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  • Reference and Value confusion

    - by rgamber
    Hi I read this question on Stack overflow, and tried to do an example. I had the below code: public static void main(String[] args){ int i = 5; Integer I = new Integer(5); increasePrimitive(i); increaseObject(I); System.out.println(i); //Prints 5 - correct System.out.println(I); //Still prints 5 System.out.println(increaseObject2(I)); //Still prints 5 } public static void increasePrimitive(int n){ n++; } public static void increaseObject(Integer n){ n++; } public static int increaseObject2(Integer n){ return n++; } Does the increaseObject print 5 because the value of reference is changing inside that function? Am I right? I am confused why the increasedObject2 prints 5 and not 6. Can anyone please explain?

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  • Spring internalisation

    - by annnuu
    English properties file can be read bt when i click on french link it couldnt read.Can u tell me the stepwise process to do this.I hav images which need to be in french when i click in french..

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  • hashmap and list compare

    - by sarah
    Hi, I have a hashmap having four values a,b,c,d and list having only a i want to see if the hashmap has the value a and print it. hashmap.get('data') results a,b,c,d list l is having a how will i print only the value a

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  • Abstract class and an inheritor: is it possible to factorize .parent() here?

    - by fge
    Here are what I think are the relevant parts of the code of these two classes. First, TreePointer (original source here): public abstract class TreePointer<T extends TreeNode> implements Iterable<TokenResolver<T>> { //... /** * What this tree can see as a missing node (may be {@code null}) */ private final T missing; /** * The list of token resolvers */ protected final List<TokenResolver<T>> tokenResolvers; /** * Main protected constructor * * <p>This constructor makes an immutable copy of the list it receives as * an argument.</p> * * @param missing the representation of a missing node (may be null) * @param tokenResolvers the list of reference token resolvers */ protected TreePointer(final T missing, final List<TokenResolver<T>> tokenResolvers) { this.missing = missing; this.tokenResolvers = ImmutableList.copyOf(tokenResolvers); } /** * Alternate constructor * * <p>This is the same as calling {@link #TreePointer(TreeNode, List)} with * {@code null} as the missing node.</p> * * @param tokenResolvers the list of token resolvers */ protected TreePointer(final List<TokenResolver<T>> tokenResolvers) { this(null, tokenResolvers); } //... /** * Tell whether this pointer is empty * * @return true if the reference token list is empty */ public final boolean isEmpty() { return tokenResolvers.isEmpty(); } @Override public final Iterator<TokenResolver<T>> iterator() { return tokenResolvers.iterator(); } // .equals(), .hashCode(), .toString() follow } Then, JsonPointer, which contains this .parent() method which I'd like to factorize here (original source here: public final class JsonPointer extends TreePointer<JsonNode> { /** * The empty JSON Pointer */ private static final JsonPointer EMPTY = new JsonPointer(ImmutableList.<TokenResolver<JsonNode>>of()); /** * Return an empty JSON Pointer * * @return an empty, statically allocated JSON Pointer */ public static JsonPointer empty() { return EMPTY; } //... /** * Return the immediate parent of this JSON Pointer * * <p>The parent of the empty pointer is itself.</p> * * @return a new JSON Pointer representing the parent of the current one */ public JsonPointer parent() { final int size = tokenResolvers.size(); return size <= 1 ? EMPTY : new JsonPointer(tokenResolvers.subList(0, size - 1)); } // ... } As mentioned in the subject, the problem I have here is with JsonPointer's .parent() method. In fact, the logic behind this method applies to TreeNode all the same, and therefore to its future implementations. Except that I have to use a constructor, and of course such a constructor is implementation dependent :/ Is there a way to make that .parent() method available to each and every implementation of TreeNode or is it just a pipe dream?

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  • How to sort an array by (smallest, largest, second smallest, second, largest) etc?

    - by Binka
    Any ideas? I can sort an array. But not in this pattern? It needs to sort by the pattern I mentioned above. public void wackySort2(int[] nums) { int sign = 0; int temp = 0; int temp2 = 0; for (int i = 0; i < nums.length; i++) { for (int j = 0; j < nums.length - 1; j++) { if (nums[j] > nums[j + 1]) { temp = nums[j]; nums[j] = nums[j + 1]; nums[j + 1] = temp; //sign = 1; System.out.println("Something has been done"); } } } }

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  • Sending two servlet responses per request

    - by sangi
    Hi, I write, because I can not solve the following problem. I have a servlet that processes some information. In response I put both text and binary content. How do I get two response, then two html page, starting from the same request? is a thing possible? The first response should continue to do what he does now, while the second would appear to make a popup window to save an image. There are easier ways to achieve the same result? Many thanks in advance

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  • Criteria: search for two different entity classes...

    - by RoCMe
    Hi! I have a "super entity" SuperEntity and three entities ChildEntity1, ..., ChildEntity3 which extends the super class. It's easy to search for all entities in the database, i.e. we could use session.createCriteria(SuperEntity.class); It's no problem to search for one specific entity type, too, just replace the SuperEntity with any of the children to look for entities of that type. But I have a problem when allowing 'multiple choice' for the types. I.e., it could be neccessary to search all entities of type 1 and 2, but not of type 3. A first idea was to create two independent queries and join the results in a final list - but that would destroy the paging which uses offset and limit functionality of the database... Is there a possibility in Criteria to join two different queries in one single result list? Kind regards, RoCMe

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  • Are hashCodes unique for Strings?

    - by Batty
    Recently, I came across a piece of code, where Map<Integer, String> is used, where Integer(key) is hashCode of some string and String value corresponding to that. Is this right thing to do? Because now, equals will not be called for the String when calling get. (get is also done using hashCode() method on String object. Or, hashCode(s) are unique for unique Strings? I checked equals od String class. There is logic written for that. I am confused.

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  • Alert Box Methods

    - by Vecta
    I just need a little advice on what may be the best method for handling my situation. I'm in need of placing three buttons in the sidebar of the website I maintain. The website is massive and hard to handle. Currently, it's all HTML files (there are over 10,000 of them believe it or not). We're transitioning to a database website so I don't want to make any sweeping changes that are site-wide, as they may just be scrapped in our re-design process in coming months. However, these buttons are for an application process. When you click on them, an alert box will need to pop up to give you a bit of information and they either allow you to cancel the action or proceed. The buttons are currently located in the left nav which is included on every page of the website. Would it be possible to accomplish this using JS or jQuery? I'd be unable to easily add scripts into the tags on all of the applicable pages, but I'd like to avoid the browser driven "http://www...Says: blah blah" message if possible. Any insight is greatly appreciated! Thank you!

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  • Need help to solve sharedPreference probem

    - by HFherasen
    I am working on this app where I have one EditText field where you can write somthing and then it get saved and added to a list(TextView). I save the content of the EditText in this way : saved += "*" + editTextFelt.getText().toString() + ". \n"; saved is a String. Everything works fine, I can even reload the app and it's still displayed in the TextView, but if i try to write somthing and save it everything that was there, now dissapear. anyone know why ? It's kind of confusing, and I have to get it to work! Thank's!! CODE: init Mehtod() sp = getSharedPreferences(fileName, 0); betaView = (TextView)findViewById(R.id.betaTextView); Ive got a button to send the text, and this is like: p ublic void onClick(View v) { switch(v.getId()){ case R.id.btnSend: saved += "*" + editTextFelt.getText().toString() + ". \n"; SharedPreferences.Editor editor = sp.edit(); editor.putString("SAVED", saved); editor.commit(); betaView.setText(sp.getString("SAVED", "Empty"));

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  • String.valueOf(int value) gives error [closed]

    - by Davidrd91
    I am trying to convert an int into a String so that I can put the String values into an SQLite Cursor. I've tried multiple syntax and methods but none seem to work for me. The Error occurs in MangaItemDB() while trying to convert any Int types aswell as the boolean. I've looked through several articles like this one but none works for me. Here's my code: public class MangaItem { private int _id; private String mangaName; private String mangaLink; private static String mangaAlpha; private static int mangaCount; private static int alphaCount; private boolean mangaComplete = false; public MangaItem MangaItemDB(int id, String mangaName, String mangaLink, String mangaAlpha, String mangaCount, String alphaCount, String mangaComplete) { MangaItem MangaItemDB = new MangaItem(); MangaItemDB._id = id; MangaItemDB.mangaName = mangaName; MangaItemDB.mangaLink = mangaLink; MangaItemDB.mangaAlpha = mangaAlpha; MangaItemDB.mangaCount = String.valueOf(int mangaCount); MangaItemDB.alphaCount = Integer.toString(getAlphaCount()); MangaItemDB.mangaComplete = String.valueOf(getMangaComplete()); return MangaItemDB; } public void incrementMangaCount() { mangaCount++; } public int getMangaCount() { return mangaCount; } public void incrementAlphaCount() { alphaCount++; } public int getAlphaCount() { return alphaCount; } public boolean setMangaComplete(boolean mangaComplete) { return true; } public boolean getMangaComplete() { return mangaComplete; } /** * @return the mangaName */ public String getMangaName() { return mangaName; } /** * @param mangaName the mangaName to set */ public void setMangaName(String mangaName) { this.mangaName = mangaName; } /** * @return the mangaLink */ public String getMangaLink() { return mangaLink; } /** * @param mangaLink the mangaLink to set */ public void setMangaLink(String mangaLink) { this.mangaLink = mangaLink; } /** * @return the mangaAlpha */ public String getMangaAlpha() { return mangaAlpha; } /** * @param mangaAlpha the mangaAlpha to set */ public void setMangaAlpha(String mangaAlpha) { this.mangaAlpha = mangaAlpha; } /** * @return the _id */ public int get_id() { return _id; } /** * @param _id the _id to set */ public void set_id(int _id) { this._id = _id; } } The lines : MangaItemDB.mangaCount = String.valueOf(mangaCount); MangaItemDB.alphaCount = Integer.toString(getAlphaCount()); MangaItemDB.mangaComplete = String.valueOf(getMangaComplete()); all give "Type mismatch: cannot convert from String to Int"

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  • Eclipse debug - line: not available

    - by Mike
    I can't seem to find anything on google telling me why this might be and what the resolution is. I'm Stepping through third party code (that I have the source for) and would really like to see the current line being executed... Looking at javac compile flags, I see the -g:none flag. If this flag is set, would this be enough to explain why I'm not able to see line numbers? If so, why would someone do this, are there performance implications? Do I need to recompile the jar myself to attach the missing debug info (if possible)? Thanks!

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  • Args error in main method for client-server program

    - by socket
    Hi I have a client and server program, all the coding is done and compiles, the client has a GUI and the server is command line. The program uses sockets. But when I run the client to connect to the server it keeps coming with the error message: "Usage: TodoClient []", rather than connecting to the server and starting up. This is where the problem lies: public static void main(String[] args) { TodoClient client; if (args.length > 2 || args.length == 0) { System.err.println("Usage: TodoClient <host> [<port>]"); } else if (args.length == 1) { client = new TodoClient(args[0], DEFAULT_PORT); } else { client = new TodoClient(args[0], Integer.parseInt(args[1])); } } Thank You

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  • Question regarding xsd

    - by Hima
    I have an application which reads the data from the database, creates an object out of the data, marshalls it into an xml and enqueue the xml to a queue which is producer. The xml is dequeued from the queue by a consumer. I need to use xsds at two different places. For database access while reading the data from the database and For interaction between producer and consumer Can the same xsd be used in both the cases? Or do I need to use different xsds?

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  • Why is this removing all elements from my LinkedList?

    - by Brian
    Why is my remove method removing every element from my Doubly Linked List? If I take out that if/else statements then I can successfully remove middle elements, but elements at the head or tail of the list still remain. However, I added the if/else statements to take care of elements at the head and tail, unfortunately this method now removes every element in my list. What am I do wrong? public void remove(int n) { LinkEntry<E> remove_this = new LinkEntry<E>(); //if nothing comes before remove_this, set the head to equal the element after remove_this if (remove_this.previous == null) head = remove_this.next; //otherwise set the element before remove_this equal to the element after remove_this else remove_this.previous.next = remove_this.next; //if nothing comes after remove_this, set the tail equal to the element before remove_this if (remove_this.next == null) tail = remove_this.previous; //otherwise set the next element's previous pointer to the element before remove_this else remove_this.next.previous = remove_this.previous; //if remove_this is located in the middle of the list, enter this loop until it is //found, then remove it, closing the gap afterwards. int i = 0; for (remove_this = head; remove_this != null; remove_this = remove_this.next) { //if i == n, stop and delete 'remove_this' from the list if (i == n) { //set the previous element's next to the element that comes after remove_this remove_this.previous.next = remove_this.next; //set the element after remove_this' previous pointer to the element before remove_this remove_this.next.previous = remove_this.previous; break; } //if i != n, keep iterating through the list i++; } }

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  • MediaType of REST

    - by user357243
    Hi, I am beginner in REST web services. I wrote a program of REST to display the HTML or XML. The @Path annotation's value is @Path("{typeDocument}"). There are two methods for GET : @GET @Produces(MediaType.TEXT_XML) public String getXml(@PathParam("typeDocument") String typeDocument) to display XML file, and @GET @Produces(MediaType.TEXT_HTML) public String getHtml(@PathParam("typeDocument") String typeDocument) to display HTML. The browser Firefox always excutes getHtml() when URL is either http://localhost:8080/sources/html or localhost:8080/sources/xml But IE always excutes getXml(). How to excute the correct method, as defined by URL, in different browser ? Thanks a lot.

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  • Should my DAOs (Database Entities) Directly match my UI Objects?

    - by scarpacci
    I am trying to figure out best practice for N-Tier application design. When designing the objects my UI needs and those that will be persisted in the DB some of my colleagues are suggesting that the objects be one in the same. This doesn't not feel right to me and I am ultimately looking for some best practice documentation to help me in this decision. I honestly do not understand why I would want to design this way given that other applications may want to interact with my Data Access Layer....or it is just ignorance or lack of understanding on my part. Any documentation, information you could provide would be greatly appreciated. Just want to better understand these concepts and I am having a hard time finding some good information on the best practice for implementing these patterns (Or it is right in front of me on what I found and I didn't understand what was being outlined). Thanks, S

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  • the difference of String.valueOf(char) and +

    - by Will Yu
    to show the default value of char ,I wrote code like this: public class TestChar { static char a; public static void main(String[] args) { System.out.println("."+String.valueOf(a)+"."); System.out.println("the default char is "+a); } } but the console output is confused.the first is ". ." ,however the second is "the default char is [](like this ,I don't know how to describe it.)" why?thanks for help

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  • JVM memory management & garbage collection book?

    - by Max
    Hi. Could anyone advice a book (or any other source) that would thoroughly reveal internals of JVM memory management & garbage collection (optimization, work, circular references, pecularities, discussions for various JVM impls...)? [What I've found so far are separate articles devoted to various aspects but no weighty tome :). Some good materials for Hotspot implementation are here. ] Thanks a lot for any advice you give.

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  • Why does the compiler complain "while expected" when I try to add more code?

    - by user1893578
    Write a program with a word containing @ character as an input. If the word doesn't contain @, it should prompt the user for a word with @. Once a word with @ is read, it should output the word then terminate. This is what I have done so far: public class find { public static void main(String[] args) { System.out.println(" Please enter a word with @ "); Scanner scan = new Scanner(System.in); String bad = "@"; String word = scan.next(); do if (!word.contains(bad)) System.out.println(" Please try again "); else System.out.println(" " + word); while (!word.contains(bad)); } } I can get it to terminate after a word containing "@" is given as input, but if I try to add a Scanner to the line after "please try again", it says while expected.

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