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  • Need to split a string into two parts in java

    - by Reddy
    I have a string which contains a contiguous chunk of digits and then a contiguous chunk of characters. I need to split them into two parts (one integer part, and one string). I tried using String.split("\D", 1), but it is eating up first character. I checked all the String API and didn't find a suitable method. Is there any method for doing this thing?

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  • How to replace all the blanks within square brackets with an underscore using sed?

    - by Ringerrr
    I figured out that in order to turn [some name] into [some_name] I need to use the following expression: s/\(\[[^ ]*\) /\1_/ i.e. create a backreference capture for anything that starts with a literal '[' that contains any number of non space characters, followed by a space, to be replaced with the non space characters followed by an underscore. What I don't know yet though is how to alter this expression so it works for ALL underscores within the braces e.g. [a few words] into [a_few_words]. I sense that I'm close, but am just missing a chunk of knowledge that will unlock the key to making this thing work an infinite number of times within the constraints of the first set of []s contained in a line (of SQL Server DDL in this case). Any suggestions gratefully received....

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  • Match multiple terms within <body> tags

    - by Jeepstone
    I've want to match any occurrence of a search term (or list of search terms) within the tags of a document. My current solution uses preg (within a Joomla plugin) $pattern = '/matchthisterm/i'; $article->text = preg_replace($pattern,"<span class=\"highlight\">\\0</span>",$article->text); But this replaces everything within the HTML of the document so I need to match the tags first. Is this even the best way to achieve this?

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  • preg_match and long strings

    - by aleluja
    Hi, This is the preg_match i am trying to use to find specific text in text file. if (preg_match($regexp,$textFile,$result) > 0) { echo "Found ".$result[0]; } else { echo "Not found"; } However, the result is always Found and nothing more. The result array is empty. Now i read that preg_match can't work with long strings. My text file is about 300KB so thats 300000 characters i guess. I am 100% sure that the searched string is in the text file, and the fact that preg_match function returns value above 0 means it found it, but it didn't place it into the result array somehow. So my question would be, how do i make it work? regexp would be /[specific text]\{(\d*)\}/ so, of course i want to be able to get the number in the parentheses.

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  • Python matching some characters into a string

    - by roaksoax
    Hi All I'm trying to extract/match data from a string using regular expression but I don't seem to get it. I wan't to extract the highlighted characters from the following string: /xubuntu/daily/current/lucid-alternate-**i386**.iso This should also work in case of: /xubuntu/daily/current/lucid-alternate-**amd64**.iso Thanks a lot for your help.

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  • Perl Regular Expression [] for <>

    - by bmucklow
    So I am trying to read an XML file into a string in Perl and send it as part of a SOAP message. I know this is not ideal as there are methods for SOAP sending files, however, I am limited to having to use the SOAP that is set up, and it is not set up for sending with file support. Therefore I need to parse out the markup tags < and replace them with []. What is the best way to do this?

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  • Good starting point to learn regular expressions.

    - by Jeremy Rudd
    I'm good at learning new languages and platforms, though whenever I try to learn Reg Ex I cannot make sense of it. I once even used the Regular Expression Designer to try and put some together. What's a good starting point to understanding what looks like the only rocket-science programming language in the world? Links to articles, books or anything else that could help me get my grounding would be appreciated.

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  • Get all link id from html source code using PREG_MATCH_ALL

    - by Jeremy Dicaire
    Hi there, I know i shouldn't do this that way but its just to retrieve all id of my links since i have a lot of them Here is the patern: <a href="mylink.php?get=123456">Click 1</a> <a href="mylink.php?get=222222">Click 2</a> <a href="mylink.php?get=81456">Click 3</a> <a href="mylink.php?get=1700">Click 4</a> I want to get all "get=" values (123456, 222222, etc.) And also the "Click 1", "Click 2", etc values using Preg_match_all() Any idea? Thanks a lot guys!!!

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  • Split text at the first instance of a letter

    - by Blankman
    I have a bunch of product sku's that look like: abc234 asdf234324 adc234-b result: abc 234 asdf 234324 adc 234-b I want to split the text at the first instance of a letter. When I say split, basically I want to have access to both parts of the text, maybe in an array? What's the best way to do this?

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  • Constructing a regular expression to wrap images with <a>

    - by bobo
    A web page contains lots of image elements: <img src="myImage.gif" width="180" height="18" /> But they may not be very well-formed, for example, the width or height attribute may be missing. And it also may not be properly closed with /. The src attribute is always there. I need a regular expression that wraps these with a hyperlink having href set to the src of the img. <a href="myImage.gif" target="_blank"><img src="myImage.gif" width="180" height="18" /></a> I can successfully locate the images using this regexp in this editor: http://gskinner.com/RegExr/: <img src="([^<]*)"[^<]*> But what is the next step?

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  • Split string into sentences based on periods

    - by rookie
    Hi all, I have written this piece of code that splits a string and stores it in a string array:- String[] sSentence = sResult.split("[a-z]\.\s+"); However, I've added the [a-z] because I wanted to deal with some of the abbreviation problem. But then my result shows up as so:- Furthermore when Everett tried to instruct them in basic mathematics they proved unresponsiv I see that I loose the pattern specified in the split function. Its okay for me to loose the period, but loosing the last letter of the word disturbs its meaning. Could some one help me with this and in addition also could someone help me with dealing with abbreviations? Like because I split the string based on periods, I do not want to loose the abbreviations. Thanks in advance

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  • Regular Expression Help

    - by Dave
    Looking for some help with a Regular Expression to do the following: Must be Alpha Char Must be at least 1 Char Must NOT be a specific value, e.g. != "Default" Thanks for any help, Dave

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  • Find telephonenumbers - finding number with and without an phone extension

    - by nWorx
    Hello there I've a table with about 130 000 records with telephonenumbers. The numbers are all formated like this +4311234567. The numbers always include international country code, local area code and then the phonenumber and sometimes an extension. There is a webservice which checks for the caller's number in the table. That service works already. But now the client wants that also if someone calls from a company which number is already in the database but not his extension, that the service will return some result. Example for table. **id** | **telephonenumber** | **name** | 1 | +431234567 | company A | 2 | +431234567890 | employee in company A | 3 | +4398765432 | company b now if somebody from company A calls with a different extension for example +43123456777, than it should return id1. But the problem is, that I don't know how many digits the extensions have. It could have 3,4 or more digits. Are there any patterns for string kind of matchings? The data is stored in a sql2005 database. Thanks

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  • Regular expressions in java

    - by rookie
    String s= "(See <a href=\"/wiki/Grass_fed_beef\" title=\"Grass fed beef\" " + "class=\"mw-redirect\">grass fed beef.) They have been used for " + "<a href=\"/wiki/Paper\" title=\"Paper\">paper-making since " + "2400 BC or before."; In the string above I have inter-mixed html with text. Well the requirement is that the output looks like:- They have been used for paper-making since 2400 BC or before. Could some one help me with a generic regular expression that would produce the desired output from the given input? Thanks in advance!

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  • regular expression on replace method of js not working

    - by user950146
    why this is not working var value = arr[row][col].replace(new RegExp('"', 'g'),'""'); Error : Webpage error details User Agent: Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 6.1; Trident/4.0; SLCC2; .NET CLR 2.0.50727; .NET CLR 3.5.30729; .NET CLR 3.0.30729; Media Center PC 6.0; InfoPath.2; Tablet PC 2.0) Timestamp: Tue, 10 Apr 2012 11:22:01 UTC Message: Object doesn't support this property or method Line: 1041 Char: 25 Code: 0 URI: http://example.com/? Message: Object doesn't support this property or method Line: 1041 Char: 25 Code: 0 URI: http://example.com/? Message: Object doesn't support this property or method Line: 1041 Char: 25 Code: 0 URI: http://example.com/? Note: : Error copied directly from debugger of IE8

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  • Regular expression to truncate a String

    - by user470184
    To truncate a String here is what I'm using : String test1 = "this is test truncation 1.pdf"; String p1 = test1.substring(0, 10) + "..."; System.out.println(p1); The output is 'this is te...' How can I access the file name extension so that output becomes : 'this is te... pdf' I could use substring method to access the last three characters but other file extensions could be 4 chars in length such as .aspx Is there a regular expression I can use so that "this is test truncation 1.pdf" becomes "this is te... pdf"

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  • How to escape regular expression in javascript ?

    - by Relax
    My codes is like pattern = 'arrayname[1]'; // fetch from dom, make literal here just for example reg = new RegExp(RegExp.quote(pattern), 'g'); mystring.replace(reg, 'arrayname[2]'); But it just cannot get running with error message says: "RegExp.quote is not a function", am i missing something simple?

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  • Java regular expression: how to include '-'

    - by changed
    I am using this pattern and matching a string. String s = "//name:value /name:value"; if (s.matches("(//?\\s*\\w+:\\w+\\s*)+")) { // it fits } This works properly. But if I want to have a string like "/name-or-address:value/name-or-address:value" which has this '-' in second part, it doesn't work. I am using \w to match A-Za-z_, but how can I include - in that?

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