Search Results

Search found 46894 results on 1876 pages for 'java native interface'.

Page 1024/1876 | < Previous Page | 1020 1021 1022 1023 1024 1025 1026 1027 1028 1029 1030 1031  | Next Page >

  • multiplying all elements in an array by an outside number?

    - by prodo
    I need to multiple all the values in an array by 3000 which in turn would create a new array that I will use to subtract from another array. I've tried to create a separate method that would do that for me but all I got back in the multiplied array was a bunch of numbers and symbols strangely? here is the code that I wrote public static void main(String[] args) { int numberOfTaxpayers = Integer.parseInt(JOptionPane.showInputDialog("Enter how many users you would like to calculate taxes for: "); int[] usernumChild = new int[numberOfTaxPayers]; for (int i = 0; i < usernumChild.length; i++) { usernumChild[i] = Integer.parseInt(JOptionPane.showInputDialog("Enter number of children for user "+ (i+1) +": ")); }//this for loop finds out the number of children per user so we can later multiply each input by 3000 to create an array that determine dependency exemption for each user int[] depndExemp = multiply(usernumChild, 3000);//this was the calling of the multiply method... somewhere here is the error!! }//end main method public static int[] multiply(int[] children, int number) { int array[] = new int[children.length]; for( int i = 0; i < children.length; i++) { children[i] = children[i] * number; }//end for return array; }//this is the method that I was shown in a previous post on how to create return an array in this the dependency exemption array but when I tested this by printing out the dependency array all I received were a jumble of wrong numbers.

    Read the article

  • Creating New Object of Other Class dynamicly ?

    - by Meko
    I am trying to create new object of other class in a for loop. like for(int i =0;i<10;i++){ Computer p1=new Computer(10,20); } and when I try anywhere to reach p1.someAction(); it say you must declare p1. But if I declare it on top of program how can I create again in loop? I also try only Computer p1; but it gave exeption ..

    Read the article

  • Why is Hibernate not loading a column?

    - by B.R.
    I've got an entity with a few properties that gets used a lot in my Hibernate/GWT app. For the most part, everything works fine, but Hibernate refuses to load one of the properties. It doesn't appear in the query, despite being annotated correctly in the entity. The relevant portion of the entity: @Column(name="HasSubSlots") @Type(type="yes_no") public boolean hasSubSlotSupport() { return hasSubSlotSupport; } And the generated SQL query: Hibernate: /* load entities.DeviceModel */ select devicemode0_.DevModel as DevModel1_0_, devicemode0_.InvModelName as InvModel2_1_0_ from DeviceModels devicemode0_ where devicemode0_.DevModel=? Despite the fact that I refer to that property, it's never loaded, lazily or not, and the getter always returns false. Any ideas on how I can dig deeper into this, or what might be wrong?

    Read the article

  • How to make NOT IN statement via Restrictions

    - by slavig
    I used this trick: List statuses = new ArrayList(); Criteria criteria = session.createCriteria(MessageQueue.class); criteria.add(Restrictions.not(Restrictions.in("message_status", statuses))); and this code creates: ...from MESSAGE_QUEUE mq where not (mq.message_status in (?, ?, ?, ?))... but I need: ...from MESSAGE_QUEUE mq where mq.message_status NOT IN (?, ?, ?, ?) Du you think they are equal statements?

    Read the article

  • Associate activity with database ID

    - by Mohit Deshpande
    I have a main ListView that is based on an adapter from my database. Each database id is "assigned" to an Activity via the ListView. And in my AndroidManifest, each activity has an intent filter with a custom action. Now with this, I have had to create this class: public final class ActivityLauncher { private ActivityLauncher() { } public static void launch(Context c, int id) { switch(id) { case 1: Intent intent = new Intent(); intent.setAction(SomeActivity.ACTION_SOMEACTIVITY); c.startActivity(intent); break; case 2: ... break; ... } } private static void st(Context context, String action) { Intent intent = new Intent(); intent.setAction(action); context.startActivity(intent); } } So I have to manually create a new case for the switch statement. This would get troublesome if I have to rearrange or delete an id. Is there any way to get around this?

    Read the article

  • i have a arraylist where i am verifying particular object is existing or not but even it exists it always returns false

    - by Raghavender Reddy
    hi i have class called userdata which returns the Userarraylist which is of type User. when ever i try to use contains method to check particular property is existing or not it always returns false why? Actually i want the array list to be generic which should return the objects that are set in array list. String className = data.getUserData().get(0).getClass().getSimpleName(); if(className.equalsIgnoreCase("User")) { ArrayList<User> userdata=new ArrayList(); userdata = data.getUserData(); System.out.println(data.getUserData().contains(u.getUserId())); if(userdata.contains(u.getUserName())) { System.out.println(userdata.get(0).getEmailId()); } }

    Read the article

  • Two forms but only 1 jsp file

    - by joshft91
    Here's what I've got going on. I have one .jsp file. However, I have two forms with multiple inputs inside those forms. What is the best way to detect that one form was submitted but not the other? Here's an example: I have this form: <form name = "login" action="index.jsp" method="get"> Username: <input id="username" name="username" type="text"/><br/> Password: <input id="password" name="password" type="password"/> <input type="submit" Value="Login" ></input> </form> If that button is clicked, I'd like to run this code: String username = request.getParameter("username"); String password = request.getParameter("password"); if((username!= null && !username.trim().equals("")) && (password != null && !username.trim().equals(""))) { DBentry DBentry=new DBentry(); boolean flag = DBentry.isTaken(username); if(flag) {%><script type="text/javascript">alert("Login Successful!");</script><% } else { %><script type="text/javascript">alert("Unrecognized username. Please register!");</script><% } } else { %><script type="text/javascript">alert("Please enter both a username and password!");</script><% } Further down I would have something exactly like it but submitting a different form. Thanks!

    Read the article

  • Hold most of the object in cache/memory insted of database?

    - by feiroox
    Hi All, It just occurred to me why not to have most of the objects in a cache(memory) when an application start. if it's not that large web application. Or to have a settings for how much I want to put in the cache/memory. I just guess it could require to have something like below 1 GB RAM or a lot less. Everything in order to speed up the application even more by not querying database. Is it good idea?

    Read the article

  • What would a compress method do in a hash table?

    - by Bradley Oesch
    For an assignment I have to write the code for a generic Hash Table. In an example Put method, there are two lines: int hash = key.hashCode(); // get the hashcode of the key int index = compress(hash); // compress it to an index I was of the understanding that the hashCode method used the key to return an index, and you would place the key/value pair in the array at that index. But here we "compress" the hash code to get the index. What does this method do? How does it "compress" the hash code? Is it necessary and/or preferred?

    Read the article

  • Best way of invoking getter by reflection

    - by Javi
    Hello, I need to get the value of a field with a specific annotation, So with reflection I am able to get this Field Object. The problem is that this field will be always private though I know in advance it will always have a getter method. I know that I can use setAccesible(true) and get its value (when there is no PermissionManager), though I prefer to invoke its getter method. I know that I could look for the method by looking for "get+fieldName" (though I know for example for boolean fields are sometimes named as "is+fieldName"). I wonder if there is a better way to invoke this getter (many frameworks use getters/setters to access the attributes so maybe they do in another way). Thanks

    Read the article

  • Array returning Null values

    - by Nick Gibson
    Dunno why it is...heres the coding for it. http://pastebin.org/301343 I know theres a lot of repetitiveness in the coding...but its because the arrays were retuning null so I got tired of messing with them. Everything works until it reaches line 224, which returns null values.

    Read the article

  • JSF form does not get submitted when form is disabled by JavaScript

    - by Steve
    This is the submit button: <h:commandButton actionListener="#{regBean.findReg}" action="#{regBean.navigate}" value="Search" /> This is the form: <h:form onsubmit="this.disabled=true;busyProcess();return true;"> If the submit button is pressed, the page shows a "busy" icon until request is processed. The problem is, the form is never submitted and the request never reaches the backend. However, if I instead take out the "disabled" call like so: <h:form onsubmit="busyProcess();return true;"> Then everything works. Any ideas?

    Read the article

  • Do running times match with O(nlogn)?

    - by user472221
    Hi I have written a class(greedy strategy) that at first i used sort method which has O(nlogn) Collections.sort(array, new SortingObjectsWithProbabilityField()); and then i used the insert method of binary search tree which takes O(h) and h here is the tree height. for different n ,the running time will be : n,running time 17,515428 33,783340 65,540572 129,1285080 257,2052216 513,4299709 which I think is not correct because for increasing n , the running time should almost increase. This method will take the running time: Exponent = -1; for(int n = 2;n<1000;n+=Math.pow(2,exponent){ for (int j = 1; j <= 3; j++) { Random rand = new Random(); for (int i = 0; i < n; i++) { Element e = new Element(rand.nextInt(100) + 1, rand.nextInt(100) + 1, 0); for (int k = 0; k < i; k++) { if (e.getDigit() == randList.get(k).getDigit()) { e.setDigit(e.getDigit() + 1); } } randList.add(e); } double sum = 0.0; for (int i = 0; i < randList.size(); i++) { sum += randList.get(i).getProbability(); } for (Element i : randList) { i.setProbability(i.getProbability() / sum); } //Get time. long t2 = System.nanoTime(); GreedyVersion greedy = new GreedyVersion((ArrayList<Element>) randList); long t3 = System.nanoTime(); timeForGreedy = timeForGreedy + t3 - t2; } System.out.println(n + "," + "," + timeForGreedy/3 ); exponent++; } thanks

    Read the article

  • how to make this in python

    - by user2980882
    The number reduction game Rules of the game: ? The first player to write a 0 wins. ? To start the game, Player 1 picks any whole number greater than 1, say 18. ? The players take turns reducing the number by either: o Subtracting 1 from the number his/her opponent just wrote, OR o Halving the number his/her opponent just wrote, rounding down if necessary. Write a Python program that lets two players play the number reduction game. Your program should: 1. Ask Player 1 to enter the starting number. 2. Use a while-loop to allow the players to take turns reducing the number until someone wins. 3. Each time a player enters a positive number (not 0), inform the other player what his/her choices are and ask him/her to enter the next number. 4. Declare the winner when someone enters 0. Example session: Player 1, enter a number greater than 1: 16 Player 2, your choices are 15 or 8: 15 Player 1, your choices are 14 or 7: 7 Player 2, your choices are 6 or 3:3 Player 1, your choices are 2 or 1:2 Player 2, your choices are 1 or 1:1 Player 1, your choices are 0 or 0:0 Player 1 wins

    Read the article

  • Is it possible to draw simultaneously on a panel?

    - by swift
    I have to develop a whiteboard application in which both the local user and the remote user should be able to draw simultaneously, is this possible? If possible then any logic? I have already developed a code but in which i am not able to do this, when the remote user starts drawing the shape which i am drawing is being replaced by his shape and co-ordinates. This problem is only when both draw simultaneously. any idea guys?

    Read the article

  • Unable to create session object

    - by Steven
    hi, i used the code Session session = new Configuration().configure(cfgurl).buildSessionFactory().openSession() ; to create a session. the cfgurl is of type URL and points to the hibernate.cfg.xml file of another project. The problem is it is getting hanged and unable to proceed further. What is the problem? Help

    Read the article

  • What values do the walkback array in the SocketException contain?

    - by akhilss
    Recently I have debugging into a problem where a connection to a database server from the application server get reset. I am pretty sure there is no reset being called from either end. But while I was debugging into the problem, while inspecting the SocketException, I found the walkback variable. arg0 SocketException (id=11532) cause SocketException (id=11532) detailMessage "Connection reset" stackTrace null walkback long[50] (id=11618) What do the values in this variable represent?

    Read the article

  • Sending an SMS in Android

    - by D4N14L
    Hey, I have been making an Android app which needs to send a text message. Here is the current code I have: public class getMessage extends Service { @Override public IBinder onBind(Intent intent) { return null; } @Override public void onStart(Intent intent, int startId) { super.onStart(intent, startId); client Phone = new client(); String[] msg = Phone.getMsg(user[0],user[1]); PendingIntent pi = PendingIntent.getActivity(this, 0, new Intent(this, getMessage.class), 0); SmsManager man = SmsManager.getDefault(); Log.e("GOT MESSAGE", msg[0]+ " : " +msg[1]); man.sendTextMessage(msg[0], null, msg[1], pi, null); Log.e("Message", "Sent the message?"); } Now, for some reason, the text message will not send using this code, and I'm not sure why. I was hoping that someone here could help me out in finding why this message won't send. No error is raised, nothing appears in the log (except for the log messages that I make myself in the code). Also, the manifest does have the correct tags. Suggestions?

    Read the article

  • Hot to set class variable to be visible to its public static methods?

    - by RCola
    Why I can noy access my variable p in mull form iterate method? How to resolve a problem? Hot to set class variable to be visible to its public static methods? public class mull { public static void main(String[] args) throws InterruptedException { final JPanel p = createAndShowGUI(); Timer timer = new Timer(1000, new MyTimerActionListener()); timer.start(); try { Thread.sleep(10000); } catch (InterruptedException e) { } timer.stop(); public static void iterate(){ for (int i = 0; i < 55; i++){ // "p cannot be resolved" p.moveSquare(i*10, i*10); p.setParamsRing(i*5, i*7, 200, 200); // p.repaint(); } } } class MyPanel extends JPanel { .... } How to access variable set in another method (in this example main())? Why Eclipse forces me to use this ((MyPanel) p).setParamsRing(i*5, i*7, 200, 200); instead of this p.setParamsRing(i*5, i*7, 200, 200);?

    Read the article

  • How to update JLabel in Swing?

    - by Roman
    I am trying to use Swing Timer and I wanted to start from a very simple program. I have a window with text: "You have n seconds", where n changes from 10 to 0 every second. I know how to generate a window with text. And I understand how Timer works (it starts an action periodically). But I cannot figure out how to combing this two things. Should I use that: JLabel label = new JLabel(myMessage); and then with timer I need to update the "myMessage" variable? But I think I need to "force" my window to "update" itself (to display a new value stored in "myMessage").

    Read the article

< Previous Page | 1020 1021 1022 1023 1024 1025 1026 1027 1028 1029 1030 1031  | Next Page >