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  • Android ArrayList Calendar add and get is different

    - by Raku ShinShou
    I put increment date of the calendar and add into arraylist, but when i loop them out, the date is all same. Calendar a = Calendar.getInstance(); ArrayList<Calendar> b = new ArrayList<Calendar>(); for (int i=0; i<3; i++) { a.add(Calendar.DATE, i>0 ? 1 : 0); b.add(a); } for (int i=0; i<b.size(); i++){ Log.d("xxx", "test=" + b.get(i)); } suppose i wan 10/11/2012, 11/11/2012, 12/11/2012 but it come out like 12/11/2012, 12/11/2012, 12/11/2012 Anyone know how to solve this?

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  • BlackBerry Field class extension will not paint.

    - by jlindenbaum
    Using JRE 5.0.0, simulator device is an 8520. On a screen I am using a FlowFieldManager(Manager.VERTICAL_SCROLL) and adding Fields to it to show data. When I do this.flowManager = new FlowFieldManager(Manager.VERTICAL_SCROLL); Field field = new Field() { protected void paint(Graphics graphics) { graphics.drawTest("Test", 0, 0); } protected void layout(int width, int height) { this.setExtend(300, 300); // just testing } } this.flowManager.add(field); The screen renders correctly and 'Test' appears on the screen. If, on the other hand, I try and abstract this into a class called CustomField with the same properties and add it to the flow manager the render will not happen. Debugging shows that the device enters into the Object, into the layout function, but not the paint function. I can't figure out why the paint function is not called when I extend Field. The 4.5 API says that layout and paint are the only functions that I really need to extend. (getPreferredWidth and getPreferredHeight will be used to calculate screen sizes etc.) Thanks in advance.

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  • Hibernate: delete many-to-many association

    - by Bar
    I have two tables with the many-to-many association. — DB fragment: loads Id Name sessions Id Date sessionsloads LoadId SessionId — Hibernate mapping fragments: /* loads.hbm.xml */ <set name="sessions" table="sessionsloads" inverse="true"> <key column="LoadId" /> <many-to-many column="SessionId" class="Session" /> </set> … /* sessions.hbm.xml */ <set name="loads" table="sessionsloads"> <key column="SessionId" /> <many-to-many column="LoadId" class="Load" /> </set> In order to remove one entry from the association table sessionsloads, I execute this code: Session session = sessionDao.getObject(sessionId); Load load = loadDao.getObject(loadId); load.getSessions().remove(session); loadDao.saveObject(load); But, after launching, this code change nothing. What's the right way to remove an association?

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  • Detect months with 31 days

    - by daddycardona
    Is there an analogous form of the following code: if(month == 4,6,9,11) { do something; } Or must it be: if(month == 4 || month == 6 etc...) { do something; } I am trying to write an if statement that checks if this month has more than 31 days.

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  • Non-empty list with null elements returned from Hibernate query

    - by John
    Hi, I'm new to hibernate so not sure if this is an expected behaviour, anyway: Session session = (Session)entityManager.getDelegate(); Criteria criteria = session.createCriteria(myRequest.class); criteria.add(Restrictions.eq("username", username)); criteria.setProjection(Projections.max("accesscount")); List<myRequest> results = criteria.list(); The returned results is a non-empty list with a single null element. I can't think of any reason why it should behave this way, any idea if this is the expected behaviour or have I done something wrong? System is on hibernate/Syabse. Thanks.

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  • download html source android?

    - by mars
    I'm trying to download a website source code and display it in a textbox but I seem to get an error and can't figure it out :s public void getHtml() throws ClientProtocolException, IOException { HttpClient httpClient = new DefaultHttpClient(); HttpContext localContext = new BasicHttpContext(); HttpGet httpGet = new HttpGet("http://www.spartanjava.com"); HttpResponse response = httpClient.execute(httpGet, localContext); String result = ""; BufferedReader reader = new BufferedReader( new InputStreamReader( response.getEntity().getContent() ) ); String line = null; while ((line = reader.readLine()) != null){ result += line + "\n"; Toast.makeText(activity.this, line.toString(), Toast.LENGTH_LONG).show(); } } how come this doesn't work and throw an IOException?

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  • Are Interfaces "Object"?

    - by PrashantGupta
    package inheritance; class A{ public String display(){ return "This is A!"; } } interface Workable{ public String work(); } class B extends A implements Workable{ public String work(){ return "B is working!"; } } public class TestInterfaceObject{ public static void main(String... args){ B obj=new B(); Workable w=obj; //System.out.println(w.work()); //invoking work method on Workable type reference System.out.println(w.display()); //invoking display method on Workable type reference //System.out.println(w.hashCode()); // invoking Object's hashCode method on Workable type reference } } As we know that methods which can be invoked depend upon the type of the reference variable on which we are going to invoke. Here, in the code, work() method was invoked on "w" reference (which is Workable type) so method invoking will compile successfully. Then, display() method is invoked on "w" which yields a compilation error which says display method was not found, quite obvious as Workable doesn't know about it. Then we try to invoke the Object class's method i.e. hashCode() which yields a successful compilation and execution. How is it possible? Any logical explanation?

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  • hibernate pagination mechanism

    - by haicnpmk44
    I am trying to use Hibernate pagination for my query (PostgreSQL ) i set setFirstResult(0), setMaxResults(20) for my sql query. My code like below: Session session = getSessionFactory().getCurrentSession(); session.beginTransaction(); Query query = session.createQuery("select id , customer_name , address from tbl_customers "); query.setFirstResult(0); query.setMaxResults(20); List<T> entities = query.list(); session.getTransaction().commit(); but when viewing SQL hibernate log, i still see full sql query: Hibernate: select customer0_.id as id9_, customer0_.customer_name as dst2_9_, customer0_.addres as dst3_9_ from tbl_customers customer0_ Why there is no LIMIT OFFSET in query of Hibernate pagination SQL log? Does anyone know about Hibernate pagination mechanism? I guess that Hibernate will select all data, put data into Resultset, and then paging in Resultset, right?

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  • What are the scenarios in which case a new class will be loaded?

    - by GK
    That is when you have any jar file attached to you your class path. then as far as i know any class from the jar is loaded for the first time when, when you create any object of that type. or If you are accessing any static member or method of that class. or when you load that by using Class.forName() method. So are there any other ways of loading a class for the first time?

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  • Created query is not supported by my DB

    - by stacker
    I created an application using seam-gen. The created operation to search the DB ends with and exception (syntax error). The query has a where clause like this: lower(barcode0_.barcode_ean) like lower((?||'%')) limit ? Does hibnerate or seam create the where clause which my DB can't understand? Or is there a workaround for SQL statement related issues in seam?

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  • add objects with different name through for loop

    - by Gandalf StormCrow
    What is the best way to do the following: List<MyObject> list = new LinkedList<MyObject>(); for(int i=0; i<30;i++) { MyObject o1 = new MyObject(); list.add(o1); } But the things is I don't wanna create objects with same name, I wanna create them with different name like o1,o2,o3,o4,o5,o6,o7,o8,o9,o10 and I wanna add each to the list. What is the best way to do this ?

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  • Quickest and most efficient method to search top 3 numbers?

    - by Donal Rafferty
    I currently have an array of around 8 - 10 numbers that changes on a periodic basis. So around every 5 - 10 seconds the numbers get updated. I need to get the top 3 numbers in the array every 10 seconds. This is all done on a mobile device. At the minute I iterate through the array 3 times and each time I take out the three highest numbers and place them in three previously declared variables. My question is what should I look to do to increase speed and efficiency in this instance?

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  • trying to switch beginning of an array with another

    - by user1874574
    I have a problem where i am trying to swap two arrays so that they switch beginnings. example: array 1 = (1,2,3,4,5,6,7,8) and array 2 = (11,12,13,14,15,16,17,18) i want to end up with the first array being (11,12,13,14,5,6,7,8) and i want the second array to be (1,2,3,4,15,16,17,18) but for some reason i end up with 1=(11,12,13,14,5,6,7,8) and 2=(11,12,13,14,15,16,17,18) my code is provided below, what am i doing wrong? public static void Mutate(Genetic lowest, Genetic secondLowest) { int halfway = (lowest.getPopulation().length)/2; int[] one = lowest.getPopulation(); int[] two = secondLowest.getPopulation(); int[] temp = secondLowest.getPopulation(); int[] temp2 = lowest.getPopulation(); for(int i = 0; i < halfway; i++){ temp[i] = one[i]; } lowest.setPopulation(temp); for(int i = 0; i < lowest.getPopulation().length; i++){ System.out.print(temp[i]); } System.out.println(); for(int i = 0; i < halfway; i++){ temp2[i] = two[i]; } for(int i = 0; i < lowest.getPopulation().length; i++){ System.out.print(temp2[i]); } }

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