Search Results

Search found 46178 results on 1848 pages for 'java home'.

Page 1002/1848 | < Previous Page | 998 999 1000 1001 1002 1003 1004 1005 1006 1007 1008 1009  | Next Page >

  • Sending two servlet responses per request

    - by sangi
    Hi, I write, because I can not solve the following problem. I have a servlet that processes some information. In response I put both text and binary content. How do I get two response, then two html page, starting from the same request? is a thing possible? The first response should continue to do what he does now, while the second would appear to make a popup window to save an image. There are easier ways to achieve the same result? Many thanks in advance

    Read the article

  • Generic factory of generic containers

    - by Feuermurmel
    I have a generic abstract class Factory<T> with a method createBoxedInstance() which returns instances of T created by implementations of createInstance() wrapped in the generic container Box<T>. abstract class Factory<T> { abstract T createInstance(); public final Box<T> createBoxedInstance() { return new Box<T>(createInstance()); } public final class Box<T> { public final T content; public Box(T content) { this.content = content; } } } At some points I need a container of type Box<S> where S is an ancestor of T. Is it possible to make createBoxedInstance() itself generic so that it will return instances of Box<S> where S is chosen by the caller? Sadly, defining the function as follows does not work as a type parameter cannot be declared using the super keyword, only used. public final <S super T> Box<S> createBoxedInstance() { return new Box<S>(createInstance()); } The only alternative I see, is to make all places that need an instance of Box<S> accept Box<? extends S> which makes the container's content member assignable to S. Is there some way around this without re-boxing the instances of T into containers of type Box<S>? (I know I could just cast the Box<T> to a Box<S> but I would feel very, very guilty.)

    Read the article

  • any way to simplify this with a form of dynamic class instantiation?

    - by gnychis
    I have several child classes that extend a parent class, forced to have a uniform constructor. I have a queue which keeps a list of these classes, which must extend MergeHeuristic. The code that I currently have looks like the following: Class<? extends MergeHeuristic> heuristicRequest = _heuristicQueue.pop(); MergeHeuristic heuristic = null; if(heuristicRequest == AdjacentMACs.class) heuristic = new AdjacentMACs(_parent); if(heuristicRequest == SimilarInterfaceNames.class) heuristic = new SimilarInterfaceNames(_parent); if(heuristicRequest == SameMAC.class) heuristic = new SameMAC(_parent); Is there any way to simplify that to dynamically instantiate the class, something along the lines of: heuristic = new heuristicRequest.somethingSpecial(); That would flatten that block of if statements.

    Read the article

  • Httpclient not returning entire response

    - by whakojacko
    Using HttpClient 4.0, Im having an issue where the response I get from the ResponseHandler is only about half of what the actual page content should be (~61k bytes in the string vs ~125k in the page returned to a browser). I cant seem to find any place where there might be some sort of limit that would limit this. Any ideas?

    Read the article

  • Cannot submit form when disabling JSF page

    - by Steve
    Simple submit button. <h:commandButton actionListener="#{regBean.findReg}" action="#{regBean.navigate}" value="Search" /> The form tag is displayed like so: <h:form onsubmit="this.disabled=true;busyProcess();return true;"> This is so if the submit button is pressed, the page shows a "busy" icon until request is processed. The problem is, the request is never submitted and it never reaches the backend. However, if I instead take out the "disabled" call like so: <h:form onsubmit="busyProcess();return true;"> Everything works. Any ideas?

    Read the article

  • How do I "valueOf" an enum given a class name?

    - by stevemac
    Lets say I have a simple Enum called Animal defined as: public enum Animal { CAT, DOG } and I have a method like: private static Object valueOf(String value, Class<?> classType) { if (classType == String.class) { return value; } if (classType == Integer.class) { return Integer.parseInt(value); } if (classType == Long.class) { return Long.parseLong(value); } if (classType == Boolean.class) { return Boolean.parseBoolean(value); } // Enum resolution here } What can I put inside this method to return an instance of my enum where the value is of the classType? I have looked at trying: if (classType == Enum.class) { return Enum.valueOf((Class<Enum>)classType, value); } But that doesn't work.

    Read the article

  • Variable from block is put into a calculation but throws off wrong reading

    - by user2926620
    I am having troubles with trying to retrieve a double variable that is already established outside the block and called inside but I want to return the value of the same variable so that I can apply it to a calculation. the variable that I want returned is: double quarter = 0; but when I plug it into quarter in my first else/if statement, it plugs in 0 and not the value in my switch block. What can I do to retrieve the value? double quarter = 0; //Date entry will be calculated by how much KW user enters switch (input) { case "2/15/13": quarter = kwUsed * 0.10; break; case "4/15/13": quarter = kwUsed * 0.12; break; case "8/15/13": quarter = kwUsed * 0.15; break; case "11/15/13": quarter = kwUsed * 0.15; break; default: System.out.println("Invalid date"); } //Declaring variables for calculations double base = 0; double over = 0; double excess = 0; double math1 = 0; double math2 = 0; //KW Calculations if (kwUsed <= 350) { base = quarter; }else if (kwUsed <= 500) { math1 = ((kwUsed - 350) * quarter); base = ((kwUsed * quarter) - math1); over = ((math1 * 0.1) + math1); }else if (kwUsed > 500) { math2 = ((kwUsed - 350) * 0.1); base = ((kwUsed * 0.1) - math2); math2 = ((kwUsed -350) - 50); over = ((math2 * 0.1) + (15 * 0.1)); double math3 =((kwUsed - 500) * 0.1); excess = ((math3 * 0.25) + math3); } Edited to clarify question.

    Read the article

  • How to make compareTo sort a list alphabetically?

    - by Alex
    Hi How do I change my code so that it lists the elements in alphabetical order from a to z. Right now it's ordering from z to a. I can't figure it out and am stuck :-/ String sName1 = ((Address)o).getSurname().toLowerCase(); String sName2 = (this.surname).toLowerCase(); int result = (sName1).compareTo(sName2); return result; Thanks :)

    Read the article

  • Need an efficient algorithm solve this kind of complex structure

    - by Rizvan
    Problem Statement is : Given 2 Dimensional array, print output for example If 4 rows and 6 columns, output would be: 1 2 3 4 5 6 16 17 18 19 20 7 15 24 23 22 21 8 14 13 12 11 10 9 I tried it is looking like square within square but when I attempted this problem, I put so many while and if loops but didn't got exact answer. If row and columns increases how to handle it? This is not homework. I was learning solving complex structure so I need to understand it by some guidance.

    Read the article

  • how to make this in python

    - by user2980882
    The number reduction game Rules of the game: ? The first player to write a 0 wins. ? To start the game, Player 1 picks any whole number greater than 1, say 18. ? The players take turns reducing the number by either: o Subtracting 1 from the number his/her opponent just wrote, OR o Halving the number his/her opponent just wrote, rounding down if necessary. Write a Python program that lets two players play the number reduction game. Your program should: 1. Ask Player 1 to enter the starting number. 2. Use a while-loop to allow the players to take turns reducing the number until someone wins. 3. Each time a player enters a positive number (not 0), inform the other player what his/her choices are and ask him/her to enter the next number. 4. Declare the winner when someone enters 0. Example session: Player 1, enter a number greater than 1: 16 Player 2, your choices are 15 or 8: 15 Player 1, your choices are 14 or 7: 7 Player 2, your choices are 6 or 3:3 Player 1, your choices are 2 or 1:2 Player 2, your choices are 1 or 1:1 Player 1, your choices are 0 or 0:0 Player 1 wins

    Read the article

  • Printing a JFrame and its components

    - by Alex Terreaux
    I have been working in a big program and one of its functionalities should be to print the contents of the main window. I checked the API and found this example: http://docs.oracle.com/javase/tutorial/2d/printing/gui.html it was very helpful, I tried to use that code in my program by placing this inside the actionperformed method of my print button: PrinterJob job = PrinterJob.getPrinterJob(); job.setPrintable(this); boolean ok = job.printDialog(); if (ok) { try { job.print(); } catch (PrinterException ex) { /* The job did not successfully complete */ } } If I click the print button, I get a printer dialog and when I tell it to print, it just prints a blank document. I know the above code is not all I need, as I've seen in the API's examples there is a print() method, but apparently they never call it, so it is pretty confusing. I've tried calling and using it many times, but with no success. Also, I think that when I finally get it to print, my window will need to be printed in the landscape orientation, it even may need some scaling. Any ideas on how to do that? I would like any useful help to help me implement this code successfully. I know I should be able to do it by myself just by checking the documentation (I've tried for almost 2 days now) but I can't get it to work. I've learned all the programming I know through the internet. Any help will be greatly appreciated.

    Read the article

  • How to determine page generation time with Struts 2 ?

    - by Samuel_xL
    I'm using Struts 2 and I'd like to determine the page generation time without an external profiler. I can easily profile the actions execute() method, but I don't know how to include the time spent before (in dispatchers, interceptors...) and after (time taken by the servlet corresponding to the view ("jsp time")). Is there simple way to do this ? And if there isn't, how could I, at least, profile the "jsp time" (maybe a tag I'm not aware of ?) ? I think it would be accurate enough to just take in account action time + jsp time. Thanks.

    Read the article

  • servlet authentication and further reference to the credentials

    - by user553592
    What I got so far: It all begins with an HTML form which prompts the user for a username and password. From there it post the acquired user/pass to a servlet, GateKeeper. GateKeeper determines if the user/pass combination match any records in the MySQL database. Here is the sql I use: SELECT id FROM Users WHERE username='?' AND password=MD5('?') where the ? indicate information provided the previous HTML form. What I need now: I need some way to store the username and id of the record in the database. GateKeeper redirects the user to a control panel upon success. Therefore, I need a method to reference the username to display simple greetings, etc and also the id so it eliminates unnecessary calls to the database. The control panel may make AJAX calls to Servlets that preform some sort of task to the MySQL database.

    Read the article

  • Tapestry5 display grid component using a hashmap

    - by Eldred
    Hi there I am trying to attempt to display a hashmap using a grid component. If I use List list = CollectionFactory.newList(MyHashMap) it returns a list however on my template page I see Empty and false when passing my parameter t:souce="list" to my grid component, therefore my grid component only returns one row. Some code snippets would be a great help. Many thanks

    Read the article

  • How can I improve the performance of this algorithm

    - by Justin
    // Checks whether the array contains two elements whose sum is s. // Input: A list of numbers and an integer s // Output: return True if the answer is yes, else return False public static boolean calvalue (int[] numbers, int s){ for (int i=0; i< numbers.length; i++){ for (int j=i+1; j<numbers.length;j++){ if (numbers[i] < s){ if (numbers[i]+numbers[j] == s){ return true; } } } } return false; }

    Read the article

  • How do I make dynamic windows in Swing?

    - by Roman
    I have a general question. I would like to have a window containing some buttons, radio buttons, text fields and so on. So, user can do something (write text, select options and press buttons). As the result of the user activity window should change it structure/appearance some element should disappear and some appear. How do I program such "updates"? Should I close an old window and open a new one or I can modify content of window without closing it?

    Read the article

  • BlackBerry Field class extension will not paint.

    - by jlindenbaum
    Using JRE 5.0.0, simulator device is an 8520. On a screen I am using a FlowFieldManager(Manager.VERTICAL_SCROLL) and adding Fields to it to show data. When I do this.flowManager = new FlowFieldManager(Manager.VERTICAL_SCROLL); Field field = new Field() { protected void paint(Graphics graphics) { graphics.drawTest("Test", 0, 0); } protected void layout(int width, int height) { this.setExtend(300, 300); // just testing } } this.flowManager.add(field); The screen renders correctly and 'Test' appears on the screen. If, on the other hand, I try and abstract this into a class called CustomField with the same properties and add it to the flow manager the render will not happen. Debugging shows that the device enters into the Object, into the layout function, but not the paint function. I can't figure out why the paint function is not called when I extend Field. The 4.5 API says that layout and paint are the only functions that I really need to extend. (getPreferredWidth and getPreferredHeight will be used to calculate screen sizes etc.) Thanks in advance.

    Read the article

< Previous Page | 998 999 1000 1001 1002 1003 1004 1005 1006 1007 1008 1009  | Next Page >