Search Results

Search found 1471 results on 59 pages for 'surface rt'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 10/59 | < Previous Page | 6 7 8 9 10 11 12 13 14 15 16 17  | Next Page >

  • Yes WinRT Devices Have a Desktop&hellip;But Not For Us

    - by D'Arcy Lussier
    So tonight this convo happened: Intrigued, I viewed the video Lee mentions and found that its the now infamous Brent Ozar video which shows a bug in Word on the Surface RT (you can read this article which talks about the tempest in a teacup that ensued). But Lee is correct – in the video, when Brent starts up Word 2013, we see this: That sure does look like a desktop doesn’t it! But…aren’t Windows RT devices *not* supposed to come with a desktop? Actually, it does. However, it’s not a *full* desktop. From Seth Rosenblatt’s fantastic Windows RT FAQ article: Windows RT will have a Desktop mode, but it will be restricted to pre-installed, Microsoft-produced software. This will include touch-optimized versions of Microsoft Word, Excel, PowerPoint, and OneNote as the new Microsoft Office So yes, there’s a desktop mode in Windows RT but no, you won’t be able to install apps to it. Confused yet? Read the rest of the Seth’s FAQ – it does a great job clearing the haze of confusion that Microsoft Marketing Merlins have cast upon all of us. D

    Read the article

  • Commandline Purge in AS11

    - by Dheeraj Kumar
    AS11 - B2B offering consists of numerous features that have been made available via commandline approach. Most of these are supplement to the already available User Interface based approach. One such is purging of runtime data. The commandline purge option enables the users to purge the runtime data, based on various criteria. This is an ANT based command, provides the flexibility to selectively set the criteria to purge the runtime data. Providing the command line option also enables the administrator to purge in bulk, without visiting the B2B UI, which can also be used for automation purpose By default archival is turned on for purge activity. As a pre-requisite, the respective folder needs to be configured in database with the proper permission. When no filename is provided for archived data, the sysdate will be considered for filename. Below are the various options to purge the runtime data Normal 0 Option ANT option   Message state -Dmsgstate   Date range -Dfromdate,  -Dtodate Format : dd/mm/yyyy hh:mm AM/PM Trading partner -Dtp   Direction -Ddirection   Message Type -Dmsgtype   Agreement Name -Dagreement   IdType/ value -Didtype,  -Didvalue   Archive -Darchive True/false By default true Archive file name -Darchivename File name (optional), will be used when archive is set to true. Normal 0 Note: When using -Darchivename the value must be a unique file name. An existing file name used with -Darchivename throws an exception v\:* {behavior:url(#default#VML);} o\:* {behavior:url(#default#VML);} w\:* {behavior:url(#default#VML);} .shape {behavior:url(#default#VML);} Normal 0 Below are the few of ant commands and various options.   Purge based on date range and message state: Normal 0 ant -f ant-b2b-util.xml b2bpurge -Dmode=RT -Dfromdate="19/12/2009 1:04 AM" -Dtodate="19/12/2009 1:05 AM" -Dmsgstate=MSG_COMPLETE -Darchivename="filename.dmp"  Purge based on direction: Normal 0 ant -f ant-b2b-util.xml b2bpurge -Dmode=RT -Ddirection="OUTBOUND" Normal 0 Purge based on agreement Name: Normal 0 ant -f ant-b2b-util.xml b2bpurge -Dmode=RT -Dagreement="agreement_name" Normal 0 Purge based on Trading partner Name: Normal 0 ant -f ant-b2b-util.xml b2bpurge -Dmode=RT -Dtp=GlobalChips Normal 0 Purge based on Message State: Normal 0 ant -f ant-b2b-util.xml b2bpurge -Dmode=RT -Dmsgstate="MSG_COMPLETE" Normal 0 ant -f ant-b2b-util.xml b2bpurge -Dmode=RT -Ddirection="OUTBOUND" -Dmsgstate="MSG_COMPLETE"

    Read the article

  • Vaadin Calendar events not shown if overnight [migrated]

    - by B_B
    In my vaadin project there is the possibility to create events that are shown by the calendar. It does works, except when the event is overnight, let's say the night from 23th to 24th, and the calendar shows as only day the 24th. In this case the part of the event that belongs to the 24th is supposed to be shown, but it is not. When I switch to weekly view, the event is shown properly. Here is the function where I get the data and use a container for the calendar: /* Fill Calendar from database */ void updateData() { final BeanItemContainer<TypeReservationEvent> container = new BeanItemContainer<TypeReservationEvent>(TypeReservationEvent.class); Map<String, Object> parameters = new HashMap<String, Object>(); parameters.put("roomParent",chosenRoom); String query = "SELECT DISTINCT res FROM EntityReservation res, EntityRoom r, EntityTable rt WHERE res.tableId = rt.id " + "AND rt.roomParent =:roomParent"; reservationList = facade.list(query, parameters); for(EntityReservation rt : reservationList) { container.addBean(new TypeReservationEvent(rt)); } container.sort(new Object[]{"start"}, new boolean[]{true}); cal.setContainerDataSource(container, "caption", "description", "start", "end", "styleName"); // Force calendar to refresh if(selectCalViewType.getValue() == chooseWeeklyView) { setViewType(calViewType.DAILY); setViewType(calViewType.WEEKLY); } else if (selectCalViewType.getValue() == chooseDailyView) { setViewType(calViewType.WEEKLY); setViewType(calViewType.DAILY); } } TIA

    Read the article

  • ?19????

    - by user13132741
    pre.ctl { font-family: "Cumberland",monospace; }td p { margin-bottom: 0in; }p { margin-bottom: 0.08in; } Oracle Night Seminar #2 Solaris 3??????: ??? ?19? ZFS, dedup ??????? ??? 2012/04/13 [email protected] ???/??? ?????/????? root ?????? ?? <???> 100MB ??????????? demo:~$ sudo mkfile 100m /dev/dsk/dedupdisk ???????? dpool ?????? zfs ?????? demo:~$ sudo zpool create -f dpool dedupdisk <??> dpool ????? demo:~$ zpool status dpool dpool dedup??? ON ??? demo:~$ sudo zfs set dedup=on dpool dpool ?????? demo:~$ zpool list dpool ???????????? dpool ???? demo:~$ sudo cp /usr/jdk/latest/jre/lib/rt.jar /dpool/. dpool ?????? -> (dedup x 1) demo:~$ zpool list dpool ??????????????? demo:~$ sudo cp /usr/jdk/latest/jre/lib/rt.jar /dpool/rt-1.jar dpool ?????? -> (dedup x 2 ) demo:~$ zpool list dpool ?????????????????? demo:~$ sudo cp /usr/jdk/latest/jre/lib/rt.jar /dpool/rt-2.jar dpool ?????? -> (dedup x 3 ) demo:~$ zpool list dpool <???> dpool ??? demo:~$ sudo zpool destroy dpool ?????????? demo:~$ sudo rm /dev/dsk/dedupdisk

    Read the article

  • How can I test if a point lies within a 3d shape with its surface defined by a point cloud?

    - by Ben
    Hi I have a collection of points which describe the surface of a shape that should be roughly spherical, and I need a method with which to determine if any other given point lies within this shape. I've previously been approximating the shape as an exact sphere, but this has proven too inaccurate and I need a more accurate method. Simplicity and speed is favourable over complete accuracy, a good approximation will suffice. I've come across techniques for converting a point cloud to a 3d mesh, but most things I have found have been very complicated, and I am looking for something as simple as possible. Any ideas? Many thanks, Ben.

    Read the article

  • Is it possible to port a Windows RT app to a Windows Phone app?

    - by balint
    Just recently released an application to the Windows Store, and I'm wondering if it is possible to "downgrade" it to Windows Phone 7.1 - until Windows Phone 8 will arrive. The real problem is with the async stuff, I've found the "Async Targeting Pack", but it requires Visual Studio 2012; however VS2012 doesn't work with the Phone SDK 7.0, 7.1. I'm not in the mood to install old and ugly Visual Studio 2010 on my brand new Windows 8 machine :) Does anyone know a workaround?

    Read the article

  • Main purpose of this task is to calculate volumes and surface areas of three dimensional geometric shapes like, cylinders, cones.

    - by Csc_Girl_Geek
    In Java Language Design your classes as below introducing: an Interface named “GeometricShapes” an abstract class named “ThreeDShapes” two child classes of ThreeDShapes: Cylinders and Cones. One test class names “TestShapes” Get the output for volumes and surface areas of cylinders and cones along with respective values of their appropriate input variables. Try to use toString() method and array. Your classes should be designed with methods that are required for Object-Oriented programming. So Far I Have: package Assignment2; public interface GeometricShapes { public void render(); public int[] getPosition(); public void setPosition(int x, int y); } package Assignment2; public abstract class ThreeDShapes implements GeometricShapes { public int[] position; public int[] size; public ThreeDShapes() { } public int[] getPosition() { return position; } public void setPosition(int x, int y) { position[0] = x; position[1] = y; } } package Assignment2; public class Cylinders extends ThreeDShapes { public Cylinder() { } public void render() { } } I don't think this is right and I do not know how to fix it. :( Please help.

    Read the article

  • PHP Form checkbox question

    - by Sef
    Hello, I have a form that takes the following inputs: Name: IBM Surface(in m^2): 9 Floor: (Checkbox1) Phone: (Checkbox2) Network: (Checkbox3) Button to send to a next php page. All those values above are represented in a table when i press the submit button. The first two (name and surname) are properly displayed in the table. The problem is with the checkboxes. If i select the first checkbox the value in the table should be presented with 1. If its not selected the value in the table should be empty. echo "<td>$Name</td>"; // works properly echo "<td>$Surface</td>"; // works properly echo "<td>....no idea for the checkboxes</td>; Some part of my php code with the variables: <?php if (!empty($_POST)) { $standnaam = $_POST["name"]; $oppervlakte = $_POST["surface"]; $verdieping = $_POST["floor"]; $telefoon = $_POST["telefoon"]; $netwerk = $_POST["netwerk"]; if (is_numeric($surface)) { $_SESSION["name"]=$name; $_SESSION["surface"]=$surface; header("Location:ExpoOverzicht.php"); } else { echo "<h1>Wrong input, Pleasee fill in again</h1>"; } if(!empty($floor) && ($phone) && ($network)) { $_SESSION["floor"]=$floor; $_SESSION["phone"]=$phone; $_SESSION["network"]=$network; header("Location:ExpoOverzicht.php"); } } ?> Second page with table: <?php $name= $_SESSION["name"]; $surface= $_SESSION["surface"]; $floor= $_SESSION["floor"]; $phone= $_SESSION["phone"]; $network= $_SESSION["network"]; echo "<table class=\"tableExpo\">"; echo "<th>name</th>"; echo "<th>surface</th>"; echo "<th>floor</th>"; echo "<th>phone</th>"; echo "<th>network</th>"; echo "<th>total price</th>"; for($i=0; $i <= $_SESSION["name"]; $i++) { echo "<tr>"; echo "<td>$name</td>"; // gives right output echo "<td>$surface</td>"; // gives right output echo "<td>...</td>"; //wrong output (ment for checkbox 1) echo "<td>...</td>"; //wrong output (ment for checkbox 2) echo "<td>...</td>"; //wrong output (ment for checkbox 3) echo "<td>....</td>"; echo "</tr>;"; } echo "</table>"; <form action="<?php echo $_SERVER["PHP_SELF"]; ?>" method="post" id="form1"> <h1>Vul de gegevens in</h1> <table> <tr> <td>Name:</td> <td><input type="text" name="name" size="18"/></td> </tr> <tr> <td>Surface(in m^2):</td> <td><input type="text" name="surface" size="6"/></td> </tr> <tr> <td>Floor:</td> <td><input type="checkbox" name="floor" value="floor"/></td> </tr> <tr> <td>Phone:</td> <td><input type="checkbox" name="phone" value="phone"/></td> </tr> <tr> <td>Network:</td> <td><input type="checkbox" name="network" value="network"/></td> </tr> <tr> <td><input type="submit" name="verzenden" value="Verzenden"/></td> </tr> </table> There might be a few spelling mistakes since i had to translate it. Best regards.

    Read the article

  • How to gain accurate results with Painter's algorithm?

    - by pimvdb
    A while ago I asked how to determine when a face is overlapping another. The advice was to use a Z-buffer. However, I cannot use a Z-buffer in my current project and hence I would like to use the Painter's algorithm. I have no good clue as to when a surface is behind or in front of another, though. I've tried numerous methods but they all fail in edge cases, or they fail even in general cases. This is a list of sorting methods I've tried so far: Distance to midpoint of each face Average distance to each vertex of each face Average z value of each vertex Higest z value of vertices of each face and draw those first Lowest z value of vertices of each face and draw those last The problem is that a face might have a closer distance but is still further away. All these methods seem unreliable. Edit: For example, in the following image the surface with the blue point as midpoint is painted over the surface with the red point as midpoint, because the blue point is closer. However, this is because the surface of the red point is larger and the midpoint is further away. The surface with the red point should be painted over the blue one, because it is closer, whilst the midpoint distance says the opposite. What exactly is used in the Painter's algorithm to determine the order in which objects should be drawn?

    Read the article

  • Rendering with Direct3D

    - by Jamie
    Hi, I'm slightly confused about how Direct3D rendering works. Basically, as long as I render to one surface, everything is fine. But when I try rendering to multiple surfaces, it seems like everything is still rendered to one surface. I think there's something wrong with my calls. For each update cycle this is what I do 1. device-BeginScene() 2. sprite-Begin(...) ... A bunch of GetRenderTarget to store the old render target, then SetRenderTarget to set a new surface, and then things like CreateVertexBuffer, SetTexture, etc to draw on the new render target. Then resetting to the old render target. sprite-Draw([the back buffer]) (the back buffer is actually another surface, not the actual back buffer. But here it is being drawn onto the actual back buffer, I think) sprite-End() device-EndScene() device-Present(...) Also, it seems like if I mix sprite drawing and non-sprite drawing onto a surface, that first one set of render commands is executed and then the other set, rather than in order by when each command was called. If anyone could shed light on any of this, it would be much appreciated.

    Read the article

  • Efficient visualization of a large voxelized volume

    - by Alejandro Piad
    Lets consider a large voxelized volume stored in an oct-tree or any other convenient structure. This volume represents, for instance, a landscape, where each block is either empty (air), or it has an specific material that will be later used to apply a texture. Voxels that are next to each other represent connected sections of the surface. What I need is an algorithm to generate a mesh from this voxels that represents the volume, with the following caracteristics: All the "holes" in the voxelized volume are correct. All the connections are correct, i.e. seamless. The surface appears smooth. In a broad sense, I want to somehow preserve the surface topology, meaning that connected sections remain connected in the resulting mesh and that the surface has a curvature that responds to the voxels topology. Imagine trying to render the Minecraft world but getting the mountain ladders to be smooth instead of blocky.

    Read the article

  • SDL_DisplayFormat works, but not SDL_DisplayFormatAlpha

    - by Bounderby
    The following code is intended to display a green square on a black background. It executes, but the green square does not show up. However, if I change SDL_DisplayFormatAlpha to SDL_DisplayFormat the square is rendered correctly. So what don't I understand? It seems to me that I am creating *surface with an alpha mask and I am using SDL_MapRGBA to map my green color, so it would be consistent to use SDL_DisplayFormatAlpha as well. (I removed error-checking for clarity, but none of the SDL API calls fail in this example.) #include <SDL.h> int main(int argc, const char *argv[]) { SDL_Init( SDL_INIT_EVERYTHING ); SDL_Surface *screen = SDL_SetVideoMode( 640, 480, 32, SDL_HWSURFACE | SDL_DOUBLEBUF ); SDL_Surface *temp = SDL_CreateRGBSurface( SDL_HWSURFACE, 100, 100, 32, 0, 0, 0, ( SDL_BYTEORDER == SDL_BIG_ENDIAN ? 0x000000ff : 0xff000000 ) ); SDL_Surface *surface = SDL_DisplayFormatAlpha( temp ); SDL_FreeSurface( temp ); SDL_FillRect( surface, &surface->clip_rect, SDL_MapRGBA( screen->format, 0x00, 0xff, 0x00, 0xff ) ); SDL_Rect r; r.x = 50; r.y = 50; SDL_BlitSurface( surface, NULL, screen, &r ); SDL_Flip( screen ); SDL_Delay( 1000 ); SDL_Quit(); return 0; }

    Read the article

  • ASP.NET Hosting :: ASP.NET File Upload Control

    - by mbridge
    The asp.net FileUpload control allows a user to browse and upload files to the web server. From developers perspective, it is as simple as dragging and dropping the FileUpload control to the aspx page. An extra control, like a Button control, or some other control is needed, to actually save the file. <asp:FileUploadID="FileUpload1"runat="server"/> <asp:ButtonID="B1"runat="server"Text="Save"OnClick="B1_Click"/> By default, the FileUpload control allows a maximum of 4MB file to be uploaded and the execution timeout is 110 seconds. These properties can be changed from within the web.config file’s httpRuntime section. The maxRequestLength property determines the maximum file size that can be uploaded. The executionTimeout property determines the maximum time for execution. <httpRuntimemaxRequestLength="8192"executionTimeout="220"/> From code behind, the mime type, size of the file, file name and the extension of the file can be obtained. The maximum file size that can be uploaded can be obtained and modified using the System.Web.Configuration.HttpRuntimeSection class. Files can be alternatively saved using the System.IO.HttpFileCollection class. This collection class can be populated using the Request.Files property. The collection contains HttpPostedFile class which contains a reference to the class. using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.UI; using System.Web.UI.WebControls; using System.IO; using System.Configuration; using System.Web.Configuration;   namespace WebApplication1 {     public partial class WebControls : System.Web.UI.Page     {         protected void Page_Load(object sender, EventArgs e)         {         }           //Using FileUpload control to upload and save files         protected void B1_Click(object sender, EventArgs e)         {             if (FileUpload1.HasFile && FileUpload1.PostedFile.ContentLength > 0)             {                 //mime type of the uploaded file                 string mimeType = FileUpload1.PostedFile.ContentType;                   //size of the uploaded file                 int size = FileUpload1.PostedFile.ContentLength; // bytes                   //extension of the uploaded file                 string extension = System.IO.Path.GetExtension(FileUpload1.FileName);                                  //save file                 string path = Server.MapPath("path");                                 FileUpload1.SaveAs(path + FileUpload1.FileName);                              }             //maximum file size allowed             HttpRuntimeSection rt = new HttpRuntimeSection();             rt.MaxRequestLength = rt.MaxRequestLength * 2;             int length = rt.MaxRequestLength;                     //execution timeout             TimeSpan ts = rt.ExecutionTimeout;             double secomds = ts.TotalSeconds;           }           //Using Request.Files to save files         private void AltSaveFile()         {             HttpFileCollection coll = Request.Files;             for (int i = 0; i < coll.Count; i++)             {                 HttpPostedFile file = coll[i];                   if (file.ContentLength > 0)                     ;//do something             }         }     } }

    Read the article

  • Boost Python - Limits to the number of arguments when wrapping a function

    - by Derek
    I'm using Boost Python to wrap some C++ functions that I've created. One of my C++ functions contains 22 arguments. Boost complains when I try to compile my solution with this function, and I'm trying to figure out if it is just because this function has too many arguments. Does anyone know if such a limit exists? I've copied the error I'm getting below, not the code because I figure someone either knows the answer to this or not - and if there is no limit then I'll just try to figure it out myself. Thanks very much in advance! Here is a copy of the beginning of the error message I receive... 1>main.cpp 1>c:\cpp_ext\boost\boost_1_47\boost\python\make_function.hpp(76): error C2780: 'boost::mpl::vector17<RT,most_derived<Target,ClassT>::type&,T0,T1,T2,T3,T4,T5,T6,T7,T8,T9,T10,T11,T12,T13,T14> boost::python::detail::get_signature(RT (__thiscall ClassT::* )(T0,T1,T2,T3,T4,T5,T6,T7,T8,T9,T10,T11,T12,T13,T14) volatile const,Target *)' : expects 2 arguments - 1 provided 1>c:\cpp_ext\boost\boost_1_47\boost\python\signature.hpp(236) : see declaration of 'boost::python::detail::get_signature' And eventually I get about a hundred copies of error messages very much resembling this one: 1>c:\cpp_ext\boost\boost_1_47\boost\python\make_function.hpp(76): error C2784: 'boost::mpl::vector17<RT,ClassT&,T0,T1,T2,T3,T4,T5,T6,T7,T8,T9,T10,T11,T12,T13,T14> boost::python::detail::get_signature(RT (__thiscall ClassT::* )(T0,T1,T2,T3,T4,T5,T6,T7,T8,T9,T10,T11,T12,T13,T14) volatile const)' : could not deduce template argument for 'RT (__thiscall ClassT::* )(T0,T1,T2,T3,T4,T5,T6,T7,T8,T9,T10,T11,T12,T13,T14) volatile const' from 'std::string (__cdecl *)(const std::string &,jal::date::JULIAN_DATE,const std::string &,const std::string &,int,const std::string &,const std::string &,const std::string &,const std::string &,const std::string &,const std::string &,int,const std::string &,const std::string &,int,const std::string &,const std::string &,const std::string &,const std::string &,const std::string &,int,const std::string &)' 1> c:\cpp_ext\boost\boost_1_47\boost\python\signature.hpp(218) : see declaration of 'boost::python::detail::get_signature' 1>c:\cpp_ext\boost\boost_1_47\boost\python\make_function.hpp(76): error C2780: 'boost::mpl::vector17<RT,most_derived<Target,ClassT>::type&,T0,T1,T2,T3,T4,T5,T6,T7,T8,T9,T10,T11,T12,T13,T14> boost::python::detail::get_signature(RT (__thiscall ClassT::* )(T0,T1,T2,T3,T4,T5,T6,T7,T8,T9,T10,T11,T12,T13,T14) volatile,Target *)' : expects 2 arguments - 1 provided 1> c:\cpp_ext\boost\boost_1_47\boost\python\signature.hpp(236) : see declaration of 'boost::python::detail::get_signature'

    Read the article

  • HIGH CPU USAGE + low memory usage

    - by hadi
    as you can see in below , there are high cpu usage by httpd request. please help me to decrease them. thanks. 28577 apache 15 0 99676 53m 3488 S 21 0.2 1:13.67 httpd 28568 apache 15 0 99676 53m 3496 S 19 0.2 1:14.92 httpd 28608 apache 15 0 99676 53m 3428 R 19 0.2 0:28.28 httpd 28615 apache 15 0 99676 53m 3436 R 19 0.2 0:25.33 httpd 28616 apache 15 0 99676 53m 3440 S 19 0.2 0:25.83 httpd 28619 apache 15 0 99676 53m 3436 R 19 0.2 0:26.12 httpd 28635 apache 15 0 97.9m 54m 3416 S 19 0.2 0:24.86 httpd 28558 apache 15 0 97.9m 54m 3432 R 17 0.2 1:40.75 httpd 28560 apache 15 0 97.9m 54m 3496 R 17 0.2 1:40.02 httpd 28621 apache 15 0 97.9m 54m 3420 S 17 0.2 0:25.61 httpd 28641 apache 16 0 97.9m 54m 3428 R 17 0.2 0:21.52 httpd 28642 apache 15 0 99756 53m 3424 R 15 0.2 0:21.46 httpd 28643 apache 15 0 99676 53m 3424 S 15 0.2 0:21.59 httpd 28594 apache 15 0 99756 53m 3428 R 13 0.2 0:44.41 httpd 28618 apache 15 0 99676 53m 3420 S 13 0.2 0:26.15 httpd 28654 apache 15 0 99676 53m 3472 S 13 0.2 0:04.27 httpd 28575 apache 15 0 99756 53m 3436 R 11 0.2 1:14.02 httpd 28576 apache 15 0 99676 53m 3496 S 11 0.2 1:16.79 httpd 28634 apache 15 0 99676 53m 3436 S 11 0.2 0:25.36 httpd 28653 apache 15 0 99676 53m 3424 S 11 0.2 0:04.35 httpd 28574 apache 15 0 99676 53m 3440 S 10 0.2 1:13.05 httpd 28592 apache 15 0 99676 53m 3492 R 10 0.2 0:45.78 httpd 28595 apache 15 0 99676 53m 3432 R 10 0.2 0:47.02 httpd 28617 apache 16 0 99676 53m 3436 S 10 0.2 0:25.32 httpd 28620 apache 15 0 99676 53m 3432 S 10 0.2 0:25.35 httpd 28597 apache 15 0 99676 53m 3428 S 8 0.2 0:43.56 httpd 11345 mysql 15 0 2927m 198m 4472 R 4 0.6 1624:43 mysqld 1 root 15 0 2036 648 552 S 0 0.0 0:16.97 init 2 root RT 0 0 0 0 S 0 0.0 0:48.50 migration/0 3 root 34 19 0 0 0 S 0 0.0 0:26.72 ksoftirqd/0 4 root RT 0 0 0 0 S 0 0.0 0:00.00 watchdog/0 5 root RT 0 0 0 0 S 0 0.0 0:04.98 migration/1 6 root 34 19 0 0 0 R 0 0.0 0:27.51 ksoftirqd/1 7 root RT 0 0 0 0 S 0 0.0 0:00.00 watchdog/1 8 root RT 0 0 0 0 S 0 0.0 0:15.42 migration/2 9 root 34 19 0 0 0 S 0 0.0 0:26.50 ksoftirqd/2 10 root RT 0 0 0 0 S 0 0.0 0:00.00 watchdog/2

    Read the article

  • How to understand the memory usage and load average in linux server

    - by Tim
    Hi, I am using a linux server which has 128GB of memory and 24 cores. I use top to see how much it is used. Its output is pasted at the end of the post. Here are two questions: (1) I see that each of the running processes occupies a very small percentage of memory (%MEM no more than 0.2%, and most just 0.0%), but how the total memory is almost used as in the fourth line of output ("Mem: 130766620k total, 130161072k used, 605548k free, 919300k buffers")? The sum of used percentage of memory over all processes seems unlikely to achieve almost 100%, doesn't it? (2) how to understand the load average on the first line ("load average: 14.04, 14.02, 14.00")? Thanks and regards! Edit: Thanks! I also really like to hear some rough numbers based on used percentage of memory to determine if a server is heavily loaded, since I once became the one who cramed the server without understanding the current load. Is swap regarded as almost the same as memory? For example, when memory and swap are almost of same size, if the memory is almost running out but the swap is still largely free, may I just view it as if the used percentage of memory + swap is still not high and run other new processes? How would you consider together CPU or memory (or memory + swap) usage? Do you become worried if either of them reaches too high or both? Output of top: $ top top - 12:45:33 up 19 days, 23:11, 18 users, load average: 14.04, 14.02, 14.00 Tasks: 484 total, 12 running, 472 sleeping, 0 stopped, 0 zombie Cpu(s): 36.7%us, 19.7%sy, 0.0%ni, 43.6%id, 0.0%wa, 0.0%hi, 0.0%si, 0.0%st Mem: 130766620k total, 130161072k used, 605548k free, 919300k buffers Swap: 63111312k total, 500556k used, 62610756k free, 124437752k cached PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND 6529 sanchez 18 -2 1075m 219m 13m S 100 0.2 13760:23 MATLAB 13210 timothy 18 -2 48336 37m 1216 R 100 0.0 3:56.75 absurdity 13888 timothy 18 -2 48336 37m 1204 R 100 0.0 2:04.89 absurdity 14542 timothy 18 -2 48336 37m 1196 R 100 0.0 1:08.34 absurdity 14544 timothy 18 -2 2888 2076 400 R 100 0.0 1:06.14 gatherData 6183 sanchez 18 -2 1133m 195m 13m S 100 0.2 13676:04 MATLAB 6795 sanchez 18 -2 1079m 210m 13m S 100 0.2 13734:26 MATLAB 10178 timothy 18 -2 48336 37m 1204 R 100 0.0 11:33.93 absurdity 12438 timothy 18 -2 48336 37m 1216 R 100 0.0 5:38.17 absurdity 13661 timothy 18 -2 48336 37m 1216 R 100 0.0 2:44.13 absurdity 14098 timothy 18 -2 48336 37m 1204 R 100 0.0 1:58.31 absurdity 14335 timothy 18 -2 48336 37m 1196 R 100 0.0 1:08.93 absurdity 14765 timothy 18 -2 48336 37m 1196 R 99 0.0 0:32.57 absurdity 13445 timothy 18 -2 48336 37m 1216 R 99 0.0 3:01.37 absurdity 28990 root 20 0 0 0 0 S 2 0.0 65:50.21 pdflush 12141 tim 18 -2 19380 1660 1024 R 1 0.0 0:04.04 top 1240 root 15 -5 0 0 0 S 0 0.0 16:07.11 kjournald 9019 root 20 0 296m 4460 2616 S 0 0.0 82:19.51 kdm_greet 1 root 20 0 4028 728 592 S 0 0.0 0:03.11 init 2 root 15 -5 0 0 0 S 0 0.0 0:00.00 kthreadd 3 root RT -5 0 0 0 S 0 0.0 0:01.01 migration/0 4 root 15 -5 0 0 0 S 0 0.0 0:08.13 ksoftirqd/0 5 root RT -5 0 0 0 S 0 0.0 0:00.00 watchdog/0 6 root RT -5 0 0 0 S 0 0.0 17:27.31 migration/1 7 root 15 -5 0 0 0 S 0 0.0 0:01.21 ksoftirqd/1 8 root RT -5 0 0 0 S 0 0.0 0:00.00 watchdog/1 9 root RT -5 0 0 0 S 0 0.0 10:02.56 migration/2 10 root 15 -5 0 0 0 S 0 0.0 0:00.34 ksoftirqd/2 11 root RT -5 0 0 0 S 0 0.0 0:00.00 watchdog/2 12 root RT -5 0 0 0 S 0 0.0 4:29.53 migration/3 13 root 15 -5 0 0 0 S 0 0.0 0:00.34 ksoftirqd/3

    Read the article

  • Opening an existing process

    - by Grasper
    I am using Eclipse in Linux through a remote connection (xrdp). My internet got disconnected, so I got disconnected from the server while eclipse was running. Now I logged in again, and I do the "top" command I can see that eclipse is running and still under my user name. Is there some way I can bring that process back into my view (I do not want to kill it because I am in the middle of checking in a large swath of code)? It doesnt show up on the bottom panel after I logged in again. Here is the "top" output: /home/mclouti% top top - 08:32:31 up 43 days, 13:06, 29 users, load average: 0.56, 0.79, 0.82 Tasks: 447 total, 1 running, 446 sleeping, 0 stopped, 0 zombie Cpu(s): 6.0%us, 0.7%sy, 0.0%ni, 92.1%id, 1.1%wa, 0.1%hi, 0.1%si, 0.0%st Mem: 3107364k total, 2975852k used, 131512k free, 35756k buffers Swap: 2031608k total, 59860k used, 1971748k free, 817816k cached PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND 13415 mclouti 15 0 964m 333m 31m S 21.2 11.0 83:12.96 eclipse 16040 mclouti 15 0 2608 1348 888 R 0.7 0.0 0:00.12 top 31395 mclouti 15 0 29072 20m 8524 S 0.7 0.7 611:08.08 Xvnc 2583 root 20 0 898m 2652 1056 S 0.3 0.1 139:26.82 automount 28990 postgres 15 0 13564 868 304 S 0.3 0.0 26:33.36 postgres 28995 postgres 16 0 13808 1248 300 S 0.3 0.0 6:54.95 postgres 31440 mclouti 15 0 3072 1592 1036 S 0.3 0.1 6:01.54 gam_server 1 root 15 0 2072 524 496 S 0.0 0.0 0:03.00 init 2 root RT -5 0 0 0 S 0.0 0.0 0:04.53 migration/0 3 root 34 19 0 0 0 S 0.0 0.0 0:00.04 ksoftirqd/0 4 root RT -5 0 0 0 S 0.0 0.0 0:00.00 watchdog/0 5 root RT -5 0 0 0 S 0.0 0.0 0:01.72 migration/1 6 root 34 19 0 0 0 S 0.0 0.0 0:00.07 ksoftirqd/1 7 root RT -5 0 0 0 S 0.0 0.0 0:00.00 watchdog/1 8 root RT -5 0 0 0 S 0.0 0.0 0:04.33 migration/2 9 root 34 19 0 0 0 S 0.0 0.0 0:00.05 ksoftirqd/2

    Read the article

  • 0% CPU in top for all processes, but load average > 1

    - by chrisdew
    On two different servers (with Ubuntu 12.04LTS AMD64) I have seen the following behaviour: op - 10:50:05 up 305 days, 21:17, 1 user, load average: 1.94, 2.52, 2.97 Tasks: 141 total, 2 running, 139 sleeping, 0 stopped, 0 zombie Cpu(s): 41.5%us, 6.5%sy, 0.0%ni, 51.8%id, 0.0%wa, 0.2%hi, 0.1%si, 0.0%st Mem: 8178432k total, 5753740k used, 2424692k free, 159480k buffers Swap: 15625208k total, 0k used, 15625208k free, 4905292k cached PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND 1 root 20 0 23928 2072 1216 S 0 0.0 0:56.42 init 2 root 20 0 0 0 0 S 0 0.0 0:00.01 kthreadd 3 root RT 0 0 0 0 S 0 0.0 0:01.23 migration/0 4 root 20 0 0 0 0 S 0 0.0 2:39.82 ksoftirqd/0 5 root RT 0 0 0 0 S 0 0.0 0:00.00 watchdog/0 6 root RT 0 0 0 0 S 0 0.0 0:02.99 migration/1 7 root 20 0 0 0 0 S 0 0.0 2:32.15 ksoftirqd/1 8 root RT 0 0 0 0 S 0 0.0 0:00.00 watchdog/1 9 root RT 0 0 0 0 S 0 0.0 0:11.67 migration/2 10 root 20 0 0 0 0 S 0 0.0 29:00.34 ksoftirqd/2 The server is working fine, but top shows all processes as using 0% CPU. A reboot fixed this on an earlier machine, but I haven't yet tried it on this one. I have tried top several times, and so am sure that I haven't accidentally pressed '<' or '' to sort by a different column. Sorting the process list by all of the available columns, stills shows 0% CPU for all displayed processes. What is going on? If this a kernel bug? Update: If I use top -p <PID> for a know, busy process, top still displays 0% CPU for that process.

    Read the article

  • ubuntu precise high hard drive I/O

    - by pavolzetor
    on ubuntu precise, all apps starts slowly, and my hard drive is all time in use. What is the cause? it was never before, even nautilus takes a lot time to load, boot is also slower. top - 18:37:05 up 1:07, 1 user, load average: 2.03, 2.34, 2.25 Tasks: 182 total, 1 running, 180 sleeping, 0 stopped, 1 zombie Cpu(s): 30.2%us, 7.2%sy, 1.4%ni, 53.9%id, 7.1%wa, 0.0%hi, 0.2%si, 0.0%st Mem: 3941576k total, 3522048k used, 419528k free, 50156k buffers Swap: 0k total, 0k used, 0k free, 1827640k cached PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND 2508 pk 20 0 1018m 189m 28m S 4 4.9 22:28.04 plugin-containe 1290 root 20 0 82336 16m 1492 S 2 0.4 0:04.41 landscape-clien 1305 root 20 0 97280 22m 5584 S 2 0.6 0:01.57 landscape-manag 4201 pk 20 0 17328 1312 924 R 2 0.0 0:00.02 top 1 root 20 0 24436 2364 1268 S 0 0.1 0:00.68 init 2 root 20 0 0 0 0 S 0 0.0 0:00.00 kthreadd 3 root 20 0 0 0 0 S 0 0.0 0:00.45 ksoftirqd/0 6 root RT 0 0 0 0 S 0 0.0 0:00.00 migration/0 7 root RT 0 0 0 0 S 0 0.0 0:00.02 watchdog/0 8 root RT 0 0 0 0 S 0 0.0 0:00.00 migration/1 10 root 20 0 0 0 0 S 0 0.0 0:00.43 ksoftirqd/1 12 root RT 0 0 0 0 S 0 0.0 0:00.01 watchdog/1 13 root 0 -20 0 0 0 S 0 0.0 0:00.00 cpuset

    Read the article

  • Will an app made for windows store support WindowsRT, windows8 and windows 8 mobile?

    - by AnhSirk Dasarp
    I am very much confused about these. I would like to develop app for windows 8 , Windows RT , and windows mobile. I have windows 8 OS installed in my laptop. As far as I know, Windows RT is for ARM based devices. HERE ARE MY QUESTIONS: I develop an app, and put in windows store. Will that can be downloaded from a ARM based device ,which runs on Windows RT, AND from a windows 8 laptop , and same from a Windows 8 mobile? OR should it be different apps ?

    Read the article

  • mips number of clock cycles and how improving code

    - by Hooman
    I'm really new in MIPS and I have these questions which I found so many dissimil answers for them ... if someone can help, it would be great. Thanks How many clock cycles does this code take? #Macro Instructions li $t0, 32 # 1 or 2 cycles ? # lui $at, Upper 16-bits of value # ori Rd, $at, Lower 16-bits of value # ----------------------------------- # ori Rt, $0, value # # Which set of instructions will be executed? div $t2, $t2, $t0 # 41 cycles? # bne Rt, $0, # break $0 # ok: div Rs, Rt # mflo Rd #Integer Instruction lw $t2, 0($t13) # 1 cycles? sw $t2, 0($t3) # 1 cycles? How those 4 lines of codes can be significantly improved? by avoiding to use Macros or ... ?

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 6 7 8 9 10 11 12 13 14 15 16 17  | Next Page >