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  • Query having 2 Where Clause

    - by Harsha M V
    i am trying to login and want to validate username and password against the records in the database. I am not sure how to pass two Where clause public Boolean login(String username, String password) throws SQLException { Cursor mCursor = db.query(TABLE_USERS, new String[] { ID, KEY_NAME, KEY_USERNAME}, KEY_USERNAME + "=" + "'"+username+"'", KEY_PASSWORD + "=" + "'"+password+"'", null, null, null, null, null); if (mCursor.moveToFirst()) { return true; } return false; } Am getting a Syntax Error.

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  • (PHP)how to hold javascript alertbox on screen

    - by Piyush
    when user changes password I want to show message "Successfully changed!" and when user clicks on OK button of alert box I call logout.php and force user to login with new password.But the problem is PHP header() is not waiting for alertbox and directly goes to logout.php. my code- if($count==1) { $sqlchange="UPDATE $tbl_name SET password='$newpassword' WHERE userId='$myusername'"; unset($result); $result=mysql_query($sqlchange,$link); if($result>0) { ?> <script type="text/javascript"> alert("Your Password has been changed successfully.Please login again."); </script> <?php header("location:logout.php"); exit; } else {....

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  • Why do i get segfault at the end of the application after everything's beed done properly ?

    - by VaioIsBorn
    #include <string.h> #include <stdlib.h> #include <stdio.h> int main(void) { unsigned char *stole; unsigned char pass[] = "m4ak47"; printf("Vnesi password: \t"); scanf("%s", stole); if(strncmp(stole, pass, sizeof(pass)) != 0) { printf("wrong password!\n"); exit(0); } else printf("Password correct\n"); printf("some stuf here...\n\n"); return 0; } This program is working nice, but with one problem - if the password is correct then it DOES do the printing of 'some stuf here...' but it also shows me segmentation fault error at the end. Why ?

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  • validation message display repeatedly

    - by Raam
    hello, in struts2, i create a simple appln.I use client side validation(using ActionClass-Validation.xml),when i get validation error it displays the message well..but a error repeatedly occur it display the old and new message again and again..how can i solve the issue? user name: xxx password error password error password : Button thankss

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  • Creating a session user login php

    - by user2419393
    I'm stuck on how to create a session for a user who logs in. I got the part of checking to make sure the log in information corresponds with the database information, but is stuck on how to take the email address and store into a session. Here is my php code below. <?php include '../View/header.php'; session_start(); require('../model/database.php'); $email = $_POST['username']; $password = $_POST['password']; $sql = "SELECT emailAddress FROM customers WHERE emailAddress ='$email' AND password = '$password'"; $result = mysql_query($sql, $db); if (!$result) { echo "DB Error, could not query the database\n"; echo 'MySQL Error: ' . mysql_error(); exit; } while ($row = mysql_fetch_assoc($result)) { echo $row['emailAddress']; } mysql_free_result($result); ?>

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  • hibernate annotation bi-directional mapping

    - by smithystar
    I'm building a web application using Spring framework and Hibernate with annotation and get stuck with a simple mapping between two entities. I'm trying to create a many-to-many relationship between User and Course. I followed one of the Hibernate tutorials and my implementation is as follows: User class: @Entity @Table(name="USER") public class User { private Long id; private String email; private String password; private Set<Course> courses = new HashSet<Course>(0); @Id @GeneratedValue @Column(name="USER_ID") public Long getId() { return id; } public void setId(Long id) { this.id = id; } @Column(name="USER_EMAIL") public String getEmail() { return email; } public void setEmail(String email) { this.email = email; } @Column(name="USER_PASSWORD") public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } @ManyToMany(cascade = CascadeType.ALL) @JoinTable(name = "USER_COURSE", joinColumns = { @JoinColumn(name = "USER_ID") }, inverseJoinColumns = { @JoinColumn(name = "COURSE_ID") }) public Set<Course> getCourses() { return courses; } public void setCourses(Set<Course> courses) { this.courses = courses; } } Course class: @Entity @Table(name="COURSE") public class Course { private Long id; private String name; @Id @GeneratedValue @Column(name="COURSE_ID") public Long getId() { return id; } public void setId(Long id) { this.id = id; } @Column(name="NAME") public String getName() { return name; } public void setName(String name) { this.name = name; } } The problem is that this implementation only allows me to go one way user.getCourses() What do I need to change, so I can go in both directions? user.getCourses() course.getUsers() Any help would be appreciated.

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  • ios - how do I concatinate strings to create a url?

    - by GeekedOut
    I am trying to make a url by first collecting the parameters, and then in one statement creating the actual url. Here is what I am trying to do: NSString *urlString = @"http://www.some_login_url.com?email=%@&password=%@"; NSString *email = self.email.text; NSString *password = self.password.text; NSString *url_to_send = [NSString stringWithFormat:@"%@%@", urlString , email , password]; So what I wanted to do was replace the @ symbols with the values in the variables, but instead the second variable just got appended to the end of the string. How would I change the last line so I could put the right parameters in their correct spots? Thanks!!

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  • SFTP in Python? (platform independent)

    - by Mark Wilbur
    I'm working on a simple tool that transfers files to a hard-coded location with the password also hard-coded. I'm a python novice, but thanks to ftplib, it was easy: import ftplib info= ('someuser', 'password') #hard-coded def putfile(file, site, dir, user=(), verbose=True): """ upload a file by ftp to a site/directory login hard-coded, binary transfer """ if verbose: print 'Uploading', file local = open(file, 'rb') remote = ftplib.FTP(site) remote.login(*user) remote.cwd(dir) remote.storbinary('STOR ' + file, local, 1024) remote.quit() local.close() if verbose: print 'Upload done.' if __name__ == '__main__': site = 'somewhere.com' #hard-coded dir = './uploads/' #hard-coded import sys, getpass putfile(sys.argv[1], site, dir, user=info) The problem is that I can't find any library that supports sFTP. What's the normal way to do something like this securely? Edit: Thanks to the answers here, I've gotten it working with Paramiko and this was the syntax. import paramiko host = "THEHOST.com" #hard-coded port = 22 transport = paramiko.Transport((host, port)) password = "THEPASSWORD" #hard-coded username = "THEUSERNAME" #hard-coded transport.connect(username = username, password = password) sftp = paramiko.SFTPClient.from_transport(transport) import sys path = './THETARGETDIRECTORY/' + sys.argv[1] #hard-coded localpath = sys.argv[1] sftp.put(localpath, path) sftp.close() transport.close() print 'Upload done.' Thanks again!

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  • [PersistenceException: org.hibernate.exception.SQLGrammarException: could not execute query]

    - by doniyor
    i need help. i am trying to select from database thru sql statement in play framework, but it gives me error, i cannot figure out where the clue is. here is the code: @Transactional public static Users findByUsernameAndPassword(String username, String password){ String hash = DigestUtils.md5Hex(password); Query q = JPA.em().createNativeQuery("select * from USERS where" + "USERNAME=? and PASSWORD=?").setParameter(1, username).setParameter(2, password); List<Users> users = q.getResultList(); if(users.isEmpty()){ return null; } else{ return users.get(0); here is the eror message: [PersistenceException: org.hibernate.exception.SQLGrammarException: could not execute query] can someone help me please! any help i would appreciate! thanks

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  • write to xml file using objective c

    - by Mith
    Hi, ok, I managed to read from xml file using NSXMLParser but now i don't know how to write to xml file. I have a xml file , say <?xml version="1.0" encoding="UTF-8"?> <root> <user id="abcd" password="pass1"/> <user id="efg" password="pass2"/> </root> Now when a new user enters details, I want to store them in a new tag.. lets say like, the id is "hhhh" and password is"pass3" I want to add a new tag with attributes as such <user id="hhhh" password="pass3"/> to the xml file. How should I do this. Please explain in an elaborate way . I am a newbie here. Any links to tutorials or examples will be much helpful. Thanks

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  • how to listen to Enter button when using JOptionPane.showOptionDialog

    - by MemoryLeak
    I use: char[] password = null; JPasswordField jpf = new JPasswordField(30); java.lang.Object [] messageInput = { prompt, jpf }; java.lang.Object [] options = { jpf , "OK", "Cancel"}; int result = JOptionPane.showOptionDialog(null, messageInput, title, JOptionPane.OK_CANCEL_OPTION, JOptionPane.QUESTION_MESSAGE, null, options, ""); JOptionPane.showMessageDialog(null, result); if (result == 1) { password = jpf.getPassword(); } else if(result == JOptionPane.CANCEL_OPTION) { } return password; to get password, but this can not listen to the Enter button. I know if I set the options parameter to null, can make the dialog listen to "enter" button, but if I do that, the dialog don't focus to the textbox when show up. Can someone help me on this ? Thanks in advance !

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  • How to disconnect an existing ruby sequel connection to a database?

    - by MG
    I mean the one which was previously established as DB = Sequel.sqlite('my_blog.db') or DB = Sequel.connect('postgres://user:password@localhost/my_db') or DB = Sequel.postgres('my_db', :user => 'user', :password => 'password', :host => 'localhost') or etcetera. The Sequel::Database class has no public instance method called "disconnect" or so though it has "connect" one. Maybe somebody already faced that problem. I would appreciate any idea.

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  • Java AD Authentication across Trusted Domains

    - by benjiisnotcool
    I am trying to implement Active Directory authentication in Java which will be ran from a Linux machine. Our AD set-up will consist of multiple servers that share trust relationships with one another so for our test environment we have two domain controllers: test1.ad1.foo.com who trusts test2.ad2.bar.com. Using the code below I can successfully authenticate a user from test1 but not on test2: public class ADDetailsProvider implements ResultSetProvider { private String domain; private String user; private String password; public ADDetailsProvider(String user, String password) { //extract domain name if (user.contains("\\")) { this.user = user.substring((user.lastIndexOf("\\") + 1), user.length()); this.domain = user.substring(0, user.lastIndexOf("\\")); } else { this.user = user; this.domain = ""; } this.password = password; } /* Test from the command line */ public static void main (String[] argv) throws SQLException { ResultSetProvider res = processADLogin(argv[0], argv[1]); ResultSet results = null; res.assignRowValues(results, 0); System.out.println(argv[0] + " " + argv[1]); } public boolean assignRowValues(ResultSet results, int currentRow) throws SQLException { // Only want a single row if (currentRow >= 1) return false; try { ADAuthenticator adAuth = new ADAuthenticator(); LdapContext ldapCtx = adAuth.authenticate(this.domain, this.user, this.password); NamingEnumeration userDetails = adAuth.getUserDetails(ldapCtx, this.user); // Fill the result set (throws SQLException). while (userDetails.hasMoreElements()) { Attribute attr = (Attribute)userDetails.next(); results.updateString(attr.getID(), attr.get().toString()); } results.updateInt("authenticated", 1); return true; } catch (FileNotFoundException fnf) { Logger.getAnonymousLogger().log(Level.WARNING, "Caught File Not Found Exception trying to read cris_authentication.properties"); results.updateInt("authenticated", 0); return false; } catch (IOException ioe) { Logger.getAnonymousLogger().log(Level.WARNING, "Caught IO Excpetion processing login"); results.updateInt("authenticated", 0); return false; } catch (AuthenticationException aex) { Logger.getAnonymousLogger().log(Level.WARNING, "Caught Authentication Exception attempting to bind to LDAP for [{0}]", this.user); results.updateInt("authenticated", 0); return true; } catch (NamingException ne) { Logger.getAnonymousLogger().log(Level.WARNING, "Caught Naming Exception performing user search or LDAP bind for [{0}]", this.user); results.updateInt("authenticated", 0); return true; } } public void close() { // nothing needed here } /** * This method is called via a Postgres function binding to access the * functionality provided by this class. */ public static ResultSetProvider processADLogin(String user, String password) { return new ADDetailsProvider(user, password); } } public class ADAuthenticator { public ADAuthenticator() throws FileNotFoundException, IOException { Properties props = new Properties(); InputStream inStream = this.getClass().getClassLoader(). getResourceAsStream("com/bar/foo/ad/authentication.properties"); props.load(inStream); this.domain = props.getProperty("ldap.domain"); inStream.close(); } public LdapContext authenticate(String domain, String user, String pass) throws AuthenticationException, NamingException, IOException { Hashtable env = new Hashtable(); this.domain = domain; env.put(Context.INITIAL_CONTEXT_FACTORY, com.sun.jndi.ldap.LdapCtxFactory); env.put(Context.PROVIDER_URL, "ldap://" + test1.ad1.foo.com + ":" + 3268); env.put(Context.SECURITY_AUTHENTICATION, simple); env.put(Context.REFERRAL, follow); env.put(Context.SECURITY_PRINCIPAL, (domain + "\\" + user)); env.put(Context.SECURITY_CREDENTIALS, pass); // Bind using specified username and password LdapContext ldapCtx = new InitialLdapContext(env, null); return ldapCtx; } public NamingEnumeration getUserDetails(LdapContext ldapCtx, String user) throws NamingException { // List of attributes to return from LDAP query String returnAttributes[] = {"ou", "sAMAccountName", "givenName", "sn", "memberOf"}; //Create the search controls SearchControls searchCtls = new SearchControls(); searchCtls.setReturningAttributes(returnAttributes); //Specify the search scope searchCtls.setSearchScope(SearchControls.SUBTREE_SCOPE); // Specify the user to search against String searchFilter = "(&(objectClass=*)(sAMAccountName=" + user + "))"; //Perform the search NamingEnumeration answer = ldapCtx.search("dc=dev4,dc=dbt,dc=ukhealth,dc=local", searchFilter, searchCtls); // Only care about the first tuple Attributes userAttributes = ((SearchResult)answer.next()).getAttributes(); if (userAttributes.size() <= 0) throw new NamingException(); return (NamingEnumeration) userAttributes.getAll(); } From what I understand of the trust relationship, if trust1 receives a login attempt for a user in trust2, then it should forward the login attempt on to it and it works this out from the user's domain name. Is this correct or am I missing something or is this not possible using the method above? --EDIT-- The stack trace from the LDAP bind is {java.naming.provider.url=ldap://test1.ad1.foo.com:3268, java.naming.factory.initial=com.sun.jndi.ldap.LdapCtxFactory, java.naming.security.authentication=simple, java.naming.referral=follow} 30-Oct-2012 13:16:02 ADDetailsProvider assignRowValues WARNING: Caught Authentication Exception attempting to bind to LDAP for [trusttest] Auth error is [LDAP: error code 49 - 80090308: LdapErr: DSID-0C0903A9, comment: AcceptSecurityContext error, data 52e, v1db0]

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  • Beginner Android Dev question navigating through intents, getting errors not sure how to fix it. I've tried rearranging and everything even tabbing.

    - by user554786
    /*I created this Sign-In page. I start by declaring variables for username/password & buttons. If user enters "test" as username & "test" as password and hits the login button, its supposed to go to the DrinksTwitter.class activity, else throw error message I created. To me the code and login makes perfect sense. I'm not sure why it wont go to the next activity I want it to go to */ package com.android.drinksonme; import android.app.Activity; import android.content.Intent; import android.os.Bundle; import android.view.View; import android.view.View.OnClickListener; import android.widget.Button; import android.widget.EditText; import android.widget.TextView; public class Screen2 extends Activity { // Declare our Views, so we can access them later private EditText etUsername; private EditText etPassword; private Button btnLogin; private Button btnSignUp; private TextView lblResult; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); // Get the EditText and Button References etUsername = (EditText)findViewById(R.id.username); etPassword = (EditText)findViewById(R.id.password); btnLogin = (Button)findViewById(R.id.login_button); btnSignUp = (Button)findViewById(R.id.signup_button); lblResult = (TextView)findViewById(R.id.result); // Check Login String username = etUsername.getText().toString(); String password = etPassword.getText().toString(); if(username.equals("test") && password.equals("test")){ final Intent i = new Intent(Screen2.this, DrinksTwitter.class); btnLogin.setOnClickListener(new OnClickListener() { public void onClick(View v) { startActivity(i); } // lblResult.setText("Login successful."); else { /* ERROR- Syntax error on token "else", { expected */ lblResult.setText("Invalid username or password."); } } }); final Intent k = new Intent(Screen2.this, SignUp.class); btnSignUp.setOnClickListener(new OnClickListener() { public void onClick(View v) { startActivity(k); } }); /* ERROR- Syntax error, insert "}" to complete Statement*/ } }

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  • Knowing the user name in a Page

    - by ctacke
    Let's assume the following: I have an IIS web site set up IIS is configured to use Digest authentication I'm running an ASP.NET page The page has a code-behing assembly that overrides Page_Load When a user navigates to that page, I get a security prompt for the username and password. If the username and password are invalid (i.e. incorrect password) is there a way for the called page, in Page_Load to know, or does IIS handle this and return the 401 before the ASP.NET engine ever gets around to resolving the actual Page class that will get executed?

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  • How to detect invalid user input in a Batch File?

    - by user2975367
    I want to use a batch file to ask for a password to continue, i have very simple code that works. @echo off :Begin cls echo. echo Enter Password set /p pass= if %pass%==Password goto Start :Start cls echo What would you like me to do? (Date/Chrome/Lock/Shutdown/Close) set /p task= if %task%==Date goto Task=Date if %task%==Chrome goto Task=Chrome if %task%==Lock goto Task=Lock if %task%==Shutdown goto Task=Shutdown if %task%==Close goto Task=Close I need to detect when the user entered an invalid password, i have spent an hour researching but i found nothing. I'm not advanced in any way so try and keep it very simple like the code above. Please help me.

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  • How to use the values from session variables in jsp pages that got saved using @Scope("session") in the mvc controllers

    - by droidsites
    Doing a web site using spring mvc. I added a SignupController to handle all the sign up related requests. Once user signup I am adding that to a session using @Scope("session"). Below is the SignupController code, SignupController.java @Controller @Scope("session") public class SignupController { @Autowired SignupServiceInter signUpService; private static final Logger logger = Logger.getLogger(SignupController.class); private String sessionUser; @RequestMapping("/SignupService") public ModelAndView signUp(@RequestParam("userid") String userId, @RequestParam("password") String password,@RequestParam("mailid") String emailId){ logger.debug(" userId:"+userId+"::Password::"+password+"::"); String signupResult; try { signUpService.registerUser(userId, password,emailId); sessionUser = userId; //adding the sign up user to the session return new ModelAndView("userHomePage","loginResult","Success"); //Navigate to user Home page if everything goes right } catch (UserExistsException e) { signupResult = e.toString(); return new ModelAndView("signUp","loginResult", signupResult); //Navigate to signUp page back if user does not exist } } } I am using "sessionUser" variable to store the signed up User Id. My understanding is that when I use @Scope("session") for the controller all the instance variables will added to HttpSession. So by that understanding I tried to access this "SessionUser" in userHomePage.jsp as, userHomepage.jsp Welcome to <%=session.getAttribute("sessionUser")%> But it throws null. So my question is how to use the values from session variables in jsp pages that got saved using @Scope("session") in the mvc controllers. Note: My work around is that pass that signed User Id to jsp page through ModelAndView, but it seems passing the value like these among the pages takes me back to managing state among pages using QueryStrings days.

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  • JQuery tab Selection problem?

    - by PeAk
    New to JQuery and I was wondering how do I keep any tabbed selected when a user reloads the web page? What part of my code do I need to change? Here is my JQuery code. $(document).ready(function() { //When page loads... $(".form-content").hide(); //Hide all content var firstMenu = $("#home-menu ul li:first"); firstMenu.show(); firstMenu.find("a").addClass("selected-link"); //Activate first tab $(".form-content:first").show(); //Show first tab content //On Click Event $("#home-menu ul li").click(function() { $("#home-menu ul li a").removeClass("selected-link"); //Remove any "selected-link" class $(this).find("a").addClass("selected-link"); //Add "selected-link" class to selected tab $(".form-content").hide(); //Hide all tab content var activeTab = $(this).find("a").attr("href"); //Find the href attribute value to identify the selected-link tab + content $(activeTab).fadeIn(); //Fade in the selected-link ID content return false; }); }); Here is the XHTML code. <div id="home-menu"> <ul> <li><a href="#personal-info-form" title="Personal Info Form Link">Personal Info</a></li> <li><a href="#contact-info-form" title="Contact Info Form Link">Contact Info</a></li> </ul> </div> <div> <div id="personal-info-form" class="form-content"> <h2>Personal Information</h2> <form method="post" action="index.php"> <fieldset> <ul> <li><label for="first_name">First Name: </label><input type="text" name="first_name" id="first_name" size="25" class="input-size" value="<?php if(!empty($first_name)){ echo $first_name; } ?>" /></li> <li><label for="middle_name">Middle Name: </label><input type="text" name="middle_name" id="middle_name" size="25" class="input-size" value="<?php if(!empty($middle_name)){ echo $middle_name; } ?>" /></li> <li><label for="last_name">Last Name: </label><input type="text" name="last_name" id="last_name" size="25" class="input-size" value="<?php if(!empty($last_name)){ echo $last_name; } ?>" /></li> <li><label for="password-1">Password: </label><input type="password" name="password1" id="password-1" size="25" class="input-size" /></li> <li><label for="password-2">Confirm Password: </label><input type="password" name="password2" id="password-2" size="25" class="input-size" /></li> <li><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form> </div> <div id="contact-info-form" class="form-content"> <h2>Contact Information</h2> <form method="post" action="index.php" id="contact-form"> <fieldset> <ul> <li><label for="address">Address 1: </label><input type="text" name="address" id="address" size="25" class="input-size" value="<?php if (isset($_POST['address'])) { echo $_POST['address']; } else if(!empty($address)) { echo $address; } ?>" /></li> <li><label for="address_two">Address 2: </label><input type="text" name="address_two" id="address_two" size="25" class="input-size" value="<?php if (isset($_POST['address_two'])) { echo $_POST['address_two']; } else if(!empty($address_two)) { echo $address_two; } ?>" /></li> <li><label for="city_town">City/Town: </label><input type="text" name="city_town" id="city_town" size="25" class="input-size" value="<?php if (isset($_POST['city_town'])) { echo $_POST['city_town']; } else if(!empty($city_town)) { echo $city_town; } ?>" /></li> <li><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="hidden" name="contact_info_submitted" value="true" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form> </div> </div>

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  • Noob question about hibernate criteria

    - by Dimitri
    Hello, I have a class called User which has 2 properties : login/password. I am trying to authenticate a user in my application using hibernate criteria but my request doesn't work. [EDIT] The returned value is NULL. I have two users in my database for testing. Here is my code : @Override public User authenticate(String login, String password) throws NullPointerException { Session session = this.getSession(); User user = (User) session .createCriteria(User.class) .add( Restrictions.and( Property.forName("login").eq(login), Property.forName("password").eq(password) )).uniqueResult(); if (user == null){ throw new NullPointerException("User not found"); } return user; } Can someone tells me what is wrong with my code? Happy new Year 2011 !!

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  • Resetting passwords without emailing the user

    - by Cory
    We need to provide a way to reset password for users who are using our website. The typical way is to send email to the user and ask to click on the link to reset. The issue is that we don't want to run a mail server just for the purpose of resetting password. Is there other clever way of reseting password without having to mail the user?

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  • Is this the right way of handling command line arguments?

    - by shadyabhi
    ask_username = True ask_password = True ask_message = True ask_number = True def Usage(): print '\t-h, --help: View help' print '\t-u, --username: Username' print '\t-p, --password: Password' print '\t-n, --number: numbber to send the sms' print '\t-m, --message: Message to send' sys.exit(1) opts, args = getopt(sys.argv[1:], 'u:p:m:n:h',["username=","password=","message=","number=","help"]) print opts, args for o,v in opts: if o in ("-h", "--help"): Usage() elif o in ("-u", "--username"): username = v ask_username = False elif o in ("-p", "--password"): passwd = v ask_password = False elif o in ("-m", "--message"): message = v ask_message = False elif o in ("-n", "--number"): number = v ask_number = False #Credentials taken here if ask_username: username = raw_input("Enter USERNAME: ") if ask_password: passwd = getpass() if ask_message: message = raw_input("Enter Message: ") if ask_number: number = raw_input("Enter Mobile number: ") I dont think it is, because I am using 4 objects just for checking if command line argument was provided... Guide me with the best way of doing it..

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  • iPhone: trouble with wrong credentials

    - by user331396
    I am writing an iPhone App that uses a HTTPS/SOAP service which needs user credentials. After I change the password used for these credentials from a valid to an invalid one I still get a valid response from the service, as if the password was never changed. When I restart the app (with the invalid password) the app immediately receives the expected '401' message. Any hints what I might left out to code? Thx :)

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  • [Linq to sql] query result what should i use Count() or Any()...

    - by Pandiya Chendur
    I am checking login of a user by this repository method, public bool getLoginStatus(string emailId, string password) { var query = from r in taxidb.Registrations where (r.EmailId == emailId && r.Password==password) select r; if (query.Count() != 0) { return true; } return false; } I saw in one of the previous questions !query.Any() would be faster... Which should i use? Any suggestion....

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  • Rewrite inline javascript into jQuery

    - by cf_PhillipSenn
    How do I rewrite this using jQuery instead of the onchange event? <input name="PasswordName" type="password" id="passwordID"> <p> <input type="checkbox" onchange="document.getElementById('passwordID').type = this.checked ? 'text' : 'password'"> Show Password </p>

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