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Search found 501 results on 21 pages for 'sin'.

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  • Is nesting types considered bad practice?

    - by Rob Z
    As noted by the title, is nesting types (e.g. enumerated types or structures in a class) considered bad practice or not? When you run Code Analysis in Visual Studio it returns the following message which implies it is: Warning 34 CA1034 : Microsoft.Design : Do not nest type 'ClassName.StructueName'. Alternatively, change its accessibility so that it is not externally visible. However, when I follow the recommendation of the Code Analysis I find that there tend to be a lot of structures and enumerated types floating around in the application that might only apply to a single class or would only be used with that class. As such, would it be appropriate to nest the type sin that case, or is there a better way of doing it?

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  • Passing an objects rotation down through its children

    - by MintyAnt
    In my topdown 2d game you have a player with a sword, like an old Zelda game. The sword is a seperate entity, and its collision box "rotates" around the player like an orbit, but always follows the player wherever he goes. The player and sword both have a vector2 heading. The sword is a weapon object that is attached to the character. In order to allow swinging in a direction, I have the following property inside sword (RotateCopy returns a copy of the mHeading after rotation) public Vector2 Heading { get { return mHeading.RotateCopy(mOwner.Rotation); } } This seems a bit messy to me, and slower than it could be. Is there a better way to "translate" the base/owner component rotations through to whatever component I am using, like this sword? Would using a rotation MATRIX be better? (Curretnly rotates by sin/cos) If so, how can I "add" up the matrices? Thank you.

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  • How can I improve my Animation

    - by sharethis
    The first approaches in animation for my game relied mostly on sine and cosine functions with the time as parameter. Here is an example of a very basic jump I implemented. if(jumping) { height = sin(time); if(height < 0) jumping = false; // player landed player.position.z = height; } if(keydown(SPACE) && !jumping) { jumping = true; time = now(); // store the starting time } So my player jumped in a perfect sine function. That seems quite natural, because he slows down when he reached the top position, and in the fall he speeds up again. But patching every animation out of sine and cosine is stretched to its limits soon. So can I improve my animation and provide a more abstract layer?

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  • 3d trajectory - calculate initial velocity

    - by Skoder
    Hey, I've got a 2D projectile code sample working, but would like to extend it to 3D. How would I calculate the initial velocity of the Z-axis? At the moment, I've got: initVel.X = (float)Math.Cos(45.0); initVel.Y = (float)Math.Sin(45.0); How would I convert this to work in 3D (and add the initial velocity for the Z-axis)? In my example, X is across, Y is up down and Z is going into the screen. I also normalize the vector and multiply it by the speed. Thanks

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  • Rotation matrix for a 3D vector

    - by Shashwat
    I have a direction vector on which I have to apply some rotation to align it to positive z-axis. To use Matrix.CreateRotationX(angle) of XNA, I need the angle for which I'd have to compute cos or tan inverse. I think this is a complex task to do. Also, eventually those are also converted to sin(angle) and cos(angle) in the matrix. Is there any inbuilt way to create rotation matrix from a 3D vector? However, I can write the function but still asking if there is one already there.

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  • Developing GLSL Shaders?

    - by skln
    I want to create shaders but I need a tool to create and see the visual result before I put them into my game. As to determine if there is something wrong with my game or if it's something with the shader I created. I've looked at some like Render Monkey and OpenGL Shader Designer from what I recall of Render Monkey it had a way to define your own attributes (now as "in" for vertex shaders = 330) easily though I can't remember to what extent. Shader Designer requires a plugin that I didn't even bother to look at creating cause it's an external process and plugin. Are there any tools out there that support a scripting language and I could easily provide specific input such as float movement = sin(elapsedTime()); and then define in float movement; in the vertex shader ? It'd be cool if anyone could share how they develop shaders, if they just code away and then plug it into their game hoping to get the result they wanted.

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  • Specifying force and angle in ApplyImpulse in box2d

    - by Deepak Mahalingam
    I need to apply an impulse on a object with a particular force and at a particular angle in Box2d. If I am right the syntax would be the following: body.GetBody().ApplyImpulse(new b2Vec2(direction, power),body.GetBody().GetWorldCenter()); The problem is my direction is in angles. I found a discussion where it was said that the way we can convert an angle into a vector would be as: new b2Vec2(Math.cos(angle*Math.PI/180),Math.sin(angle*Math.PI/180)); Now I am not sure how to combine these two. In other words, if I wish to apply a force of 30 units at an angle of 30 degrees at the center of the object, how should I do it?

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  • Find the new coordinates using a starting point, a distance, and an angle

    - by dqhendricks
    Okay, say I have a point coordinate. var coordinate = { x: 10, y: 20 }; Now I also have a distance and an angle. var distance = 20; var angle = 72; The problem I am trying to solve is, if I want to travel 20 points in the direction of angle from the starting coordinate, how can I find what my new coordinates will be? I know the answer involves things like sin/cosin, because I used to know how to do this, but I have since forgotten the formula. Can anyone help?

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  • Calculate random points (pixel) within a circle (image)

    - by DMills
    I have an image that contains a circles at a specific location, and of a specific diameter. What I need to do is to be able to calculate random points within the circle, and then manipulate said the pixels they correlate to. I have the following code already: private Point CalculatePoint() { var angle = _random.NextDouble() * ( Math.PI * 2 ); var x = _originX + ( _radius * Math.Cos( angle ) ); var y = _originY + ( _radius * Math.Sin( angle ) ); return new Point( ( int )x, ( int )y ); } And that works fine for finding all the points at the circumference of the circle, but I need all points from anywhere in the circle. If this doesn't make sense let me know and I will do my best to clarify.

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  • Orienting ship movement in asteroids [closed]

    - by BadSniper
    Possible Duplicate: Move sprite in the direction it is facing? I'm programming asteroids game. I'm trying to give velocity in the direction of ship face. I've tried using velocity.x = velocity.x * cos r, velocity.y = velocity.y * sin r where velocity is a vector and r is the angle rotated. but it's not moving in right direction. Could someone help with this problem? It is supposed to return the vector in which ship is facing. I don't understand the problem.

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  • Using Optical Flow in EmguCV

    - by Meko
    HI. I am trying to create simple touch game using EmguCV.Should I use optical flow to determine for interaction between images on screen and with my hand ,if changes of points somewhere on screen more than 100 where the image, it means my hand is over image? But how can I track this new points? I can draw on screen here the previous points and new points but It shows on my head more points then my hand and I can not track my hands movements. void Optical_Flow_Worker(object sender, EventArgs e) { { Input_Capture.SetCaptureProperty(Emgu.CV.CvEnum.CAP_PROP.CV_CAP_PROP_POS_FRAMES, ActualFrameNumber); ActualFrame = Input_Capture.QueryFrame(); ActualGrayFrame = ActualFrame.Convert<Gray, Byte>(); NextFrame = Input_Capture.QueryFrame(); NextGrayFrame = NextFrame.Convert<Gray, Byte>(); ActualFeature = ActualGrayFrame.GoodFeaturesToTrack(500, 0.01d, 0.01, 5); ActualGrayFrame.FindCornerSubPix(ActualFeature, new System.Drawing.Size(10, 10), new System.Drawing.Size(-1, -1), new MCvTermCriteria(20, 0.3d)); OpticalFlow.PyrLK(ActualGrayFrame, NextGrayFrame, ActualFeature[0], new System.Drawing.Size(10, 10), 3, new MCvTermCriteria(20, 0.03d), out NextFeature, out Status, out TrackError); OpticalFlowFrame = new Image<Bgr, Byte>(ActualFrame.Width, ActualFrame.Height); OpticalFlowFrame = NextFrame.Copy(); for (int i = 0; i < ActualFeature[0].Length; i++) DrawFlowVectors(i); ActualFrameNumber++; pictureBox1.Image = ActualFrame.Resize(320, 400).ToBitmap() ; pictureBox3.Image = OpticalFlowFrame.Resize(320, 400).ToBitmap(); } } private void DrawFlowVectors(int i) { System.Drawing.Point p = new Point(); System.Drawing.Point q = new Point(); p.X = (int)ActualFeature[0][i].X; p.Y = (int)ActualFeature[0][i].Y; q.X = (int)NextFeature[i].X; q.Y = (int)NextFeature[i].Y; p.X = (int)(q.X + 6 * Math.Cos(angle + Math.PI / 4)); p.Y = (int)(q.Y + 6 * Math.Sin(angle + Math.PI / 4)); p.X = (int)(q.X + 6 * Math.Cos(angle - Math.PI / 4)); p.Y = (int)(q.Y + 6 * Math.Sin(angle - Math.PI / 4)); OpticalFlowFrame.Draw(new Rectangle(q.X,q.Y,1,1), new Bgr(Color.Red), 1); OpticalFlowFrame.Draw(new Rectangle(p.X, p.Y, 1, 1), new Bgr(Color.Blue), 1); }

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  • Simulate Pivot Rotate Using Transform In SVG

    - by Dested
    I have a rectangle in SVG that I need to rotate on a pivot from a specific point. The best way I can see to do this is transform to the xy of the pivot, rotate the degree, and then transform again. The problem is the xy of the second transform. I assume its going to take cos and sin to some extent, just not sure where or why. * | | | would rotate -90degrees to *--- Maybe im looking at this the wrong way, can anyone clearify?

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  • Dijkstra’s algorithm and functions

    - by baris_a
    Hi guys, the question is: suppose I have an input function like sin(2-cos(3*A/B)^2.5)+0.756*(C*D+3-B) specified with a BNF, I will parse input using recursive descent algorithm, and then how can I use or change Dijkstra’s algorithm to handle this given function? After parsing this input function, I need to execute it with variable inputs, where Dijkstra’s algorithm should do the work. Thanks in advance. EDIT: May be I should ask also: What is the best practice or data structure to represent given function?

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  • tinymce - url templates, image add etc not loading

    - by Ali
    Hi guys I'm trying to integrate the tinymce plugin however I'm running into problems such that almost every feature which requires a plugin to be rendered i.e the add url popup or add image pop up - it opens an empty pop up window. Even if I try to open it inline I get the same blank popup window.. what should I be looking at here.. I can't notice any error sin firebug..

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  • Plot ECG in Winforms

    - by Moon .
    i have no previous experience in plotting in winforms, in one form i want to plot ecg. or lets say a sin wave or any wave function in a specific area, but what i am doing is e.c.g.. rest of the form will be normal form with buttons and labels, can anybody be nice enough to through in a tutorial :)

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  • Fixing VBSCRIPT inaccurate mathematical results due to rounding

    - by jay
    Try running this in a .VBS file MsgBox(545.14-544.94) You get a neat little answer of 0.199999999999932! This rounding issue also occurs unfortunately in Sin(2 * pi) since VB can only ever see the (user defined) variable pi as accurate as 3.14159265358979. Is rounding it manually (and loosing accuracy) the only way to improve the result? What is the most effective way of dealing with this kind of problem?

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  • half-sine pulse shaping

    - by kos
    hi, i wanted to know what is the pulse shape of the modem.oqpskmod? and if it is not half-sine pulse shape, how is it possible to make it half-sine pulse shape as it is stated in ieee 802.15.4(zigbee) standard where it shows it as follows p(t)=sin(pi*t/2*Tc) if 0<=t<=2Tc p(t)=0 if otherwise ? thanks a lot!

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  • Equation parsing in Python

    - by MikeCroucher
    How can I (easily) take a string such as 'sin(x)*x^2' which might be entered by a user at runtime and produce a python function that could be evaluated for any value of x? Does anyone know of any libraries or modules that takes care of this sort of thing?

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  • How to find relation between change in latitudes at centre of map and top/bottom

    - by Imran
    Hi, Im having little trouble finding a relation between the movement at centre and edge of a circle, Im doing for panning world map,my map extent is 180,89:-180,-89, my map pans by adding change(dx,dY) to its extents and not its centre. Now a situation has arrrised where I have to move the map to a specific centre, to calculate the change in longitudes is very easy and simple, but its the change in lattitudes that has caused problem. It seems the change in centreY of map is more than the change at edge of the mapY, or simply if I have to move the map centre from 0long,0lat to 73long,33lat, for dX I simply get 73, but for dY apparently it looks 33 but if i add 33 to top of map that is 89 , it will be 122 which is incorrect since Latitudes are between 90 and -90 . It seems a case a projection of a circle on 2D plane where the edge of circle since is moving backward due to angle expereinces less change and the centre expereinces more change, now is there a relation between these two factors? I tried converting the difference between OriginY and destinationY into radians and then add to Top and Bottom of Map, but it did'nt really work for me. Please note that the map is project on a virtual canvas whose width starts from 256 and increases by 256*2^z , z=0 is default and whole world is visible at that extent of canvas code: public void moveMapTo(double destinationLongitude,double destinationLattitude) // moves map to the new centre { double dXLong=destinationLongitude-centreLongitude; double atanhsinO = atanh(Math.sin(destinationLattitude * Math.PI / 180.00)); double atanhsinD = atanh(Math.sin(centreLatitude * Math.PI / 180.00)); double atanhCentre = (atanhsinD + atanhsinO) / 2; double latitudeSpan =destinationLattitude - centreLatitude; double radianOfCentreLatitude = Math.atan(Math.sinh(atanhCentre)); double dXLat=latitudeSpan / Math.cos(radianOfCentreLatitude); dXLat*=getLattitudeSpan()*(Math.PI/180); <--- HERE IS THE PORBLEM System.out.println("dxLong:"+dXLong+"_dxLat:"+dXLat); mapLeft+=dXLong; mapRight+=dXLong; mapTop+=dXLat; mapBottom+=dXLat; } ////latitude span function private double getLattitudeSpan() { double latitudeSpan = mapTop - mapBottom; latitudeSpan = latitudeSpan / Math.cos(radianOfCentreLatitude); return Math.abs(latitudeSpan); } //ht

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  • How to get visible size of DisplayObject with perspective projection

    - by Ain
    The following is entirely a math question. As we know, PerspectiveProjection delivers perspective transformations in 3D represented by the interdependent values of fieldOfView and focalLength according to the following formula: focalLength = stageWidth/2 * (cos(fieldOfView/2) / sin(fieldOfView/2) Bjørn Gunnar Staal has prepared a good image to illustrate the situation. Q: How to get the visible on-screen size of the DisplayObject (Cube on the above-linked image) to which PerspectiveProjection has been applied?

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  • Polar and Cartesian calculations not completely working?

    - by Smoka
    double testx, testy, testdeg, testrad, endx, endy; testx = 1; testy = 1; testdeg = atan2( testx, testy) / Math::PI* 180; testrad = sqrt(pow(testx,2) + pow(testy,2)); endx = testrad * cos(testdeg); endy = testrad * sin(testdeg); All parts of this seem to equate properly, except endx and endy should = testx and testy they do when calculating by hand.

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  • Gaps In Plot Of Piecewise Function in Matlab

    - by eng_sub
    Hello, I want to plot a piecewise function, but I don't want any gaps to appear at the junctures, for example: t=[1:8784]; b=(26.045792 + 13.075558*sin(0.0008531214*t - 2.7773943)).*((heaviside(t-2184))-(heaviside(t-7440))); plot(b,'r','LineWidth', 1.5);grid on there should not be any gaps appearing in the plot between the three intervals , but they do. I want the graph to be continueous without gaps. Any suggestions on how to achieve that. Thanks in advance.

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