Dimensions of a collection, and how to traverse it in an efficient, elegant manner
- by Bruce Ferguson
I'm trying to find an elegant way to deal with multi-dimensional collections in Scala. My understanding is that I can have up to a 5 dimensional collection using tabulate, such as in the case of the following 2-Dimensional array:
val test = Array.tabulate[Double](row,col)(_+_)
and that I can access the elements of the array using
for(i<-0 until row) {
for(j<-0 until col) {
test(i)(j) = 0.0
}
}
If I don't know a priori what I'm going to be handling, what might be a succinct way of determining the structure of the collection, and spanning it, without doing something like:
case(Array(x)) =>
for(i<-1 until dim1) {
test(i) = 0.0
}
case(Array(x,y)) =>
for(i<-1 until dim1) {
for(j<-1 until dim2) {
test(i)(j) = 0.0
}
}
case(Array(x,y,z)) =>
...
The dimensional values n1, n2, n3, etc... are private, right? Also, would one use the same trick of unwrapping a 2-D array into a 1-D vector when dealing with n-Dimensional objects if I want a single case to handle the traversal?
Thanks in advance
Bruce
