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  • I can't load the css files

    - by mfalcon
    I want to load some .css files to my Django project but I don't know why they aren't loaded. The css files are located at "/myproject/media/css". settings.py: import os.path PROJECT_DIR = os.path.dirname(__file__) MEDIA_ROOT = os.path.join(PROJECT_DIR, 'media') urls.py: from django.conf import settings ... (r'^media/(?P<path>.*)$', 'django.views.static.serve', {'document_root': settings.MEDIA_ROOT, 'show_indexes': True}), ) base.html: <link rel="stylesheet" type="text/css" media="all" href="{{ MEDIA_ROOT }}css/myStyle.css" />

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  • Wrong sessionID being used in callback, but only on one particular computer

    - by user210119
    I am writing a Python/Django web application that uses OAuth (for the TwitterAPI, not that it should matter). I am storing a session ID in my login function, and then after using OAuth to get the user's token, I try to retrieve the sessionID in my callback function. The callback function then always fails(throws an exception) because it can't find the OAuth token in the session. Through the debugger, I am able to determine that the session ID that the server is using is incorrect - it does not match the session ID that was stored in the login function. It's therefore unsurprising that the Oauth tokens were not there. The session that appears in the callback was the same one each time (until I tried deleting it - see "things I've tried below"), and it started out as an old session, with some data in it that is from a different django app running on the same server that I hadn't touched in a couple weeks. Here's the kicker: everything I described is an issue only on our production server, and only when connecting to it from my computer. Let me clarify: this only happens with my particular laptop. I can connect to the app just fine from someone else's computer. Other people cannot connect with their accounts on my computer. Furthmore, I can connect just fine to the app when it is running on my localhost using the built-in django webserver, just not to the production server. My setup: my server and local box are running= Django 1.2.0 and Python 2.6.5. My local box is running Snow Leopard and the Django webserver, the server is running Ubuntu, Apache2, and mod-wsgi. For sessions, I am using Django's default session backend (DB). Things I have tried, all to no avail: logging in with a different account, including new accounts that have never OAuthed to this app before Clearing cookies, using incognito mode, using a different web browser on my same computer. Each time, upon inspecting my cookies, the sessionID matched the sessionID in the login function and was different from the sessionID in the callback. deleting the session in the database that appears in the callback function, (the one that appeared to be old data). The callback function still fails, and the sessionID it appears to be using is now a new one using a different session backend (DB-cache, flat file, etc...) restarting the server, my computer, etc. My first question on StackOverflow, so bear with me if I didn't quite follow local conventions. I am just at a loss as to what to even look for - what are the things that could possibly be causing sessions to not work on my particular computer, and (so far!) only my particular computer?

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  • Would this hack for per-object permissions in django work?

    - by Edward
    According to the documentation, a class can have the meta option permissions, described as such: Options.permissions Extra permissions to enter into the permissions table when creating this object. Add, delete and change permissions are automatically created for each object that has admin set. This example specifies an extra permission, can_deliver_pizzas: permissions = (("can_deliver_pizzas", "Can deliver pizzas"),) This is a list or tuple of 2-tuples in the format (permission_code, human_readable_permission_name). Would it be possible to define permissions at run time by: permissions = (("can_access_%s" % self.pk, / "Has access to object %s of type %s" % (self.pk,self.__name__)),) ?

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  • Why can't I save my model with a generic relation twice in Django?

    - by e-satis
    I got a model TrackedItem with a generic relation linking to any model it is supposed to track. If I do that: t = TrackedItem(content_object=MyModel) t.save() t.save() I get : IntegrityError: (1062, "Duplicate entry '1' for key 'PRIMARY'") Indeed, the first save has created an entry with "1" as a PK. But the second save should not insert, it should update. How am I suppose to update a model I can't save twice? With an ordinary model I can save as much as I want.

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  • What is the best way to format Django urls for two parameters, either of which are optional?

    - by Parker
    I'm designing a gallery application for viewing vehicle pictures and there are two parameters: Manufacturer Vehicle type Right now you can view either, but not both. Urls go like so: /manufacturer/# /type/# Where # is an ID number. How/can I format my URLs so it can accept both? My current solution is to do: /both/#/# but this requires some retooling since the application doesn't know when you want to filter by both. Any insight would be appreciated.

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  • Why is django admin not accepting Nullable foreign keys?

    - by p.g.l.hall
    Here is a simplified version of one of my models: class ImportRule(models.Model): feed = models.ForeignKey(Feed) name = models.CharField(max_length=255) feed_provider_category = models.ForeignKey(FeedProviderCategory, null=True) target_subcategories = models.ManyToManyField(Subcategory) This class manages a rule for importing a list of items from a feed into the database. The admin system won't let me add an ImportRule without selecting a feed_provider_category despite it being declared in the model as nullable. The database (SQLite at the moment) even checks out ok: >>> .schema ... CREATE TABLE "someapp_importrule" ( "id" integer NOT NULL PRIMARY KEY, "feed_id" integer NOT NULL REFERENCES "someapp_feed" ("id"), "name" varchar(255) NOT NULL, "feed_provider_category_id" integer REFERENCES "someapp_feedprovidercategory" ("id"), ); ... I can create the object in the python shell easily enough: f = Feed.objects.get(pk=1) i = ImportRule(name='test', feed=f) i.save() ...but the admin system won't let me edit it, of course. How can I get the admin to let me edit/create objects without specifying that foreign key?

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  • how to read a static file in .py file using django ..

    - by zjm1126
    this is my error code: text = open('/media/a.txt', 'rb').read() and my perplexed is: when i use this : text = open('a.txt', 'rb').read() it can be running but when i put the 'a.txt' to the 'media' folder, i can't running , why ? thanks IOError at / [Errno 13] file not accessible: '/media/a.txt'

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  • How do I use Django to insert a Geometry Field into the database?

    - by alex
    class LocationLog(models.Model): user = models.ForeignKey(User) utm = models.GeometryField(spatial_index=True) This is my database model. I would like to insert a row. I want to insert a circle at point -55, 333. With a radius of 10. How can I put this circle into the geometry field? Of course, then I would want to check which circles overlap a given circle. (my select statement)

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  • Django: way to test what class a generic relation content_object is?

    - by bitbutter
    In my project I have a class, NewsItem. Instances of NewsItem act like a wrapper. They can be associated with either an ArtWork instance, or an Announcement instance. Here's how the NewsItem model looks: class NewsItem(models.Model): content_type = models.ForeignKey(ContentType) object_id = models.PositiveIntegerField() content_object = generic.GenericForeignKey('content_type', 'object_id') date = models.DateTimeField(default=datetime.datetime.now,) class Meta: ordering = ('-date',) def __unicode__(self): return (self.title()) In a template I'm dealing with a NewsItem instance, and would like to output a certain bunch of html it it's 'wrapping' an Artwork instance, and a different bunch of html if it's wrapping an Announcement instance. Could someone explain how I can write a conditional to test for this? My first naive try looked like this: {% if news_item.content_object.type=='Artwork' %}do this{% else %}do that{% endif %}

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  • How do I use django settings in my logging.ini file?

    - by slypete
    I have a BASE_DIR setting in my settings.py file: BASE_DIR = os.path.dirname(os.path.abspath(__file__)) I need to use this variable in my logging.ini file to setup my file handler paths. The initialization of logging happens in the same file, the settings.py file, below my BASE_DIR variable: LOG_INIT_DONE=False if not LOG_INIT_DONE: logging.config.fileConfig(LOGGING_INI) LOG_INIT_DONE=True Thanks, Pete

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  • Custom rendering a radioselect in django form / accessing single element?

    - by Oli
    I have a form like this: CHOICES = [ ('a', 'a_value'), ('b', 'b_value'), ('c', 'c_value') ] self.fields["choice"] = forms.ChoiceField( widget=RadioSelect(), choices=CHOICES, ) How can I select a single element of this form field in my template? I want to be able to do something like: <tr><td>{{form.choice.a}}</td><td>some custom extra field</td></tr> Or is there another way to change how the RadioSelect is rendered?

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  • Is it hacky to manually construct JSON and manually handle GET, POST instead of using a proper RESTful API for AJAX functionality?

    - by kliao
    I started building a Django app, but this probably applies to other frameworks as well. In Backbone.js methods that call the server (fetch(), create(), destroy(), etc.), should you be using a proper RESTful API such as one provided by Tastypie or Django-Piston? I've founded it easier and more flexible to just construct the JSON in my Django Views, which are mapped to some URLs that Backbone.js can use. Then again, I'm probably not leveraging Tastypie/Django-Piston functionality to the fullest. I'm not ready to make a full-fledged RESTful API for my app yet. I simply would like to use some of the AJAXy functionality that Backbone.js supports. Pros/Cons of doing this?

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  • Translate model fields' attributes from a Database with Django?

    - by Luiz C.
    I'm trying to create a Model that has fields that have the following attributes translatable: verbose_name and choices. I can easily do this by tagging the strings and using the i18l middleware. The problem is that I don't want to define the translation in po/mo files. Is there a way to pull this data from a database table? If so, any examples? There are some options out there that offer model content translation. That is not my case. I need to translate the verbose_name, choices and error_messages from database.

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  • How do I create a Django ModelForm, so that it's fields are sometimes required, sometimes not?

    - by Graf
    Ok, here is the question. Imagine I have a ModelForm which have only two fields. like this one: class ColorForm(forms.Form): color_by_name = forms.CharField() color = forms.IntegerField(widget = forms.Select(choices=COLOR_CHOICES)) So a user can either input a color name, a choose it from a list. Color is required, but that doesn't mean, that user should enter it manually. There do I put validation, so that my code checks if user selected color in dropdownlist and if not then he should write it manually?

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