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  • How to store coordinates in a database

    - by Tim
    Hello all! I have a Flex GUI where I have to place quadrate elements. The position of these elements need to be stored into a database. So I can create two integer fields in the db table x and y. Also I need an angle, because the user can rotate these elements, so I can also make a int (int is okay, I do not need a double value therefore). As a ORM, I use Hibernate. But the question is, if creating three integer fields is the best way to handle this. Perhaps someone can tell me if this will be okay or if there are better ways? Thanks a lot in advance & Best Regards.

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  • OpenGL - have object follow mouse

    - by kevin james
    I want to have an object follow around my mouse on the screen in OpenGL. (I am also using GLEW, GLFW, and GLM). The best idea I've come up with is: Get the coordinates within the window with glfwGetCursorPos. The window was created with window = glfwCreateWindow( 1024, 768, "Test", NULL, NULL); and the code to get coordinates is double xpos, ypos; glfwGetCursorPos(window, &xpos, &ypos); Next, I use GLM unproject, to get the coordinates in "object space" glm::vec4 viewport = glm::vec4(0.0f, 0.0f, 1024.0f, 768.0f); glm::vec3 pos = glm::vec3(xpos, ypos, 0.0f); glm::vec3 un = glm::unProject(pos, View*Model, Projection, viewport); There are two potential problems I can already see. The viewport is fine, as the initial x,y, coordinates of the lower left are indeed 0,0, and it's indeed a 1024*768 window. However, the position vector I create doesn't seem right. The Z coordinate should probably not be zero. However, glfwGetCursorPos returns 2D coordinates, and I don't know how to go from there to the 3D window coordinates, especially since I am not sure what the 3rd dimension of the window coordinates even means (since computer screens are 2D). Then, I am not sure if I am using unproject correctly. Assume the View, Model, Projection matrices are all OK. If I passed in the correct position vector in Window coordinates, does the unproject call give me the coordinates in Object coordinates? I think it does, but the documentation is not clear. Finally, to each vertex of the object I want to follow the mouse around, I just increment the x coordinate by un[0], the y coordinate by -un[1], and the z coordinate by un[2]. However, since my position vector that is being unprojected is likely wrong, this is not giving good results; the object does move as my mouse moves, but it is offset quite a bit (i.e. moving the mouse a lot doesn't move the object that much, and the z coordinate is very large). I actually found that the z coordinate un[2] is always the same value no matter where my mouse is, probably because the position vector I pass into unproject always has a value of 0.0 for z. Edit: The (incorrectly) unprojected x-values range from about -0.552 to 0.552, and the y-values from about -0.411 to 0.411.

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  • Java Simple WGS84 Lat Lon to Pixel X, Y

    - by Cnich
    I've read a multitude of information regarding map projection today. The amount of information available is overwhelming. I am attempting to simply convert lat, long values into a screen X, Y coordinate not using any map. I do not need the values projected onto any map, just on the window. The window itself is representing approx. a 1500x1500 meter location. Lat, Long accuracy needed is to a 1/10th of a second. What may be some simpler ways in converting lat/long representation to the screen? I've read several articles and post regarding translation onto images, but nothing related to the natural java coordinate system. Thanks for any insight.

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  • Simplest Algorithm for 2D Interpolation

    - by Gayan
    I have two shapes which are cross sections of a channel. I want to calculate the cross section of an intermediate point between the two defined points. What's the simplest algorithm to use in this situation? P.S. I came across several algorithms like natural neighbor and poisson which seemed complex. I'm looking for a simple solution which could be implemented quickly

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  • Covering Earth with Hexagonal Map Tiles

    - by carrier
    Many strategy games use hexagonal tiles. One of the main advantages is that the distance between the center of any tile and all its neighboring tiles is the same. I was wondering if anyone has any thoughts on marrying a hexagonal tile system with the traditional geographic system (longitude/latitude). I think it would be interesting to cover a globe with hexagonal tiles and be able to map a geographic coordinate to a tile. Has anyone seen anything remotely close to this before? UPDATE I'm looking for a way to subdivide the surface of a sphere so that each division has the same surface area. Ideally, the centers of adjacent sub-divisions would be equidistant.

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  • Algorithm for 2D Interpolation

    - by Gayan
    I have two shapes which are cross sections of a channel. I want to calculate the cross section of an intermediate point between the two defined points. What's the simplest algorithm to use in this situation? P.S. I came across several algorithms like natural neighbor and poisson which seemed complex. I'm looking for a simple solution which could be implemented quickly EDIT: I removed the word "Simplest" from the title since it might be misleading

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  • Translate google co-ordinates to the pixels on picture.

    - by kalininew
    I have a city "map" (for example - Moscow). She in accuracy repeats the contours the given city in google maps (that is it is copied from google maps and it is a little processed, but the sense remained the same). Also I have object co-ordinates in a city (in co-ordinates of google). Problem: how to translate google co-ordinates to the co-ordinates of my picture (that is in pixels on OX and OY on a picture). That is I receive google-co-ordinates and it is necessary for me to draw this point on my picture. I know that on small scales (for example on city scales) it to make simply enough (it is necessary to learn what google-co-ordinates has one of picture corners, then to learn "price" of one pixel in google-co-ordinates on a picture on axes OX and OY separately). But on the big scales (country scale) "price" of one pixel will be not a constant, and will vary strongly enough and the method described above cannot be applied. How to solve a problem on country scales?

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  • google maps, cellid to location

    - by Dels
    According to this sample: http://www.codeproject.com/KB/mobile/DeepCast.aspx It's possible to request a gps coordinate (longitude & latitude) including range when sending cellid information (MCC, MNC, towerid, etc) Can someone tell me the actual parameter to request/post to this address? http://www.google.com/glm/mmap It could be something like this http://www.google.com/glm/mmap?mcc=xxx&mnc=xxx&towerid=xxx And i would like to know what response we would get. I have observe OpenCellid website and they provide some nice API to begin with, but i want to know about that in google map too (since they have more completed database). OpenCellID API

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  • Convet long/lat to pixel x/y on a given picure.

    - by kalininew
    I have a city "map" (for example - Moscow). She in accuracy repeats the contours the given city in google maps (that is it is copied from google maps and it is a little processed, but the sense remained the same). Also I have object co-ordinates in a city (in co-ordinates of google). Problem: how to translate google co-ordinates to the co-ordinates of my picture (that is in pixels on OX and OY on a picture). That is I receive google-co-ordinates and it is necessary for me to draw this point on my picture. I know that on small scales (for example on city scales) it to make simply enough (it is necessary to learn what google-co-ordinates has one of picture corners, then to learn "price" of one pixel in google-co-ordinates on a picture on axes OX and OY separately). But on the big scales (country scale) "price" of one pixel will be not a constant, and will vary strongly enough and the method described above cannot be applied. How to solve a problem on country scales?

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  • Changing Screen co-ordinates

    - by Anu
    Hi, Just i come across one application.When i load that application,the actual applcation is like toolbar only.Its get loaded in the top of the screen.And the desktop items automatically get moved and displayed below toolbar.Even when i open any other window and maximized the windoe,its get maximized below toolbar only.The screen co ordinates changed to new size. If before the screen size as (0,0,800,600),after this applcation loading it changed to (0,100,800,600). When i exit the application the screen changed to original position and all desktop items get arranged to original positiom. Hows it possible? Can i do that in MFC.

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  • I've got my 2D/3D conversion working perfectly, how to do perspective

    - by user346992
    Although the context of this question is about making a 2d/3d game, the problem i have boils down to some math. Although its a 2.5D world, lets pretend its just 2d for this question. // xa: x-accent, the x coordinate of the projection // mapP: a coordinate on a map which need to be projected // _Dist_ values are constants for the projection, choosing them correctly will result in i.e. an isometric projection xa = mapP.x * xDistX + mapP.y * xDistY; ya = mapP.x * yDistX + mapP.y * yDistY; xDistX and yDistX determine the angle of the x-axis, and xDistY and yDistY determine the angle of the y-axis on the projection (and also the size of the grid, but lets assume this is 1-pixel for simplicity). x-axis-angle = atan(yDistX/xDistX) y-axis-angle = atan(yDistY/yDistY) a "normal" coordinate system like this --------------- x | | | | | y has values like this: xDistX = 1; yDistX = 0; xDistY = 0; YDistY = 1; So every step in x direction will result on the projection to 1 pixel to the right end 0 pixels down. Every step in the y direction of the projection will result in 0 steps to the right and 1 pixel down. When choosing the correct xDistX, yDistX, xDistY, yDistY, you can project any trimetric or dimetric system (which is why i chose this). So far so good, when this is drawn everything turns out okay. If "my system" and mindset are clear, lets move on to perspective. I wanted to add some perspective to this grid so i added some extra's like this: camera = new MapPoint(60, 60); dx = mapP.x - camera.x; // delta x dy = mapP.y - camera.y; // delta y dist = Math.sqrt(dx * dx + dy * dy); // dist is the distance to the camera, Pythagoras etc.. all objects must be in front of the camera fac = 1 - dist / 100; // this formula determines the amount of perspective xa = fac * (mapP.x * xDistX + mapP.y * xDistY) ; ya = fac * (mapP.x * yDistX + mapP.y * yDistY ); Now the real hard part... what if you got a (xa,ya) point on the projection and want to calculate the original point (x,y). For the first case (without perspective) i did find the inverse function, but how can this be done for the formula with the perspective. May math skills are not quite up to the challenge to solve this. ( I vaguely remember from a long time ago mathematica could create inverse function for some special cases... could it solve this problem? Could someone maybe try?)

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  • transform longitude latitude into meters

    - by Sponge
    I need a function that maps gps positions to x/y values like this: getXYpos(GeoPoint relativeNullPoint, GeoPoint p){ deltaLatitude=p.latitude-relativeNullPoint.latitude; deltaLongitude=p.longitude-relativeNullPoint.longitude; ... resultX=latitude (or west to east) distance in meters from p to relativeNullPoint resultY=longitude (or south to north) distance in meters from p to relativeNullPoint } i have seen some implementations of "distance of two geoPoints" but they all just calculate the air-line distance. i think the deltaLongitude can be transformed into meters directly but the deltaLatitude depends in the Longitude. does anyone know how this problem can be solved?

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  • Finding Cities within 'X' Kilometers (or Miles)

    - by Mike Curry
    This may or may not be clear, leave me a comment if I am off base, or you need more information. Perhaps there is a solution out there already for what I want in PHP. I am looking for a function that will add or subtract a distance from a longitude OR latitude value. Reason: I have a database with all Latitudes and Longitudes in it and want to form a query to extract all cities within X kilometers (or miles). My query would look something like this... Select * From Cities Where (Longitude > X1 and Longitude < X2) And (Latitude > Y1 and Latitude < Y2) Where X1 = Longitude - (distance) Where X2 = Longitude + (distance) Where Y1 = Latitude - (distance) Where Y2 = Latitude + (distance) I am working in PHP, with a MySql Database. Open to any suggestions also! :)

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  • Extract co-ordinates from a vector of co-ordinates and save to file

    - by barsil sil
    I have a vector which contains a list co-ordinates ...x1,y1 ; x2,y2....xn,yn I am trying to extract each individual element which is a co-ordinate and then save them to file as a nice delineated co-ord pair which can be easily read. Or what would be nice i to save them so I can plot something in excel e.t.c (as cols of x and y values). My original vector size is 31, and was originally constructed as vector<vector<Point> > myvector( previous vector.size() ); Thanks !

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  • min max coordinate of cells , given cell length in c#

    - by Raj
    Please see attached picture to better understand my question i have a matrix of cells of [JXI] , cell is square in shape with length "a" my question is .. is there a way to use FOR loop to assign MIN,MAX coordinate to each cell taking origin (0,0) at one corner Thanks "freeimagehosting.net/uploads/3b09575180.jpg" i was trying following code but no success int a ; a = 1; for (int J=1; J<=5; J++) { for (int I = 1; I <= 5; I++) { double Xmin = ((I - 1)*a ); double Ymin = ((J - 1) * a); double Xmax = (I * a ); double Ymax = (J * a); } }

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  • calculating a gps coordinate given a point, bearing and distance

    - by user530509
    Hello, I have a problem which draws my back in some project for some time now. Im basically looking to trap a polygon using x,y points drawn by some script ive written. lat1,lon1 are the center gps cords of the polygon and im looking for its surrounding polygon. here is a part of my code in python: def getcords(lat1,lon1,dr,bearing): lat2=asin(sin(lat1)*cos(dr)+cos(lat1)*sin(dr)*cos(bearing)) lon2=lon1+atan2(sin(bearing)*sin(dr)*cos(lat1),cos(dr)-sin(lat1)*sin(lat2)) return [lat2,lon2] my input goes like this: lat1,lon1 - are given in decimal degrees. -dr is the angular computed by dividing the distance in miles by the earth's -raiuds(=3958.82) -bearing between 0-360 degrees. however for the input getcorsds1(42.189275,-76.85823,0.5/3958.82,30) i get [-1.3485899508698462, -76.8576637627568], however [42.2516666666667,-76.8097222222222] is the right answer. as for the angular distance i calculate it simply by dividing the distance in miles by the earth's raiuds(=3958.82). anybody?

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  • Convert long/lat to pixel x/y on a given picure.

    - by Kalinin
    I have a city "map" (for example - Moscow). She in accuracy repeats the contours the given city in google maps (that is it is copied from google maps and it is a little processed, but the sense remained the same). Also I have object co-ordinates in a city (in co-ordinates of google). Problem: how to convert google co-ordinates to the co-ordinates of my picture (that is in pixels on OX and OY on a picture). That is I receive google-co-ordinates and it is necessary for me to draw this point on my picture. The most desired variant of the answer - is based on javascript, but it is possible and on php. I know that on small scales (for example on city scales) it to make simply enough (it is necessary to learn what google-co-ordinates has one of picture corners, then to learn "price" of one pixel in google-co-ordinates on a picture on axes OX and OY separately). But on the big scales (country scale) "price" of one pixel will be not a constant, and will vary strongly enough and the method described above cannot be applied. How to solve a problem on country scales?

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  • C++ library for Coordinate Transformation Matrices (CTM)?

    - by BastiBense
    I'm looking for a C++ library which allows for easy integration of Coordinate Transformation Matrices (CTM) in my application. You might know CTMs from PDF or PostScript. For one project we are using C++/Qt4 as a framework, which offers a QTransform class, which provides methods like .translate(double x, double y) or .rotate(double degrees). After doing some transformations, it would allow me to get all 6 CTM values, which I could feed into a PDF library or use a transformation matrix in export files. Qt's API also allows for arbitrary mapping of polygons (QPolygon), rectangles (QRect) and other primitive data structures into transformed coordinate systems. So basically I'm looking for something similar to what Qt provides, but without the need of using Qt. I know I could do the matrix multiplications myself, but I'm not really interested in doing so, as I'm very sure that someone already solved this problem, so please no links to books or other guides on how to multiply matrices. Thanks!

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  • Convert Lat/Longs to X/Y Co-ordinates

    - by michael
    I have the Lat/Long value of New York City, NY; 40.7560540,-73.9869510 and a flat image of the earth, 1000px × 446px. I would like to be able to convert, using Javascript, the Lat/Long to an X,Y coordinate where the point would reflect the location. So the X,Y coordinate form the Top-Left corner of the image would be; 289, 111 Things to note: don't worry about issues of what projection to use, make your own assumption or go with what you know might work X,Y can be form any corner of the image Bonus points for the same solution in PHP (but I really need the JS)

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  • Why doesn't JFreeCharts correctly connect the points in my xy-line graph?

    - by Javajava
    /Each letter A,T,G,C represents a direction for the plot to graph. Specifically, “A” means move right, “T” is move down, “C” is move up, and “G” is move left. When the applet reads A,T,C, it plots the graph correctly. However, when I plot G, the graph is messed up. When I input "ACACACA," the graph is like a rising staircase. When I input "gtgtgt," the graph should look like a staircase, but it looks like a lightning bolt instead/ /This is all one code... i don't know why it's all split up like this:/ import java.applet.Applet; import java.awt.*; import java.awt.event.*; import java.util.Scanner.*; import java.jfree.chart.*; import java.jfree.data.xy.*; import java.jfree.chart.plot.PlotOrientation; public class If_Graph extends Applet implements ActionListener{ Panel panel; TextArea textarea, outputArea; Button move; String thetext; Scanner reader = new Scanner(System.in); String thetext2; int size,p,q; int x,y; public void init(){ setSize(500,500); //set size of applet panel = new Panel(); add(panel); setVisible(true); textarea= new TextArea(10,20); add(textarea); move=new Button("Graph"); move.addActionListener(this); add(move); } public void actionPerformed(ActionEvent e) { XYSeries series = new XYSeries("DNA Walk"); x= 0; y = 0; series.add(x,y); if(e.getSource() == move) { thetext=textarea.getText(); //the text is the DNA bases pasted thetext=thetext.replaceAll(" ",""); //removes spaces thetext2 = ""; for(int i=0; i<thetext.length(); i++) { char a = thetext.charAt(i); switch (a) { case 'A': //moves right x+=1; y+=0; series.add(x,y); break; case 'a': x+=1;y+=0; series.add(x,y); break; case 'C': //moves up x+=0; y+=1; series.add(x,y); break; case 'c': x+=0; y+=1; System.out.println(x + "," + y); series.add(x,y); break; case 'G': //move left x-=1; y+=0; series.add(x,y); System.out.println("G is: "+ x +"," +y); break; case 'g': x-=1; y+=0; System.out.println("g is: " +x + "," + y); series.add(x,y); break; case 'T': //move down x+=0; y-=1; series.add(x,y); System.out.println("T is: "+ x +"," +y); break; case 't': x+=0; y-=1; series.add(x,y); System.out.println("t is: "+ x +"," +y); break; default: // series.add(0,0); break; } } XYDataset xyDataset = new XYSeriesCollection(series); JFreeChart chart = ChartFactory.createXYLineChart ("DNA Random Walk", "", "", xyDataset, PlotOrientation.VERTICAL, true, true, false); ChartFrame frame1=new ChartFrame("DNA Random Walk",chart); frame1.setVisible(true); frame1.setSize(300,300); outputArea.setText(thetext2); } } }

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  • whats a sure shot way to make sure objects appear correctly positioned on stage

    - by dubbeat
    Hi, I've being having a lot of trouble recently getting objects (UIComponents containing movieclips) to appear correctly in the right positions. For example, my current dilema is I have a container that is 3 layers deep. outer layer inner layer display layer This hiearachy was built in CS4 as a movieclip. In the display layer in CS4 I figured out where I want to place 16 different "box" movieclips. I dont want to create these boxes maunually at design time, instead I want to add them at run time. So I know what container I want to add my boxes to. I know what positions they "would" be at in CS4 environment. Whats the best way to add them in the correct locations with code? The "box" I'm trying to add in a movieclip held inside of a UIComponent. Is there a "rule of thumb" to do this type of thing? I'm sure I'm going to encounter this problem again and again and I'd like to just blow the problem out of the water once and for all with the "right way" to do this.

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  • How to calculate the touch location with convertToWorldSpace?

    - by Paul
    i would like to convert the touch location as a world coordinate in my tile game. With this code, i clicked on the right of the screen (so that my character walks in the tiled game, and the background goes slowly to the left) : - (void)ccTouchesEnded:(NSSet *)touches withEvent:(UIEvent *)event { for( UITouch *touch in touches ) { CGPoint location = [touch locationInView: [touch view]]; location = [[CCDirector sharedDirector] convertToGL: location]; CGPoint test = [self convertToWorldSpace:location]; CCLOG(@"test : %.2g", test.x); The test log gives me : 50, 72, 1e+02, 2.6e+02, 4.2e+02, (and then goes down) 3.2e+02, 9.5, -1.9e+02, etc. Does anyone know why? I would like to calculate the "real" coordinate of the touch, so that i know when the character has to keep going (click on the right of its actual position) or if he has to turn and go backwards. (click on the left of its actual position) Thanks for your help

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  • Determining if a coordinate is on a line

    - by TGCBraun
    I´m coding a little app that allows the user to draw multiple shapes and then remove or resize them. It´s working perfectly on rectangles and ovals, but I´m having issues with lines. Here´s a method that I wrote to find if the clicked spot on the screen is part of a specific line: public boolean containsLocation(int x, int y) { int m = (getY2() - getY()) / (getX2() - getX()); int b = getY() - (m * getX()); if (y == (m * x) + b) { return true; } return false; I´m using the famous y = mx + b formula and replacing y and x to find if the clicked spot is part of the line. The problem is when I click on the screen to remove the line, it only works if I click on the very fist coordinate (x,y) where the line starts. Nothing happens when I click anywhere else along the line. Can anyone shed a light on what I´m doing wrong? Thanks a lot.

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