Search Results

Search found 10747 results on 430 pages for 'password'.

Page 97/430 | < Previous Page | 93 94 95 96 97 98 99 100 101 102 103 104  | Next Page >

  • Trouble making login page?

    - by Ken
    Okay, so I want to make a simple login page. I've created a register page successfully, but i can't get the login thing down. login.php: <?php session_start(); include("mainmenu.php"); $usrname = mysql_real_escape_string($_POST['usrname']); $password = md5($_POST['password']); $con = mysql_connect("localhost", "root", "g00dfor@boy"); if(!$con){ die(mysql_error()); } mysql_select_db("users", $con) or die(mysql_error()); $login = "SELECT * FROM `users` WHERE (usrname = '$usrname' AND password = '$password')"; $result = mysql_query($login); if(mysql_num_rows($result) == 1 { $_SESSION = true; header('Location: indexlogin.php'); } else { echo = "Wrong username or password." ; } ?> indexlogin.php just echoes "Login successful." What am I doing wrong? Oh, and just FYI- my database is "users" and my table is "data".

    Read the article

  • PAM authentication problem

    - by mdipierro
    I am using this module to authenticate using pam: http://code.google.com/p/web2py/source/browse/gluon/contrib/pam.py I can call authenticate('username','password') and it returns True/ False. It works for any 'username' but 'root'. My guess is that there is a security restriction in PAM that does not allow to check for the root password. I need to be able to check the root password. Is there anything I can change in the pam.conf or somewhere else to remove this restriction?

    Read the article

  • Search and replace

    - by zx
    Hi, I have a really large SQL dump around 400MB. It's in the following format, "INSERT INTO user VALUES('USERID', 'USERNAME', 'PASSWORD', '0', '0', 'EMAIL', 'GENDER', 'BIRTHDAY', '182', '13', '640', 'Married', 'Straight', '', 'Yes', 'Yes', '1146411153', '1216452123', '1149440844', '0', picture', '1', '0', '0', 'zip', '0', '', '0', '', '', '0')" Is there anyway I can just get the email and password out from that, I want to import the users into another table. Anyone know how I can do this and just get email-password stripped out from that content? Thank you in advance

    Read the article

  • How to prevent PHP variables from being arrays?

    - by MJB
    I think that (the title) is the problem I am having. I set up a MySQL connection, I read an XML file, and then I insert those values into a table by looping through the elements. The problem is, instead of inserting only 1 record, sometimes I insert 2 or 3 or 4. It seems to depend on the previous values I have read. I think I am reinitializing the variables, but I guess I am missing something -- hopefully something simple. Here is my code. I originally had about 20 columns, but I shortened the included version to make it easier to read. $ctr = 0; $sql = "insert into csd (id,type,nickname,hostname,username,password) ". "values (?,?,?,?,?,?)"; $cur = $db->prepare($sql); for ($ctr = 0; $ctr < $expected_count; $ctr++) { list ( $lbl, $type, $nickname, $hostname, $username, $password) = ""; $bind_vars = array(); $lbl = "csd_{$ctr}"; $type = $ref->itm->csds->$lbl->type; $nickname = $ref->itm->csds->$lbl->nickname; $hostname = $ref->itm->csds->$lbl->hostname; $username = $ref->itm->csds->$lbl->username; $password = $ref->itm->csds->$lbl->password; $bind_vars = array($id,$type,$nickname,$hostname,$username,$password); $res = $db->execute($cur, $bind_vars); # this is a separate function which works, but which only # does SELECTS and cannot be the problem. I include it because I # want to count the total rows. printf ("%d CSDs on that ITEM now.\n", CountCSDs($id_to_sync)); } P.S. I also tagged this SimpleXML because that is how I am reading the file, though that code is not included above. It looks like this: $Ref = simplexml_load_file($file);

    Read the article

  • Asp.net membership salt?

    - by chobo2
    Hi Does anyone know how Asp.net membership generates their salt key and then how they encode it(ie is it salt + password or password + salt)? I am using sha1 with my membership but I would like to recreate the same salts so the built in membership stuff could hash the stuff the same way as my stuff can. Thanks Edit 2 Never Mind I mis read it and was thinking it said bytes not bit. So I was passing in 128 bytes not 128bits. Edit I been trying to make it so this is what I have public string EncodePassword(string password, string salt) { byte[] bytes = Encoding.Unicode.GetBytes(password); byte[] src = Encoding.Unicode.GetBytes(salt); byte[] dst = new byte[src.Length + bytes.Length]; Buffer.BlockCopy(src, 0, dst, 0, src.Length); Buffer.BlockCopy(bytes, 0, dst, src.Length, bytes.Length); HashAlgorithm algorithm = HashAlgorithm.Create("SHA1"); byte[] inArray = algorithm.ComputeHash(dst); return Convert.ToBase64String(inArray); } private byte[] createSalt(byte[] saltSize) { byte[] saltBytes = saltSize; RNGCryptoServiceProvider rng = new RNGCryptoServiceProvider(); rng.GetNonZeroBytes(saltBytes); return saltBytes; } So I have not tried to see if the asp.net membership will recognize this yet the hashed password looks close. I just don't know how to convert it to base64 for the salt. I did this byte[] storeSalt = createSalt(new byte[128]); string salt = Encoding.Unicode.GetString(storeSalt); string base64Salt = Convert.ToBase64String(storeSalt); int test = base64Salt.Length; Test length is 172 what is well over the 128bits so what am I doing wrong? This is what their salt looks like vkNj4EvbEPbk1HHW+K8y/A== This is what my salt looks like E9oEtqo0livLke9+csUkf2AOLzFsOvhkB/NocSQm33aySyNOphplx9yH2bgsHoEeR/aw/pMe4SkeDvNVfnemoB4PDNRUB9drFhzXOW5jypF9NQmBZaJDvJ+uK3mPXsWkEcxANn9mdRzYCEYCaVhgAZ5oQRnnT721mbFKpfc4kpI=

    Read the article

  • protecting my web page and folder from external using .htaccess and .htpassword in php

    - by Testadmin
    Hai I want to protect a folder (protect) and the files inside that folder. I have created a .htaccess file and put the following code. AuthName "Myfolder" AuthType Basic AuthUserFile url/protect/.htpasswd Require valid-user Also created a .htpassword file which contain username:password When I run my URL http://localhost/url/protect, I got a pop up asking username and password, I entered username as username and password as password. After that I got an error page "server error 500" "The server encountered an internal error and was unable to complete your request. Either the server is overloaded or there was an error in a CGI script. If you think this is a server error, please contact the webmaster." Why this happened?. Any thing wrong here? Anything needs to see my pages under the folder. Please give me the answer.

    Read the article

  • Authentication from url in Restlet

    - by DutrowLLC
    I've been using Restlets "ChallengeResponse" mechanism to authenticate users so far. ChallengeResponse challengeResponse = getRequest().getChallengeResponse(); if( challengeResponse == null ){ throw new RuntimeException("not authenticated"); } String login = challengeResponse.getIdentifier(); String password = new String(challengeResponse.getSecret()); From my understanding, "ChallengeResponse" requires that the username and password are put into headers. However a client needs to put the credentials into the url like so: https://username:[email protected]/my_secure_document When I looked at what was actually sent, it looks like the password is being hashed. What is the proper way to authenticate in this fashion using Restlet?

    Read the article

  • Setting a profile property in asp.net MVC while creating a user.

    - by twal
    In my application, an authorized user will Register a new customer and set their username and password, etc. The customer will not be registering them self. I have the following code in a class file which creates the new user, and it works just fine. public MembershipCreateStatus CreateUser(string userName, string password, string email, string employeeID) { if (String.IsNullOrEmpty(userName)) throw new ArgumentException("Value cannot be null or empty.", "userName"); if (String.IsNullOrEmpty(password)) throw new ArgumentException("Value cannot be null or empty.", "password"); if (String.IsNullOrEmpty(email)) throw new ArgumentException("Value cannot be null or empty.", "email"); MembershipCreateStatus status; /// _membershipProvider.CreateUser("asdas","ds123BB", email, "asdasd", "asdasdad", true, null, out status); _membershipProvider.CreateUser(userName, password, email, null, null, true, null, out status); string answer = status.ToString(); return status; } However I would also like to set an employeeID property for the profile when creating this user. how would I set the EmployeeID when creating a new user?? Thanks

    Read the article

  • cakephp phone number validation

    - by hellosheikh
    i am new to cakephp 2.x so i dont know how to do this .. i want to login the user from his email address and phone number..what my intention is if the number in database is this "12345" and the user is trying to login through this number "+12345" he can be login into the system.. i have written a code but i dont know how can i use this or to adjust my code within the auth component as the auth component is autometically logging the user .. here is my controller public function beforeFilter() { parent::beforeFilter(); $this->Auth->authenticate = array( 'Authenticate.Cookie' => array( 'fields' => array( 'username' => 'email', 'password' => 'password' ), 'userModel' => 'User', 'scope' => array('User.active' => 1) ), 'Authenticate.MultiColumn' => array( 'fields' => array( 'username' => 'email', 'password' => 'password' ), 'columns' => array('email', 'mobileNo'), 'userModel' => 'User', ) ); } public function login() { if ($this->Auth->login() || $this->Auth->loggedIn()) { $this->redirect('/users/dashboard'); }else{ $this->layout='logindefault'; $this->set('title_for_layout', 'Account Login'); /*$this->Auth->logout(); $cookie = $this->Cookie->read('Auth.User'); */ if ($this->request->is('post')) { if ($this->Auth->login() || $this->Auth->loggedIn()) { if ($this->Session->check('Auth.User')){ $this->_setCookie($this->Auth->user('idUser')); $this->redirect('/users/dashboard'); } }else { $this->Session->setFlash('Incorrect Email/Password Combination'); } }} } here is the code which i am trying to add .. $mobileNo='+123456789'; if (strpos($mobileNo,'+') !== false) { $mobileNo=str_replace("+", "",$mobileNo); } ?

    Read the article

  • Ajax success function firing before java class responds

    - by user1899281
    I am creating a login function with ajax and am having an issue where the success function (SuccessLogin) fires before getting an ajax response. I am running the code as google web app from eclipse and I can see when debugging the java class file, that the javascript is throwing an alert for the success response from the class being false before the debugger catches the break point in the class file. I have only been writing code for a couple months now so I am sure its a stupid little error on my part. $(document).ready(function() { sessionChecker() // sign in $('#signInForm').click(function () { $().button('loading') var email = $('#user_username').val(); sessionStorage.email = $('#user_username').val(); var password= $('#user_password').val(); var SignInRequest = { type: "UserLoginRequest", email: email, password: password } var data= JSON.stringify(SignInRequest); //disabled all the text fields $('.text').attr('disabled','true'); //start the ajax $.ajax({ url: "/resources/user/login", type: "POST", data: data, cache: false, success: successLogin(data) }); }); //if submit button is clicked $('#Register').click(function () { $().button('loading') var email = $('#email').val(); if ($('#InputPassword').val()== $('#ConfirmPassword').val()) { var password= $('input[id=InputPassword]').val(); } else {alert("Passwords do not match"); return ;} var UserRegistrationRequest = { type: "UserRegistrationRequest", email: email, password: password } var data= JSON.stringify(UserRegistrationRequest); //disabled all the text fields $('.text').attr('disabled','true'); //start the ajax $.ajax({ url: "/resources/user/register", type: "POST", data: data, cache: false, success: function (data) { if (data.success==true) { //hide the form $('form').fadeOut('slow'); //show the success message $('.done').fadeIn('slow'); } else alert('data.errorReason'); } }); return false; }); }); function successLogin (data){ if (data.success) { sessionStorage.userID= data.userID var userID = data.userID sessionChecker(userID); } else alert(data.errorReason); } //session check function sessionChecker(uid) { if (sessionStorage.userID!= null){ var userID = sessionStorage.userID }; if (userID != null){ $('#user').append(userID) $('#fat-menu_1').fadeOut('slow') $('#fat-menu_2').append(sessionStorage.email).fadeIn('slow') }; }

    Read the article

  • Zend Framework :: Is this code good for user login (Its begining- because that I want to know if its

    - by Yosef
    Hi, I new in Zend. Main Question: Is this code good for user login (Its beginning- because that I want to know if its can be improve)? Code understanding question: Is every time that in action call to his view- code execution in action not going to next row until view request? (I asking about IndexAction that I write down) Thanks view index.phtml <? echo $this->form controller IndexAction.php public function indexAction() { $form=new Application_Form_Login(); $this->view->form = $form; if ($this->getRequest()->isPost()) { $formData = $this->getRequest()->getPost(); if ($form->isValid($formData)) { echo " test value username: ".$form->getValue('username'); } } } form Login.php public function init() { $this->setMethod('post'); $this->setName('user login'); $username = new Zend_Form_Element_Text('username'); $username->setLabel("username") ->setRequired(true) ->addFilter('StripTags') ->addFilter('StringTrim') ->addValidator('NotEmpty'); $password = new Zend_Form_Element_Password('password'); $password->setLabel('password') ->setRequired(true) ->addFilter('StripTags') ->addFilter('StringTrim') ->addValidator('NotEmpty'); $submit = new Zend_Form_Element_Submit('submit'); $this->addElements(array($username, $password, $submit)); }

    Read the article

  • Alloy MVC Framework Titanium Network (Model)

    - by flyingDuck
    I'm trying to authenticate using the Model in Alloy. I have been trying to figure this problem out since yesterday. If anybody could help me, I'd really appreciate it. So, I have a view login.xml, then a controller login.js. The login.js contains the following function: var user = Alloy.Models.user; //my user.js model function login(e) { if($.username.value !== '' && $.password.value !== ''){ if(user.login($.username.value, $.password.value)){ Alloy.createController('home').getView().open(); $.login.close(); } }else{ alert('Username and/or Password required!'); } } Then in my user.js model, it's like this: extendModel : function(Model) { _.extend(Model.prototype, { login: function(username, password) { var first_name, last_name, email; var _this = this; var url = 'http://myurl.com/test.php'; var auth = Ti.Network.createHTTPClient({ onerror: function(e){ alert(e.error); }, onload: function(){ var json = this.responseText; var response = JSON.parse(json); if(response.logged == true){ first_name = response.f_name; last_name = response.l_name; email = response.email; _this.set({ loggedIn: 1, username: email, realname: first_name + ' ' + last_name, email: email, }); _this.save(); }else{ alert(response.message); } }, }); auth.open('POST', url); var params = { usernames: username, passwords: password, }; auth.send(params); alert(_this.get('email')); //alert email }, }); When I click on login in login.xml it calls the function login in index.js. So, now my problem is that, when I click the button for the first time, I get an empty alert from alert(_this.get('email')), but then when I click the button the second time, everything works fine, it alerts the email. I have no idea what's going on. Thank you for the help.

    Read the article

  • Automatic authentication in PHPMyAdmin

    - by Konstantin
    Hello! I have a local phpMyAdmin (installed via apt-get) adn I'm tired of entering login and password every time I try to open it. Database contains no sensitive info, just test tables, and is visible only from 127.0.0.1 I want phpMyAdmin already be logged in as root user with password 1234 (for example) when I open it. How do I do that? P.S. Saving password in a browser is not what I want.

    Read the article

  • Convery MSSQL Varbinary field to MYSQL, keeping data intact

    - by Mike Sheridan
    I was given the dawnting task of converting a ASP website to PHP and MSSQL to MySQL, and I ran into an issue that hopefully somebody can help I have a user table which has a password field with datatype Varbinary(128), are using pwdencrypt to encrypt the password. Is there a way to transfer that over to MySQL, and somehow i need to be able to keep the password intact... how can i go about that? any pointers would be greatly appreciated!

    Read the article

  • is it safe to call "plink.exe" in an application

    - by EBAGHAKI
    i want to use "plink.exe -u username -pw securepassword" on my windows visual c++ program. will username and password remain safe while calling this command? I mean can a hacker steal or sniff the username and password? (consider hacker can't get to the password directly from the exe file)

    Read the article

  • function fetch() on a non-object problem

    - by shin
    I have this url, http://webworks.net/ww.incs/forgotten-password-verification.php?verification_code=974bf747124c69f12ae3b36afcaccc68&[email protected]&redirect=/ww.admin/index.php And this gives the following error. Fatal error: Call to a member function fetch() on a non-object in /var/www/webworks/ww.incs/basics.php on line 23 Call Stack: 0.0005 338372 1. {main}() /var/www/webworks/ww.incs/forgotten-password-verification.php: 0 0.0020 363796 2. dbRow() /var/www/webworks/ww.incs/forgotten-password-verification.php:18 The forgotten-password-verification.php require 'login-libs.php'; login_check_is_email_provided(); // check that a verification code was provided if( !isset($_REQUEST['verification_code']) || $_REQUEST['verification_code']=='' ){ login_redirect($url,'novalidation'); } // check that the email/verification code combination matches a row in the user table // $password=md5($_REQUEST['email'].'|'.$_REQUEST['password']); $r=dbRow('select * from user_accounts where email="'.addslashes($_REQUEST['email']).'" and verification_code="'.$_REQUEST['verification_code'].'" and active' ); if($r==false){ login_redirect($url,'validationfailed'); } // success! set the session variable, then redirect $_SESSION['userdata']=$r; $groups=json_decode($r['groups']); $_SESSION['userdata']['groups']=array(); foreach($groups as $g)$_SESSION['userdata']['groups'][$g]=true; if($r['extras']=='')$r['extras']='[]'; $_SESSION['userdata']['extras']=json_decode($r['extras']); login_redirect($url); And login-libs, require 'basics.php'; $url='/'; $err=0; function login_redirect($url,$msg='success'){ if($msg)$url.='?login_msg='.$msg; header('Location: '.$url); echo '<a href="'.htmlspecialchars($url).'">redirect</a>'; exit; } // set up the redirect if(isset($_REQUEST['redirect'])){ $url=preg_replace('/[\?\&].*/','',$_REQUEST['redirect']); if($url=='')$url='/'; } // check that the email address is provided and valid function login_check_is_email_provided(){ if( !isset($_REQUEST['email']) || $_REQUEST['email']=='' || !filter_var($_REQUEST['email'], FILTER_VALIDATE_EMAIL) ){ login_redirect($GLOBALS['url'],'noemail'); } } // check that the captcha is provided function login_check_is_captcha_provided(){ if( !isset($_REQUEST["recaptcha_challenge_field"]) || $_REQUEST["recaptcha_challenge_field"]=='' || !isset($_REQUEST["recaptcha_response_field"]) || $_REQUEST["recaptcha_response_field"]=='' ){ login_redirect($GLOBALS['url'],'nocaptcha'); } } // check that the captcha is valid function login_check_is_captcha_valid(){ require 'recaptcha.php'; $resp=recaptcha_check_answer( RECAPTCHA_PRIVATE, $_SERVER["REMOTE_ADDR"], $_REQUEST["recaptcha_challenge_field"], $_REQUEST["recaptcha_response_field"] ); if(!$resp->is_valid){ login_redirect($GLOBALS['url'],'invalidcaptcha'); } } basics.php is, session_start(); function __autoload($name) { require $name . '.php'; } function dbInit(){ if(isset($GLOBALS['db']))return $GLOBALS['db']; global $DBVARS; $db=new PDO('mysql:host='.$DBVARS['hostname'].';dbname='.$DBVARS['db_name'],$DBVARS['username'],$DBVARS['password']); $db->query('SET NAMES utf8'); $db->num_queries=0; $GLOBALS['db']=$db; return $db; } function dbQuery($query){ $db=dbInit(); $q=$db->query($query); $db->num_queries++; return $q; } function dbRow($query) { $q = dbQuery($query); return $q->fetch(PDO::FETCH_ASSOC); } define('SCRIPTBASE', $_SERVER['DOCUMENT_ROOT'] . '/'); require SCRIPTBASE . '.private/config.php'; if(!defined('CONFIG_FILE'))define('CONFIG_FILE',SCRIPTBASE.'.private/config.php'); set_include_path(SCRIPTBASE.'ww.php_classes'.PATH_SEPARATOR.get_include_path()); I am not sure how to solve the problem. Any help will be appreciated. Thanks in advance. UPDATE: My db CREATE TABLE IF NOT EXISTS `user_accounts` ( `id` int(11) unsigned NOT NULL AUTO_INCREMENT, `email` text, `password` char(32) DEFAULT NULL, `active` tinyint(4) DEFAULT '0', `groups` text, `activation_key` varchar(32) DEFAULT NULL, `extras` text, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=10 ; INSERT INTO `user_accounts` (`id`, `email`, `password`, `active`, `groups`, `activation_key`, `extras`) VALUES (2, '[email protected]', '6d24dde9d56b9eab99a303a713df2891', 1, '["_superadministrators"]', '5d50e39420127d0bab44a56612f2d89b', NULL), (3, '[email protected]', 'e83052ab33df32b94da18f6ff2353e94', 1, '[]', NULL, NULL), (9, '[email protected]', '9ca3eee3c43384a575eb746eeae0f279', 1, '["_superadministrators"]', '974bf747124c69f12ae3b36afcaccc68', NULL);

    Read the article

  • Exception of Binding form data to object

    - by Captain Kidd
    I'm practising Spring MVC.But fail to populate command object in Controller when I use spring standard tag. For example: "form:input path="password"" But I perfectly do this with HTML standard tag. Like: "input type="text" name="password"" I wonder the way how to use Spring tag binding data. In addition, I think configuration and coding is right in my sample. protected ModelAndView onSubmit(HttpServletRequest request, HttpServletResponse response, Object command, BindException errors) throws Exception { UserFormBean b = (UserFormBean)command; System.out.println("s"); return super.onSubmit(request, response, command, errors); } <form:form commandName="command" action="/SpringFrame/register.html"> <form:input path="password"/> <!-- <input type="text" name="password"/> --> <input type="submit"/> </form:form>

    Read the article

  • Why does this code block say "not all code paths return a value"?

    - by Kishan
    I wrote following code...but i am getting Error like: Error 1 'LoginDLL.Class1.Login(string, string, string)': not all code paths return a value Please help me... Thanks in advance... My code is as given below... public int Login(string connectionString,string username,string password) { SqlConnection con=new SqlConnection(connectionString); con.Open(); SqlCommand validUser = new SqlCommand("SELECT count(*) from USER where username=@username", con); validUser.Parameters.AddWithValue("@username", username); int value=Convert.ToInt32(validUser.ExecuteScalar().ToString()); if (value == 1) { //check for password SqlCommand validPassword = new SqlCommand("SELECT password from USER where username=@username", con); validPassword.Parameters.AddWithValue("@username", username); string pass = validPassword.ExecuteScalar().ToString(); if (pass == password) { //valid login return 1; } else { return 0; } } else if (value == 0) { return 2; } }

    Read the article

  • Login as SYS user to Oracle 11g from .NET

    - by Jens Bannmann
    Using the Oracle Data Provider for .NET, my application connects to the database using the privileged SYS user. The connection string is as follows: Data Source=MyTnsName;User ID=sys;Password=MySysPassword;DBA Privilege=SYSDBA This works fine with Oracle 10, but Oracle 11 keeps complaining about an invalid username or password. I verified that the password is correct - other apps work fine with the same credentials. Note that for regular users (without the DBA Privilege part), connecting to Oracle 11 works perfectly. So, what's wrong? Update: This is not an issue with case sensitivity - when constructing the connection string, the password case is not altered by my code, and the password works fine with other, non-.NET-applications. I suspect that this might be caused by the Oracle 10 client I'm using to connect to the 11 database. Oracle states that the client is upward-compatible, the only drawback being that you cannot use some new features of the database. However, SYSDBA connections clearly are not a new Oracle 11 feature, and - again - a non-.NET-app (Keeptool Hora) can connect using the same setup. Any other ideas? Update 2: The problem persists when using an Oracle 11 client :-(

    Read the article

  • Salting example in Zend Framework

    - by Geoffrey
    Hello all, I am pretty new to the Zend framework and looking to build an application with pretty tight password security. I have been trying to follow the user guides in relation to password salting but haven't had any luck so far. I have setup my database and table adapter (As described in the documentation on the Zend Framework site but it didn't seem to finish the example (or I am not following well enough!) I have started with: $authAdapter = new Zend_Auth_Adapter_DbTable($dbAdapter, 'users', 'username', 'password', "MD5(CONCAT('".Zend_Registry::get('staticSalt')."', ?, password_salt))" ); But from here, what is done with the password salt? I just need an example and I'll be away! Does anyone have an example or point me in the right direction?? Many thanks!

    Read the article

  • How do I do client-side form validation in jQuery?

    - by marcamillion
    I am trying to use this plugin: http://docs.jquery.com/Plugins/Validation Where #user_new is the id for my form, this is what my code looks like: $('#user_new').validate({ rules: { user[username]: "required", user[email]: { required: true, email: true } }, messages: { user[username]: "Please specify your name", user[email]: { required: "We need your email address to contact you", email: "Your email address must be in the format of [email protected]" } } }) Where these are how my input fields look when the page is rendered (generated by Rails): <input class="clearField curved" id="user_f_name" name="user[f_name]" size="30" type="text" value="First Name" /><br /> <input class="clearField curved" id="user_l_name" name="user[l_name]" size="30" type="text" value="Last Name" /><br /> <input class="clearField curved" id="user_username" name="user[username]" size="30" type="text" value="Username" /><br /> <input class="clearField curved" id="user_password" name="user[password]" size="30" type="password" value="Password" /><br /> <input class="clearField curved" id="user_password_confirmation" name="user[password_confirmation]" size="30" type="password" value="Password" /><br /> <input class="clearField curved" id="user_email" name="user[email]" size="30" type="text" value="Email Address" /><br /> I was just trying to validate username & email first. Then take it from there. For the life of me, I can't figure out how to specify the syntax and the rules for working with this plugin. Help!

    Read the article

  • Sending email using Java, connecting to a gmail host hangs

    - by Tot
    I would like to send emails via Java code. I added in my library the following .JARs: log4j.jar, smtp.jar, mailapi.jar,ctivation.jar. And my Java class looks like this: import java.util.Properties; import javax.mail.*; import javax.mail.internet.*; public class SendEmail { public static void main(String [] args) { String to = "[email protected]"; String from = "[email protected]"; String host = "smtp.gmail.com"; Properties properties = System.getProperties(); properties.setProperty("mail.smtp.host", host); properties.setProperty("mail.smtp.starttls.enable", "true"); properties.setProperty("mail.smtp.auth", "true"); SmtpAuthenticator authentication = new SmtpAuthenticator(); javax.mail.Message msg = new MimeMessage(Session .getInstance(properties, authentication)); try { msg.setFrom(new InternetAddress(from)); msg.setRecipient(Message.RecipientType.TO, new InternetAddress(to)); msg.setSubject("Subject"); msg.setText("Working fine..!"); System.out.println("fine1 !!"); Transport transport = Session.getDefaultInstance( properties , null).getTransport("smtp"); System.out.println("fine2 !!"); transport.connect("smtp.gmail.com" , 465 , "username", "password"); System.out.println("fine3 !!"); Transport.send(msg); System.out.println("fine!!"); } catch(Exception exc) { System.out.println(exc); } } } My SmtpAuthenticator class: import javax.mail.Authenticator; import javax.mail.PasswordAuthentication; public class SmtpAuthenticator extends Authenticator { public SmtpAuthenticator() { super(); } @Override public PasswordAuthentication getPasswordAuthentication() { String username = "user"; String password = "password"; if ((username != null) && (username.length() > 0) && (password != null) && (password.length() > 0)) { return new PasswordAuthentication(username, password); } return null; } } When i run my Java application class it prints: fine1 !! fine2 !! And it hangs. How can I get rid of this problem?

    Read the article

  • unable to install mysql completely on debian 5.0

    - by austin powers
    hi, its been a couple of days that I'm trying to install mysql on my vps which has debian 5.0 with 256mb ram. I've installed webmin also. here is the symptoms : after installing mysql using either webmin or apt-get I am trying to connect to mysql for changing root password but every time I cope with this error : ERROR 1045 (28000): Access denied for user 'root'@'localhost' (using password: YES) so I start to investigate and I understand there is no root user inside mysql database when I use : UPDATE user SET password=PASSWORD('newpassword') WHERE user="root"; it says 0 row affected I reinstall mysql for several times but the same problem still exits. please help me how can I install mysql-server as well as mysql-client correctly. regards.

    Read the article

  • I have a problem with mysql and php

    - by neo skosana
    Hi I have a problem, this is my code: $db = new mysqli("localhost", "root", "", "blah"); $result1 = $db-query("select * from c_register where email = '$eml' and password = '$pass'"); if($result1-fetch_array()) { $auth->createSession(); $_SESSION['user'] = 'client'; promptUser("You have successfully logged in!!!","index.php"); } $db = new mysqli("localhost", "root", "", "blah"); $result2 = $db-query("select * from b_register where email = '$eml' and password = '$pass'"); if($result2-fetch_array()) { $auth->createSession(); $_SESSION['user'] = 'business'; promptUser("You have successfully logged in!!!","index.php"); } $db = new mysqli("localhost", "root", "", "blah"); $result3 = $db-query("select * from g_register where email = '$eml' and password = '$pass'"); if($result3-fetch_array()) { $auth->createSession(); $_SESSION['user'] = 'employee'; promptUser("You have successfully logged in!!!","index.php"); } $db = new mysqli("localhost", "root", "", "blah"); $result4 = $db-query("select * from k_register where email = '$eml' and password = '$pass'"); if($result4-fetch_array()) { $auth->createSession(); $_SESSION['user'] = 'super'; promptUser("You have successfully logged in!!!","index.php"); } else { promptUser("Username/Password do not match. Please try again!!!",""); } Funny enough this code works, but I no that I went about it the wrong way. I am new with php and mysql, so please help. I also tried e.gresult4->free(); for all the variable that save the data, and I got this error: Fatal error: Call to a member function free() on a non-object in...

    Read the article

  • Remote SQL login page C#

    - by Crazyd22
    Hey, I am trying to create a login page that checks the username and password with the database on the server. The server is located in a different country. This is the code I have so far: #region Building the connection string string Server = "XX.XXX.XX.XX, XXXX"; string Username = "_Username_"; string Password = "_Password_"; string Database = "_Database_"; string ConnectionString = "Data Source=" + Server + ";"; ConnectionString += "User ID=" + Username + ";"; ConnectionString += "Password=" + Password + ";"; ConnectionString += "Initial Catalog=" + Database; #endregion SqlConnection SQLConnection = new SqlConnection(); try { SQLConnection.ConnectionString = ConnectionString; SQLConnection.Open();   // You can get the server version // SQLConnection.ServerVersion } catch (Exception Ex) { // Try to close the connection if (SQLConnection != null) SQLConnection.Dispose();   // Create a (useful) error message string ErrorMessage = "A error occurred while trying to connect to the server."; ErrorMessage += Environment.NewLine; ErrorMessage += Environment.NewLine; ErrorMessage += Ex.Message;   // Show error message (this = the parent Form object) MessageBox.Show(this, ErrorMessage, "Connection error", MessageBoxButtons.OK, MessageBoxIcon.Error);   // Stop here return; } I am getting the error message: Non-negative number required. Parameter name: count I have accepted wildcards on my server and I have no idea what that error means? Any help would be appreciated, Thanks.

    Read the article

< Previous Page | 93 94 95 96 97 98 99 100 101 102 103 104  | Next Page >