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  • Error using maven profiles

    - by user3127896
    I've added two profiles to my application and that how it looks: <profiles> <profile> <id>dev</id> <properties> <db.username>root</db.username> <db.password>root</db.password> <db.connectionURL>localhost:3306</db.connectionURL> <db.driverClass>com.mysql.jdbc.Driver</db.driverClass> </properties> </profile> <profile> <id>prod</id> <properties> <db.username>prodroot</db.username> <db.password>prodpass</db.password> <db.connectionURL>localhost:3306</db.connectionURL> <db.driverClass>com.mysql.jdbc.Driver</db.driverClass> </properties> </profile> </profiles> In my jdbc.properties file i changed values like this: jdbc.driverClassName=${db.driverClass} jdbc.dialect=org.hibernate.dialect.MySQLDialect jdbc.databaseurl=jdbc:mysql://${db.connectionURL}/dbname jdbc.username=${db.username} jdbc.password=${db.password} And here's bean from spring-container.xml <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close" p:driverClassName="${jdbc.driverClassName}" p:url="${jdbc.databaseurl}" p:username="${jdbc.username}" p:password="${jdbc.password}" /> When i try to deploy my application i got following error: SEVERE: Exception sending context initialized event to listener instance of class org.springframework.web.context.ContextLoaderListener org.springframework.beans.factory.BeanDefinitionStoreException: Invalid bean definition with name 'dataSource' defined in ServletContext resource [/WEB-INF/spring-servlet.xml]: Could not resolve placeholder 'db.driverClass' Structure of project: Any ideas what i'm doing wrong? Thanks in advance!

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  • Simple question on database query.

    - by GK
    I have been asked in an interview, To write a sql query which fetches the first three records with highest value on some column from a table. i had written a query which fetched all the records with highest value, but didnt get how exactly i can get only first three records of those. could you help me in this. thanks.

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  • What Happens if i create a byte array continuously in a while loop with different size and add read an stream into it?

    - by SajidKhan
    I want to read an audio file into multiple byte arrays , with different size . And then add into a shared memory. What will happen if use below code. Does the byte array gets over written. I understand it will creat multiple byte array , how do i erase those byte arrays after my code does what it needs to do. int TotalBuffer = 10; while (TotalBuffer !=0){ bufferData = new byte[AClipTextFileHandler.BufferSize.get(j)]; input.read(bufferData); Sharedbuffer.put(bufferData); i++; j++; TotalBuffer--; }

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  • Best way of invoking getter by reflection

    - by Javi
    Hello, I need to get the value of a field with a specific annotation, So with reflection I am able to get this Field Object. The problem is that this field will be always private though I know in advance it will always have a getter method. I know that I can use setAccesible(true) and get its value (when there is no PermissionManager), though I prefer to invoke its getter method. I know that I could look for the method by looking for "get+fieldName" (though I know for example for boolean fields are sometimes named as "is+fieldName"). I wonder if there is a better way to invoke this getter (many frameworks use getters/setters to access the attributes so maybe they do in another way). Thanks

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  • Abstract class get parameter from implementing subclass?

    - by soren.qvist
    I'm wondering if there is way to do this without breaking encapsulation, I want the abstract class to rely on parameters defined in the implementing subclass. Like so: public abstract class Parent { private int size; private List<String> someList; public Parent() { size = getSize(); someList = new ArrayList<String>(size); } public abstract int getSize(); } public class Child extends Parent { @Override public int getSize() { return 5; } } Is this ugly? Is there a better way? And perhaps more importantly, is this even a good idea?

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  • Explicit constructor still has default values even though a default constructor is not invoked.

    - by Phoenix
    According to my understanding a default constructor initializes the state of the object to default values, so if i provide an explicit no-arg public constructor like this then how are the values of d and e still getting initialized to zero because in this case the default constructor is not invoked. public class B extends A{ private int d; private int e; public B() { System.out.println(d); System.out.println(e); } } EDIT:: The only thing default constructor does is call to super() then how come if i have a explicitly mentioned a constructor here and A has a protected variable say c which is initialized to 17 in its constructor. Should I not be explicitly calling super() to be able to see that change since I'm using my own constructor ? Why is B still getting the value of 17 through inheritance ?

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  • Is this Leftist Tree piece of code from Wikipedia correct?

    - by they changed my name
    Link public Node merge(Node x, Node y) { if(x == null) return y; if(y == null) return x; // if this was a max height biased leftist tree, then the // next line would be: if(x.element < y.element) if(x.element.compareTo(y.element) > 0) { // x.element > y.element Node temp = x; x = y; y = temp; } x.rightChild = merge(x.rightChild, y); if(x.leftChild == null) { // left child doesn't exist, so move right child to the left side x.leftChild = x.rightChild; x.rightChild = null; x.s = 1; } else { // left child does exist, so compare s-values if(x.leftChild.s < x.rightChild.s) { Node temp = x.leftChild; x.leftChild = x.rightChild; x.rightChild = temp; } // since we know the right child has the lower s-value, we can just // add one to its s-value x.s = x.rightChild.s + 1; } return x; } What makes me ask this question is: if(x.element.compareTo(y.element) > 0) { // x.element > y.element Node temp = x; x = y; y = temp; } Isn't that just not gonna work, since the references are only switched inside the method?

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  • Switching application-wide theme programmatically?

    - by Cheezmeister
    EDIT: Related question here: Multi theme support in android app I'm attempting to get a user-chosen theme and feel like I'm frustratingly close. Defining the theme in AndroidManifest.xml works as it should, but (as best I can tell) can't change based on app preferences: <application android:theme="@style/theme_sunshine" android:icon="@drawable/icon" android:label="@string/app_name"> Alternatively, setting it dynamically in each activity also works: someChosenTheme = PreferenceManager.getDefaultSharedPreferences(this).getString("themePreference", "theme_twilight"); setTheme(someOtherChosenTheme); But that seems messy, and I'd rather set the theme for the entire app in one place. My first thought was to grab the application context as soon as my main activity launches and do it there: getApplicationContext().setTheme(R.style.theme_dummy); As best I can tell[0], this ought to do the trick, but in fact it's not doing anything--the entire app has the default Android style. Is the above valid, and if so, might I be doing something else dumb? I'm working in API level 3 if that matters. Prods in the right direction greatly appreciated! [0] http://developer.android.com/reference/android/content/Context.html#setTheme%28int%29 http://developer.android.com/reference/android/content/Context.html#getApplicationContext%28%29

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  • question about quicksort 3 way partition

    - by davit-datuashvili
    i want implement quicksort 3 way partition here is code public class quick3{ public static void quicksort3(int a[],int l,int r){ int k; int v=a[r]; if (r<=l) return; int i=l; int j=r; int p=l-1; int q=r; for (;;) { while (a[++i]<v); while (v<a[--j]) if (j==i) break; if (i>=j) break; swap( a,i, j); if (a[i]==v){ p++; swap(a,p,i);} if (v==a[j]){ q--; swap( a,q,j); } } swap(a,i,r); j=i-1; i=i+1; for (k=1;k<=p;k++,j--) swap(a,k,j); for (k=r-1;k>=q;k--,i++) swap(a,k,i); quicksort3(a,l,j); quicksort3(a,i,r); } public static void main(String[]args){ int a[]=new int[]{4,6,5,9,7,8,3}; quicksort3(a,0,a.length-1); for (int i=0;i<a.length;i++){ System.out.println(a[i]); } } public static void swap(int a[],int i,int j){ int t=a[i]; a[i]=a[j]; a[j]=t; } } after change result is 4 8 7 6 3 5 9 any suggestion?please help

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  • division problems

    - by David
    This line of code: System.out.println ("aray[j], "+aray[j]+", divided by sum, "+sum+", equals: aray[j]/sum: "+ aray[j]/sum) ; is yeilding this line of text: aray[j], 21, divided by sum, 100, equals: aray[j]/sum: 0 why is it doing this? (everything is right eccept that the answer should be .21)

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  • Resultset To List

    - by Gnaniyar Zubair
    I want to convert my Resultset to List in my JSP page. and want to display all the values. This is my query: SELECT userId, userName FROM user; I have executed that using preparedstatement and got the Resultset. But how to convert it as a List and want to display the result like this: userID userName ------------------ 1001 user-X 1006 user-Y 1007 user-Z

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  • what is difference between JDK 1.4 and JDK1.6.

    - by Vipin Nemade
    hi friend, I have created the project using the JDK 1.4. Now I want to use JDK 1.6 version in my project. for this what steps are required.Means I want to know the what changes is require in code to get a JDK 1.6 feature.Basically I am talking about the features that is added in JDK 1.6. If any one list out that changes it is very helpful. Thanks in advance..............................

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  • Hibernate subclass with foreign key relationships

    - by shikarishambu
    I need some help defining the following object hierarchy/ database relationship in Hibernate From the object sense – Agent is inherited from Person and Agency is inherited from Organization. they are inherited from Party which can have multiple Addresses associated with it The database consists of Agent - ID - Name -PartyID (references Party.ID) Agency -ID -Name -PartyID (references Party.ID) Address -AddrID -PartyID (references Party.ID) -Street Party. -PartyID

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  • Finding the specific type held in an ArrayList<Object> (ie. Object = String, etc.)

    - by Christopher Griffith
    Say I have an ArrayList that I have cast to an ArrayList of objects. I know that all the objects that were in the ArrayList I cast were of the same type, but not what the type was. Now, if the ArrayList is not empty, I could take one of the objects in it and use the instanceof operator to learn what the actual type is. But what of the case where the ArrayList is empty? How do I determine what type Object actually is then? Is it possible?

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  • Creating Linear Layout with TextViews using a for loop

    - by cad8
    Hi all, I was wondering if there is a way to dynamically create an additional linear layout with a textview within a predefined liner layout. THis is my code so you get the gist of what I am asking: LinearLayout MainLL= (LinearLayout) findViewById(R.id.myLayoutId); for(int i=0; i<5; i++) { LinearLayout childLL= new LinearLayout(this); childLL.setOrientation(LinearLayout.VERTICAL); childLL.setLayoutParams(new LayoutParams(LayoutParams.FILL_PARENT, LayoutParams.FILL_PARENT)); childLL.setGravity(Gravity.LEFT); TextView text = new TextView(this); text.setText("The Value of i is :"i); text.setTextSize(12); text.setGravity(Gravity.LEFT); text.setLayoutParams(new LayoutParams(LayoutParams.FILL_PARENT, LayoutParams.WRAP_CONTENT)); childLL.addView(text); MainLL.addView(childLL); } My problem is that I am only getting "The Value of i is :0" as the output, i.e. the first instance. Any help would be much appreciated

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  • Is it standard behavior for this code to throw a NullPointerException?

    - by Eric
    I've had a big problem in some library code, which I've pinned down to a single statement: System.out.println((String) null); Ok, the code doesn't actually look like that, but it certainly calls println with a null argument. Doing this causes my whole applicaio to throw an unexpected NullPointerException. In general, should println throw this exception under that circumstance, or is this non-standard behavior due to a poor implementation of the out instance?

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  • Struts html:checkbox query

    - by sarah
    Hi All, i have the following code . <td> <html:checkbox name="userForm" property="isActive" /></td> and in Form is have property called isActive of type char ,how would i get the checked value of it ,i am getting some symbols like 'o' if checked. I am using userform.getIsActive() ,where i am going wrong .I want 'y' or 'n' values

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  • Netbeans configuration problem

    - by Yatendra Goel
    I am using Netbeans 6.8 The problem is that the projects explorer (that displays all the projects and their contents) displays each package as a node. For instance, if there is package hierarchy like this; com.mycompany.myproject.package1.package1.1 then it displays 5 nodes for the five packages which is very disturbing while development. Is there any way by which I can configure it(Netbeans) so that it groups all the subpackages of a package under one node and displays the subpackages only when I expand the package node?

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