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• XAML support for local-name() in XPath

  - by emddudley

  I'd like to bind to the element name of a node in my XmlDataProvider. I can't seem to get local-name() to work within my XPath expression. Does XAML support local-name()? <TextBlock Text="{Binding XPath=local-name()}" />

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• YQL How to use wildcard in XPath

  - by uku

  Hello, I have a malformed page to scrape, and have had a hard time getting the correct XPath for YQL. I can scrape individual fields that I need using, for example: //*[@id="cell_12345"] But what I really need to do is return all elements who's ID begins with cell_. Something like: //*[@id="cell_"*] How do I do this? Also, if anybody can point me to a good XPath reference it would be very helpful. Thanks!

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• xpath: string manipulation

  - by Jindan Zhou

  So in my scrapy project I was able to isolate some particular fields, one of the field return something like: [Rank Info] on 2013-06-27 14:26 Read 174 Times which was selected by expression: (//td[@class="show_content"]/text())[4] I usually do post-processing to extract the datetime information, i.e., 2013-06-27 14:26 Now since I've learned a little more on the xpath substring manipulation, I am wondering if it is even possible to extract that piece of information in the first place, i.e., in the xpath expression itself? Thanks,

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• Parse HTML with CSS or XPath selectors?

  - by ovolko

  My goal is to parse HTML with lxml, which supports both XPath and CSS selectors. I can tie my model properties either to CSS or XPath, but I'm not sure which one would be the best, e.g. less fuss when HTML layout is changed, simpler expressions, greater extraction speed. What would you choose in such a situation?

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• Nokogiri parsing Rackspace return using XPath in Rails

  - by Schroedinger

  Hey guys, I'm using Nokogiri to parse a return from the Rackspace API so I'm using their sample code to response = server.get '/customers/'[email protected]_id.to_s+'/domains/', server.xml_format doc = Nokogiri::XML::parse response.body puts "xpath values" doc.xpath("//name").each do |node| puts node.text end As my code to use Nokogiri to return the nodelist of nodes of the element for some reason I seem to have missed something obvious and I just for the life of me cannot get it to parse the list of nodes and return them to me, is there something simple I can do to fix to have it return the list of nodes? Cheers

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• NamespaceContext and using namespaces with XPath

  - by Jherico

  Resolving an xpath that includes namepsaces in Java appears to require the use of a NamespaceContext object, mapping prefixes to namespace urls and vice versa. But I can find no mechanism for getting a NamespaceContext other than implementing it myself. This seems counter-intuitive. Is there any easy way to acquire a NamespaceContext from a document, or to create one, or failing that, to forgo prefixes altogether and specify the xpath with fully qualified names?

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• Use of text() function when using xPath in dom4j

  - by jlawless

  I have inherited an application that parses xml using dom4j and xPath: The xml being parsed is similar to the following: <cache> <content> <transaction> <page> <widget name="PAGE_ID">WRK_REGISTRATION</widget> <widget name="TRANS_DETAIL_ID">77145</widget> <widget name="GRD_ERRORS" /> </page> <page> <widget name="PAGE_ID">WRK_REGISTRATION</widget> <widget name="TRANS_DETAIL_ID">77147</widget> <widget name="GRD_ERRORS" /> </page> <page> <widget name="PAGE_ID">WRK_PROCESSING</widget> <widget name="TRANS_DETAIL_ID">77152</widget> <widget name="GRD_ERRORS" /> </page> </transaction> </content> </cache> Individual Nodes are being searched using the following: String xPathToGridErrorNode = "//cache/content/transaction/page/widget[@name='PAGE_ID'][text()='WRK_DNA_REGISTRATION']/../widget[@name='TRANS_DETAIL_ID'][text()='77147']/../widget[@name='GRD_ERRORS_TEMP']"; org.dom4j.Element root = null; SAXReader reader = new SAXReader(); Document document = reader.read(new BufferedInputStream(new ByteArrayInputStream(xmlToParse.getBytes()))); root = document.getRootElement(); Node gridNode = root.selectSingleNode(xPathToGridErrorNode); where xmlToParse is a String of xml similar to the excerpt provided above. The code is trying to obtain the GRD_ERROR node for the page with the PAGE_ID and TRANS_DETAIL_ID provided in the xPath. I am seeing an intermittent (~1-2%) failure (returned node is null) of this selectSingleNode request even though the requested node is in the xml being searched. I know there are some gotchas associated with using text()= in xPath and was wondering if there was a better way to format the xPath string for this type of search.

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• Interpret a rule applying multiple xpath queries on multiple XML documents

  - by Damien

  Hi, I need to build a component which would take a few XML documents in input and check the following kind of rules: XML1:/bookstore/book[price>35.00] != null and (XML2:/city/name = 'Montreal' or XML3://customer[@language] contains 'en') Basically my component should be able to: substitute the XML tokens with the corresponding XML document(before colon) apply xpath query on this XML document check the xpath output against expected result ("=", "!=", "contains") follow the basic syntax ("and", "or" and parentheses) tell if the rule is true or false Do you know any library which could help me? maybe JavaCC? Thanks

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• Nokogiri (Ruby) and XPath

  - by JP

  Does Nokogiri only support XPath 1.0? I'm trying to do simple string replacement in a value-of cell, like so (where element contains something like '* My string (useless text)') <xsl:value-of select="replace(element,'^\*\ (.+)\ \(.*\)$','\\1')"> Is this poorly formed XSL? Or is there a limitation with Nokogiri?

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• XPath tools for Mac OS X

  - by Paul Lefebvre

  When I worked mostly in Windows, I used Stylus Studio to test out XPath on my XML files. Now that I primarily use OS X, I haven't found an equivalent tool. What tools for OS X do you recommend for XPath work?

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• I need a way to implement the function matches() from XPath 2.0 with functions from XPath 1.0

  - by Jenny Smith

  I have the following piece of code: root="//valueExpression[matches(self::*,'pattern')]/.." But I can only use XPath 1.0 and I get an exception for the function matches(). Can you please help me with a solution using only functions from XPath 1.0 ?

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• Xpath visualization

  - by JavaRocky

  I am looking for a XML tool which does the following things. Allows me to enter xpath expressions and highlights the nodes selected Assists me in creating complex xpath expressions. What are other people using out there? I've used something from source forge but it only selects one matched node.

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• Custom xsl rendering for lookup field in list view (SharePoint 2010)

  - by Luc

  I'm trying to change rendering of a list column on list view page. After a few tutorials and some hair pulling I managed to create an xslt for a calculated and currency field (from fldtypes_XXXXXX.xsl): <xsl:template match ="FieldRef[@Name='MarkCalc']" mode="Text_body"> <xsl:param name="thisNode" select="."/> <xsl:value-of select="$thisNode/@*[name()=current()/@Name]" disable-output-escaping ="yes"/> </xsl:template> <xsl:template match="FieldRef[@Name='CurrencyTest']" mode="Number_body"> <xsl:param name="thisNode" select="."/> <b><xsl:value-of disable-output-escaping="yes" select="$thisNode/@*[name()=current()/@Name]" /></b> </xsl:template> Then I tried to do the same for a lookup field, but it just won't work. This is my last attempt (I copied it from SharePoint designer). What am I missing? <xsl:template match="FieldRef[(@Encoded) and @Name='Lookup1']" mode="Lookup_body"> <xsl:param name="thisNode" select="."/> <b><xsl:value-of select="$thisNode/@*[name()=current()/@Name]" disable-output-escaping="yes" /></b> </xsl:template>

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• XSLT: Regular Expression function does not work?

  - by Fedor Steeman

  Ok, this one has been driving me up the wall... I have a xslt function that is supposed to split out the Zip-code part from a Zip+City string depending on the country. I cannot get it to work! This is what I got so far: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:exslt="http://exslt.org/functions" xmlns:xs="http://www.w3.org/2001/XMLSchema"> <xsl:function name="exslt:GetZip" as="xs:string"> <xsl:param name="zipandcity" as="xs:string"/> <xsl:param name="countrycode" as="xs:string"/> <xsl:choose> <xsl:when test="$countrycode='DK'"> <xsl:analyze-string select="$zipandcity" regex="(\d{4}) ([A-Za-zÆØÅæøå]{3,24})"> <xsl:matching-substring> <xsl:value-of select="regex-group(1)"/> </xsl:matching-substring> <xsl:non-matching-substring> <xsl:text>fail</xsl:text> </xsl:non-matching-substring> </xsl:analyze-string> </xsl:when> <xsl:otherwise> <xsl:text>error</xsl:text> </xsl:otherwise> </xsl:choose> </xsl:function> I am running it on a source XML where the following values are passed to the function: zipandcity: "DK-2640 København SV" countrycode: "DK" ...will output 'fail'! I think there is something I am misunderstanding here...

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• How to change the footer image in each page of xsl-fo according to certain condition

  - by Thunder

  Is there a way to change the footer image in each page of xsl-fo according to certain condition?

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• More efficient approach to XSLT for-each

  - by Paul

  I have an XSLT which takes a . delimted string and splits it into two fields for a SQL statement: <xsl:for-each select="tokenize(Path,'\.')"> <xsl:choose> <xsl:when test="position() = 1 and position() = last()">SITE = '<xsl:value-of select="."/>' AND PATH = ''</xsl:when> <xsl:when test="position() = 1 and position() != last()">SITE = '<xsl:value-of select="."/>' </xsl:when> <xsl:when test="position() = 2 and position() = last()">AND PATH = '<xsl:value-of select="."/>' </xsl:when> <xsl:when test="position() = 2">AND PATH = '<xsl:value-of select="."/></xsl:when> <xsl:when test="position() > 2 and position() != last()">.<xsl:value-of select="."/></xsl:when> <xsl:when test="position() > 2 and position() = last()">.<xsl:value-of select="."/>' </xsl:when> <xsl:otherwise>zxyarglfaux</xsl:otherwise> </xsl:choose> </xsl:for-each> The results are as follows: INPUT: North OUTPUT: SITE = 'North' AND PATH = '' INPUT: North.A OUTPUT: SITE = 'North' AND PATH = 'A' INPUT: North.A.B OUTPUT: SITE = 'North' AND PATH = 'A.B' INPUT: North.A.B.C OUTPUT: SITE = 'North' AND PATH = 'A.B.C' This works, but is very lengthy. Can anyone see a more efficient approach? Thanks!

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• problem using the xsl method for-each

  - by joe

  Using XSL I am trying to turn this XML: <book><title>This is a <b>great</b> book</title></book> into this XML: <book>This is a <bold>great</bold> book</book> using this xsl: <xsl:for-each select="book/title/*"> <xsl:choose> <xsl:when test="name() = 'b'"> <bold> <xsl:value-of select="text()"/> </bold> </xsl:when> <xsl:otherwise> <xsl:value-of select="text()"/> </xsl:otherwise> </xsl:choose> </xsl:for-each> but my output is looking like this: <book><bold>great</bold></bold> Can anyone explain why the root text of <title> is getting lost? I believe my for-each select statement may need to be modified but I can't figure out what is should be. Keep in mind that I cannot use an <xsl:template match> because of the complexity of my style sheet. Thanks!

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• XML and XSLT: need it to sort only certain child nodes

  - by MT

  Hello, I need to have my XSLT stylesheet sort my XML file's child nodes, but only certain ones. Here's an example of what the XML is like: <?xml version="1.0"?> <xmltop> <child1 num="1"> <data>12345</data> </child1> <child1 num="2"> <data>12345</data> </child1> <child2 num="3"> <data>12345</data> </child2> <child2 num="2"> <data>12345</data> </child2> <child2 num="1"> <data>12345</data> </child2> </xmltop> And this is the XSL file I'm using: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/xmltop"> <xsl:copy> <xsl:apply-templates> <xsl:sort select="@num"/> </xsl:apply-templates> </xsl:copy> </xsl:template> <xsl:template match="child2"> <xsl:copy-of select="."/> </xsl:template> </xsl:stylesheet> This creates problems for me because the nodes are stripped of their tags, and their contents remain, making my XML invalid. I'm not really an expert at XSL so pardon me if this is a dumb question. The <child2>'s are sorted properly. Thank you.

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• XPath with optional tbody element

  - by Phrogz

  As in this Stack Overflow answer imagine that you need to select a particular table and then all the rows of it. Due to the permissiveness of HTML, all three of the following are legal markup: <table id="foo"><tr>...</tr></table> <table id="foo"><tbody><tr>...</tr></tbody></table> <table id="foo"><tr>...</tr><tbody><tr>...</tr></tbody></table> You are worried about tables nested in tables, and so don't want to use an XPath like table[@id="foo"]//tr. If you could specify your desired XPath as a regex, it might look something like: table[@id="foo"](/tbody)?/tr In general, how can you specify an XPath expression that allows an optional element in the hierarchy of a selector? To be clear, I'm not trying to solve a real-world problem or select a specific element of a specific document. I'm asking for techniques to solve a class of problems.

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• Xpath fails if an element has a a xmlns attribute

  - by Callum Lamb

  Im trying to use xml to parse a .COLLADA file. The problem is I can't seem to use xpath() to access elements if the root tag has a xmlns attribute. For example this works: $string = <<<TEST <?xml version="1.0" encoding="utf-8"?> <COLLADA version="1.4.1"> <library_materials> <material id="Material" name="Material"> <instance_effect url="#Material-effect"/> </material> <material id="Material2" name="Material"> <instance_effect url="#Material-effect2"/> </material> </library_materials> </COLLADA> TEST; $lol = new SimpleXMLElement($string); print_r($lol->library_materials->xpath("material[@id='Material2']")); But this doesn't: $string = <<<TEST <?xml version="1.0" encoding="utf-8"?> <COLLADA xmlns="http://www.collada.org/2005/11/COLLADASchema" version="1.4.1"> <library_materials> <material id="Material" name="Material"> <instance_effect url="#Material-effect"/> </material> <material id="Material2" name="Material"> <instance_effect url="#Material-effect2"/> </material> </library_materials> </COLLADA> TEST; $lol = new SimpleXMLElement($string); print_r($lol->library_materials->xpath("material[@id='Material2']")); How does the xmlns suddenly make the xml tree unusable? I thought it just defined the namespace so you could tell it apart from other identical tags in other namespaces. What am I missing?

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• Loop XML including all its children using xpath and SimpleXMLElement

  - by Andersson

  Im having a big xml tree with a simple structure. All I want to do is get a node by its attribute using xpath and loop the children. param1 - correct language param1 & param3 - correct node by its id and the parents id. (Need to use parent id when multiplie id appears. The id is not declared as id in DTD) public function getSubmenuNodesRe($language, $id1,$id2) { $result = $this->xml->xpath("//*[@language='$language']//*[@id='$id1']//menuitem[@id='$id2']/*"); return $result; } This works well, I get the node Im expecting. I having no problems looping the array returned by the xpath query. But when i try to loop childnodes all attributes are gone and many of the methods also. Except getName(). function printNodeName($node) { echo $node->getName(). " - \"" . $node['id']. "\"<br>"; if($node->children()->getName() == "menuitem") { $s = $node->children(); printNodeName($s); } } $result = $xmlNode->getSubmenuNodesRe($_GET['language'], 'foo','bar'); if ($result) { while(list( , $node) = each($result)) { if ($node->getName() == "menuitem") { printNodeName($node); } } } Why is that? only the name will be printed for the $s. Really need help to solve this one, any assistance is deeply appreciated! Thanks for your time.

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• Xpath: Selecting all of an element type?

  - by Johannes

  I'm just starting to learn Xpath, I'm trying to write a line of code that will select all of the actors in EACH movie parent (through Java!). Below, I have an example of one movie, but there are multiple <Movie> elements, each with <Actor> elements. <Movie Genre = 'Other'> <Title>Requiem For A Dream</Title> <ReleaseYear>2000</ReleaseYear> <Director>Darren Aronofsky</Director> <Actor Character = 'Sara Goldfarb'>Ellen Burstyn</Actor> <Actor Character = 'Harry Goldfarb'>Jared Leto</Actor> <Actor Character = 'Marion Silver'>Jennifer Connelly</Actor> <Actor Character = 'Tyrone C. Love'>Marlon Wayans</Actor> </Movie> Currently, I can only select the first <Actor> element of each <Movie> element -- is it possible to select all of them without using a for loop? Here is my current line of code that displays the first <Actor> element of every <Movie> element: System.out.println("Starring: " + xpath.evaluate("Actor", movieNode) + " as " + xpath.evaluate("Actor/@Character", movieNode) + "\n"); Any and all help if much appreciated!

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• Using a string inside the DocumentBuilder parse method (need it for parsing XML using XPath)

  - by dierre

  Hi guys! I'm trying to create a RESTful webservice using a Java Servlet. The problem is I have to pass via POST method to a webserver a request. The content of this request is not a parameter but the body itself. So I basically send from ruby something like this: url = URI.parse(@host) req = Net::HTTP::Post.new('/WebService/WebServiceServlet') req['Content-Type'] = "text/xml" # req.basic_auth 'account', 'password' req.body = data response = Net::HTTP.start(url.host, url.port){ |http| puts http.request(req).body } Then I have to retrieve the body of this request in my servlet. I use the classic readline, so I have a string. The problem is when I have to parse it as XML: private void useXML( final String soft, final PrintWriter out) throws ParserConfigurationException, SAXException, IOException, XPathExpressionException, FileNotFoundException { DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance(); domFactory.setNamespaceAware(true); // never forget this! DocumentBuilder builder = domFactory.newDocumentBuilder(); Document doc = builder.parse(soft); XPathFactory factory = XPathFactory.newInstance(); XPath xpath = factory.newXPath(); XPathExpression expr = xpath.compile("//software/text()"); Object result = expr.evaluate(doc, XPathConstants.NODESET); NodeList nodes = (NodeList) result; for (int i = 0; i < nodes.getLength(); i++) { out.println(nodes.item(i).getNodeValue()); } } The problem is that builder.parse() accepts: parse(File f), parse(InputSource is), parse(InputStream is). Is there any way I can transform my xml string in an InputSource or something like that? I know it could be a dummy question but Java is not my thing, I'm forced to use it and I'm not very skilled.

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• XSL - How to match consecutive comma-separated tags

  - by PocketLogic

  I'm trying to match a series of xml tags that are comma separated, and to then apply an xslt transformation on the whole group of nodes plus text. For example, given the following partial XML: <p>Some text here <xref id="1">1</xref>, <xref id="2">2</xref>, <xref id="3">3</xref>. </p> I would like to end up with: <p>Some text here ^1,2,3.</p> A much messier alternate would also be acceptable at this point: <p>Some text here ¹^,²^,³.</p> I have the transformation to go from a single xref to a sup: <xsl:template match="xref""> ^{<xsl:apply-templates/>} </xsl:template> But I'm at a loss as to how to match a group of nodes separated by commas. Thanks.

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• XSLT templates and recursion

  - by user333411

  Hi All, Im new to XSLT and am having some problems trying to format an XML document which has recursive nodes. My XML Code: Hopefully my XML shows: All <item> are nested with <items> An item can have either just attributes, or sub nodes The level to which <item> nodes are nested can be infinently deep <?xml version="1.0" encoding="utf-8" ?> - <items> <item groupID="1" name="Home" url="//" /> - <item groupID="2" name="Guides" url="/Guides/"> - <items> - <item groupID="26" name="Online-Poker-Guide" url="/Guides/Online-Poker-Guide/"> - <items> - <item> <id>107</id> - <title> - <![CDATA[ Poker Betting - Online Poker Betting Structures ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/online-poker-betting-structures ]]> </url> </item> - <item> <id>114</id> - <title> - <![CDATA[ Beginners&#39; Poker - Poker Hand Ranking ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/online-poker-hand-ranking ]]> </url> </item> - <item> <id>115</id> - <title> - <![CDATA[ Poker Terms - 4th Street and 5th Street ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/online-poker-poker-terms ]]> </url> </item> - <item> <id>116</id> - <title> - <![CDATA[ Popular Poker - The Popularity of Texas Hold&#39;em ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/online-poker-popularity-texas-holdem ]]> </url> </item> - <item> <id>364</id> - <title> - <![CDATA[ The Impact of Traditional Poker on Online Poker (and vice versa) ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/online-poker-tradional-vs-online ]]> </url> </item> - <item> <id>365</id> - <title> - <![CDATA[ The Ultimate, Absolute Online Poker Scandal ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/online-poker-scandal ]]> </url> </item> </items> - <items> - <item groupID="27" name="Beginners-Poker" url="/Guides/Online-Poker-Guide/Beginners-Poker/"> - <items> + <item> <id>101</id> - <title> - <![CDATA[ Poker Betting - All-in On the Flop ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/Beginners-Poker/poker-betting-all-in-on-the-flop ]]> </url> </item> + <item> <id>102</id> - <title> - <![CDATA[ Beginners&#39; Poker - Choosing an Online Poker Room ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/Beginners-Poker/beginners-poker-choosing-a-room ]]> </url> </item> + <item> <id>105</id> - <title> - <![CDATA[ Beginners&#39; Poker - Choosing What Type of Poker to Play ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/Beginners-Poker/beginners-poker-choosing-type-to-play ]]> </url> </item> + <item> <id>106</id> - <title> - <![CDATA[ Online Poker - Different Types of Online Poker ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/Beginners-Poker/online-poker ]]> </url> </item> + <item> <id>109</id> - <title> - <![CDATA[ Online Poker - Opening an Account at an Online Poker Site ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/Beginners-Poker/online-poker-opening-an-account ]]> </url> </item> + <item> <id>111</id> - <title> - <![CDATA[ Beginners&#39; Poker - Poker Glossary ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/Beginners-Poker/beginners-poker-glossary ]]> </url> </item> + <item> <id>117</id> - <title> - <![CDATA[ Poker Betting - What is a Blind? ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/Beginners-Poker/poker-betting-what-is-a-blind ]]> </url> </item> - <item> <id>118</id> - <title> - <![CDATA[ Poker Betting - What is an Ante? ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/Beginners-Poker/poker-betting-what-is-an-ante ]]> </url> </item> + <item> <id>119</id> - <title> - <![CDATA[ Beginners Poker - What is Bluffing? ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/Beginners-Poker/online-poker-what-is-bluffing ]]> </url> </item> - <item> <id>120</id> - <title> - <![CDATA[ Poker Games - What is Community Card Poker? ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/Beginners-Poker/online-poker-what-is-community-card-poker ]]> </url> </item> - <item> <id>121</id> - <title> - <![CDATA[ Online Poker - What is Online Poker? ]]> </title> - <url> - <![CDATA[ /Guides/Online-Poker-Guide/Beginners-Poker/online-poker-what-is-online-poker ]]> </url> </item> </items> </item> </items> </item> </items> </item> </items> The XSL code: <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="html" indent="yes"/> <xsl:template name="loop"> <xsl:for-each select="items/item"> <ul> <li><xsl:value-of select="@name" /></li> <xsl:if test="@name and child::node()"> <ul> <xsl:for-each select="items/item"> <li><xsl:value-of select="@name" />test</li> </xsl:for-each> </ul> <xsl:call-template name="loop" /> </xsl:if> <xsl:if test="child::node() and not(@name)"> <xsl:for-each select="/items"> <li><xsl:value-of select="id" /></li> </xsl:for-each> </xsl:if> </ul> </xsl:for-each> <xsl:for-each select="item/items/item"> <li>hi</li> </xsl:for-each> </xsl:template> <xsl:template match="/" name="test"> <xsl:call-template name="loop" /> </xsl:template> </xsl:stylesheet> Im trying to write the XSL so that every <items> node will render a <ul> and every <items> node will render an <li>. The XSL needs to be recursive because i cant tell how deep the nested nodes will go. Can anyone help? Regards, Al

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