Search Results

Search found 2396 results on 96 pages for 'rate'.

Page 10/96 | < Previous Page | 6 7 8 9 10 11 12 13 14 15 16 17  | Next Page >

  • Massive Crawling requests from Google Apps Engine useragent

    - by SilentPlayer
    Hi friends, I'm badly affected with 'Google AppEngine-Google' UserAgent.. receiving 5/6 requests per second on http server. This bot is crawling my site just like GoogleBot does. Following is the sample of url in my access logs. 72.14.192.3 - - [19/May/2010:01:27:06 +0000] "GET /some-url/etc-123.htm HTTP/1.1" 200 4707 "-" "AppEngine-Google; (+http://code.google.com/appengine; appid: harpy000)" I have checked the ip address it is registered with Google Inc. Can anyone tell me where i can report Abuse to Google Inc. Or any information about this issue. Thank you!

    Read the article

  • Can Haproxy deny a request by IP if its stick-table is full?

    - by bantic
    In my haproxy configs I'm setting a stick-table of size 5 that stores every incoming IP address (for 1 minute), and it is set as nopurge so new entries won't get stored in the table. What I'd like to have happen is that they would get denied, but that isn't happening. The stick-table line is: stick-table type ip size 5 expire 1m nopurge store gpc0 And the whole configs are: global maxconn 30000 ulimit-n 65536 log 127.0.0.1 local0 log 127.0.0.1 local1 debug stats socket /var/run/haproxy.stat mode 600 level operator defaults mode http timeout connect 5000ms timeout client 50000ms timeout server 50000ms backend fragile_backend tcp-request content track-sc2 src stick-table type ip size 5 expire 1m nopurge store gpc0 server fragile_backend1 A.B.C.D:80 frontend http_proxy bind *:80 mode http option forwardfor default_backend fragile_backend I have confirmed (connecting to haproxy's stats using socat readline /var/run/haproxy.stat) that the stick-table fills up with 5 IP addresses, but then every request after that from a new IP just goes straight through -- it isn't added to the stick-table, nothing is removed from the stick-table, and the request is not denied. What I'd like to do is deny the request if the stick-table is full. Is this possible? I'm using haproxy 1.5.

    Read the article

  • Traffic shaping on Linux with HTB: weird results

    - by DADGAD
    I'm trying to have some simple bandwidth throttling set up on a Linux server and I'm running into what seems to be very weird stuff despite a seemingly trivial config. I want to shape traffic coming to a specific client IP (10.41.240.240) to a hard maximum of 75Kbit/s. Here's how I set up the shaping: # tc qdisc add dev eth1 root handle 1: htb default 1 r2q 1 # tc class add dev eth1 parent 1: classid 1:1 htb rate 75Kbit # tc class add dev eth1 parent 1:1 classid 1:10 htb rate 75kbit # tc filter add dev eth1 parent 1:0 protocol ip prio 1 u32 match ip dst 10.41.240.240 flowid 1:10 To test, I start a file download over HTTP from the said client machine and measure the resulting speed by looking at Kb/s in Firefox. Now, the behaviour is rather puzzling: the DL starts at about 10Kbyte/s and proceeds to pick up speed until it stabilizes at about 75Kbytes/s (Kilobytes, not Kilobits as configured!). Then, If I start several parallel downloads of that very same file, each download stabilizes at about 45Kbytes/s; the combined speed of those downloads thus greatly exceeds the configured maximum. Here's what I get when probing tc for debug info [root@kup-gw-02 /]# tc -s qdisc show dev eth1 qdisc htb 1: r2q 1 default 1 direct_packets_stat 1 Sent 17475717 bytes 1334 pkt (dropped 0, overlimits 2782 requeues 0) rate 0bit 0pps backlog 0b 12p requeues 0 [root@kup-gw-02 /]# tc -s class show dev eth1 class htb 1:1 root rate 75000bit ceil 75000bit burst 1608b cburst 1608b Sent 14369397 bytes 1124 pkt (dropped 0, overlimits 0 requeues 0) rate 577896bit 5pps backlog 0b 0p requeues 0 lended: 1 borrowed: 0 giants: 1938 tokens: -205561 ctokens: -205561 class htb 1:10 parent 1:1 prio 0 **rate 75000bit ceil 75000bit** burst 1608b cburst 1608b Sent 14529077 bytes 1134 pkt (dropped 0, overlimits 0 requeues 0) **rate 589888bit** 5pps backlog 0b 11p requeues 0 lended: 1123 borrowed: 0 giants: 1938 tokens: -205561 ctokens: -205561 What I can't for the life of me understand is this: how come I get a "rate 589888bit 5pps" with a config of "rate 75000bit ceil 75000bit"? Why does the effective rate get so much higher than the configured rate? What am I doing wrong? Why is it behaving the way it is? Please help, I'm stumped. Thanks guys.

    Read the article

  • SpeechSynthesizer in C# creates wav that has 22kHz... needs to be 16kHz

    - by Adrian
    My C# application needs to covert text to wav file and inject it into a Skype call. The code that creates the wav file is below. The problem is that the file has 22kHz sample rate and Skype accepts only 16kHz. Is there any way to adjust this setting? using (System.IO.FileStream stream = System.IO.File.Create("message.wav")) { System.Speech.Synthesis.SpeechSynthesizer speechEngine = new System.Speech.Synthesis.SpeechSynthesizer(); speechEngine.SetOutputToWaveStream(stream); speechEngine.Speak(number); stream.Flush(); }

    Read the article

  • Does Google rate the webpage by amount of visits?

    - by petiar
    Hi there, there is quite extensive discussion about this topic on another website and I am really losing my confidence. The thing is that I claim that the amount (count) of visits is NOT a criteria for increasing the PR of the particular web because: a) Google just doesn't know about every single visit on a webpage (in case it's not using GA) b) Google just would not rate by something what Google actually affects Thanks for your opinions. Peter.

    Read the article

  • Is it possible to rate-limit an scp/sftp/rsync/etc transfer from the command-line? ie, manual QoS on

    - by warren
    Specifically, I am looking to rate-limit an scp or sftp session (or other arbitrary network call) in the call itself. For example, let's say I want to copy 100MB to one server, and 1GB to another. I'd like to be able to run both of these at the same time, but maintain a QoS for "normal" computer usage - somewhat similar to how you can rate-limit bittorrent. Is there a way to do this without touching the networking hardware? I'm envisioning something akin to: magic-qos-tool 'scp file user@host:/path/to/file' Or.. scp -rate 40kbps file user@host:/path/to/file

    Read the article

  • Is it possible to rate-limit an scp/sftp/rsync transfer from the command-line? ie, manual QoS on a s

    - by warren
    Specifically, I am looking to rate-limit an scp or sftp session in the call itself. For example, let's say I want to copy 100MB to one server, and 1GB to another. I'd like to be able to run both of these at the same time, but maintain a QoS for "normal" computer usage - somewhat similar to how you can rate-limit bittorrent. Is there a way to do this without touching the networking hardware? I'm envisioning something akin to: magic-qos-tool 'scp file user@host:/path/to/file' Or.. scp -rate 40kbps file user@host:/path/to/file

    Read the article

  • How to move to next textfield using keyboardtype numberandpunctuation using textfield notification

    - by Rani
    Hi guys, I am having code ItemsController.h UITextField* quantity; UITextField* rate; UITextField* tax2; ItemController.m quantity=[[UITextField alloc]initWithFrame:CGRectMake(158,10.5,140,30)]; quantity.textColor = [UIColor blackColor]; quantity.font = [UIFont systemFontOfSize:15.0]; quantity.backgroundColor = [UIColor clearColor]; quantity.returnKeyType=UIReturnKeyNext; quantity.keyboardType = UIKeyboardTypeNumbersAndPunctuation; quantity.leftViewMode = UITextFieldViewModeAlways; quantity.delegate = self; rate=[[UITextField alloc]initWithFrame:CGRectMake(158,10.5,140,30)]; rate.textColor = [UIColor blackColor]; rate.font = [UIFont systemFontOfSize:15.0]; rate.backgroundColor = [UIColor clearColor]; rate.returnKeyType=UIReturnKeyNext; rate.keyboardType = UIKeyboardTypeNumbersAndPunctuation; rate.leftViewMode = UITextFieldViewModeAlways; rate.delegate = self; tax2=[[UITextField alloc]initWithFrame:CGRectMake(158,10.5,140,30)]; tax2.textColor = [UIColor blackColor]; tax2.font = [UIFont systemFontOfSize:15.0]; tax2.backgroundColor = [UIColor clearColor]; tax2.returnKeyType=UIReturnKeyDone; tax2.keyboardType = UIKeyboardTypeAlphabet; tax2.leftViewMode = UITextFieldViewModeAlways; tax2.delegate = self; - (BOOL)textFieldShouldReturn:(UITextField*)textField { if(textField==quantity) { [rate becomeFirstResponder]; } if(textField == rate) { [tax2 becomeFirstResponder]; } else if(textField==tax2) { [textField resignFirstResponder]; } return YES; } Using UITextfield notifications while I am moving from quantity textfield to rate textfield the keyboard type is alphabetical its getting actually I gav eit has Number and punctuation why I am not getting. can any one help me to solve this as soon as possible. Thanks in advance.

    Read the article

  • C# .Net Serial DataReceived Event response too slow for high-rate data.

    - by Matthew
    Hi, I have set up a SerialDataReceivedEventHandler, with a forms based program in VS2008 express. My serial port is set up as follows: 115200, 8N1 Dtr and Rts enabled ReceivedBytesThreshold = 1 I have a device I am interfacing with over a BlueTooth, USB to Serial. Hyper terminal receives the data just fine at any data rate. The data is sent regularly in 22 byte long packets. This device has an adjustable rate at which data is sent. At low data rates, 10-20Hz, the code below works great, no problems. However, when I increase the data rate past 25Hz, there starts to recieve mulitple packets on one call. What I mean by this is that there should be a event trigger for every incoming packet. With higher output rates, I have tested the buffer size (BytesToRead command) immediatly when the event is called and there are multiple packets in the buffer then. I think that the event fires slowly and by the time it reaches the code, more packes have hit the buffer. One test I do is see how many time the event is trigger per second. At 10Hz, I get 10 event triggers, awesome. At 100Hz, I get something like 40 event triggers, not good. My goal for data rate is 100HZ is acceptable, 200Hz preferred, and 300Hz optimum. This should work because even at 300Hz, that is only 52800bps, less than half of the set 115200 baud rate. Anything I am over looking? public Form1() { InitializeComponent(); serialPort1.DataReceived += new SerialDataReceivedEventHandler(serialPort1_DataReceived); } private void serialPort1_DataReceived(object sender, SerialDataReceivedEventArgs e) { this.Invoke(new EventHandler(Display_Results)); } private void Display_Results(object s, EventArgs e) { serialPort1.Read(IMU, 0, serial_Port1.BytesToRead); }

    Read the article

  • How do you set rate limit access to your API using Iptables?

    - by Cory
    How can you set rate limit access to API using Iptables. Tried to set limit using port 80, but I don't want to set limit to the web access entirely. Is there a way to specified a subdomain rather than port. Example: set rate limit to api.example.com not example.com? If there is no way to set rate limit by subdomain, what is the suggested rate limit access to port 80 without risking blocking a legitimate web user? One connection per second would be enough?

    Read the article

  • how to keep display tick rate steady when using continuous collision detection?

    - by nas Ns
    (I've just found about this forum). I hope it is ok to repost my question again here. I posted this question at stackoverflow, but it looks like I might get better help here. Here is the question: I've implemented basic particles motion simulation with continuous collision detection. But there is small issue in display. Assume simple case of circles moving inside square. All elastic collisions. no firction. All motion is constant speed. No forces are involved, no gravity. So when a particle is moving, it is always moving at constant speed (in between collisions) What I do now is this: Let the simulation time step be 1 second (for example). This is the time step simulation is advanced before displaying the new state (unless there is a collision sooner than this). At start of each time step, time for the next collision between any particles or a particle with a wall is determined. Call this the TOC time; let’s say TOC was .5 seconds in this case. Since TOC is smaller than the standard time step, then the system is moved by TOC and the new system is displayed so that the new display shows any collisions as just taking place (say 2 circles just touched each other’s, or a circle just touched a wall) Next, the collision(s) are resolved (i.e. speeds updated, changed directions etc..). A new step is started. The same thing happens. Now assume there is no collision detected within the next 1 second (those 2 circles above will not be in collision any more, even though they are still touching, due to their speeds showing they are moving apart now), Hence, simulation time is advanced now by the full one second, the standard time step, and particles are moved on the screen using 1 second simulation time and new display is shown. You see what has just happened: One frame ran for .5 seconds, but the next frame runs for 1 second, may be the 3rd frame is displayed after 2 seconds, may be the 4th frame is displayed after 2.8 seconds (because TOC was .8 seconds then) and so on. What happens is that the motion of a particle on the screen appears to speed up or slow down, even though it is moving at constant speed and was not even involved in a collision. i.e. Looking at one particle on its own, I see it suddenly speeding up or slowing down, becuase another particle had hit a wall. This is because the display tick is not uniform. i.e. the frame rate update is changing, giving the false illusion that a particle is moving at non-constant speed while in fact it is moving at constant speed. The motion on the screen is not smooth, since the screen is not updating at constant rate. I am not able to figure how to fix this. If I want to show 2 particles at the moment of the collision, I must draw the screen at different times. Drawing the screen always at the same tick interval, results in seeing 2 particles before the collision, and then after the collision, and not just when they colliding, which looked bad when I tried it. So, how do real games handle this issue? How to display things in order to show collisions when it happen, yet keep the display tick constant? These 2 requirements seem to contradict each other’s.

    Read the article

  • Trying to get the associated value from an Enum at runtime in Java

    - by devoured elysium
    I want to accomplish something like the following (my interest is in the toInt() method). Is there any native way to accomplish this? If not, how can I get the integer associated with an enum value (like in C#) ? enum Rate { VeryBad(1), Bad(2), Average(3), Good(4), Excellent(5); private int rate; private Rate(int rate) { this.rate = rate; } public int toInt() { return rate; } } Thanks

    Read the article

  • "Google a raté le coche avec Chrome OS" affirment certains experts qui s'inquiètent des retards pris par le système d'exploitation

    "Google a raté le coche avec Chrome OS", affirment certains experts qui s'inquiètent des retards pris par système d'exploitation de Google Chrome OS aurait du voir le jour en 2010. Et pourtant, personne encore ne l'a vu pointer le bout de son nez. Du coup, certains experts s'inquiètent. Pour eux, le marché change vite, trop vite. Chrome OS est destiné a équiper les appareils de puissance moindre, comme les netbooks et les ordinateurs lowcost. Seulement : "il y a un an, personne n'aurait pu prédire les grands changements qui sont survenus". Ce que les analystes veulent dire, c'est qu'au moment où Google à annoncé son produit, les netbooks avaient le vent en poupe. Aujourd'hui, ils so...

    Read the article

  • Why is programming sometimes viewed as a second-rate role?

    - by CaptainCodeman
    I've been a programmer for most of my life. I recently interviewed for a management job in a company and the interviewer looked at my CV asked me "How do we know you're not just a programmer". Which in my opinion is quite a rude thing to say, but it's not an isolated incident and I've heard other similar things in other settings. It does seem that for some reason being a programmer is viewed as having a lower station, especially in settings where they have a separate IT department which is viewed as a support role. Is a career in software development doomed to being a second-rate support citizen?

    Read the article

  • Google a-t-il raté son entrée sur le marché des tablettes ? Android connaît une "croissance pénible" d'après DisplaySearch

    Google a-t-il raté son entrée sur le marché des tablettes ? Android connaît une "croissance pénible" d'après DisplaySearch Six mois après le lancement d'Android 3 (alias Honeycomb), force est de constater que les ventes des tablettes qui tournent dessus sont loin de défrayer les chroniques, elles ne semblent pas être en mesure en tout cas de freiner les ventes frénétiques de l'iPad d'Apple. Pour l'analyste Richard Shim de DisplaySearch, l'univers Android connaît une « croissance pénible » avec Honeycomb : « il est clair que les premières tablettes fondées sur Android ne s'écoulent pas aussi bien que ce que beaucoup attendaient, quelques marques avec lesquelles ...

    Read the article

  • Which one of the Google Analytics stats should be my top priority to improve SEO: visits, pageviews, bounce rate, new visitors, or visit duration

    - by HOY
    My site is getting a lot of traffic from an image (a company logo image) because this image is ranked 1st in Google search results for a company's title. (I have no idea how that happened.) This image is must for my website, but it is not relevant to the site content, so irrelevant people search for the image and find out about my site. I get interesting statistics: Pros: Total Visits & Avg. New Visits Cons: Avg. Page/Visit, Avg. Visit Duration, Bounce Rate I am confused if this image is helpful to my website. I don't know what the balance between those 5 statistics should be. My website is 2 months old, and we are working on SEO at the moment. Edit: here are the details about the image: Search Keyword: arcelik logo Search Site: google.com.tr Search URL

    Read the article

  • VLOOKUP in Excel, part 2: Using VLOOKUP without a database

    - by Mark Virtue
    In a recent article, we introduced the Excel function called VLOOKUP and explained how it could be used to retrieve information from a database into a cell in a local worksheet.  In that article we mentioned that there were two uses for VLOOKUP, and only one of them dealt with querying databases.  In this article, the second and final in the VLOOKUP series, we examine this other, lesser known use for the VLOOKUP function. If you haven’t already done so, please read the first VLOOKUP article – this article will assume that many of the concepts explained in that article are already known to the reader. When working with databases, VLOOKUP is passed a “unique identifier” that serves to identify which data record we wish to find in the database (e.g. a product code or customer ID).  This unique identifier must exist in the database, otherwise VLOOKUP returns us an error.  In this article, we will examine a way of using VLOOKUP where the identifier doesn’t need to exist in the database at all.  It’s almost as if VLOOKUP can adopt a “near enough is good enough” approach to returning the data we’re looking for.  In certain circumstances, this is exactly what we need. We will illustrate this article with a real-world example – that of calculating the commissions that are generated on a set of sales figures.  We will start with a very simple scenario, and then progressively make it more complex, until the only rational solution to the problem is to use VLOOKUP.  The initial scenario in our fictitious company works like this:  If a salesperson creates more than $30,000 worth of sales in a given year, the commission they earn on those sales is 30%.  Otherwise their commission is only 20%.  So far this is a pretty simple worksheet: To use this worksheet, the salesperson enters their sales figures in cell B1, and the formula in cell B2 calculates the correct commission rate they are entitled to receive, which is used in cell B3 to calculate the total commission that the salesperson is owed (which is a simple multiplication of B1 and B2). The cell B2 contains the only interesting part of this worksheet – the formula for deciding which commission rate to use: the one below the threshold of $30,000, or the one above the threshold.  This formula makes use of the Excel function called IF.  For those readers that are not familiar with IF, it works like this: IF(condition,value if true,value if false) Where the condition is an expression that evaluates to either true or false.  In the example above, the condition is the expression B1<B5, which can be read as “Is B1 less than B5?”, or, put another way, “Are the total sales less than the threshold”.  If the answer to this question is “yes” (true), then we use the value if true parameter of the function, namely B6 in this case – the commission rate if the sales total was below the threshold.  If the answer to the question is “no” (false), then we use the value if false parameter of the function, namely B7 in this case – the commission rate if the sales total was above the threshold. As you can see, using a sales total of $20,000 gives us a commission rate of 20% in cell B2.  If we enter a value of $40,000, we get a different commission rate: So our spreadsheet is working. Let’s make it more complex.  Let’s introduce a second threshold:  If the salesperson earns more than $40,000, then their commission rate increases to 40%: Easy enough to understand in the real world, but in cell B2 our formula is getting more complex.  If you look closely at the formula, you’ll see that the third parameter of the original IF function (the value if false) is now an entire IF function in its own right.  This is called a nested function (a function within a function).  It’s perfectly valid in Excel (it even works!), but it’s harder to read and understand. We’re not going to go into the nuts and bolts of how and why this works, nor will we examine the nuances of nested functions.  This is a tutorial on VLOOKUP, not on Excel in general. Anyway, it gets worse!  What about when we decide that if they earn more than $50,000 then they’re entitled to 50% commission, and if they earn more than $60,000 then they’re entitled to 60% commission? Now the formula in cell B2, while correct, has become virtually unreadable.  No-one should have to write formulae where the functions are nested four levels deep!  Surely there must be a simpler way? There certainly is.  VLOOKUP to the rescue! Let’s redesign the worksheet a bit.  We’ll keep all the same figures, but organize it in a new way, a more tabular way: Take a moment and verify for yourself that the new Rate Table works exactly the same as the series of thresholds above. Conceptually, what we’re about to do is use VLOOKUP to look up the salesperson’s sales total (from B1) in the rate table and return to us the corresponding commission rate.  Note that the salesperson may have indeed created sales that are not one of the five values in the rate table ($0, $30,000, $40,000, $50,000 or $60,000).  They may have created sales of $34,988.  It’s important to note that $34,988 does not appear in the rate table.  Let’s see if VLOOKUP can solve our problem anyway… We select cell B2 (the location we want to put our formula), and then insert the VLOOKUP function from the Formulas tab: The Function Arguments box for VLOOKUP appears.  We fill in the arguments (parameters) one by one, starting with the Lookup_value, which is, in this case, the sales total from cell B1.  We place the cursor in the Lookup_value field and then click once on cell B1: Next we need to specify to VLOOKUP what table to lookup this data in.  In this example, it’s the rate table, of course.  We place the cursor in the Table_array field, and then highlight the entire rate table – excluding the headings: Next we must specify which column in the table contains the information we want our formula to return to us.  In this case we want the commission rate, which is found in the second column in the table, so we therefore enter a 2 into the Col_index_num field: Finally we enter a value in the Range_lookup field. Important:  It is the use of this field that differentiates the two ways of using VLOOKUP.  To use VLOOKUP with a database, this final parameter, Range_lookup, must always be set to FALSE, but with this other use of VLOOKUP, we must either leave it blank or enter a value of TRUE.  When using VLOOKUP, it is vital that you make the correct choice for this final parameter. To be explicit, we will enter a value of true in the Range_lookup field.  It would also be fine to leave it blank, as this is the default value: We have completed all the parameters.  We now click the OK button, and Excel builds our VLOOKUP formula for us: If we experiment with a few different sales total amounts, we can satisfy ourselves that the formula is working. Conclusion In the “database” version of VLOOKUP, where the Range_lookup parameter is FALSE, the value passed in the first parameter (Lookup_value) must be present in the database.  In other words, we’re looking for an exact match. But in this other use of VLOOKUP, we are not necessarily looking for an exact match.  In this case, “near enough is good enough”.  But what do we mean by “near enough”?  Let’s use an example:  When searching for a commission rate on a sales total of $34,988, our VLOOKUP formula will return us a value of 30%, which is the correct answer.  Why did it choose the row in the table containing 30% ?  What, in fact, does “near enough” mean in this case?  Let’s be precise: When Range_lookup is set to TRUE (or omitted), VLOOKUP will look in column 1 and match the highest value that is not greater than the Lookup_value parameter. It’s also important to note that for this system to work, the table must be sorted in ascending order on column 1! If you would like to practice with VLOOKUP, the sample file illustrated in this article can be downloaded from here. Similar Articles Productive Geek Tips Using VLOOKUP in ExcelImport Microsoft Access Data Into ExcelImport an Access Database into ExcelCopy a Group of Cells in Excel 2007 to the Clipboard as an ImageShare Access Data with Excel in Office 2010 TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips DVDFab 6 Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 Quickly Schedule Meetings With NeedtoMeet Share Flickr Photos On Facebook Automatically Are You Blocked On Gtalk? Find out Discover Latest Android Apps On AppBrain The Ultimate Guide For YouTube Lovers Will it Blend? iPad Edition

    Read the article

  • What does O(log n) mean exactly?

    - by Andreas Grech
    I am currently learning about Big O Notation running times and amortized times. I understand the notion of O(n) linear time, meaning that the size of the input affects the growth of the algorithm proportionally...and the same goes for, for example, quadratic time O(n2) etc..even algorithms, such as permutation generators, with O(n!) times, that grow by factorials. For example, the following function is O(n) because the algorithm grows in proportion to its input n: f(int n) { int i; for (i = 0; i < n; ++i) printf("%d", i); } Similarly, if there was a nested loop, the time would be O(n2). But what exactly is O(log n)? For example, what does it mean to say that the height of a complete binary tree is O(log n)? I do know (maybe not in great detail) what Logarithm is, in the sense that: log10 100 = 2, but I cannot understand how to identify a function with a logarithmic time.

    Read the article

  • What does the 'Burst Rate' stat mean in HDTune?

    - by UpTheCreek
    I recently upgraded my laptop's v slow hard drive to a seagate momentus 7200. Everything is working fine, but I'm a bit confused by these benchmark results: The burst rate is significantly less than the Maximim transfer rate, and not much higher than the normal minimum (if you ignore the spikes). What's going on here? On the HDtune website it defines Burst Rate as: ...the highest speed (in megabytes per second) at which data can be transferred from the drive interface (IDE or SCSI for example) to the operating system. Which begs some questions... e.g. if this is the highest, then how did the bechmarking tool record the 103MB/sec maximum? And if this really is the true maximum, then where is the bottleneck? The laptops SATA interface is on an Intel 82801GBM southbridge controller. When I check in hardware manager, I see that it's driver is iaStor.sys from 2005. Maybe that's the issue? I'll look for a newever version, but any insights would be appreciated. Thanks

    Read the article

  • MacMini transmit rate stuck at 11, every other device can connect at full 54Mbit/s?

    - by chum of chance
    I have a MacMini circa 2007 that's getting very low transmit rates via wifi, 8-11. I have other devices that are getting full 54, including a MacBook Air. With everything else off, the MacMini doesn't want to seem to go any faster. Since it has been previously connected to ethernet its entire life, I was wondering if there were some settings I can change to speed up the connection. Option-clicking the network icon gives this read out: PHY Mode: 802.11g Channel: 1 (2.4 Ghz) Security: WPA2 Personal RSSI: -73 Transmit Rate: 11 My new MacBook Air has the following readout: PHY Mode: 802.11n Channel: 1 (2.4 Ghz) Security: WPA2 Personal RSSI: -66 Transmit Rate: 79 Both have full bars and the wireless router is in the same room to eliminate any obstructions from the equation. Could the MacMini be connecting at an older protocol, like 802.11b and be reporting erroneously that it is connected at 802.11g? This would explain why I haven't seen a transmit rate above 11. Any further trouble shooting I can try before buying a new USB 802.11n device? The WiFi router is a DLink DIR-615. I can see other devices, and none, even the other g connected devices, are getting below 30-40 MBit/s. What's going on here?

    Read the article

  • Wireless is detected, but not connecting. Ethernet works. How to correct the wireless address?

    - by Lucas
    I am running Ubuntu 14.04 with cable internet, and my wireless is detected and connected, but I cannot connect to the internet. I know the problem is with my machine because other machines are connecting to the same router just fine. I can connect via ethernet just fine as well. Here are some notable tests: ping 192.168.0.105 works with 0% packet loss, but ping 192.168.0.1 has 100% packet loss. When I plug in my ethernet, ping 192.168.0.1 works with 0% packet loss. My wireless name is tg, and the router ip is 192.168.0.1 (where I can enter username and password). I suspect that I need to change my wireless address from 192.168.0.105 to 192.168.0.1. Any suggestions on how to proceed? extra info: [lucas@lucas-ThinkPad-W520]/home/lucas$ iwconfig eth0 no wireless extensions. lo no wireless extensions. wlan0 IEEE 802.11abgn ESSID:"tg" Mode:Managed Frequency:2.462 GHz Access Point: 00:02:6F:83:F8:F4 Bit Rate=1 Mb/s Tx-Power=15 dBm Retry long limit:7 RTS thr:off Fragment thr:off Power Management:off Link Quality=62/70 Signal level=-48 dBm Rx invalid nwid:0 Rx invalid crypt:0 Rx invalid frag:0 Tx excessive retries:52 Invalid misc:166 Missed beacon:0 [lucas@lucas-ThinkPad-W520]/home/lucas$ ifconfig eth0 Link encap:Ethernet HWaddr f0:de:f1:b2:53:53 inet addr:192.168.0.100 Bcast:192.168.0.255 Mask:255.255.255.0 inet6 addr: fe80::f2de:f1ff:feb2:5353/64 Scope:Link UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:980003 errors:0 dropped:0 overruns:0 frame:0 TX packets:498384 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:1320506168 (1.3 GB) TX bytes:59780591 (59.7 MB) Interrupt:20 Memory:f3a00000-f3a20000 lo Link encap:Local Loopback inet addr:127.0.0.1 Mask:255.0.0.0 inet6 addr: ::1/128 Scope:Host UP LOOPBACK RUNNING MTU:65536 Metric:1 RX packets:21927 errors:0 dropped:0 overruns:0 frame:0 TX packets:21927 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:0 RX bytes:1781719 (1.7 MB) TX bytes:1781719 (1.7 MB) wlan0 Link encap:Ethernet HWaddr 24:77:03:29:8f:dc inet addr:192.168.0.105 Bcast:192.168.0.255 Mask:255.255.255.0 inet6 addr: fe80::2677:3ff:fe29:8fdc/64 Scope:Link UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:11828 errors:0 dropped:0 overruns:0 frame:0 TX packets:15444 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:4855662 (4.8 MB) TX bytes:2250585 (2.2 MB) [lucas@lucas-ThinkPad-W520]/home/lucas$ lspci -nn | grep 0280 03:00.0 Network controller [0280]: Intel Corporation Centrino Ultimate-N 6300 [8086:4238] (rev 3e) [lucas@lucas-ThinkPad-W520]/home/lucas$ rfkill list 0: hci0: Bluetooth Soft blocked: no Hard blocked: no 1: tpacpi_bluetooth_sw: Bluetooth Soft blocked: no Hard blocked: no 2: phy0: Wireless LAN Soft blocked: no Hard blocked: no with ethernet unplugged: [lucas@lucas-ThinkPad-W520]/home/lucas$ route -n | grep UG 0.0.0.0 192.168.0.1 0.0.0.0 UG 0 0 0 wlan0 with ethernet plugged in: [lucas@lucas-ThinkPad-W520]/home/lucas$ route -n | grep UG 0.0.0.0 192.168.0.1 0.0.0.0 UG 0 0 0 eth0 [lucas@lucas-ThinkPad-W520]/home/lucas$ nm-tool NetworkManager Tool State: connected (global) - Device: wlan0 [tg] ---------------------------------------------------------- Type: 802.11 WiFi Driver: iwlwifi State: connected Default: no HW Address: 24:77:03:29:8F:DC Capabilities: Speed: 52 Mb/s Wireless Properties WEP Encryption: yes WPA Encryption: yes WPA2 Encryption: yes Wireless Access Points (* = current AP) tatum: Infra, 40:8B:07:D8:A5:04, Freq 2437 MHz, Rate 54 Mb/s, Strength 42 W PA WPA2 ums: Infra, 00:20:A6:72:52:BF, Freq 2437 MHz, Rate 54 Mb/s, Strength 59 Alpha 40: Infra, 28:CF:E9:86:59:5D, Freq 5260 MHz, Rate 54 Mb/s, Strength 30 W PA WPA2 thepromiselan: Infra, 58:6D:8F:51:E5:54, Freq 2452 MHz, Rate 54 Mb/s, Strength 34 $ PA WPA2 xfinitywifi: Infra, 06:1D:D5:84:27:A0, Freq 2437 MHz, Rate 54 Mb/s, Strength 52 *tg: Infra, 00:02:6F:83:F8:F4, Freq 2462 MHz, Rate 54 Mb/s, Strength 73 W PA2 ums: Infra, 00:20:A6:A1:9F:25, Freq 2452 MHz, Rate 54 Mb/s, Strength 44 BRIAN-PC_Network:Infra, 20:AA:4B:DD:93:D6, Freq 2462 MHz, Rate 54 Mb/s, Strength 35 W PA2 HOME-C0F8: Infra, 44:32:C8:D2:C0:F8, Freq 2412 MHz, Rate 54 Mb/s, Strength 40 W PA WPA2 abcsexy: Infra, 28:28:5D:27:5D:85, Freq 2412 MHz, Rate 54 Mb/s, Strength 27 W PA WPA2 IPv4 Settings: Address: 192.168.0.105 Prefix: 24 (255.255.255.0) Gateway: 192.168.0.1 DNS: 192.168.0.1 - Device: eth0 [Wired connection 1] ------------------------------------------- Type: Wired Driver: e1000e State: connected Default: yes HW Address: F0:DE:F1:B2:53:53 Capabilities: Carrier Detect: yes Speed: 100 Mb/s Wired Properties Carrier: on IPv4 Settings: Address: 192.168.0.100 Prefix: 24 (255.255.255.0) Gateway: 192.168.0.1 DNS: 192.168.0.1

    Read the article

  • Visits-PageViews-Bounce Rate-New Visitors-Visit Duration (Google Analytics), which one is top priority for seo?

    - by HOY
    This is the case: My site is getting a lot of trafic from an image (a company logo image) because this image is ranked 1.st in google search results for a company's title. (I have no idea how that happened) This image is must for my website, but it is not relevant with site content so irrelevant people search for the image and finds out about my site, so that I get interesting statistics: http://postimage.org/image/3oyvrjoz9/ Pros: Total Visits & Avg. New Visits Cons: Avg. Page/Visit, Avg. Visit Duration, Bounce Rate In summary I am confused if this image is helpful to my website ? Because I don't know the balance between those 5 statistics P.S: My website is 2 months old, and we are working on seo at the moment Another P.S: Kindly ask you to not provide assumtions, because I also have assumptions, I need real knowledge. Edit: Search Keyword is: arcelik logo Search Site: google.com.tr Search URL: https://www.google.com.tr/search?hl=en&q=arcelik+logo&bav=on.2,or.r_gc.r_pw.r_qf.&bvm=bv.41524429,d.Yms&biw=1366&bih=667&um=1&ie=UTF-8&tbm=isch&source=og&sa=N&tab=wi&ei=oZIDUfutAseVswa9zYHwCw

    Read the article

  • Form iteration function not working properly

    - by Moses
    My function is supposed to iterate all forms in the document, and bind an onclick function to each 'calculate' element int he form. The problem is, the function that executes on any of the click events executes in the context of the the last i in the loop. Here is the JavaScript that I'm using: window.onload = function(){ calculateSavings(); } function calculateSavings(){ for (i = 0; i < document.forms.length; i++) { var e = document.forms[i]; e.calculate.onclick = function() { var hours = e.hours.value; var rate = e.rate.value; alert(hours * rate); } } } And here is the HTML it is attached to: <!doctype html> <html> <body> <form> <label for="hours">Hours: </label><input type="text" id="hours" name="hours"> <label for="rate">Rate: </label><input type="text" id="rate" name="rate"> <input type="button" name="calculate" value="Calculate"> <div id="savings"></div> </form> <form> <label for="hours">Hours: </label><input type="text" id="hours" name="hours"> <label for="rate">Rate: </label><input type="text" id="rate" name="rate"> <input type="button" name="calculate" value="Calculate"> <div id="savings"></div> </form> </body> </html> I'm sure this is a really basic question but the solution is completely eluding me at this point.

    Read the article

< Previous Page | 6 7 8 9 10 11 12 13 14 15 16 17  | Next Page >