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  • Quickest and most efficient method to search top 3 numbers?

    - by Donal Rafferty
    I currently have an array of around 8 - 10 numbers that changes on a periodic basis. So around every 5 - 10 seconds the numbers get updated. I need to get the top 3 numbers in the array every 10 seconds. This is all done on a mobile device. At the minute I iterate through the array 3 times and each time I take out the three highest numbers and place them in three previously declared variables. My question is what should I look to do to increase speed and efficiency in this instance?

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  • How to get radio button's id and convert to string?

    - by user3461659
    I am working in Android Studio and am trying to get the ID of the selected radio button and then store the ID in a string. Is this possible? I have tried replacing the .getText() method below with .getId() but it wont let me store it as a string: RadioGroup radioGroup = (RadioGroup) findViewById(R.id.radioGroup); radioGroup.setOnCheckedChangeListener(new RadioGroup.OnCheckedChangeListener() { @Override public void onCheckedChanged(RadioGroup radioGroup, int checkedId) { RadioButton checkedRadioButton = (RadioButton) findViewById(checkedId); String text = checkedRadioButton.getText().toString(); Toast.makeText(getApplicationContext(), text, Toast.LENGTH_SHORT).show(); } });

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  • Non-empty list with null elements returned from Hibernate query

    - by John
    Hi, I'm new to hibernate so not sure if this is an expected behaviour, anyway: Session session = (Session)entityManager.getDelegate(); Criteria criteria = session.createCriteria(myRequest.class); criteria.add(Restrictions.eq("username", username)); criteria.setProjection(Projections.max("accesscount")); List<myRequest> results = criteria.list(); The returned results is a non-empty list with a single null element. I can't think of any reason why it should behave this way, any idea if this is the expected behaviour or have I done something wrong? System is on hibernate/Syabse. Thanks.

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  • which delimeter to use while spliting String

    - by London
    I need to split this line string in each line, I need to get the third word(film name) but as you see the delimeter is one big blank character in some cases its small like before the numbers at the end or its big as in front of numbers at front. I tried using string split with(" ") regex, and also \t but get the out of the bounds error. 400115305 Lionel_Atwill The_Song_of_Songs_(1933_film) 7587 400115309 Brian_Aherne A_Night_to_Remember_(1943_film) 7952 Did anyone have the same problem?

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  • starting index from 1 not from 0

    - by M.H
    My question is simple (I think it is silly too) ,how can I start the index in an ArrayList from 1 instead of 0 ? is this possible directly (I mean is there a code for this ) ?. Actually a friend asked me this question today, first I thought that it is a silly question but after a while I thought if there is a direct way to do that and decided to ask it to you (maybe you have some brilliant ideas :) )

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  • add objects with different name through for loop

    - by Gandalf StormCrow
    What is the best way to do the following: List<MyObject> list = new LinkedList<MyObject>(); for(int i=0; i<30;i++) { MyObject o1 = new MyObject(); list.add(o1); } But the things is I don't wanna create objects with same name, I wanna create them with different name like o1,o2,o3,o4,o5,o6,o7,o8,o9,o10 and I wanna add each to the list. What is the best way to do this ?

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  • How the clients (client sockets) are identified?

    - by Roman
    To my understanding by serverSocket = new ServerSocket(portNumber) we create an object which potentially can "listen" to the indicated port. By clientSocket = serverSocket.accept() we force the server socket to "listen" to its port and to "accept" a connection from any client which tries to connect to the server through the port associated with the server. When I say "client tries to connect to the server" I mean that client program executes "nameSocket = new Socket(serverIP,serverPort)". If client is trying to connect to the server, the server "accepts" this client (i.e. creates a "client socket" associated with this client). If a new client tries to connect to the server, the server creates another client socket (associated with the new client). But how the server knows if it is a "new" client or an "old" one which has already its socket? Or, in other words, how the clients are identified? By their IP? By their IP and port? By some "signatures"? What happens if an "old" client tries to use Socket(serverIP,serverIP) again? Will server create the second socket associated with this client?

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  • database deign advice wanted: double data entry

    - by john
    hi, I'm designing a database for capturing clinical trial data. The data are entered twice by two persons, independently and the results must be matched. What are the best database tools to use to achieve the best results. Any one has similar experiences? Your helps are highly appreciated. thanks.

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  • Httpclient not returning entire response

    - by whakojacko
    Using HttpClient 4.0, Im having an issue where the response I get from the ResponseHandler is only about half of what the actual page content should be (~61k bytes in the string vs ~125k in the page returned to a browser). I cant seem to find any place where there might be some sort of limit that would limit this. Any ideas?

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  • BlackBerry Field class extension will not paint.

    - by jlindenbaum
    Using JRE 5.0.0, simulator device is an 8520. On a screen I am using a FlowFieldManager(Manager.VERTICAL_SCROLL) and adding Fields to it to show data. When I do this.flowManager = new FlowFieldManager(Manager.VERTICAL_SCROLL); Field field = new Field() { protected void paint(Graphics graphics) { graphics.drawTest("Test", 0, 0); } protected void layout(int width, int height) { this.setExtend(300, 300); // just testing } } this.flowManager.add(field); The screen renders correctly and 'Test' appears on the screen. If, on the other hand, I try and abstract this into a class called CustomField with the same properties and add it to the flow manager the render will not happen. Debugging shows that the device enters into the Object, into the layout function, but not the paint function. I can't figure out why the paint function is not called when I extend Field. The 4.5 API says that layout and paint are the only functions that I really need to extend. (getPreferredWidth and getPreferredHeight will be used to calculate screen sizes etc.) Thanks in advance.

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  • JQuery Tabs - HTML not displayed in any other tab except default tab

    - by user346347
    I'm pretty new to jquery, but I have a tab structure working and make a $.getJSON call to retrieve the JSON results from the backend. Now, I have 3 tabs: Tab1, Tab2 and Tab3. All the three tabs have the same divs but different content. The content shows up just fine in the first tab which is shown by default, but on clicking the 2nd tab, I make the same $.getJSON call and retrieve the JSON just fine, the same HTML is being constructed on the fly and set in the DIV within the tab but it is not being displayed... Any pointers??

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  • What are the scenarios in which case a new class will be loaded?

    - by GK
    That is when you have any jar file attached to you your class path. then as far as i know any class from the jar is loaded for the first time when, when you create any object of that type. or If you are accessing any static member or method of that class. or when you load that by using Class.forName() method. So are there any other ways of loading a class for the first time?

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