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  • StackOverFlowException - but oviously NO recursion/endless loop

    - by user567706
    Hi there, I'm now blocked by this problem the entire day, read thousands of google results, but nothing seems to reflect my problem or even come near to it... i hope any of you has a push into the right direction for me. I wrote a client-server-application (so more like 2 applications) - the client collects data about his system, as well as a screenshot, serializes all this into a XML stream (the picture as a byte[]-array]) and sends this to the server in regular intervals. The server receives the stream (via tcp), deserializes the xml to an information-object and shows the information on a windows form. This process is running stable for about 20-25 minutes at a submission interval of 3 seconds. When observing the memory usage there's nothing significant to see, also kinda stable. But after these 20-25 mins the server throws a StackOverflowException at the point where it deserializes the tcp-stream, especially when setting the Image property from the byte[]-array. I thoroughly searched for recursive or endless loops, and regarding the fact that it occurs after thousands of sucessfull intervals, i could hardly imagine that. public byte[] ImageBase { get { MemoryStream ms = new MemoryStream(); _screen.Save(ms, System.Drawing.Imaging.ImageFormat.Jpeg); return ms.GetBuffer(); } set { if (_screen != null) _screen.Dispose(); //preventing well-known image memory leak MemoryStream ms = new MemoryStream(value); try { _screen = Image.FromStream(ms); //<< EXCEPTION THROWING HERE } catch (StackOverflowException ex) //thx to new CLR management this wont work anymore -.- { Console.WriteLine(ex.Message + Environment.NewLine + ex.StackTrace); } ms.Dispose(); ms = null; } } I hope that more code would be unnecessary, or it could get very complex... Please help, i have no clue at all anymore thx Chris

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  • Changing FileNames using RegEx and Recursion

    - by yeahumok
    Hello I'm trying to rename files that my program lists as having "illegal characters" for a SharePoint file importation. The illegal characters I am referring to are: ~ # % & * {} / \ | : < ? - "" What i'm trying to do is recurse through the drive, gather up a list of filenames and then through Regular Expressions, pick out file names from a List and try to replace the invalid characters in the actual filenames themselves. Anybody have any idea how to do this? So far i have this: (please remember, i'm a complete n00b to this stuff) class Program { static void Main(string[] args) { string[] files = Directory.GetFiles(@"C:\Documents and Settings\bob.smith\Desktop\~Test Folder for [SharePoint] %testing", "*.*", SearchOption.AllDirectories); foreach (string file in files) { Console.Write(file + "\r\n"); } Console.WriteLine("Press any key to continue..."); Console.ReadKey(true); string pattern = " *[\\~#%&*{}/:<>?|\"-]+ *"; string replacement = " "; Regex regEx = new Regex(pattern); string[] fileDrive = Directory.GetFiles(@"C:\Documents and Settings\bob.smith\Desktop\~Test Folder for [SharePoint] %testing", "*.*", SearchOption.AllDirectories); StreamWriter sw = new StreamWriter(@"C:\Documents and Settings\bob.smith\Desktop\~Test Folder for [SharePoint] %testing\File_Renames.txt"); foreach(string fileNames in fileDrive) { string sanitized = regEx.Replace(fileNames, replacement); sw.Write(sanitized + "\r\n"); } sw.Close(); } } So what i need to figure out is how to recursively search for these invalid chars, replace them in the actual filename itself. Anybody have any ideas?

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  • XSLT templates and recursion

    - by user333411
    Hi All, Im new to XSLT and am having some problems trying to format an XML document which has recursive nodes. My XML Code: Hopefully my XML shows: All <item> are nested with <items> An item can have either just attributes, or sub nodes The level to which <item> nodes are nested can be infinently deep <?xml version="1.0" encoding="utf-8" ?> - <items> <item groupID="1" name="Home" url="//" /> - <item groupID="2" name="Guides" url="/Guides/"> - <items> - <item groupID="26" name="Online-Poker-Guide" url="/Guides/Online-Poker-Guide/"> - <items> - <item> <id>107</id> - <title> - <![CDATA[ Poker Betting - Online Poker Betting Structures ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/online-poker-betting-structures ]]> </url> </item> - <item> <id>114</id> - <title> - <![CDATA[ Beginners&#39; Poker - Poker Hand Ranking ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/online-poker-hand-ranking ]]> </url> </item> - <item> <id>115</id> - <title> - <![CDATA[ Poker Terms - 4th Street and 5th Street ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/online-poker-poker-terms ]]> </url> </item> - <item> <id>116</id> - <title> - <![CDATA[ Popular Poker - The Popularity of Texas Hold&#39;em ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/online-poker-popularity-texas-holdem ]]> </url> </item> - <item> <id>364</id> - <title> - <![CDATA[ The Impact of Traditional Poker on Online Poker (and vice versa) ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/online-poker-tradional-vs-online ]]> </url> </item> - <item> <id>365</id> - <title> - <![CDATA[ The Ultimate, Absolute Online Poker Scandal ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/online-poker-scandal ]]> </url> </item> </items> - <items> - <item groupID="27" name="Beginners-Poker" url="/Guides/Online-Poker-Guide/Beginners-Poker/"> - <items> + <item> <id>101</id> - <title> - <![CDATA[ Poker Betting - All-in On the Flop ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/Beginners-Poker/poker-betting-all-in-on-the-flop ]]> </url> </item> + <item> <id>102</id> - <title> - <![CDATA[ Beginners&#39; Poker - Choosing an Online Poker Room ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/Beginners-Poker/beginners-poker-choosing-a-room ]]> </url> </item> + <item> <id>105</id> - <title> - <![CDATA[ Beginners&#39; Poker - Choosing What Type of Poker to Play ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/Beginners-Poker/beginners-poker-choosing-type-to-play ]]> </url> </item> + <item> <id>106</id> - <title> - <![CDATA[ Online Poker - Different Types of Online Poker ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/Beginners-Poker/online-poker ]]> </url> </item> + <item> <id>109</id> - <title> - <![CDATA[ Online Poker - Opening an Account at an Online Poker Site ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/Beginners-Poker/online-poker-opening-an-account ]]> </url> </item> + <item> <id>111</id> - <title> - <![CDATA[ Beginners&#39; Poker - Poker Glossary ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/Beginners-Poker/beginners-poker-glossary ]]> </url> </item> + <item> <id>117</id> - <title> - <![CDATA[ Poker Betting - What is a Blind? ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/Beginners-Poker/poker-betting-what-is-a-blind ]]> </url> </item> - <item> <id>118</id> - <title> - <![CDATA[ Poker Betting - What is an Ante? ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/Beginners-Poker/poker-betting-what-is-an-ante ]]> </url> </item> + <item> <id>119</id> - <title> - <![CDATA[ Beginners Poker - What is Bluffing? ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/Beginners-Poker/online-poker-what-is-bluffing ]]> </url> </item> - <item> <id>120</id> - <title> - <![CDATA[ Poker Games - What is Community Card Poker? ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/Beginners-Poker/online-poker-what-is-community-card-poker ]]> </url> </item> - <item> <id>121</id> - <title> - <![CDATA[ Online Poker - What is Online Poker? ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/Beginners-Poker/online-poker-what-is-online-poker ]]> </url> </item> </items> </item> </items> </item> </items> </item> </items> The XSL code: <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="html" indent="yes"/> <xsl:template name="loop"> <xsl:for-each select="items/item"> <ul> <li><xsl:value-of select="@name" /></li> <xsl:if test="@name and child::node()"> <ul> <xsl:for-each select="items/item"> <li><xsl:value-of select="@name" />test</li> </xsl:for-each> </ul> <xsl:call-template name="loop" /> </xsl:if> <xsl:if test="child::node() and not(@name)"> <xsl:for-each select="/items"> <li><xsl:value-of select="id" /></li> </xsl:for-each> </xsl:if> </ul> </xsl:for-each> <xsl:for-each select="item/items/item"> <li>hi</li> </xsl:for-each> </xsl:template> <xsl:template match="/" name="test"> <xsl:call-template name="loop" /> </xsl:template> </xsl:stylesheet> Im trying to write the XSL so that every <items> node will render a <ul> and every <items> node will render an <li>. The XSL needs to be recursive because i cant tell how deep the nested nodes will go. Can anyone help? Regards, Al

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  • Javascript tail recursion

    - by Misha Moroshko
    Why the following code runs so.... slow....... ? <html><body><script type="text/javascript"> var i = 0; f(); function f() { if (i == 5000) { document.write("Done"); } else { i++; tail(); } } function tail() { var fn = tail.caller; var args = arguments; setTimeout(function() {fn.apply(this, args)}, 0); }; </script></body></html>

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  • XSLT-Looping and recursion based on parameter passed

    - by contactkx
    I have an XML organized like below- <section name="Parent 1 Text here" ID="1" > <section name="Child 1 Text here" ID="11"> </section> <section name="Child 2 Text here" ID="12"> <section name="GrandChild Text here" ID="121" > </section> </section> </section> <section name="Parent 2 Text here" ID="2" > <section name="Child 1 Text here" ID="22"> </section> <section name="Child 2 Text here" ID="23"> <section name="GrandChild Text here" ID="232" > </section> </section> </section> I have to produce the below output XML - <section name="Parent 1 Text here" ID="1" > <section name="Child 2 Text here" ID="12"> <section name="GrandChild Text here" ID="121" > </section> </section> </section> <section name="Parent 2 Text here" ID="2" > <section name="Child 2 Text here" ID="23"> </section> </section> I have to achive above using XSLT 1.0 transformation. I was planning to pass a comma separated string as a parameter with value= "1,12,121,2,23" My question- How to loop the comma separated parameter in XSLT 1.0 ? Is there a simpler way to achieve the above. Please remember I have to do this in XSLT 1.0 Your help is appreciated.

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  • Looping and recursion based on parameter passed

    - by contactkx
    I have an XML organized like below- <section name="Parent 1 Text here" ID="1" > <section name="Child 1 Text here" ID="11"> </section> <section name="Child 2 Text here" ID="12"> <section name="GrandChild Text here" ID="121" > </section> </section> </section> <section name="Parent 2 Text here" ID="2" > <section name="Child 1 Text here" ID="22"> </section> <section name="Child 2 Text here" ID="23"> <section name="GrandChild Text here" ID="232" > </section> </section> </section> I have to produce the below output XML - <section name="Parent 1 Text here" ID="1" > <section name="Child 2 Text here" ID="12"> <section name="GrandChild Text here" ID="121" > </section> </section> </section> <section name="Parent 2 Text here" ID="2" > <section name="Child 2 Text here" ID="23"> </section> </section> I have to achive above using XSLT 1.0 transformation. I was planning to pass a comma separated string as a parameter with value= "1,12,121,2,23" My question- How to loop the comma separated parameter in XSLT 1.0 ? Is there a simpler way to achieve the above. Please remember I have to do this in XSLT 1.0 Your help is appreciated.

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  • Binary Tree operator overloading and recursion

    - by furious.snail
    I was wondering how to overload the == operator for a binary tree to compare if two trees have identical data at same nodes. So far this is what I have: bool TreeType::operator==(const TreeType& otherTree) const { if((root == NULL) && (otherTree.root == NULL)) return true; //two null trees are equal else if((root != NULL) && (otherTree.root != NULL)) { return((root-info == otherTree.root-info) && //this part doesn't actually do anything recursively... //(root-left == otherTree.root-left) && //(root-right == otherTree.root-right)) } else return false; //one tree is null the other is not } I have a similar function that takes two TreeNode pointers as parameters but I've been stuck on how to convert it to this function.

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  • Checking to see if a number is evenly divisible by other numbers with recursion in Python

    - by Ernesto
    At the risk of receiving negative votes, I will preface this by saying this is a midterm problem for a programming class. However, I have already submitted the code and passed the question. I changed the name of the function(s) so that someone can't immediately do a search and find the correct code, as that is not my purpose. I am actually trying to figure out what is actually MORE CORRECT from two pieces that I wrote. The problem tells us that a certain fast food place sells bite-sized pieces of chicken in packs of 6, 9, and 20. It wants us to create a function that will tell if a given number of bite-sized piece of chicken can be obtained by buying different packs. For example, 15 can be bought, because 6 + 9 is 15, but 16 cannot be bought, because no combination of the packs will equal 15. The code I submitted and was "correct" on, was: def isDivisible(n): """ n is an int Returns True if some integer combination of 6, 9 and 20 equals n Otherwise returns False. """ a, b, c = 20, 9, 6 if n == 0: return True elif n < 0: return False elif isDivisible(n - a) or isDivisible(n - b) or isDivisible(n - c): return True else: return False However, I got to thinking, if the initial number is 0, it will return True. Would an initial number of 0 be considered "buying that amount using 6, 9, and/or 20"? I cannot view the test cases the grader used, so I don't know if the grader checked 0 as a test case and decided that True was an acceptable answer or not. I also can't just enter the new code, because it is a midterm. I decided to create a second piece of code that would handle an initial case of 0, and assuming 0 is actually False: def isDivisible(n): """ n is an int Returns True if some integer combination of 6, 9 and 20 equals n Otherwise returns False. """ a, b, c = 20, 9, 6 if n == 0: return False else: def helperDivisible(n): if n == 0: return True elif n < 0: return False elif helperDivisible(n - a) or helperDivisible(n - b) or helperDivisible(n - c): return True else: return False return helperDivisible(n) As you can see, my second function had to use a "helper" function in order to work. My overall question, though, is which function do you think would provide the correct answer, if the grader had tested for 0 as an initial input?

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  • Recursive Batch File

    - by MCZ
    I have a file that looks this: head1,head2,head3,head4,head5,head6 a11,a12,keyA,a14,a15,a16 a21,a22,keyB,a24,a25 a31,a32,keyC,a34 a41,a42,keyB,a44,a44 a51,a52,keyA,a54,a55,a56 a61,a62,keyA,a64,a65,a66 a71,a72,keyC,a74 some message Objective: Write list of unique keys to a text file. For example, the result for the file described above should be: keyA, keyB, keyC Here's the pseudocode I would like to implement in batch file recur.bat Read second line of inputfile If no key exist on second line, return else continue Append keyX to list FINDSTR /v keyX inputfile Pipe results to recur.bat I don't know if this is the most efficient way to do this without using actual programming language. Any suggestions for actual batch file code?

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  • Where can we use "This" in Recursion methode...

    - by T_Geek
    Hi . I have a methode in a static class which try to convert bi*nar*y tre to list I'd like to make a recusion but I couldn't I've implemented some opertation in my class like add,delet,find.it's too easy to implement its . Here is the code class ARB { private: struct BT { int data; BT *l; BT *r; }; struct BT *p; public ARB(); ~ARB(); void del(int n); void add(int n); }; void ARB::del(int num) { //The code ,don't care about it }; main() { // BTR T; T.add(3); T.add(5); }; Here is what should we do to transfert the code from Benary tree tolist LLC ARB::changeit() { LLC x; while(this!=NULL) { x.add(this->data); // if(this.l==NULL) { x.print(); //To print the elemnts of List return(x); } else { x=changeit(this.l); } if(this.r!=NULL) { x.~LLC(); x=changeit(this.r); return(x); } } }

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  • Linked list Recursion ...

    - by epsilon_G
    hey , I'd like to make a recursive function using C++ I make this class class linklist { private: struct node { int data; node *link; }*p; void linklist::print_num(node* p) { if (p != NULL) { cout << p->data << " "; print_num (p->link); } } in the main program what should I write ...

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  • error in running recursion

    - by GOsha
    if running function returns server misconfiguration error function build_path($cid) { $result = array(); $DB = new MySQLTable; $DB->TblName = 'shop_categories'; $where['cat_id']['='] = $DB->CleanQuest($cid); $res = $DB->Select('cat_id,cat_name,cat_parent', $where); if($res !== 'false') { $pid = mysql_fetch_array($res); if($pid['cat_parent'] !== 0) { Echo $pid['cat_parent']; build_path($pid['cat_parent']); } else { Echo $pid['cat_id']; return true; } } return false; } I can't find an error here. Please help. Sorry for disturbing you all. The trouble was in comparison 'if($pid['cat_parent'] !== 0)': $pid['cat_parent'] was a string with int(0) Can i build this function to store full path without using GLOBALS and SESSION vars?

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  • How to recursively change folder permissions on WAMP server [closed]

    - by user1543227
    How do I change folder permissions recursively in Windows 7? Specifically, for my WAMP server, I want to change the permissions of my "www" folder so that its contents can be viewed over the Internet, and I want all of its subfolders to have the same permissions. Currently, for each folder, I'm getting the following message in my browser: "You don't have permission to access / on this server." I believe there's a simple command I could enter in a terminal for recursively changing folder permissions for global access; I just don't know what it is.

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  • Recursion problem overloading an operator

    - by Tronfi
    I have this: typedef string domanin_name; And then, I try to overload the operator< in this way: bool operator<(const domain_name & left, const domain_name & right){ int pos_label_left = left.find_last_of('.'); int pos_label_right = right.find_last_of('.'); string label_left = left.substr(pos_label_left); string label_right = right.substr(pos_label_right); int last_pos_label_left=0, last_pos_label_right=0; while(pos_label_left!=string::npos && pos_label_right!=string::npos){ if(label_left<label_right) return true; else if(label_left>label_right) return false; else{ last_pos_label_left = pos_label_left; last_pos_label_right = pos_label_right; pos_label_left = left.find_last_of('.', last_pos_label_left); pos_label_right = right.find_last_of('.', last_pos_label_left); label_left = left.substr(pos_label_left, last_pos_label_left); label_right = right.substr(pos_label_right, last_pos_label_right); } } } I know it's a strange way to overload the operator <, but I have to do it this way. It should do what I want. That's not the point. The problem is that it enter in an infinite loop right in this line: if(label_left<label_right) return true; It seems like it's trying to use this overloading function itself to do the comparision, but label_left is a string, not a domain name! Any suggestion?

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  • Suggestion for chkstk.asm stackoverfolw exception in C++ with Visual Studio 2010

    - by Gulshan
    I am working with an implementation of merge sort. I am doing C++ Visual Studio 2010. But when I took a array of 300000 integers for timing, it is showing an unhandled stackoverflow exception and taking me to a readonly file named "chkstk.asm". I reduced the size to 200000 and it worked. Again the same code worked with C-free 4 editor (mingw 2.95) without any problem while the size was 400000. Do you have any suggestion to get the code working in Visual Studio? May be the recursion in the mergesort is causing the problem.

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  • Drawing the call stack in a recursive method

    - by Shaza
    Hey, I want to draw the call stack for any recursive method, so I've created a schema like this, recursiveMethod(){ //Break recursion condition if(){ // Add value here to the return values' list- No drawing return } else{ //Draw stack with the value which will be pushed to the stack here variable <- recursiveMethod() //Clear the drawing which represents the poped value from the stack here return variable }} Notes: This schema can draw recursive methods with n recursive call by making the recursive calls in a separate return statements. returnValues list, is a list which save all the return values, just for viewing issues. What do you think of this? any suggestions are extremely welcomed.

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  • Result in an argument isn't correct

    - by Paulo Nunes
    So I have this piece of prolog code: my_avalia(A,R) :- A=="Koza" -koza(R,0,0,e,89). koza(R,_,_,_,87):-!,write(R). koza(R,X,Y,V,C):-movex(V,X,X1),movey(V,Y,Y1),confirma(X1,Y1,Z),Z==1->(append(R,[emFrente],U),L is (C-1),koza(U,X1,Y1,V,L)). The matter is that when I write the "R" at koza(), it has the correct values, however it ends up with a empty list in my_avalia when I call it like this: my_avalia("Koza",R). My recursion might be incorrect but I don't really know what's wrong with it. Thanks in advance.

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  • Suggestion for chkstk.asm stackoverflow exception in C++ with Visual Studio 2010

    - by Gulshan
    I am working with an implementation of merge sort. I am doing C++ Visual Studio 2010. But when I took a array of 300000 integers for timing, it is showing an unhandled stackoverflow exception and taking me to a readonly file named "chkstk.asm". I reduced the size to 200000 and it worked. Again the same code worked with C-free 4 editor (mingw 2.95) without any problem while the size was 400000. Do you have any suggestion to get the code working in Visual Studio? May be the recursion in the mergesort is causing the problem.

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  • Sending data recursively using jquery $.ajax gives stack overflow error..

    - by Rosdi
    Why am I getting "too much recursion" error when I do the following? function sendTheNames() { alert("start submitting names.."); return function (array) { var name = $(array.shift()).text(); $.ajax({ url: "test.jsp?name=" + name, complete: function () { if (array.length > 0) { return arguments.callee(array); } } }); }; } $(document).ready(function () { var selectedNames = []; $('ul li input:checked').each(function () { selectedNames.push($(this).parent()); }); alert("begin"); sendTheNames()(selectedNames); alert("done"); });

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  • Making change recursively: How do I modify my algorithm to print all combinations?

    - by cb
    I have an algorithm that recursively makes change in the following manner: public static int makeChange(int amount, int currentCoin) { //if amount = zero, we are at the bottom of a successful recursion if (amount == 0){ //return 1 to add this successful solution return 1; //check to see if we went too far }else if(amount < 0){ //don't count this try if we went too far return 0; //if we have exhausted our list of coin values }else if(currentCoin < 0){ return 0; }else{ int firstWay = makeChange(amount, currentCoin-1); int secondWay = makeChange(amount - availableCoins[currentCoin], currentCoin); return firstWay + secondWay; } } However, I'd like to add the capability to store or print each combination as they successfully return. I'm having a bit of a hard time wrapping my head around how to do this. The original algorithm was pretty easy, but now I am frustrated. Any suggestions? CB

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  • Fibonacci sequence subroutine returning one digit too high...PERL

    - by beProactive
    #!/usr/bin/perl -w use strict; sub fib { my($num) = @_; #give $num to input array return(1) if ($num<=1); #termination condition return($num = &fib($num-1) + &fib($num-2)); #should return sum of first "n" terms in the fibonacci sequence } print &fib(7)."\n"; #should output 20 This subroutine should be outputting a summation of the first "x" amount of terms, as specified by the argument to the sub. However, it's one too high. Does this have something to do with the recursion? Thanks.

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