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Search found 3956 results on 159 pages for 'regex cookbook'.

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  • Perl Strip Comments with Regex Unique Request

    - by YoDar
    Hello, I'm running a code that read files, do some parsing but need to ignore all comments. There are good explanations how to conduct it. like this link $/ = undef; $_ = <>; s#/\*[^*]*\*+([^/*][^*]*\*+)*/|("(\\.|[^"\\])*"|'(\\.|[^'\\])*'|.[^/"'\\]*)#defined $2 ? $2 : ""#gse; print; My first problem is that after run this line $/ = undef; my code doesn't work properly. Actually, I don't know what it does. But if I could turn it back after ignoring all comments it will be helpful. In general, What is the useful way to ignore all comments without changing the rest of the code ? Thanks, YoDar

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  • preg_replace - don't include string if $4 is blank

    - by bradenkeith
    I have this expression: $regex_phone = '/^(?:1(?:[. -])?)?(?:\((?=\d{3}\)))?([2-9]\d{2})' .'(?:(?<=\(\d{3})\))? ?(?:(?<=\d{3})[.-])?([2-9]\d{2})' .'[. -]?(\d{4})(?: (?i:ext)\.? ?(\d{1,5}))?$/'; if(!preg_match($regex_phone, $data['phone'])){ $error[] = "Please enter a valid phone number."; }else{ $data['phone'] = preg_replace($regex_phone, '($1) $2-$3 ext.$4', $data['phone']); } That will take a phone number such as: 803-888-8888 ext 2 as well as 803-888-8888 First number formats as: (803) 888-8888 ext.2 -- the desired effect Second number formats as: (803) 888-8888 ext. -- blank extension How can I set it so that if $4 is blank, that ext. won't show? Thanks so much for any help you can offer. I hope this was clear.

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  • regular expression for challenge value

    - by Salman
    Hi what will be the regular expression to extract challenge var value i am interested in this vlaue 03AHJ_Vut9LJLOJuCsjF9PbSSMncTyUe7Y4dHX11eRLae3LGfDZ0hSfDR7jZq2ZrKJxyC-LRSSppv72oHKaQMsd-EnoVNL6p7liTh7siN26zzTA_E2rcC_JQ15613Azz4qm8HjPtAyksUdc7QZydszwolk92hBPrAAig this value changes every time we refresh it so the expression has to be generic enough to pick up what ever is the value var RecaptchaState = { site : '6LeKCL8SAAAAADV5Dr-lfY2eOEV8rubeN25BAKp2', challenge : '03AHJ_Vut9LJLOJuCsjF9PbSSMncTyUe7Y4dHX11eRLae3LGfDZ0hSfDR7jZq2ZrKJxyC-LRSSppv72oHKaQMsd-EnoVNL6p7liTh7siN26zzTA_E2rcC_JQ15613Azz4qm8HjPtAyksUdc7QZydszwolk92hBPrAAig', is_incorrect : false, programming_error : '', error_message : '', server : 'http://www.google.com/recaptcha/api/', timeout : 18000}; any help will be appreciated, or any method to extract this value in any server side lang

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  • Regular expression to truncate a String

    - by user470184
    To truncate a String here is what I'm using : String test1 = "this is test truncation 1.pdf"; String p1 = test1.substring(0, 10) + "..."; System.out.println(p1); The output is 'this is te...' How can I access the file name extension so that output becomes : 'this is te... pdf' I could use substring method to access the last three characters but other file extensions could be 4 chars in length such as .aspx Is there a regular expression I can use so that "this is test truncation 1.pdf" becomes "this is te... pdf"

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  • Find and replace braced tags within a MySQL table

    - by Cy
    I have about 40000 records in that table that contains plain text and within the plain text, contains that kind of tags which its only characteristic is that they are braced between [ ] [caption id="attachment_2948" align="alignnone" width="480" caption="the caption goes here"] How could I remove those? (replace by nothing) I could also run a PHP program if necessary to do the cleanup.

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  • regular expression: extract last 2 characters

    - by dotnet-practitioner
    what is the best way to extract last 2 characters of a string using regular expression. For example, I want to extract state code from the following "A_IL" I want to extract IL as string.. please provide me C# code on how to get it.. string fullexpression = "A_IL"; string StateCode = some regular expression code.... thanks

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  • Regular Expression doesn't match

    - by dododedodonl
    Hi All, I've got a regular expression in my cocoa-touch app (using RegexKitLite). NSString *week = [[NSString alloc] initWithFormat:@"%@", [pageContent stringByReplacingOccurrencesOfRegex:@"<select name=\"week\" class=\"selectbox\" style='width:134' onChange=\"doDisplayTimetable(NavBar, topDir);\">(.+?)<option value=\"(.+?)\">(.+?)</option>" withString:@"$2"]]; I expect it to match with the section of this (what is in NSString pageContent): <span class="selection"> <nobr> Periode<br> <span class="absatz"> &nbsp;<br> </span> <select name="week" class="selectbox" style='width:134' onChange="doDisplayTimetable(NavBar, topDir);"> <option value="14">17-5 - 16-7</option> </select> </nobr> </span> But it doesn't... I need the value of the option, it is possible that there is more than one (in that case I need them both separated by a ,. Can someone help me out? Regards, Dodo

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  • Regular expression from font to span (size and colour) and back (VB.NET)

    - by chapmanio
    Hi, I am looking for a regular expression that can convert my font tags (only with size and colour attributes) into span tags with the relevant inline css. This will be done in VB.NET if that helps at all. I also need a regular expression to go the other way as well. To elaborate below is an example of the conversion I am looking for: <font size="10">some text</font> To then become: <span style="font-size:10px;">some text</span> So converting the tag and putting a "px" at the end of whatever the font size is (I don't need to change/convert the font size, just stick px at the end). The regular expression needs to cope with a font tag that only has a size attribute, only a color attribute, or both: <font size="10">some text</font> <font color="#000000">some text</font> <font size="10" color="#000000">some text</font> <font color="#000000" size="10">some text</font> I also need another regular expression to do the opposite conversion. So for example: <span style="font-size:10px;">some text</span> Will become: <font size="10">some text</font> As before converting the tag but this time removing the "px", I don't need to worry about changing the font size. Again this will also need to cope with the size styling, font styling, and a combination of both: <span style="font-size:10px;">some text</span> <span style="color:#000000;">some text</span> <span style="font-size:10px; color:#000000;">some text</span> <span style="color:#000000; font-size:10px;">some text</span> I apprecitate this is a lot to ask, I am hopeless with regular expressions and need to find a way of making these conversions in my code. Thanks so much to anyone that can/is willing to help me!

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  • Strings, regexp and files

    - by A Moose
    <?php $iprange = array( "^12\.34\.", "^12\.35\.", ); foreach($iprange as $var) { if (preg_match($var, $_SERVER['REMOTE_ADDR'])) { I'm looking to have a list that will constitute each of the values inside the array. Let's call it iprange.txt, from which I would extract the variable $iprange. I would also be updating the file with new ranges, but I also want to convert those strings to regexp if that's something that's needed in php, as it is in the above example. If you could help me with the two following issues: I understand that somehow I would be using an array include, but I'm not sure how to implement it. I would like to run a cron that would update the text file and turn it into a regexp acceptable for use in the above example, if you think regexp is a good idea and there isn't another option. I know how to apply a cron in a directadmin gui, but I don't know what the cronned file would look like.

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  • Finding if a sentence contains a specific phrase in Ruby

    - by TenJack
    Right now I am seeing if a sentence contains a specific word by splitting the sentence into an array and then doing an include to see if it contains the word. Something like: "This is my awesome sentence.".split(" ").include?('awesome') But I'm wondering what the fastest way to do this with a phrase is. Like if I wanted to see if the sentence "This is my awesome sentence." contains the phrase "my awesome sentence". I am scraping sentences and comparing a very large number of phrases, so speed is somewhat important.

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  • Regular Expression for accurate word-count using JavaScript

    - by Haidon
    I'm trying to put together a regular expression for a JavaScript command that accurately counts the number of words in a textarea. One solution I had found is as follows: document.querySelector("#wordcount").innerHTML = document.querySelector("#editor").value.split(/\b\w+\b/).length -1; But this doesn't count any non-Latin characters (eg: Cyrillic, Hangul, etc); it skips over them completely. Another one I put together: document.querySelector("#wordcount").innerHTML = document.querySelector("#editor").value.split(/\s+/g).length -1; But this doesn't count accurately unless the document ends in a space character. If a space character is appended to the value being counted it counts 1 word even with an empty document. Furthermore, if the document begins with a space character an extraneous word is counted. Is there a regular expression I can put into this command that counts the words accurately, regardless of input method?

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  • ruby parametrized regular expression

    - by astropanic
    I have a string like "{some|words|are|here}" or "{another|set|of|words}" So in general the string consists of an opening curly bracket,words delimited by a pipe and a closing curly bracket. What is the most efficient way to get the selected word of that string ? I would like do something like this: @my_string = "{this|is|a|test|case}" @my_string.get_column(0) # => "this" @my_string.get_column(2) # => "is" @my_string.get_column(4) # => "case" What should the method get_column contain ?

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  • Ruby Regexp methods?

    - by fjs6
    Is there a gem/example_code that allows to work with regexps? I am not looking for what a regexp can do, but what can be done to a Regexp object. For example: r = Regexp.new(...) r.min_length => the minimum length of a matching string r = Regexp.new("car(less)?") r.min_length => 3 for the string "car" Thanks!

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  • How can I convert SQL comments with -- to # using Perl?

    - by NJTechie
    I have various SQL files with '--' comments and we migrated to the latest version of MySQL and it hates these comments. I want to replace -- with #. I am looking for a recursive, inplace replace one-liner. This is what I have: perl -p -i -e 's/--/# /g'` ``fgrep -- -- * A sample .sql file: use myDB; --did you get an error I get the following error: Unrecognized switch: --did (-h will show valid options). p.s : fgrep skipping 2 dashes was just discussed here if you are interested. Any help is appreciated.

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  • Replacing certain words with links to definitions using Javascript

    - by adharris
    I am trying to create a glossary system which will get a list of common words and their definitions via ajax, then replace any occurrence of that word in certain elements (those with the useGlossary class) with a link to the full definition and provide a short definition on mouse hover. The way I am doing it works, but for large pages it takes 30-40 seconds, during which the page hangs. I would like to either decrease the time it takes to do the replacement or make it so that the replacement is running in the background without hanging the page. I am using jquery for most of the javascript, and Qtip for the mouse hover. Here is my existing slow code: $(document).ready(function () { $.get("fetchGlossary.cfm", null, glossCallback, "json"); }); function glossCallback(data) { $(".useGlossary").each(function() { var $this = $(this); for (var i in data) { $this.html($this.html().replace(new RegExp("\\b" + data[i].term + "\\b", "gi"), function(m) {return makeLink(m, data[i].def);})); } $this.find("a.glossary").qtip({ style: { name: 'blue', tip: true } }) }); } function makeLink(m, def) { return "<a class='glossary glossary" + m.replace(/\s/gi, "").toUpperCase() + "' href='reference/glossary.cfm' title='" + def + "'>" + m + "</a>"; } Thanks for any feedback/suggestions!

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  • JQuery - remove the chars not matching regEx

    - by JQueryBeginner
    Hi All, I am trying to use jquery for validating forms. This is the pattern that is allowed in a text box for a user. var pattern = /^[a-zA-Z0-9!#$&%*+,-./: ;=?@_]/g; If the user types anything else other than this then that has to be replaced with a "". $(document).ready(function() { $('#iBox').blur(function() { var jVal = $('#iBox').val(); if(jVal.match(pattern)) { alert("Valid"); } else { alert("New "+jVal.replace(!(pattern),"")); } }); }); }); But the replace function does not work this way.

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  • regular expression on replace method of js not working

    - by user950146
    why this is not working var value = arr[row][col].replace(new RegExp('"', 'g'),'""'); Error : Webpage error details User Agent: Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 6.1; Trident/4.0; SLCC2; .NET CLR 2.0.50727; .NET CLR 3.5.30729; .NET CLR 3.0.30729; Media Center PC 6.0; InfoPath.2; Tablet PC 2.0) Timestamp: Tue, 10 Apr 2012 11:22:01 UTC Message: Object doesn't support this property or method Line: 1041 Char: 25 Code: 0 URI: http://example.com/? Message: Object doesn't support this property or method Line: 1041 Char: 25 Code: 0 URI: http://example.com/? Message: Object doesn't support this property or method Line: 1041 Char: 25 Code: 0 URI: http://example.com/? Note: : Error copied directly from debugger of IE8

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  • How to sub with matched groups and variables in Python

    - by Syed
    Hi, new to python. This is probably simple but I haven't found an answer. rndStr = "20101215" rndStr2 = "20101216" str = "Looking at dates between 20110316 and 20110317" outstr = re.sub("(.+)([0-9]{8})(.+)([0-9]{8})",r'\1'+rndStr+r'\2'+rndStr2,str) The output I'm looking for is: Looking at dates between 20101215 and 20101216 But instead I get: P101215101216 The values of the two rndStr's doesn't really matter. Assume its random or taken from user input (I put static vals here to keep it simple). Thanks for any help.

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  • replace <br> to new line between pre tag

    - by saturngod
    I want to convert <p>Code is following</p> <pre> &lt;html&gt;<br>&lt;/html&gt; </pre> to <p>Code is following</p> <pre> &lt;html&gt; &lt;/html&gt; </pre> I don't know how to write regular expression for replace between pre tag in PHP. I tried this code http://stackoverflow.com/questions/1517102/replace-newlines-with-br-tags-but-only-inside-pre-tags but it's not working for me.

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  • regexp to match string with (comma-separated) number at start and to split into number and rest?

    - by mix
    Given a string such as: 23,234,456 first second third How can I split string this into two parts, where part 1 contains the number at the beginning and part 2 contains the rest---but only if the string STARTS with a number, and the number can be comma-separated or not? In other words, I want two results: 23,234,456 and first second third. If there's a number in that string that isn't part of the first number then it should be in the second result. My best stab at this so far, to grab the number at the beginning, is something like this: ^[0-9]+(,[0-9]{3})* Which seems to grab a comma-separated or non-comma-separated number that starts the line. However, when I run this in the Javascript console I get not only the full number, but also a match on just the last 3 digits with their preceeding ,. (e.g. 23,234,456 and ,456). As for getting the rest into another var I'm having trouble. I tried working with \b, etc., but I think I must be missing something fundamental about grabbing the rest of the line. I'm doing this in Javascript in case it matters. More examples of what to match and what not to match. 2 one two three should return 2 and one two three 2345 one two three should return 2345 and one two three 2 one 2 three should return 2 and one 2 three 2,234 one two 3,000 should return 2,234 and one two 3,000 The space between parts 1 and two could be included in the beginning of part 2.

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  • Java Split not working as expected

    - by daaabears
    I am trying to use a simple split to break up the following string: 00-00000 My expression is: ^([0-9][0-9])(-)([0-9])([0-9])([0-9])([0-9])([0-9]) And my usage is: String s = "00-00000"; String pattern = "^([0-9][0-9])(-)([0-9])([0-9])([0-9])([0-9])([0-9])"; String[] parts = s.split(pattern); If I play around with the Pattern and Matcher classes I can see that my pattern does match and the matcher tells me my groupCount is 7 which is correct. But when I try and split them I have no luck.

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  • Convert Json date string to JavaScript date object

    - by dagda1
    Hi, I have the following JSON object which has a date field in the following format: { "AlertDate": "\/Date(1277334000000+0100)\/", "Progress": 1, "ReviewPeriod": 12 } I want to write a regular expression or a function to convert it to a javascript object so that it is in the form: { "AlertDate": "AlertDate":new Date(1277334000000), "Progress": 1, "ReviewPeriod": 12 } The above date format fails validation in the JQuery parseJSON method. I would like to convert the 1277334000000+0100 into the correct number of milliseconds to create the correct date when eval is called after validation. Can anyone help me out with a good approach to solving this? Cheers Paul

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