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  • Is there a free PDF printer / distiller that creates signable documents?

    - by Coderer
    I've used various methods (mentioned elsewhere on this site) to create PDFs, using a printer driver or converting from PostScript, etc. The common problem is that if I open any of the output files in the newer versions of Adobe Reader, there's an option to "Place Signature" but it's greyed out, or gives an error message that the feature has been disabled for this document. As far as I can tell, there's an option set somewhere in the document metadata that tells Reader "allow the user to sign this document", or don't. None of the free/open source tools that have been been linked to in other SU posts have had this listed as an option (though to be fair I haven't actually downloaded and tried all of them). Is there a tool that does this? Can I just poke a bit with a hex editor somewhere to turn on this functionality? I can sometimes get access to Acrobat Professional to turn on this option, but doing it for every desired case would be more work than I care to do. The current workaround for single-page documents is: Print the document to PDF (possibly via postscript) Open a single-page blank PDF with the "signable" bit turned on in Reader create a custom "stamp" using the Reader markup tools, by importing the printed-to document "stamp" an image of the printed document on the blank page, hoping to get it centered about right place a signature over the document-but-not-really you just stamped This obviously does not scale well at all. It would be much better if I could: Print the document to PDF Drag the document to a simple shortcut / tool / whatever Open the document in Reader Place a signature in the document ETA: Sorry, maybe I should have been clearer -- I'm talking about the certificate-based digital signing available in Adobe Reader, not adding a virtual ink signature. Also, any solution really would have to be available offline.

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  • How to show "only number" in picture cross-reference in Word 2007 document?

    - by kornelijepetak
    I have many pictures in a document and I reference them very often in text. I don't want to lose the order so I am using Insert - Cross-reference. This opens the cross-reference dialog where I can set Reference type to Picture. For "Insert reference to", there are 5 choices: - Entire caption - Only label and number - Only caption text - Page number - Above/below What I need is a reference that would be inserted like this: [4], and not like this: [Picture 4]; None of these options enable me to do it. Is there any way to make Word 2007 insert a reference to only Caption Number? Note: The document is written in Croatian language which has 7 declension cases, so using "Picture 4" would not be valid in all cases. Actually caption label Picture is set to croatian word "Slika" and when I need to say say "in the picture" I can't because it would be "na Slici 5." and not "na Slika 5." (like Word would make me do). That's why I need to reference only the caption number. Is that possible in Word 2007?

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  • Why is XSP/mono giving me file/write errors with lucence?

    - by acidzombie24
    I am using mono 2.6.7, xsp 2.8.? and i am not sure what else. I'll try downgrading xsp and whatever else. Today i notice my server randomly gets Http Error 500, internal server error. I looked in my log files http://www.pastie.org/1426236 and it appears that the problem is locking lucence which it does by creating a file called write.lock. This use to work with no problem but now it gives me pain. It will fix itself if i refresh the page several times but it will break just as easily. My other site will not work everytime i restart apache and i need to by hand delete the file (at least it doesnt get random 500 errors). However now it just says Lock obtain timed out: NativeFSLock@/var/www/SITE_2/App_Data/LuceneIndex_a/write.lock no matter what. I even chmod -R 777 the directory and still no luck. write.lock doesnt even exist. I have no clue whats going on. Any ideas?

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  • xpath 2.0 query - how to test for the first occurence of an element in a xml document

    - by Mike
    I have the following xsl template: <xsl:template match="para"> <fo:block xsl:use-attribute-sets="paragraph.para"> <!-- if first para in document --> <!--<xsl:if test="//para[1] intersect .">--> <xsl:if test="//para[1] intersect ."> <xsl:attribute name="space-after">10pt</xsl:attribute> <xsl:attribute name="background-color">yellow</xsl:attribute> </xsl:if> <xsl:choose> <xsl:when test="preceding-sibling::*[1][self::title]"> <xsl:attribute name="text-indent">0em</xsl:attribute> </xsl:when> <xsl:when test="parent::item"> <xsl:attribute name="text-indent">0em</xsl:attribute> </xsl:when> <xsl:otherwise> <xsl:attribute name="text-indent">1em</xsl:attribute> </xsl:otherwise> </xsl:choose> <xsl:apply-templates/> </fo:block> </xsl:template> The problem I am having is selecting the very first para node in the document from the following xml: <document> <section> <paragraph> <para>Para Text 1*#</para> <para>Para Text 2</para> </paragraph> </section> <paragraph> <para>Para Text 3*</para> <para>Para Text 4</para> <para>Para Text 5</para> <sub-paragraph> <para>Para Text 6*</para> <para>Para Text 7</para> </sub-paragraph> </paragraph> <appendix> <paragraph> <para>Para Text 8*</para> </paragraph> <paragraph> <para>Para Text 9</para> </paragraph> </appendix> </document> the xpath I am currently using is "//para[1] intersect ." which is selecting the first para for each group of para (denoted with a * in XML sample). Any ideas on how I can just select the first occurance of para within document (denoted with a #)?

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  • Integrating OSB - B2B for a healthcare scenario

    - by Ramesh Nittur
    Usecase 1: Admin to send a HL7 Message to Pharmacy. OSB to use B2B for translating the XML document to HL7 native document using the translation webservice exposed by B2B. B2B configuration Oracle B2B 11g PS2 release has exposed a webservices to translate XML document to Native document. This service needs an outbound agreement configured with "HL7 Message Facility ID" as the Identifier. Document Type and revision can be identified from the document itself. B2B translation webservice can be used in two mode, one for only translation and another for translation and routing. OSB-B2B Integration sample are developed based on the "b2b-005-hl7" sample in OTN. We are not going to discuss about the b2b metadata configuration creation details, as it is dealt detail in OTN sample document. OSB Configuration Steps to create OSB Configuration sample: Create a OSB Project with name OSB-B2B Create BusinessService with name B2BBusinessService to consume B2B TranslateService URL http://<host:8001>/b2b/services/ TranslateService

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  • Pass data from one form to another on a seperate page

    - by Micanio
    I am building a price/distance calculator with Google Maps API and am trying to pass the info from the calculator to a booking form on a separate page. My first form has 2 submit buttons - one to make the calculation, and one to submit the relevant data to the booking form. I'm stuck trying to make the 2nd button work. Once the API calculation has been made, I get 4 values - From, To, Cost, Distance. I am trying to pass the From, To and Cost values into my booking form by clicking the second button. But I can;t seem to get it to work. I've tried POST and GET but I think I may have been doing something wrong with both. Any help is appreciated. Code for API form: <script type="text/javascript" src="http://maps.google.com/maps?file=api&amp;v=2&amp;key=ABQIAAAAwCUxKrPl8_9WadET5dc4KxTqOwVK5HCwTKtW27PjzpqojXnJORQ2kUsdCksByD4hzcGXiOxvn6C4cw&sensor=true"></script> <script type="text/javascript"> var geocoder = null; var location1 = null; var location2 = null; var gDir = null; var directions = null; var total = 0; function roundNumber(num, dec) { var result = Math.floor(num*Math.pow(10 ,dec))/Math.pow(10,dec); return result; } function from(form) { address1=form.start.options[form.start.selectedIndex].value form.address1.value=address1 form.address1.focus() } function to(form) { address2=form.end.options[form.end.selectedIndex].value form.address2.value=address2 form.address2.focus() } function initialize() { var map = new GMap2(document.getElementById("map_canvas")); map.setCenter(new GLatLng(54.019066,-1.381531),9); map.setMapType(G_NORMAL_MAP); geocoder = new GClientGeocoder(); gDir = new GDirections(map); GEvent.addListener(gDir, "load", function() { var drivingDistanceMiles = gDir.getDistance().meters / 1609.344; var drivingDistanceKilometers = gDir.getDistance().meters / 1000; var miles = drivingDistanceMiles.toFixed(0); //var cost = (((miles - 1) * 1.9) + 3.6).toFixed(2); var meters = gDir.getDistance().meters.toFixed(1); if(miles < 70){ var cost = miles *1.75; } if(miles >70){ var cost = miles *1.2; } document.getElementById('from').innerHTML = '<strong>From: </strong>' + location1.address; document.getElementById('to').innerHTML = '<strong>To: </strong>' + location2.address; document.getElementById('cost').innerHTML = '<span class="fare"><strong>Estimated Taxi FARE:</strong>' + ' £' + cost.toFixed(2) + '</span>'; document.getElementById('miles').innerHTML = '<strong>Distance: </strong>' + miles + ' Miles'; }); } function showLocation() // start of possible values for address not recognized on google search // values for address1 { if (document.forms[0].address1.value == "heathrow" || document.forms[0].address1.value == "Heathrow" || document.forms[0].address1.value == "heathrow airport" || document.forms[0].address1.value == "Heathrow Airport" || document.forms[0].address1.value == "London Heathrow" || document.forms[0].address1.value =="london heathrow" ) { (document.forms[0].address1.value = "Heathrow Airport"); } if (document.forms[0].address2.value == "heathrow" || document.forms[0].address2.value == "Heathrow" || document.forms[0].address2.value == "heathrow airport" || document.forms[0].address2.value == "Heathrow Airport" || document.forms[0].address2.value == "London Heathrow" || document.forms[0].address2.value =="london heathrow" ) { (document.forms[0].address2.value = "Heathrow Airport"); } geocoder.getLocations(document.forms[0].address1.value + document.forms[0].uk.value || document.forms[0].start.value + document.forms[0].uk.value, function (response) { if (!response || response.Status.code != 200) { alert("Sorry, we were unable to find the first address"); } else { location1 = {lat: response.Placemark[0].Point.coordinates[1], lon: response.Placemark[0].Point.coordinates[0], address: response.Placemark[0].address}; geocoder.getLocations(document.forms[0].address2.value + document.forms[0].uk.value, function (response) { if (!response || response.Status.code != 200) { alert("Sorry, we were unable to find the second address"); } else { location2 = {lat: response.Placemark[0].Point.coordinates[1], lon: response.Placemark[0].Point.coordinates[0], address: response.Placemark[0].address}; gDir.load('from: ' + location1.address + ' to: ' + location2.address); } }); } }); } </script> <style> #quote { font-family: Georgia, "Times New Roman", Times, serif; } </style> </head> <body style="background-color: rgb(255, 255, 255);" onUnload="GUnload()" onLoad="initialize()"> <div id="sidebar"> <!--MAPS--> <div id="calc_top"></div> <div id="calc_body"> <div id="calc_inside"> <span style="font-size: 16px; font-weight: bold;">Get A Quote Now</span> <p class="disclaimer">Fares can be calculated using either Area, Exact Address or Postcode, when entering address please include both road name and area i.e. <em>Harrogate Road, Ripon</em>. You can also select a pickup point and destination from the dropdown boxes. </p> <form onSubmit="showLocation(); return false;" action="#" id="booking_form"> <p> <select onChange="from(this.form)" name="start"> <option selected="selected">Select a Pickup Point</option> <option value="Leeds Bradford Airport">Leeds Bradford Airport</option> <option value="Manchester Airport">Manchester Airport</option> <option value="Teesside International Airport">Teeside Airport</option> <option value="Liverpool John Lennon Airport">Liverpool Airport</option> <option value="East Midlands Airport">East Midlands Airport</option> <option value="Heathrow International Airport">Heathrow Airport</option> <option value="Gatwick Airport">Gatwick Airport</option> <option value="Stanstead Airport">Stanstead Airport</option> <option value="Luton International Airport">Luton Airport</option> </select> </p> <p> <input type="text" value="From" name="address1"><br> <p> <select onChange="to(this.form)" name="end"> <option selected="selected">Select a Destination</option> <option value="Leeds Bradford Airport">Leeds Bradford Airport</option> <option value="Manchester Airport">Manchester Airport</option> <option value="Teesside International Airport">Teeside Airport</option> <option value="Liverpool John Lennon Airport">Liverpool Airport</option> <option value="East Midlands Airport">East Midlands Airport</option> <option value="Heathrow International Airport">Heathrow Airport</option> <option value="Gatwick Airport">Gatwick Airport</option> <option value="Stanstead Airport">Stanstead Airport</option> <option value="Luton International Airport">Luton Airport</option> </select> </p> <input type="text" value="To" name="address2"><br> <input type="hidden" value=" uk" name="uk"> <br> <input type="submit" value="Get Quote"> <input type="button" value="Reset" onClick="resetpage()"><br /><br /> <input type="submit" id="CBSubmit" value="Confirm and Book" action=""/> </p> </form> <p id="from"><strong>From:</strong></p> <p id="to"><strong>To:</strong></p> <p id="miles"><strong>Distance: </strong></p> <p id="cost"><span class="fare"><strong>Estimated Taxi FARE:</strong></span></p> <p id="results"></p> <div class="style4" style="width: 500px; height: 500px; position: relative; background-color: rgb(229, 227, 223);" id="map_canvas"></div> </div> </div> Code for Booking Form: <form method="post" action="contactengine.php" id="contact_form"> <p> <label for="Name" id="Name">Name:</label> <input type="text" name="Name" /> <label for="Email" id="Email">Email:</label> <input type="text" name="Email" /> <label for="tel" id="tel">Tel No:</label> <input type="text" name="tel" /><br /><br /> <label for="from" id="from">Pickup Point:</label> <input type="text" name="from" value="" /><br /><br /> <label for="to" id="to">Destination:</label> <input type="text" name="to" value=""/><br /> <label for="passengers" id="passengers">No. of passengers</label> <input type="text" name="passengers" /><br /><br /> <label for="quote" id="quote">Price of journey:</label> <input type="text" name="quote" value="" /><br /><br /> <label for="Message" id="Message">Any other info:</label> <textarea name="Message" rows="20" cols="40"></textarea> <br /> Are you an account holder?<br /> <label for="account" id="yes" /> Yes:</label> <input type="radio" class="radio" value="yes" name="account"> <label for="account" id="yes" /> No:</label> <input type="radio" class="radio" value="no" name="account"> </p> <small>Non-account holders will have to pay a £5 booking fee when confirming thier booking</small> <input type="submit" name="submit" value="Submit" class="submit-button" /> </p> </form> Thanks in advance

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  • How to build a Singleton-like dependency injector replacement (Php)

    - by Erparom
    I know out there are a lot of excelent containers, even frameworks almost entirely DI based with good strong IoC classes. However, this doesn't help me to "define" a new pattern. (This is Php code but understandable to anyone) Supose we have: //Declares the singleton class bookSingleton { private $author; private static $bookInstance; private static $isLoaned = FALSE; //The private constructor private function __constructor() { $this->author = "Onecrappy Writer Ofcheap Novels"; } //Sets the global isLoaned state and also gets self instance public static function loanBook() { if (self::$isLoaned === FALSE) { //Book already taken, so return false return FALSE; } else { //Ok, not loaned, lets instantiate (if needed and loan) if (!isset(self::$bookInstance)) { self::$bookInstance = new BookSingleton(); } self::$isLoaned = TRUE; } } //Return loaned state to false, so another book reader can take the book public function returnBook() { $self::$isLoaned = FALSE; } public function getAuthor() { return $this->author; } } Then we get the singelton consumtion class: //Consumes the Singleton class BookBorrower() { private $borrowedBook; private $haveBookState; public function __construct() { this->haveBookState = FALSE; } //Use the singelton-pattern behavior public function borrowBook() { $this->borrowedBook = BookSingleton::loanBook(); //Check if was successfully borrowed if (!this->borrowedBook) { $this->haveBookState = FALSE; } else { $this->haveBookState = TRUE; } } public function returnBook() { $this->borrowedBook->returnBook(); $this->haveBookState = FALSE; } public function getBook() { if ($this->haveBookState) { return "The book is loaned, the author is" . $this->borrowedbook->getAuthor(); } else { return "I don't have the book, perhaps someone else took it"; } } } At last, we got a client, to test the behavior function __autoload($class) { require_once $class . '.php'; } function write ($whatever,$breaks) { for($break = 0;$break<$breaks;$break++) { $whatever .= "\n"; } echo nl2br($whatever); } write("Begin Singleton test", 2); $borrowerJuan = new BookBorrower(); $borrowerPedro = new BookBorrower(); write("Juan asks for the book", 1); $borrowerJuan->borrowBook(); write("Book Borrowed? ", 1); write($borrowerJuan->getAuthorAndTitle(),2); write("Pedro asks for the book", 1); $borrowerPedro->borrowBook(); write("Book Borrowed? ", 1); write($borrowerPedro->getAuthorAndTitle(),2); write("Juan returns the book", 1); $borrowerJuan->returnBook(); write("Returned Book Juan? ", 1); write($borrowerJuan->getAuthorAndTitle(),2); write("Pedro asks again for the book", 1); $borrowerPedro->borrowBook(); write("Book Borrowed? ", 1); write($borrowerPedro->getAuthorAndTitle(),2); This will end up in the expected behavior: Begin Singleton test Juan asks for the book Book Borrowed? The book is loaned, the author is = Onecrappy Writer Ofcheap Novels Pedro asks for the book Book Borrowed? I don't have the book, perhaps someone else took it Juan returns the book Returned Book Juan? I don't have the book, perhaps someone else took it Pedro asks again for the book Book Borrowed? The book is loaned, the author is = Onecrappy Writer Ofcheap Novels So I want to make a pattern based on the DI technique able to do exactly the same, but without singleton pattern. As far as I'm aware, I KNOW I must inject the book inside "borrowBook" function instead of taking a static instance: public function borrowBook(BookNonSingleton $book) { if (isset($this->borrowedBook) || $book->isLoaned()) { $this->haveBook = FALSE; return FALSE; } else { $this->borrowedBook = $book; $this->haveBook = TRUE; return TRUE; } } And at the client, just handle the book: $borrowerJuan = new BookBorrower(); $borrowerJuan-borrowBook(new NonSingletonBook()); Etc... and so far so good, BUT... Im taking the responsability of "single instance" to the borrower, instead of keeping that responsability inside the NonSingletonBook, that since it has not anymore a private constructor, can be instantiated as many times... making instances on each call. So, What does my NonSingletonBook class MUST be in order to never allow borrowers to have this same book twice? (aka) keep the single instance. Because the dependency injector part of the code (borrower) does not solve me this AT ALL. Is it needed the container with an "asShared" method builder with static behavior? No way to encapsulate this functionallity into the Book itself? "Hey Im a book and I shouldn't be instantiated more than once, I'm unique"

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  • to change the style of div

    - by ramyatk06
    hi guys, I have 2 buttons and 2 divs div1 and div2.On click button1 div1 is made visible and div2 invisible,On clicking button2 div2 is made visible and div1 is invisible. For that i used javascript. function showdiv2() { document.getElementById("div2").style.visibility="visible"; document.getElementById("div2").style.display="inline"; document.getElementById("div1").style.visibility="hidden"; document.getElementById("div1").style.display = "none"; document.getElementById("lbl_msg").innerHTML = "" } function showdiv1() { document.getElementById("div1").style.visibility="visible"; document.getElementById("div1").style.display="inline"; document.getElementById("div2").style.visibility="hidden"; document.getElementById("div2").style.display = "none"; document.getElementById("lbl_msg").innerHTML = "" } In div2 i have a gridview in which i have a linkbutton named lnkDelete.In its click control is going to div1.In click of lnkDelete,i want to make div1 invisible,but on clicking button1 div1 should be visible.Can anybody help to make div1 invisible in clickevent of lnkDelete in codebehind?

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  • o write a C++ program to encrypt and decrypt certain codes.

    - by Amber
    Step 1: Write a function int GetText(char[],int); which fills a character array from a requested file. That is, the function should prompt the user to input the filename, and then read up to the number of characters given as the second argument, terminating when the number has been reached or when the end of file is encountered. The file should then be closed. The number of characters placed in the array is then returned as the value of the function. Every character in the file should be transferred to the array. Whitespace should not be removed. When testing, assume that no more than 5000 characters will be read. The function should be placed in a file called coding.cpp while the main will be in ass5.cpp. To enable the prototypes to be accessible, the file coding.h contains the prototypes for all the functions that are to be written in coding.cpp for this assignment. (You may write other functions. If they are called from any of the functions in coding.h, they must appear in coding.cpp where their prototypes should also appear. Do not alter coding.h. Any other functions written for this assignment should be placed, along with their prototypes, with the main function.) Step 2: Write a function int SimplifyText(char[],int); which simplifies the text in the first argument, an array containing the number of characters as given in the second argument, by converting all alphabetic characters to lower case, removing all non-alpha characters, and replacing multiple whitespace by one blank. Any leading whitespace at the beginning of the array should be removed completely. The resulting number of characters should be returned as the value of the function. Note that another array cannot appear in the function (as the file does not contain one). For example, if the array contained the 29 characters "The 39 Steps" by John Buchan (with the " appearing in the array), the simplified text would be the steps by john buchan of length 24. The array should not contain a null character at the end. Step 3: Using the file test.txt, test your program so far. You will need to write a function void PrintText(const char[],int,int); that prints out the contents of the array, whose length is the second argument, breaking the lines to exactly the number of characters in the third argument. Be warned that, if the array contains newlines (as it would when read from a file), lines will be broken earlier than the specified length. Step 4: Write a function void Caesar(const char[],int,char[],int); which takes the first argument array, with length given by the second argument and codes it into the third argument array, using the shift given in the fourth argument. The shift must be performed cyclicly and must also be able to handle negative shifts. Shifts exceeding 26 can be reduced by modulo arithmetic. (Is C++'s modulo operations on negative numbers a problem here?) Demonstrate that the test file, as simplified, can be coded and decoded using a given shift by listing the original input text, the simplified text (indicating the new length), the coded text and finally the decoded text. Step 5: The permutation cypher does not limit the character substitution to just a shift. In fact, each of the 26 characters is coded to one of the others in an arbitrary way. So, for example, a might become f, b become q, c become d, but a letter never remains the same. How the letters are rearranged can be specified using a seed to the random number generator. The code can then be decoded, if the decoder has the same random number generator and knows the seed. Write the function void Permute(const char[],int,char[],unsigned long); with the same first three arguments as Caesar above, with the fourth argument being the seed. The function will have to make up a permutation table as follows: To find what a is coded as, generate a random number from 1 to 25. Add that to a to get the coded letter. Mark that letter as used. For b, generate 1 to 24, then step that many letters after b, ignoring the used letter if encountered. For c, generate 1 to 23, ignoring a or b's codes if encountered. Wrap around at z. Here's an example, for only the 6 letters a, b, c, d, e, f. For the letter a, generate, from 1-5, a 2. Then a - c. c is marked as used. For the letter b, generate, from 1-4, a 3. So count 3 from b, skipping c (since it is marked as used) yielding the coding of b - f. Mark f as used. For c, generate, from 1-3, a 3. So count 3 from c, skipping f, giving a. Note the wrap at the last letter back to the first. And so on, yielding a - c b - f c - a d - b (it got a 2) e - d f - e Thus, for a given seed, a translation table is required. To decode a piece of text, we need the table generated to be re-arranged so that the right hand column is in order. In fact you can just store the table in the reverse way (e.g., if a gets encoded to c, put a opposite c is the table). Write a function called void DePermute(const char[],int,char[], unsigned long); to reverse the permutation cypher. Again, test your functions using the test file. At this point, any main program used to test these functions will not be required as part of the assignment. The remainder of the assignment uses some of these functions, and needs its own main function. When submitted, all the above functions will be tested by the marker's own main function. Step 6: If the seed number is unknown, decoding is difficult. Write a main program which: (i) reads in a piece of text using GetText; (ii) simplifies the text using SimplifyText; (iii) prints the text using PrintText; (iv) requests two letters to swap. If we think 'a' in the text should be 'q' we would type aq as input. The text would be modified by swapping the a's and q's, and the text reprinted. Repeat this last step until the user considers the text is decoded, when the input of the same letter twice (requesting a letter to be swapped with itself) terminates the program. Step 7: If we have a large enough sample of coded text, we can use knowledge of English to aid in finding the permutation. The first clue is in the frequency of occurrence of each letter. Write a function void LetterFreq(const char[],int,freq[]); which takes the piece of text given as the first two arguments (same as above) and returns in the 26 long array of structs (the third argument), the table of the frequency of the 26 letters. This frequency table should be in decreasing order of popularity. A simple Selection Sort will suffice. (This will be described in lectures.) When printed, this summary would look something like v x r s z j p t n c l h u o i b w d g e a q y k f m 168106 68 66 59 54 48 45 44 35 26 24 22 20 20 20 17 13 12 12 4 4 1 0 0 0 The formatting will require the use of input/output manipulators. See the header file for the definition of the struct called freq. Modify the program so that, before each swap is requested, the current frequency of the letters is printed. This does not require further calls to LetterFreq, however. You may use the traditional order of regular letter frequencies (E T A I O N S H R D L U) as a guide when deciding what characters to exchange. Step 8: The decoding process can be made more difficult if blank is also coded. That is, consider the alphabet to be 27 letters. Rewrite LetterFreq and your main program to handle blank as another character to code. In the above frequency order, space usually comes first.

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  • Write a C++ program to encrypt and decrypt certain codes.

    - by Amber
    Step 1: Write a function int GetText(char[],int); which fills a character array from a requested file. That is, the function should prompt the user to input the filename, and then read up to the number of characters given as the second argument, terminating when the number has been reached or when the end of file is encountered. The file should then be closed. The number of characters placed in the array is then returned as the value of the function. Every character in the file should be transferred to the array. Whitespace should not be removed. When testing, assume that no more than 5000 characters will be read. The function should be placed in a file called coding.cpp while the main will be in ass5.cpp. To enable the prototypes to be accessible, the file coding.h contains the prototypes for all the functions that are to be written in coding.cpp for this assignment. (You may write other functions. If they are called from any of the functions in coding.h, they must appear in coding.cpp where their prototypes should also appear. Do not alter coding.h. Any other functions written for this assignment should be placed, along with their prototypes, with the main function.) Step 2: Write a function int SimplifyText(char[],int); which simplifies the text in the first argument, an array containing the number of characters as given in the second argument, by converting all alphabetic characters to lower case, removing all non-alpha characters, and replacing multiple whitespace by one blank. Any leading whitespace at the beginning of the array should be removed completely. The resulting number of characters should be returned as the value of the function. Note that another array cannot appear in the function (as the file does not contain one). For example, if the array contained the 29 characters "The 39 Steps" by John Buchan (with the " appearing in the array), the simplified text would be the steps by john buchan of length 24. The array should not contain a null character at the end. Step 3: Using the file test.txt, test your program so far. You will need to write a function void PrintText(const char[],int,int); that prints out the contents of the array, whose length is the second argument, breaking the lines to exactly the number of characters in the third argument. Be warned that, if the array contains newlines (as it would when read from a file), lines will be broken earlier than the specified length. Step 4: Write a function void Caesar(const char[],int,char[],int); which takes the first argument array, with length given by the second argument and codes it into the third argument array, using the shift given in the fourth argument. The shift must be performed cyclicly and must also be able to handle negative shifts. Shifts exceeding 26 can be reduced by modulo arithmetic. (Is C++'s modulo operations on negative numbers a problem here?) Demonstrate that the test file, as simplified, can be coded and decoded using a given shift by listing the original input text, the simplified text (indicating the new length), the coded text and finally the decoded text. Step 5: The permutation cypher does not limit the character substitution to just a shift. In fact, each of the 26 characters is coded to one of the others in an arbitrary way. So, for example, a might become f, b become q, c become d, but a letter never remains the same. How the letters are rearranged can be specified using a seed to the random number generator. The code can then be decoded, if the decoder has the same random number generator and knows the seed. Write the function void Permute(const char[],int,char[],unsigned long); with the same first three arguments as Caesar above, with the fourth argument being the seed. The function will have to make up a permutation table as follows: To find what a is coded as, generate a random number from 1 to 25. Add that to a to get the coded letter. Mark that letter as used. For b, generate 1 to 24, then step that many letters after b, ignoring the used letter if encountered. For c, generate 1 to 23, ignoring a or b's codes if encountered. Wrap around at z. Here's an example, for only the 6 letters a, b, c, d, e, f. For the letter a, generate, from 1-5, a 2. Then a - c. c is marked as used. For the letter b, generate, from 1-4, a 3. So count 3 from b, skipping c (since it is marked as used) yielding the coding of b - f. Mark f as used. For c, generate, from 1-3, a 3. So count 3 from c, skipping f, giving a. Note the wrap at the last letter back to the first. And so on, yielding a - c b - f c - a d - b (it got a 2) e - d f - e Thus, for a given seed, a translation table is required. To decode a piece of text, we need the table generated to be re-arranged so that the right hand column is in order. In fact you can just store the table in the reverse way (e.g., if a gets encoded to c, put a opposite c is the table). Write a function called void DePermute(const char[],int,char[], unsigned long); to reverse the permutation cypher. Again, test your functions using the test file. At this point, any main program used to test these functions will not be required as part of the assignment. The remainder of the assignment uses some of these functions, and needs its own main function. When submitted, all the above functions will be tested by the marker's own main function. Step 6: If the seed number is unknown, decoding is difficult. Write a main program which: (i) reads in a piece of text using GetText; (ii) simplifies the text using SimplifyText; (iii) prints the text using PrintText; (iv) requests two letters to swap. If we think 'a' in the text should be 'q' we would type aq as input. The text would be modified by swapping the a's and q's, and the text reprinted. Repeat this last step until the user considers the text is decoded, when the input of the same letter twice (requesting a letter to be swapped with itself) terminates the program. Step 7: If we have a large enough sample of coded text, we can use knowledge of English to aid in finding the permutation. The first clue is in the frequency of occurrence of each letter. Write a function void LetterFreq(const char[],int,freq[]); which takes the piece of text given as the first two arguments (same as above) and returns in the 26 long array of structs (the third argument), the table of the frequency of the 26 letters. This frequency table should be in decreasing order of popularity. A simple Selection Sort will suffice. (This will be described in lectures.) When printed, this summary would look something like v x r s z j p t n c l h u o i b w d g e a q y k f m 168106 68 66 59 54 48 45 44 35 26 24 22 20 20 20 17 13 12 12 4 4 1 0 0 0 The formatting will require the use of input/output manipulators. See the header file for the definition of the struct called freq. Modify the program so that, before each swap is requested, the current frequency of the letters is printed. This does not require further calls to LetterFreq, however. You may use the traditional order of regular letter frequencies (E T A I O N S H R D L U) as a guide when deciding what characters to exchange. Step 8: The decoding process can be made more difficult if blank is also coded. That is, consider the alphabet to be 27 letters. Rewrite LetterFreq and your main program to handle blank as another character to code. In the above frequency order, space usually comes first.

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  • To View multiple uploaded images [closed]

    - by Nilesh Sonawane
    PHP Javascript Image Upload function updatepicture(pic) { document.getElementById("image").setAttribute("src", pic); document.getElementById("image1").setAttribute("src", pic); document.getElementById("image2").setAttribute("src", pic); } Vastu deals Image Upload Upload message will go here. //query for insert timepass.php 0) { if ($_FILES['file']['size'] parent.document.getElementById("message").innerHTML = ""; parent.document.getElementById("file").value = ""; window.parent.updatepicture(""); parent.document.getElementById("message").innerHTML = "There was an error uploading your image. Please try again later."; parent.document.getElementById("message").innerHTML = "Your file is larger than 150kb. Please choose a different picture.";

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  • Writing Strings to files in python

    - by Leif Andersen
    I'm getting the following error when trying to write a string to a file in pythion: Traceback (most recent call last): File "export_off.py", line 264, in execute save_off(self.properties.path, context) File "export_off.py", line 244, in save_off primary.write(file) File "export_off.py", line 181, in write variable.write(file) File "export_off.py", line 118, in write file.write(self.value) TypeError: must be bytes or buffer, not str I basically have a string class, which contains a string: class _off_str(object): __slots__ = 'value' def __init__(self, val=""): self.value=val def get_size(self): return SZ_SHORT def write(self,file): file.write(self.value) def __str__(self): return str(self.value) Furthermore, I'm calling that class like this: def write(self, file): for variable in self.variables: variable.write(file) I have no idea what is going on. I've seen other python programs writing strings to files, so why can't this one? Thank you very much for your help.

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  • how to write the code for this program specially in mathematica? [closed]

    - by asd
    I implemented a solution to the problem below in Mathematica, but it takes a very long time (hours) to compute f of kis or the set B for large numbers. Somebody suggested that implementing this in C++ resulted in a solution in less than 10 minutes. Would C++ be a good language to learn to solve these problems, or can my Mathematica code be improved to fix the performance issues? I don't know anything about C or C++ and it should be difficult to start to learn this languages. I prefer to improve or write new code in mathematica. Problem Description Let $f$ be an arithmetic function and A={k1,k2,...,kn} are integers in increasing order. Now I want to start with k1 and compare f(ki) with f(k1). If f(ki)f(k1), put ki as k1. Now start with ki, and compare f(kj) with f(ki), for ji. If f(kj)f(ki), put kj as ki, and repeat this procedure. At the end we will have a sub sequence B={L1,...,Lm} of A by this property: f(L(i+1))f(L(i)), for any 1<=i<=m-1 For example, let f is the divisor function of integers. Here I put some part of my code and this is just a sample and the question in my program could be more larger than these: «««««««««««««««««««««««««««««««««««« f[n_] := DivisorSigma[0, n]; g[n_] := Product[Prime[i], {i, 1, PrimePi[n]}]; k1 = g[67757] g[353] g[59] g[19] g[11] g[7] g[5]^2 6^3 2^7; k2 = g[67757] g[353] g[59] g[19] g[11] g[7] g[5] 6^5 2^7; k3 = g[67757] g[359] g[53] g[19] g[11] g[7] g[5] 6^4 2^7; k4 = g[67759] g[349] g[53] g[19] g[11] g[7] g[5] 6^5 2^6; k5 = g[67757] g[359] g[53] g[19] g[11] g[7] g[5] 6^4 2^8; k6 = g[67759] g[349] g[53] g[19] g[11] g[7] g[5]^2 6^3 2^7; k7 = g[67757] g[359] g[53] g[19] g[11] g[7] g[5] 6^5 2^6; k8 = g[67757] g[359] g[53] g[19] g[11] g[7] g[5] 6^4 2^9; k9 = g[67757] g[359] g[53] g[19] g[11] g[7] g[5]^2 6^3 2^7; k10 = g[67757] g[359] g[53] g[19] g[11] g[7] g[5] 6^5 2^7; k11 = g[67759] g[349] g[53] g[19] g[11] g[7] g[5]^2 6^4 2^6; k12 = g[67757] g[359] g[53] g[19] g[11] g[7] g[5]^2 6^3 2^8; k13 = g[67757] g[359] g[53] g[19] g[11] g[7] g[5]^2 6^4 2^6; k14 = g[67757] g[359] g[53] g[19] g[11] g[7] g[5]^2 6^3 2^9; k15 = g[67757] g[359] g[53] g[19] g[11] g[7] g[5]^2 6^4 2^7; k16 = g[67757] g[359] g[53] g[23] g[11] g[7] g[5] 6^4 2^8; k17 = g[67757] g[359] g[59] g[19] g[11] g[7] g[5] 6^4 2^7; k18 = g[67757] g[359] g[53] g[23] g[11] g[7] g[5] 6^4 2^9; k19 = g[67759] g[353] g[53] g[19] g[11] g[7] g[5] 6^4 2^6; k20 = g[67763] g[347] g[53] g[19] g[11] g[7] g[5] 6^4 2^7; k = Table[k1, k2, k3, k4, k5, k6, k7, k8, k9, k10, k11, k12, k13, k14, k15, k16, k17, k18, k19, k20]; i = 1; count = 0; For[j = i, j <= 20, j++, If[f[k[[j]]] - f[k[[i]]] > 0, i = j; Print["k",i]; count = count + 1]]; Print["count= ", count] ««««««««««««««««««««««««««««««««««««

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  • do I use document.activeElement to detect focus changes?

    - by jedierikb
    After looking at the answers here: http://stackoverflow.com/questions/497094/how-do-i-find-out-which-javascript-element-has-focus http://stackoverflow.com/questions/483741/how-to-determine-which-html-page-element-has-focus I can see that using document.activeElement is a great way to know which element has focus. But how do I use document.activeElement to detect changes to focus (or maybe I don't and I need to research a better way. Want to know if I am barking up the wrong tree).

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  • Is there a way to use sharepoint as the back-end versioning and storage for my custom document manag

    - by Aaron Palmer
    I want to build a custom document management web application that ties in with sharepoint for the actual document versioning and storage. I'm hoping for something like a sharepoint widget that I can plug into my web application that would allow me to tie in with sharepoint and download documents, make edits to them, and upload them back to sharepoint, with sharepoint handling all of the versioning and storage. If WSS is the answer to this, are there licensing issues that I need to consider? Thanks.

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  • Oracle: how to use updateXML to update multiple nodes in a document?

    - by Alessandro Vernet
    I can write: update my_table set xml = updateXML(xml, '/a/b', '1') where document_id = 123 Now what if in the same update query I also want to set /a/c to 2 (in addition /a/b to 1)? I am tempted to write: update my_table set xml = updateXML(xml, '/a/b', '1'), xml = updateXML(xml, '/a/c', '2') where document_id = 123 But this give me a "ORA-00957: duplicate column name". Any suggestion on how to do this?

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  • Could the Print document ive built in .net cause a UriFormatException?

    - by Smoka
    After adding Print Document, Dialog, and Button to my Forms app i now have UriFormatException and A first chance exception of type 'System.ComponentModel.Win32Exception' occurred in System.Drawing.dll Additional information: Access is denied Is there something wrong with the strings in my Document? Preview looks fine. but unhandled exception's when it tries to print.

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