes built-in Flashback technologies, with features that address these challenges and questions, and enable you to perform faster, easier, and convenient recovery from logical corruptions. HistoryFlashback Query, the first Flashback Technology, was introduced in Oracle 9i. It provides a simple, powerful and completely non-disruptive mechanism for data verification and recovery from logical errors, and enables users to view the state of data at a previous point in time.Flashback Technologies were further enhanced in Oracle 10g, to provide fast, easy recovery at the database, table, row, and even at a transaction level.Oracle Database 11g introduced an innovative method to manage and query long-term historical data with Flashback Data Archive. The 11g release also introduced Flashback Transaction, which provides an easy, one-step operation to back out a transaction. Oracle Database versions 11.2.0.2 and beyond further enhanced the performance of these features. Note that all the features listed here work without requiring any kind of restore operation.In addition, Flashback features are fully supported with the new multi-tenant capabilities introduced with Oracle Database 12c, Flashback Features Oracle Flashback Database enables point-in-time-recovery of the entire database without requiring a traditional restore and recovery operation. It rewinds the entire database to a specified point in time in the past by undoing all the changes that were made since that time.Oracle Flashback Table enables an entire table or a set of tables to be recovered to a point in time in the past.Oracle Flashback Drop enables accidentally dropped tables and all dependent objects to be restored.Oracle Flashback Query enables data to be viewed at a point-in-time in the past. This feature can be used to view and reconstruct data that was lost due to unintentional change(s) or deletion(s). This feature can also be used to build self-service error correction into applications, empowering end-users to undo and correct their errors.Oracle Flashback Version Query offers the ability to query the historical changes to data between two points in time or system change numbers (SCN) Oracle Flashback Transaction Query enables changes to be examined at the transaction level. This capability can be used to diagnose problems, perform analysis, audit transactions, and even revert the transaction by undoing SQLOracle Flashback Transaction is a procedure used to back-out a transaction and its dependent transactions.Flashback technologies eliminate the need for a traditional restore and recovery process to fix logical corruptions or make enquiries. Using these technologies, you can recover from the error in the same amount of time it took to generate the error. All the Flashback features can be accessed either via SQL command line (or) via Enterprise Manager.  Most of the Flashback technologies depend on the available UNDO to retrieve older data. The following table describes the various Flashback technologies: their purpose, dependencies and situations where each individual technology can be used.   Example Syntax Error investigation related:The purpose is to investigate what went wrong and what the values were at certain points in timeFlashback Queries  ( select .. as of SCN | Timestamp )   - Helps to see the value of a row/set of rows at a point in timeFlashback Version Queries  ( select .. versions between SCN | Timestamp and SCN | Timestamp)  - Helps determine how the value evolved between certain SCNs or between timestamps Flashback Transaction Queries (select .. XID=)   - Helps to understand how the transaction caused the changes.Error correction related:The purpose is to fix the error and correct the problems,Flashback Table  (flashback table .. to SCN | Timestamp)  - To rewind the table to a particular timestamp or SCN to reverse unwanted updates Flashback Drop (flashback table ..  to before drop )  - To undrop or undelete a table Flashback Database (flashback database to SCN  | Restore Point )  - This is the rewind button for Oracle databases. You can revert the entire database to a particular point in time. It is a fast way to perform a PITR (point-in-time recovery). Flashback Transaction (DBMS_FLASHBACK.TRANSACTION_BACKOUT(XID..))  - To reverse a transaction and its related transactions Advanced use cases Flashback technology is integrated into Oracle Recovery Manager (RMAN) and Oracle Data Guard. So, apart from the basic use cases mentioned above, the following use cases are addressed using Oracle Flashback. Block Media recovery by RMAN - to perform block level recovery Snapshot Standby - where the standby is temporarily converted to a read/write environment for testing, backup, or migration purposes Re-instate old primary in a Data Guard environment – this avoids the need to restore an old backup and perform a recovery to make it a new standby. Guaranteed Restore Points - to bring back the entire database to an older point-in-time in a guaranteed way. and so on..I hope this introductory overview helps you understand how Flashback features can be used to investigate and recover from logical errors.  As mentioned earlier, I will take a deeper-dive into to some of the critical Flashback features in my upcoming blogs and address common use cases.

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  • Disk Drive not working

    - by user287681
    The CD/DVD drive on my sisters' (I'm helping her shift from Win. XP (now officially deprecated by Microsoft) to Ubuntu) system. Now, it may end up being a failed attempt, all together (Almost the whole last year (when she's been on XP) the disk drive hasn't (not even powering on) been working.), I just want to make sure I've explored every remote possibility. Because I figure, "Huh, now that I've got Ubuntu running, instead of XP, that (just) might make a difference.". I have tried using the sudo lshw command in the terminal, to (seemingly) no avil, but, who knows, you might be able to make something out of it. Here's the output: kyra@kyra-Satellite-P105:~$ sudo lshw [sudo] password for kyra: kyra-satellite-p105 description: Notebook product: Satellite P105 () vendor: TOSHIBA version: PSPA0U-0TN01M serial: 96084354W width: 64 bits capabilities: smbios-2.4 dmi-2.4 vsyscall32 configuration: administrator_password=disabled boot=oem-specific chassis=notebook frontpanel_password=unknown keyboard_password=unknown power-on_password=disabled uuid=00900559-F88E-D811-82E0-00163680E992 *-core description: Motherboard product: Satellite P105 vendor: TOSHIBA physical id: 0 version: Not Applicable serial: 1234567890 *-firmware description: BIOS vendor: TOSHIBA physical id: 0 version: V4.70 date: 01/19/20092 size: 92KiB capabilities: isa pci pcmcia pnp upgrade shadowing escd cdboot acpi usb biosbootspecification *-cpu description: CPU product: Intel(R) Core(TM)2 CPU T5500 @ 1.66GHz vendor: Intel Corp. physical id: 4 bus info: cpu@0 version: Intel(R) Core(TM)2 CPU T5 slot: U2E1 size: 1667MHz capacity: 1667MHz width: 64 bits clock: 166MHz capabilities: fpu fpu_exception wp vme de pse tsc msr pae mce cx8 apic sep mtrr pge mca cmov pat pse36 clflush dts acpi mmx fxsr sse sse2 ss ht tm pbe syscall nx x86-64 constant_tsc arch_perfmon pebs bts rep_good nopl aperfmperf pni dtes64 monitor ds_cpl est tm2 ssse3 cx16 xtpr pdcm lahf_lm dtherm cpufreq *-cache:0 description: L1 cache physical id: 5 slot: L1 Cache size: 16KiB capacity: 16KiB capabilities: asynchronous internal write-back *-cache:1 description: L2 cache physical id: 6 slot: L2 Cache size: 2MiB capabilities: burst external write-back *-memory description: System Memory physical id: c slot: System board or motherboard size: 2GiB capacity: 3GiB *-bank:0 description: SODIMM DDR2 Synchronous physical id: 0 slot: M1 size: 1GiB width: 64 bits *-bank:1 description: SODIMM DDR2 Synchronous physical id: 1 slot: M2 size: 1GiB width: 64 bits *-pci description: Host bridge product: Mobile 945GM/PM/GMS, 943/940GML and 945GT Express Memory Controller Hub vendor: Intel Corporation physical id: 100 bus info: pci@0000:00:00.0 version: 03 width: 32 bits clock: 33MHz configuration: driver=agpgart-intel resources: irq:0 *-display:0 description: VGA compatible controller product: Mobile 945GM/GMS, 943/940GML Express Integrated Graphics Controller vendor: Intel Corporation physical id: 2 bus info: pci@0000:00:02.0 version: 03 width: 32 bits clock: 33MHz capabilities: msi pm vga_controller bus_master cap_list rom configuration: driver=i915 latency=0 resources: irq:16 memory:d0200000-d027ffff ioport:1800(size=8) memory:c0000000-cfffffff memory:d0300000-d033ffff *-display:1 UNCLAIMED description: Display controller product: Mobile 945GM/GMS/GME, 943/940GML Express Integrated Graphics Controller vendor: Intel Corporation physical id: 2.1 bus info: pci@0000:00:02.1 version: 03 width: 32 bits clock: 33MHz capabilities: pm bus_master cap_list configuration: latency=0 resources: memory:d0280000-d02fffff *-multimedia description: Audio device product: NM10/ICH7 Family High Definition Audio Controller vendor: Intel Corporation physical id: 1b bus info: pci@0000:00:1b.0 version: 02 width: 64 bits clock: 33MHz capabilities: pm msi pciexpress bus_master cap_list configuration: driver=snd_hda_intel latency=0 resources: irq:44 memory:d0340000-d0343fff *-pci:0 description: PCI bridge product: NM10/ICH7 Family PCI Express Port 1 vendor: Intel Corporation physical id: 1c bus info: pci@0000:00:1c.0 version: 02 width: 32 bits clock: 33MHz capabilities: pci pciexpress msi pm normal_decode bus_master cap_list configuration: driver=pcieport resources: irq:40 ioport:3000(size=4096) memory:84000000-841fffff ioport:84200000(size=2097152) *-pci:1 description: PCI bridge product: NM10/ICH7 Family PCI Express Port 2 vendor: Intel Corporation physical id: 1c.1 bus info: pci@0000:00:1c.1 version: 02 width: 32 bits clock: 33MHz capabilities: pci pciexpress msi pm normal_decode bus_master cap_list configuration: driver=pcieport resources: irq:41 ioport:4000(size=4096) memory:84400000-846fffff ioport:84700000(size=2097152) *-network description: Wireless interface product: PRO/Wireless 3945ABG [Golan] Network Connection vendor: Intel Corporation physical id: 0 bus info: pci@0000:03:00.0 logical name: wlan0 version: 02 serial: 00:13:02:d6:d2:35 width: 32 bits clock: 33MHz capabilities: pm msi pciexpress bus_master cap_list ethernet physical wireless configuration: broadcast=yes driver=iwl3945 driverversion=3.13.0-29-generic firmware=15.32.2.9 ip=10.110.20.157 latency=0 link=yes multicast=yes wireless=IEEE 802.11abg resources: irq:43 memory:84400000-84400fff *-pci:2 description: PCI bridge product: NM10/ICH7 Family PCI Express Port 3 vendor: Intel Corporation physical id: 1c.2 bus info: pci@0000:00:1c.2 version: 02 width: 32 bits clock: 33MHz capabilities: pci pciexpress msi pm normal_decode bus_master cap_list configuration: driver=pcieport resources: irq:42 ioport:5000(size=4096) memory:84900000-84afffff ioport:84b00000(size=2097152) *-usb:0 description: USB controller product: NM10/ICH7 Family USB UHCI Controller #1 vendor: Intel Corporation physical id: 1d bus info: pci@0000:00:1d.0 version: 02 width: 32 bits clock: 33MHz capabilities: uhci bus_master configuration: driver=uhci_hcd latency=0 resources: irq:23 ioport:1820(size=32) *-usb:1 description: USB controller product: NM10/ICH7 Family USB UHCI Controller #2 vendor: Intel Corporation physical id: 1d.1 bus info: pci@0000:00:1d.1 version: 02 width: 32 bits clock: 33MHz capabilities: uhci bus_master configuration: driver=uhci_hcd latency=0 resources: irq:19 ioport:1840(size=32) *-usb:2 description: USB controller product: NM10/ICH7 Family USB UHCI Controller #3 vendor: Intel Corporation physical id: 1d.2 bus info: pci@0000:00:1d.2 version: 02 width: 32 bits clock: 33MHz capabilities: uhci bus_master configuration: driver=uhci_hcd latency=0 resources: irq:18 ioport:1860(size=32) *-usb:3 description: USB controller product: NM10/ICH7 Family USB UHCI Controller #4 vendor: Intel Corporation physical id: 1d.3 bus info: pci@0000:00:1d.3 version: 02 width: 32 bits clock: 33MHz capabilities: uhci bus_master configuration: driver=uhci_hcd latency=0 resources: irq:16 ioport:1880(size=32) *-usb:4 description: USB controller product: NM10/ICH7 Family USB2 EHCI Controller vendor: Intel Corporation physical id: 1d.7 bus info: pci@0000:00:1d.7 version: 02 width: 32 bits clock: 33MHz capabilities: pm debug ehci bus_master cap_list configuration: driver=ehci-pci latency=0 resources: irq:23 memory:d0544000-d05443ff *-pci:3 description: PCI bridge product: 82801 Mobile PCI Bridge vendor: Intel Corporation physical id: 1e bus info: pci@0000:00:1e.0 version: e2 width: 32 bits clock: 33MHz capabilities: pci subtractive_decode bus_master cap_list resources: ioport:2000(size=4096) memory:d0000000-d00fffff ioport:80000000(size=67108864) *-pcmcia description: CardBus bridge product: PCIxx12 Cardbus Controller vendor: Texas Instruments physical id: 4 bus info: pci@0000:0a:04.0 version: 00 width: 32 bits clock: 33MHz capabilities: pcmcia bus_master cap_list configuration: driver=yenta_cardbus latency=176 maxlatency=5 mingnt=192 resources: irq:17 memory:d0004000-d0004fff ioport:2400(size=256) ioport:2800(size=256) memory:80000000-83ffffff memory:88000000-8bffffff *-firewire description: FireWire (IEEE 1394) product: PCIxx12 OHCI Compliant IEEE 1394 Host Controller vendor: Texas Instruments physical id: 4.1 bus info: pci@0000:0a:04.1 version: 00 width: 32 bits clock: 33MHz capabilities: pm ohci bus_master cap_list configuration: driver=firewire_ohci latency=64 maxlatency=4 mingnt=3 resources: irq:17 memory:d0007000-d00077ff memory:d0000000-d0003fff *-storage description: Mass storage controller product: 5-in-1 Multimedia Card Reader (SD/MMC/MS/MS PRO/xD) vendor: Texas Instruments physical id: 4.2 bus info: pci@0000:0a:04.2 version: 00 width: 32 bits clock: 33MHz capabilities: storage pm bus_master cap_list configuration: driver=tifm_7xx1 latency=64 maxlatency=4 mingnt=7 resources: irq:17 memory:d0005000-d0005fff *-generic description: SD Host controller product: PCIxx12 SDA Standard Compliant SD Host Controller vendor: Texas Instruments physical id: 4.3 bus info: pci@0000:0a:04.3 version: 00 width: 32 bits clock: 33MHz capabilities: pm bus_master cap_list configuration: driver=sdhci-pci latency=64 maxlatency=4 mingnt=7 resources: irq:17 memory:d0007800-d00078ff *-network description: Ethernet interface product: PRO/100 VE Network Connection vendor: Intel Corporation physical id: 8 bus info: pci@0000:0a:08.0 logical name: eth0 version: 02 serial: 00:16:36:80:e9:92 size: 10Mbit/s capacity: 100Mbit/s width: 32 bits clock: 33MHz capabilities: pm bus_master cap_list ethernet physical tp mii 10bt 10bt-fd 100bt 100bt-fd autonegotiation configuration: autonegotiation=on broadcast=yes driver=e100 driverversion=3.5.24-k2-NAPI duplex=half latency=64 link=no maxlatency=56 mingnt=8 multicast=yes port=MII speed=10Mbit/s resources: irq:20 memory:d0006000-d0006fff ioport:2000(size=64) *-isa description: ISA bridge product: 82801GBM (ICH7-M) LPC Interface Bridge vendor: Intel Corporation physical id: 1f bus info: pci@0000:00:1f.0 version: 02 width: 32 bits clock: 33MHz capabilities: isa bus_master cap_list configuration: driver=lpc_ich latency=0 resources: irq:0 *-ide description: IDE interface product: 82801GBM/GHM (ICH7-M Family) SATA Controller [IDE mode] vendor: Intel Corporation physical id: 1f.2 bus info: pci@0000:00:1f.2 version: 02 width: 32 bits clock: 66MHz capabilities: ide pm bus_master cap_list configuration: driver=ata_piix latency=0 resources: irq:19 ioport:1f0(size=8) ioport:3f6 ioport:170(size=8) ioport:376 ioport:18b0(size=16) *-serial UNCLAIMED description: SMBus product: NM10/ICH7 Family SMBus Controller vendor: Intel Corporation physical id: 1f.3 bus info: pci@0000:00:1f.3 version: 02 width: 32 bits clock: 33MHz configuration: latency=0 resources: ioport:18c0(size=32) *-scsi physical id: 1 logical name: scsi0 capabilities: emulated *-disk description: ATA Disk product: ST9250421AS vendor: Seagate physical id: 0.0.0 bus info: scsi@0:0.0.0 logical name: /dev/sda version: SD13 serial: 5TH0B2HB size: 232GiB (250GB) capabilities: partitioned partitioned:dos configuration: ansiversion=5 sectorsize=512 signature=000d7fd5 *-volume:0 description: EXT4 volume vendor: Linux physical id: 1 bus info: scsi@0:0.0.0,1 logical name: /dev/sda1 logical name: / version: 1.0 serial: 13bb4bdd-8cc9-40e2-a490-dbe436c2a02d size: 230GiB capacity: 230GiB capabilities: primary bootable journaled extended_attributes large_files huge_files dir_nlink recover extents ext4 ext2 initialized configuration: created=2014-06-01 17:37:01 filesystem=ext4 lastmountpoint=/ modified=2014-06-01 21:15:21 mount.fstype=ext4 mount.options=rw,relatime,errors=remount-ro,data=ordered mounted=2014-06-01 21:15:21 state=mounted *-volume:1 description: Extended partition physical id: 2 bus info: scsi@0:0.0.0,2 logical name: /dev/sda2 size: 2037MiB capacity: 2037MiB capabilities: primary extended partitioned partitioned:extended *-logicalvolume description: Linux swap / Solaris partition physical id: 5 logical name: /dev/sda5 capacity: 2037MiB capabilities: nofs *-remoteaccess UNCLAIMED vendor: Intel physical id: 1 capabilities: inbound kyra@kyra-Satellite-P105:~$

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  • SQL Table stored as a Heap - the dangers within

    - by MikeD
    Nearly all of the time I create a table, I include a primary key, and often that PK is implemented as a clustered index. Those two don't always have to go together, but in my world they almost always do. On a recent project, I was working on a data warehouse and a set of SSIS packages to import data from an OLTP database into my data warehouse. The data I was importing from the business database into the warehouse was mostly new rows, sometimes updates to existing rows, and sometimes deletes. I decided to use the MERGE statement to implement the insert, update or delete in the data warehouse, I found it quite performant to have a stored procedure that extracted all the new, updated, and deleted rows from the source database and dump it into a working table in my data warehouse, then run a stored proc in the warehouse that was the MERGE statement that took the rows from the working table and updated the real fact table. Use Warehouse CREATE TABLE Integration.MergePolicy (PolicyId int, PolicyTypeKey int, Premium money, Deductible money, EffectiveDate date, Operation varchar(5)) CREATE TABLE fact.Policy (PolicyKey int identity primary key, PolicyId int, PolicyTypeKey int, Premium money, Deductible money, EffectiveDate date) CREATE PROC Integration.MergePolicy as begin begin tran Merge fact.Policy as tgtUsing Integration.MergePolicy as SrcOn (tgt.PolicyId = Src.PolicyId) When not matched by Target then Insert (PolicyId, PolicyTypeKey, Premium, Deductible, EffectiveDate)values (src.PolicyId, src.PolicyTypeKey, src.Premium, src.Deductible, src.EffectiveDate) When matched and src.Operation = 'U' then Update set PolicyTypeKey = src.PolicyTypeKey,Premium = src.Premium,Deductible = src.Deductible,EffectiveDate = src.EffectiveDate When matched and src.Operation = 'D' then Delete ;delete from Integration.WorkPolicy commit end Notice that my worktable (Integration.MergePolicy) doesn't have any primary key or clustered index. I didn't think this would be a problem, since it was relatively small table and was empty after each time I ran the stored proc. For one of the work tables, during the initial loads of the warehouse, it was getting about 1.5 million rows inserted, processed, then deleted. Also, because of a bug in the extraction process, the same 1.5 million rows (plus a few hundred more each time) was getting inserted, processed, and deleted. This was being sone on a fairly hefty server that was otherwise unused, and no one was paying any attention to the time it was taking. This week I received a backup of this database and loaded it on my laptop to troubleshoot the problem, and of course it took a good ten minutes or more to run the process. However, what seemed strange to me was that after I fixed the problem and happened to run the merge sproc when the work table was completely empty, it still took almost ten minutes to complete. I immediately looked back at the MERGE statement to see if I had some sort of outer join that meant it would be scanning the target table (which had about 2 million rows in it), then turned on the execution plan output to see what was happening under the hood. Running the stored procedure again took a long time, and the plan output didn't show me much - 55% on the MERGE statement, and 45% on the DELETE statement, and table scans on the work table in both places. I was surprised at the relative cost of the DELETE statement, because there were really 0 rows to delete, but I was expecting to see the table scans. (I was beginning now to suspect that my problem was because the work table was being stored as a heap.) Then I turned on STATS_IO and ran the sproc again. The output was quite interesting.Table 'Worktable'. Scan count 0, logical reads 0, physical reads 0, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0.Table 'Policy'. Scan count 0, logical reads 0, physical reads 0, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0.Table 'MergePolicy'. Scan count 1, logical reads 433276, physical reads 60, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0. I've reproduced the above from memory, the details aren't exact, but the essential bit was the very high number of logical reads on the table stored as a heap. Even just doing a SELECT Count(*) from Integration.MergePolicy incurred that sort of output, even though the result was always 0. I suppose I should research more on the allocation and deallocation of pages to tables stored as a heap, but I haven't, and my original assumption that a table stored as a heap with no rows would only need to read one page to answer any query was definitely proven wrong. It's likely that some sort of physical defragmentation of the table may have cleaned that up, but it seemed that the easiest answer was to put a clustered index on the table. After doing so, the execution plan showed a cluster index scan, and the IO stats showed only a single page read. (I aborted my first attempt at adding a clustered index on the table because it was taking too long - instead I ran TRUNCATE TABLE Integration.MergePolicy first and added the clustered index, both of which took very little time). I suspect I may not have noticed this if I had used TRUNCATE TABLE Integration.MergePolicy instead of DELETE FROM Integration.MergePolicy, since I'm guessing that the truncate operation does some rather quick releasing of pages allocated to the heap table. In the future, I will likely be much more careful to have a clustered index on every table I use, even the working tables. Mike  

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  • Separating physics and game logic from UI code

    - by futlib
    I'm working on a simple block-based puzzle game. The game play consists pretty much of moving blocks around in the game area, so it's a trivial physics simulation. My implementation, however, is in my opinion far from ideal and I'm wondering if you can give me any pointers on how to do it better. I've split the code up into two areas: Game logic and UI, as I did with a lot of puzzle games: The game logic is responsible for the general rules of the game (e.g. the formal rule system in chess) The UI displays the game area and pieces (e.g. chess board and pieces) and is responsible for animations (e.g. animated movement of chess pieces) The game logic represents the game state as a logical grid, where each unit is one cell's width/height on the grid. So for a grid of width 6, you can move a block of width 2 four times until it collides with the boundary. The UI takes this grid, and draws it by converting logical sizes into pixel sizes (that is, multiplies it by a constant). However, since the game has hardly any game logic, my game logic layer [1] doesn't have much to do except collision detection. Here's how it works: Player starts to drag a piece UI asks game logic for the legal movement area of that piece and lets the player drag it within that area Player lets go of a piece UI snaps the piece to the grid (so that it is at a valid logical position) UI tells game logic the new logical position (via mutator methods, which I'd rather avoid) I'm not quite happy with that: I'm writing unit tests for my game logic layer, but not the UI, and it turned out all the tricky code is in the UI: Stopping the piece from colliding with others or the boundary and snapping it to the grid. I don't like the fact that the UI tells the game logic about the new state, I would rather have it call a movePieceLeft() method or something like that, as in my other games, but I didn't get far with that approach, because the game logic knows nothing about the dragging and snapping that's possible in the UI. I think the best thing to do would be to get rid of my game logic layer and implement a physics layer instead. I've got a few questions regarding that: Is such a physics layer common, or is it more typical to have the game logic layer do this? Would the snapping to grid and piece dragging code belong to the UI or the physics layer? Would such a physics layer typically work with pixel sizes or with some kind of logical unit, like my game logic layer? I've seen event-based collision detection in a game's code base once, that is, the player would just drag the piece, the UI would render that obediently and notify the physics system, and the physics system would call a onCollision() method on the piece once a collision is detected. What is more common? This approach or asking for the legal movement area first? [1] layer is probably not the right word for what I mean, but subsystem sounds overblown and class is misguiding, because each layer can consist of several classes.

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  • WHERE x = @x OR @x IS NULL

    - by steveh99999
    Every SQL DBA and developer should read the blog of MVP Erland Sommarskog – but particularly  his article on dynamic search conditions in T-SQL. I’ve linked above to his SQL 2005 article but his 2008 version is also a must-read. I seem to regularly come across uses of the SQL in the title above… Erland’s article explains in detail why this is inefficient, but I came across a nice example recently… A stored procedure contained the following code :- WHERE @Name is null or [Name] like @Name as a nonclustered index exists on the Name column, you might assume this would be handled efficiently by SQL Server. However, I got the following output from SET STATISTICS IO Table 'xxxxx'. Scan count 15, logical reads 47760, physical reads 9, read-ahead reads 13872, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0. Note the high number of logical reads… After a bit of investigation, we found that @Name could never actually be set to NULL in this particular example. ie the @x IS NULL was spurious… So, we changed the call to WHERE  [Name] like @Name Now, how much more efficient is this code ? Table 'xxxxx'. Scan count 3, logical reads 24, physical reads 0, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0 A nice easy win in this case…… a full index scan has been replaced by a significantly more efficient index seek. I managed to recreate the same behaviour on Adventureworks – here’s a quick query to demonstrate :- USE adventureworks SET STATISTICS IO ON DECLARE @id INT = 51721 SELECT * FROM Sales.SalesOrderDetail WHERE @id IS NULL OR salesorderid = @id SELECT * FROM Sales.SalesOrderDetail WHERE salesorderid = @id Take a look at the STATISTICS IO output and compare the actual query plans used to prove the impact of  WHERE @id IS NULL. And just to follow some of Erland’s advice – here’s how you could get similar performance if it was possible that @id could actually sometimes contain NULL. DECLARE @sql NVARCHAR(4000), @parameterlist NVARCHAR(4000) DECLARE @id INT = 51721 – or change to NULL to prove query is functionally correct SET @sql = 'SELECT * FROM Sales.SalesOrderDetail WHERE 1 = 1' IF @id IS NOT NULL SET @sql = @sql + ' AND salesorderid = @id' IF @id IS NULL SET @sql = @sql + ' AND salesorderid IS NULL' SET @parameterlist = '@id INT' EXEC sp_executesql @sql, @parameterlist,@id Sometimes I think we focus too much on hardware and SQL Server configuration – when really the answer is focus on writing efficient SQL.

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  • Package upgrade on Ubuntu raid server and grub setup issue

    - by RecNes
    I have remote Ubuntu 10.10 server running on raid system. I did package upgrade yesterday night for security reasons. During the upgrade, grub installation screen appeared and asked me which partition I wanted to install grub. Options are sda,sdb,md1 and md2. I decide to install them on both sda and sdb partitions. I wondering, was I make true decision? If machine get reboot is it can be boot up safely? You can find fdisk output and fstab mount points below: Fstab: proc /proc proc defaults 0 0 none /dev/pts devpts gid=5,mode=620 0 0 /dev/md0 none swap sw 0 0 /dev/md1 /boot ext3 defaults 0 0 /dev/md2 / ext3 defaults 0 0 Fdisk: Disk /dev/sda: 750.2 GB, 750156374016 bytes 255 heads, 63 sectors/track, 91201 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00029bb5 Device Boot Start End Blocks Id System /dev/sda1 1 262 2102562 fd Linux raid autodetect /dev/sda2 263 295 265072+ fd Linux raid autodetect /dev/sda3 296 91201 730202445 fd Linux raid autodetect Disk /dev/md0: 2152 MB, 2152923136 bytes 2 heads, 4 sectors/track, 525616 cylinders Units = cylinders of 8 * 512 = 4096 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/md0 doesn't contain a valid partition table Disk /dev/md1: 271 MB, 271319040 bytes 2 heads, 4 sectors/track, 66240 cylinders Units = cylinders of 8 * 512 = 4096 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/md1 doesn't contain a valid partition table Disk /dev/md2: 747.7 GB, 747727224832 bytes 2 heads, 4 sectors/track, 182550592 cylinders Units = cylinders of 8 * 512 = 4096 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/md2 doesn't contain a valid partition table Disk /dev/sdb: 750.2 GB, 750156374016 bytes 255 heads, 63 sectors/track, 91201 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00088969 Device Boot Start End Blocks Id System /dev/sdb1 1 262 2102562 fd Linux raid autodetect /dev/sdb2 263 295 265072+ fd Linux raid autodetect /dev/sdb3 296 91201 730202445 fd Linux raid autodetect

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  • How to use Hardware RAID in Ubuntu Server

    - by user2071938
    I have an Adaptec RAID-Controller and created an RAID-1(Mirroring) succesfully. Now I have installed Ubuntu Server 12.04.3. When I type fdisk -l I get this output: bf@fileserver:~$ sudo fdisk -l Disk /dev/sda: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders, total 1953525168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0x00000000 Disk /dev/sda doesn't contain a valid partition table Disk /dev/sdb: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders, total 1953525168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0x00000000 Disk /dev/sdb doesn't contain a valid partition table Disk /dev/sdc: 80.0 GB, 80026361856 bytes 255 heads, 63 sectors/track, 9729 cylinders, total 156301488 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x0004c454 Device Boot Start End Blocks Id System /dev/sdc1 * 2048 499711 248832 83 Linux /dev/sdc2 501758 156301311 77899777 5 Extended /dev/sdc5 501760 156301311 77899776 8e Linux LVM Disk /dev/mapper/fileserver--vg-root: 75.6 GB, 75606523904 bytes 255 heads, 63 sectors/track, 9191 cylinders, total 147668992 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/mapper/fileserver--vg-root doesn't contain a valid partition table Disk /dev/mapper/ddf1_Data: 1000.1 GB, 1000065728512 bytes 255 heads, 63 sectors/track, 121584 cylinders, total 1953253376 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0x00000000 Disk /dev/mapper/ddf1_Data doesn't contain a valid partition table Disk /dev/mapper/fileserver--vg-swap_1: 4160 MB, 4160749568 bytes 255 heads, 63 sectors/track, 505 cylinders, total 8126464 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/mapper/fileserver--vg-swap_1 doesn't contain a valid partition table The 80 GB HDD is for the System The 1000.2 GB HDD should be for my data. But I'm a bit confused becauser there are listed two 1000.2 GB HDDs, due the Hardware RAID shoudln't there be only one HDD vissible to the OS? (I have two 1000.2 GB HDDs in an Raid-1 Array) dmraid gives me bf@fileserver:~$ sudo dmraid -r /dev/sdb: ddf1, ".ddf1_disks", GROUP, ok, 1953253376 sectors, data@ 0 /dev/sda: ddf1, ".ddf1_disks", GROUP, ok, 1953253376 sectors, data@ 0 so It seems to be ok? But how do I partitionate this disks and which one should I mount(sdb or sda?) Hope you can help me thx Florian

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  • Merging free space of hard drive to primary partition

    - by Dibya Ranjan
    I have purchased a new HDD, I tried to format making 1 primary partition, I converted the rest unallocated space to extended partition then to logical drive now I have 3 logical drives. I feel that the size allocated to the primary partition is less so I used shrink option to the 3 logical partitions in diskmgmt but each partition is resulting in one memory block of Free space. Now I want to merge these free spaces to my primary partition.

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  • Recover RAID 5 data after created new array instead of re-using

    - by Brigadieren
    Folks please help - I am a newb with a major headache at hand (perfect storm situation). I have a 3 1tb hdd on my ubuntu 11.04 configured as software raid 5. The data had been copied weekly onto another separate off the computer hard drive until that completely failed and was thrown away. A few days back we had a power outage and after rebooting my box wouldn't mount the raid. In my infinite wisdom I entered mdadm --create -f... command instead of mdadm --assemble and didn't notice the travesty that I had done until after. It started the array degraded and proceeded with building and syncing it which took ~10 hours. After I was back I saw that that the array is successfully up and running but the raid is not I mean the individual drives are partitioned (partition type f8 ) but the md0 device is not. Realizing in horror what I have done I am trying to find some solutions. I just pray that --create didn't overwrite entire content of the hard driver. Could someone PLEASE help me out with this - the data that's on the drive is very important and unique ~10 years of photos, docs, etc. Is it possible that by specifying the participating hard drives in wrong order can make mdadm overwrite them? when I do mdadm --examine --scan I get something like ARRAY /dev/md/0 metadata=1.2 UUID=f1b4084a:720b5712:6d03b9e9:43afe51b name=<hostname>:0 Interestingly enough name used to be 'raid' and not the host hame with :0 appended. Here is the 'sanitized' config entries: DEVICE /dev/sdf1 /dev/sde1 /dev/sdd1 CREATE owner=root group=disk mode=0660 auto=yes HOMEHOST <system> MAILADDR root ARRAY /dev/md0 metadata=1.2 name=tanserv:0 UUID=f1b4084a:720b5712:6d03b9e9:43afe51b Here is the output from mdstat cat /proc/mdstat Personalities : [linear] [multipath] [raid0] [raid1] [raid6] [raid5] [raid4] [raid10] md0 : active raid5 sdd1[0] sdf1[3] sde1[1] 1953517568 blocks super 1.2 level 5, 512k chunk, algorithm 2 [3/3] [UUU] unused devices: <none> fdisk shows the following: fdisk -l Disk /dev/sda: 80.0 GB, 80026361856 bytes 255 heads, 63 sectors/track, 9729 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000bf62e Device Boot Start End Blocks Id System /dev/sda1 * 1 9443 75846656 83 Linux /dev/sda2 9443 9730 2301953 5 Extended /dev/sda5 9443 9730 2301952 82 Linux swap / Solaris Disk /dev/sdb: 750.2 GB, 750156374016 bytes 255 heads, 63 sectors/track, 91201 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000de8dd Device Boot Start End Blocks Id System /dev/sdb1 1 91201 732572001 8e Linux LVM Disk /dev/sdc: 500.1 GB, 500107862016 bytes 255 heads, 63 sectors/track, 60801 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00056a17 Device Boot Start End Blocks Id System /dev/sdc1 1 60801 488384001 8e Linux LVM Disk /dev/sdd: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000ca948 Device Boot Start End Blocks Id System /dev/sdd1 1 121601 976760001 fd Linux raid autodetect Disk /dev/dm-0: 1250.3 GB, 1250254913536 bytes 255 heads, 63 sectors/track, 152001 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/dm-0 doesn't contain a valid partition table Disk /dev/sde: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x93a66687 Device Boot Start End Blocks Id System /dev/sde1 1 121601 976760001 fd Linux raid autodetect Disk /dev/sdf: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0xe6edc059 Device Boot Start End Blocks Id System /dev/sdf1 1 121601 976760001 fd Linux raid autodetect Disk /dev/md0: 2000.4 GB, 2000401989632 bytes 2 heads, 4 sectors/track, 488379392 cylinders Units = cylinders of 8 * 512 = 4096 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 524288 bytes / 1048576 bytes Disk identifier: 0x00000000 Disk /dev/md0 doesn't contain a valid partition table Per suggestions I did clean up the superblocks and re-created the array with --assume-clean option but with no luck at all. Is there any tool that will help me to revive at least some of the data? Can someone tell me what and how the mdadm --create does when syncs to destroy the data so I can write a tool to un-do whatever was done? After the re-creating of the raid I run fsck.ext4 /dev/md0 and here is the output root@tanserv:/etc/mdadm# fsck.ext4 /dev/md0 e2fsck 1.41.14 (22-Dec-2010) fsck.ext4: Superblock invalid, trying backup blocks... fsck.ext4: Bad magic number in super-block while trying to open /dev/md0 The superblock could not be read or does not describe a correct ext2 filesystem. If the device is valid and it really contains an ext2 filesystem (and not swap or ufs or something else), then the superblock is corrupt, and you might try running e2fsck with an alternate superblock: e2fsck -b 8193 Per Shanes' suggestion I tried root@tanserv:/home/mushegh# mkfs.ext4 -n /dev/md0 mke2fs 1.41.14 (22-Dec-2010) Filesystem label= OS type: Linux Block size=4096 (log=2) Fragment size=4096 (log=2) Stride=128 blocks, Stripe width=256 blocks 122101760 inodes, 488379392 blocks 24418969 blocks (5.00%) reserved for the super user First data block=0 Maximum filesystem blocks=0 14905 block groups 32768 blocks per group, 32768 fragments per group 8192 inodes per group Superblock backups stored on blocks: 32768, 98304, 163840, 229376, 294912, 819200, 884736, 1605632, 2654208, 4096000, 7962624, 11239424, 20480000, 23887872, 71663616, 78675968, 102400000, 214990848 and run fsck.ext4 with every backup block but all returned the following: root@tanserv:/home/mushegh# fsck.ext4 -b 214990848 /dev/md0 e2fsck 1.41.14 (22-Dec-2010) fsck.ext4: Invalid argument while trying to open /dev/md0 The superblock could not be read or does not describe a correct ext2 filesystem. If the device is valid and it really contains an ext2 filesystem (and not swap or ufs or something else), then the superblock is corrupt, and you might try running e2fsck with an alternate superblock: e2fsck -b 8193 <device> Any suggestions? Regards!

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  • Re-sizing disk partition linux/vm

    - by Tiffany Walker
    I VM Player running a linux guest and I was wanting to know how do I expand the disk? In the VM player I gave more disk space but I am not sure how to mount/expand/connect the new disk space to the system. My old disk space was 14GB [root@localhost ~]# df -h / Filesystem Size Used Avail Use% Mounted on /dev/mapper/VolGroup-lv_root 14G 4.5G 8.2G 36% / Then I expanded it and now I see sda2 which is the new space? [root@localhost ~]# fdisk -l Disk /dev/sda: 128.8 GB, 128849018880 bytes 255 heads, 63 sectors/track, 15665 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000cd44d Device Boot Start End Blocks Id System /dev/sda1 * 1 64 512000 83 Linux Partition 1 does not end on cylinder boundary. /dev/sda2 64 2611 20458496 8e Linux LVM Disk /dev/mapper/VolGroup-lv_root: 14.5 GB, 14537457664 bytes 255 heads, 63 sectors/track, 1767 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/mapper/VolGroup-lv_swap: 6408 MB, 6408896512 bytes 255 heads, 63 sectors/track, 779 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Do I need to mount the new space first? resize2fs -p /dev/mapper/VolGroup-lv_root 108849018880 resize2fs 1.41.12 (17-May-2010) The containing partition (or device) is only 3549184 (4k) blocks. You requested a new size of 1474836480 blocks. resize2fs -p /dev/mapper/VolGroup-lv_root 128849018880 resize2fs 1.41.12 (17-May-2010) resize2fs: Invalid new size: 128849018880 [root@localhost ~]# lvextend -L+90GB /dev/mapper/VolGroup-lv_root Extending logical volume lv_root to 103.54 GiB Insufficient free space: 23040 extents needed, but only 0 available [root@localhost ~]# lvextend -L90GB /dev/mapper/VolGroup-lv_root Extending logical volume lv_root to 90.00 GiB Insufficient free space: 19574 extents needed, but only 0 available EDIT: So after trying pvcreate/vgextend nothing has so far worked. I'm guessing the new disk space added from VM Player is not showing up? pvscan PV /dev/sda2 VG VolGroup lvm2 [19.51 GiB / 0 free] Total: 1 [19.51 GiB] / in use: 1 [19.51 GiB] / in no VG: 0 [0 ]

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  • linux hardware raid 10 / lvm / virtual machine partition alignment and filesystem optimization

    - by Jason Ward
    I've been reading everything I can find about partition alignment and filesystem optimization (ext4 and xfs) but still don't know enough to be confident in setting up my current configuration. My remaining confusion comes from the LVM layer and if I should use raid parameters on the filesystem in guest os'es. My main questions are: When I use 'pvcreate --dataalignment' do I use the stripe-width as calculated for a filesystem on RAID (128kB for ext4 in my situation), the Stripe size of the RAID set (256kB), something else altogether, or do I not need this? When I create ext2/3/4 or xfs filesystems in guests on the Logical Volumes, should I add the settings for the underlying RAID (e.g. mkfs.ext4 -b 4096 -E stride=64,stripe-width=128)? Does anyone see any glaring errors in my set up below? I'm running some benchmarks now but haven't done enough to start comparing results. I have four drives in RAID 10 on a 3ware 9750-4i controller (more details on the settings below) giving me a 6.0TB device at /dev/sda. Here is my partition table: Model: LSI 9750-4i DISK (scsi) Disk /dev/sda: 5722024MiB Sector size (logical/physical): 512B/512B Partition Table: gpt Number Start End Size File system Name Flags 1 1.00MiB 257MiB 256MiB ext4 BOOTPART boot 2 257MiB 4353MiB 4096MiB linux-swap(v1) 3 4353MiB 266497MiB 262144MiB ext4 4 266497MiB 4460801MiB 4194304MiB Partition 1 is to be the /boot partition for my xen host. Partition 2 is swap. Partition 3 is to be the root (/) for my xen host. Partition 4 is to be (the only) physical volume to be used by LVM (for those who are counting, I left about 1.2TB unallocated for now) For my Xen guests, I usually create a Logical Volume of the needed size and present it to the guests for them to partition as needed. I know there are other ways of handling that but this method works best for my situation. Here's the hardware of interest on my CentOS 6.3 Xen Host: 4x Seagate Barracuda 3TB ST3000DM001 Drives (sector size: 512 logical/4096 physical) 3ware 9750-4i w/BBU (sector size reported: 512 logical/512 physical) All four drives make up a RAID 10 array. Stripe: 256kB Write Cache enabled Read Cache: intelligent StoreSave: Balance Thanks!

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  • How can I recover XFS partitions from a formatted HD?

    - by giuprivite
    I deleted the partition table of my HD. I wanted to format another one, but by mistake, I formatted the wrong one. Then I also created some new partition on it. Now I would like, if possible, to recover my old data. The old configuration was this: A primary NTFS partition with Windows, and a secondary partition with four logical partitions: a swap and three XFS partitions (two for Ubuntu and OpenSuSE, and one with the home for both systems). This is the output I get when I run gpart in a terminal: ubuntu@ubuntu:~$ sudo gpart /dev/sdb Begin scan... Possible partition(Windows NT/W2K FS), size(39997mb), offset(0mb) Possible extended partition at offset(39997mb) Possible partition(Linux swap), size(8189mb), offset(39997mb) Possible partition(SGI XFS filesystem), size(40942mb), offset(48187mb) Possible partition(SGI XFS filesystem), size(40942mb), offset(89149mb) Possible partition(SGI XFS filesystem), size(175044mb), offset(130112mb) End scan. Checking partitions... Partition(OS/2 HPFS, NTFS, QNX or Advanced UNIX): primary Partition(Linux swap or Solaris/x86): logical Partition(Linux ext2 filesystem): logical Partition(Linux ext2 filesystem): orphaned logical Partition(Linux ext2 filesystem): orphaned logical Ok. Guessed primary partition table: Primary partition(1) type: 007(0x07)(OS/2 HPFS, NTFS, QNX or Advanced UNIX) size: 39997mb #s(81915360) s(63-81915422) chs: (0/1/1)-(1023/254/63)d (0/1/1)-(5098/254/51)r Primary partition(2) type: 015(0x0F)(Extended DOS, LBA) size: 265245mb #s(543221849) s(81915435-625137283) chs: (1023/254/63)-(1023/254/63)d (5099/0/1)-(38912/254/2)r Primary partition(3) type: 000(0x00)(unused) size: 0mb #s(0) s(0-0) chs: (0/0/0)-(0/0/0)d (0/0/0)-(0/0/0)r Primary partition(4) type: 000(0x00)(unused) size: 0mb #s(0) s(0-0) chs: (0/0/0)-(0/0/0)d (0/0/0)-(0/0/0)r Looking the first eight lines, it seems the data are still there... but I don't know how to recover them. I have a free second HD of about 500 GB (the formatted one is 320 GB) that I can use for the recovery process.

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